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GE 4 - Assignment No.3 (Scratch)

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1 1  ( 5) 29 1  ( 5) 29
((
) (
) )
2
2
5
1
1  2.23606799775 29 1  2.23606799775 29
F29 
(
) (
)
2.23606799775
2
2
3.23606799775 29  1.23606799775 29
F29  .447213595(
) (
)
2
2
F29  .447213595((1.61803399) 29  (.618033989) 29 )
F29 
F29  .447213595((1.61803399) 29  (.618033989) 29 )
F29  (.447213595)((1,149,851.02576399)  (8.6967790760274))
F29  (.447213595)(1,149,851.02576486)
F29  514,229.01094674
F29  514,229
F
The Sublime Triangle or Golden Triangle is an Isosceles Triangle.
Its ratio, specifical ly from the side of ' a' to base ' b' is equivalent
a
 .
b
Now, providing the given figure, the vertex angle will be solved as :
b
  2 sin 1 ( )
2a
1
  2 sin 1 (
)
2( )
1

5( )
to the Golden Ratio which is 1.618. So,
  36
1 1  5 30 1  5 30
((
) (
) )
2
2
5
1
1  2.23606799775 30 1  2.23606799775 30
F30 
((
) (
) )
2.23606799775
2
2
3.23606799775 30  1.23606799775 30
F30  .447213595((
) (
) )
2
2
F30  .447213595((1.6180339930  (.618033089) 30 )
F30 
F30  (.447213595)((1860498.0431225)  (5.37467025573202))
F30  (.447213595)(1860498.04312196)
F30  832,040.018355037
F30  832,040
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