Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE IM No.: ME6-2S-2020-2021 College of Engineering Bambang Campus DEGREE PROGRAM SPECIALIZATION YEAR LEVEL Bachelor of Science in COURSE NO. Mechanical Engineering COURSE TITLE 2nd Year TIME FRAME MECH02 Advanced Mathematics for ME 3 WK NO. hrs/week I. UNIT TITLE/CHAPTER TITLE: Numerical Methods and Analysis II. LESSON TITLE: Numerical Analysis III. 2-3 IM NO. 1 II.1 Numerical Methods: Introduction, Discrete Algebra, Accuracy, Errors II.2 Numerical analysis in Engineering: Taylor Series LESSON OVERVIEW: The course program differentiates accuracy from error approximation. It gives an overview to students the significance of finding and computing for the error as one criteria to satisfy numerical calculation. It also provide details on how the error is estimated in numerical analysis. The Taylor Series, together with MacLaurin series are derived and discussed in estimating the truncation error and know its applicability to other advanced topics such as Power series. IV. DESIRED LEARNING OUTCOMES: 1. Define accuracy and error estimation. 2. Discuss the different types of error encountered in numerical computation and modeling. 3. Solve problems involving Taylor and McLaurin series. V. LESSON CONTENT: 1. Introduction, Discrete Algebra, Accuracy and Error The algebraic type of mathematics is different from the numerical type of mathematics. In solving algebraic functions such as ODEs and calculus, there are few choices on how to solve the problem with algebraic solution. The numerical method gives numerical solution that are tabulated and represented in graphs, means that choice of numerical method or algorthim depends on its applicability. The results can be selected based on its accuracy and when to start or end the computation. Thus, it is essential for mechanical engineers to know and learn numerical methods, the estimation of errors and order of convergence. Such numerical problems have complicated equation that finding its roots is a difficult task. We begin the discussion with round-off errors. The round-off error is caused by chopping, or discarding all the digits from some decimal or rounding of values. The rule of rounding the error to n significant digit is same as replacing the the decimal with significant digits. ROUNDOFF RULE: To round a number x to k no. of decimals, use chop the signficant digits after the (k+1)st digit. and add to x then NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 1 of 6 Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE IM No.: ME6-2S-2020-2021 Sample: Round the number 1.23454621 to k=2 decimals, 3 decimals, 4 decimals and 5 decimals. Using the roundoff rule, a.) . , so that 1.23454621+0.005 becomes 1.23954621. Then chop off the (k+1)st digit, which is starting 3rd digit, remove “954621” to get 1.23. b.) . , so that 1.23454621+0.0005 becomes 1.23504621. Then chop off the (k+1)st digit, which is starting 4th digit, remove “04621” to get 1.235. c.) . , so that 1.23454621+0.00005 becomes 1.23459621. Then chop th off the (k+1)st digit, which is starting 5 digit, remove “9621” to get 1.2345. d.) . , so that 1.23454621+0.000005 becomes 1.23455121. Then chop off the (k+1)st digit, which is starting 6th digit, remove “121” to get 1.23455. NOTE: The rounding of values may lead to round-off error which is very dangerous in the computation of large data. It is therefore important to analyze some computational programs and expect some roundoff errors in-between the series of computation. The experimental errors are simply caused by human errors or error specified in the tool for gathering the needed data. The truncation errors result from truncating or prematurely breaking off and usually computed when using Taylor series and getting the difference with the supposed computation of sum of the terms. The formula in getting the error depends on the true value and approximated value, getting the difference, Sometimes, getting the absolute value of the difference is used in some experiments to denote absolute error. For the relative error, get the ratio between computed error and true value, i.e. Sometimes, the errors are limited with error bounds (β) depending on the practice used in the field of study, that is, | | | | In error propagation, when the computed errors with bounds are carried or propagated to the next computation, usually affects the accuracy of overall computation. Thus, bounds for error is simply getting the sum of error bounds while bounds for relative error are added under multiplication/division. a.) In addition and subtraction, bound for the error of the results is given by the sum of the error bounds for the terms. b.) In multiplication and division, bound for relative error of the results is given by the sum of the bounds for the relative errors. Sample Problem 1: Approximations of 3.14159265358979 … are 22/7 and 355/113. Determine the corresponding errors and relative errors to 3 significant digits. Solution: Since 22/7 is the irrational number that defines pi, it is the true value. The 355/113 is the approximated value (AV). Thus, computing the errors gives 22 355 1 1.264222503 10 . 7 113 791 NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 2 of 6 Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE 1 355 113 22 7 1 2486 4.022526146 10 IM No.: ME6-2S-2020-2021 . Note that we cannot apply the rounding-off rule since we only need to consider 3 significant digits in exponential form and not the decimal form. Sample Problem 2: Determine the absolute error and relative error when approximating the derivative of x=2 using the approximation formula, 5 at ′ with h=0.1 Solution: The approximation formula represents the approximated value while the true value is simply the derivative ′ at x=2. AV: 0.1 2 0.1 5 2 0.1 0.1 6.09 6 0.9 0.1 2 TV: 2 Thus, 5 | 2 2 2 . . | 0.1 0.1 2 5 5 2 5 5 1 . . 2. Taylor and Maclaurin Series The Taylor series given a function f(x), a real value a for which the nth derivative 0, hence the Taylor series of f about a is defined as Note: ≡ . is defined for all ! Moreover, we define the radius of convergence of the Taylor series as the largest ∈ , , the series converges. 0 such that, for all When the center a =0, the Taylor series is called Maclaurin series. Sample Problem 1: Determine the Taylor series for the function Recalling the Taylor series form, at a=0. ! we express the terms when n=0, n=1, n=2, n=3, n=4 and so on. NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 3 of 6 Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE n=0: 0 n=1: 0 n=2: 0 n=3: 0 n=4: 0 0 ! 1 IM No.: ME6-2S-2020-2021 (Note: 0! = 1) (the derivative of ex is ex) ! ! ! ! Now, adding the terms (n=1 to n=4) to form the Taylor series of ex is written in the form: ⋯ ! ! This is the fourth-degree Taylor series approximation since up to fourth derivative is solved. Sample Problem 2: Determine the Maclaurin series for the function Recalling the Maclaurin series form, . 0 0 ! we express the terms when n=0, n=1, n=2, n=3, n=4 and so on. n=0: 0 n=1: 0 n=2: 0 n=3: 0 n=4: 0 ! ! ! ! ! 0 sin 0 0 (Note: x0 = 1 and ≡ ) cos 0 sin 0 0 cos 0 sin 0 0 Therefore, the Maclaurin series of sinx is written in the form: ⋯ ! ! This is the fourth-degree Taylor series approximation since up to fourth derivative is solved. Sample Problem 3: Determine the Taylor series for the function The Taylor series form, at x=1. NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 4 of 6 Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE 1 n=0: 1 n=1: 1 n=2: 1 n=3: 1 1 ! 1 1 ! ln 1 1 0 IM No.: ME6-2S-2020-2021 1 ! 1 (Note: first derivative of ln x = 1/x) (Note: derivative 1/x is -1/x2) ! (Note: derivative of -1/x2 is 2/x3) ! Therefore, the Taylor series of lnx at x=1 is written in the form: ⋯ ! ! This is the third-degree Taylor series approximation since up to third derivative is solved. VI. LEARNING ACTIVITIES: Seatwork #1: Solve the following problems and box your final answers. Pattern the step-by-step solution in sample problems. 1.) Write the Maclaurin series form of cos 2x. 2.) Write the Taylor series form of at x0=1. 3.) Use the formula in approximating the derivative (same as Sample Problem 2) of at x=1 using h=0.5. Compute the absolute and relative errors. 4.) What is the greatest value of h that can be used to approximate the derivative of of with an error of no more than 1%? VII. 2 3 1 at x=4 5.) Determine the relative error when approximating e-1 using fifth-degree Taylor polynomial with respect to ex compared to sixth-degree Taylor polynomial. (Hint: express the degree series using x=-1 to get the exact values) EVALUATION To be given via MS Teams NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 5 of 6 Republic of the Philippines NUEVA VIZCAYA STATE UNIVERSITY Bambang, Nueva Vizcaya INSTRUCTIONAL MODULE VIII. IM No.: ME6-2S-2020-2021 ASSIGNMENT: Assignment #1. Solve the following problems and box your final answers. Pattern the step-by-step solution in sample problems. 1.) Determine the absolute and relative error when approximating 2 polynomial compared to seventh-degree Taylor polynomial. using sixth-degree Taylor 2.) Determine the absolute and relative error that occurs when approximating the integral 3 using three rectangles, each with width ∆ 1 and for which the heights are f(0), f(1), f(2) where f(x)=3x. (Hint: the expressed integral is TV while area (∆ is the AV) 3.) Determine the absolute and relative error that occurs when approximating the integral 2 using three rectangles, each with width ∆ 0.5 and for which the heights are f(0), f(1), f(2) where f(x)=2x2. (Hint: the expressed integral is TV while area (∆ is the AV) IX. REFERENCES: E. Kreyzsig, Advanced Engineering Mathematics, 10th Edition, John Wiley & Sons, 2011. United States of America NVSU-FR-ICD-05-00 (040221) In accordance with Section 185, Fair Use of a Copyrighted Work of Republic Act 8293, the copyrighted works included in this material may be reproduced for educational purposes only and not for commercial distribution. Page 6 of 6