Uploaded by dragonslayermvp37

hw1t++1.5+average+rate+of+change

advertisement
••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••
:
: W1 - 1.5 Average Rates of Change
•
•
: MHF4U
s
:. :!� .e�• • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • • ::?��½"::"1 �� �- • • • • • • • • • �
'1
J Calculate the average rate of change for the function g(x)
b) 2
a) 2 S XS 4
-
::I
sx s3
s -7.
-:.
--
-;J:J___--,
-- lS
s x s 2.25
flt\-:
j (l. '7
� ). s - ').__
-
- � Cl)
Iv\:: jl;1..,01) - � C;i)
-
-:. ?ct('-(-,
o."'J..5
o'- \
ll._
,-
( \o
-7
f) 2 S XS 2.01
J..,, -)._
(0-7
11°�
-: l3
e) 2 S XS 2.1
M-:. ��,d--S)--jC½
:l.,-S -')..,
05
l
°\
-
M-=- �(ds_,5)-jC:2.-L
3 .. �
�
d) 2
c) 2 S XS 2.5
fV\-;. jC,)- �(�)
M-=. �(�)-:'.)(�)
�
4<L
=- �
= 4x 2 - Sx + 1 over each interval.
2.01 .. ;)...
7o ll ta 4
o.o
L(
I
-7
(f,.o'-(
2) An emergency flare is shot into the air. Its height, in meters, above the ground at various times in its flight is
given in the following table:
0.0
Time (s)
Height (m)
2.00
0.5
15.75
1.0
27.00
2.5
2.0
1.5
45.75
42.00
35.75
3.0
47.00
Determine the average rate of change in the height of the flare during each interval
a) 1.0
st s 2.0
N\:. n l;).
JV\-::..
M :::.
b) 3.0
1 -�c \)
�- \
<tJ... - J.--7
-1
15
st s 4.0
N\ -:
V\C41 - lti)
t{ - )
- 4� - '-17
i
M/S
--- -5 'V\/S
3.5
45.75
4.0
42.00
Download