SIME- DETAILED LESSON PLAN
MAY 14, 2021
I. OBJECTIVES:
At the end of the lesson the students will be able to:
a. Explain the Ohms law.
b. Identify the formula of Ohms law.
c. Solve the problem using the correct formula of Ohms law.
II. Content
a. Subject matter: OHMS LAW
b. Materials:
1. Laptop
2. Projector
c. References: https://www.introduction-electrical-electronics...from
various fundamental laws which include coulombs law, OHMS LAW.
III. A. Preparatory Activities.
*Prayer
*Checking of attendance
*Review / recall
Class can you still recall our previous topic?
Last meeting we were able to discussed about 3-way switch
B. Activity:
1.” GUESS THE WORD”
Direction: Group the students into 3. Form this letter into a word. Those
who make it first I will give you a prize, 2nd and 3rd group.
What was the word being formed?
Presentation of the lesson
This time we will learn the Ohms Law.
But before that please read the objectives
2. “Treasure Hunting” ( make a box and put the names of scientist about
OHMS LAW. (AMP-Frenchman Andre M. Ampere)
(VOLT- Italian Alexandro Volta)
(OHM- George Simon Ohm)
C. Analysis:
1. What is law?Political Science Integration
2. What is Theory?
3. What is the difference between law and theory
Law- is a rule or set of rules created and enforce through social
government institutions to regulate behavior.
4. Why do you think Ohms law is very applicable in electronics and
Electricity
D. Discussion:
Ohms Law Magic Triangle
V=VOLTAGE
I= CURRENT
R=RESISTAN
CE
Ohms law – defines the relationship between power, voltage, current and
resistance.(physics)
These basic electrical units apply to direct current, and alternating current..
Voltage- is measured in ” VOLTS”.
Symbolized by the letter “V”
Current- is measured in “Amps” Symbolized by the letter “I”
Resistance- is measured in “Ohms” symbolized by letter “R”
Quantity
current
symbol
voltage
resistance
E or V
R
I
unit of measurement
Ampere (Amp)
Volt
Ohm
To find Resistance
R=V/I
unit of abbriviation
A
V
Ω
To find Current
I=V/R
To find Voltage
V=IXR
1. A Motor with an operating resistance of 32 is connected to a voltage source .
The current in the circuit is 2A . What is the voltage of the source?
Given: R= 32Ω, I= 2A
Required: V=?
Equation:V= IR
Solution: V= (2A)(32Ω)
Answer: 64V
2. Find the current through a resistor of 24Ω. If the voltage across the resistor is
6V.
Given: R= 24Ω, V= 6V
Required: I=?
Equation:I= V/R
Solution: I= (120V)(12 Ω)
Answer: I=10A
3 . A small light bulb is connected to 6V battery and draws 2A of current. What is
the reisistance of the bulb?
Given: V= 6V, I= 2A
Required: R=?
Equation:R= V/I
Solution: R= (6V)(2A)
Answer: 3Ω
Power-
Ckt.
No.
Load
No. of
Outlets
Total rating in
Watts
Total rating
in
Ampere
1.
Lighting Outlets
9
900w
3.91A
2
Lighting Outlets
10
1,000w
4.35A
3
Convenience Outlets
6
2,160w
9.39A
4
Convenience Outlets
6
2,160w
9.39A
5
Range Outlet
1
8,000w
34.78A
6
Water heater Outlet
1
2,500w
10.86A
7
Aircon Unit Outlet
1
1,119w
4.87A
8
Aircon Unit Outlet
1
1,119w
4.87A
18,958w
82.42 A
Total Rating
III. Evaluation:
1. In a circuit 4A is flowing through the bulb. The voltage across the bulb
is 220V. What is the bulb resistance?
A. write the equation________________ R= V/I
b. replace the known value___________ R= 220V I= 4 A R= ?
c. solve___________________________ R= 55Ω
2. You light a bulb with a supply of 110V. If a bulb has a resistance of 10 ohms.
How much current is flowing.
a. write the equation ________________ I= V/R
b. replace the known values __________ V= 110V
R= 10Ω
I=?
c. solve___________________________ I= 11A
3. A motor with an operating resistance of 32 ohms. The current in the circuit
is 1.5A. What is the voltage of the source?
a. write the equation _________________ V= IXR
b. replace the known values ___________ I= 1.5A
R= 32 Ω
c. solve ____________________________ V= 48V
ANSWER KEY:
1. 55Ω
2. 11A
3. 48V
V. ASSIGNMENT:
What is series circuit and parallel circuit ( research )
V=?