7 Mathematics Quarter 1 – Module 10: Estimating the Square Root of a Whole Number to the Nearest Hundredth 1 Mathematics – Grade 7 Quarter 1 – Module 10: Estimating the Square Root of a Whole Number to the Nearest Hundredth Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties. Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this book are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them. Regional Director: Gilbert T. Sadsad Assistant Regional Director: Jessie L. Amin Development Team of the Module Writer: Jeric C. Dino Editor: Lilli Ann O. Hermogenes Reviewer: Dioleta B. Borais 2 MODULE 10 ESTIMATING THE SQUARE ROOT OF A WHOLE NUMBER TO THE NEAREST HUNDREDTH INTRODUCTION In your previous modules, you were able to differentiate a rational number from irrational number. You were also able to determine in what two integers the square root of a given number lie. But have you ever wondered how to estimate the square root of a number that is not a perfect square up to the nearest hundredth? In this module, you are going to learn about: estimating the square root of a whole number to the nearest hundredth. VOCABULARY LIST β Estimate – to find something close to a specific value. β Hundredth – the second digit after the decimal point of a decimal number. PRE – TEST Estimate the following square roots to the nearest hundredth. 1. √17 3. √75 2. √23 4. √99 To get things started, you may begin by answering Activity 1 to recall your knowledge on rational and irrational numbers. ACTIVITY 1: Which one is Irrational? Identify whether each number is rational or 1. −12 6. 1.234789423412 … 2. 24 7. π 3. √3 8. −8.7 4. 2 3 5. 0.5555555 … irrational. 9. √81 10. √12 3 Were you able to determine which of those numbers are rational and which ones are irrational? When is a number rational? When is it irrational? π Rational numbers are numbers that can be expressed as a ratio π , where π πππ π are integers, while irrational numbers are numbers that cannot be expressed as a ratio of two integers. Some of these numbers are commonly expressed as square roots, or sometimes a non – terminating, non – repeating decimal. Now, proceed to Activity 2 to recall your knowledge on estimating the square root of a whole number to the nearest two integers. ACTIVITY 2: Place in Between Determine in what two integers the following numbers lie. 1. √7 4. √82 2. √15 5. √103 3. √57 The numbers listed in Activity 2 are irrational numbers. Their square root is not an integer or a terminating, repeating decimal. But what if we look for its square root up to the nearest tenth or even to the nearest hundredth, is there a way to do it without using calculators? Here are some of the ways to estimate the square root of a whole number up to the nearest hundredth: A. Divide and Average Method It is difficult and tedious to use guess and check in estimating the square root of a whole number up to the nearest hundredth. So, this method called the Divide and Average Method can be used. The following are the steps in estimating the square root of a whole number using this method. 4 STEP 1: Estimate. Find two perfect squares between which the number lies. STEP 2: Divide. Divide the number by one of those square roots. Use the square root closest to that number. STEP 3: Average. Get an improved estimate by getting the average of the divisor and quotient in Step 2. STEP 4: Using the result in Step 3, repeat Steps 2 and 3 until we find a number that is accurate enough (depending on the decimal place we want to approximate). ( Illustrative Examples 1. Estimate √10 to the nearest tenth. Solution: Step 1: Find two perfect squares between which the number lies. 9 < 10 < 16 → 9 and 16 are perfect squares √9 < √10 < √16 → 10 is closer to 9 3 < √10 < 4 → 3 will be the first estimate of √10 Step 2: We divide 10 by our first estimate which is 3. 10 3 ≈ 3. 33 → we will Since we are looking for the nearest tenth, get the quotient to the nearest hundredth. Step 3: Get the average of the estimate (3) and the quotient in Step 2 (3.33). 3+3.33 2 = 6.33 2 = 3.165 → the average is 3.165 or 3.17 Step 4: Repeat Steps 2 and 3 until the divisor and the quotient in Step 3 agree in tenths place. 5 β’ We divide 10 by our new estimate which is 3.17. 10 ≈ 3.154 3.17 → the new quotient is 3.154 or 3.15 Notice that the new quotient (3.15) and divisor (3.17) agree in the tenths place. β’ We get the average of 3.15 and 3.17. 3.15 + 3.17 6.32 = = 3.16 ππ 3.2 2 2 Thus, √ππ ≈ π. π to the nearest tenths. 2. Estimate √31 to the nearest hundredth. Solution: Step 1: Find two perfect squares between which the number lies. 25 < 31 < 36 → 25 and 36 are perfect squares √25 < √31 < √36 → 31 is closer to 36 5 < √31 < 6 → 6 will be our first estimate of √31 Step 2: We divide 31 by our first estimate which is 6. 31 6 ≈ 5.167 → since we are looking for the nearest hundredth, we will get the quotient to the nearest thousandth Step 3: Get the average of the estimate (6) and the quotient in Step 2 (5.167). 6+5.167 2 = 11.167 2 = 5.5835 → the average is 5.5835 or 5.584 6 Step 4: Repeat Steps 2 and 3 until the divisor and the quotient in Step 3 agree in hundredths place. β’ We divide 31 by our second estimate which is 5.584 31 ≈ 5.556 5.584 → the second quotient is 5.556 β’ Get the average of the second estimate (5.584) and the second quotient (5.556) 5.584 + 5.556 11.14 = = 5.57 2 2 Here, since our divisor and quotient do not agree yet in the hundredths place, we repeat Steps 2 and 3. β’ Divide 31 by our new estimate which is 5.57 31 ≈ 5.566 5.57 → the new quotient is 5.5655 or 5.566 (or 5.57) Note that our divisor and quotient already agree in the hundredths place. β’ Get the average of 5.57 and 5.566 5.57 + 5.566 11.136 = = 5.568 ππ 5.57 2 2 Thus, √ππ ≈ π. ππto the nearest hundredth. Checkpoint 1 Estimate the value of the following square roots to the nearest hundredth using Divide and Average Method. 1. √11 3. √71 2. √46 4. √103 7 B. Square Root Estimate Formula Aside from the Divide and Average Method, this formula in estimating for the square root of a whole number to the nearest hundredth can also be used: π΅ →the number which we want the square root of πΊ →the closest perfect square to the given number N Illustrative Examples 1. Estimate √14 to the nearest hundredth. Solution: √π΅ ≈ √πΊ + π΅−πΊ π√πΊ π΅ = ππ πΊ = ππ → ππππ ππ π‘ πππππππ‘ π ππ’πππ π‘π 14 14 − 16 √14 ≈ √16 + 2√16 2 ≈4− 2 β4 1 ≈4− 4 ≈ 4 − 0.25 ≈ 3.75 Hence, √ππ ≈ π. ππ 2. Estimate √105 to the nearest hundredth. Solution: √π΅ ≈ √πΊ + π΅−πΊ π√πΊ π΅ = πππ πΊ = πππ → ππππ ππ π‘ πππππππ‘ π ππ’πππ π‘π 105 105 − 100 √105 ≈ √100 + 2√100 5 ≈ 10 + 2 β 10 1 ≈ 10 + 4 ≈ 10 + 0.25 ≈ 10.25 Hence, √πππ ≈ ππ. ππ 8 Checkpoint 2 Estimate the following square roots to the nearest hundredth using Square Root Estimate Formula and verify it using the Divide and Average Method. 1. √29 2. √57 3. √90 4. √115 Were you able to perform Checkpoint 2? Which method is more accurate in estimating the square root of a whole number to the nearest hundredth? Why? Do you know other ways/methods in estimating the square root of a whole number to the nearest hundredth? Share it with your classmates! REMEMBER Divide and Average Method, and Square Root Estimate Formula are just two of many ways to estimate the square root of whole number to the nearest hundredth. But neither of these methods give us the EXACT value of the square root of irrational numbers. The only value we can determine is its estimate. ENRICHMENT Square Root Algorithm Method This algorithm for square roots resembles the long division algorithm, and it was taught in schools in days before calculators. Here are the steps and examples using this method: Illustrative Example 1. Estimate √8 to the nearest hundredth. β’ Step 1: Group the given number into pairs. Since we are estimating to the nearest hundredth, we are going to add two pairs of zeros after the decimal point. 9 β’ Step 2: Determine the largest integer whose square is less than or equal to the given number and write that integer above and to the left of the given number. 12 = 1 ππ = π 32 = 9 The integer 2 will be used since its square is less than 8, also because 32 is already more than 8. β’ Step 3: Square the first integer estimate, and write it below the given number. β’ Step 4: Subtract the result just like in division algorithm. Then bring down the next two pairs of numbers (00 in this example). β’ Step 5: Double the units digit of the first integer estimate, and write it to the left of the result in Step 4. This will become the tens digit of our second integer estimate. This is 4 because 2 times 2 equals 4. This is our second integer estimate. β’ Step 6: Determine the largest integer to be written as the units digit of our second integer estimate such that the product of that largest integer and our second integer estimate is less than or equal to our next number (400). Then, repeat Steps 3 and 4. Why 48? Here, we will try to get as close to 400 as possible, but not more than 400. 47 x 7 = 329 → this is still small 48 x 8 = 384 → this is close to 400 49 x 9 = 441 → this is already more than 400 10 β’ Step 7:Repeat Step 5 48 = 40 + 8 Now, double the units digit 8. 8 x 2 = 16 Then, 40 + 16 = 56 This is our 3rd integer estimate β’ Step 8: Repeat Step 6, only that we will try to get as close to 1600 as possible (it can be less than or greater than 1600) Why 563? Here, we will try to get as close to 1600 as possible 562 x 2 = 1124 → this is too small for 1600 563 x 3 = 16689 → this is close to 1600 Note: Here, we will only take which value is closest since we are already looking for the hundredths digit. Hence, √π ≈ π. ππ Try this! Estimate √120 to the nearest hundredth using this method. Compare the value that you have obtained to the result when the other two methods (you have learned) are used. 11 POST TEST Estimate the following square roots to the nearest hundredth. 1. √27 3. √175 2. √68 4. √390 Assignment Estimate √120 to the nearest hundredth using this method. Compare the value that you have obtained to the result when the other two methods (you have learned) are used. ANSWER KEY Pretest 2. 3 and 4 1. 4.12 3. 7 and 8 2. 4.80 4. 9 and 10 3. 8.66 5. 10 and 11 4. 9.95 ACTIVITY 1 CHECKPOINT 1 1. Rational 1. 3.32 2. Rational 2. 6.78 3. Irrational 3. 8.43 4. Rational 4. 10.15 5. Rational CHECKPOINT 2 6. Irrational 1. 5.39 7. Irrational 2. 7.54 8. Rational 3. 9.49 9. Rational 4. 10.72 10. Irrational ACTIVITY 2 1. 2 and 3 POST TEST 1. 5.20 12 2. 8.25 ENRICHMENT (TRY THIS!) 3. 13.23 Answer: 10.95 4. 19.75 13 REFERENCES Internet Sources: • https://www.showme.com/sh/?h=dQ9fHWq • http://www.math.com/school/subject1/lessons/S1U1L9DP.html • https://www.homeschoolmath.net/teaching/square-root-algorithm.php 14