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Electromagnetic Fields and Waves (Module 2)

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ElECTROMAGNETIC
FIELDS AND WAVES
COORDINATE SYSTEMS
AND
TRANSFORMATION
(MODULE 2)
1
Module Learning Outcomes
• Define Electromagnetics (EM)
• Solve problems involving spherical
coordinates.
• Solve problems involving cylindrical
coordinates.
• Transform from one coordinate system to
another.
2
INTRODUCTION
• In general, the physical quantities we shall be
dealing with in EM are functions of space and time.
• In order to describe the spatial variations of the
quantities, we must be able to define all points
uniquely in space in a suitable manner.
• A point or vector can be represented in any
curvilinear coordinate system, which may be
orthogonal or non-orthogonal.
3
INTRODUCTION CONTINUED
• An orthogonal system is one in which the
coordinate surfaces are mutually perpendicular.
• Nonorthogonal systems are hard to work with, and
they are of little or no practical use.
• Examples of orthogonal coordinate systems include
the Cartesian (or rectangular), the circular
cylindrical, the spherical, the elliptic cylindrical,
the parabolic cylindrical, the conical, the prolate
spheroidal, the oblate spheroidal, and the
ellipsoidal.
4
Cartesian Coordinates (x, y, z)
A point P can be represented as (x, y, z) as illustrated in
figure 1.1. The ranges of the coordinate variables x, y, z are:
−∞ < π‘₯ < ∞
−∞ < 𝑦 < ∞
−∞ < 𝑧 < ∞
A vector A in Cartesian (otherwise known as rectangular)
coordinates can be written as:
(𝐴π‘₯, 𝐴𝑦 , 𝐴𝑧, ) or 𝐴π‘₯ 𝒂𝒙 + 𝐴𝑦 π’‚π’š + 𝐴𝑧 𝒂𝒛
5
Circular Cylindrical Coordinates (𝝆, πœ™, 𝒛)
A vector A in cylindrical coordinates can
be written as:
𝐴𝜌 , π΄πœ™ , 𝐴𝑧 𝒐𝒓 𝐴𝜌 𝒂𝝆 + π΄πœ™ π’‚πœ™ + 𝐴𝑧 𝒂𝒛
The variables ranges from:
Radial distance: 0 ≤ 𝜌 < ∞
Azimuthal angle: 0 ≤ πœ™ < 2πœ‹
Z-axis
: −∞ < 𝑧 < ∞
The magnitude of A is:
𝐴 = 𝑨𝝆 2 + π‘¨πœ™ 2 + 𝑨𝒛
1
2 2
6
Circular Cylindrical Coordinates (𝝆, πœ™, 𝒛)
𝒂𝝆 . 𝒂𝝆 = π’‚πœ™ . π’‚πœ™ = 𝒂𝒛 . 𝒂𝒛 = 𝟏
𝒂𝝆 . π’‚πœ™ = π’‚πœ™ . 𝒂𝒛 = 𝒂𝒛 . 𝒂𝝆 = 𝟎
𝒂𝝆 × π’‚πœ™ = 𝒂𝒛
π’‚πœ™ × π’‚π’› = 𝒂𝝆
𝒂𝒛 × π’‚π† = π’‚πœ™
7
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
Cartesian to Cylindrical
π‘₯2 + 𝑦2
𝑦
−1
∅ = π‘‘π‘Žπ‘›
π‘₯
𝑧=𝑧
𝜌=
• This is for point-to-point
transformation
8
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
Cylindrical to Cartesian
π‘₯ = πœŒπ‘π‘œπ‘ ∅
𝑦 = πœŒπ‘ π‘–π‘›∅
𝑧=𝑧
• This is for point-to-point
transformation
9
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
The
unit
vector
relationship between the
Cartesian
coordinate
system
and
the
Cylindrical
coordinate
system:
π‘Žπ‘₯ = πΆπ‘œπ‘ ∅π‘Žπ‘ − 𝑆𝑖𝑛∅π‘Ž∅
π‘Žπ‘¦ = 𝑆𝑖𝑛∅π‘Žπ‘ + πΆπ‘œπ‘ ∅π‘Ž∅
π‘Ž 𝑧 = π‘Žπ‘§
10
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
The
unit
vector
relationship between the
cylindrical
coordinate
system and the Cartesian
coordinate system:
π‘ŽπœŒ = πΆπ‘œπ‘ ∅π‘Žπ‘₯ + 𝑆𝑖𝑛∅π‘Žπ‘¦
π‘Ž∅ = −𝑆𝑖𝑛∅π‘Žπ‘₯ + πΆπ‘œπ‘ ∅π‘Žπ‘¦
π‘Ž 𝑧 = π‘Žπ‘§
11
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
In matrix form, we write the transformation of vector A
from 𝐴π‘₯ , 𝐴𝑦 , 𝐴𝑧 to 𝐴𝜌 , 𝐴∅ , 𝐴𝑧 as:
𝐴𝜌
πΆπ‘œπ‘ ∅ 𝑆𝑖𝑛∅ 0
𝐴∅ = −𝑆𝑖𝑛∅ πΆπ‘œπ‘ ∅ 0
0
0
1
𝐴𝑧
𝐴π‘₯
𝐴𝑦
𝐴𝑧
This equation is used for vector-to-vector
transformation.
12
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE CYLINDRICAL COORDINATE SYSTEM
In matrix form, we write the transformation of vector A
from 𝐴𝜌 , 𝐴∅ , 𝐴𝑧 to 𝐴π‘₯ , 𝐴𝑦 , 𝐴𝑧 as:
𝐴π‘₯ πΆπ‘œπ‘ ∅ −𝑆𝑖𝑛∅ 0
𝐴𝑦 = 𝑆𝑖𝑛∅ πΆπ‘œπ‘ ∅ 0
𝐴𝑧
0
0
1
𝐴𝜌
𝐴∅
𝐴𝑧
This equation is used for vector-to-vector
transformation.
13
SPHERICAL COORDINATES (r, 𝜽, ∅)
A vector A in spherical coordinates may
be written as:
π΄π‘Ÿ , π΄πœƒ , π΄πœ™ 𝒐𝒓 π΄π‘Ÿ 𝒂𝒓 + π΄πœƒ π’‚πœ½ + π΄πœ™ π’‚πœ™
The variables ranges from:
Radius of the Sphere: 0 ≤ π‘Ÿ < ∞
Colatitude:
0≤πœƒ≤πœ‹
Azimuthal angle:
0 ≤ πœ™ < 2πœ‹
The magnitude of A is:
𝐴 = 𝑨𝒓 2 + π‘¨πœ½ 2 + 𝑨∅
1
2 2
14
SPHERICAL COORDINATES (r, 𝜽, ∅)
𝒂𝒓 . 𝒂𝒓 = π’‚πœ½ . π’‚πœ½ = π’‚πœ™ . π’‚πœ™ = 𝟏
𝒂𝒓 . π’‚πœ½ = π’‚πœ½ . π’‚πœ™ = π’‚πœ™ . 𝒂𝒓 = 𝟎
𝒂𝒓 × π’‚πœ½ = π’‚πœ™
π’‚πœ½ × π’‚πœ™ = 𝒂𝒓
π’‚πœ™ × π’‚π’“ = π’‚πœ½
15
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
Cartesian to Spherical
π‘Ÿ=
π‘₯2 + 𝑦2 + 𝑧2
πœƒ = π‘‘π‘Žπ‘›−1
∅=
π‘₯2 + 𝑦2
𝑧
π‘‘π‘Žπ‘›−1
𝑦
π‘₯
These equations are used for
point-to-point transformation
16
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
Spherical to Cartesian
π‘₯ = π‘Ÿπ‘ π‘–π‘›πœƒπ‘π‘œπ‘ ∅
𝑦 = π‘Ÿπ‘ π‘–π‘›πœƒπ‘ π‘–π‘›∅
𝑧 = π‘Ÿπ‘π‘œπ‘ πœƒ
These equations are
used for point-to-point
transformation
17
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
The unit vector relationship between the
cartesian coordinate system and the
spherical coordinate system:
π‘Žπ‘₯ = π‘†π‘–π‘›πœƒπΆπ‘œπ‘ ∅π‘Žπ‘Ÿ + πΆπ‘œπ‘ πœƒπΆπ‘œπ‘ ∅π‘Žπœƒ − 𝑆𝑖𝑛∅π‘Ž∅
π‘Žπ‘¦ = π‘†π‘–π‘›πœƒπ‘†π‘–π‘›∅π‘Žπ‘Ÿ + πΆπ‘œπ‘ πœƒπ‘†π‘–π‘›∅π‘Žπœƒ + πΆπ‘œπ‘ ∅π‘Ž∅
π‘Žπ‘§ = πΆπ‘œπ‘ π‘Žπ‘Ÿ − π‘†π‘–π‘›πœƒπ‘Žπœƒ
18
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
The unit vector relationship between the
spherical coordinate system and the
Cartesian coordinate system:
π‘Žπ‘Ÿ = π‘†π‘–π‘›πœƒπΆπ‘œπ‘ ∅π‘Žπ‘₯ + π‘†π‘–π‘›πœƒπ‘†π‘–π‘›∅π‘Žπ‘¦ + πΆπ‘œπ‘ πœƒπ‘Žπ‘§
π‘Žπœƒ = πΆπ‘œπ‘ πœƒπΆπ‘œπ‘ ∅π‘Žπ‘₯ + πΆπ‘œπ‘ πœƒπ‘†π‘–π‘›∅π‘Žπ‘¦ − π‘†π‘–π‘›πœƒπ‘Žπ‘§
π‘Ž∅ = −𝑆𝑖𝑛∅π‘Žπ‘₯ + πΆπ‘œπ‘ ∅π‘Žπ‘¦
19
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
In matrix form, we write the transformation of vector A
from 𝐴π‘₯ , 𝐴𝑦 , 𝐴𝑧 to π΄π‘Ÿ , π΄πœƒ , 𝐴∅ as:
π΄π‘Ÿ
π‘†π‘–π‘›πœƒπΆπ‘œπ‘ ∅ π‘†π‘–π‘›πœƒπ‘†π‘–π‘›∅ πΆπ‘œπ‘ πœƒ
π΄πœƒ = πΆπ‘œπ‘ πœƒπΆπ‘œπ‘ ∅ πΆπ‘œπ‘ πœƒπ‘†π‘–π‘›∅ −π‘†π‘–π‘›πœƒ
𝐴∅
−𝑆𝑖𝑛∅
πΆπ‘œπ‘ ∅
0
𝐴π‘₯
𝐴𝑦
𝐴𝑧
This equation is used for vector-to-vector
transformation.
20
RELATIONSHIP BETWEEN THE CARTESIAN COORDINATE
SYSTEM AND THE SPHERICAL COORDINATE SYSTEM
In matrix form, we write the transformation of vector A
from π΄π‘Ÿ , π΄πœƒ , 𝐴∅ to 𝐴π‘₯ , 𝐴𝑦 , 𝐴𝑧 as:
𝐴π‘₯ π‘†π‘–π‘›πœƒπΆπ‘œπ‘ ∅ πΆπ‘œπ‘ πœƒπΆπ‘œπ‘ ∅ −𝑆𝑖𝑛∅
𝐴𝑦 = π‘†π‘–π‘›πœƒπ‘†π‘–π‘›∅ πΆπ‘œπ‘ πœƒπ‘†π‘–π‘›∅ πΆπ‘œπ‘ ∅
𝐴𝑧
πΆπ‘œπ‘ πœƒ
−π‘†π‘–π‘›πœƒ
0
π΄π‘Ÿ
π΄πœƒ
𝐴∅
This equation is used for vector-to-vector
transformation.
21
THE DISTANCE BETWEEN TWO POINTS IN THE THREE
COORDINATE SYSTEMS
• Cartesian
𝑑 2 = π‘₯2 − π‘₯1 2 − 𝑦2 − 𝑦1 2 + 𝑧2 − 𝑧1 2
• Cylindrical
𝑑 2 = 𝜌22 + 𝜌12 − 2𝜌1 𝜌2 πΆπ‘œπ‘  ∅2 − ∅1 + 𝑧2 − 𝑧1
• Spherical
2
𝑑 2 = π‘Ÿ22 + π‘Ÿ12 − 2π‘Ÿ1 π‘Ÿ2 πΆπ‘œπ‘ πœƒ2 πΆπ‘œπ‘ πœƒ1 − 2π‘Ÿ1 π‘Ÿ2 π‘†π‘–π‘›πœƒ2 π‘†π‘–π‘›πœƒ1 πΆπ‘œπ‘  ∅2 − ∅1
22
ASSIGNMENT
Obtain the point and vector transformation
relationship between cylindrical and
spherical coordinates (PROBLEM 2.16) on
Page 56 of Elements of Electromagnetics by
N.O. Sadiku (2018).
23
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