2nd Session Model Answer
16) D
1) D
2) 1270m
3) B
4) A
5) A
6) D
7) C
8) C
9) D
10) A
11) B
12) A
13) A
14) c
15) C
𝑃2 = 2𝑃
𝑃 = 𝜌𝑔ℎ
𝑃 = 𝜌𝑔ℎ
𝑃 = 𝑃𝑜𝑖𝑙 + 𝑃𝑤
17)
17.5x106=830x9.8X+1000x9.8x(200
0-x)
17.5x106 = 8134X +1.96x107 –
9800X
X= 1270 m
𝑃 = 𝑃𝑏𝑜𝑡 − 𝑃𝑡𝑜𝑝
= 1.1𝑥103 𝑥10(2.2
− 2) = 2.2𝑥103 𝑃𝑎
𝐹
𝑃 = 𝜌𝑔ℎ =
𝐴
𝐹
290
ℎ=
=
𝜌𝑔𝐴 930𝑥9.8𝑥0.036
= 0.88 𝑚
𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
110𝑥103 = 100𝑥103
+ (1020𝑥10𝑥ℎ)
10𝑥103 = 10200ℎ
ℎ = 0.98 𝑚 ≈ 1𝑚
𝑃 = 𝜌𝑔ℎ = 1020𝑥10𝑥10𝑥103
= 108 𝑃𝑎
(𝑚𝑁)(𝑉)
𝐹 = 𝑚𝑎 =
= 𝑚𝑛𝑉
𝑡
= 6.6𝑥10−27 𝑥5𝑥104 𝑥1.5𝑥107
= 4.95𝑥10−15 𝑁
𝐹 4.95𝑥10−15
𝑃= =
𝐴
1𝑥10−4
= 4.95𝑥10−11
≈ 5𝑥10−11 𝑃𝑎
𝑃 = 𝜌𝑔ℎ = 1000𝑥9.8𝑥0.3
= 2940 𝑃𝑎
𝑃𝑡𝑜𝑡𝑎𝑙 = 100000 + (1030𝑥80𝑥9.8)
= 907520
≈ 900000
Same as (5)
𝑃 = 𝜌𝑔ℎ
15200 = 10𝑥0.8𝑥𝜌
𝜌 = 1900 𝑘𝑔/𝑚3
𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
(450 − 100)𝑥103 = 1030𝑥9.8ℎ
ℎ = 34.6 𝑚
𝑃 = 𝜌𝑔ℎ
100𝑥103 = 13.6𝑥103 𝑥9.8ℎ
ℎ = 0.75 𝑚
𝑃1 = 𝑃2
800 𝑋 = 1200 𝑌
P1 = 800x15=12000
P2= 1200x10=12000
18) c
𝑃1
𝑃2
𝜌 ℎ
𝑃
1800𝑥20
19) 1- B
2Closed
“B”,
Opened
“A”
20)
21)
22) A
23) C
a- 𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
Closed “A”, Opened “B”
b- 𝑃𝑎
c- 𝑆𝑙𝑜𝑝𝑒 (𝐴) > 𝑆𝑙𝑜𝑝𝑒(𝐵)
𝜌(𝐴) > 𝜌(𝐵)
a- 𝑃𝑎
b- 𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
c- 𝑆𝑙𝑜𝑝𝑒 (𝐴) > 𝑆𝑙𝑜𝑝𝑒(𝐵)
𝜌(𝐴) > 𝜌(𝐵)
𝑃 = 𝑃𝑤 + 𝑃𝐻𝑔 = 103 𝑥0.5𝑥9.8
+ 13600𝑥9.8𝑥0.1
= 1.8𝑥104 𝑁/𝑚2
𝑃 = 𝜌𝑔ℎ
𝑃∝𝜌
𝜌𝑘 < 𝜌𝑤 → 𝑃𝑎 < 𝑃𝑏
24) D
25) AA- 𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
1.11𝑥105 = 1.013𝑥105 + (1030𝑥10𝑥1)
𝑁
𝑁/𝑚2
= 1.11𝑥105 2
B𝑚
B- 𝐹 = 𝑃 𝑥 𝐴
5569.7 𝑁
26) C
27) A) C
A- 𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ = 1.013𝑥105 +
𝑁
B) A
800𝑥0.2𝑥9.8 = 1.02868𝑥105
𝑚2
B𝐹 =𝑃𝑥𝐴=
1.028𝑥105 𝑥0.4𝑥0.6 = 24688.3 𝑁
28) i) B
ii) A
iii) B
1
= 𝜌1 ℎ1 → 𝑃 = 1200𝑥60 = 2
2 2
1- A ) d
b) d
c) b
2- A)e
b) e
d) a
P= Pa + 𝜌𝑔ℎ(𝑠𝑢𝑟𝑓𝑎𝑐𝑒 𝑡𝑜 𝑝𝑜𝑖𝑛𝑡 𝑎) =
Pa+ 𝜌𝑔 (H-h) = Pa + 𝜌𝑔𝐻 - 𝜌𝑔ℎ
𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ
𝑆𝑙𝑜𝑝𝑒 = 𝜌𝑔
29) C
2
1
𝑃 = 𝑃𝑎 + 𝑃𝑜𝑖𝑙 + 𝑃𝐻2𝑂 + 𝑃𝐻𝑔
= 1.013𝑥105
+ (7200𝑥10𝑥0.5)
+ (1000𝑥10𝑥0.2)
+ (13600𝑥10𝑥0.1)
𝑁
= 120400 2
𝑚
𝐹 = 𝑃 𝑥 𝐴 = 120400𝑥100𝑥10−4
= 1204 𝑁
𝑃 = 𝑃𝐻2𝑂 + 𝑃𝐻𝑔 = 1000𝑥10𝑥0.1
+ 13600𝑥10𝑥0.1
𝑁
= 14600 2
𝑚
𝑃 = 𝜌𝑔ℎ
30) B
31) A
32) B
33) A
34) C
3.4𝑥1.013𝑥105 = 1000𝑥10𝑥ℎ
ℎ = 34.442 𝑚
𝑃 = 𝜌𝑔ℎ
= 1000𝑥 9.8𝑥20
= 196000
𝑃 = 𝑃𝑎 + 𝜌𝑔ℎ = 105
+ (1000𝑥 10 𝑥6)
= 1.6𝑥105 𝑁/𝑚2
𝐹 ↑ 𝑚𝑔
↑𝑃= =
𝐴
↑𝐴
𝐹
2𝑃 = 1
𝐴
Decreasing area to half
2
35) A
36) C
37) A
38) B
39) B
keeping the force constant,
therefore pressure increases to
double.
𝑃 = 2𝑥2.5𝑥105
= 5𝑥105 𝑁/𝑚2
𝐹
↑𝑃=
↓𝐴
𝑃=
𝑃=
𝐹 𝐹𝑐
𝑃𝑎 𝐴𝑐
20𝑥20 1
=
=
=
𝐴 𝐹𝑐𝑑 𝑃𝑎 𝐴𝑐𝑑 20𝑥40 2
𝐹 𝑚𝑔 𝜌𝑉𝑔 𝜌𝐴𝑋𝑔
=
=
=
= 𝜌𝑋𝑔
𝐴
𝐴
𝐴
𝐴
𝑃
→𝜌=
𝑋𝑔
2