College Physics: Explore and Apply
Second Edition
Chapter 6 Clickers
Impulse and Linear
Momentum
Prepared by
Elliot Mylott
University of Portland
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Which of the Following Statements Is
Not Correct About Linear Momentum?
a. Linear momentum is a vector quantity.
b. Linear momentum is conserved in a collision.
c. Linear momentum is independent of reference frame.
d. Linear momentum is the product of a system object’s mass and
velocity.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Which of the Following Statements Is
Not Correct About Linear Momentum?
a. Linear momentum is a vector quantity.
b. Linear momentum is conserved in a collision.
c. Linear momentum is independent of reference frame.
d. Linear momentum is the product of a system object’s mass and
velocity.
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A 2-kg Rubber Ball with an Initial Speed of 10 m/s
Bounces off a Wall. Immediately After the Bounce,
the Ball Has a Speed of 5 m/s. What Is the Change
in the Ball’s Momentum?
a. 10 kg * m / s2
b. 20 kg * m / s2
c. 30 kg * m / s2
d. None of the options are correct.
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A 2-kg Rubber Ball with an Initial Speed of 10 m/s
Bounces off a Wall. Immediately After the Bounce,
the Ball Has a Speed of 5 m/s. What Is the Change
in the Ball’s Momentum?
a. 10 kg * m / s2
b. 20 kg * m / s2
c. 30 kg * m / s2
d. None of the options are correct.
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A 10-kg Ball Is Thrown up with a Speed of 9.8 m/s.
Use the Impulse-Momentum Theorem to Find the
Time It Takes to Reach Its Highest Position.
a. 0.5 s
b. 1.0 s
c. 1.5 s
d. 2.0 s
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A 10-kg Ball Is Thrown up with a Speed of 9.8 m/s.
Use the Impulse-Momentum Theorem to Find the
Time It Takes to Reach Its Highest Position.
a. 0.5 s
b. 1.0 s
c. 1.5 s
d. 2.0 s
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Jen (50 kg) and David (75 kg), Both on Rollerblades,
Push off Each Other Abruptly. After the Push, Jen
Has a Velocity of −3.0 m/s. What Is David’s Velocity?
a. +2.0 m/s
b. +3.0 m/s
c. +4.5 m/s
d. Not enough information is given to determine David’s velocity.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Jen (50 kg) and David (75 kg), Both on Rollerblades,
Push off Each Other Abruptly. After the Push, Jen
Has a Velocity of −3.0 m/s. What Is David’s Velocity?
a. +2.0 m/s
b. +3.0 m/s
c. +4.5 m/s
d. Not enough information is given to determine David’s velocity.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Two Identical Carts Travel Toward Each Other at the
Same Speed and Collide with Each Other. What Can
We Conclude?
a. The final linear momentum of the two carts will sum to zero.
b. The carts will have zero velocity after the collision.
c. After the collision, the carts will be moving with the same speed
but in opposite directions.
d. We cannot reach any of these conclusions.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Two Identical Carts Travel Toward Each Other at the
Same Speed and Collide with Each Other. What Can
We Conclude?
a. The final linear momentum of the two carts will sum to zero.
b. The carts will have zero velocity after the collision.
c. After the collision, the carts will be moving with the same speed
but in opposite directions.
d. We cannot reach any of these conclusions.
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Two Carts Travel Toward Each Other on a
Frictionless Track at the Same Speed and Collide
with Each Other. One of the Carts Has a Mass Five
Times That of the Other Cart. Which Cart
Experiences the Greater Change in Momentum?
a. The smaller cart experiences greater change in momentum.
b. The larger cart experiences greater change in momentum.
c. They have the same change in momentum.
d. It depends on the final speed of the carts.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Two Carts Travel Toward Each Other on a
Frictionless Track at the Same Speed and Collide
with Each Other. One of the Carts Has a Mass Five
Times That of the Other Cart. Which Cart
Experiences the Greater Change in Momentum?
a. The smaller cart experiences greater change in momentum.
b. The larger cart experiences greater change in momentum.
c. They have the same change in momentum.
d. It depends on the final speed of the carts.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 1000-kg Car Is Moving at 10 m/s with Respect to
the Ground When the Car Hits a Barrier. The Car Is
Stopped in 0.5 s by the Force of the Barrier on the
Car. What Is the Magnitude of the Average Force the
Barrier Exerted on the Car During the Collision?
a. 2000 N
b. 5000 N
c. 20,000 N
d. Impossible to determine from the information given
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 1000-kg Car Is Moving at 10 m/s with Respect to
the Ground When the Car Hits a Barrier. The Car Is
Stopped in 0.5 s by the Force of the Barrier on the
Car. What Is the Magnitude of the Average Force the
Barrier Exerted on the Car During the Collision?
a. 2000 N
b. 5000 N
c. 20,000 N
d. Impossible to determine from the information given
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 1000-kg Car Is Moving at 10 m/s with Respect to
the Ground When the Car Hits a Barrier Equipped
with a Impact Attenuator, Which Extends the
Duration of the Crash. The Car Is Now Stopped in
0.75 s by the Force of the Barrier on the Car. What Is
the Magnitude of the Average Force the Impact
Attenuator Exerted on the Car During the Collision?
a. 7500 N
b. 13,333 N
c. 20,000 N
d. Impossible to determine from the information given
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 1000-kg Car Is Moving at 10 m/s with Respect to
the Ground When the Car Hits a Barrier Equipped
with a Impact Attenuator, Which Extends the
Duration of the Crash. The Car Is Now Stopped in
0.75 s by the Force of the Barrier on the Car. What Is
the Magnitude of the Average Force the Impact
Attenuator Exerted on the Car During the Collision?
a. 7500 N
b. 13,333 N
c. 20,000 N
d. Impossible to determine from the information given
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball and the Sad Ball. If
Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Statements
Is Not Correct?
a. The final momentum of the sad ball is zero.
b. The final momentum of the happy ball is equal in
magnitude to its initial momentum.
c. The change in the momentum of the sad ball is larger
than the change in the momentum of the happy ball.
d. The impulse exerted on the happy ball is greater than the
impulse exerted on the sad ball.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball and the Sad Ball. If
Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Statements
Is Not Correct?
a. The final momentum of the sad ball is zero.
b. The final momentum of the happy ball is equal in
magnitude to its initial momentum.
c. The change in the momentum of the sad ball is larger
than the change in the momentum of the happy ball.
d. The impulse exerted on the happy ball is greater than the
impulse exerted on the sad ball.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball (mh) and the Sad Ball (ms).
If Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Equations Is
Not Correct? (Take “up” to Be the Positive Axis.)
a. ms ( v i )  J s  0
b. mh ( v i )  Jh  mh ( v f )
c. ms ( v i )  mh ( v i )
d. mh ( v i )  mh ( v f )
e. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball (mh) and the Sad Ball (ms).
If Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Equations Is
Not Correct? (Take “up” to Be the Positive Axis.)
a. ms ( v i )  J s  0
b. mh ( v i )  Jh  mh ( v f )
c. ms ( v i )  mh ( v i )
d. mh ( v i )  mh ( v f )
e. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball (mh) and the Sad Ball (ms).
If Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Equations Is
Not Correct? (Take “up” to Be the Positive Axis.)
a. J s  ms ( v i )
b. Jh  2mh ( v i )
c.
Jh  2 J s
d. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Consider the Happy Ball (mh) and the Sad Ball (ms).
If Dropped from a Height h, the Sad Ball Does Not
Bounce and the Happy Ball Bounces Back to Its
Original Height. Which of the Following Equations Is
Not Correct? (Take “up” to Be the Positive Axis.)
a. J s  ms ( v i )
b. Jh  2mh ( v i )
c.
Jh  2 J s
d. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Based on the Impulse Applied to Each Ball and
Newton’s Third Law, Which Ball Will Apply a Bigger
Impulse to an Object It Hits?
a. The happy ball will apply the larger impulse.
b. The happy ball and the sad ball will apply the same impulse.
c. The sad ball will apply the larger impulse.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
Based on the Impulse Applied to Each Ball and
Newton’s Third Law, Which Ball Will Apply a Bigger
Impulse to an Object It Hits?
a. The happy ball will apply the larger impulse.
b. The happy ball and the sad ball will apply the same impulse.
c. The sad ball will apply the larger impulse.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
An Impulse-Momentum Bar Chart Describes the
Following Situation: A Bullet Is Fired Horizontally
into a Block of Wood Resting on a Table.
Immediately After the Bullet Joins the Block, the
Block and the Bullet Move Together in the Positive
x-Direction. Which Equation Is Correct?
a. mBv Bi  mwv wi  J  mBv Bf  mwv wf
b. mBv Bi  0  0  mBv Bf  mwv wf
c. mBv Bi  mwv wi  J  (mB  mw )v f
d. mBv Bi  0  0  (mB  mw )v f
e. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
An Impulse-Momentum Bar Chart Describes the
Following Situation: A Bullet Is Fired Horizontally
into a Block of Wood Resting on a Table.
Immediately After the Bullet Joins the Block, the
Block and the Bullet Move Together in the Positive
x-Direction. Which Equation Is Correct?
a. mBv Bi  mwv wi  J  mBv Bf  mwv wf
b. mBv Bi  0  0  mBv Bf  mwv wf
c. mBv Bi  mwv wi  J  (mB  mw )v f
d. mBv Bi  0  0  (mB  mw )v f
e. They are all correct.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 50-kg Stunt Diver Is Falling at a Speed of 20 m/s
When She Is Stopped by Sinking into a Cushion
That Exerts an Average Force of 500 N on Her. How
Much Time Did It Take Her to Stop Moving Once She
Hit the Cushion?
a. 0.5 s
b. 1.0 s
c. 2.0 s
d. 5.0 s
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 50-kg Stunt Diver Is Falling at a Speed of 20 m/s
When She Is Stopped by Sinking into a Cushion
That Exerts an Average Force of 500 N on Her. How
Much Time Did It Take Her to Stop Moving Once She
Hit the Cushion?
a. 0.5 s
b. 1.0 s
c. 2.0 s
d. 5.0 s
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 10-kg Object at Rest Explodes into a 2-kg Object
and an 8-kg Object. Which of the Following Options
Could Describe the Final Velocities of the Objects?
a. The 8-kg object moves in the +y direction and the 2-kg
object moves in the −x direction.
b. The 8-kg object moves in the +x direction and the 2-kg
object moves in the −x direction.
c. The 8-kg object moves in the +y direction and the 2-kg
object moves in the +y direction.
d. The 8-kg object moves in the −y direction and the 2-kg
object moves in the −x direction.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
A 10-kg Object at Rest Explodes into a 2-kg Object
and an 8-kg Object. Which of the Following Options
Could Describe the Final Velocities of the Objects?
a. The 8-kg object moves in the +y direction and the 2-kg
object moves in the −x direction.
b. The 8-kg object moves in the +x direction and the 2-kg
object moves in the −x direction.
c. The 8-kg object moves in the +y direction and the 2-kg
object moves in the +y direction.
d. The 8-kg object moves in the −y direction and the 2-kg
object moves in the −x direction.
Copyright © 2019 Pearson Education, Inc. All Rights Reserved
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