Kuta Software - Infinite Calculus Name___________________________________ Mean Value Theorem for Integrals Date________________ Period____ For each problem, find the average value of the function over the given interval. 1) f ( x) = − x 2 − 2 x + 5; [−4, 0] 2) f ( x) = − x 4 + 2 x 2 + 4; [−2, 1] f(x) −8 −6 −4 f(x) 8 8 6 6 4 4 2 2 −2 2 4 6 8 x −8 −6 −4 −2 2 −2 −2 −4 −4 −6 −6 −8 −8 4 6 8 x For each problem, find the values of c that satisfy the Mean Value Theorem for Integrals. 2 3 + x + ; [−3, 1] 2 2 x f ( x) = − 3) 4) f ( x) = 4 ; [−4, −2] x2 f(x) −8 −6 −4 f(x) 8 8 6 6 4 4 2 2 −2 2 4 6 8 x −8 −6 −4 −2 2 −2 −2 −4 −4 −6 −6 −8 −8 ©x t2x0t113b wKqu8t3aW pSZoOfHtAwranrRe5 dLoLjC6.p m 3AilYlZ br2iQglhutAsm crye3sNe6ruvNeDdU.l r YMha7daeV 7wRiftQh6 7IsnRfaidnYiCtjek bCnaNlvcNuul4uMsS.X -1- 4 6 8 x Worksheet by Kuta Software LLC For each problem, find the average value of the function over the given interval. 5) f ( x) = − x 3 + 7 x 2 − 11 x + 3; [1, 5] 6) f ( x) = − x 5 + 3 x 3 ; [0, 1] 8) f ( x) = x 5 − 2 x 3 + x; [−1, 0] 1 2 7) f ( x) = 4 x ; [0, 3] 9) 1 f ( x) = ; x 10) f ( x) = x 5 − 4 x 3 + 2 x − 1; [−2, 2] [2, 3] 11) f ( x) = − x 5 + 4 x 3 − 5 x − 3; [−2, 0] 12) f ( x) = x 5 − 2 x 3 − 2; [−1, 1] For each problem, find the average value of the function over the given interval. Then, find the values of c that satisfy the Mean Value Theorem for Integrals. 13) f ( x) = − x + 2; [−2, 2] 1 2 15) f ( x) = −3(2 x − 6) ; [3, 5] ©3 v2o0K123f qK0uQtpal CSmonfYtJwwaCrXey TLxLVCf.6 H RAClNlV nrXiqgIhztwsU 5rMemsZeirZvvesdD.6 z QMdaedwe3 rwtiytlhu MIQn1fVivnyintveN iC2aUlacSuElruysu.3 14) f ( x) = − x 2 − 8 x − 17; [−6, −3] 16) f ( x) = -2- 4 (2 x + 6) 2 ; [−6, −5] Worksheet by Kuta Software LLC Kuta Software - Infinite Calculus Name___________________________________ Mean Value Theorem for Integrals Date________________ Period____ For each problem, find the average value of the function over the given interval. 1) f ( x) = − x 2 − 2 x + 5; [−4, 0] 2) f ( x) = − x 4 + 2 x 2 + 4; [−2, 1] f(x) −8 −6 −4 f(x) 8 8 6 6 4 4 2 2 −2 2 4 6 8 x −8 −6 −4 −2 2 −2 −2 −4 −4 −6 −6 −8 −8 4 6 8 x 19 = 3.8 5 11 ≈ 3.667 3 For each problem, find the values of c that satisfy the Mean Value Theorem for Integrals. 2 3 + x + ; [−3, 1] 2 2 x f ( x) = − 3) 4) f ( x) = 4 ; [−4, −2] x2 f(x) −8 −6 −4 f(x) 8 8 6 6 4 4 2 2 −2 2 4 6 8 x −8 −6 −4 −2 2 −2 −2 −4 −4 −6 −6 −8 −8 6 8 x −2 2 ≈ −2.828 3−4 3 ≈ −1.309 3 ©1 32J0w1S3O DK6u9t0aq WSPoLfvtkw2a3r9eU 5LKLNCU.g v PAylQlI MraivgAhEt8s3 trHefsceJrmvpegdT.B I UMLaxd7eH QwUirtwhg uIZn3fmiKnNiltYez SCfaelfc6uQlmuRsV.o 4 -1- Worksheet by Kuta Software LLC For each problem, find the average value of the function over the given interval. 5) f ( x) = − x 3 + 7 x 2 − 11 x + 3; [1, 5] 6) f ( x) = − x 5 + 3 x 3 ; [0, 1] 10 ≈ 3.333 3 7 ≈ 0.583 12 8) f ( x) = x 5 − 2 x 3 + x; [−1, 0] 1 2 7) f ( x) = 4 x ; [0, 3] − 8 3 ≈ 4.619 3 9) 1 f ( x) = ; x 1 ≈ −0.167 6 10) f ( x) = x 5 − 4 x 3 + 2 x − 1; [−2, 2] [2, 3] −1 ln 3 − ln 2 ≈ 0.405 11) f ( x) = − x 5 + 4 x 3 − 5 x − 3; [−2, 0] − 12) f ( x) = x 5 − 2 x 3 − 2; [−1, 1] −2 2 ≈ −0.667 3 For each problem, find the average value of the function over the given interval. Then, find the values of c that satisfy the Mean Value Theorem for Integrals. 13) f ( x) = − x + 2; [−2, 2] 14) f ( x) = − x 2 − 8 x − 17; [−6, −3] Average value of function: 2 Values that satisfy MVT: 0 1 2 15) f ( x) = −3(2 x − 6) ; [3, 5] Average value of function: −2 Values that satisfy MVT: −5, −3 16) f ( x) = Average value of function: −4 35 Values that satisfy MVT: ≈ 3.889 9 4 (2 x + 6) 2 ; [−6, −5] 1 ≈ 0.167 6 Values that satisfy MVT: −3 − 6 ≈ −5.449 Average value of function: Create your own worksheets like this one with Infinite Calculus. Free trial available at KutaSoftware.com ©s q2C0Y1o3w OKCuJtgaY WSoo1fYtJwFa0rfea wLMLAC5.W q aALl6lS MrpitgqhMtwsK QrnehsQe7r9vyeUdE.G 8 4MlaKdpe2 YweiLtChc lInndffiYnziMtIeo 8CbaGlmcEuTlxuzsd.N -2- Worksheet by Kuta Software LLC