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Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Objectives
1
•
•
Axis systems
Coordinate
transformation
Aircraft Equations of Motion
2
•
3
6 dof forces and
moments Eqs.
•
EOM into
longitudinal and
lateral motions
AE-426 Flight Dynamics --- 201
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•
Kinematic Eqs.
And its need
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Aircraft Equations of Motion
-Introduction
•What is Flight Dynamics?
•Is the study of aircraft motion and
its characteristics due to internally
or externally generated
disturbances.
Aircraft Equations of Motion
AE-426 Flight Dynamics -- 201
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Aircraft Equations of Motion
-Introduction
Dynamics
Studying the motion with acceleration
of particles and rigid bodies
(Kinetics)
Kinematics
Studying the motion including
the effects of forces on motion
Describing motion i.e. position,
velocity, and acceleration, without
reference to forces
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Introduction
Six degrees of freedom (6-DOF) motions
Experiences motions in three dimensions
- 3 translational degrees describes the
trajectory
- 3 rotational degrees describes the orientation
Rigid Aircraft Body
Derive the general equations of motion (EOM)
Aircraft Equations of Motion
Define the axis system, or coordinate systems,
or reference frame in which these equations
are derived
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Axis Systems
Why we need axis systems?
• To derive aircraft EOM.
• To define a particular vector (aerodynamic forces, weight,
thrust, …)
Characteristics of these axis systems
• Right-hand Orthogonal
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Axis Systems (Cont.)
Earth Axis System (Non-Rotating): XE, YE, ZE
• Inertial. Why?
• Rotational velocity of the earth is neglected
• Acceptable for supersonic airplanes but not hypersonic
• Fixed on Earth, XE to North, YE to East, ZE to center
of Earth.
Body Axis System (Rotating): Xb, Yb, Zb
• Non-inertial.
• Fixed on aircraft c.g., Xb out to nose, Yb out to right
wing, Zb down of aircraft.
• Easy to find moments and products of inertia.
cg
α
Yb
Ys
Xb
Zs
Stability Axis System: Xs, Ys, Zs
• Obtained by rotating body axis by angle of attack α.
• Xs in direction of relative wind V∞, Ys out to right
wing, Zs down of aircraft.
Zb
Xs
O
XE
V∞
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YE
Aircraft Equations of Motion
ZE
Aircraft Equations of Motion
-Coordinate Transformations
Weight Vector
•πΉ
=𝐹
=𝐹
0
= 0
π‘Š
0
= 0
π‘šπ‘”
Aerodynamic Forces
•πΉ
−𝐷
=𝐹 = 𝐹
−𝐿
Thrust Vector
•πΉ
Aircraft Equations of Motion
𝑇 cos πœ™
0
=𝐹 =
−𝑇 sin πœ™
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
cg
O
XE
Yb
YE
ZE
Zb
Aircraft Equations of Motion
Xb
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Earth to Body Axis Transformation
• Three consecutive Euler rotations through Euler angles in order.
─ 1st rotation through YAW (Heading) angle Ψ.
─ 2nd rotation through PITCH angle Θ.
─ 3rd rotation through ROLL angle Φ.
Earth Axis
System
0
• Angles limits: −90∘
−180∘
Aircraft Equations of Motion
Ψ, Θ, Φ
Body Axis
System
≤ Ψ ≤ 360∘
≤ Θ ≤ 90∘
≤ Φ ≤ 180∘
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
STEP (1): Rotate 𝐹⃗ = 𝑋 πš€Μ‚ + π‘Œ πš₯Μ‚ + 𝑍 π‘˜ in
Earth axis by Ψ about z-axis to get:
STEP (2): Rotate 𝐹⃗ = 𝑋 πš€Μ‚ + π‘Œ πš₯Μ‚ + 𝑍 π‘˜ in
intermediate axis by Θ about y-axis to get:
• Intermediate axis πš€Μ‚ , πš₯Μ‚ , π‘˜ with 𝐹⃗ = 𝑋 πš€Μ‚ + π‘Œ πš₯Μ‚ + 𝑍 π‘˜
• 𝑋 = +𝑋 cos Ψ + π‘Œ sin Ψ
• π‘Œ = −𝑋 sin Ψ + π‘Œ cos Ψ
• 𝑍 = +𝑍
cos Ψ sin Ψ 0 𝑋
𝑋
• π‘Œ = − sin Ψ cos Ψ 0 π‘Œ
0
0
1 𝑍
𝑍
• Another intermediate axis πš€Μ‚
π‘Œ πš₯Μ‚ + 𝑍 π‘˜
• 𝑋 = 𝑋 cos Θ − 𝑍 sin Θ
•π‘Œ =π‘Œ
• 𝑍 = 𝑋 sin Θ + 𝑍 cos Θ
cos Θ 0 − sin Θ
𝑋
• π‘Œ = 0
1
0
sin Θ 0 cos Θ
𝑍
• 𝐹⃗ = 𝑅 Ψ πΉβƒ—
Aircraft Equations of Motion
, πš₯Μ‚ , π‘˜
with 𝐹⃗ = 𝑋 πš€Μ‚ +
𝑋
π‘Œ
𝑍
• 𝐹⃗ = 𝑅 Θ πΉβƒ— = 𝑅 Θ π‘… Ψ πΉβƒ—
AE-426 Flight Dynamics --- 201
STEP (3): Rotate 𝐹⃗ = 𝑋 πš€Μ‚ + π‘Œ πš₯Μ‚ + 𝑍 π‘˜
in intermediate axis by Φ about x-axis to get:
• Body axis πš€Μ‚, πš₯Μ‚, π‘˜ with 𝐹⃗ = 𝑋
• 𝑋 = +𝑋
• π‘Œ = +π‘Œ cos Φ + 𝑍 sin Φ
• 𝑍 = −π‘Œ sin Φ + 𝑍 cos Φ
𝑋
1
0
0
• π‘Œ = 0 cos Φ sin Φ
𝑍
0 − sin Φ cos Φ
πš€Μ‚ + π‘Œ πš₯Μ‚ + 𝑍 π‘˜
𝑋
π‘Œ
𝑍
• 𝐹⃗ = 𝑅 Φ πΉβƒ— = 𝑅 Φ π‘… Θ π‘… Ψ πΉβƒ—
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Stability to Body Axis Transformation
• Required to transform aerodynamic forces.
• Rotate stability axis system about y-axis through positive angle of attack
Body Axis
System
𝛼 about y
Stability
Axis System
•
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Coordinate Transformations (Cont)
Summary of Axes Transformation
• Earth to body axis transformation:
𝐹⃗ = 𝑅 Φ π‘… Θ π‘… Ψ πΉβƒ—
• Body to Earth axis transformation:
𝐹⃗ = 𝑅 −Ψ π‘… −Θ π‘… −Φ πΉβƒ—
𝐹⃗ = 𝑅 Ψ π‘… Θ π‘… Φ πΉβƒ—
• Stability to body axis transformation:
𝐹⃗ = 𝑅 𝛼 𝐹⃗
• Overall;
Earth Axis
System
Aircraft Equations of Motion
Ψ, Θ, Φ
Body Axis
System
AE-426 Flight Dynamics --- 201
𝛼
Stability Axis
System
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Aircraft Equations of Motion
-Aircraft Force Equations
• Developed from Newton’s 2nd Law;
𝑑 π‘šπ‘‰
𝑑𝑑 Inertial
(
=
𝐹
βŸβƒ—
)
. .
• Newton’s 2nd Law is valid only in an inertial reference frame.
• Iner al frame → fixed in space with no rela ve mo on.
• Assumptions to develop EOM:
– Aircraft is a rigid body.
– Aircraft mass is constant.
– Earth axis system is assumed to be inertial.
• Three translational EOM.
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Force Equations (Cont)
• Since Newton’s 2nd Law applies only in an inertial (non-rotating) axis system BUT
ALL THE ACTION happen on a non-inertial (rotating) axis system, then, we need
to write aircraft EOM in its body axis system.
• So, we need a vector transformation relationship;
𝑑𝐴⃗
𝑑𝑑
𝑑𝐴⃗
=
𝑑𝑑
+ πœ” × π΄βƒ—
Where
: represents any vector which is to be transformed.
: is the angular rotation vector of rotating system relative to non-rotating
system.
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Force Equations (Cont.)
Steps to Develop Aircraft Force EOM
STEP β‘  : Starting with Newton’s 2nd Law;
𝑑 π‘šπ‘‰
𝑑𝑑 Inertial
𝑑 𝑉
π‘š
𝑑𝑑 Inertial
π‘š π‘Žβƒ—Inertial
= 𝐹⃗
= 𝐹⃗
= 𝐹⃗
STEP β‘‘ : Expressing π‘Žβƒ—Inertial in body axis system and accounting for the rotation of body axis on the aircraft;
Aircraft Equations of Motion
Μ‡
π‘Žβƒ—Inertial Body = 𝑉Body + πœ”Body ×
𝑉Body
π‘ˆΜ‡
πš€Μ‚
Μ‡
π‘Žβƒ—Inertial Body = 𝑉
+ 𝑃
Μ‡
π‘Š Body
π‘ˆ
π‘ˆΜ‡ + π‘„π‘Š − 𝑅𝑉
π‘˜
⇒ 𝑉̇ + π‘…π‘ˆ − π‘ƒπ‘Š
𝑅
π‘Š Body
π‘ŠΜ‡ + 𝑃𝑉 − π‘„π‘ˆ Body
AE-426 Flight Dynamics --- 201
πš₯Μ‚
𝑄
𝑉
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Aircraft Equations of Motion
-Aircraft Force Equations (Cont)
STEP β‘’ : Newton’s 2nd Law becomes;
π‘Žβƒ—Inertial Body
π‘ˆΜ‡ + π‘„π‘Š − 𝑅𝑉
π‘š 𝑉̇ + π‘…π‘ˆ − π‘ƒπ‘Š
π‘ŠΜ‡ + 𝑃𝑉 − π‘„π‘ˆ Body
=
𝐹⃗Body
=
𝐹
𝐹
𝐹 Body
STEP β‘£ : Expanding RHS of 𝐹⃗Body ;
𝐹
𝐹
𝐹⃗Body = 𝐹
= 𝐹
𝐹 Body
𝐹
Body
𝐹
+ 𝐹
𝐹
Body
𝐹
+ 𝐹
𝐹
Body
STEP β‘€ : Combine and separate Eq. π‘Žβƒ—Inertial Body = 𝐹⃗Body ;
π‘š π‘ˆΜ‡ + π‘„π‘Š − 𝑅𝑉
π‘š 𝑉̇ + π‘…π‘ˆ − π‘ƒπ‘Š
=
−π‘šπ‘” sin Θ
+
=
π‘šπ‘” sin Φ cos Θ
+
π‘š π‘ŠΜ‡ + 𝑃𝑉 − π‘„π‘ˆ
=
π‘šπ‘” cos Φ cos Θ
+
Aircraft Equations of Motion
−𝐷 cos 𝛼 + 𝐿 sin 𝛼
𝐹
−𝐷 sin 𝛼 − 𝐿 cos 𝛼
AE-426 Flight Dynamics --- 201
+
𝑇 cos Φ
+
0
+
−𝑇 sin Φ
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Aircraft Equations of Motion
-Aircraft Moment Equations
• Developed from Newton’s 2nd Law;
• Angular momentum of aircraft;
• Three rotational EOM.
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
Steps to Develop Aircraft Moment EOM
STEP β‘  : Starting with a small elemental mass dm of aircraft located at dome distance from c.g. and
rotating with positive angular rates about c.g.;
π‘Ÿβƒ—dm = π‘₯πš€Μ‚ + 𝑦πš₯Μ‚ + π‘§π‘˜
STEP β‘‘ : Expressing the velocity of dm and accounting for its rotation around c.g.;
Aircraft Equations of Motion
𝑉dm =
π‘‘π‘Ÿβƒ—dm
+ πœ”Body × π‘Ÿβƒ—dm
𝑑𝑑 Body
𝑉dm =
πœ”Body × π‘Ÿβƒ—dm
𝑉dm =
𝑄𝑧 − 𝑅𝑦 πš€Μ‚ + 𝑅π‘₯ − 𝑃𝑧 πš₯Μ‚ + 𝑃𝑦 − 𝑄π‘₯ π‘˜
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
Steps to Develop Aircraft Moment EOM
STEP β‘  : Starting with a small elemental mass dπ‘š of aircraft located at some distance from c.g. and rotating
with positive angular rates about c.g.;
π‘Ÿβƒ—dm = π‘₯πš€Μ‚ + 𝑦πš₯Μ‚ + π‘§π‘˜
STEP β‘‘ : Expressing the velocity of dπ‘š and accounting for its rotation around c.g.;
𝑉
=
π‘‘π‘Ÿβƒ—
+ πœ”Body × π‘Ÿβƒ—
𝑑𝑑 Body
𝑉
=
πœ”Body × π‘Ÿβƒ—
𝑉
=
𝑄𝑧 − 𝑅𝑦 πš€Μ‚ + 𝑅π‘₯ − 𝑃𝑧 πš₯Μ‚ + 𝑃𝑦 − 𝑄π‘₯ π‘˜
STEP β‘’ : Linear momentum of dπ‘š and accounting for its rotation around c.g.;
Linear Momentum =
=
Aircraft Equations of Motion
dπ‘šπ‘‰
dπ‘š 𝑄𝑧 − 𝑅𝑦 πš€Μ‚ + 𝑅π‘₯ − 𝑃𝑧 πš₯Μ‚ + 𝑃𝑦 − 𝑄π‘₯ π‘˜
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
STEP β‘£ : Angular momentum of dπ‘š;
d𝐻 = π‘Ÿβƒ—
d𝐻
d𝐻
d𝐻
=
πš€Μ‚
π‘₯
dπ‘š 𝑄𝑧 − 𝑅𝑦
d𝐻 = 𝑃 𝑦 + 𝑧
d𝐻 = 𝑄 π‘₯ + 𝑧
d𝐻 = 𝑅 π‘₯ + 𝑦
× dπ‘šπ‘‰
πš₯Μ‚
𝑦
dπ‘š 𝑅π‘₯ − 𝑃𝑧
π‘˜
𝑧
dπ‘š 𝑃𝑦 − 𝑄π‘₯
dπ‘š − 𝑄π‘₯𝑦 dπ‘š − 𝑅π‘₯𝑧 dπ‘š
dπ‘š − 𝑅𝑦𝑧 dπ‘š − 𝑃π‘₯𝑦 dπ‘š
dπ‘š − 𝑃π‘₯𝑧 dπ‘š − 𝑄𝑦𝑧 dπ‘š
STEP β‘€ : Integrating;
d𝐻 = 𝑃
𝑦 +𝑧
dπ‘š − 𝑄
π‘₯𝑦 dπ‘š − 𝑅
π‘₯𝑧 dπ‘š
d𝐻 = 𝑄
π‘₯ +𝑧
dπ‘š − 𝑅
𝑦𝑧 dπ‘š − 𝑃
π‘₯𝑦 dπ‘š
d𝐻 = 𝑅
Aircraft Equations of Motion
π‘₯ +𝑦
dπ‘š − 𝑃
π‘₯𝑧 dπ‘š − 𝑄
AE-426 Flight Dynamics --- 201
𝑦𝑧 dπ‘š
Moments of Inertia
𝐼
𝐼
𝐼
Products of Inertia
𝐼
𝐼
𝐼
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
Integrating;
𝐻 = 𝑃𝐼 − 𝑄𝐼 − 𝑅𝐼
𝐻 = 𝑄𝐼 − 𝑅𝐼 − 𝑃𝐼
𝐻 = 𝑅𝐼 − 𝑃𝐼 − 𝑄𝐼
The same can be obtained applying basic physics using, 𝐻 = πΌβƒ—πœ”. If aircraft has an xz plane
of symmetry, then
𝐻 = 𝑃𝐼 − 𝑅𝐼
𝐻 = 𝑄𝐼
𝐻 = 𝑅𝐼 − 𝑃𝐼
𝐻 = 𝑃𝐼
Aircraft Equations of Motion
− 𝑅𝐼
πš€Μ‚ + 𝑄𝐼
πš₯Μ‚ + 𝑅𝐼 − 𝑃𝐼
AE-426 Flight Dynamics --- 201
π‘˜
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
STEP β‘₯ : Taking the time rate of angular momentum vector 𝐻 = 𝑃𝐼 − 𝑅𝐼
𝑑𝐻
𝑑𝑑
=
𝑑𝐻
𝑑𝑑
+πœ”
πš€Μ‚ + 𝑄𝐼
πš₯Μ‚ + 𝑅𝐼 − 𝑃𝐼
π‘˜;
×𝐻
Where,
𝑃̇𝐼
− 𝑅̇ 𝐼
𝑄̇ 𝐼
=
𝑅̇𝐼 − 𝑃̇𝐼
𝑑𝐻
𝑑𝑑
+ 𝑃𝐼 Μ‡ − 𝑅𝐼 Μ‡
+ 𝑄𝐼 Μ‡
+ 𝑅𝐼 Μ‡ − 𝑃𝐼 Μ‡
Since aircraft mass distribution is constant,
𝑑𝐻
𝑑𝑑
𝑃̇𝐼
− 𝑅̇ 𝐼
𝑄̇ 𝐼
=
𝑅̇ 𝐼 − 𝑃̇𝐼
Combining all,
𝑑𝐻
𝑑𝑑
𝑃̇𝐼
− 𝑅̇ 𝐼
𝑄̇ 𝐼
=
𝑅̇𝐼 − 𝑃̇𝐼
Aircraft Equations of Motion
+
𝑃𝐼
πš€Μ‚
𝑃
− 𝑅𝐼
πš₯Μ‚
𝑄
𝑄𝐼
π‘˜
𝑅
𝑅𝐼 − 𝑃𝐼
AE-426 Flight Dynamics --- 201
𝑃̇𝐼 + 𝑄𝑅 𝐼 − 𝐼
⟹ 𝑄̇ 𝐼 − 𝑃𝑅 𝐼 − 𝐼
𝑅̇ 𝐼 + 𝑃𝑄 𝐼 − 𝐼
− 𝑅̇ + 𝑃𝑄 𝐼
+ 𝑃 −𝑅 𝐼
+ 𝑄𝑅 − 𝑃̇ 𝐼
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Aircraft Equations of Motion
-Aircraft Moment Equation (Cont)
STEP ⑦ : The three moment equations in the body axis are found from:
𝑑𝐻
𝑑𝑑
=𝑀
Where,
𝑀
𝐿
= 𝑀
𝑁
𝐿
𝑀
𝑁
=
rolling moment
= pitching moment
yawing moment
𝐿
+ 𝑀
𝑁
Since aircraft mass distribution is constant,
𝑃̇𝐼
𝑄̇ 𝐼
+
𝑄𝑅 𝐼 − 𝐼
−
𝑅̇ + 𝑃𝑄 𝐼
=
𝐿
−
𝑃𝑅 𝐼 − 𝐼
+
=
𝑀
𝑅̇ 𝐼
+
𝑃𝑄 𝐼
+
𝑃 −𝑅 𝐼
𝑄𝑅 − 𝑃̇ 𝐼
=
𝑁
π‘Žπ‘›π‘”π‘’π‘™π‘Žπ‘Ÿ
π‘Žπ‘π‘π‘’π‘™π‘’π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘›
π‘‘π‘’π‘Ÿπ‘šπ‘ 
Aircraft Equations of Motion
−𝐼
π‘”π‘¦π‘Ÿπ‘œ
π‘π‘Ÿπ‘’π‘π‘’π‘ π‘ π‘–π‘œπ‘›
π‘‘π‘’π‘Ÿπ‘šπ‘ 
π‘π‘œπ‘’π‘π‘™π‘–π‘›π‘”
π‘‘π‘’π‘Ÿπ‘šπ‘ 
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft EOM’s
• Six differential EOM;
•
•
•
•
Dependent variables:
Independent variable:
Nonlinear ODE.
No closed-form analytical solution, only numerical methods.
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Aircraft EOM’s (Cont)
Longitudinal
EOM
EOM can
be
decoupled
π‘š π‘ˆΜ‡ + π‘„π‘Š − 𝑅𝑉 = −π‘šπ‘” sin Θ + −𝐷 cos 𝛼 + 𝐿 sin 𝛼 + 𝑇 cos Φ
𝑄̇𝐼 − 𝑃𝑅 𝐼 − 𝐼 + 𝑃 − 𝑅 𝐼 = 𝑀
π‘š π‘ŠΜ‡ + 𝑃𝑉 − π‘„π‘ˆ = π‘šπ‘” cos Φ cos Θ + −𝐷 sin 𝛼 − 𝐿 cos 𝛼 − 𝑇 sin Φ
𝑃̇ 𝐼
Lateral EOM
+ 𝑄𝑅 𝐼 − 𝐼
− 𝑅̇ + 𝑃𝑄 𝐼
=𝐿 +𝐿
π‘š 𝑉̇ + π‘…π‘ˆ − π‘ƒπ‘Š = π‘šπ‘” sin Φ cos Θ + 𝐹
𝑅̇ 𝐼 + 𝑃𝑄 𝐼
−𝐼
+ 𝑄𝑅 − 𝑃̇ 𝐼
+𝐹
=𝑁 +𝑁
• BENEFIT: easier to solve three EOM simultaneously for many flight conditions.
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Aircraft Kinematic EOM’s
• Additional Eqs are required with the 6 EOM to completely solve
aircraft motion, Why?
ο€­ Only 6 Eqs, with
ο€­ More than 6 unknowns:
• Are found by relating body axis system angular velocity rates (
to time rate of change of Euler angle “Euler rates” (
), How?
)
ο€­ Since the magnitude of the three body rate must equal the magnitude of
the three Euler rates;
ο€­ the following equality must satisfy:
Aircraft Equations of Motion
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Aircraft Equations of Motion
-Aircraft Kinematic EOM’s (Cont)
• Note this:
• For the above to be valid, both sides must be on the same axis
system.
• Euler rates vectors are found from the Euler rotation sequences
(Recall slide 9);
Aircraft Equations of Motion
AE-426 Flight Dynamics --- 201
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Aircraft Equations of Motion
-Aircraft Kinematic EOM’s (Cont)
• Rewrite in body axis system:
• Hence;
• Carrying out the mathematics;
or
Aircraft Equations of Motion
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examples
EX 4.1: given the following Euler angles and rates
EX 4.2: given the following Euler angles and rates
Ψ = 0 𝑑𝑒𝑔, ΨΜ‡ = 10
𝑑𝑒𝑔
Θ = 0 𝑑𝑒𝑔, ΘΜ‡ = 0
𝑠
𝑑𝑒𝑔
Φ = 90 𝑑𝑒𝑔, ΦΜ‡ = 0
𝑠
Ψ = 0 𝑑𝑒𝑔, ΨΜ‡ = 0
The roll, pitch, and yaw rates are
The roll, pitch, and yaw rates are
𝑃=0
, 𝑄 = 10
𝑑𝑒𝑔
𝑠
𝑑𝑒𝑔
Φ = 90 𝑑𝑒𝑔, ΦΜ‡ = 0
𝑠
Θ = 0 𝑑𝑒𝑔, ΘΜ‡ = 20
,𝑅 =0
𝑃=0
a 10 deg/s Euler yaw rate ΨΜ‡ is felt by the pilot as
10 deg/s pitch rate Q
Aircraft Equations of Motion
,𝑄 = 0
, 𝑅 = −20
a 20 deg/s Euler pitch rate ΘΜ‡ is felt by the pilot as
-20 deg/s yaw rate R
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