Search EN What is Scribd? Ebooks Audiobooks Magazines Podcasts Sheet Music Upload Documents Read free for 30 days Snapshots Documents Teaching Methods & Materials Mathematics 0 ratings · 835 views · 4 pages You might also like Calculus Cheat Sheet Derivatives Uploaded by Juan Carlos Betancur on Aug 31, 2013 Worked Examples in Mathematics for Scientists and Engineers Full description G. Stephenson Save 0% 0% Embed Share Print Download now of 4 1 Search document Libro Fisica I-Roberto Portillo deosx Calculus Cheat Sheet Derivatives Definition and Notation f ( x + h) - f ( x) If y = f ( x ) then the derivative is defined to be f ¢ ( x ) = lim . h ®0 h If y = f ( x ) then all of the following are Di erentiation (Calculus) Mathematics Question Bank = f ( x ) all of the following are equivalent notations for derivative evaluated at = a . If equivalent notations for the derivative. df dy d f ¢ ( x ) = y¢ = = = ( f ( x ) ) = Df ( x ) dx dx dx f ¢ ( a ) = y¢ x =a = df = dx x =a dy dx Mohmmad Khaja Shareef = Df ( a ) x =a Interpretation of the Derivative 2. f ¢ ( a ) is the instantaneous rate of If y = f ( x ) then, 1. m = f ¢ ( a ) is the slope of the tangent change of f ( x ) at x = a . line to y = f ( x ) at 3. If f ( x ) is the position of an object at = a and the equation of the tangent line at x = a is time x then f ¢ ( a ) is the velocity of This website stores data such as cookies to enable essential site functionality, as well as marketing, personalization, and analytics. Privacy Policy given by = f ( a ) + f ¢ ( a )( x - a ) . the object at x = a . Maxima And Minima Derivative Mathematical Analysis Calculus Basic Properties and Formulas ( x ) are differentiable functions (the derivative exists), c and n are any real numbers, 1. ( c f )¢ = c f ¢ ( x ) 5. 2. ( f ± g )¢ = f ¢ ( x ) ± g ¢ ( x ) 6. 3. ( f g )¢ = f ¢ g + d dx d kuliah1_2015.ppt x ) = n x - – Power Rule ( dx f g ¢ – Product Rule n n 1 wira d ( f ( g ( x ) ) ) = f ¢ ( g ( x ) ) g¢ ( x ) dx This is the Chain Rule 7. æ f ö¢ f ¢ g - f g ¢ Related 4. titles – Quotient Rule çg÷ = 2 g è ø (c) = 0 If f ( x ) and Common Derivatives d dx d dx d dx d dx d dx d ( x) = 1 dx d ( sin x ) = cos x dx d a x ) = a x ln ( a ) ( dx ( cot ) = - csc2 x d d ( tan ) = sec2 x 1 -1 1- x 1 ( sec x ) = sec x tan x d ( tan dx -1 x) = d ( ln ( x ) ) = dx d 2 ( cos x ) = - dx x x e )=e ( dx 1 sin - x ) = ( dx ( cos x ) = - sin x d ( csc x ) = - csc x cot x 1 x , x>0 1 ( ln x ) = x , dx 1 - x2 d 1 ( log a ( x ) ) = dx 1 + x2 Major Revision Facts in Mathematics B. N. Kumar x¹0 1 x ln a , x>0 Partial Derivatives © 2005 Paul Dawkins Visit http://tutorial.math.lamar.edu for a complete set of Calculus notes. Aien Nurul Ain Calculus Cheat Sheet Chain Rule Variants The chain rule applied to some specific functions. n n -1 d d 1. éë f ( x ) ùû = n éë f ( x ) ùû f ¢ ( x ) 5. cos éë f ( x )ùû = - f ¢ ( x ) sin éë f ( x ) ùû dx dx d d ( x) 2. e = f ¢ ( x ) e f ( x) 6. tan éë f ( x ) ùû = f ¢ ( x ) sec 2 éë f ( x ) ùû dx dx d f ¢( x) d 7. ( sec [ f ( x)]) = f ¢( x) sec [ f ( x)] tan [ f ( x)] 3. ln éë f ( x ) ùû = dx dx f ( x) f ¢( x) d -1 d 8. tan é f x ù = ( ) ¢ 2 4. sin éë f ( x ) ùû = f ( x ) cos éë f ( x ) ùû ë û dx 1 + ëé f ( x )ùû dx ) ( ( ) ( ( ) ( ) ) ( ( ) d2 f dx 2 and is defined as f ¢¢ ( x ) = ( f ¢ ( x ) )¢ , i.e. the derivative of the first derivative, f ¢ ( x ) . f ( n) f ( n) Andrew Igla ) Higher Order Derivatives th The Second Derivative is denoted as The n Derivative is denoted as ( 2) f ¢¢ ( x ) = f ( x ) = Mathematics 1St First Order Linear Di erential Equations 2Nd Second… ( x) = dn f dx n AP Calculus Cheat Sheet 3d5w2d and is defined as ¢ ( x ) = ( f ( n-1) ( x ) ) , i.e. the derivative of st (n-1) derivative, f ( ) ( x ) . You're Readingthe a Preview n -1 Implicit Differentiation ¢ if e Find 2 x -9 y + 3 y 2 Upload your documents to download. = sin ( y ) + 11x . Remember y = y ( x ) here, so products/quotients of x and y will use the product/quotient rule and derivatives of y will use the chain rule. The “trick” is to OR differentiate as normal and every time you differentiate a y you tack on a y¢ (from the chain rule). After differentiating solve for ¢ . Become a Scribd member for full access. Your ¢ + 11 are free. cos (30 y ) ydays e 2 x -9 y ( 2 - 9 y¢ ) + 3x 2 y 2 + 2 x3 y y¢ =first 2e 2 x -9 y (2x 3 - 9 y¢e 2 x -9 y + 3x y + 2 x y y¢ = cos ( y ) y¢ + 11 2 2 Þ 3 y¢ = 2 x -9 y 2 y - 9e2 x -9 y - cos ( y ) ) y¢ = 11 - 2Continue e - 3x2 yfor Free 11 - 2e 2 x -9 y - 3x 2 y 2 2 3 y - 9e2 x -9 y - cos ( y ) A-level Maths Revision (Cheeky Revision Shortcuts) Scool Revision Increasing/Decreasing – Concave Up/Concave Down Critical Points x = c is a critical point of f ( x ) provided either Concave Up/Concave Down 1. If f ¢¢ ( x ) > 0 for all x in an interval I then 1. f ¢ ( c ) = 0 or 2. f ¢ ( c ) doesn’t exist. fulltext.pdf మ f ( x ) is concave up on the interval I. చం ద ఖ 2. If f ¢¢ ( x ) < 0 for all x in an interval I then Increasing/Decreasing 1. If f ¢ ( x ) > 0 for all x in an interval I then f ( x ) is concave down on the interval I. f ( x ) is increasing on the interval I. 2. If f ¢ ( x ) < 0 for all x in an interval I then Inflection Points x = c is a inflection point of f ( x ) if the f ( x ) is decreasing on the interval I. = c. concavity changes at 3. If f ¢ ( x ) = 0 for all x in an interval I then f ( x ) is constant on the interval I. © 2005 Paul Dawkins Visit http://tutorial.math.lamar.edu for a complete set of Calculus notes. Calculus Equations And Answers (Speedy Study Guides) Speedy Publishing You're reading a preview Unlock full access (page 3) by uploading documents or with a 30 Day Free Trial Cebu - FB 14 Math Kei Dee Continue for Free Calculus Cheat Sheet Related Rates Sketch picture and identify known/unknown quantities. Write down equation relating quantities and differentiate with respect to t using implicit differentiation (i.e. add on a derivative every time you differentiate a function of t). Plug in known quantities and solve for the unknown quantity. Ex. A 15 foot ladder is resting against a wall. Ex. Two people are 50 ft apart when one The bottom is initially 10 ft away and is being starts walking north. The angleq changes at 1 0.01 rad/min. At what rate is the distance pushed towards the wall at 4 ft/sec. How fast between them changing when q = 0.5 rad? is the top moving after 12 sec? We have q ¢ = 0.01 rad/min. and want to find x¢ . We can use various trig fcns but easiest is, x¢ sec q = Þ secq tan q q ¢ = 50 50 We know q = 0.05 so plug in q ¢ and solve. x¢ sec ( 0.5 ) tan ( 0.5 )( 0.01) = 50 x¢ = 0.3112 ft/sec Remember to have calculator in radians! x¢ is negative because x is decreasing. Using Pythagorean Theorem and differentiating, x 2 + y 2 = 152 Þ 2 x x¢ + 2 y y¢ = 0 After 12 sec we have x = 10 - 12 ( 14 ) = 7 and so y = 152 - 72 = 176 . Plug in and solve for ¢ . Real Analysis and Probability: Solutions to Problems Robert P. Ash CNS-GEAS 5 [] Achilles Aldave You're Reading a Preview 7 ( - 14 ) + 176 y¢ = 0 Þ y¢ = 7 ft/sec Upload 4 176your documents to download. Optimization Sketch picture if needed, write down equation toOR be optimized and constraint. Solve constraint for one of the two variables and plug into first equation. Find critical points of equation in range of variables and verify that they areamin/max needed. for full access. Your Become Scribd as member Ex. We’re enclosing a rectangular field with Ex. Determine point(s) on y = x 2 + 1 that are free. 500 ft of fence material and one side first of the30 days are closest to (0,2). field is a building. Determine dimensions that will maximize the enclosed area. Shortcuts to College Calculus Refreshment Kit Juan Acevedo Continue for Free 2 2 Minimize f = d 2 = ( x - 0 ) + ( y - 2 ) and the Maximize A = xy subject to constraint of x + 2 y = 500 . Solve constraint for x and plug into area. A = y ( 500 - 2 y ) x = 500 - 2 y Þ = 500 - 2 y 2 Differentiate and find critical point(s). A¢ = 500 - 4 y Þ y = 125 nd By 2 deriv. test this is a rel. max. and so is the answer we’re after. Finally, find x. x = 500 - 2 (125) = 250 constraint is y = x 2 + 1 . Solve constraint for x 2 and plug into the function. x2 = y - 1 Þ f = x2 + ( y - 2) exam Maria Deborah Vivas Baluran 2 2 = y -1 + ( y - 2) = y2 - 3 y + 3 Differentiate and find critical point(s). f ¢ = 2y - 3 Þ y = 32 nd By the 2 derivative test this is a rel. min. and so all we need to do is find x value(s). x 2 = 32 - 1 = 12 Þ x = ± 12 The dimensions are then 250 x 125. The 2 points are then ( 1 2 ) ( , 32 and - 1 2 , 32 ) © 2005 Paul Dawkins Visit http://tutorial.math.lamar.edu for a complete set of Calculus notes. Geometric functions in computer aided geometric design Oscar Ruiz Reward Your Curiosity Everything you want to read. Anytime. Anywhere. Any device. SOR Vol1 Print mohsinciviljmi Read free for 30 days No Commitment. Cancel anytime. Factoring and Algebra - A Selection of Classic Mathematical Articles… Share this document CSPacademic Einstein's Relativity: A Bureau 42 Primer (Version A: Full Math) W. 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