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Syarifuddin Husain
205644010
Soal No. 2 UAS
Diketahui
Reaksi adalah P
Ditanya : Tentukan Persamaan Laju Reaksinya
5R
10
0.01
47
3.196
259.8
Wkatalis
P
T
gram
Kg
psi
atm
K
3
5.5 cm /dt
19.8 L/jam
Laju Gas P
Run
1
2
3
4
Cain (mol/dm )
0.1500
0.1200
0.0900
0.0600
3
0.1260
0.1050
0.0825
0.0570
3
Caout (mol/dm )
PENYELESAIAN :
1. Cao Value
PV = nRT
Cao
0.1500
mol/L
Fao
2.9704
mol/jam
2. Fao Value
Fao = Cao * vo
3. Looking the Conditions : 2
Ca/Cao = (1-Xa)/(1+EaXa)
Xa = (1- (Ca/Cao))/(1+(Ea(Ca/Cao)))
4. Ea Value
Ea = (Koef. Product - Koef. Reactan
)/Koef. Reactan
Ea
4
Tabel Perhitungan
Run
1
2
3
Cain/Cao Caout/Cao
0.9999
0.8399
0.7999
0.6999
0.5999
0.5499
4
0.3999
0.3799
Plot
CaaV
0.1380
0.1125
-rA'
10.9015
9.3065
0.0863
0.0585
0
6.8258
4.5338
0
CaaV
0.1380
0.1125
0.0863
Xain
Xaout
0.000029 0.036729
0.047652 0.078982
0.117684 0.140664
DeltaXa
0.0367
0.0313
0.0230
-rA'
10.9015
9.3065
6.8258
0.0585
0.230812 0.246075
0.0153
4.5338
-rA' Vs CaaV
12.0000
10.0000
y = 80.01x
R² = 0.998
8.0000
6.0000
-rA'
4.0000
Linear (-rA')
2.0000
0.0000
-2.00000.0000
Maka, didapatkan pers. Laju reaksinya adalah :
-rA' = (80.01 L/hr.Kg Cat) * (CA, mol/L)
0.0500
0.1000
0.1500