Seepage Team members ο§ George Savvas - 21005742 ο§ Rami Kaawach - 21054783 ο§ Youssef Elsheriff - 21051726 Table 1a. – measured and calculated pressure heads Points Actual experimental reading from standpipe (Units + mm) Measured pressure head from standpipe reading (m) Calculated pressure head from flow net drawing (m) A 0.5 0.0125 0.5 B 4 + 0.4 0.1040 4 C 5 + 15 0.1400 5.5 D 5 + 16 0.1410 5.5 E 2 + 35 0.0850 3.5 F + 28 0.0280 1 Table 1b. – derived and calculated pore water pressures Points Derived pore water pressure from standpipe reading (kPa) Calculated pore water pressure from flow net (kPa) A 0.1250 5 B 1.0040 40 C 1.4000 55 D 1.4100 55 E 0.8500 35 F 0.2800 10 Figure 1 Figure 2 Datum Figure 3 Calculation of seepage and outflow velocity Calculation of seepage velocity 25mm Measured times What are the differences between outflow and seepage velocity ? Δπ‘π΄ = 33.97π ο§ Through calculations we can observe that: start π£π΄ & π£π΅ > π£ππ£πππππ ππ’π‘ππππ€ Δπ‘π΅ = 41.44π π£π΄ = 50ππ = 1.472mm/s 33.97π π£π΅ = 50ππ = 1.207mm/s 41.44π end Calculation of outflow velocity Figure 1 – Visual aid to help with seepage velocity calculations ο§ Some of the possible reasons behind π£π΄ & π£π΅ being greater than π£ππ£πππππ ππ’π‘ππππ€ are: ο§ π£π΄ & π£π΅ > π£ππ£πππππ ππ’π‘ππππ€ • Deriving an expression to allow us to calculate outflow velocity π π π£= = π‘ π΄ π΄ 500 × 103 ππ 5.90π π£1 = = 0.437mm/s 460 × 422ππ ο§ Assumption that flow is steady 500 × 103 ππ 6.47π π£2 = = 0.398mm/s 460 × 422ππ ο§ Application of π = π£π΄ 3 500 × 10 ππ 6.16π π£3 = = 0.418mm/s 460 × 422ππ π£ππ£πππππ ππ’π‘ππππ€ = 0.437 ππ π + 0.398 ππ π + 0.418 ππ π = 0.418 ππ π 3 ο§ Difference of cross-sectional areas gives rise to this difference Calculation of porewater pressure What assumptions are made prior to calculation of the pore water pressure using the flow net ? 1. Porewater pressure & rates of flow do not change overtime 2. Assumption that the retaining wall is fully impermeable 3. When considering Bernoulli’s equation the velocity terms are neglected 4. Datum is impermeable Calculating elevation heads (π§π₯ ) relative to datum ο§ Utilizing figure 3: @B: π§π΅ =8m @C: π§πΆ =6m @D: π§π· =5m @E: π§πΈ =6m What is the difference between the calculated and measured pore water pressures and why could these differences arise ? ο§ Differences arise due to the experimental & model results considering different units ο§ Experimental error – Misreading the meniscus of the stand pipe Estimating total hydraulic head (π»π₯ ) ο§ Utilizing the following equation: Δπ»π = Δπ» (π − 1) ο§ Using the data from figure 3: Δπ»π = 3.5π (8 − 1) Δπ»π = 0.5π ο§ Calculating total head @B: π»π΅ = 12.5π − 0.5π = 12π 1 πΈπ ππππ @C: π»π = 12.5π − 0.5π × 2 = 11.5π 2 πΈππ ππππ @D: π»π· = 12.5π − 0.5π × 4 = 10.5π 4 πΈππ ππππ @E: π»πΈ = 12.5π − 0.5π × 2 = 11.5π 6 πΈππ ππππ Calculating pressure head (βπ₯ ) Calculating pore water pressure (π’π₯ ) ο§ Utilizing the following equation: ο§ Utilizing the following equation: βπ₯ = π»π₯ − π§π₯ @B:βπ΅ = π»π΅ − π§π΅ = 12π − 8π = 4π @C:βπΆ = π»πΆ − π§πΆ = 11.5π − 6π = 5.5π @D:βπ· = π»π· − π§π· = 10.5π − 5π = 5.5π @E:βπΈ = π»πΈ − π§πΈ = 9.5π − 6π = 3.5π π’π₯ = πΎπ€ βπ₯ @B: π’π΅ = πΎπ΅ βπ΅ = 10 ππ π3 β 4π = 40πππ @C: π’πΆ = πΎπΆ βπΆ = 10 ππ π3 β 5.5π = 55πππ @D: π’π· = πΎπ· βπ· = 10 ππ π3 β 5.5π = 55πππ @E: π’πΈ = πΎπΈ βπΈ = 10 ππ π3 β 3.5π = 35πππ