MAP4C Foundations for College Mathematics, Grade 12, College Preparation Version A (NOTE: Throughout this course you will find examples and support questions with answers. Dependent upon rounding of values, answers given may differ slightly from what you calculate.) MAP4C – Foundations for College Mathematics Introduction MAP4C - Foundations for College Mathematics 12 Welcome to the Grade 12 Foundations for College Mathematics, MAP4C. This fullcredit course is part of the new Ontario Secondary School curriculum (2007). Materials This course is self-contained and does not require a textbook. You will however, need the following items: • • • • • **Scientific calculator (this is a must have instrument) Lined paper Graph paper Ruler Writing utensil (preferably a pencil with an eraser) Structure of Lessons Each lesson contains one or two concepts and multiple examples for complete insight. Definitions will be bolded for emphasis. At the end of each new concept, there are support questions to complete on your own to check for full understanding. At the end of each lesson, there are several key questions that cover all concepts learned in the lesson which need to be submitted for evaluation. Evaluation In order to be granted a credit in this course, you must: • • • Successfully complete the Key Questions for each unit and submit them for evaluation within the required time frame (40%) Complete and pass the midterm exam (30%) Complete and pass the final exam (30%) Copyright © 2007, Durham Continuing Education Page 2 of 38 MAP4C – Foundations for College Mathematics Introduction Key Questions, the midterm exam and the final exam will be evaluated on the basis of the following four categories of achievement (outlined by the Ministry of Education): • • • • Knowledge & Understanding 40% Applications 40% Communication 10% Thinking & Inquiry 10% Support Questions Support Questions will be noted with this pencil icon. These questions will help you understand and master each new concept and are not to be submitted for evaluation. • • Answer support questions in your notebook and keep them as a reference for key questions. Check your answers to support questions by using the “Support Question Solutions” at the end of each unit. Key Questions Key Questions will be noted with this key icon. These questions evaluate your achievement of the expectations for the lesson and must be submitted at the end of each unit. • • • Write your solutions (a solution is a step by step process of how you get to your final answer) on your own paper. Write the lesson number on the top of the page and label each question clearly when you submit your work. You must try all key questions and complete most of them successfully in order to pass each unit. Midterm and Final Examinations The midterm and final exams are weighted exams. The midterm will cover material learned in Units #1 - 2 and will be a two hour exam. The final examination will cover material from Units #1 - 4 and will be a two hour exam as well. Copyright © 2007, Durham Continuing Education Page 3 of 38 MAP4C – Foundations for College Mathematics Introduction Table of Contents Unit 1 Lesson 1 Lesson 2 Lesson 3 Lesson 4 Lesson 5 Future Value of an Annuity Present Value of an Annuity Mortgages Amortization Tables Renting Vs Buying Unit 2 Lesson 6 Lesson 7 Lesson 8 Lesson 9 Lesson 10 Exponents Linear, Quadratic and Exponential Functions Scatter Plots Line of Best Fit and Extrapolation Uses and Misuses of Sample Data Unit 3 Lesson 11 Lesson 12 Lesson 13 Lesson 14 Lesson 15 Survey Design The Media and Data Management Imperial and Metric Measurements and Conversions Perimeter Area/Surface Area Unit 4 Lesson 16 Lesson 17 Lesson 18 Lesson 19 Lesson 20 Volume Trigonometric Ratios Law of Sine Law of Cosine Trigonometry and Problem Solving Copyright © 2007, Durham Continuing Education Page 4 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Lesson 1 Future Value of an Annuity MAP4C – Foundations for College Mathematics Lesson 1 Lesson One Concepts ¾ Calculating the future value of an annuity with matching payment and compounding frequencies Future Value of an Annuity Annuity is a series of equal deposits made at equal time intervals. Each deposit is made at the end of each time interval. R[(1 + i ) − 1] i n FV = FV = the amount the investment “grows” to R = the regular deposit made in dollars i = interest rate, as a decimal, per compounding period OR = interest rate as a decimal # of interest periods in 1 year n = number of compounding periods OR = # of compounding periods per year multiplied by the # of years A compounding period means the time frame in which compound interest is calculated. Example 1 Noah deposits $1500 at the end of each six months in an account that pays 6% compounded semi-annually. What is the amount in the account at the end of 15 years. Solution R = the regular deposit made in dollars = 1500 i = interest rate, as a decimal, per compounding period OR = interest rate as a decimal # of interest periods in 1 year .06 = 2 =0.03 Copyright © 2007, Durham Continuing Education Page 6 of 38 MAP4C – Foundations for College Mathematics Lesson 1 n = number of compounding periods OR = # of compounding periods per year multiplied by the # of years = 2 x 15 = 30 30 1500[(1 + .03 ) − 1] FV = .03 = 71 363.12 The amount at the end of 15 years is $71 363.12 Example 2 How much did Noah earn in interest from his annuity in example 1. Solution 1500 x 2 x 15 = $45 000 Interest Earned = total of annuity at investment – total principal paid into annuity. = 71 363.12 – 45 000.00 = $26 363.12 Example 3 Steven wants to buy a $5000.00 car when he graduates from high school. He deposits $85 at the end of each month in an account that pays 9% compounded monthly. Steven will graduate in 4 years. Will he have enough money by then? Solution R = 85 .09 i= = 0.0075 12 n = 4 x 12 = 48 85[(1 + .0075 ) − 1] .0075 = 4889 .26 48 FV = Steven will not have quite enough to purchase his $5000 car. Copyright © 2007, Durham Continuing Education Page 7 of 38 MAP4C – Foundations for College Mathematics Lesson 1 Support Questions R[(1 + i ) − 1] . Calculate FV for each set of values. i n 1. Use the formula FV = a. R = $400, i=0.04, n = 12 .05 b. R = $100, i= , n = 50 2 .08 c. R = $500, i= , n = 36 12 2. Calculate the amount of each annuity. a. $200 deposited at the end of each year for 5 years at 4% compounded annually. b. $1000 deposited every six months for 4 years at 9% compounded semiannually. 1 c. $450 deposited at the end of every three months for 10 years at 4 % 2 compounded quarterly. 3. The Smith’s are buying a house and deposit $1500 every month into an account that pays 5% compounded monthly. How much will they have in 2 years? Key Question #1 R[(1 + i ) − 1] . Calculate FV for each set of values. Use the formula FV = i n 1. a. R = $100, i=0.035, n = 10 .08 b. R = $300, i= , n = 30 2 .10 , n = 48 c. R = $450, i= 4 Copyright © 2007, Durham Continuing Education Page 8 of 38 MAP4C – Foundations for College Mathematics Lesson 1 Key Question #1 (continued) 2. Calculate the amount of each annuity. 1 a. $1000 deposited every six months for 6 years at 5 % compounded semi2 annually. b. $600 deposited at the end of each year for 10 years at 4.25% compounded annually. c. $1500 deposited at the end of every three months for 25 years at 5.75%compounded quarterly. 3. Brianna deposits $150 at the end of each quarter into an account that pays 8% compounded quarterly. Calculate the amount in the account at the end of each time period. a. b. c. d. 4 years 9 months 6.75 years 20.5 years 4. Beginning one month after birth of their son, Noah, the Nelsons deposited $100 each month in an annuity for his college fund. The annuity earned interest at an average rate of 6.8% compounded monthly until his 18th birthday. What was the amount of Noah’s college fund on his 18th birthday? 5. Referring to question 4, how much interest did Noah’s college fund earn in total on his 18th birthday? Copyright © 2007, Durham Continuing Education Page 9 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Lesson 2 Present Value of an Annuity MAP4C – Foundations for College Mathematics Lesson 2 Lesson Two Concepts ¾ Calculating the present value of an annuity with matching payment and compounding frequencies Present Value of an Annuity The principal that must be invested now to provide an annuity is called the Present Value of an Annuity. R[1 − (1 + i) ] i −n PV = PV = the amount of the investment that must be invested now R = the regular withdrawal made in dollars i = interest rate, as a decimal, per compounding period OR = interest rate as a decimal # of interest periods in 1 year n = number of compounding periods OR = # of compounding periods per year multiplied by the # of years A compounding period means the time frame in which compound interest is calculated. Example 1 Joey’s annuity pays $2700 at the end of each year for 4 years, starting 1 year from now. The annuity earns 6.5% compounded annually. Determine the present value of the annuity. Solution R = the regular withdrawal made in dollars = 2700 i = interest rate, as a decimal, per compounding period OR = interest rate as a decimal # of interest periods in 1 year .065 = 1 =0.065 Copyright © 2007, Durham Continuing Education Page 11 of 38 MAP4C – Foundations for College Mathematics Lesson 2 n = number of compounding periods OR = # of compounding periods per year multiplied by the # of years =1x4 =4 −4 2700[1 − (1 + .065 ) ] PV = .065 = 9249 .66 The amount to invest now is $9249.66 in order to withdraw $2700 each year for 4 years. Example 2 How much will Joey earn in interest from his annuity in example 1. Solution 2700 x 4 = $10 800 Interest Earned = total of annuity at investment – total principal paid into annuity. = 10 800.00 – 9249.66 = $1550.34 Example 3 Kristen is converting her RRSP into an income fund. She wishes to receive $1500 every six months for the next 20 years, starting 6 months from now. She is guaranteed an interest rate of 6.25% compounded semi-annually. How much must Kristen deposit now to pay for the annuity? Solution R = 1500 .0625 i= = 0.03125 2 n = 2 x 20 = 40 1500[1 − (1 + .03125 ) PV = .03125 = 33982 .11 −40 ] Kristen must deposit $33 982.11 now to have semi-annually payment of $1500.00 Copyright © 2007, Durham Continuing Education Page 12 of 38 MAP4C – Foundations for College Mathematics Lesson 2 Support Questions R[1 − (1 + i) ] Use the formula PV = . Calculate PV for each set of values. i −n 1. 2. a. R = $400, i=0.04, n = 20 .05 b. R = $100, i= , n = 20 2 .08 c. R = $700, i= , n = 36 12 Calculate the present value amount of each annuity. a. $200 withdrawn at the end of each year for 6 years at 4% compounded annually. b. $1000 withdrawn every six months for 4 years at 10% compounded semiannually. 1 c. $750 withdrawn at the end of every three months for 10 years at 4 % 2 compounded quarterly. 3. Cliff has recently sold his business. He sets up an annuity that will pay him $3000.00 per month for the next 10 years. The first payment is to be made 1 month from now. Cliff can invest his money at 5.5% compounded monthly. How much does the annuity cost today? Key Question #2 R[1 − (1 + i) ] . Calculate FV for each set of values. i −n 1. Use the formula PV = a. R = $100, i=0.025, n = 15 .08 b. R = $200, i= , n = 50 4 .10 , n = 36 c. R = $750, i= 4 Copyright © 2007, Durham Continuing Education Page 13 of 38 MAP4C – Foundations for College Mathematics Lesson 2 Key Question #2 (continued) 2. Calculate the amount of each annuity. 1 a. $1200 withdrawn every six months for 5 years at 4 % compounded semi2 annually. b. $500 withdrawn at the end of each year for 12 years at 4.75% compounded annually. c. $1250 withdrawn at the end of every three months for 20 years at 6.25% compounded quarterly. 3. Don won the “Cash for Life” lottery and will receive a $1000 per week for the next 25 years. How much must the lottery corporation invest today into an account that pays 4% compounded weekly to provide Don with the prize? 4. An annuity pays $1200 per year for 15 years. The money is invested at 5.2% compounded annually. The first payment is made 1 year after the purchase of the annuity. Determine the interest earned by the annuity over the 15 years. 5. Noah wants to buy a 5 year annuity. He has two options. • • Option A pays $1000 at the end of each year, starting one year from now. It earns interest at 6.25% compounded annually. Option B pays $500 at the end of every six months, starting six months from now. It earns interest at 6.25% compounded semi-annually. Which annuity should Noah choose? Write an explanation that includes calculations to support your answer. Copyright © 2007, Durham Continuing Education Page 14 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Lesson 3 Mortgage Payments MAP4C – Foundations for College Mathematics Lesson 3 Lesson Three Concepts ¾ Calculating mortgage payments with matching payment and compounding frequencies ¾ Introducing mortgage terminology Mortgage Terminology Mortgage: is a loan to buy property, with the property as security Mortgagor: the person buying the property Mortgagee: the lending institution lending the money to the purchaser (mortgagor) Down payment: a required percent of the purchased price given in cash prior to the mortgage being given Amortized: when both the principal and interested on a mortgage is repaid with a series of equal regular payments Amortization Period: the length of time a mortgage is repaid Term: The length of time that a mortgage is must be paid in full or renegotiated under newly negotiated interest rate When calculating the mortgage payment “R” the present value formula is used. R[1 − (1 + i) ] i −n PV = Example 1 A house is purchased for $150 000 with a 10% down payment. What is the monthly mortgage payment on the house with a 5 year term at 6% compounded monthly amortized over 25 years? Solution Down payment = 150 000 (.10) = $15 000 PV = amount of mortgage = 150 000 – 15 000 = 135 000 Copyright © 2007, Durham Continuing Education Page 16 of 38 MAP4C – Foundations for College Mathematics Lesson 3 i = interest rate, as a decimal, per compounding period OR = interest rate as a decimal # of interest periods in 1 year .06 = 12 =0.005 n = number of compounding periods OR = # of compounding periods per year multiplied by the # of years = 12 x 25 = 300 −300 R[1 − (1 + .005 ) ] 135000 = .005 135000 = 155.207R 135000 155.207R = 155.207 155.207 869.81 = R The monthly payment for the next 5 years will be $869.81 per month. Example 2 In example 1, if that was the payment amount for the entire 25 years how much was paid in total and what was the total amount paid in interest for the house? Solution Total paid for the house = 869.89 x 300 (total number of payments) = 260 943 +15 000 (down payment) = $275 943 Total interest paid = 275 943 – 150 000 = $125 943 Copyright © 2007, Durham Continuing Education Page 17 of 38 MAP4C – Foundations for College Mathematics Lesson 3 Support Questions 1. Determine the monthly payment for each mortgage. The interest is compounded monthly. a. b. c. d. Mortgage amount $140 000 $200 000 $175 000 $350 000 Amortization period 30 years 25 years 20 years 25 years Interest rate 6% 5.25% 6.20% 5.95% 2. Determine the total interest paid for each of questions in question 1. 3. Elaine purchased a house for $225 000. She made a down payment of 25% of the purchase price and took out a mortgage for the rest. The mortgage has an interest rate of 7.25% compounded monthly, and amortization period of 30 years, and a 3 year term. Calculate Elaine’s monthly payment. 4. The Nelson’s have a mortgage of $125 000 amortized over 25 years at 7% compounded monthly. After the original 5 year term, the mortgage is renewed at 6.5% compounded monthly. Calculate the new monthly payment. Key Question #3 1. Determine the monthly payment for each mortgage. The interest is compounded monthly. Mortgage amount Amortization period Interest rate a. $185 000 25 years 6.25% b. $220 000 30 years 5.75% 2. Determine the total interest paid for each of questions in question 1. 3. Ashlee purchased a house for $875 000. She made a down payment of 15% of the purchase price and took out a mortgage for the rest. The mortgage has an interest rate of 6.95% compounded monthly, and amortization period of 20 years, and a 5 year term. Calculate Ashley’s monthly payment. Copyright © 2007, Durham Continuing Education Page 18 of 38 MAP4C – Foundations for College Mathematics Lesson 3 Key Question #3 (continued) 4. The Vaughan’s have a mortgage of $725 000 amortized over 25 years at 4.25% compounded monthly. After the original 4 year term, the mortgage is renewed at 4.0% compounded monthly. Calculate the new monthly payment. 5. A bank charges 7.75% compounded monthly on a mortgage. The Markins have an excellent credit rating. They negotiated a rate of 7% compounded monthly on a mortgage on $230 000 amortized over 25 years. By how much did the Markins reduce their monthly payment by negotiating the lower rate of interest? Copyright © 2007, Durham Continuing Education Page 19 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Lesson 4 Amortization Table MAP4C – Foundations for College Mathematics Lesson 4 Lesson Four Concepts ¾ Calculating mortgage payments with matching payment and compounding frequencies ¾ Introducing the concept of an amortization table and calculating the monthly interest paid, principal paid and outstanding balance Amortization Table (Schedule) An amortization table shows in detail how the mortgage is to be repaid over a predetermined period of time. It lists each payment, how much of each payment is interest how much of each payment goes to reduce the mortgage, and the outstanding principal after each payment. Example 1 Complete and amortization table for the first six monthly payments given the following information: Monthly payment: $ 694.63 Mortgage amount: $90000 Interest rate: 8% compounded monthly Solution Payment Number 0 1 Monthly Interest Payment Paid None None $694.63 .08 90000( ) = 600 12 2 $694.63 3 $694.63 4 $694.63 5 $694.63 6 $694.63 89905.37( .08 ) = 599.37 12 89810.11( .08 ) = 598.73 12 89714.21( .08 ) = 598.09 12 89617.67( .08 ) = 597.45 12 89520.49( .08 ) = 596.80 12 Copyright © 2007, Durham Continuing Education Principal Paid None 694.63 – 600.00= $94.63 694.63 – 599.37= $95.26 694.63 – 598.73= $95.90 694.63 – 598.09= $96.54 694.63 – 597.45= $97.18 694.63 – 596.80= $97.83 Outstanding Principal $90 000 90 000 – 94.63= $89 905.37 89 905.37 – 95.26= $89 810.11 89 810.11 – 95.90= $89 714.21 89 714.21 – 96.54= $89 617.67 89 617.67 – 97.18= $89 520.49 89 520.49 – 97.83= $89 422.66 Page 21 of 38 MAP4C – Foundations for College Mathematics Lesson 4 Example 2 A mortgage of $200 000 is required to purchase a house. The mortgage will be repaid with equal monthly payments over 25 years at 10% compounded monthly. What is the monthly payment and complete an amortization table showing the first three payments. Solution ⎛ .10 ⎞ R[1 − ⎜1 + ⎟ 12 ⎠ ⎝ 200000 = .10 12 200000 = 110.047R −300 ] 200000 110.047R = 110.047 110.047 1817.40 = R Payment Number 0 1 Monthly Interest Payment Paid $1817.40 .10 200000( ) = 1666.67 12 2 $1817.40 3 $1817.40 199849.27( .10 ) = 1665.41 12 199697.28( .10 ) = 1664.14 12 Copyright © 2007, Durham Continuing Education Principal Paid 1817.40 – 1666.67= $150.73 1817.40 – 1665.41= $151.99 1817.40 – 1664.14= $153.26 Outstanding Principal $200 000 200 000 – 150.73= $199 849.27 199 849.27– 151.99= $199 697.28 199 697.28 – 153.26= $199 544.02 Page 22 of 38 MAP4C – Foundations for College Mathematics Lesson 4 Support Questions 1. Complete the first six payments in an amortization table given the following information. Show all steps. Monthly payment: $ 1340.37 Interest rate: 8.25% compounded monthly Mortgage amount: $170 000 2. Using question 1, how much interest was paid in the first 6 months? 3. Using question 1, how much principal was paid off the mortgage after six payments? 4. The Nelson’s have a mortgage of $125 000 amortized over 20 years at 8% compounded monthly. Determine the monthly payment and create an amortization table for the first six payments. Key Question #4 1. Complete the first six payments in an amortization table given the following information. Show all steps. Monthly payment: $1590.25 Interest rate: 7% compounded monthly Mortgage amount: $225 000 2. Using question 1, how much interest was paid in the first 6 months? 3. Using question 1, how much principal was paid off the mortgage after six payments? 4. A mortgage of $300 000 amortized over 35 years at 7.25% compounded monthly. Determine the monthly payment and create an amortization table for the first six payments. 5. Using question 4, how much interest was paid in the first 6 months? 6. Using question 4, how much principal was paid off the mortgage after six payments? Copyright © 2007, Durham Continuing Education Page 23 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Lesson 5 Housing: Owning Vs Renting MAP4C – Foundations for College Mathematics Lesson 5 Lesson Five Concepts ¾ Advantages and disadvantages of buying a home ¾ Advantages and disadvantages of renting a home Accommodations: Rent vs. Buy Why Rent? Choice Today you’ll find more choice of rental accommodation than ever before – as well as more amenities and flexible housing styles. Location When considering cost, don’t forget the cost of commuting to work. Often rental properties are more central for jobs, amenities and transit than homes in suburban communities. And if you want to be right downtown in a major metropolitan area, renting is almost always more affordable than owning a condo. Space Apartment units are typically larger than comparable suite types in new condominium properties. Simplicity Compared to owning a home, rental living is easy: • • • • • Property staff to call if anything goes wrong Full-time maintenance staff to handle maintenance and repairs No snow shovelling or lawn maintenance No worries when you go away on vacation A single monthly rent cheque pays for all of the above – compared to many separate bills when you own a house, and a separate condo fee when you own a condo Savings Renting leaves you more disposable income for things like travel, recreation or buying a vacation home: • • Lower, controlled cost – The cost of renting is a bargain compared to total home ownership costs that include taxes, utilities, insurance and maintenance. What’s more, your rental costs are fixed for the term of your lease. By contrast, condo fees are more unpredictable, and most home ownership costs have been rising much more quickly than the rate of inflation. Five-year advantage – People say paying rent is like throwing money away. But if you plan to move in the next five years, you could say the same about a Copyright © 2007, Durham Continuing Education Page 25 of 38 MAP4C – Foundations for College Mathematics • Lesson 5 mortgage. In the first five years of ownership, most of your mortgage payments are applied to interest, with minimal paid to the principal. So you won’t get this money back when you sell, and you’ll have all the hassles and costs of putting your house on the market. Possible deductible – In some situations, your rent may be deductible. Home ownership costs are not. Flexibility When you rent, you can pack up and leave at the end of your lease, without having to find a buyer and wait for the sale to close. Why Buy? Advantages of Buying home Buying a house has its positive and negative aspects and so before deciding whether to go ahead and purchase that home, look at the pros and cons in conjunction with your situation and decision will be appropriate for you. Advantages of buying Build Equity As you are making your mortgage payment, you're building equity. Equity is the portion of the property that you actually own through your payments, versus the portion that you still owe the mortgage lender. The longer you stay in your home and the more mortgage payment you make, the more equity you'll have. This may assist you in using your equity in purchasing another property or another useful investment. Appreciation of housing value Over time housing prices gradually increase although this may fluctuate, in general housing prices consistently over a long period go up. Stability and Freedom By owning your own home you can decorate and renovate your home whichever way you like. Also staying in a common location for a number of years will provide a stable environment for children growing up. Financial Credibility Owning your own home helps you establish financial credibility with banking institutions which can help if you intend to finance in the future. Independence Provides you with independence and privacy from landlords with inspections of your home. Landlord limitations on pets, renovations etc will not longer apply. Copyright © 2007, Durham Continuing Education Page 26 of 38 MAP4C – Foundations for College Mathematics Lesson 5 Pride A house is only a building while a home is when people living within its walls. Owning your own home provides owners with the sense of pride and satisfaction knowing that they created, renovated and enjoyed times within their home. Buy vs. Rent Comparison Chart Advantages Considerations Property builds equity Responsible for maintenance Sense of community, stability, and security Responsible for property taxes Buy Free to change decor and Possibility of foreclosure and loss landscaping of equity Not dependent on landlord to maintain property Little or no responsibility for maintenance Rent Easier to move Less mobility than renting No tax benefits No equity is built up No control over rent increases Possibility of eviction Copyright © 2007, Durham Continuing Education Page 27 of 38 MAP4C – Foundations for College Mathematics Lesson 5 Example 1 Brenda and Richard have 2 children in elementary school. The couple earns $81 000. Richard has a 2 year contract as a consultant with the Ministry of Education and Brenda works part time as a early childhood educator. They are moving from their small 2 bedroom rental apartment to be closer to where both Brenda and Richard work. They have $15 000 in savings. The only debt they have is a car payment of $425 per month. The following below shows two options for their new housing needs. Which option should be recommended? Option A: Buy • 4 bedrooms, 2 bathrooms, average kitchen, all appliances, average living room, unfinished basement, no garage, small yard • 1400 square feet of living space • price $140 000 • interest rate 7.5% • term: 5 years • amortization period 25 years • down payment 5% • mortgage payment $976.75 per month • taxes $1800 per year • utilities $417 per month Option B: Rent • 3 bedrooms, 2 bathrooms, large kitchen, large living room, full recreation room in basement and 1 car garage, large yard • 1850 square feet • $1250 per month rent • 1 year lease minimum • responsible landlord that lives in another town • must maintain yard to satisfactory level • utilities $350 month Solution Organize the information for each scenario to make a choice OPTION A: Buying PROS • can build equity • can finish basement and have more living space • can resell at any time • reasonable monthly mortgage payment and taxes • comes with appliances CONS • large financial commitment with contract job • cost money to finish basement • extra home repair costs are now owners responsibilities • small yard for the young children • upfront cost such as land transfer tax and lawyer fees Copyright © 2007, Durham Continuing Education Page 28 of 38 MAP4C – Foundations for College Mathematics Lesson 5 Monthly calculations: Monthly Payments = Mortgage + utilities + taxes + car payment = 976.75 + 417 + 1800/12 + 425 = $1968.75 Monthly Income = 81000/12 = $6750 (Gross income) OPTION B: Renting PROS • only 1 year minimum commitment • large rooms • large yard for children • no property taxes • minimal yard care needed • has garage CONS • no equity • tied to at least one year in the lease • landlord is not local • rent is more than property tax and mortgage payment in option A Monthly calculations: Monthly Payments = rent + utilities + car payment = 1250 + 350 + 425 = $2025 Rental monthly cost ($2025) exceeds monthly owning costs ($1968.75). Since they will be building equity and the cost of living in both places is roughly the same and keeping in mind that the upfront costs could be covered by the savings, then purchasing the house would likely be the best choice. Despite the purchased property having less living space the building of the equity by purchasing a home would likely outweigh this shortcoming. Copyright © 2007, Durham Continuing Education Page 29 of 38 MAP4C – Foundations for College Mathematics Lesson 5 Support Questions 1. Michelle is a single mom of 3 children in elementary school. She earns $60 000 (net). She has $5 000 in savings. The only debt she has is $2000 owing on a credit card. The following below shows two options for her new housing needs. Option A: Buy • 3 bedrooms, 1 bathrooms, average kitchen, no appliances, average living room, finished basement, garage, average sized yard • 1750 square feet of living space • price $210 000 • annual interest rate 7.05% compounded monthly • term: 5 years • amortization period 25 years • down payment 0% • taxes $2200 per year • utilities $400 per month Option B: Rent • 4 bedrooms, 1 bathrooms, large kitchen, large living room, unfinished basement no garage, large yard • 2000 square feet • $1250 per month rent • 1 year lease minimum • responsible landlord that lives next door • utilities $375 month • yard maintained by landlord a. Calculate the monthly mortgage payment for option A. b. List 4 pros and 4 cons of both options. c. Calculate the total monthly payment for both options. d. Which option would you choose? Justify your choice. Key Question #5 1. List 3 advantages of renting and 3 advantages of owning a home. 2. These are the costs of an apartment. Rent: $1270/month; water: $400/year; heating: 1600/year; electricity: 1550/year. How much is owed per month? Copyright © 2007, Durham Continuing Education Page 30 of 38 MAP4C – Foundations for College Mathematics Lesson 5 Key Question #5 (continued) 3. Lester and Evelyn want to either rent an apartment or purchase a house with at least three bedrooms. Their combined gross income is $120 000. If they buy a house, they will need a down payment of 5%. They have been approved for a mortgage of 6.05% compounded monthly for a 7 year term amortized over 20 years. Lester and Evelyn enjoy travelling often and frequent the gym on a regular basis. They also enjoy eating out at least twice per week at fine dinning restaurants. Option A: Buy • 2 bedrooms, 2 bathrooms, new kitchen, appliances included, average living room, finished basement, 2 car garage, small yard • 1700 square feet of living space • price $280 000 • taxes $3500 per year • utilities $400 per month Option B: Rent • 3 bedrooms apartment, 2 bathrooms, large kitchen, large living room, parking space • 1200 square feet • $1870 per month rent • 1 month to month • property manager onsite • utilities $300 month • parking in secured area a. Calculate the monthly mortgage payment for option A. b. List 4 pros and 4 cons of both options. c. Calculate the total monthly payment for both options. d. Which option would you choose? Justify your choice. 4. Explain one advantage for each when renting: choice, location, space, simplicity, savings and flexibility. Copyright © 2007, Durham Continuing Education Page 31 of 38 MAP4C Foundations for College Mathematics, Grade 12, College Preparation Answers to Support Questions MAP4C – Foundations for College Mathematics Support Question Answers Lesson 1: 1 a. b. 50 ⎛ .05 ⎞ 100[⎜ 1 + − 1] 2 ⎟⎠ ⎝ FV = .05 2 = $9748.43 400[(1 + .04 ) − 1] FV = .04 = $6010.32 12 c. 36 ⎛ .08 ⎞ 500[⎜ 1 + − 1] 12 ⎟⎠ ⎝ FV = .08 12 = $20267.78 2 a. b. ⎛ .09 ⎞ 1000[⎜ 1 + 2 ⎟⎠ ⎝ FV = .09 2 = $9380.01 200[(1 + .04 ) − 1] FV = .04 = $1083.26 5 4×2 − 1] c. 10×4 ⎛ .045 ⎞ 450[⎜ 1 + 4 ⎟⎠ ⎝ FV = .045 4 = $22575.07 − 1] 3. ⎛ .05 ⎞ 1500[⎜ 1 + 12 ⎟⎠ ⎝ FV = .05 12 = $37778.88 2×12 − 1] Therefore the Smiths will have saved $37778.88 in two years. Copyright © 2007, Durham Continuing Education Page 33 of 38 MAP4C – Foundations for College Mathematics Support Question Answers Lesson 2: 1 a. b. 400[1 − (1 + .04 ) PV = .04 = $5436.13 −20 ⎛ .05 ⎞ 100[1 − ⎜ 1 + 2 ⎟⎠ ⎝ PV = .05 2 = $1558.92 ] −20 ] c. ⎛ .08 ⎞ 700[1 − ⎜ 1 + 12 ⎟⎠ ⎝ PV = .08 12 = $22338.26 2 −36 ] a. b. −8 1000[1 − (1 + 0.05 ) ] PV = 0.05 = $6463.21 200[1 − (1 + .04 ) ] .04 = $1048.42 −6 PV = c. ⎛ 0.045 ⎞ 750[1 − ⎜ 1 + 4 ⎟⎠ ⎝ PV = .045 4 = $24051.19 −40 ⎛ .055 ⎞ 3000[1 − ⎜ 1 + 12 ⎟⎠ ⎝ PV = .055 12 = $276430.75 −10×12 ] 3. ] Cliff will need to invest $276 430.75 now so that he can withdraw $3000 per month for the next ten years. Copyright © 2007, Durham Continuing Education Page 34 of 38 MAP4C – Foundations for College Mathematics Support Question Answers Lesson 3: 1 a. ⎛ .06 ⎞ R[1 − ⎜ 1 + 12 ⎟⎠ ⎝ 140000 = .06 12 140000 = 166.792R 140000 166.792R = 166.792 166.792 839.37 = R b. −12×30 ⎛ .0525 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 200000 = .0525 12 200000 = 166.876R 200000 166.876R = 166.876 166.876 1198.49 = R ] c. ⎛ .062 ⎞ R[1 − ⎜ 1 + 12 ⎟⎠ ⎝ 175000 = .062 12 175000 = 137.355R 175000 137.355R = 137.355 137.355 1274.07 = R 2 −12×25 ] d. −12×20 ] ⎛ .0595 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 350000 = .0595 12 350000 = 155.946R 350000 155.946R = 155.946 155.946 2244.37 = R −12×25 ] a. 839.37 x 360 = 302 173.20 302 173.20 – 140 000.00 = $162 173.20 in interest b. 1198.49 x 300 = 359 547.00 359 547.00 – 200 000.00 = $159 547.00 in interest c. 1274.07 x 240 = 305 776.80 305 776.80 – 175 000.00 = $130 776.80 in interest d. 2244.37 x 300 = 673 311.00 673 311.00 – 350 000.00 = $323 311.00 in interest Copyright © 2007, Durham Continuing Education Page 35 of 38 MAP4C – Foundations for College Mathematics Support Question Answers 3. down payment = $225 000.00 x 0.25 = $56250.00 mortgage needed = 225 000.00 – 56 250.00 = 168 750.00 ⎛ .0725 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 168 750 = .0725 12 168 750 = 146.590R 168 750 146.590R = 146.590 146.590 1151.17 = R −12×30 ] 4. payment for 1st 5 years ⎛ .07 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 125000 = .07 12 125000 = 141.538R 125000 141.538R = 141.538 141.538 883.16 = R balance after 5 years of payments −12×25 ] ⎛ .07 ⎞ 883.16[1 − ⎜ 1 + 12 ⎟⎠ ⎝ PV = .07 12 PV = 113947.48 −12×20 ] New monthly payment ⎛ .065 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 113947.48 = .065 12 113947.48 = 134.125R 113947.48 134.125R = 134.125 134.125 849.56 = R −12×20 ] Copyright © 2007, Durham Continuing Education Page 36 of 38 MAP4C – Foundations for College Mathematics Support Question Answers Lesson 4: 1. a. Payment Number 0 1 Monthly Interest Payment Paid $1340.37 .0825 170000( ) = 1168.75 12 2 $1340.37 3 $1340.37 4 $1340.37 5 $1340.37 6 $1340.37 169828.38( .0825 ) = 1167.57 12 169655.58( .0825 ) = 1166.38 12 169481.59( .0825 ) = 1165.19 12 169306.41( .0825 ) = 1163.98 12 169130.02( .0825 ) = 1162.77 12 Principal Paid 1340.37– 1168 .75 = $171.62 1340.37– 1167 .57 = $172.80 1340.37– 1166 .38 = $173.99 1340.37– 1165 .19 = $175.18 1340.37– 1163 .98 = $176.39 1340.37– 1162 .77 = $177.60 Outstanding Principal $170 000 170 000 – 171.62= $169 828.38 169 828.38 – 172.80= $169 655.58 169 655.58 – 173.99= $169 481.59 169 481.59– 175.18= $169 306.41 169 306.41– 176.39= $169 130.02 169 130.02– 177.60= $168 952.42 2. 1168.75 + 1167.57 + 1166.38 + 1165.19 + 1163.98 + 1162.77 = $6994.64 in interest paid. 3. 171.62 + 172.80 + 173.99 + 175.18 + 176.39 + 177.60 = $1047.58 paid to the principal 4. ⎛ .08 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 125 000 = .08 12 125 000 = 119.554R 125 000 119.554R = 119.554 119.554 1045.55 = R −12×20 ] Copyright © 2007, Durham Continuing Education Page 37 of 38 MAP4C – Foundations for College Mathematics 4. Support Question Answers Continued… Payment Number 0 1 Monthly Interest Payment Paid $1045.55 .08 125000( ) = 833.33 12 2 $1045.55 3 $1045.55 4 $1045.55 5 $1045.55 6 $1045.55 124787.78( .08 ) = 831.92 12 124574.15( .08 ) = 830.49 12 124359.08( .08 ) = 829.06 12 124142.59( .08 ) = 827.62 12 123924.66( .08 ) = 826.16 12 Principal Paid 1045.55– 833 .33 = $212.22 1045.55– 831.92= $213.63 1045.55– 830 .49 = $215.06 1045.55– 829 .06 = $216.49 1045.55– 827 .62 = $217.93 1045.55– 826 .16 = $219.39 Outstanding Principal $125 000 125 000 – 212.22= $124 787.78 124 787.78– 213.63= $124 574.15 124 574.14 – 215.06= $124 359.08 124 359.08– 216.49= $124 142.59 124 142.59– 217.93= $123 924.66 123 924.66– 219.39= $123 705.27 Lesson 5: 1 a. ⎛ .0705 ⎞ R [1 − ⎜ 1 + 12 ⎟⎠ ⎝ 210 000 = .0705 12 210 000 = 140.851R 210 000 140.851R = 140.851 140.851 1490.94 = R −12×25 ] b. answers vary 2200 + 400 = $2074.27 12 Option B: 1250 + 375 = $1625.00 c. Option A: 1490.94 + d. answers vary Copyright © 2007, Durham Continuing Education Page 38 of 38