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Assignment #2
Hydrostatic Pressure Due: December 25
Name: Ali kamel abdul-ameer
Include additional worksheets with calculations for partial credits in the event your final answer is not correct.
1 Calculate the hydrostatic pressure at the bottom of the fluid column for each case shown.
12 the
Calculate
the equivalent
A well has
following
profile: density at 7000' depth of the following mixed fluid column.
Gravel
Sp. gr = 2.68
Porosity 25%
5720
Casing
5720
5720
Total depth 16,400' (vertical well)
16'' Open Hole, Surface casing 13 3/8" OD and 12 3/7" ID of 68.00 lb/ft set at 2000'. 12.5'' Open Hole,
Intermediate Casing 9 5/8"OD and ID of 8 2/3", 47 lb/ft, set at 8,458' .8.5'' Open Hole, Drilling liner 7" (6" ID)
(Grade N-80) interval between 8,400' to 14,200' Open Hole, Bit diameter 5.5"
Drill string:
5" drill pipe 19.50 lb/ft nominal weight, (4.276" ID) surface to 8300'.
3 1/2'' drill pipe 13.30 lb/ft nominal weight between 8,300' to 15,200'.
(For the ID on the 3 1/2" drill pipe remember that density of steel is 65.5 lb/gal)
Drill collars, 4 3/4" OD, x 2 1/4" ID, 46.70 ppf, 15200' to TD.
Surface mud system:
3 mud tanks, each 9' high, 7' wide, 36' long.
With the entire drill string out of the hole:
Mud level in tanks No. 1 & 2 is 72" of mud and tank No. 3 has 60" of mud (M.W: 11 ppg) For the following
2
𝑽𝑽𝑻𝑻𝑻𝑻𝑻𝑻𝑻𝑻
3
Calculate the total capacity of the surface mud system in bbl.
πŸ•πŸ• × πŸ—πŸ— × πŸ‘πŸ‘πŸ‘πŸ‘
= πŸ‘πŸ‘ ×
= 𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ•πŸ•πŸ•πŸ• 𝒃𝒃𝒃𝒃𝒃𝒃
πŸ“πŸ“. πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”
Calculate total mud volume in the three tanks in bbls.
questions 2 to 9, do calculation by hand using equations from the lectures.
πŸ•πŸ•πŸ•πŸ•
×πŸ•πŸ•×πŸ‘πŸ‘πŸ‘πŸ‘
πŸ”πŸ”πŸ”πŸ”
×πŸ•πŸ•×πŸ‘πŸ‘πŸ‘πŸ‘
π‘½π‘½π’Žπ’Žπ’Žπ’Žπ’Žπ’Ž = 𝟐𝟐 οΏ½πŸπŸπŸπŸπŸ“πŸ“.πŸ”πŸ”πŸ”πŸ”πŸ”πŸ” οΏ½ + οΏ½πŸπŸπŸπŸπŸ“πŸ“.πŸ”πŸ”πŸ”πŸ”πŸ”πŸ” οΏ½ = πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•. πŸ—πŸ—πŸ—πŸ— 𝒃𝒃𝒃𝒃𝒃𝒃
4
Calculate the capacity in bbl/ft for each well section.
(𝟏𝟏𝟏𝟏. πŸ’πŸ’πŸπŸπŸ–πŸ–)𝟐𝟐
𝒃𝒃𝒃𝒃𝒃𝒃
𝑽𝑽𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺(𝟏𝟏) =
= 𝟎𝟎. 𝟏𝟏𝟏𝟏
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝒇𝒇𝒇𝒇
(πŸ–πŸ–. πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”)𝟐𝟐
𝒃𝒃𝒃𝒃𝒃𝒃
𝑽𝑽𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺(𝟐𝟐) =
= 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎𝟎𝟎
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝒇𝒇𝒇𝒇
(πŸ”πŸ”)𝟐𝟐
𝒃𝒃𝒃𝒃𝒃𝒃
𝑽𝑽𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺𝑺(πŸ‘πŸ‘) =
= 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎𝟎𝟎
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝒇𝒇𝒇𝒇
5
Calculate total hole volume with the entire drill string out of the hole.
οΏ½πŸ–πŸ–. πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”πŸ”πŸπŸ × (πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–)οΏ½ + οΏ½πŸ”πŸ”πŸπŸ × (𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏 − πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–)οΏ½ + (πŸ“πŸ“. πŸ“πŸ“πŸπŸ × (𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏 − 𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏))
𝑽𝑽𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉 =
= πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–. πŸ‘πŸ‘πŸ‘πŸ‘ 𝒃𝒃𝒃𝒃𝒃𝒃
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
6
Calculate the displacement of the "5 drill pipe.
πŸ“πŸ“πŸπŸ − πŸ’πŸ’. 𝟐𝟐𝟐𝟐𝟐𝟐𝟐𝟐
𝒃𝒃𝒃𝒃𝒃𝒃
𝑽𝑽𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅 =
× πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ– = 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎𝟎𝟎𝟎𝟎
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝒇𝒇𝒇𝒇
7
Calculate the displacement of the complete drill string.
𝑽𝑽𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅−𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔 =
[𝟐𝟐𝟐𝟐 − (πŸ’πŸ’. 𝟐𝟐𝟐𝟐𝟐𝟐)𝟐𝟐 ]πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ– + [(πŸ’πŸ’. 𝟐𝟐𝟐𝟐𝟐𝟐)𝟐𝟐 − (πŸ‘πŸ‘. πŸ“πŸ“)𝟐𝟐 ](𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏 − πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–) + [(πŸ’πŸ’. πŸ•πŸ•πŸ•πŸ•)𝟐𝟐 − (𝟐𝟐. 𝟐𝟐𝟐𝟐)𝟐𝟐 ](𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏 − 𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏)
= 𝟏𝟏𝟏𝟏𝟏𝟏 𝒃𝒃𝒃𝒃𝒃𝒃
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
8
Calculate the total hole volume with the bit on the bottom.
𝑽𝑽𝑻𝑻𝑻𝑻𝑻𝑻𝑻𝑻𝑻𝑻 = 𝑽𝑽𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉 − 𝑽𝑽𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅−𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔𝒔 = πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–. πŸ‘πŸ‘πŸ‘πŸ‘ − 𝟏𝟏𝟏𝟏𝟏𝟏 = πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•. πŸ‘πŸ‘πŸ‘πŸ‘ 𝒃𝒃𝒃𝒃𝒃𝒃
9
Calculate the hydrostatic pressure at bottom of hole.
π‘·π‘·πŸπŸ = 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎 × ρ × π‘»π‘»π‘»π‘»π‘»π‘» = 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎 × πŸπŸπŸπŸ × πŸπŸπŸπŸπŸπŸπŸπŸπŸπŸ = πŸ—πŸ—πŸ—πŸ—πŸ—πŸ—πŸ—πŸ—. πŸ–πŸ– 𝒑𝒑𝒑𝒑𝒑𝒑
10 Calculate the pressure at the bottom of each well.
10 Calculate the pressure at the bottom of each well.
4258.8 psi
4212 psi
11 Given the following well design:
735.243
psi
a)Calculate total hole volume with the entire drill string in the hole.
𝑽𝑽𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉 =
(𝟏𝟏𝟏𝟏. πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘)𝟐𝟐
(πŸ•πŸ•)𝟐𝟐
(πŸ’πŸ’. πŸ“πŸ“)𝟐𝟐 − (πŸ‘πŸ‘. πŸ“πŸ“)𝟐𝟐
(πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ• − πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’) − (πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•) οΏ½
· πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’ +
οΏ½ = πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–. 𝟎𝟎𝟎𝟎 𝒃𝒃𝒃𝒃𝒃𝒃
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝑽𝑽𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉 =
(𝟏𝟏𝟏𝟏. πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘)𝟐𝟐
(πŸ•πŸ•)𝟐𝟐
(πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ• − πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’) = πŸ–πŸ–πŸ–πŸ–πŸ–πŸ–. πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’πŸ’
· πŸ’πŸ’πŸπŸπŸπŸπŸπŸ +
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏. πŸ’πŸ’
b)Calculate total hole volume with the entire drill string out of the hole.
CSG Specification: (13 3/8" CSG (12.5" ID) and 7" Liner (6" ID))
Drill Pipe Specification: (4.5" DP (3.5" ID))
12 Calculate the equivalent density at 7000' depth of the following mixed fluid column.
1200ft
2800ft
𝑻𝑻𝑻𝑻𝑻𝑻 𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉𝒉 𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑𝒑 𝒂𝒂𝒂𝒂 𝒕𝒕𝒕𝒕𝒕𝒕 𝒃𝒃𝒃𝒃𝒃𝒃𝒃𝒃𝒃𝒃𝒃𝒃 π’Šπ’Šπ’Šπ’Š ∢ −
𝑷𝑷𝒄𝒄 = 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎�(𝟏𝟏𝟏𝟏𝟏𝟏𝟏𝟏 × πŸ—πŸ—) + (𝟐𝟐𝟐𝟐𝟐𝟐𝟐𝟐 × πŸπŸπŸπŸ) + (πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘ × πŸπŸπŸπŸ)οΏ½
= πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘. πŸ”πŸ” 𝒑𝒑𝒑𝒑𝒑𝒑
𝑺𝑺𝑺𝑺 𝒕𝒕𝒕𝒕𝒕𝒕 𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆𝒆 𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅𝒅 ∢ −
ρ=
4500ft
𝑷𝑷π‘ͺπ‘ͺ
πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘πŸ‘. πŸ”πŸ”
=
= 𝟏𝟏𝟏𝟏. 𝟐𝟐𝟐𝟐𝟐𝟐 𝒑𝒑𝒑𝒑𝒑𝒑
𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎 × π‘»π‘»π‘»π‘»π‘»π‘» 𝟎𝟎. 𝟎𝟎𝟎𝟎𝟎𝟎 × πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•πŸ•
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