Adding consecutive numbers
We can put what Gauss discovered into an easy-to-use formula, which is:
(n / 2)(first number + last number) = sum, where n is the number of integers.
Let's use the example of adding the numbers 1-100 to see how the formula works.
Find the sum of the consecutive numbers 1-100:
(100 / 2)(1 + 100)
50(101) = 5,050
Add consecutive even numbers
N(n+1)
N = no. of integers in series
Add consecutive odd numbers
NxN
N = no. of integers in series