PHYSICS
Acharya
Name Viru
Pa
I: H
a P
C
ec e
a
a
Wo k hop
a
a
b
a
a
a ab a
h ab
.
1) Ma e a ca P ed c
a) W a
hi k ab
ha ha e
he -c
Velocity
Constant
b) I
a a
a
a
,
e
no
a
el ci d i g he
fi
acceleration
a
a
a
a
a
?
) W a
Voxt
a
acceleration ( 9. 8m44
Constant
) I
a
b
a
h
a
due to
,
,
?
a
a
a
a
, d, b
a
,
.
+
tzqt
2
?
a
gravity
,
a
¥
=
a
) I
a,Δ ,
,
a l
Δ =
=
.
a
¥5s
a
Voxt
d=
2) A
? ( ecificall ,
i )
+
lzaxt
ca
a) Y
a
ab
( fall).
b
t
fall
b) I
=
TY
a
✗
✗
=
=
=
✗◦
0
25
+
12
b
b
Want
+
.
+
.D
F¥÷
=
a
a
b 1.3
tzaxt
(0-515)
875m
a
=
25 / ,
(d).
2
+
0
0
a a
.
515
a
seconds
a
'
Pa
II: La
c
a a A
e
N
a a
a
3
/ .I
a a a
a
a) O
35 ab
a
a a
b) O
a
a.A
ba
b
.
a
a a a
.I a
a ba
ba
a a
.
ba
a
a
b
a
ab
a
,
,
a
- -a
a
a
a
a
a
a
a
a
.W a
? (H
: ∆𝑣
𝑣𝑜)
𝑣𝑓
Vb
=3
.66mk
jnveloitkyonlyalong%Ff.SE
3m12
>
•
is
,
) F
a
Nochange velocity
✗ direction
observed
only
Hence direction
#
acceleration
hence
_
MY
axis
v.
okay
.
.
ofauuagyace.isonlyinyascis.in the downward direction
.
a a
a
ab
b
. Ma
.
H
𝑥𝑖
𝑥𝑓
𝑣𝑥
a
V
0
=
𝑖
range
=
=3
𝑎
=
m/s
0
𝑓
𝑣
𝑣
𝑖
𝑓
𝑎
a
Cliff
=
0
=
2.099
=
=
Uytayt
=
=
-9.8
-17.5
b
a
) I
ba
✗
=
a
a
Xo
V. ✗t
-1
6=0
a
V.
+
✗
a
+
(f)
d=6
tzaxt
≥
C a e
a
a) S
=
a
b) D
60.0° a
+
(2-099) (2)
ba
ba
a
4
a
a
a
4
=
198
.
{(
g.
-
+
8) (4)
Yo
15.4m
=
a
a
a
50.0
b
a
a
ba .
ba
) W a
a
a
a
ace e
%
=
Yo
ba
) A
d
Voet + { a #
19.6
a a a
.
a
a
a a
, h?
+
2
e: A ba
,
Y= Yo
◦
+0
6 =3 (f)
i. C-
a a
(a
a -
a
a
a
b
b
,
a - .
). H
.
?
a
a
ba
: