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Junior Cert Trigonometry

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2nd Year
Maths
Higher Level
Carl Brien
Trigonometry
“The secret of getting ahead is getting started.”
Mark Twain
No part of this publication may be copied, reproduced or transmitted in any form or by any
means, electronic, mechanical, photocopying, recording, or otherwise, without prior written
permission from The Dublin School of Grinds. (Notes reference: 2-mat-h-trigonometry).
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Trigonometry is worth 5% to 7% of the Junior Cert.
It appears on Paper 2.
Contents 1)
Pythagoras ............................................................................................................................................................................3 3)
Minutes................................................................................................................................................................................ 17 2)
4)
5)
6)
7)
8)
Sin, Cos, Tan ...................................................................................................................................................................... 11 Angles of elevation/depression................................................................................................................................ 20 From one to another...................................................................................................................................................... 26 Evaluating trigonometric functions........................................................................................................................ 29 Past and probable exam questions ......................................................................................................................... 30 Solutions ............................................................................................................................................................................. 48 © The Dublin School of Grinds
Page 2
Carl Brien
1) Pythagoras
Pythagoras is a famous rule of trigonometry which comes up every single year in the Junior Cert.
On page 16 of The Formulae and Tables Booklet you will see the following:
Note: Be careful with the letters a, b and c because the examiner often labels the triangles in your Junior Cert with these
letters, but they may have nothing to do with these letters in Pythagoras’ Theorem.
The way I like to remember this is: (π‘™π‘œπ‘›π‘”π‘’π‘ π‘‘ 𝑠𝑖𝑑𝑒)! = (π‘œπ‘‘β„Žπ‘’π‘Ÿ 𝑠𝑖𝑑𝑒)! + (π‘œπ‘‘β„Žπ‘’π‘Ÿ 𝑠𝑖𝑑𝑒)!
Note: The longest side is always the one across from the right angle.
Question 1.1 Find the length of π‘₯.
x
3
4
Comments ©The Dublin School of Grinds
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Carl Brien
Question 1.2 Find the length of 𝑦.
y
12
13
Note: Sometimes we are asked to write our answer in ‘surd form’. ‘Surd form’ is just another phrase for ‘square root’, so
it just means there will be a square root in our answer.
Question 1.3 Find 𝑧, in surd form.
7
4
z
Question 1.4 π‘Žπ‘π‘ is an isosceles triangle with:
π‘Žπ‘ = |𝑏𝑐|, π‘Žπ‘ = 72 and β¦Ÿπ‘Žπ‘π‘ = 90°. ind |𝑏𝑐|.
a
√72
c
b
Comments ©The Dublin School of Grinds
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Carl Brien
Question 1.5 The lengths of the sides of a right angled triangle are as shown in the diagram.
2x + 2
i) Using the theorem of Pythagoras, write an equation n π‘₯.
x + 1
x + 2
ii) Solve this equation to find π‘₯ correct to 2 decimal places.
Comments ©The Dublin School of Grinds
Page 5
Carl Brien
Note: Sometimes the examiner gives us a real life situation which requires the use of Pythagoras. You can also be asked
to list the assumptions you have made. Don’t let this confuse you. hink bout he ext xample:
When fire occurs in high raise buildings, the firefighters cannot use the regular stairs or lifts. They can reach some
floors using ladders. In order to determine the ladder length, they apply the Pythagorean Theorem as they can estimate
the height of the floor affected and the horizontal distance they can use to keep the ladder in position.
Question 1.6 Dublin Fire Brigade use their 10 metre ladder to reach the 3rd storey of an apartment block. The windowsill on the 3rd
storey is 8 metres above the ground. Find the distance from the foot of the ladder to the base of the building.
Comments ©The Dublin School of Grinds
Page 6
Carl Brien
Question 1.7 A plane takes 4 hours to travel from Dublin to Madrid at a speed of 575 km/h. The distance from Madrid to Rome is
1300 km. Find the distance from Rome to Dublin correct to the nearest kilometre. List any assumptions you have made.
Comments ©The Dublin School of Grinds
Page 7
Carl Brien
Question 1.8 A kite is held by a string 13 metres long.
hen lown n he
ind t s
etres above the ground. How far is the point A from B, correct to the nearest metre? List any assumptions you have made.
Comments ©The Dublin School of Grinds
Page 8
Carl Brien
Question 1.9 Show that Sutton is 14km further from Birmingham than Walsall is from Birmingham.
Walsall
Sutton
26km
8km
Oldbury
6km
Birmingham
Comments ©The Dublin School of Grinds
Page 9
Carl Brien
Question 1.10 The height of a wooden goal post is 2.5m and the width is 7m James wants to play a prank by nailing X bars on the goal as shown: What is the minimum total length of wood that James needs to make the prank a success, correct to the nearest metre? Comments ©The Dublin School of Grinds
Page 10
Carl Brien
2) Sin, Cos, Tan
On page 16 of The Formulae and Tables Booklet you will see the following:
However, as with Pythagoras, the letters a, b and c can be very confusing. Therefore you must learn the rules a different
way, as follows:
𝑆𝑖𝑛 =
π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’
β„Žπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’
πΆπ‘œπ‘  =
π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘
β„Žπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’
π‘‡π‘Žπ‘› =
The way to remember these formulae is: π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’
π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘
SOH CAH TOA
or Silly Old Harry, Caught A Herring, Trawling Off America
or Some Old Horses, Can Always Hear, Their Owners Approaching
Comments ©The Dublin School of Grinds
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Carl Brien
To use these formulae, you clearly have to know how to label the sides of a triangle:
The hypotenuse is the side across from the right angle. The opposite is the side across from the angle we are using. The adjacent is the other side. hyp
x opp
or x hyp
adj
adj
opp
Note:
You should always label your triangle sides. When labelling the sides we can use the nicknames
β„Žπ‘¦π‘, π‘œπ‘π‘, π‘Žπ‘‘π‘—. on’t se β„Ž, π‘œ, π‘Ž because the letter β„Ž often gets mixed up with ‘β„Žπ‘’π‘–π‘”β„Žπ‘‘’. Note:
In these questions you will often end up with something like π‘π‘œπ‘ π‘₯ =
π‘₯ = cos !!
!
!
Casio: π‘†β„Žπ‘–π‘“π‘‘, π‘π‘œπ‘ 
!
!
, o o ind π‘₯ you write
. This is called cos inverse. The way you get this on your calculator is by pressing:
Sharp: 2𝑛𝑑 πΉπ‘’π‘›π‘π‘‘π‘–π‘œπ‘›, π‘π‘œπ‘ 
If you’re using a Sharp, make sure to include the brackets after the π‘π‘œπ‘  !! .
If you’re using a Casio, the brackets are automatically included J.
You should get 30 as your answer.
Note:
You need to make sure your calculator is in ‘degrees’ mode (there are other more complicated modes you must
use at Leaving Cert but at Junior Cert the examiner can only ask you questions in degrees).
To check if your calculator is in degrees mode:
Casio: There should be a little ‘D’ at the top of the screen.
Sharp: There should be a little ‘DEG’ at the top of the screen.
If your calculator isn’t in degrees mode you can change it as follows:
Casio: π‘†β„Žπ‘–π‘“π‘‘, π‘€π‘œπ‘‘π‘’, 3 Comments ©The Dublin School of Grinds
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Carl Brien
Sharp: 𝑆𝑒𝑑𝑒𝑝, 0, 0 Note: if you have any problems with your calculator make sure to ask me. Your calculator is a sound chap, you just have
to know how to deal with him.
Question 2.1 Find the measure of the angle x.
Question 2.2 In the triangle 𝐴𝐡𝐢, 𝐡𝐢 = 1 and 𝐴𝐡 = 3.
Find ∠𝐡𝐴𝐢 .
Comments ©The Dublin School of Grinds
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Carl Brien
Note: s
ell s sing in, os
Question 2.3 an o ind angles,
e an se hem o ind sides:
Find x, orrect o hree ecimal laces. Question 2.4 Calculate the measure of the angle 𝐡, correct to the nearest degree
9
B
40
Comments ©The Dublin School of Grinds
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Carl Brien
Question 2.5 Find π‘₯, correct to one decimal place. Note: e areful ith our lgebra t he nd f his uestion!!!
17
x
30˚
Question 2.6 An architect’s view of Leinster Rugby’s proposed new North Strand at The RDS is given below:
The architect has informed the engineer of the following specifications: |AB|=5m |AC|=15m |⦟DAB|=40˚ Find (i) |AD| correct to two decimal places (ii) |DC| correct to two decimal places
Comments ©The Dublin School of Grinds
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Carl Brien
Comments ©The Dublin School of Grinds
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Carl Brien
3) Minutes
You must be able to change angles from decimals to a thing called ‘minutes’.
For example: Change 37.36° to the nearest minute.
Casio:
Sharp: You should get 37°21′36"
To change from decimals to minutes, type in the number with the decimal, then press the
button with all the commas (2 buttons above number 8), then press equals. To change from decimals to minutes type in the number with the decimal, then press 2nd
function, then DMS. The 37 is the degrees, the 21 is the minutes and the 36 is a thing called seconds. If your value for seconds is 30 or
greater you round up. If it is less than 30 you round down. Therefore we will round up: 37°22 Question 3.1 Change 50.27° to the nearest minute.
Question 3.2 Change 50.38° to the nearest minute.
Comments ©The Dublin School of Grinds
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Carl Brien
Question 3.3
Change 60.73° to the nearest minute.
Question 3.4
Change 12.39° to the nearest minute.
Sometimes an angle will be given to you in degrees and minutes so you have to be careful when putting this into your
calculator. For example: Find sin 31°26′ correct to 4 decimal places.
Casio Calculator:
Sharp Calculator: Press Sin, hen 1, hen he omma utton, hen 26, then the comma button again, then
equals. Press Sin, then 31, then the DMS button, then 26, then the DMS button again, hen quals. You should get 0.5215061194 (depending on your calculator you may even get more decimal places). We are asked to round off to 4 decimal places so our answer is 0.5215 Question 3.5 Evaluate sin 35°7′ to four decimal places.
Question 3.6 Comments ©The Dublin School of Grinds
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Carl Brien
Evaluate cos 40°8′ to four decimal places. Question 3.7 Evaluate tan 52°29′ to three decimal places. Question 3.8 Evaluate sin 12°98′ to three decimal places. Question 3.9 Evaluate cos 82°33′ to four decimal places. Comments ©The Dublin School of Grinds
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Carl Brien
4) Angles of elevation/depression There are two other points we must know to help us with ‘real life’ scenarios: i)
Angle of elevation: This is the angle your line of vision makes with the horizontal when looking up: Li
ig
of s
ne ht Angle of elevation Horizontal ii)
Angle of depression: This is the angle your line of vision makes with the horizontal when looking down: Horizontal Line of s
ig
Angle of depression ht Comments ©The Dublin School of Grinds Page 20 Carl Brien Question 4.1 A boat is anchored off the coast near 100m high cliffs in Co. Kerry. The angle of elevation from the boat to the cliff top is
15˚. he ext day the boat moves further towards land and anchors again. This time the angle of elevation is 38˚. ow
far did the boat move? Give your answer correct to the nearest metre and make assumptions as necessary, stating them clearly. Comments ©The Dublin School of Grinds
Page 21
Carl Brien
Question 4.2 A boat sails due east from the base, A, of a 30m high lighthouse, [AD]. t he oint B the angle of depression of the boat
from the top of the lighthouse is 68°. en econds ater he oat s t he oint C and the angle of depression is now 33°.
i)
ii)
Find |BC|, he istance he oat as ravelled n his ime.
Calculate the average speed at which the boat is sailing between B and C. ive our nswer n
second, correct to one decimal place.
D
etres er
30m
A
B
C
Comments ©The Dublin School of Grinds
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Carl Brien
Question 4.3 The beach at Brittas Bay slopes downwards at a constant angle of 12˚ to the horizontal. How far out into the sea can a
man walk before the water covers his head? Make assumptions as necessary. Comments ©The Dublin School of Grinds
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Carl Brien
Note: If you’re asked to “explain your answer”, simply explain it with maths.
For example, in the question below the answer is Yes or No. When they ask you to explain your choice, don’t waffle.
Explain using methods like Pythagoras, sin, cos, tan etc.
Question 4.4 The city council decides to construct a ramp for the local skate park. Before they start construction, they ask some
skaters for their advice:
“We want a ramp that is 3 meters high at the top, but we don’t want the angle of elevation to be more than 20˚.” The city council comes up with a design. The design has the ratio of max height to ramp length of 3:8. Does this designs fit in with the skaters requests? Explain your answer.
Comments ©The Dublin School of Grinds
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Carl Brien
Question 4.5 A builder called Mark wants to build a canopy roof. Since he is worried about the chance of collapse due to the weight of
snow, he asks the advice of a friend in Canada who is in the building trade. His Canadian friend says that it is best to
build a roof with a pitch greater than 40˚ so that the snow will not accumulate. Mark’s design for the roof is illustrated
below:
3.5 m
8 m
Has Mark followed the advice of his friend? Explain your answer. Comments ©The Dublin School of Grinds
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Carl Brien
5) From one to another
We can be given what 𝑆𝑖𝑛, πΆπ‘œπ‘  or π‘‡π‘Žπ‘› is equal to and then from this be asked to find another one.
There are 5 steps:
1) Sketch a right angled triangle.
2) Label the angles given.
3) Label the two sides given.
4) Find the missing side using Pythagoras.
5) Fill out the answer.
Question 5.1 If 𝑠𝑖𝑛π‘₯ =
!
!
, find the value of cos π‘₯.
Comments ©The Dublin School of Grinds
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Carl Brien
Question 5.2 Given that Tan A = 4, write CosA in the form
!
!
, x ∈ N.
Question 5.3 !
! !
!
!
Given that Cos x = , write Sin x in the form
, a, b ∈ N
Comments ©The Dublin School of Grinds
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Carl Brien
Sometimes they actually give you the triangle, which is handy J.
Question 5.4 Use the information given in the diagram to find Sin A and Cos A. ive our nswer n urd orm.
7
A
2
Comments ©The Dublin School of Grinds
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Carl Brien
6) Evaluating trigonometric functions
This section sounds complicated but these types of questions are actually embarrassingly easy. You simply use page 13
of the Formulae and Tables booklet, or your calculator.
Note: If given Sin! θ, we rewrite this as (Sin θ)! . The same rule applies for Cos and Tan. f sing our calculator, you
must put in the brackets!
Question 6.1 Evaluate: Sin! 30˚ + Tan! 45˚. Question 6.2 Evaluate: 1 − 2π‘‡π‘Žπ‘›! 45°. Question 6.3 Verify that:
!"#!"°!"#!"° ! !
!"# ! !"°
=4
Comments ©The Dublin School of Grinds
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Carl Brien
7) Past and probable exam questions
Question 1 ©The Dublin School of Grinds
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Carl Brien
Question 2 ©The Dublin School of Grinds
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Carl Brien
Question 3 a)
b)
c)
d)
(More space for your solution on next page) ©The Dublin School of Grinds
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Carl Brien
©The Dublin School of Grinds
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Carl Brien
Question 4 ©The Dublin School of Grinds
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Carl Brien
Question 5 ©The Dublin School of Grinds
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Carl Brien
Question 6 ©The Dublin School of Grinds
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Carl Brien
Question 7 ©The Dublin School of Grinds
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Carl Brien
Question 8 ©The Dublin School of Grinds
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Carl Brien
©The Dublin School of Grinds
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Carl Brien
Question 9 ©The Dublin School of Grinds
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Carl Brien
©The Dublin School of Grinds
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Carl Brien
Question 10 ©The Dublin School of Grinds
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Carl Brien
Question 11 ©The Dublin School of Grinds
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Carl Brien
Question 12 ©The Dublin School of Grinds
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Carl Brien
Question 13 ©The Dublin School of Grinds
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Carl Brien
Question 14 ©The Dublin School of Grinds
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Carl Brien
Question 15 (Note: this question contains a mixture of topics)
©The Dublin School of Grinds
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Carl Brien
8) Solutions
Question 1.1 x2 = 42 + 32
x2 = 16 + 9
x2 = 25
x = 5
Question 1.2 132 = 122 + y2
169 = 144 + y2
169 144 = y2
25 = y2
⟹y=5
Question 1.3 7 2 = 4 2 + z2
49 = 16 + z2
49 – 16 = z2
33 = z2
⟹ z = 33
Question 1.4 ( 72 )2 = |ac|2 + |bc|2
72 = 2π‘₯ 2 (Remember: |ac| = |bc|)
!"
= x2
!
36 = x2
36 = x = 6
Question 1.5 (2x+2)2 = (x+2)2 + (x+2)2
1) (2x+2)(2x+2) = 4x2 + 4x + 4x + 4 = 4x2 + 8x + 4
2) (x+1)(x+1) = x2 + 2x + 1
3) (x+2)(x+2) = x2 + 4x + 4
∴ 4x2 + 8x + 4 = x2 + 2x + 1 + x2 + 4x + 4
4x2 + 8x + 4 = 2x2 + 6x + 5
2x2 + 2x 1
a = 2, b = 2, c = 1
!!± ! ! !!!"
!!
=
=
=
!!± !! !!(!)(!!)
!(!)
!!± !! !!(!)(!!)
!(!)
!!± !!! !!± !"
!
!!! !"
=
!
!!± !"
x=
or x=
!
!
x = 0.37 or x= 1.37
©The Dublin School of Grinds
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Carl Brien
Question 1.6 (10)! = π‘₯ ! + (8)!
100 = π‘₯ ! + 64
100 − 64 = π‘₯ !
36 = π‘₯ !
36 = π‘₯
6 π‘š = π‘₯
Question 1.7 (π‘₯)! = 2300 ! + (1300)!
π‘₯ ! = 5,290,000 + 1,690,000
π‘₯ ! = 6,980,000
π‘₯ = 6,980,000
π‘₯ = 2641.968963 π‘˜π‘š
x = 2642 km
Question 1.8 Assume that the kite (length of string) is at its longest which is 13 m.
132 = 92 + |AB|2
169 = 81 + |AB|2
88 = |AB|2
|AB| = 88
|AB=9m|
Question 1.9 Find distance from Walsall to Birmingham
hyp2 = 82 + 62 ⟹ hyp2 = 64 + 36 ⟹ hyp2 = 100 ⟹ hyp = 10
Now find distance from Sutton to Birmingham
262 = 102 + x2
676 = 100 + x2
676 – 100 = x2
x2 = 576
x = 576 = 24
Sutton is 14km further from Birmingham than Walsall is from Birmingham.
©The Dublin School of Grinds
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Carl Brien
Question 1.10 hyp2 = 72 + 2.52
hyp2 = 49 + 6.25
hyp2 = 55.25
hyp = 55.25
hyp = 7.433
We need two planks so we need to multiply 7.433 by 2 = 14.866. The minimum length, correct to the nearest metre, is 15m.
Question 2.1 !
x = sin 1( ) = 30o
!
Question 2.2 !
|∠𝐡𝐴𝐢| = tan 1 ( ) = 30o
!
Question 2.3 !
cos 45o =
!"
40 cos 45o = x
x = 28.284
©The Dublin School of Grinds
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Carl Brien
Question 2.4 !"
B = tan 1( ) = 77o
!
Question 2.5 tan 30o =
x=
Question 2.6 (i) Find |AD|
(ii) Find |DC|
x=
!"
!"# !"
!"
!
= 29.4
Cos 40o =
!
!"# !"
!
!
= 6.53m
First get |DB|:
6.532 = 52 + x2
42.6409 = 25 + x2
17.6409 = x2
x = 4.2m
|DC|2 = 102 + 4.22
|DC|2 = 117.6409
|DC| = 117.6409
|DC| = 10.85
©The Dublin School of Grinds
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Carl Brien
Question 3.1 50.27° to the nearest minute
= 50° 16’
Question 3.2 50.38° to the nearest minute
= 50° 23’
Question 3.3 60.73° to the nearest minute
= 60° 44’
Question 3.4
60.73° to the nearest minute
= 60° 44’
Question 3.5 Sin 35° 7’ = 0.5752
Question 3.6 Cos 40° 8’ = 0.7645
Question 3.7 Tan 52° 29’ = 1.302
Question 3.8 Sin 12° 98’ = 0.236
Question 3.9 Cos 82° 33’ = 0.1297
Question 4.1 Tan 15° =
!""
!""
!
Tan 35° =
!""
!""
!
y=
x=
!"# !"°
!"# !"°
x = 373.21m
y = 128m
π·π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘šπ‘œπ‘£π‘’π‘‘ = π‘₯ − 𝑦
= 373.21 − 128
= 245π‘š
Question 4.2 (i)
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Carl Brien
!"
Tan 68° =
⇒ |AB| =
|!"|
!"
!"# !"°
= 12.121m
!"
Tan 33° =
⇒ |AC| =
|!"|
!"
!"# !!°
= 46.196m
∴ BC = AC – AB = 34.075 m
(ii)
π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ 𝑆𝑝𝑒𝑒𝑑 =
34.075π‘š
= 3.41 π‘š/𝑠
10 𝑠𝑒𝑐
Question 4.3 If the man is Carl, assume his height to be 1.5 m.
x is the distance Carl needs to walk out.
!.!
Tan 12° =
⇒x=
!
!.!
!"# !"° = 7.1m
Question 4.4 Ramp height =3m
!
θ = Sin 1( ) = 22°
!
No, as 22° > 20°
Question 4.5 ©The Dublin School of Grinds
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Carl Brien
!.!
θ = Tan 1( ) = 41.2°
!
He has followed the advice, as 41.2° > 40°
©The Dublin School of Grinds
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Carl Brien
Question 5.1 sin x =
!
!
42 = ( 7)2 + adj2
16 = 7 + adj2
9 = adj2
adj = 3
⇒ Cos x =
!"#
!!"
= !
!
Question 5.2 x2 = 42 + 12
x2 = 17
x = 17
!
⇒ Cos A =
!"
Question 5.3 72 = 12 + opp2
49 = 1 + opp2
opp2 = 48
opp = 48 = 4 3
Sin x =
©The Dublin School of Grinds
! !
!
Page 55
Carl Brien
Question 5.4 x2 = 72 + 22
x2 = 49 + 4
x2 = 53
x = 53
!
Sin A =
Cos A =
!"
!
!"
Question 6.1 Sin2 30° + Tan2 45° =
=1
!
!
!
!
+1
Question 6.2 1 – 2 Tan2 45° = 1 – 2
= –1
Question 6.3 Verify that
! ©The Dublin School of Grinds
!"# !"° !"# !"°!!
!"# ! !"°
!
!!
!
!
!
=
!
!
!
=4
=4
Page 56
Carl Brien
Solutions to past and probable exam questions Question 1 (a)
|!"|
Sin 60° =
!"
10(Sin 60°) = |AB|
|AB| = 8.66 cm
(b)
(i)
|!"|
Tan 65° =
!"
10 Tan 65° = |op|
|op| = 21.4 cm
(ii)
|∠ mon| = |∠ mop| + |∠ pon|
|∠ mop| = 25°
!".!
|∠ pon| = Cos 1( ) = 44.49°
!"
44.49° + 25° = 69.5°
Question 2 (i)
(ii)
Sin 30° =
!
!
!
⇒x=
!"# !"°
x=4
Use Pythagoras:
42 = 22 + adj2
16 = 4 + adj2
12 = adj2
adj = 12 = 2 3 = 3.464m
3.464 ×2 = y
y = 6.93m
©The Dublin School of Grinds
Page 57
Carl Brien
Question 3 (a)
Tan A = 4 ⇒ opp = 4 and adj = 1
x2 = 42 + 12
x2 = 16 + 1
x2 = 17
x = 17
!
Cos A =
(b)
!"
!"#
!
=
Cos =
!!"
!
2
π‘₯
= 3
9
x=
(c)
!(!)
!
=6
x2 = 72 + 22
x2 = 49 + 4
x = 53
Sin A =
Cos A =
(d)
!
!"
!
!"
32 = 22 + x2
9 = 4 + x2
x2 = 5
x= 5
Sin θ =
©The Dublin School of Grinds
!
!
Page 58
Carl Brien
Question 4 (i)
|ac|2 = 92 + 122
|ac|2 = 81 + 144
|ac| = 225 = 15
(ii)
Tan 36.87° =
⇒ |cd| =
(iii)
!"
!"# !".!"°
!"
|!"|
= 20π‘˜π‘š
Find |ad|
|ad|2 = 152 + 202
|ad|2 = 225 + 400
|ad|2 = 625
|ad| = 25km
Total length = 25 + 20 + 12 + 9 = 66km
Question 5 (i)
Tan 1
(ii)
!.!
!
Tan 28° =
= 28°
!
!"
13(Tan 28°) = x
x = 6.9m
Question 6 (a)
Sin 25° = 0.423, Cos 25° = 0.906, Tan 25° = 0.466
Sin 50° = 0.766, Cos 50° = 0.643, Tan 50° = 1.192
(b)
(i)
No. While Sin and Cos are always less than 1, tan is only less than 1 for angles less than 45°. (At 45°, opp = adj ⇒ Tan
45° = 1, Tan 50° = 1.192)
(ii)
No. Trigonometric functions are not linear.
!"# !"°
E.g.
= 1.8 ≠ 2
!"# !"°
(iii)
∴ Cos 40° < Cos 20° No. Cos reduces with increasing angle (for θ < 180°)
Cos 40° = 0.766, Cos 20 = 0.940
©The Dublin School of Grinds
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Carl Brien
Question 7 (a)
!
Tan 60° = ⇒ 3 x = h
!
(b)
Tan 30° =
1
! !
!"!!
3 x
24
−π‘₯
3
24 – x = 3x
24 = 4x
x=6
= h = 3(6) = 10.39m
Question 8 (a)
Angle of elevation = 65°
(b)
!
Tan 65° =
!"
h = 10(Tan 65°) = 21.45m
(c)
Total height of tree = 21.45m + 1.75m = 23.2m
(d)
He may not be as tall as Sean
Question 9 (a) (i)
(ii)
24
Tan A =
(b) (i)
!"
!
Cos 60° =
(ii)
!
!
|pr| : Cos 60° =
|!"|
!
!"
⇒ 12( ) = |pr| = 6
!
(c) (i)
|∠ bac| = 41° alternate angles
(ii)
Tan 41° =
⇒ |ba| =
©The Dublin School of Grinds
!"
|!"|
!"
!"# !"°
= 40.26
Page 60
Carl Brien
Ans. = 40m
Question 10 (a)
(b)
Sin 1 (0.5045) = 30.2982°
|!"|
Cos 50°48’ =
!"
20(Cos 50°48’) = |rq|
|rq| = 12.6m
(c)
Tan
Question 11 (a)
(b)
1
!
= = 50°
!
|AB|2 = |BC|2 + |AC|2
22 = 12 + |AC|2
4 = 1 + |AC|2
|AC|2 = 3
⇒ |AC| = 3
Cos ∠ BAC =
(c)
!
!
= 30°
x2 = 12 + 12
x2 = 2
x= 2
!
Cos 45° =
!
(d)
Cos 75° =
!! !
Cos 45° =
Cos 30° =
!
!
!
!
!
= 0.259
= 0.707
= 0.866
0.259 ≠ 0.707 + 0.866
©The Dublin School of Grinds
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Carl Brien
Question 12 (a)
The circumference will be used to calculate the radius of the Spire, which will help to give the full distance that Maria
is from the Spire.
2πr = 7.07m
r=
Tan 60° =
!.!"
!!
= 1.126
!
!".!"#
= 123.194 m
Add Maria’s height,
123.194 + 1.72
Ans = 125m
©The Dublin School of Grinds
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Carl Brien
Question 13 (a)
|∠ B| = 50°
Sin B = 0.766
(b)
!
Sin 50° =
!
⇒ 8(Sin 50°) = h
H = 6m
(c)
!
Area of ABC = Base × Height
!
!
= (7.5 × 6) = 22.5 cm2
!
Question 14 (a)
(b)
!
Tan 30° =
!"
⇒ x = 18 (Tan 30°) = 10.4m
We need to know what Jasmine’s height is and add it to the result we got in part (a).
©The Dublin School of Grinds
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Carl Brien
Question 15 (i)
Use construction 13 on page 67 of the notes.
(ii)
530
(iii)
cos 53° = 0.60181502
= 0.602 (correct to 3 decimal places)
(iv) Because the answer in part (ii) is rounded off to a whole number it gives a different answer.
©The Dublin School of Grinds
Page 64
Carl Brien
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