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Homework 2

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chayapatmanorungruengrat
6412101010
EF×=O ;
Fzsin7O°tF
,
cos
600-505300-45-177=0
0.93971=21-0.51--1--9.930
EFy=O;
1=205700+551'n3o°
-
Y
g.hn
¥
goy
,sin6o° -3-50-7=0
F
p
,
✗
60
5/-3
"
0.34201=2 -0.86601=1--1-7
1--2=9.60 kN #
7hr
F
,
1--1=1 -83kW#
{
F×=ojFsinO- -15-405600-805300=0
,
Fy=oj8sin3o° -45in 60°
2
FsinO-
{
=3 -9282
-
FcosQ=o
F- cos -0=0.5359
y
①
2
;
Sino
Otano
=
8kW
7.3301
Cos
=
7.3301
Go
0=82.230--82.20#
Fsin 82.230=3.9282
f- =3 -96466N 3.96kW
-_
5kW
To
44N
#
(a)
F
✗
{ Fz=O;
Fap
1.5
1.
{ F×=O;
FAD
✗
FAB
-
-_
392.4N
523.2N
-_
Fz=O; FAB
{ F×=0
; Fac
FAB
6
-
392N
-_
{
2
-_
=
°
52+22+1.52
523N #
Fy=0j
2
2
F
2019.817=0
-
4
Fa ,
Zo
-219.36
FAD
y
)NFAC
FAB
-219.36N
3
Fac=Fa☐=F= 54.84N 54.8N #
__
Fac __FAD=F
=0
45
20
(a)
#
✓ 45
20
2019.81
0
(a)
{
✗
=
1.52+22+1.52
1.
y
4019.817N
#
1.5
Fy=O; FAB -762.69
FAB
Fac
763N
=
Fac -762.69
Fac
{
4019.817=0
52+22+1,52
FAD -762.69N
2-
-
=
0
__
219N#
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