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t
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i
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= 0.
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4
Re
qu
i
r
e
d:
p
u
r
c
h
as
ep
r
i
c
epan
db
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n
ddi
s
c
o
u
n
tDb.
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r
mu
l
a:
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i–b
)
( )
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1
1
+1
i
p=Rv–Db
Co
mp
u
t
at
i
o
n
s
:
)
(
1
(
1
+0.
041
25
Db=50,
000(
0.
041
25–0.
04)
0.
041
25
)
(
0.
91
1
5497
35
Db=50,
000(
0.
001
25)
=50,
000(
0.
001
25)(
22.
0981
7
541
)
0.
041
25
Db=P1
,
381
.
1
4
p=50,
000=1
,
381
.
1
4=P48,
61
8.
86
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h
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amp
l
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dwi
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ds
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x
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.
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l
u
t
i
o
n
:
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v
e
n
:
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j=1
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.
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r
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5
b=1
t=1
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2%=0.
1
2
m =2
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1
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b=
=0.
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5
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n=2(
1
0.
5)=21
Re
qu
i
r
e
d:
p
u
r
c
h
as
ep
r
i
c
epan
db
o
n
dp
r
e
mi
u
mPb.
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r
mu
l
a:
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b–i
)
Co
mp
u
t
at
i
o
n
s
:
Pb=36,
000(
0.
07
5–0.
06)
( )
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1
1
+i
i
p=Pv+Rb
)
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(
Pb=36,
000(
0.
01
5)
Pb=P6,
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60
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1
2
i=
=0.
06
2
(
1
+0.
06)
1
0.
06
)
0.
7
05644597
=36,
000(
0.
01
5)(
1
1
.
7
6407
662)
0.
06
p=36,
000+6,
352.
60=P42,
352.
60
T
h
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dt
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n
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mi
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