ALGEBRAIC EXPRESSIONS • • • • • • • • • • Real numbers Surds lie between integers Rounding-off Integers Products Factorization: Common Factor Factorization: Difference of Squares Factorization: Trinomials Factorization: Grouping in Pairs Factorization: Cubes Algebraic Fractions Algebraic Language 1 REAL NUMBERS Rational Numbers A rational number is a number that can be expressed in the form a b where b 0 and where a and b are integers. 2 Examples ◼ a) Integers 5 e.g. 5 can be written as where 5 and 1 are 1 integers. ◼ b) Mixed fractions e.g. 2 3 7 ◼ c) Terminating decimals e.g. 0,25 = 25 = 1 100 ◼ 4 d) Recurring decimals have an infinite pattern & can be expressed as a fraction e.g. 0, 3 = 0, 3333333; 0, 12 = 0, 12121212 3 Converting Recurring Decimals to Fractions ◼ ▪ E.g. a) Show that 0,3 is rational. Let x = 0, 333333.... l0x = 3, 333333 (multiply both sides by 10) l0x - x = 3, 33333 – 0, 33333 (subtract equations) 9x = 3, 0000000 9x = 3 x = 3 … a rational number! E.g. b) Show that 0, 12 is rational. Let x = 0, 12121212 100x = 12, 12121212 (multiply both sides by 100) 99x = 12, 000000 (subtract equations) 12 4 x = 99 = 33 … a rational number! 4 EXERCISE 1. Are these numbers rational and why? (a) (b) 1 3 4 −2 1 6 (c) 6 (d) - 3 (e) 0, 72 (f) 1, 4142 5 2. Show that the following recurring decimals are rational: (a) 0, 4 (b) 0, 21 (c) 0, 14 (d) 19, 45 (e) 0, 124 (f) 0, 124 6 Irrational numbers ◼ ◼ ◼ Numbers that cannot be written in the form where b 0 Therefore recurring numbers that neither terminate nor recur with a pattern E.g. a) 5,739129… b) -4,883291103… c) a b Irrational Numbers in Circles & Squares 7 The Number ◼ ◼ is the ratio of the circumference of a circle to its diameter is = 3,142857143…. Rounding-off π ◼ However, can be approximated as an improper fraction 22 7 π as a Rational Number 8 EXERCISE 1 State whether the following numbers are rational or irrational: (a) 8 (b) 16 (c) 7 (d) 7 1 (e) 25 (f) 0 (g) 5 2 (h) − 1 16 (i) - 0, 13 (j) 0, 42 (k) (l) 0, 2453756… 9 EXERCISE 2 Classify numbers by placing ticks in the appropriate columns: Number −3 Real Rational Integer Whole Natural Irrational 1 6 0,14674 16 5 -3 22 7 0, 3 8, 23647 10 SURDS LIE BETWEEN INTEGERS E.g. Determine without the use of a calculator, between which 2 integers 11 lies. ◼ Find an integer smaller and bigger than 11 that can be square rooted … 9 and 16 ◼ Now create an inequality … 9 < 11 < 16 ◼ Square root all integers … 9 11 16 ◼ Solve … 3 11 4 11 = 3,3166 ◼ Check using a calculator … 11 EXERCISE Without using a calculator, determine between which two integers the following irrational numbers lie: (a) (b) (c) (d) (e) (f) 30 27 3 43 − 6 7 33 12 ROUNDING-OFF INTEGERS ◼ ◼ If it is > 5 or = 5 … round up If it is < 5 … round down ◼ Remember! If you are rounding-off to 2 decimal places, the third decimal place determines whether you round up or down etc. ◼ E.g. (a) 2, 31437 (2 d.p.) … Answer:2, 31 (b) 0, 77777 (3 d.p.) … Answer: 0, 778 (c) 245, 13589 (4 d.p.) … Answer: 245,1359 Rounding-off Numbers 13 EXERCISE 1 Round off the following numbers to the number of decimal places indicated: ◼ (a) 9, 23584 (3 decimal places) ◼ (b) 67, 2436 (2 decimal places) ◼ (c) 4, 3768534 (4 decimal places) ◼ (d) 17,247398 (5 decimal places) ◼ (e) 79, 9999 (3 decimal places) ◼ (f) 34, 2784682 (4 decimal places) ◼ (g) 5,555555 (5 decimal places) 14 EXERCISE 2 Simplify and round-off to the number of decimal places indicated: ▪ (a) 7,53427 (3 decimal places) ▪ (b) 3,3333 (4 decimal places) ▪ (c) 36,268 (2 decimal places) ▪ (d) (2,64) (2,18) (5 decimal places) ▪ (e) (1,64) 1,64 (2 decimal places) 3 6 2 6 6 15 PRODUCTS ◼ ◼ E.g. x (y + z) = xy + xz - Multiply each term inside the bracket by the number outside the bracket E.g. (a + b)(c + d) = ac + ad + bc + bd - This is done by using the FOIL method The Product Game 16 Examples Expand and simplify the following: ◼ (a) (x + 2) (x + 3) = x + 3x + 2 x + 6 2 = x + 5x + 6 2 ◼ Squaring a Binomial Example (b) (x + 2) (x² + x - 1) = x + x − x + 2x + 2x − 2 3 2 2 = x 3 + 3x 2 + x − 2 17 ▪ (c) x(x²-2xy+3y²) - 2y(x² -2xy+3y²) = x( x 2 − 2 xy + 3 y 2 ) − 2 y ( x 2 − 2 xy + 3 y 2 ) = x 3 − 2 x 2 y + 3xy 2 − 2 x 2 y + 4 xy 2 − 6 y 3 = x 3 − 4 x 2 y + 7 xy 2 − 6 y 2 ▪ (d) (a – 3b) (a – 3b)² = (a − 3b)(a − 3b) 2 = (a − 3b)(a 2 − 6ab + 9b 2 ) = a(a − 6ab + 9b ) − 3b(a − 6ab + 9b ) 2 2 2 2 = a 3 − 6a 2 b + 9ab 2 − 3a 2 b + 18ab 2 − 27b 3 = a − 9a b + 27ab − 27b 3 2 2 3 18 Exercise 1: 4 Simplify: ◼ (a) (x + 3)(x - 3) ◼ (b) (x - 6)(x + 6) ◼ (c) (2x - l)(2x + l) ◼ (d) (4x + 9)(4x - 9) ◼ (e) (3x - 2y)(3x + 2y) ◼ (f) (4a³ b + 3)(4a³ b - 3) ◼ (g) (2x – 3 + y)(2x – 3 – y) ◼ (h) (1 – a )(1 – a )(1 + a) 19 Exercise 2 2 Simplify: ◼ (a) 2x(3x - 4y)² - (7x - 2xy) ◼ (b) (5y + 1)² - (3y + 4)(2 - 3y) ◼ (c) (2x + y) - (3x - 2y) + (x - 4y)(x + 4y) ◼ (d) (8m - 3n)(4m + n) - (n - 3m)(n + 3m) ◼ (e) (3a + b)(3a - b)(2a + 5b) 20 Exercise 3 Simplify: ◼ (a) (x + 1)(x² + 2x + 3) ◼ (b) (x - 1)(x² - 2x + 3) ◼ (c) (2x + 4)(x² - 3x + 1) ◼ (d) (2x - 4)(x² - 3x + 1) ◼ (e) (3x-y)(2x² + 4xy – y² ) ◼ (f) (3x - 2y)(9 x² + 6xy + 4 y² ) ◼ (g) (3x + 2y)(9x² - 6xy + 4y² ) ◼ (h) (2a + 3b)² ◼ (i) (2a² - 3b)² 21 FACTORIZATION: Common Factor The Factor Game ◼ The golden rule of factorization is to always look for the highest common factor first: Basic examples Common Factor with Variables Complex example e.g. a(x-y) – 2(x-y)² = (x-y)[a-2(x-y)] = (x-y)(a-2x+2y) 22 Common Brackets Exercise: ◼ ◼ ◼ ◼ ◼ ◼ ◼ ◼ (a) a(x + y ) + b(x + y ) (c) p(q + r ) + m(r + q ) (e) (x − y ) − 3(x − y ) (g) (m − n) + (m − n) (i) 7 x(m − 3n) + 4 y(3n − m) (k) 2x(3 p + q) + 4 y(− q − 3 p) (m) 4x(a − 2) + (2 − a ) (o) (a − 3b) − c(3b − a) + d (3b − a) 2 6 3 2 3 (b) x(a + b) + y(a + b) (d) 2 x(m − 3n) − 5 y(m − 3n) (f) (a + c ) + (a + c ) (h) 7 x(m − 3n) − 4 y(3n − m) (j) 7 x(m + 3n) + 4 y(− m − 3n) (l) (a − b ) − ( pb − pa ) (n) 2x (3a − b) − 12x(b − 3a) 4 5 2 23 FACTORIZATION: Difference of Squares There must be 2 terms that you can take the square-root of and a minus sign. Basic examples ▪ a) a − b = 2 2 ( a − b )( a + b ) 2 2 2 2 = (a − b)(a + b) ▪ b) x 2 − 9 = ( x 2 − 9 )( x 2 + 9 ) = ( x − 3)( x + 3) Difference of Squares Example 24 Complex examples ▪ a) 49x 4 − 64 y 2 ( )( = 7x 2 − 8y 7x 2 + 8y ▪ b) ) 4 − (x − y ) 2 = [2 + (x − y )][2 − (x − y )] = (2 + x − y )(2 − x + y ) ▪ c) 8a 8 − 8b 8 ( = 8(a = 8(a = 8 a 8 − b8 4 − b4 2 − b2 ) )(a )(a 4 + b4 2 + b2 ( ) )(a 4 + b4 )( ) = 8(a − b )(a + b ) a 2 + b 2 a 4 + b 4 ) 25 Complex Exercise ◼ ◼ ◼ ◼ ◼ ◼ ◼ ◼ (a) 100m 8 − n 6 (b) 144x − 225y (c) 12k − 75m (d) p − 16 (e) z − 81 (f) 27a − 3ab (g) (x + b) − c (n) 25a − 16(a − m) 4 4 2 2 4 8 3 2 2 2 2 2 26 FACTORIZATION: Trinomials Make sure you know your times-tables and factors! ◼ ◼ ◼ ◼ ◼ ◼ ◼ ◼ ◼ E.g. a) a 2 + 6a + 8 Factors of 8: 1 x 8 or 4 x 2 The middle term (6a) is obtained by adding the factors of 8 … 4 + 2 = 6 Therefore: = (a + 4)(a + 2) E.g. b) 3x 2 − 21x − 24 2 = 3 ( x − 7 x − 8) First take out common factor! Factors of 8: 1 x 8 or 4 x 2 The middle term (7x) is obtained by adding the factors of 8 … -8 +1 = -7 Therefore: = 3( x 2 − 7 x − 8) Trinomial with Common Factor = 3( x − 8)( x + 1) 27 Note: ◼ If the sign of the last term of a trinomial is positive, the signs in the brackets are the same i.e. (… - …)(… - …) or (… + …)(… + …) ◼ If the sign of the last term of a trinomial is negative, the signs in the brackets are different, i.e. both positive or both negative i.e. (… + …)(… - …) or (… - …)(… + …) Visualizing Factorization 28 Basic Exercise Factorize fully : ◼ ◼ ◼ ◼ ◼ ◼ ◼ a 2 + 7a + 12 (a) (c) a 2 + 4a − 12 (e) x 2 − 9 x + 20 (g) x 2 − 12 x + 35 (i) p 2 + 5 p − 6 (k) k 2 − 11k + 28 (m) k 2 + 6k + 9 a 2 − 7a + 12 (b) 2 a (d) − 4a − 12 2 x − 11x − 12 (f) 2 p (h) − 5 p − 6 (j) p 2 − 5 p + 6 (l) k 2 − 5k − 84 (o) k 2 − 8k + 16 29 Complex Exercise Factorize fully: ◼ ◼ ◼ ◼ ◼ (a) (b) (c) (d) (e) 3k 2 − 3k − 18 2k 2 − 14k − 36 4k 2 + 12k − 40 6 g 2 + 24g − 30 k 3 + 11k 2 − 8k 30 More advanced trinomials E.g. a) 21p 2 + 25 p − 4 ◼ ◼ ◼ Step 1: Check for the HCF … none Step 2: Write down the brackets and the factors of the first term and the factors of the last term … (7p 1)(3p 4) Step 3: Now multiply the innermost and the outermost terms … 1 3 p = 3 p 7 p 4 = 28 p Step 4: To find the middle term ... - 3p + 28p = + 25p ◼ Step 5: Complete the factors … (7p – 1)(3p + 4) Note! This method involves trial and error and you need to keep t ◼ trying different options until you get ones that will work. 31 E.g. b) 24a 2 − 10ab − b 2 ◼ ◼ ◼ ◼ ◼ Step 1: Check for the HCF … none Step 2: Write down the brackets and the factors of the first term and the factors of the last term … (12a b)(2a b) Step 3: Now multiply the innermost and the outermost terms … 2ab x 12ab Step 4: To find the middle term ... -12ab + 2ab = - 10ab Step 5: Complete the factors … (12a + b)(2a – b) 32 Advanced Exercise 1. Factorize fully: ◼ ◼ ◼ ◼ ◼ ◼ (a) 2 p + 3 p + 1 (c) 15 p 2 − 8 p + 1 (e) 2m 2 − 5m − 3 (g) 2m 2 − 7m + 6 (i) 6k 2 − 5k − 21 (k) 18k 2 − 3k − 10 2 3p2 − 4 p +1 (b) (d) 18m 2 + 3m − 1 (f) 5m 2 + 14m + 8 (h) 6k 2 − 11k − 10 (j) 20k 2 + 24k − 9 (l) 15 − x − 6 x 2 33 FACTORIZATION: Grouping in pairs Group terms with common factors or similar brackets! ax + ay + px + py E.g. ◼ Group the terms that look similar (i.e. those that could potentially have common factors) ◼ Factorize each pair separately and then take out the common bracket: ax + ay + px + py = a( x + y ) + p( x + y ) = ( x + y )(a + p ) 34 Switch-arounds “taking out a negative” ◼ - x + y = - (x - y) and – x – y = - (x + y) E.g. a) Factorize a 2 + a − 6ax − 6 x = (a 2 + a ) + (−6ax − 6 x) = a (a + 1) − 6 x(a + 1) = (a + 1)(a − 6 x) 35 ◼ b) Factorize: p3 − 3 p 2 − p + 3 = ( p 3 − 3 p 2 ) + ( − p + 3) = p 2 ( p − 3) − ( p − 3) = ( p − 3)( p 2 − 1) = ( p − 3)( p − 1)( p + 1) ◼ (c) Factorize: 6m2 + 3m − 6 p −12mp = (6m 2 + 3m) + (−6 p − 12mp) = 3m(2m + 1) − 6 p(1 + 2m) = 3m(2m + 1) + 6 p(2m + 1) = (2m + 1)(3m + 6 p) = 3(2m + 1)(m + 2 p) 36 Exercise Factorize: ◼ (a) 6a 3 − 2a 2 − 54a + 18 ◼ (b) p 2 − (d + t ) p + dt ◼ (c) m 2 − 9 − (m − 3)(1 − 2m) ◼ (d) x 2 − y 2 − x − y ◼ (e) p 2 − 4 pq + 4q 2 − 16t 2 37 FACTORIZATION: Cubes Sum of Cubes x.x²=x³ y.y²=y³ x³ + y³ = (x+y)(x² - xy + y²) Take the cube root of each term Times factors of first bracket to get middle term Sum of Cubes Example 38 Difference of Cubes x.x²=x³ y.y²=y³ x³ - y³ = (x-y)(x² + xy + y²) Take the cube root of each term Difference of Cubes Example Times factors of first bracket to get middle term Visualization of Factorizing a Cubic Expression 39 ALGEBRAIC FRACTIONS Simplify the following expressions: ◼ (a) ◼ (b) 12a 3 b 4 t 18a 5 bt 2 7 12a c 24a c 5d 25d 2a 3−5 b 4 −1t 1−1 = 3 2a − 2 b 3 t 0 = 3 2b 3 = 3a 2 = = = = 12a 2 c 25d 5d 24a 7 c 12 25a 2 cd 5 24a 7 cd 5a 2 − 7 c 1−1 d 1−1 2 5 2a 5 40 Whenever the numerator contains two or more terms, factorize the expression in the numerator and simplify ◼ (c) 6c 2 + 12c 6c 2 ◼ (d) 9x2 −1 3x − 1 6c (c + 2) 6c 2 c+2 = c = (3 x + 1)(3 x − 1) = 3x − 1 = 3x + 1 Simplifying Basic Algebraic Expressions 41 EXERCISE 1 Simplify the following: ◼ (a) ◼ (c) ◼ (e) ◼ (g) ◼ (i) 24 x 6 y 10 z 36 x 8 yz 2 5 8m 2m 25 2x3 6 y 4x3 y 3y 2 x 4p −8p 4p 2 4t 2 + 4m 4m 2 (b) 25 x 3 y 5 z 2 75 xy 6 z 2 (d) 6t 2 4t 3 p p2 (f) m2 − m m (h) 3s 2 − 6 s 6s (j) w3 − w 2 w2 4 8 42 EXERCISE 2 Simplify ◼ ◼ ◼ 2w 1 (a) + 3 6 (c) 3 + 2 t t2 (e) 7 2 1 − + 3 6r 9rt 3r c c (b) − 3 4 (d) 5 − 3 + 1 w3 w 2 (f) 3 5 7 − + −4 2 2 2 y w 4 yw 6 y 43 More Advanced Algebraic Fractions Examples a) b) ( x − 5)( x − 1) + 2( x − 5) x −5 xy − x 2 x2 2 2 2 y −x y + xy Simplifying Complex Algebraic Expressions ( x − 5)[( x − 1) + 2] = x −5 = ( x − 1) + 2 = x +1 xy − x 2 y 2 + xy = 2 2 y −x x2 x( y − x) y ( y + x) = ( y − x )( y + x ) x2 y = x 44 Exercise Simplify: a) x 2 + 5x + 4 x ( x + 1) b) x 2 ( x − 1) + x 2 − 1 x ( x − 1) c) x2 + x − 2 2+ x 2( x − 2) 6 − 3x d) 1− 2x x+4 1 − + 4 x 2 − 1 2 x 2 − 3x + 1 1 − x 45