Calculations: Part I: Variation of the Piezometric Head along the Venturi Meter. Flow Rate Q: π= πΈππ ππππ’ππ − ππ‘πππ‘ ππππ’ππ ππππ π= 10πΏ − 0πΏ = 0.16722 πΏ/π 59.8π π = 0.16722 πΏ/π × 1π3 = 0.00016722π3 /π 1000πΏ Converting Piezometric Head: Piezometric Table No. 1 Piezometric Table No.2 1π 1π β = 275 ππ × 1000ππ = 0.275π β = 215 ππ × 1000ππ = 0.215π Piezometric Table No. 3 Piezometric Table No.4 β = 142 ππ × 1π 1000ππ = 0.142π β = 65 ππ × Piezometric Table No. 5 β = 5ππ × 1π 1000ππ 1π 1000ππ = 0.065π Piezometric Table No.6 = 0.005π β = 153ππ × 1π 1000ππ = 0.153π Area of the Tube: Piezometric Table No. 1 π= π(24.5ππ× 2 1π ) 1000ππ 4 Piezometric Table No.2 = 0.0004714π 2 Piezometric Table No. 3 π= π(11.6ππ× 2 1π ) 1000ππ 4 Piezometric Table No. 1 π= π(13.6ππ× 2 1π ) 1000ππ 4 = 0.0001452π2 Piezometric Table No.4 = 0.0001057π 2 π= π(10.5ππ× 2 1π ) 1000ππ 4 Piezometric Table No.2 = 0.0000866π2 π= π(9.8ππ× 2 1π ) 1000ππ 4 = 0.0000754π 2 π= π(24.5ππ× 2 1π ) 1000ππ 4 = 0.0004714π2 Velocity: Piezometric Table No. 1 π= 0.00016722π3 /π 0.0004714π2 = 0.354713 π/π Piezometric Table No. 3 π= 0.00016722π3 /π 0.0001057π2 = 1.58232 π/π Piezometric Table No. 5 π= 0.00016722π3 /π 0.0000754π2 = 2.21696 π/π Piezometric Table No.2 π= 0.00016722π3 /π 0.0001452π2 = 1.15115 π/π Piezometric Table No.4 π= 0.00016722π3 /π 0.0000866π2 = 1.93121 π/π Piezometric Table No.6 π= 0.00016722π3 /π 0.0004714π2 = 0.35471 π/π Velocity Head: Piezometric Table No. 1 Piezometric Table No.2 0.354713 π/π 1.15115 π/π 9.81π 2( 2 ) π = 0.00685 π 2( 9.81π ) π 2 = 0.07218 π Piezometric Table No. 3 Piezometric Table No.4 1.58232 π/π 1.93121 π/π 2( 9.81π ) π 2 = 0.13637 π 2( 9.81π ) π 2 = 0.20314 π Piezometric Table No. 5 Piezometric Table No.6 2.21696 π/π 0.35471 π/π 9.81π 2( 2 ) π = 0.2677 π Total Head: 2( 9.81π ) π 2 = 0.00685 π Piezometric Table No. 1 0.275π + 0.354713 π/π 2( 9.81π ) π 2 Piezometric Table No.2 = 0.28185 π Piezometric Table No. 3 0.142π + 1.58232 π/π 2( 9.81π ) π 2 2.21696 π/π 2( 9.81π ) π 2 1.15115 π/π 9.81π ) π 2 2( = 0.28718 π Piezometric Table No.4 = 0.27837 π Piezometric Table No. 5 0.005π + 0.215π + 0.065π + 1.93121 π/π 2( 9.81π ) π 2 = 0.26814 π Piezometric Table No.6 = 0.2727 π 0.153π + 0.35471 π/π 2( 9.81π ) π 2 = 0.15985 π Part 2: Calibration of the Venturi Meter: Flow Rate at Each Trial: Trial 1: π= 10πΏ−0πΏ 59.8π Trial 2: 1π3 × 1000πΏ = 0.000167 π3 /π Trial 3: π= 10πΏ−0πΏ 74.99π 10πΏ−0πΏ 66.57π 1π3 × 1000πΏ = 0.00015 π3 /π Trial 4: 1π3 × 1000πΏ = 0.000133 π3 /π Trial 5: 10πΏ−0πΏ π= π= 10πΏ−0πΏ 79.28π 1π3 × 1000πΏ = 0.000126 π3 /π Trial 6: 1π3 π = 119.03π × 1000πΏ = 0.000084 π3 /π π= 10πΏ−0πΏ 253.1π 1π3 × 1000πΏ = 0.000040 π3 /π Height Difference: Trial 1: Trial 2: 1π 1π ββ = (275ππ − 5ππ) × 1000π = 0.27π βh = (245ππ − 40ππ) × 1000π = 0.205π Trial 3: Trial 4: ββ = (220ππ − 50ππ) × 1π 1000π = 0.17π Trial 5: ββ = (180ππ − 113ππ) × 1π 1000π = 0.146π Trial 6: 1π ββ = (180ππ − 113ππ) × 1000π = 0.067π 1π ββ = (161ππ − 147ππ) × 1000π = 0.014π Value of B: Assuming trial 5 diameter as throat diameter and trial 1 diameter as pipe diameter 9.81π 2( 2 ) π π΅ = 0.000075π √ 2 0.000075π2 1−( ) 0.000471π2 2π π΅ = π5 √ π 2 1 − (π5 ) 1 2 5 π ⁄2 π΅ = 0.0003385 π Discharge Coefficient: Trial 1: πΆ= Trial 2: 0.000167 π3 /π 5⁄ π 2 0.0003385 √0.27π π = 0.95081 = 0.98022 Trial 4: 0.000133 π3 /π 5⁄ π 2 0.0003385 √0.17π π = 0.95554 0.000126 π3 /π πΆ= 5⁄ π 2 √0.146π π = 0.9753 0.0003385 Trial 5: πΆ= 5⁄ π 2 √0.205π π 0.0003385 Trial 3: πΆ= 0.00015 π3 /π πΆ= Trial 6: π3 π 0.000084 5⁄ π 2 0.0003385 √0.067π π = 0.95892 Average Discharge Coefficient: πΆ= 0.000040 π3 /π 5⁄ π 2 0.0003385 √0.014π π = 0.98655 πΆππ£π = 0.95081+0.98022+0.95554+0.9753+0.95892+0.98655 6 =0.967890109 From the plot, Q vs. (h1-hT)1/2 y = 0.000326268x Discharge Coefficient: πΆππππ‘ = 0.000326268 π΅ = 0.000326268 0.0003385 = 0.9638641064 Average of Cavg and Cplot: πΆπππππ = 0.967890109+0.9638641064 2 =0.96591681 Reynolds Number: ο Assuming throat diameter is 0.0098m, area is 0.00007543m2 ο Temperature is at 25β ο ρ of water is 997.08 kg/m3 ο μ of water is 0.8937×10-3 Pa-s Trial 1: ππ π = Trial 2: π3 997.08ππ 0.0098π(0.000167 )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) ππ π = π3 997.08ππ )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) 0.0098π(0.00015 ππ π =24239.35761 ππ π =21774.2765 Trial 3: Trial 4: ππ π = π3 997.08ππ 0.0098π(0.000133 )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) ππ π = π3 997.08ππ )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) 0.0098π(0.000126 ππ π =19329.42506 ππ π =18283.47105 Trial 5: Trial 6: ππ π = π3 997.08ππ 0.0098π(0.000084 )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) ππ π =12177.71642 ππ π = π3 997.08ππ )( ) π π3 0.00007543m2 (0.8937×10−3 ππβπ ) 0.0098π(0.000040 ππ π =5727.039056 Pressure Drop: Trial 1: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.27π) Trial 2: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.205π) βπ =2640.965796 Pa βπ =2005.177734 Pa Trial 3: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.17π) Trial 4: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.146π) βπ = 19329.42506 Pa βπ = 18283.47105 Pa Trial 1: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.067π) Trial 2: βπ = (997.08ππ/π3 )(9.81π/π 2 )(0.014π) βπ = 12177.71642 Pa βπ = 5727.039056 Pa