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quadratic equations

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Mrs. Evany B. Colobong
At the end of the session, the
students should be able to:
a. Write a quadratic equation in standard
form;
b. Identify quadratic equations; and
c. Appreciate the importance of quadratic
equations.
ο‚žProduct of
π‘š
𝑛
Powers
π‘Ž βˆ™ π‘Ž = π‘Žπ‘š+𝑛
ο‚žPowers of
π‘š
ο‚žQuotient
π‘š
ο‚žPowers
of Powers
π‘Žπ‘
Product
= π‘Žπ‘š π‘π‘š
of Quotient
𝑛
𝑛
π‘Ž
π‘Ž
π‘Ž
π‘š−𝑛
=
π‘Ž
= 𝑛
𝑛
π‘Ž
𝑏
𝑏
ο‚žPower of Powers
π‘š 𝑛
π‘šπ‘›
(π‘Ž ) = π‘Ž
Simplify the following.
1.
2.
3.
4.
5.
4
6
βˆ™π‘₯
2 3
π‘₯
=
4 5
3π‘Ž 𝑏 βˆ™ 4π‘Ž 𝑏 =
3
2
π‘š 𝑛
=
π‘šπ‘›
2 5
π‘Ž 𝑏 =
2
3
3π‘₯ 𝑦
𝑧5
3
=
Solve for the product of the
following.
1.
2.
3.
4.
5.
2
3(π‘₯ + 7)
2𝑠(𝑠 − 4)
2
3 − 4π‘š
(π‘₯ + 9)(π‘₯ − 2)
(2𝑑 − 1)(𝑑 + 5)
𝟐
𝟐
𝒙 − πŸ“π’™ + πŸ‘ = 𝟎
𝒓 = πŸπŸ’πŸ’
πŸ— − πŸ’π’™ = πŸπŸ“
πŸπ’” + πŸ‘π’• = −πŸ•
𝟐
𝟐
𝒕 − πŸ•π’• + πŸ”
πŸ—π’“ − πŸπŸ“ = 𝟎
𝒄 = πŸπŸπ’ − πŸ“
πŸ–π’Œ − πŸ‘ = 𝟏𝟐
Which of the following is a linear equation?
𝟐
𝒙 − πŸ“π’™ + πŸ‘ = 𝟎
𝟐
𝒕 − πŸ•π’• + πŸ”
𝟐
𝒓 = πŸπŸ’πŸ’
𝟐
πŸ—π’“ − πŸπŸ“ = 𝟎
QUADRATIC EQUATIONS
ο‚žA
Quadratic Equation in One
Variable
is
a
mathematical
sentence of degree 2 that can be
written in the following standard
2
form π‘Žπ‘₯ + 𝑏π‘₯ + 𝑐 = 0, where π‘Ž, 𝑏
and 𝑐 are real numbers and π‘Ž ≠ 0.
ο‚žIn
2
π‘Žπ‘₯
the equation,
is the
quadratic term, 𝑏π‘₯ is the linear
term, and 𝑐 is the constant term.
Examples:
2
ο‚ž 2π‘₯ − 6π‘₯ − 15 = 0
ο‚ž 2π‘₯ π‘₯ − 4 = 18
ο‚ž π‘₯−3 π‘₯+1 =4
QUADRATIC
EQUATION
VALUES
STANDARD FORM OF 𝒂, 𝒃
and 𝒄
𝒂=𝟐
πŸπ’™πŸ − πŸ”π’™ − πŸπŸ“ = 𝟎 πŸπ’™πŸ − πŸ”π’™ − πŸπŸ“ = 𝟎 𝒃 = −πŸ”
𝒄 = −πŸπŸ“
𝒂=𝟐
πŸπ’™ 𝒙 − πŸ’ = πŸπŸ–
πŸπ’™πŸ − πŸ–π’™ − πŸπŸ– = 𝟎 𝒃 = −8
𝒄 = −𝟏8
𝒂=𝟏
𝒙 − πŸ‘ 𝒙 + 𝟏 = πŸ’ π’™πŸ − πŸπ’™ − πŸ• = 𝟎 𝒃 = −𝟐
𝒄 = −πŸ•
QUADRATIC
TERM
LINEAR
TERM
CONSTANT
TERM
πŸπ’™πŸ
−πŸ”π’™
−πŸπŸ“
πŸπ’™πŸ
−πŸ–π’™
−πŸπŸ–
π’™πŸ
−πŸπ’™
−πŸ•
Tell whether each equation is QUARATIC or
NOT QUADRATIC.
1.
2.
3.
4.
5.
2
π‘₯
+ 7π‘₯ + 12 = 0
−3π‘₯ π‘₯ + 5 = 0
12 − 4π‘₯ = 0
π‘₯ + 7 π‘₯ − 7 = 3π‘₯
2π‘₯ + π‘₯ + 4 = π‘₯ − 3 + (π‘₯ − 3)
Write each equation in standard form then
identify the values of π‘Ž, 𝑏 and 𝑐.
1.
2.
3.
4.
5.
2
2π‘₯
+ 5π‘₯ − 3 = 0
2
3 − 2π‘₯ = 7
π‘₯ 4π‘₯ + 6 = 28
3π‘₯ − 7 5π‘₯ + 2 = 0
2
−3π‘₯ + 5π‘₯ = 7
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