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Applied Econometrics Assignment - II (Kaneez Fatima) - Copy

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Submitted to: Dr. Tanweer ul Islam
Submitted by: Kaneez Fatima
MS ECONOMICS 2K20
NUST SCHOOL OF SOCIAL SCIENCES & HUMANITIES
Applied Econometrics Assignment # 2
Q. Proof
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟐 ) = π’‚πŸπŸ
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟏 ) = π’‚πŸ
Solution:
Before giving the proof, we have to check the data for stationarity
If it is stationary, then the mean value will remain constant over time i.e. πœ‡ = 0. If π’‚πŸ is constant,
then its mean value is also constant; the absolute value of π’‚πŸ is less than 1.
Using autoregressive model AR (1):
Let π’šπ’• =π’‚πŸ π’šπ’•−𝟏 + πœΊπ’• i.e., put π’‚πŸ = 𝟎 → 𝝁 = 𝟎
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟏 ) = 𝚬[(π’‚πŸ π’šπ’•−𝟏 + πœΊπ’• )π’šπ’•−𝟏 ]
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟏 ) = π’‚πŸ 𝚬(π’šπŸπ’•−𝟏 )
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟏 ) = π’‚πŸ πˆπŸπ’š
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟏 ) =
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟏 )
𝒗𝒂𝒓(π’šπ’• , π’šπ’•−𝟏 )
Due to stationarity, the variance of π’šπ’• = the variance of π’šπ’•−𝟏
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟏 ) = π’‚πŸ
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟐 ) = 𝚬[(π’‚πŸ π’šπ’•−𝟏 + πœΊπ’• )π’šπ’•−𝟐 ]
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟐 ) = 𝚬[(π’‚πŸ (π’‚πŸ π’šπ’•−𝟐 + πœΊπ’•−𝟏 ) + πœΊπ’• )π’šπ’•−𝟐 ]
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟐 ) = 𝚬(π’‚πŸπŸ π’šπŸπ’•−𝟐 + π’‚πŸ πœΊπ’•−𝟏 π’šπ’•−𝟐 + πœΊπ’• π’šπ’•−𝟐 )
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟐 ) = π’‚πŸπŸ πˆπŸπ’š
Due to stationarity, the variance of π’šπ’• = the variance of π’šπ’•−𝟐
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟐 ) =
𝒄𝒐𝒗(π’šπ’• , π’šπ’•−𝟐 )
𝒗𝒂𝒓(π’šπ’• , π’šπ’•−𝟐 )
𝒄𝒐𝒓𝒓(π’šπ’• , π’šπ’•−𝟐 ) = π’‚πŸπŸ
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