GE1707 The Mathematics of Finance Simple Interest Simple Interest • A fixed percentage of the principal (the total amount invested) paid to a depositor or an investor each year the principal is left on deposit or has been invested; usually denoted by πΌπΌ • Fixed amount paid to a bank or any lender (one who gives money to a borrower) each year the principal has been borrowed • Formula: ππππππππππππ πΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌ = ππππππππππππππππππ π₯π₯ π π π π π π π π π₯π₯ ππππππππ or simply πΌπΌ = ππππππ Where: πΌπΌ - Simple Interest ππ - Principal ππ - Rate π‘π‘ - Time Then the final amount or Maturity value (πΉπΉ) at the end of π‘π‘ years can be solved using πΉπΉ = ππ + πΌπΌ Derived Formulas πΌπΌ 1. ππ = 2. ππ = ππππ πΌπΌ ππππ πΌπΌ 3. π‘π‘ = ππππ 4. πΉπΉ = ππ + πΌπΌ = ππ + ππππππ πΉπΉ = ππ(1 + ππππ) Example 1: If β±1,500 was borrowed at 8% simple interest, how much will the interest be for 2 years? Given: ππ = β±1,500; ππ = 8% ππππ .08; π‘π‘ = 2 years Find: πΌπΌ Example 2: If β±300 is the interest at 9% after 4 months, how much was borrowed? 4 1 Given: πΌπΌ = β±300; ππ = 9% ππππ .09; π‘π‘ = ππππ year 12 3 Find: ππ Example 3: If β±1,912.50 is the interest for investing β±9,000 for 2 years and 6 months, find the rate of interest. Given: πΌπΌ = β±1,912.50; ππ = β±9,000; π‘π‘ = 2.5 years Find: ππ Example 4: Accumulate β±8,000 for 1 year and 6 months at 10% simple interest. Given: ππ = β±8,000; π‘π‘ = 1.5 years;ππ = 10% ππππ .1 Find: πΉπΉ 05 Handout 1 *Property of STI Page 1 of 13 GE1707 Simple Discount Discount π·π· is a deduction from maturity amount πΉπΉ of an obligation allowed for paying it currently. The formula is π·π· = πΉπΉπΉπΉπΉπΉ, where: π·π· − discount πΉπΉ − amount of maturity ππ − discount rate π‘π‘ − time or term of discount To find ππ, use ππ = πΉπΉ − π·π· or ππ = πΉπΉ(1 − ππππ) Derived Formulas are π·π· π·π· π·π· ππ = ; π‘π‘ = ; and πΉπΉ = πΉπΉπΉπΉ πΉπΉπΉπΉ ππππ Example: Find the present value of β±2,000, which is due at the end of 90 days at 5% simple discount. 1 Given: πΉπΉ = β±2,000; π‘π‘ = ; ππ = .05 4 Actual Time This is the actual number of days between two (2) dates. Approximate Time This method considered that there were 30 days in each month or 360 days in one (1) year. Example 1: A note dated February 28 is due to be paid August 1. How many days will the note run? Example 2: Find the due date for a 130-day note dated July 7. Example 3: Determine the actual time and approximate time from March 3, 2015 to September 10, 2015. 05 Handout 1 *Property of STI Page 2 of 13 GE1707 Ordinary and Exact Interest Exact Interest denoted by πΌπΌππ , is a type of simple interest computed based on 365 days, that is, the exact number ππ year. of days in a year. In other words, the time π‘π‘ for 1 day is π‘π‘ = ππππππ ππππππππ πΌπΌππ = Pr 365 Ordinary Interest denoted by πΌπΌππ , is a type of interest computed based on 360 days, that is, assuming each month 1 year. in a year has 30 days. In other words, the time π‘π‘ for 1 day is π‘π‘ = 360 ππππππππ πΌπΌππ = Pr 360 Example 1: Find the interest on β±28, 700 at 7.3% from March 14, 2016 to August 16, 2016 using the following: a. ordinary interest using actual time c. exact interest using actual time b. ordinary interest using approximate time d. exact interest using approximate time Solution: Given: ππ = β±28,700 ππ = 7.3% = 0.073 The first step is to determine the approximate time and actual time of the term, then compute for the ordinary interest and exact interest. Month Actual Time Approximate Time March 14, 2016 31-14=17 30-14=16 April 30 30 May 31 30 June 30 30 July 31 30 August 16, 2016 16 16 Total 155 152 a. Ordinary Interest using Actual Time: πΌπΌ = ππππππ 155 πΌπΌ = 28,700(0.073) οΏ½ οΏ½ 360 πΌπΌ = β±902.06 π‘π‘ = 155 days c. π‘π‘ = 155 days b. Ordinary Interest using Approximate Time: πΌπΌ = ππππππ 155 πΌπΌ = 28,700(0.073) οΏ½ οΏ½ 360 πΌπΌ = β±884.60 Exact Interest using Actual Time: πΌπΌ = ππππππ 155 πΌπΌ = 28,700(0.073) οΏ½ οΏ½ 365 πΌπΌ = β±889.70 π‘π‘ = 152 days d. Exact Interest using Approximate Time: π‘π‘ = 155 days πΌπΌ = ππππππ 155 πΌπΌ = 28,700(0.073) οΏ½ οΏ½ 365 πΌπΌ = β±872.48 05 Handout 1 *Property of STI Page 3 of 13 GE1707 Compound Interest Compound Interest is interest computed on the sum of the original principal of a deposit or loan and the interest accumulated. It is denoted by πΌπΌππ . Computing for the Total Number of Conversion Periods When the interest rate is compounded annually, interest is computed once a year. Thus, one (1) conversion period is equivalent to one (1) year. The frequency of conversion, denoted by ππ, is the number of times that the interest is computed in the span of one (1) year. The time or the number of years of the term compounded interest is denoted by π‘π‘. Thus, the total number of conversion periods for the entire term, denoted by ππ, is the product of the number of years π‘π‘ and the frequency of conversion ππ. ππ = π‘π‘π‘π‘ The following table shows the different values of ππ given a particular frequency conversion ππ and time π‘π‘. Total Number of Conversions for the Entire Term at Various Conversion Periods Frequency of Time (π‘π‘) Description Conversion Period Conversion (ππ) Annually 1 year 1 year 1 Semiannually 6 months 3 years 2 Quarterly 3 months 2 years 4 Monthly 1 month 5 years 12 Value of ππ 1 6 8 60 The value of ππ (total number of conversions for the entire term) is dependent of ππ (frequency of conversion). If the term π‘π‘ is kept constant, ππ increases as ππ increases. Similarly, ππ is also dependent on π‘π‘. If ππ is held constant, ππ increases at π‘π‘ increases. Computing Interest Rates per Period Suppose you want to know how much the interest rate per period is for compound interest charged on a particular loan or investment. How do you get this value? First, determine the nominal rate, or the rate charge that may be converted several times per year, say semiannually. This type of rate is denoted by ππ. For example, you are investing β±36,000 for 5 years in a bank that pays 3% compounded semiannually. The nominal rate ππ is 3% or 0.03. Now, to get the interest per period, denoted by ππ, divide the nominal rate by the frequency of conversion per year as follows: ππ ππ = ππ The following table shows the different interest rates per period given a particular nominal rate: Interest Rate per Period for Various Conversion Periods Frequency of Interest Rate per Nominal Rate (ππ) Description Interest Period Conversion (ππ) Period (ππ) Annually 1 year 1 10% 10% or 0.10 Semiannually 6 months 2 12% 6% or 0.06 Quarterly 3 months 4 14% 3.5% or 0.035 Monthly 1 month 12 16% 1.33% or 0.0133 The accumulated value of the principal ππ at the end of the term is called the compound amount, denoted by the variable πΉπΉ. The formula for compound amount at the end of ππ periods is given by πΉπΉ = ππ(1 + ππ)ππ Where: • πΉπΉ is the compound amount or accumulated value of the principal ππ at the end of the term 05 Handout 1 *Property of STI Page 4 of 13 GE1707 • • • ππ is the present value or original principal ππ is the interest rate per period ππ is the total number of conversions periods. Example 1 If Mrs. De Leon invested β±12,900 for 4 years in a bank that pays 3% compounded semiannually, how much will she receive after 4 years? Given: ππ = β±12,900; π‘π‘ = 4 years; ππ = 2; ππ = 0.03 Solution: First solve for ππ and ππ. ππ 0.03 ππ = = = 0.015 and ππ = π‘π‘π‘π‘ = 4(2) = 8 ππ 2 Since the total number of conversion periods in 4 years is 8 and the interest rate per period is 1.5% or 0.015, it follows that πΉπΉ = ππ(1 + ππ)ππ = (β±12,900.00)(1 + 0.015)8 = β±14,531.75. Mrs. De Leon will receive β±14,531.75 after 4 years. Computing Compound Interest Compound interest is the total interest earned for the entire term. You can obtain it by getting the difference between the compound amount πΉπΉ and the principal or present value ππ. πΌπΌππ = πΉπΉ − ππ Example 2 Refer to the previous example. How much interest will Mrs. De Leon’s investment earn? Given: ππ = β±12,900.00; πΉπΉ = β±14,531.75 Solution: The compounded interest is computed as πΌπΌππ = πΉπΉ − ππ = β±14,531.75 − β±12,900.00 = β±1,631.75. Mrs. De Leon’s investment will earn total interest of β±1,631.75 after 4 years. Example 3 Find the compound interest earned at the end of 20 months if β±150,000 is invented in a fund that pays 20% compounded monthly. Given: ππ = β±150,000; ππ = 20% ππππ 0.2; ππ = 12; π‘π‘ = 20 months’ Solution: First solve for the interest rate per period. ππ ππ = ππ 0.2 = 12 οΏ½οΏ½οΏ½οΏ½οΏ½ = 0.01666 20 Next, solve for the total number of conversion periods. Note that π‘π‘ = 20 months means π‘π‘ = years. 12 ππ = π‘π‘π‘π‘ 20 = οΏ½ οΏ½ (12) 12 = 20 Compute the compound amount. πΉπΉ = ππ(1 + ππ)ππ = β±150,000(1 + 0.01666)20 = β±208,767.53 Lastly, compute for the compound interest. πΌπΌππ = πΉπΉ − ππ = β±208,767.53 − β±150,000 = β±58,767.53 05 Handout 1 *Property of STI Page 5 of 13 GE1707 The compounded interest earned for β±150,000.00 invested in a fund that pays 20% compounded monthly at the end of 20 months is β±58,767.53. Example 4 Accumulate β±30,000 for 3 years and 6 months at 16% compounded semiannually. 6 Given: ππ = β±30,000; π‘π‘ = 3 years; ππ = 16% (ππ = 2) 12 Solution: To accumulate means to find the compound amount. First, solve for the interest per period. ππ 0.16 ππ = = = 0.08 ππ 2 Next, solve for the total number of conversion periods. 6 ππ = π‘π‘π‘π‘ = οΏ½3 π¦π¦π¦π¦π¦π¦π¦π¦π¦π¦οΏ½ (2) = (3.5)(2) = 7 12 Compute the compound amount. πΉπΉ = ππ(1 + ππ)ππ πΉπΉ = β±30,000.00(1 + 0.08)7 = β±51,414.73 1 The compound amount at the end of 3 years of β±30,000.00 invested at 16% (m=2) is β±51,414.73. 2 Example 5 3 If β±1.5 million is invested in a fund that pays 23 % compounded monthly for 10 years and 8 months, how much 4 will be in the fund at the end of the term? 3 Given: ππ = β±1,500,000 ππ = 23 % 4 ππ = 12 π‘π‘ = 10 years and 8 months Solution: First, solve for the interest per period ππ. 3 23 % 23.75% 0.2375 ππ 4 = ππ = = = = 0.01979 ππ 12 12 12 Next, solve for the total number of conversion periods. 8 ππ = π‘π‘π‘π‘ = οΏ½10 οΏ½ (12) = 128 12 Compute the compound amount. πΉπΉ = ππ(1 + ππ)ππ πΉπΉ = β±1,500,000.00(1 + 0.01979)128 πΉπΉ = β±18,431,385.42 3 If β±1.5 million is invested for 10 years and 8 months in a fund that pays 23 % compounded monthly, the 4 compound amount at the end of the term is β±18,431,385.42. Present Value and Compound Interest Present Value refers to the value of a certain sum of money at the present time. πΉπΉ ππ = ππππ ππ = πΉπΉ(1 + ππ)−ππ (1 + ππ)ππ where • ππ is the present value • πΉπΉ is the future value or compound amount • ππ is the interest per period • ππ is the total number of conversion periods Example 6 What is the present value of β±35,000 due in 7 years and 6 months if the rate is 12% compounded quarterly? Given: πΉπΉ = β±35,000; π‘π‘ = 7 π¦π¦π¦π¦π¦π¦π¦π¦π¦π¦ ππππππ 6 ππππππππβπ π ππππ 7.5 π¦π¦π¦π¦π¦π¦π¦π¦π¦π¦; ππ = 12% = 0.12; ππ = 4 Solution: Solve for ππ and ππ. ππ 0.12 ππ = = = 0.03 ππ 4 ππ = π‘π‘π‘π‘ = (7.5)(4) = 30 Substitute the values of πΉπΉ, ππ, and ππ in the formula for ππ. 05 Handout 1 *Property of STI Page 6 of 13 GE1707 πΉπΉ β±35,000 = = β±14,419.54 ππ (1 + ππ) (1 + 0.03)30 Another way to solve the problem is by using the equivalent formula for ππ, ππ = πΉπΉ(1 + ππ)−ππ = β±35,000(1 + 0.03)−30 = β±35,000(1.03)−30 = β±14,419.54 The present value of β±35,000.00 that is due at the end of 7.5 years is β±14,419.54. ππ = Example 7 A certain principal ππ was invested at 6% compounded semiannually. If this principal amounted to β±94,500 at the end of 3 years, how much was the principal? Find the compound interest earned. Given: πΉπΉ = β±94,500; π‘π‘ = 3 π¦π¦π¦π¦π¦π¦π¦π¦π¦π¦; ππ = 6% ππππ 0.06; ππ = 2 Solution: Solve first for ππ and ππ. ππ 0.06 ππ = = = 0.03 ππ 2 ππ = π‘π‘π‘π‘ = (3)(2) = 6 Use the values of πΉπΉ, ππ and ππ to solve for ππ. ππ = πΉπΉ(1 + ππ)−ππ = β±94,500.00(1 + 0.03)−6 = β±79,142.26 The compound interest πΌπΌππ is then computed as πΌπΌππ = πΉπΉ − ππ = β±94,500.00 − β±79,142.26 = β±15,357.74 The present value of β±94,500.00 that is due at the end of 3 years is β±79, 142.26. The compounded interest that the investment earned is β±15,357.74. Stocks and Bonds Stocks A stock is a type of security that signifies ownership in a corporation and represents a claim on part of the corporation’s assets and earnings. Stocks are classified into two (2) types: the common stock and the preferred stock. In the Philippines, stocks are traded regularly at various marketplaces such as Philippines Stock Exchange (PSE) and Market Stock Exchange (MSE). These are places where an investor can buy or sell stocks through a licensed broker authorized to transact business in the market stock places. Bonds A bond is a certificate or a written contract in which the debtor promises to pay its holder a specified amount of money, plus a certain rate of interest at a stated future date. A company that needs money can borrow from investors by selling bonds. A bond is a debt covering a long term such as 10, 20 or more years. The investor is the bondholder who is guaranteed to be repaid at a specified future date. Typical bonds which are issued in various denominators are payable at par value or face value at maturity date. The par value or face value is the principal borrowed as stated in the bond. The par value is usually the price the investor pays when buying the bond from the issuing company. An investor may sell the bond at any time to another investor. Bonds are traded among investors. Hence, the value of a bond fluctuates up and down during its lifetime, depending on how many investors are willing to pay for it. The amount the investor actually pays for the bond is called the market. 05 Handout 1 *Property of STI Page 7 of 13 GE1707 A bond is sold at par when it is sold at a price equal to the face or par value, and is sold at premium when it is sold at a price higher than its face or par value. The bond is bought at a discount if it is bought for less than its par value. Dividends on Preferred and Common Stocks Dividends are the distribution of a company’s profits to its shareholders. Shareholders are persons who own shares of stocks in a corporation. There are two (2) types of stocks: preferred and common stocks. Preferred stocks is a class of corporate stock in which the investor has preferential rights over the common shareholders to dividends and a company’s assets. Common stocks is a class of corporate stock in which the investor has voting rights and shares directly in the success or failure of the business. A par value is an arbitrary monetary figure specified in the corporate charter for each share of stock and printed on each stock certificate. The dividend for par value preferred stock is quoted as a percent of the par value. Alternatively, a no-par value stock is a stock that does not have a par value and the dividend is quoted as a peso amount per share. Cumulative preferred stock is a type of preferred stock that receives a dividend each year. The dividend in arrears is the amount of dividends that accumulate and are owned to cumulative preferred shareholders before for past years in which no dividends are paid. Preferred stocks are categorized as nonparticipating and participating. Nonparticipating stock means that shareholders receive only fixed dividend, while participating stock means that the shareholders may receive additional dividends if the company perform well. Convertible preferred means the stock may be exchanged for a specified number of common shares in the future. The following are the formulas used in stocks: ππππππππππ ππππππππππππ ππππππππππππππππ π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) ππππππππππ ππππππππππππππππππ ππππππππππππππππ = ππππππππππππ ππππ π π βππππππππ × π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ ππππππππππ ππππππππππππ ππππππππππππππππ = ππππππππππ ππππππππππππππππ – ππππππππππ ππππππππππππππππππ ππππππππππππππππ π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππππππππ) = ππππππ π£π£π£π£π£π£π£π£π£π£ × π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππππ Example 1: The AUS Enterprises has 1,500,000 shares of common stock outstanding. If a dividend of β±30,000,000 was declared by the company directors last year, what are the dividends per share of common stock? Solution: Because the company has no preferred stock, the common shareholders will receive the entire dividends. Given: ππππππππππ ππππππππππππ ππππππππππππππππ = β±30,000,000 ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) = 1,500,000 ππππππππππ ππππππππππππ ππππππππππππππππ π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) 30,000,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = 1,500,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = β±20 ππππππ π π βππππππ The dividend per share of stock is β±20 Example 2: The board of directors of SSS, Inc. has declared a dividend of β±18,000,000. The company has 40,000 shares preferred stock that pay β±60 per share and 80,000 shares of common stock. Calculate the amount of dividends due the preferred shareholders and the dividend per share of common stock. Solution: πΊπΊπΊπΊπΊπΊπΊπΊπΊπΊ: ππππππππππππ ππππ π π βππππππππ (ππππππππππππππππππ) = 40,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππππππππ) = β±60 ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) = 80,000 05 Handout 1 *Property of STI Page 8 of 13 GE1707 The total amount of dividends of a preferred stock is ππππππππππ ππππππππππππππππππ ππππππππππππππππ = ππππππππππππ ππππ π π βππππππππ × π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ ππππππππππ ππππππππππππππππππ ππππππππππππππππ = 40,000(60) ππππππππππ ππππππππππππππππππ ππππππππππππππππ = β±2,400,000 Total amount of common dividend is ππππππππππ ππππππππππππ ππππππππππππππππ = ππππππππππ ππππππππππππππππ − ππππππππππ ππππππππππππππππππ ππππππππππππππππ ππππππππππ ππππππππππππ ππππππππππππππππ = 18,000,000 − 2,400,000 πππππ‘π‘ππππ ππππππππππππ ππππππππππππππππ = β±15,600,000 ππππππππππ ππππππππππππ ππππππππππππππππ ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = β±195 ππππππ π π βππππππ The dividend per share of common stock is β±195. π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = Example 3: Neri Corporation has 70,000 shares of β±2,000 per value, 5% cumulative preferred stock and 250,000 shares of common stock. Although no dividend was declared last year, a β±25,000,000 dividend was declared this year. Determine the amount of dividends due the preferred shareholders and the dividend per share of common stock. Solution: Take note that preferred stock is cumulative and the company did not pay a dividend in the previous year, the preferred shareholders are entitled to the dividends in arrears and the dividend for the current period. Given: ππππππ π£π£π£π£π£π£π£π£π£π£ = β±2,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππππ = 5% = 0.05 ππππππππππππ ππππ π π βππππππππ (ππππππππππππππππππ) = 70,000 ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) = 250,000 ππβππ ππππππππππππππππ ππππππ π π βππππππ ππππ ππ ππππππππππππππππππ π π π π π π π π π π ππππ π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππππππππ) = ππππππ π£π£π£π£π£π£π£π£π£π£ × π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππππ π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππππππππ) = 2,000(.05) π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππππππππ) = β±100 ππππππππππππππππ ππππππ π π βππππππ The total dividend on a preferred stock in arrears is ππππππππππ ππππππππππππππππππ ππππππππππππππππ = ππππππππππππ ππππ π π βππππππππ × π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ ππππππππππ ππππππππππππππππππ ππππππππππππππππ = 70,000(100) ππππππππππ ππππππππππππππππππ ππππππππππππππππ = β±7,000,000 ππππππππππ ππππππππππππππππππ ππππππππππππππππ = 7,000,000 (ππππππππππππππ) + 7,000,000 (ππππππππππππππ π¦π¦π¦π¦π¦π¦π¦π¦) ππππππππππ ππππππππππππππππππ ππππππππππππππππ = β±14,000,000 The amount of dividends due for preferred stock is β±14,000,000 The amount of dividends due for common stock is ππππππππππ ππππππππππππ ππππππππππππππππ = ππππππππππ ππππππππππππππππ − ππππππππππ ππππππππππππππππππ ππππππππππππππππ ππππππππππ ππππππππππππ ππππππππππππππππ = 25,000,000 – 14,000,000 ππππππππππ ππππππππππππ ππππππππππππππππ = β±11,000,000 Computing for the dividend per share ππππππππππ ππππππππππππ ππππππππππππππππ ππππππππππππ ππππ π π βππππππππ (ππππππππππππ) 11,000,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = 250,000 π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = β±44 ππππππ π π βππππππ The dividend per share of common stock is β±44. π·π·π·π·π·π·π·π·π·π·π·π·π·π·π·π· ππππππ π π βππππππ (ππππππππππππ) = 05 Handout 1 *Property of STI Page 9 of 13 GE1707 Stock Valuation Stock Valuation is the process of calculating the values of goods or materials owned by a company or available for sale in a store at a particular time. A. Current Yield for a Stock To measure how much you have earned on a stock as compared with other investments, compute for the current yield. The current yield is a way of determining the current value of a stock. The current yield shows how much dividend you can get as a percentage of the current price of the stock per share. If a stock pays no dividend, there is no current yield. The current yield is computed using the formula: πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ ππππππ π π βππππππ πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ Example 4: If MMDN Corporation paid a dividend of β±142.60 per share last year. If yesterday’s last price was β±2,300, what is the current yield on the stock? Solution: Given: π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ ππππππ π π βππππππ = β±142.60 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ = β±2,300 π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ ππππππ π π βππππππ πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ 142.60 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = 2,300 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = 0.062 ππππ 6.2% Example 5: Calculate the current yield for MMDN Corporation stock, which pays a dividend of β±70 per year and is currently selling at β±1,400 per share. Solution: Given: π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ ππππππ π π βππππππ = β±70 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ = β±1,400 π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ ππππππ π π βππππππ πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ 70 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = 1,400 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = 0.05 ππππ 5% The current yield rate per share is 5%. B. Price-Earnings Ratio of Stock Another thing that some people use to help them decide which stock to buy is the price-earnings ratio. This ratio is found using the formula: πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ ππππππππππ − ππππππππππππππππ π π π π π π π π π π = πΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈ ππππππ π π βππππππ Example 6: WSS Inc. is currently selling for β±2,685 per share. If the company had earnings per share of β±89.50 in the past year, what is the price-earnings ratio for WSS? Solution: Given: πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ = β±2,685 πΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈ ππππππ π π βππππππ = β±89.50 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ ππππππππππ − ππππππππππππππππ π π π π π π π π π π = πΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈ ππππππ π π βππππππ 2,685 ππππππππππ − ππππππππππππππππ π π π π π π π π π π = 89.50 ππππππππππ − ππππππππππππππππ π π π π π π π π π π = 30 ππππ 30: 1 This means investors are currently willing to pay 30 times the earnings for one share of WSS stock. 05 Handout 1 *Property of STI Page 10 of 13 GE1707 Example 7: Sofia would like to own stocks in SSS and GSIS, but she does not know if either stock is a good buy. One thing she can do is to look at the price-earnings ratio for each. a. SSS, price share β±2,464, annual net income per share β±88, and b. GSIS, price share β±1,900, annual net income per share β±76. Solution: Use the formula for price-earnings ratio to get a. Price-earnings ratio for SSS Given: πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ = β±2,464 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ 2,464 ππππππππππ − ππππππππππππππππ π π π π π π π π π π = = = 28 πΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈ ππππππ π π βππππππ 88 The price-earnings ratio of SSS stock is 28 times per share. b. Price-earnings ratio for GSIS Given: πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ = β±1,900 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ ππππππ π π βππππππ 1,900 ππππππππππ − ππππππππππππππππ π π π π π π π π π π = = = 25 πΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈπΈ ππππππ π π βππππππ 76 The price-earnings ratio of GSIS stock is 25 times per share. The price-earnings ratio is not a perfect guide to future market behavior of a stock. Occasionally a low priceearnings ratio implies that the stock is undervalued in the market-in order words a good buy. At times a low price-earnings ratio denotes that investors see a poor future for the company. C. Cost, Proceeds, and Gain (or loss) of a Stock Proceeds are the amount of money that an investor receives after selling a stock. It is computed as the value of shares less the broker’s commission. The stockbroker’s commission is the fee charges for assisting in the purchase or sale of shares of stocks; percent of the cost of the stock transaction. A stockbroker is a professional in stock market trading and investment who acts as an agent in the selling and buying of stocks or other securities. The gain (or loss) is the difference between the cost of purchasing the stock and the proceeds and received when selling the stock. One more factor affecting the commission is whether the amount of shares purchased is a round lot (multiple of 100 shares), or an odd lot (less than 100 shares). The commission rate on a round lot is generally a bit lower than an odd lot. The following formula will be used: πΆπΆπΆπΆπΆπΆπΆπΆ ππππ ππβππππππππ = ππππππππππ ππππππ π π βππππππ × ππππππππππππ ππππ π π βππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π π π π π π π π π π π π π π π π π π π = πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ × πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππ ππππππππππ ππππππππ = πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ + ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππ ππππππππππ ππππ π π βππππππππ = ππππππππππ ππππππ π π βππππππ × ππππππππππππ ππππ π π βππππππππ ππππππππππππππππ = ππππππππππππ ππππ π π βππππππππ − ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππ πΊπΊπΊπΊπΊπΊπΊπΊ (ππππ ππππππππ) ππππ π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘ = ππππππππππππππππ − ππππππππππ πΆπΆπΆπΆπΆπΆπΆπΆ Example 8: Shiela purchased 250 shares of AUS Inc. common stock at β±3,500 per share. A few months later, you sell the shares at β±4,000. Her stockbroker charges 3% commission on round lots and 4% on odd lots. Calculate the (a) total cost, (b) the proceeds, and (c) the gain or loss on the transaction. Solution: Given: Price per share = β±3,500 Commission rate (round lots) =3%=0.03 Number of shares = 250 Commission rate (odd lots) =4%=0.04 a. Cost of purchasing stock πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ = ππππππππππ ππππππ π π βππππππ × ππππππππππππ ππππ π π βππππππππ = 3,500(250) = β±875,000 π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ = πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ × πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ πππππ‘π‘π‘π‘ π π π π π π π π π π ππππππ ππππππππππππππππππππ = 200 π π βππππππππ × 3,500 × 0.03 = β±21,000 05 Handout 1 *Property of STI Page 11 of 13 GE1707 ππππππ ππππππ ππππππππππππππππππ = 50 π π βππππππππ × 3,500 × 0.04 = β±7,000 ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππππ = 21,000 + 7,000 = 28,000 ππππππππππ ππππππππ = πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ + ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππππ = 875,000 + 28,000 = 903,000 The total cost of 250 shares of common stock is β±903,000. b. Proceeds from selling stock ππππππππππ ππππ π π βππππππππ = ππππππππππ ππππππ π π βππππππ × ππππππππππππ ππππ π π βππππππππ = 4,000(250) = β±1,000,000 π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππππ = πΆπΆπΆπΆπΆπΆπΆπΆ ππππ π π βππππππππ × πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππ π π π π π π π π π π ππππππ ππππππππππππππππππππ = 200 π π βππππππππ × 4,000 × 0.03 = β±24,000 ππππππ ππππππ ππππππππππππππππππππ = 50 π π βππππππππ × 4,000 × 0.04 = β±8,000 ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππππ = 24,000 + 8,000 = β±32,000 ππππππππππππππππ = ππππππππππ ππππ π π βππππππππ − ππππππππππ π΅π΅π΅π΅π΅π΅π΅π΅π΅π΅ππ ′ π π ππππππππππππππππππππ = 1,000,000 − 32,000 = β±968,000 The proceeds on common stock are β±968,000. c. Gain (or loss) on the transaction πΊπΊπΊπΊπΊπΊπΊπΊ (ππππ ππππππππ)ππππ π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘π‘ = ππππππππππππππππ − ππππππππππ πΆπΆπΆπΆπΆπΆπΆπΆ = 968,000 − 903,000 = β±65,000 The transaction gain is β±65,000. Bond Valuation Bond valuation is a technique for determining the fair value of a particular bond. A. Current Yield of Bond The current yield of a bond is computed by dividing the annual interest by the purchase price of a bond. The current yield is obtained using the formula: π΄π΄ππππππππππ πΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌ πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = ππππππππππ ππππ ππ π΅π΅π΅π΅π΅π΅π΅π΅ Example 9: What is the current yield of a bond whose face value is β±14,500 and pays a yearly interest of 12% if purchased at face value at β±13,920? Solution: When the price of bond is β±14,500 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = When the price of bond is β±13,920 πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππ = π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ ππππππππππππππππ . 12(14,500) = = 12% ππππππππππ ππππ π΅π΅π΅π΅π΅π΅π΅π΅ 14,500 π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄π΄ πΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌπΌ . 12(14,500) = = 12.5% ππππππππππ ππππ π΅π΅π΅π΅π΅π΅π΅π΅ 13,920 B. Price of a Bond using General Method The same with stocks, when bonds are sold or bought, charge is commonly added to the price of the bond. The following variables will be in our mathematical treatment of bonds: ππ = π π π π π π π π π π π π π π π π π π π π π£π£π£π£π£π£π£π£π£π£ ππππ ππππππππ πΉπΉ = πΉπΉπΉπΉπΉπΉπΉπΉ π£π£π£π£π£π£π£π£π£π£ ππππ ππππππ π£π£π£π£π£π£π£π£π£π£ ππππ π‘π‘βππ ππππππππ ππ = ππππππππππ ππππ ππ ππππππππ ππ = π΅π΅π΅π΅π΅π΅π΅π΅ ππππππππ ππ = πΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆπΆ ππππππππππππππ ππ = ππππππππππππππ ππππππππππππππππ ππππππππ ππ = ππππππππππππ ππππ ππππππππππππππππππππ ππππππ π¦π¦π¦π¦π¦π¦ππ π‘π‘ = ππππππππ ππππππππππππ (π‘π‘π‘π‘π‘π‘π‘π‘) ππππ π‘π‘βππ ππππππππ ππππ ππππππππππππππππππππ ππ = ππππππππππππππππ ππππππππ ππππππππππππππππ ππππππππ ππ = ππππππππππππππππ ππππππππππππππππ ππππππππ The regular (periodic) interest payment from the bond will be: πΆπΆπΆπΆπ’π’π’π’π’π’π’π’ ππππππππππππππ = πΉπΉπΉπΉπΉπΉπΉπΉ π£π£π£π£π£π£π£π£π£π£ × ππππππππππππππππ ππππππππ ππππππππππππππππ ππππππππ 05 Handout 1 *Property of STI Page 12 of 13 GE1707 ππ = πΉπΉπΉπΉ The price of a bond is computed using the formula below: 1 − (1 + ππ)−ππ οΏ½ ππ = ππ(1 + ππ)−ππ + ππ οΏ½ ππ Example 10: A β±3,200, at 9% bond pays coupons quarterly and will be redeemed on July 7, 2016. Find the price if the bond is bought on July 7, 2012 to yield 8% compounded quarterly if the bond is redeemed at par, (b) if the bond if redeemable at 110%. Given: ππ = β±3,200 ππ = 4 The redemption value is ππ = 8% ππππ .08 π‘π‘ = 4 π¦π¦π¦π¦π¦π¦π¦π¦π¦π¦ ππ = 9% ππππ .09 ππ = π‘π‘π‘π‘ = 4(4 = 16) 0.09 ππ . 08 ππ = .0225 ππ = = = .02 ππ = = 4 ππ 4 ππ The coupon payments are β±72. ππ = πΉπΉπΉπΉ = 3,200(. 0225) = β±72 1 − (1 + ππ)−ππ οΏ½ ππ 1 − (1 + .02)−16 οΏ½ ππ = 3,200(1 + .02)−16 + 72 οΏ½ . 02 1 − (1.02)−16 οΏ½ ππ = 3,200(1.02)−16 + 72 οΏ½ . 02 ππ = 3,200(0.7284458137) + 72(13.57770931) ππ = 2,331.026604 + 977.5950706 ππ = β±3,308.62 The price of the bond to yield 8% is β±3,308.62. ππ = ππ(1 + ππ)−ππ + ππ οΏ½ At 110% redemption means ππ = 3,200(1.10) = β±3,520 1 − (1 + ππ)−ππ οΏ½ ππ = ππ(1 + ππ)−ππ + ππ οΏ½ ππ 1 − (1 + 0.02)−16 οΏ½ ππ = 3,520(1 + 0.02)−16 + 72 οΏ½ 0.02 ππ = 3,520(0.7284458137) + 72(13.57770931) ππ = 2,564.129264 + 977.5950706 ππ = β±3,541.72 The price of the bond is β±3,541.72. REFERENCES: Cordova, W., Gotauco, C., Ledesma, F., & Tabuloc, M.C. (2017). Mathematics of finance. Quezon City: Abiva Publishing House, Inc. Regacho, C., Benjamin, JB., & Oryan, S. (2017). Mathematics skills for life. Quezon City: Abiva Publishing House, Inc. Sirug, W. (2016). General mathematics. Manila: Mindshapers Co., Inc. 05 Handout 1 *Property of STI Page 13 of 13