Uploaded by subala

Ionic Bonding

advertisement
Bonding Series 3
Ionic Bonding
1
Introduction
This is the final booklet in the Bonding Series. A lot of the material here
was studied in Year 11.
There is lots of practise material here. Most marks for ionic bonding should
never be lost in an exam.
The past paper questions with commentary and answers are found at the
rear of the booklet. Pay attention to the comments about the tougher
questions
Enjoy!
S de Naipir
2
Describing ionic bonding with dot and cross diagrams
There are three parts to describing ionic bonding with dot and cross. Part 1: Draw the atoms
showing the outer electrons and draw a curved arrow to show the electrons moving from the
metal atom to the non-metal atom.
Here we are using a group 1 metal atom, lithium and group 7 atoms.
Notice only the outer electrons are drawn. Call this stage Before.
3
Practising Before stage with lithium atoms and halogen atoms. Add the outer electrons to
both atoms in each example and then draw the arrow to show electron movement. Potassium
atoms are on the left and halogen atoms are on the right.
LiF
LiCl
LiBr
4
LiI
Practising Before stage with sodium atoms and halogen atoms. Add the outer electrons to
both atoms in each example and then draw the arrow to show electron movement. Potassium
atoms are on the left and halogen atoms are on the right.
NaF
NaCl
5
NaBr
NaI
6
Practising Before stage with potassium atoms and halogen atoms. Add the outer electrons
to both atoms in each example and then draw the arrow to show electron movement.
Potassium atoms are on the left and halogen atoms are on the right.
KF
KCl
KBr
7
KI
Part 2: The After stage. The dot and cross diagrams for the ions formed after electron
donation
LiF
LiCl
8
LiBr
LiI
9
Practising Part 2: The After stage. Draw the dot and cross diagrams for the ions formed in
the following ionic compounds:
LiF
LiCl
LiBr
10
LiI
Part 3: The final statement
The electrostatic forces of attraction between the cations and anions are the ionic bond.
Write out the final statement 5 times
11
Putting all steps together: The model answer
The electrostatic forces of attraction between the cations and anions is the ionic bond.
12
Group 2 and Halogens
Group 2 metal atoms have 2 electrons in their outer shells
Group 7 Halogens have 7 electrons in their outer shells.
Group 2 metal atoms donate 2 electrons to non-metal atoms, but halogens atom can only
accept 1 electron. Therefore, 2 halogen atoms are needed to accept the donated electrons.
Here are the before bonding and after diagrams showing an Mg atom donating its two
electrons to 2 F atoms to form an Mg2+ ion and 2 F- ions.
Before
After
The electrostatic forces of attraction between the cations and anions is the ionic bond.
13
Practising Before stage with Mg atoms and 2 halogen atoms. Add the outer electrons to
both atoms in each example and then draw the arrow to show electron movement.
MgF2
MgCl2
14
MgBr2
MgI2
15
Practising Before stage with Ca atoms and 2 halogen atoms. Add the outer electrons to
both atoms in each example and then draw the arrow to show electron movement.
CaF2
CaCl2
16
CaBr2
CaI2
17
Practising Part 2: The After stage. Draw the dot and cross diagrams for the ions formed in
the following ionic compounds:
MgF2
MgCl2
MgBr2
18
MgI2
CaF2
CaCl2
19
CaBr2
CaI2
20
Part 3: The final statement
The electrostatic forces of attraction between the cations and anions are the ionic bond.
Write out the final statement 5 times
21
Practising the full model exam answer. (All 3 stages)
Describe, using dot and cross diagrams, the ionic bonding of the following ionic compounds
MgF2
MgCl2
22
MgBr2
MgI2
23
CaF2
CaCl2
24
CaBr2
CaI2
25
Group 2 and Group 6
Group 2 metal atoms have 2 electrons in their outer shells
Group 6 non-metal atoms have 6 electrons in their outer shells.
Group 2 metal atoms donate 2 electrons to group 6 non-metal atoms,
Here are the before bonding and after diagrams showing an Mg atom donating its two
electrons to 1 O atom to form an Mg2+ ion and an O2- ions.
Before
After
The electrostatic forces of attraction between the cations and anions are the ionic bond.
26
Practising Before stage with Mg atoms and Group 7 atoms. Add the outer electrons to both
atoms in each example and then draw the arrow to show electron movement.
MgO
MgS
27
MgSe
Practising Before stage with Ca atoms and Group 6 atoms. Add the outer electrons to both
atoms in each example and then draw the arrow to show electron movement.
CaO
28
CaS
CaSe
29
Practising Part 2: The After stage. Draw the dot and cross diagrams for the ions formed in
the following ionic compounds:
MgO
MgS
MgSe
30
CaO
CaS
CaSe
31
Part 3: The final statement
The electrostatic forces of attraction between the cations and anions are the ionic bond.
Write out the final statement 5 times
32
Practising the full model exam answer. (All 3 stages)
Describe, using dot and cross diagrams, the ionic bonding of the following ionic compounds
MgO
MgS
33
MgSe
CaO
34
CaS
CaSe
35
Group 1 and Group 6
Group 1 metal atoms have 1electron in their outer shells
Group 6 non-metal atoms have 6 electrons in their outer shells.
2 Group 1 metal atoms each donate 1 electron to group 6 non-metal atoms,
Here are the before bonding and after diagrams showing 2 Na atoms donating electrons to 1
O atom to form 2 Na+ ions and 1 O2- ion.
Before
After
The electrostatic forces of attraction between the cations and anions are the ionic bond.
36
Practising Before stage with Li atoms and Group 6 atoms. Add the outer electrons to both
atoms in each example and then draw the arrow to show electron movement.
Li2O
Li2S
37
Li2Se
Practising Before stage with sodium atoms and Group 6 atoms. Add the outer electrons to
both atoms in each example and then draw the arrow to show electron movement.
Na2O
38
Na2S
Na2Se
39
Practising Before stage with Potassium atoms and Group 6 atoms. Add the outer electrons
to both atoms in each example and then draw the arrow to show electron movement.
K2O
K2S
40
K2Se
Practising Part 2: The After stage. Draw the dot and cross diagrams for the ions formed in
the following ionic compounds:
Li2O
Li2S
41
Li2Se
Na2O
Na2S
42
Na2Se
K2O
K2S
43
K2Se
Na2Se
44
Part 3: The final statement
The electrostatic forces of attraction between the cations and anions are the ionic bond.
Write out the final statement 5 times
45
Practising the full model exam answer. (All 3 stages)
Describe, using dot and cross diagrams, the ionic bonding of the following ionic compounds
Li2O
Li2S
46
Li2Se
Na2O
47
Na2S
Na2Se
48
K2O
K2S
49
K2Se
50
Ionic structures
You must know the following two ionic structures:
NaCl
A giant 3D ionic lattice
•
•
Each Na+ ion is surrounded by 6 Cl-ions
Each Cl- ion is surrounded by 6 Na+ ions
Therefore, the crystal co-ordination number in NaCl is 6:6
51
Cesium Chloride
Giant 3D Ionic Lattice
•
•
Each Cs+ ion is surrounded by 8 Cl-ions
Each Cl- ion is surrounded by 8 Cs+ ions
Make sure you label the ions. The red ions are Cl- ions. The green ion is Cs+
Therefore, the crystal co-ordination number in CsCl is 8:8
52
Properties of Ionic Solid Structures
Properties
Reason for properties
Molten or dissolved salts have free ions to carry the
charge.
Molten or dissolved
salts conduct electricity
Solid ionic compounds don’t have free ions or electrons
to carry the charge
Solid Ionic compounds
Salts are hard because of tight packing lattices, say, the
positive and negative ions are strongly attached among
themselves.
Brittle
(break easily)
If pressure is applied to an ionic solid, ions of similar
charges may be forced to closer together. The electrostatic
repulsion can be enough to split the ionic lattice.
Melting point is high, because lots of energy is needed to
overcome the strong electrostatic forces of attraction
between the cations and ions.
Melting Point
53
Explain why are ionic structures are hard, brittle and have high melting
points?
Explain why ionic solids don’t conduct electricity?
Explain when ionic compounds conduct electricity and why?
54
Solubility of ionic solids
Some salts dissolve in water. Here’s what happens to the ions when they are added to water
The δ- of water orient themselves around cations ( + ions).
The δ- of water orient themselves around anion (- ions).
Salts dissolves when the attraction between the polar water molecules and the ions is
greater than the energy of salt’s lattice energy.
55
Note: You can be asked to draw these diagrams for any salt that dissolves
in water. You have practice this on following pages:
Show how, and explain why, the following salts dissolve in water
LiF
KBr
56
NaI
NaCl
57
Past paper Questions with Commentary
Comment
This question appeared on the mock exam and was poorly answered. Many students drew
covalent dot and cross diagrams. It appears that many thought that dot and cross diagrams
are only for covalent compounds.
The key information is magnesium fluoride. This contains a metal and a non-metal.
Therefore, it is a salt (ionic compound).
Comment
This is a simple recall question. You either remember it or you don’t. CsCl has a coordination number 8:8
Beware that the examiner could use CsF, CsBr, CsI in this type of question.
Answer
8
58
Comment
This is a tough question on structures.
You must understand and know the melting point and electrical conductivity of metals, ionic,
giant covalent, and simple covalent structures.
Answer:
A is simple molecular
Why?
Low melting point and does not conduct electricity.
D is ionic
Why?
High melting point and does not conduct electricity when solid, but does when dissolved
59
B probably giant covalent, but could be ionic
Why?
Probably giant covalent due to high melting point and does not conduct electricity.
Could be ionic because not all ionic solids (salts) are soluble. The Bunsen couldn’t melt the
salt to allow electrical conductivity to be tested when molten.
C is probably metallic, but could be giant covalent as graphite conducts electricity
Why?
Both metals and graphite have high melting points and conduct electricity
Comment
On the mark scheme the words probably and could be are in bold. If you leave these words
out, you will not get the marks. Unfair? I think so.
Comment
A straight-forward question. Remember no covalent diagrams.
60
Comment
This is a tough question.
Answer
Sodium and Oxygen because they have the largest difference in electronegativities.
Comment
This is a simple question.
61
Comment
This question is a tough. You have to how NaCl is structured within this cube, so we we look
at that here:
The grey lines are guiding lines. Notice how the cations and anions alternate on different lines.
Here the diagram without the guiding lines:
62
Answer
To answer the question, complete the diagram using Mg2+ and S2-instead of Na+ and
Cl-
I have included a practise sheet for you to use when practising this type of question.
63
Practise Sheet
64
Comment
A recall question. You either remember it or you don’t
Answer
8
Comment
An easy question
65
Comment
This is an easy question. You simply look for compounds made of metal and non-metals
ions. You must know your ions.
Answer
MgO and Al2O3
66
Comment
A straight-forward question
Answer
Co-ordinaton number of NaCl is 6:6
67
Comment
This is a straight-forward question. I would recommend you draw the diagram. See page 55.
Just replace the cations and anion for the ions in this question.
Comment
An easy question
68
Comment
A tough question.
Ionic bonds get some covalent character when the positive ion is small with a high positive
charge and the negative ion is large.
The highly charged + ion will pull the large – ion’s electron cloud towards itself. This is like a
covalent bond.
Answer
Positive ions must increase charge and decrease size (in order to pull the negative ion’s
electron cloud)
Negative ions must increase charge and increase size (in order to have its negative
electron cloud pulled by the positive ion)
69
Comment
An easy question
Comment
An easy question
Comment
An easy question. You must know your ions to work out the formula of lithium hydride, LiH
See page 67 to help you answer this question. Just replace Na+ and Cl- with Li+ and H-
70
Comment
An easy question
Comment
An interesting question. The smaller black ion is Li- and the larger white ion is Br –
How would you work that out? Li is smaller than Br.
Answer
The smaller black ion is Li- and the larger white ion is Br –
Crystal co-ordination number of LiBr is 6:6
71
Comment
An easy question
Comment
A NaCl is ionic and soluble. Be careful you read part (b) correctly.
Answer
(a) Sodium chloride
(b) Iodine
72
Comment
A good comparison question. I have added blank cubes to allow you to practise drawing this
shape
Answer
The small white ions are Cl- and large black ion is Cs+
Crystal co-ordination number of CsCl is 8:8
Cs+ is larger than Na+ so more Cl- ions can fit around it.
73
Draw CsCl. State its crystal co-ordination number and explain it differs from NaCl’s
74
Comment
An easy question. The small white ions are Na+ and large white ions are Cl-
Comment
Most of this question is easy. It is important to include a labelled diagram as part of your
answer. The last bullet point is difficult.
75
Answer
You should be able to answer the first two bullet points. The answer to the third bullet point is
given below:
In the electrostatic forces of attraction between the ions, like same charge ions repel and
differently charged ions attract.
Comment
The water molecules mentioned in (a) are not the water molecules in the formula of the
compound. Ignore the water molecules in the formula. You must know your ions. The ions
made with Ba(OH)2 dissolves in water are Ba2+ and OH-
Answer
See page 55 to help you answer this question just replace Na+ with Ba2+ and Cl- with OH-
76
Download