Uploaded by bowman38305

ENGR 315 Enginering Analysis aka Differential Equations Exam 1 Equation Sheet

advertisement
Separable:
𝑑𝑦 𝑓 (π‘₯ )
=
𝑑π‘₯ 𝑔(𝑦)
∫ 𝑔(𝑦)𝑑𝑦 = ∫ 𝑓(π‘₯)𝑑π‘₯
Homogenous:
𝑦 = 𝑒π‘₯
x = uy
Exact:
𝑀(π‘₯, 𝑦)𝑑π‘₯ + 𝑁(π‘₯, 𝑦)𝑑𝑦 = 0
𝑒 = ∫ 𝑀𝑑π‘₯ + π‘˜(𝑦) = ∫ 𝑁𝑑𝑦 + 𝑙(π‘₯)
If NOT Exact:
𝑃(π‘₯, 𝑦)𝑑π‘₯ + 𝑄(π‘₯, 𝑦)𝑑𝑦 = 0
1
𝑅(π‘₯) = (𝑃𝑦 − 𝑄π‘₯ )
𝑄
πΌπ‘›π‘‘π‘’π‘”π‘Ÿπ‘Žπ‘‘π‘–π‘›π‘” πΉπ‘Žπ‘π‘‘π‘œπ‘Ÿ = 𝐹(π‘₯) = 𝑒π‘₯𝑝 ∫ 𝑅 (π‘₯ )𝑑π‘₯
1
1
𝑅 (𝑦) = − (𝑃𝑦 − 𝑄π‘₯ ) = (𝑄π‘₯ − 𝑃𝑦 )
𝑃
𝑃
πΌπ‘›π‘‘π‘’π‘”π‘Ÿπ‘Žπ‘‘π‘–π‘›π‘” πΉπ‘Žπ‘π‘‘π‘œπ‘Ÿ = 𝐹(𝑦) = 𝑒π‘₯𝑝 ∫ 𝑅 (𝑦)𝑑𝑦
Linear First Order:
𝑦 ′ + 𝑝(π‘₯)𝑦 = π‘Ÿ(π‘₯)
𝑦 = 𝑒 −β„Ž(π‘₯) [∫ 𝑒 β„Ž(π‘₯) π‘Ÿ(π‘₯ )𝑑π‘₯ + 𝑐],
Bernoulli:
𝑦 ′ + 𝑝(π‘₯)𝑦 = 𝑔(π‘₯)𝑦 π‘Ž ,
β„Ž(π‘₯) = ∫ 𝑝(π‘₯ )𝑑π‘₯
𝑒 = 𝑦1−π‘Ž
Download