Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine Section D Endocrine Mechanism • PHYSIOLOGY A – CELL PHYSIOLOGY Dr. Felipe C. Barbon • • Cell – basic unit of the human body that has different parts and different activities but trying to attain the same goal – homeostasis. Homeostasis – maintaining the constancy of the internal environment which is the EXTRACELLULAR FLUID – condition of the fluids outside the cell. Why Extracellular Fluid is referred to as the internal environment? • Neural and Endocrine Control Mechanisms Negative Feedback • opposition of the regulating system against a certain activity in the body. • If there is an increase activity in the body the regulating system will oppose the activity and bring the condition back to normal but not to the point of below normal. • Negative feedback on the endocrine mechanism: o Hormone that affects another hormone o Stimulatory hormones if the body is in need of hormones o Inhibitory hormones if there is an increase in hormones • E.g.: Increase blood pressure can damage the cardiovascular system. Thus the regulating system will oppose the activity will bring it down, back to normal. b) Modified Negative Feedback • Applies ONLY in the endocrine system. • Maintenance of normal hormones in the blood is non-hormonal metabolitedependent • Non-hormonal agent controlling a hormonal agent in the circulation of the body. • E.g. Plasma glucose in the blood being controlled by the hormone Insulin. But Insulin being controlled by glucose which is a non-hormonal metabolite. Thus, the level of the hormonal agent is affected by the non-hormonal agent but that non-hormonal agent is controlled by the affected hormone. Positive Feedback • progression and enhancement of the certain condition to regain the normal function of the body. • E.g. coagulation activity of the blood during blood vessel injury. Constriction of the injured blood vessel→activation of the platelets→activation of clotting factor→clotting for the prevention of blood loss. To attain homeostasis, constant condition of the said environment must be maintained including the amount of solute and the amount of water. No balance or equilibrium especially in the amount of solutes inside and outside the cell (e.g. more Sodium ions outside the cell and Potassium ions inside and/or outside the cell.) – no equal amount of ions: no equilibrium. In homeostasis we just maintain the amount of solutes and water in the ECF to maintain a constant or normal activities of the different cells inside the body. All cells and organs in the body are being regulated by the nervous and endocrine system. 1. Nervous System – controls the activity of different cells or tissues in the body. They generate nerve impulses (action potential or electrical activities of neurons.) Neural Control • • • Responsible for the secretory and mechanical activities of the body which can either be voluntary or involuntary. Mostly affects the activity of skeletal, cardiac or smooth muscles and the secretory cells. Onset of action: Rapid Onset and Short duration Two types of Neurons in the body: 2. a. Motor or somatic neurons • controls the skeletal muscles that makes it a voluntary control. b. Autonomic neurons • controls the involuntary activity of the cardiac and smooth muscles. Endocrine System- make use of endocrine tissues or cells. Releases hormones that regulate the activity of the human body. Known as the hormonal or the humoral control. ! a) Because ECF is present inside the body which is the normal environment of the different cells present in the body. Regulating Systems Responsible for the metabolic activities of the body although it affects motor and secretory activities minimally. Includes all cells responsible for metabolism. Onset of action: delayed and long duration. Reproduction: endocrine mechanismdependent. Failure of the endocrine system is failure of the ability to reproduce. c) Escoto, Kelvin C.E. • d) E.g. Continuous increase uterine contraction during labor to promote birth of the baby. Feed Forward Control • The body anticipates the effect of a certain stimulus in the environment allowing the body to react in advance to the said stimulus that will affect the body. • E.g. A person not used to exercise being forced to exercise will have an anticipatory reaction of increase respiratory rate and heart rate even without the increase muscular activity. Up regulation vs. Down regulation 1. 2. 3. 4. Smooth Endoplasmic Reticulum • Needed for lipid synthesis Rough Endoplasmic Reticulum • Needed for protein synthesis Golgi Complex • Concerned with the secretion that packages the agents that are to be secreted. Said to be numerous in actively secreting cells Mitochondria • Numerous in actively metabolizing cell. • Power-house of the cell Physiology is more concerned with the cell membrane The cell membrane Neurons generate impulses basically action potentials. For an impulse to be generated, neurons should have an uninterrupted connection but the neural connections have gaps or spaces that are known as synapses. Thus, for a neuron to produce an impulse, it should have a chemical agent to overcome the gaps. This chemical agent is also known as the neurotransmitter. Plus, another neuron must have a receptor to receive and continue the transmitted impulse by the neuron with a neurotransmitter. For a hormone to affect effectively the cells they control, the hormone should react to a hormone receptor. e) f) Up-Regulation • Decreased amount of neurons and hormones in the regulation system would result to decrease effect in the action that would lessen the control on the affected cell. Thus, the affected cell will INCREASE the receptors. Increase the number of receptors would increase the effect of the neurons or the hormones in the controlled cell. Down-Regulation • Lesser amount of the control agents (the neurons or the hormones) The controlled cell will DECREASE the number of receptors to maintain the normal activity of the body. Structures that allow the cell to be in close contact with another cell and prevents separation of one cell to another: 1. Tight Junctions (Zonula Occludens) • Concerned with transport of ions and water molecules. • Involved in Paracellular Transportation wherein agents pass in between cells but they do not pass through the cell membrane (Apical and Basal part.) It involves two proteins: Ø Occludins Ø Claudins – determines the characteristic permeability of the membrane. The greater the amount of claudins means the tighter is its junctions. The tighter the junctions, the lesser the permeability. 2. 3. Macula Adherens (Desmosome) Gap Junctions • Also known as pores or the openings in the membrane that forms the channels • Promote transportation but also concerned with cell communication. • Functional unit: Connexons – made up of the connexins protein. Escoto, Kelvin C.E. • 4. Contrary to paracellular transportation is Transcellular Transportation wherein the utilization of the agents passes or penetrates the gap junctions of the cell membrane. - Hemidesmosome • Allows the basal portion to be in close contact with the basement membrane. - - Activities on the Different Parts of the Cell 1. 2. Apical Region • Area of absorption and secretion. Some of the secreted agents are needed for cellular protection. 2. Lateral Region • The cell is close contact with another cell – transport and communication. • Cell contact and Adhesion 3. Basal Region • Area where cells are affected if there are activities coming from the neurons and hormones that creates ion gradients allowing the cell to create electrical changes. The Cell Membrane § Maintains the composition (solute) of ICF and ECF § Regulates cellular transport § Site of signal transduction or cell communication § Acts as an anchor for structural proteins (stability, size and shape) Easily transports lipid agents that are amphipathic (Lipid soluble). Phosphatidylcholine Phosphatidylserine Phosphatidylethonolamine Phophatidylinositol Ø Cholesterol Moderator molecule providing mechanical stability as well as flexibility Makes the membrane less permeable to water Prevents lipid crystallization Proteins 40-50% • part wherein the transport of watersoluble agents can be observed. Responsible for the transport of watersoluble particles. Functions: • Receptor for hormones and neurotransmitter agents • Source of enzymes • Skeletal Framework • Stability Two Types of Proteins: 1. Integral proteins or the Transmembrane proteins. § They are capable of functioning as: Ø channels (pores/opening in the membrane) Ø carriers (transporters) of the water-soluble particles 2. Peripheral Protein – present mostly on the surface of the membrane. § Can function as antigenic markers 3. Carbohydrates • Majority are present in the extracellular surface. • Usually combined with proteins (CHO+CHON = glycoproteins) and lipids (CHO + Lipids =glycolipids.) They don’t appear as pure carbohydrates in the cell membrane. • Difficult to transport water-soluble agents penetrating the lipid bilayer • Functions as: § Serve as antigenic markers § Provide stability § Attachment agent § Cell communication § Some can function as cell channels (Glycoproteins)that transport watersoluble particles. Composition of the Cell Membrane 1. Lipids • 50-60% (almost equal with the amount of protein) Ø Phospholipids – major lipids found in the cell membrane. They are amphipathic (can combine with fats and water molecules.) Arranged as a bilayer – Phospholipid bilayer. Semi-permeable vs. Selectively Permeable Cell Membrane § § Semi-permeable membrane can only transport water or solvent molecules and not of the solute. Selectively Permeable Capable of transporting both solvent and solute molecules. Selection is observed in the transport of solutes. Cell of the human body is selectively permeable. Escoto, Kelvin C.E. - Most of the cells in the body are selectively permeable. During a resting human cell its cell membrane is: § § § § § Note: Permeability of the membrane can be altered. E.g. the skeletal muscle cell is in need of glucose. The permeability can be changed allowing the permeability of the skeletal muscle cell to become permeable to glucose. Here come’s the importance of the hormonal control wherein the aid of insulin will allow the membrane of the muscle cell to let glucose be transported. Different Transport Activities in the Cell Active Transport § Needs energy for its activity § Transport of agent going against the direction of the energy gradient. (activista. Against!) § Lower to higher pressure gradient § Uphill/”Pump” Transport (e.g. the Na-K ion pump. Meaning the the action is active from a lower to higher gradient. § Unidirectional (going inside) § E.g. In Na-K pump, sodium ions inside the cell lesser than outside since Sodium is the major extracellular cation, and the movement of the active transport is from lower to higher movement that’s sodium ions when actively transported, the movement of the transport will be from the inside to the outside (Dalawang P.I.S.O. – 2 Potassium ions Inside. 3 Sodium ions Outside) § Uses carriers to oppose the energy gradient to facilitate transport agents in and out of the cell that’s why it is energy or mitochondrial activitydependent. Thus, the greater the energy gradient, the greater the energy consumption by the carriers. § It is a continuous process because equilibrium can never be attained. The manner of transportation is from lower to higher. In the area of lower concentration, the area progressively becomes lower while in the area of higher concentration, progressive amount of agent is being increased. It is possible for a continuous process as long as the cells are still alive. If the cell dies there will be no functioning mitochondria, no energy will be produced to supply the process. Limited number of carriers in the membrane. If these are exhausted the rate of transport will stop. If the maximum rate of active transport is reached, you can never increase the rate of reaction – this condition is called saturation. The transport is continuous but the rate of transport cannot be increased. When plotted: initially only a few number of carriers are utilized and then there will be a gradual increase in the rate of transport. When the carriers in the membrane are now involved in the transport, the transport will still continue but it will undergo plateau and the rate of transport will not increase – Saturation Kinetics. In renal physiology it is known as Transport maximum (Tm) Active transport: they are not concerned with the transport of fatty acids except for the short chain fatty acids which utilizes carriers and normally happen in the colonic mucosa. Happens only in living things since mitochondria is a pre-requisite for energy production. Would ONLY utilize a transcellular transport Passive Transport § Does not require energy § A type of transport wherein the agent goes along with the direction of the energy gradient (go with the flow) § Direction: from higher to lower gradient § Downhill Transport § Bidirectional (either going inside or outside the cell) § Uses channels § Channels could be gated wherein the activities can be controlled or regulated. Closing the gates of the channel prevents the transport while opening the gates promote transport. § It is a non-continuous process because if the concentration of a certain agent transported by the cell has the same amount of agent outside and inside the cell there will be no presence of energy gradient, there will be no continuous passive transport because the agent cannot go along the gradient since there is already equilibrium wherein the concentration is equal inside and outside the cell. § Water in passive transport is dependent upon the effect of osmotic pressure. § Passive transport is more concerned with lipophilic agents. § For the transport of lipid materials, they only penetrate the lipid bilayer without utilizing channels. § Can be observed in living and non-living cells. It happens in non-living cells since it does not require energy. E.g. a dry paper placed in water. The paper will absorb the water by passive process. § Utilizes either transcellular or paracellular transport. Escoto, Kelvin C.E. Common Gradients Encountered by the Cell during Transport: § Concentration gradient (Pressure gradient) Hydrostatic or Osmotic pressures § Electrical Gradient We do not use the principle of the movement of the agent from a higher to lower or lower to higher gradient to electrical gradient. For us to know whether the activity is going along or going against the gradient, look at the electrical charge of the agent being transported and the electrical charge of the area where the agent is to be transported. E.g. Positively charged agents transported to a positively charged area is considered ACTIVE TRANSPORTATION since like charges repel. Attraction is seen in unlike charges wherein easy passage of the agent won’t be hindered it’ll just go with the flow. Usually passive transport does not utilize carriers except to facilitated Passive Transport. In this type of transport, the carriers involved in the activity does not move the transport agent against the gradient. They help facilitate the agent to get transported in the gradient along the gradient. So, there is no energy expenditure. In passive transport, specific or non- specific channels can be utilized to process the transport. E.g. the transport of water, they utilize a specific water channels known as aquaporins, that will not transport any other substances aside from water. Another example is the Na-K leak channels. PASSIVE TRANSPORT Along a gradient Downhill No ATP consumption ACTIVE TRANSPORT Against a gradient Uphill/Pump ATP utilization (Mitochondria) No carrier Always involves carrier Glycoprotein channels Glycoprotein channels No inhibition Equilibrium Bidirectional Undergoes inhibition Saturation Unidirectional Hydrophilic agents →CHON channels (gated/non-gated) Hydrophilic agents →CHON channels (transporters) Living/non-living cells Living cells Water→CHON channels Carrier →facilitated diffusion Lipophilic→Lipid bilayer Carrier vs. Channel: • In transport involving channels. The larger the energy gradient the faster the passive transport. • Carrier-involved activities are slower compared to channel-involved activities because they • need energy to perform action. They will wait for the mitochondria to produce energy. After the energy is produced, they have to metabolize the ATP to have a high energy phosphate bonds. Plus, they have to counteract the force of the energy-gradient which will also take time. Carrier and Channel (gated-channel) activities can be regulated. Factors Affecting the Transport: • • • • • • Channels/pores are concerned mostly with passive transport and the passive transport activity is usually energy independent, they don’t require energy for their activity. But, they can also be specific. The selectivity and specificity depends on the size (molecular weight), shape and electrical charge of the agent and the transport involving channels can be regulated by means of its gating-properties. Solubility Nature of the substance Membrane thickness Area of transport Energy gradient Different Gating-Mechanisms: • Voltage-gated o A change in the electrical activity of the cell would allow the voltagegated cell membrane to open or close. o All excitable cells of the body have electrical activities. o Outside surface of the cell – Positive o Inside surface of the cell – when the cell is resting the cell is Negatively charged: Inside-negative condition. • Ligand-gated o Usually associated with the guanosine proteins which can sometimes have an inhibitory or stimulatory effect. o Ligands- chemical agents involved in creating change in membrane permeability. In the neurons, these are the neurotransmitter. In the endocrine system, these are the hormones. o Ligands not in contact with the channel are closed. Ligand in contact with the channel is open. o For any chemical agents to exert their effects, the cell itself must have a receptor for the ligand. o Neurotransmitter o E.g. Acetylcholine the major neurotransmitter must have the cholinergic receptor. Two types of cholinergic receptors: 1. Muscarinic CR 2. Nicotinic CR o Epinephrine and norepinephrine must have epinephrine and norepinephrine receptors (adrenergic receptors) Two types of adrenergic receptors: 1. Alpha AR 2. Beta AR Escoto, Kelvin C.E. Hormones – whatever the name of the hormone is the name of their receptors o Growth hormone – Growth hormone receptor G-Protein-Linked Channels o Some ligands are dependent with Gproteins. For them to exert their effects on the channel they control, the channel must contain G-proteins. If that is a guanosine stimulatory proteins, the channel will be opened. If it is an inhibitory G protein, the transfer will be prevented. o E.g. In the skeletal muscle or adipose when the cell is resting, no transport of glucose is happening but in the presence of insulin, which serves as the ligand, will help open up the glucose channels. o • o Mechanically-gated/Stress-activated • o Stretching the cell-membrane can open up the channels since the channels are pulled apart. Note: Not all activities of the channel can be regulated because some channels are non-gated; They are always open wherein it can be completely open or partial. The activity will now be continuous transport and is known as passive or leaky channels. These channels can be seen in the GIT. DIFFERENT PASSIVE TRANSPORTS Passive transport of small amount of agents: Osmosis – only water or solvent molecules are being transported. o Allows water/solvent molecules to move from lesser to greater solute concentration. Plus, the solute must be osmotically active to attract water. o Osmotic pressure is highly dependent on the amount of osmotically active agents present in the solution. o The greater the amount of the active osmotic agents, the greater is the osmotic pressure, the greater the ability to attract water. o RBC on an isotonic solution: Ø No change in volume and cell size since they have the same concentration of solutes; the water will not have any net flow to any direction. They can move in and out BUT in equal amounts. Isotonic concentration Ø Sodium Chloride (NaCl): 0.9% or 280-300 mOsm/L (ave. 290) Ø Glucose: 0.5% Ø Lesser value: Hypotonic Ø Greater value: Hypertonic RBC on a hypotonic solution: Ø Swelling of cell will occur. If the cell has the amount of greater solute, water will move from the hypotonic to the cell allowing it to swell and burst. Ø Irreversible o RBC on a hypertonic solution: Ø The hypertonic solution has the higher concentration allowing the water to move out of the cell making it crenate or shrink. (just remember HYPERCREN) Ø Reversible Diffusion – mostly concerned with solute transport; but can also promote solvent transport. o o o Simple Diffusion – the transport of the solute does not require any membrane or it can require a membrane but that membrane should be permeable to all solvents and solutes. Facilitated Diffusion – the diffusive process requires the activity of a carrier. Isotonic – normal condition of the human body fluid. Normal human cell environment. Escoto, Kelvin C.E. Filtration – transport of the solvents and solutes on a highly porous membrane with numerous channels. Commonly seen in fenestrated capillaries of the GIT and kidney especially in the glomerulus. o There is selective filtration: almost everything is being filtered in the glomerulus except the large particles (blood and protein.) Passive transport of large amount of agents: Bulk Flow – e.g. flow of urine, flow of bile in the biliary ducts, blood flow o They follow pressure differences o In the cardiovascular system, the highest pressure can be recorded in the left ventricle while the lowest pressure can be recorded in the right ventricle – Central Venous Pressure (CVP) Solvent Drag – always observed whenever there is bulk flow. (e.g. in the plasma) o Van’t Hoff’s law – osmotic pressure is dependent on the concentration of the osmotically active particles. Diffusion Laws o Fick’s Law o Stokes-Einstein Equation Determination of Plasma Osmolarity đˇđś = đ × đˇđđđđđ đľđ + đˇđđđđđ đŽđđđđđđ đŠđźđľ + đđ đ. đ Estimate of PO = Plasma Na x 2 Normal Values: Normal Tonicity: 280-300 mosm/L Sodium: 135-145 meq/L Glucose: 60-110 mg/dL BUN: 8-20 mg/dL Note: Tonicity is dependent on the presence of solutes. Wherein the solutes should be osmotically active; it should be able to attract water. An osmole holding on to water should not be able to traverse the membrane and move out the area. o E.g. With a normal amount of plasma proteins, the body can retain normal amount of water in the vascular compartment. If the plasma proteins will decrease the water will move out of the vascular compartment and will go to the interstitial spaces that will produce edema. o Solutes that are able to penetrate the membrane and stays in the area are good osmotic agents which makes the osmotic coefficient equal to one. These are the proteins in the blood specifically albumin. o If the osmotic coefficient is equal to zero that makes the agent ineffective. o Plasma proteins are responsible for maintaining the osmotic pressure in the blood while the Electrolytes are essential in maintaining the osmotic pressure inside the cell. o Regulatory Cell Volume Decrease Ø If the plasma is hypotonic it is expected that the cells are going to swell but the body will try to maintain to normalize the shape of the red blood cell. If there is a transient hypotonicity of the plasma, the cell will transport some of the electrolytes or solutes out of the cell to lessen the number of osmotically active agents. o o o o Regulatory Cell Volume Increase Ø Vice Versa DIFFERENT ACTIVE TRANSPORTS Carrier mediated that involves carrier proteins present in the cell membrane. Some types of active transports do not require carriers in the membrane but are involved almost in the movement of the membrane. Energy dependent Steps during the Active Transport: 1. Association – usually starts with the binding of the agent to the carrier molecule. 2. Translocation – The carrier will change its configuration or shape that will promote the movement of the agent to another location. 3. Dissociation – When they are on their location the carrier will release the agent allowing them to separate from one another. Carrier o Energy-dependent o Selectivity and specificity (dependent on the size and shape of the binding site of the carrier molecule. The agent should fit exactly on the binding site of the carrier molecule) o Can undergo saturation or inhibition (Competitive inhibition) o The activity can be regulated or mediated using chemical agents usually a ligand (hormones) Primary Active Transport o Agents are moving all against their electrochemical gradient. o Can progress on their own without any simultaneous transport happening. 1. Uniport Ø Carrier transports one agent at a time. Ø Hydrogen pump 2. Antiport Ø Exchange transport Ø One is transported in and another one is transported out Ø E.g. Na-K exchange pump, H-K exchange pump Ø Na-K exchange pump is an electrogenic transport that happens continuously in an excited cell like cell of the muscles and neurons. Ø PISO directions cannot be changed. Escoto, Kelvin C.E. 2PISO: 2 Potassium In. 3 Sodium Out Influx – Transport of ions inside the cell Efflux – transport of ions outside the cell • • • Note! Some Active Transport are non-electrogenic. It means that the exchange of ions is in equal amounts. E.g. the Hydrogen-Potassium Exchange pump. 2H ions in exchange of 2K ions would still have an exchange mechanism but will not create an electrical change in the cell. Making it a non-electrogenic active transport or an Electro-Neutral Pump. Secondary Active Transport o Some agents are transported against their gradient while other agents are transported along their gradient. o Only occur when another active transport is simultaneously happening. o Antiport-dependent o Mechanism will be effective when there is Na-K exchange pump. 1. o 2. Similar to uniport Hydrogen pump ATP-Binding Cassette Transporters o A type of transport associated with Cystic Fibrosis Transmembrane Conductance Regulator (CFTR) • • Carrier independent Do not utilize carriers but the cell membrane acts as a whole that forms vesicles. 1. Endocytosis – membrane of the cell takes in the agent. Exemplified by: Phagocytosis – ingestion of large agents. o Pinocytosis – intake of agents in fluid form. o Involves a “docking” process wherein there is binding with a specific membrane protein receptor that will form a vesicle in the cell membrane coated by clathrin. o The vesicle is initially part of the membrane. They are coated with clathrin. Vesicles are then separated from the cell membrane and referred to as vacuoles. After the vesicles separate they will be surrounded with lysosomes and agents will be digested. The clathrin will separate from the vesicle after digestion and the clathrin will be recycled and allow the membrane to perform another endocytosis. o Once the vesicles trapped a certain agent it will also need other accessory proteins like adaptin and dynamin. There is also involvement of microtubules and the dynein protein. o Portions without clathrin are not involved in endocytosis o Absorption can be regulated: Ø Fluid phase Unregulated Absorption; nonspecific E.g. absorption in the GIT Ø Adsorptive Endocytosis Regulated Absorption Requires a chemical agent or ligands which will react with the receptors to start the activity Receptor mediated or adsorptive endocytosis Transcytosis or Cytopempsis o Rapid transport of substance o Endocytosis at the apical portion of the cell followed by exocytosis at the basal part of the cell. o Counter Transport o Exchange transport o E.g. Sodium Calcium Counter transport that is dependent on the Na gradient provided by the Na-K exchange pump: Na transported inward. Ca efflux happens simultaneously. o Digoxins – cardiac glycosides that inhibits the Na-K ATPase activity that decreases the activity of the symporters and counter transporters. ATP-Dependent Transporters or ATPase Ion Transporters o P-Type Ø Similar to antiport V-Type Ø Ø Na-K exchange pump, H-K exchange pump VESICULAR TRANSPORT Depends its activity with the normal NaK pump activity. E.g. Sodium – Glucose cotransport, Sodium-amino acid cotransport (2 substances), Na-K Chloride cotransport (3 substances) Other Carrier-mediated Transport from Berne and Levy: Active Transport also have another type of carriermediated active transport and this are the: 1. o Symport o Also known as Co-transport/Coupled Transport. o Carries several agents at a time. o Usually transports 2 agents at a time but can also transport 3 agents simultaneously in one direction. o 2. Ø 2. 3. Exocytosis/Emeiocytosis – moves the agent outward. o Reverse phagocytosis and pinocytosis Escoto, Kelvin C.E. o o o 1. 2. Also needs clathrin In the movement of the vesicle, it needs the protein Kinesin Secretory vs. Excretory Activities of the Cell Similar to the direction of transport: out of the cell. Secretion – releasing of agents that are need by the body and can affect the activity of other cells. Excretion – excreted agents are considered waste products and released from the body. Renal System: major excretory system of the body that excretes almost all waste products of the body except carbon dioxide that are excreted by the respiratory system. o Note: Secretion and Excretion can also be regulated, partially-regulated or non-regulated. o 2 Pathways Involved in Exocytosis 1. Constitutive Pathway Ø Continuous partially Ø E.g. of non-regulated secretory activity is the secretion of the mucus, secretion of mucus cannot be control or can be controlled at least partially. 2. Non-Constitutive Pathway Ø Fully regulated pathway using a ligand that will initiate the transport. Passive Transport Osmosis Diffusion • • Simple Facilitated Filtration Bulk Flow Solvent Drag Active Transport Carrier Mediated: • Uniport (Primary) • Symport (Secondary) • Antiport (Primary) Transcytosis Pinocytosis Phagocytosis Factors that Affect the Transport of the Cell 1. 2. 3. 4. 5. Nature of the Substance o Lipid soluble agents easily penetrates the membrane since there is no need for them to look for channels as they can directly penetrate the lipid bilayer membrane. Size of the Agent/Molecular Weight o It should be very small (>2nm or 20 Ångström) and it should be very light (69,000 MW) to easily pass through the membrane. Membrane Thickness o The thicker the membrane the lesser the rate of transport whether active or passive transport. Surface Area o The greater the area the greater the transport; the lesser the area the lesser the transport. Number of Channels/Pores o In passive transport: the greater the channels, the faster the rate. Permeability coefficient –permeability of the membrane is dependent on the number and size of channels. 6. Number of Carriers o The greater the carriers in number, the faster the rate of transport. 7. Membrane Permeability o Semi-permeable membrane can only transport water. 8. Exposure o The longer the agents are exposed to the membrane, the greater the rate of transport. o Lesser time the agent is exposed; lesser amount of agent is being transported. 9. Energy Gradient o Passive transport with greater energy gradient = grater the force = greater the rate o Active Transport with greater energy gradient = greater force needed = the rate of the transport is lesser Gradient Time Limitation – combined length of exposure and energy gradient. o o o o Cell Signaling or Cell Communication Also known as signal transduction Gap junction – part of the membrane used for cell communication by adjacent cells or cells in direct contact with one another. Connexons – are chemical agents made up of smaller proteins called connexins and are used for communication by distant cells or nearby cells that are not directly in contact with another cell. Communication using Chemical agents: Ø Synaptic communication using neurotransmitter can be used in adjacent cell communication. Ø Hormones are used during distant cellcommunication. o Autocrine - cells communicating with another identical cell within the area and are not directly in contact with one another. Ø Released to interstitial fluid Ø E.g. communication happening in the islets of Langerhans: a group of cells present in the pancreas. Beta cells communicating with another beta cells. o Paracrine - cells communicating with another nonidentical cell within the area and are not directly in contact with one another. Ø E.g. Beta cells communicating with another alpha cells in the islets of Langerhans in the pancreas. For the Communication to Happen: 1. Change must be created in the extracellular region that will eventually affect the cell. Extracellular change will be transformed by the affected cell into intracellular changes or also known as intracellular messages. Intracellular agents will be affected by the changes allowing to produce an activity that will be directed to extracellular change. 2. For it to react to extracellular change affecting the cell, ligand-receptor interaction is needed. Receptors can be present in the cytoplasm or the nucleus (intracellular receptors). 3. Interaction of Ligand and receptor will produce Ligand-receptor complex that will now activate certain enzymes present in the intracellular surface of Escoto, Kelvin C.E. 4. the cell. These enzymes are known as the second messengers. Once these second messengers are activated, they will affect certain type of protein or an enzyme in the cytoplasm. Then it will create a response directed to the extracellular change affecting the cell. STEPS IN CELLULAR COMMUNICATION WITH CHEMICAL AGENT USE 1. 2. 3. 4. Synthesis of the Agent • Ligand is needed to activate the cell. Release of the Agent • E.g. In the synapse the NTA are normally produced in the pre-synaptic. Transport of Agents Towards the Target Cell • The agents from the pre-synaptic are released to the post-synaptic once the agents are needed. Interaction with the Cellular Receptor • The cell should have the receptor for effective communication. Intracellular Receptors: Nucleus Cytoplasm Cell Surface (membrane) Receptors: Ion channel linked Cytokine linked Catalytic linked (receptor tyrosine kinase) G-Protein linked – also activates ion channels { Second Messengers 7. Adenyl Cyclase (CAMP) Phospholipase A2 Transducin Pathway Phospholipase C (IP3) Agents from the pre-synaptic will interact with the receptors of the post-synaptic. Formation of Ligand-Receptor Complex Activation of the Second Messengers • In this part the ligand-receptor complex activates certain group of enzymes in the intracellular surface of the cell membrane. Cellular Change Activity • The activation of the 2nd messengers will make a response or reaction on the ligand directed towards the change affecting the cell. • 5. 6. 1. 2. 3. 4. 8. Termination of Agent’s Effects • The effect of the agent is non-continuous. Thus, it is terminated once the effect of the agent is seen on the targeted cell receptor. Common Types of Termination: • Reuptake Termination of the neurotransmitter in the neural communication. After termination in the post-synaptic, the agent is taken back by the presynaptic to be reutilized for another communication. • Destruction of the Agent Enzymes terminate the effects of the agent. The effect is delayed since the effect of the ligand (Neurotransmitter) must be allowed to interact with target cell first (post-synaptic) before it is activated. Usually happens in the target cell. Enzymes that usually deactivate the Agents: 1. Acetylcholine esterase destroy the acetylcholine 2. Monoamino Oxidase (MAO) and Catechol-O-methyltransferase (COMT) destroys epinephrine and norepinephrine 3. Insulinase – Insulin 4. ADH – Vasopressin Other Communication Termination: In certain cases, termination is made by decreasing the activity of the target cell secreting the ligand to reduce the amount of ligand in the area. Change in the conformation of the receptor protein can be a mean to stop the communication process since the ligand will not be able to activate the receptor. Ligand or the Chemical Agents § Classified base on size and solubility: § Small and lipophilic molecules usually affect the target cells by interacting with receptors present inside the cell; affects intracellular receptors since they easily penetrate the membrane. § Large and lipophilic molecules – although they are lipophilic, they still cannot penetrate the lipid bilayer because of their large size. To affect the activity of the cell, they interact with membrane receptors which are seen in all hydrophilic agents. § Hydrophilic molecules – affect membrane receptors Receptors § Effect of ligands is dependent on the presence and number of receptors. § Located in the cytoplasm, nucleus or cell membrane. § Made mostly of proteins § Exhibits high degree of specificity § High affinity to a specific signaling activity § § Down regulation or desensitization Ø Decreases the sensitivity and increases the threshold or stimulation. Up regulation or super sensitization Ø Increases the sensitivity and decreases the threshold or stimulation. Escoto, Kelvin C.E. Apoptosis § Programmed death of a cell § Rate of destruction is equal to the rate of production. § Characterized by overall compaction of a cell and its nucleus and the orderly dissection of the chromatin by endonucleases. § Mediated by proteolytic enzymes called caspases. § Two Phases: Ø Activation phase -Self destruction/suicide Ø Execution phase “eat me” -Markers for phagocytes (macrophages, from monocytes) § Two Distinct Pathways: Ø Extracellular pathway -Involves a death ligand (TNF) Ø Intracellular Pathway -Decreased function of the mitochondria will release the caspases that will cause death of the cell. Ø Whether extra- or intra- cellular, it uses caspses. Ø Erythrocytes are not included since it is anucleated. Escoto, Kelvin C.E. Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine Section D Endocrine Mechanism • PHYSIOLOGY A – CELL PHYSIOLOGY Dr. Felipe C. Barbon • • Cell – basic unit of the human body that has different parts and different activities but trying to attain the same goal – homeostasis. Homeostasis – maintaining the constancy of the internal environment which is the EXTRACELLULAR FLUID – condition of the fluids outside the cell. Why Extracellular Fluid is referred to as the internal environment? • Neural and Endocrine Control Mechanisms Negative Feedback • opposition of the regulating system against a certain activity in the body. • If there is an increase activity in the body the regulating system will oppose the activity and bring the condition back to normal but not to the point of below normal. • Negative feedback on the endocrine mechanism: o Hormone that affects another hormone o Stimulatory hormones if the body is in need of hormones o Inhibitory hormones if there is an increase in hormones • E.g.: Increase blood pressure can damage the cardiovascular system. Thus the regulating system will oppose the activity will bring it down, back to normal. b) Modified Negative Feedback • Applies ONLY in the endocrine system. • Maintenance of normal hormones in the blood is non-hormonal metabolitedependent • Non-hormonal agent controlling a hormonal agent in the circulation of the body. • E.g. Plasma glucose in the blood being controlled by the hormone Insulin. But Insulin being controlled by glucose which is a non-hormonal metabolite. Thus, the level of the hormonal agent is affected by the non-hormonal agent but that non-hormonal agent is controlled by the affected hormone. Positive Feedback • progression and enhancement of the certain condition to regain the normal function of the body. • E.g. coagulation activity of the blood during blood vessel injury. Constriction of the injured blood vessel→activation of the platelets→activation of clotting factor→clotting for the prevention of blood loss. To attain homeostasis, constant condition of the said environment must be maintained including the amount of solute and the amount of water. No balance or equilibrium especially in the amount of solutes inside and outside the cell (e.g. more Sodium ions outside the cell and Potassium ions inside and/or outside the cell.) – no equal amount of ions: no equilibrium. In homeostasis we just maintain the amount of solutes and water in the ECF to maintain a constant or normal activities of the different cells inside the body. All cells and organs in the body are being regulated by the nervous and endocrine system. 1. Nervous System – controls the activity of different cells or tissues in the body. They generate nerve impulses (action potential or electrical activities of neurons.) Neural Control • • • Responsible for the secretory and mechanical activities of the body which can either be voluntary or involuntary. Mostly affects the activity of skeletal, cardiac or smooth muscles and the secretory cells. Onset of action: Rapid Onset and Short duration Two types of Neurons in the body: 2. a. Motor or somatic neurons • controls the skeletal muscles that makes it a voluntary control. b. Autonomic neurons • controls the involuntary activity of the cardiac and smooth muscles. Endocrine System- make use of endocrine tissues or cells. Releases hormones that regulate the activity of the human body. Known as the hormonal or the humoral control. ! a) Because ECF is present inside the body which is the normal environment of the different cells present in the body. Regulating Systems Responsible for the metabolic activities of the body although it affects motor and secretory activities minimally. Includes all cells responsible for metabolism. Onset of action: delayed and long duration. Reproduction: endocrine mechanismdependent. Failure of the endocrine system is failure of the ability to reproduce. c) Escoto, Kelvin C.E. • d) E.g. Continuous increase uterine contraction during labor to promote birth of the baby. Feed Forward Control • The body anticipates the effect of a certain stimulus in the environment allowing the body to react in advance to the said stimulus that will affect the body. • E.g. A person not used to exercise being forced to exercise will have an anticipatory reaction of increase respiratory rate and heart rate even without the increase muscular activity. Up regulation vs. Down regulation 1. 2. 3. 4. Smooth Endoplasmic Reticulum • Needed for lipid synthesis Rough Endoplasmic Reticulum • Needed for protein synthesis Golgi Complex • Concerned with the secretion that packages the agents that are to be secreted. Said to be numerous in actively secreting cells Mitochondria • Numerous in actively metabolizing cell. • Power-house of the cell Physiology is more concerned with the cell membrane The cell membrane Neurons generate impulses basically action potentials. For an impulse to be generated, neurons should have an uninterrupted connection but the neural connections have gaps or spaces that are known as synapses. Thus, for a neuron to produce an impulse, it should have a chemical agent to overcome the gaps. This chemical agent is also known as the neurotransmitter. Plus, another neuron must have a receptor to receive and continue the transmitted impulse by the neuron with a neurotransmitter. For a hormone to affect effectively the cells they control, the hormone should react to a hormone receptor. e) f) Up-Regulation • Decreased amount of neurons and hormones in the regulation system would result to decrease effect in the action that would lessen the control on the affected cell. Thus, the affected cell will INCREASE the receptors. Increase the number of receptors would increase the effect of the neurons or the hormones in the controlled cell. Down-Regulation • Lesser amount of the control agents (the neurons or the hormones) The controlled cell will DECREASE the number of receptors to maintain the normal activity of the body. Structures that allow the cell to be in close contact with another cell and prevents separation of one cell to another: 1. Tight Junctions (Zonula Occludens) • Concerned with transport of ions and water molecules. • Involved in Paracellular Transportation wherein agents pass in between cells but they do not pass through the cell membrane (Apical and Basal part.) It involves two proteins: Ø Occludins Ø Claudins – determines the characteristic permeability of the membrane. The greater the amount of claudins means the tighter is its junctions. The tighter the junctions, the lesser the permeability. 2. 3. Macula Adherens (Desmosome) Gap Junctions • Also known as pores or the openings in the membrane that forms the channels • Promote transportation but also concerned with cell communication. • Functional unit: Connexons – made up of the connexins protein. Escoto, Kelvin C.E. • 4. Contrary to paracellular transportation is Transcellular Transportation wherein the utilization of the agents passes or penetrates the gap junctions of the cell membrane. - Hemidesmosome • Allows the basal portion to be in close contact with the basement membrane. - - Activities on the Different Parts of the Cell 1. 2. Apical Region • Area of absorption and secretion. Some of the secreted agents are needed for cellular protection. 2. Lateral Region • The cell is close contact with another cell – transport and communication. • Cell contact and Adhesion 3. Basal Region • Area where cells are affected if there are activities coming from the neurons and hormones that creates ion gradients allowing the cell to create electrical changes. The Cell Membrane § Maintains the composition (solute) of ICF and ECF § Regulates cellular transport § Site of signal transduction or cell communication § Acts as an anchor for structural proteins (stability, size and shape) Easily transports lipid agents that are amphipathic (Lipid soluble). Phosphatidylcholine Phosphatidylserine Phosphatidylethonolamine Phophatidylinositol Ø Cholesterol Moderator molecule providing mechanical stability as well as flexibility Makes the membrane less permeable to water Prevents lipid crystallization Proteins 40-50% • part wherein the transport of watersoluble agents can be observed. Responsible for the transport of watersoluble particles. Functions: • Receptor for hormones and neurotransmitter agents • Source of enzymes • Skeletal Framework • Stability Two Types of Proteins: 1. Integral proteins or the Transmembrane proteins. § They are capable of functioning as: Ø channels (pores/opening in the membrane) Ø carriers (transporters) of the water-soluble particles 2. Peripheral Protein – present mostly on the surface of the membrane. § Can function as antigenic markers 3. Carbohydrates • Majority are present in the extracellular surface. • Usually combined with proteins (CHO+CHON = glycoproteins) and lipids (CHO + Lipids =glycolipids.) They don’t appear as pure carbohydrates in the cell membrane. • Difficult to transport water-soluble agents penetrating the lipid bilayer • Functions as: § Serve as antigenic markers § Provide stability § Attachment agent § Cell communication § Some can function as cell channels (Glycoproteins)that transport watersoluble particles. Composition of the Cell Membrane 1. Lipids • 50-60% (almost equal with the amount of protein) Ø Phospholipids – major lipids found in the cell membrane. They are amphipathic (can combine with fats and water molecules.) Arranged as a bilayer – Phospholipid bilayer. Semi-permeable vs. Selectively Permeable Cell Membrane § § Semi-permeable membrane can only transport water or solvent molecules and not of the solute. Selectively Permeable Capable of transporting both solvent and solute molecules. Selection is observed in the transport of solutes. Cell of the human body is selectively permeable. Escoto, Kelvin C.E. - Most of the cells in the body are selectively permeable. During a resting human cell its cell membrane is: § § § § § Note: Permeability of the membrane can be altered. E.g. the skeletal muscle cell is in need of glucose. The permeability can be changed allowing the permeability of the skeletal muscle cell to become permeable to glucose. Here come’s the importance of the hormonal control wherein the aid of insulin will allow the membrane of the muscle cell to let glucose be transported. Different Transport Activities in the Cell Active Transport § Needs energy for its activity § Transport of agent going against the direction of the energy gradient. (activista. Against!) § Lower to higher pressure gradient § Uphill/”Pump” Transport (e.g. the Na-K ion pump. Meaning the the action is active from a lower to higher gradient. § Unidirectional (going inside) § E.g. In Na-K pump, sodium ions inside the cell lesser than outside since Sodium is the major extracellular cation, and the movement of the active transport is from lower to higher movement that’s sodium ions when actively transported, the movement of the transport will be from the inside to the outside (Dalawang P.I.S.O. – 2 Potassium ions Inside. 3 Sodium ions Outside) § Uses carriers to oppose the energy gradient to facilitate transport agents in and out of the cell that’s why it is energy or mitochondrial activitydependent. Thus, the greater the energy gradient, the greater the energy consumption by the carriers. § It is a continuous process because equilibrium can never be attained. The manner of transportation is from lower to higher. In the area of lower concentration, the area progressively becomes lower while in the area of higher concentration, progressive amount of agent is being increased. It is possible for a continuous process as long as the cells are still alive. If the cell dies there will be no functioning mitochondria, no energy will be produced to supply the process. Limited number of carriers in the membrane. If these are exhausted the rate of transport will stop. If the maximum rate of active transport is reached, you can never increase the rate of reaction – this condition is called saturation. The transport is continuous but the rate of transport cannot be increased. When plotted: initially only a few number of carriers are utilized and then there will be a gradual increase in the rate of transport. When the carriers in the membrane are now involved in the transport, the transport will still continue but it will undergo plateau and the rate of transport will not increase – Saturation Kinetics. In renal physiology it is known as Transport maximum (Tm) Active transport: they are not concerned with the transport of fatty acids except for the short chain fatty acids which utilizes carriers and normally happen in the colonic mucosa. Happens only in living things since mitochondria is a pre-requisite for energy production. Would ONLY utilize a transcellular transport Passive Transport § Does not require energy § A type of transport wherein the agent goes along with the direction of the energy gradient (go with the flow) § Direction: from higher to lower gradient § Downhill Transport § Bidirectional (either going inside or outside the cell) § Uses channels § Channels could be gated wherein the activities can be controlled or regulated. Closing the gates of the channel prevents the transport while opening the gates promote transport. § It is a non-continuous process because if the concentration of a certain agent transported by the cell has the same amount of agent outside and inside the cell there will be no presence of energy gradient, there will be no continuous passive transport because the agent cannot go along the gradient since there is already equilibrium wherein the concentration is equal inside and outside the cell. § Water in passive transport is dependent upon the effect of osmotic pressure. § Passive transport is more concerned with lipophilic agents. § For the transport of lipid materials, they only penetrate the lipid bilayer without utilizing channels. § Can be observed in living and non-living cells. It happens in non-living cells since it does not require energy. E.g. a dry paper placed in water. The paper will absorb the water by passive process. § Utilizes either transcellular or paracellular transport. Escoto, Kelvin C.E. Common Gradients Encountered by the Cell during Transport: § Concentration gradient (Pressure gradient) Hydrostatic or Osmotic pressures § Electrical Gradient We do not use the principle of the movement of the agent from a higher to lower or lower to higher gradient to electrical gradient. For us to know whether the activity is going along or going against the gradient, look at the electrical charge of the agent being transported and the electrical charge of the area where the agent is to be transported. E.g. Positively charged agents transported to a positively charged area is considered ACTIVE TRANSPORTATION since like charges repel. Attraction is seen in unlike charges wherein easy passage of the agent won’t be hindered it’ll just go with the flow. Usually passive transport does not utilize carriers except to facilitated Passive Transport. In this type of transport, the carriers involved in the activity does not move the transport agent against the gradient. They help facilitate the agent to get transported in the gradient along the gradient. So, there is no energy expenditure. In passive transport, specific or non- specific channels can be utilized to process the transport. E.g. the transport of water, they utilize a specific water channels known as aquaporins, that will not transport any other substances aside from water. Another example is the Na-K leak channels. PASSIVE TRANSPORT Along a gradient Downhill No ATP consumption ACTIVE TRANSPORT Against a gradient Uphill/Pump ATP utilization (Mitochondria) No carrier Always involves carrier Glycoprotein channels Glycoprotein channels No inhibition Equilibrium Bidirectional Undergoes inhibition Saturation Unidirectional Hydrophilic agents →CHON channels (gated/non-gated) Hydrophilic agents →CHON channels (transporters) Living/non-living cells Living cells Water→CHON channels Carrier →facilitated diffusion Lipophilic→Lipid bilayer Carrier vs. Channel: • In transport involving channels. The larger the energy gradient the faster the passive transport. • Carrier-involved activities are slower compared to channel-involved activities because they • need energy to perform action. They will wait for the mitochondria to produce energy. After the energy is produced, they have to metabolize the ATP to have a high energy phosphate bonds. Plus, they have to counteract the force of the energy-gradient which will also take time. Carrier and Channel (gated-channel) activities can be regulated. Factors Affecting the Transport: • • • • • • Channels/pores are concerned mostly with passive transport and the passive transport activity is usually energy independent, they don’t require energy for their activity. But, they can also be specific. The selectivity and specificity depends on the size (molecular weight), shape and electrical charge of the agent and the transport involving channels can be regulated by means of its gating-properties. Solubility Nature of the substance Membrane thickness Area of transport Energy gradient Different Gating-Mechanisms: • Voltage-gated o A change in the electrical activity of the cell would allow the voltagegated cell membrane to open or close. o All excitable cells of the body have electrical activities. o Outside surface of the cell – Positive o Inside surface of the cell – when the cell is resting the cell is Negatively charged: Inside-negative condition. • Ligand-gated o Usually associated with the guanosine proteins which can sometimes have an inhibitory or stimulatory effect. o Ligands- chemical agents involved in creating change in membrane permeability. In the neurons, these are the neurotransmitter. In the endocrine system, these are the hormones. o Ligands not in contact with the channel are closed. Ligand in contact with the channel is open. o For any chemical agents to exert their effects, the cell itself must have a receptor for the ligand. o Neurotransmitter o E.g. Acetylcholine the major neurotransmitter must have the cholinergic receptor. Two types of cholinergic receptors: 1. Muscarinic CR 2. Nicotinic CR o Epinephrine and norepinephrine must have epinephrine and norepinephrine receptors (adrenergic receptors) Two types of adrenergic receptors: 1. Alpha AR 2. Beta AR Escoto, Kelvin C.E. Hormones – whatever the name of the hormone is the name of their receptors o Growth hormone – Growth hormone receptor G-Protein-Linked Channels o Some ligands are dependent with Gproteins. For them to exert their effects on the channel they control, the channel must contain G-proteins. If that is a guanosine stimulatory proteins, the channel will be opened. If it is an inhibitory G protein, the transfer will be prevented. o E.g. In the skeletal muscle or adipose when the cell is resting, no transport of glucose is happening but in the presence of insulin, which serves as the ligand, will help open up the glucose channels. o • o Mechanically-gated/Stress-activated • o Stretching the cell-membrane can open up the channels since the channels are pulled apart. Note: Not all activities of the channel can be regulated because some channels are non-gated; They are always open wherein it can be completely open or partial. The activity will now be continuous transport and is known as passive or leaky channels. These channels can be seen in the GIT. DIFFERENT PASSIVE TRANSPORTS Passive transport of small amount of agents: Osmosis – only water or solvent molecules are being transported. o Allows water/solvent molecules to move from lesser to greater solute concentration. Plus, the solute must be osmotically active to attract water. o Osmotic pressure is highly dependent on the amount of osmotically active agents present in the solution. o The greater the amount of the active osmotic agents, the greater is the osmotic pressure, the greater the ability to attract water. o RBC on an isotonic solution: Ø No change in volume and cell size since they have the same concentration of solutes; the water will not have any net flow to any direction. They can move in and out BUT in equal amounts. Isotonic concentration Ø Sodium Chloride (NaCl): 0.9% or 280-300 mOsm/L (ave. 290) Ø Glucose: 0.5% Ø Lesser value: Hypotonic Ø Greater value: Hypertonic RBC on a hypotonic solution: Ø Swelling of cell will occur. If the cell has the amount of greater solute, water will move from the hypotonic to the cell allowing it to swell and burst. Ø Irreversible o RBC on a hypertonic solution: Ø The hypertonic solution has the higher concentration allowing the water to move out of the cell making it crenate or shrink. (just remember HYPERCREN) Ø Reversible Diffusion – mostly concerned with solute transport; but can also promote solvent transport. o o o Simple Diffusion – the transport of the solute does not require any membrane or it can require a membrane but that membrane should be permeable to all solvents and solutes. Facilitated Diffusion – the diffusive process requires the activity of a carrier. Isotonic – normal condition of the human body fluid. Normal human cell environment. Escoto, Kelvin C.E. Filtration – transport of the solvents and solutes on a highly porous membrane with numerous channels. Commonly seen in fenestrated capillaries of the GIT and kidney especially in the glomerulus. o There is selective filtration: almost everything is being filtered in the glomerulus except the large particles (blood and protein.) Passive transport of large amount of agents: Bulk Flow – e.g. flow of urine, flow of bile in the biliary ducts, blood flow o They follow pressure differences o In the cardiovascular system, the highest pressure can be recorded in the left ventricle while the lowest pressure can be recorded in the right ventricle – Central Venous Pressure (CVP) Solvent Drag – always observed whenever there is bulk flow. (e.g. in the plasma) o Van’t Hoff’s law – osmotic pressure is dependent on the concentration of the osmotically active particles. Diffusion Laws o Fick’s Law o Stokes-Einstein Equation Determination of Plasma Osmolarity đˇđś = đ × đˇđđđđđ đľđ + đˇđđđđđ đŽđđđđđđ đŠđźđľ + đđ đ. đ Estimate of PO = Plasma Na x 2 Normal Values: Normal Tonicity: 280-300 mosm/L Sodium: 135-145 meq/L Glucose: 60-110 mg/dL BUN: 8-20 mg/dL Note: Tonicity is dependent on the presence of solutes. Wherein the solutes should be osmotically active; it should be able to attract water. An osmole holding on to water should not be able to traverse the membrane and move out the area. o E.g. With a normal amount of plasma proteins, the body can retain normal amount of water in the vascular compartment. If the plasma proteins will decrease the water will move out of the vascular compartment and will go to the interstitial spaces that will produce edema. o Solutes that are able to penetrate the membrane and stays in the area are good osmotic agents which makes the osmotic coefficient equal to one. These are the proteins in the blood specifically albumin. o If the osmotic coefficient is equal to zero that makes the agent ineffective. o Plasma proteins are responsible for maintaining the osmotic pressure in the blood while the Electrolytes are essential in maintaining the osmotic pressure inside the cell. o Regulatory Cell Volume Decrease Ø If the plasma is hypotonic it is expected that the cells are going to swell but the body will try to maintain to normalize the shape of the red blood cell. If there is a transient hypotonicity of the plasma, the cell will transport some of the electrolytes or solutes out of the cell to lessen the number of osmotically active agents. o o o o Regulatory Cell Volume Increase Ø Vice Versa DIFFERENT ACTIVE TRANSPORTS Carrier mediated that involves carrier proteins present in the cell membrane. Some types of active transports do not require carriers in the membrane but are involved almost in the movement of the membrane. Energy dependent Steps during the Active Transport: 1. Association – usually starts with the binding of the agent to the carrier molecule. 2. Translocation – The carrier will change its configuration or shape that will promote the movement of the agent to another location. 3. Dissociation – When they are on their location the carrier will release the agent allowing them to separate from one another. Carrier o Energy-dependent o Selectivity and specificity (dependent on the size and shape of the binding site of the carrier molecule. The agent should fit exactly on the binding site of the carrier molecule) o Can undergo saturation or inhibition (Competitive inhibition) o The activity can be regulated or mediated using chemical agents usually a ligand (hormones) Primary Active Transport o Agents are moving all against their electrochemical gradient. o Can progress on their own without any simultaneous transport happening. 1. Uniport Ø Carrier transports one agent at a time. Ø Hydrogen pump 2. Antiport Ø Exchange transport Ø One is transported in and another one is transported out Ø E.g. Na-K exchange pump, H-K exchange pump Ø Na-K exchange pump is an electrogenic transport that happens continuously in an excited cell like cell of the muscles and neurons. Ø PISO directions cannot be changed. Escoto, Kelvin C.E. 2PISO: 2 Potassium In. 3 Sodium Out Influx – Transport of ions inside the cell Efflux – transport of ions outside the cell • • • Note! Some Active Transport are non-electrogenic. It means that the exchange of ions is in equal amounts. E.g. the Hydrogen-Potassium Exchange pump. 2H ions in exchange of 2K ions would still have an exchange mechanism but will not create an electrical change in the cell. Making it a non-electrogenic active transport or an Electro-Neutral Pump. Secondary Active Transport o Some agents are transported against their gradient while other agents are transported along their gradient. o Only occur when another active transport is simultaneously happening. o Antiport-dependent o Mechanism will be effective when there is Na-K exchange pump. 1. o 2. Similar to uniport Hydrogen pump ATP-Binding Cassette Transporters o A type of transport associated with Cystic Fibrosis Transmembrane Conductance Regulator (CFTR) • • Carrier independent Do not utilize carriers but the cell membrane acts as a whole that forms vesicles. 1. Endocytosis – membrane of the cell takes in the agent. Exemplified by: Phagocytosis – ingestion of large agents. o Pinocytosis – intake of agents in fluid form. o Involves a “docking” process wherein there is binding with a specific membrane protein receptor that will form a vesicle in the cell membrane coated by clathrin. o The vesicle is initially part of the membrane. They are coated with clathrin. Vesicles are then separated from the cell membrane and referred to as vacuoles. After the vesicles separate they will be surrounded with lysosomes and agents will be digested. The clathrin will separate from the vesicle after digestion and the clathrin will be recycled and allow the membrane to perform another endocytosis. o Once the vesicles trapped a certain agent it will also need other accessory proteins like adaptin and dynamin. There is also involvement of microtubules and the dynein protein. o Portions without clathrin are not involved in endocytosis o Absorption can be regulated: Ø Fluid phase Unregulated Absorption; nonspecific E.g. absorption in the GIT Ø Adsorptive Endocytosis Regulated Absorption Requires a chemical agent or ligands which will react with the receptors to start the activity Receptor mediated or adsorptive endocytosis Transcytosis or Cytopempsis o Rapid transport of substance o Endocytosis at the apical portion of the cell followed by exocytosis at the basal part of the cell. o Counter Transport o Exchange transport o E.g. Sodium Calcium Counter transport that is dependent on the Na gradient provided by the Na-K exchange pump: Na transported inward. Ca efflux happens simultaneously. o Digoxins – cardiac glycosides that inhibits the Na-K ATPase activity that decreases the activity of the symporters and counter transporters. ATP-Dependent Transporters or ATPase Ion Transporters o P-Type Ø Similar to antiport V-Type Ø Ø Na-K exchange pump, H-K exchange pump VESICULAR TRANSPORT Depends its activity with the normal NaK pump activity. E.g. Sodium – Glucose cotransport, Sodium-amino acid cotransport (2 substances), Na-K Chloride cotransport (3 substances) Other Carrier-mediated Transport from Berne and Levy: Active Transport also have another type of carriermediated active transport and this are the: 1. o Symport o Also known as Co-transport/Coupled Transport. o Carries several agents at a time. o Usually transports 2 agents at a time but can also transport 3 agents simultaneously in one direction. o 2. Ø 2. 3. Exocytosis/Emeiocytosis – moves the agent outward. o Reverse phagocytosis and pinocytosis Escoto, Kelvin C.E. o o o 1. 2. Also needs clathrin In the movement of the vesicle, it needs the protein Kinesin Secretory vs. Excretory Activities of the Cell Similar to the direction of transport: out of the cell. Secretion – releasing of agents that are need by the body and can affect the activity of other cells. Excretion – excreted agents are considered waste products and released from the body. Renal System: major excretory system of the body that excretes almost all waste products of the body except carbon dioxide that are excreted by the respiratory system. o Note: Secretion and Excretion can also be regulated, partially-regulated or non-regulated. o 2 Pathways Involved in Exocytosis 1. Constitutive Pathway Ø Continuous partially Ø E.g. of non-regulated secretory activity is the secretion of the mucus, secretion of mucus cannot be control or can be controlled at least partially. 2. Non-Constitutive Pathway Ø Fully regulated pathway using a ligand that will initiate the transport. Passive Transport Osmosis Diffusion • • Simple Facilitated Filtration Bulk Flow Solvent Drag Active Transport Carrier Mediated: • Uniport (Primary) • Symport (Secondary) • Antiport (Primary) Transcytosis Pinocytosis Phagocytosis Factors that Affect the Transport of the Cell 1. 2. 3. 4. 5. Nature of the Substance o Lipid soluble agents easily penetrates the membrane since there is no need for them to look for channels as they can directly penetrate the lipid bilayer membrane. Size of the Agent/Molecular Weight o It should be very small (>2nm or 20 Ångström) and it should be very light (69,000 MW) to easily pass through the membrane. Membrane Thickness o The thicker the membrane the lesser the rate of transport whether active or passive transport. Surface Area o The greater the area the greater the transport; the lesser the area the lesser the transport. Number of Channels/Pores o In passive transport: the greater the channels, the faster the rate. Permeability coefficient –permeability of the membrane is dependent on the number and size of channels. 6. Number of Carriers o The greater the carriers in number, the faster the rate of transport. 7. Membrane Permeability o Semi-permeable membrane can only transport water. 8. Exposure o The longer the agents are exposed to the membrane, the greater the rate of transport. o Lesser time the agent is exposed; lesser amount of agent is being transported. 9. Energy Gradient o Passive transport with greater energy gradient = grater the force = greater the rate o Active Transport with greater energy gradient = greater force needed = the rate of the transport is lesser Gradient Time Limitation – combined length of exposure and energy gradient. o o o o Cell Signaling or Cell Communication Also known as signal transduction Gap junction – part of the membrane used for cell communication by adjacent cells or cells in direct contact with one another. Connexons – are chemical agents made up of smaller proteins called connexins and are used for communication by distant cells or nearby cells that are not directly in contact with another cell. Communication using Chemical agents: Ø Synaptic communication using neurotransmitter can be used in adjacent cell communication. Ø Hormones are used during distant cellcommunication. o Autocrine - cells communicating with another identical cell within the area and are not directly in contact with one another. Ø Released to interstitial fluid Ø E.g. communication happening in the islets of Langerhans: a group of cells present in the pancreas. Beta cells communicating with another beta cells. o Paracrine - cells communicating with another nonidentical cell within the area and are not directly in contact with one another. Ø E.g. Beta cells communicating with another alpha cells in the islets of Langerhans in the pancreas. For the Communication to Happen: 1. Change must be created in the extracellular region that will eventually affect the cell. Extracellular change will be transformed by the affected cell into intracellular changes or also known as intracellular messages. Intracellular agents will be affected by the changes allowing to produce an activity that will be directed to extracellular change. 2. For it to react to extracellular change affecting the cell, ligand-receptor interaction is needed. Receptors can be present in the cytoplasm or the nucleus (intracellular receptors). 3. Interaction of Ligand and receptor will produce Ligand-receptor complex that will now activate certain enzymes present in the intracellular surface of Escoto, Kelvin C.E. 4. the cell. These enzymes are known as the second messengers. Once these second messengers are activated, they will affect certain type of protein or an enzyme in the cytoplasm. Then it will create a response directed to the extracellular change affecting the cell. STEPS IN CELLULAR COMMUNICATION WITH CHEMICAL AGENT USE 1. 2. 3. 4. Synthesis of the Agent • Ligand is needed to activate the cell. Release of the Agent • E.g. In the synapse the NTA are normally produced in the pre-synaptic. Transport of Agents Towards the Target Cell • The agents from the pre-synaptic are released to the post-synaptic once the agents are needed. Interaction with the Cellular Receptor • The cell should have the receptor for effective communication. Intracellular Receptors: Nucleus Cytoplasm Cell Surface (membrane) Receptors: Ion channel linked Cytokine linked Catalytic linked (receptor tyrosine kinase) G-Protein linked – also activates ion channels { Second Messengers 7. Adenyl Cyclase (CAMP) Phospholipase A2 Transducin Pathway Phospholipase C (IP3) Agents from the pre-synaptic will interact with the receptors of the post-synaptic. Formation of Ligand-Receptor Complex Activation of the Second Messengers • In this part the ligand-receptor complex activates certain group of enzymes in the intracellular surface of the cell membrane. Cellular Change Activity • The activation of the 2nd messengers will make a response or reaction on the ligand directed towards the change affecting the cell. • 5. 6. 1. 2. 3. 4. 8. Termination of Agent’s Effects • The effect of the agent is non-continuous. Thus, it is terminated once the effect of the agent is seen on the targeted cell receptor. Common Types of Termination: • Reuptake Termination of the neurotransmitter in the neural communication. After termination in the post-synaptic, the agent is taken back by the presynaptic to be reutilized for another communication. • Destruction of the Agent Enzymes terminate the effects of the agent. The effect is delayed since the effect of the ligand (Neurotransmitter) must be allowed to interact with target cell first (post-synaptic) before it is activated. Usually happens in the target cell. Enzymes that usually deactivate the Agents: 1. Acetylcholine esterase destroy the acetylcholine 2. Monoamino Oxidase (MAO) and Catechol-O-methyltransferase (COMT) destroys epinephrine and norepinephrine 3. Insulinase – Insulin 4. ADH – Vasopressin Other Communication Termination: In certain cases, termination is made by decreasing the activity of the target cell secreting the ligand to reduce the amount of ligand in the area. Change in the conformation of the receptor protein can be a mean to stop the communication process since the ligand will not be able to activate the receptor. Ligand or the Chemical Agents § Classified base on size and solubility: § Small and lipophilic molecules usually affect the target cells by interacting with receptors present inside the cell; affects intracellular receptors since they easily penetrate the membrane. § Large and lipophilic molecules – although they are lipophilic, they still cannot penetrate the lipid bilayer because of their large size. To affect the activity of the cell, they interact with membrane receptors which are seen in all hydrophilic agents. § Hydrophilic molecules – affect membrane receptors Receptors § Effect of ligands is dependent on the presence and number of receptors. § Located in the cytoplasm, nucleus or cell membrane. § Made mostly of proteins § Exhibits high degree of specificity § High affinity to a specific signaling activity § § Down regulation or desensitization Ø Decreases the sensitivity and increases the threshold or stimulation. Up regulation or super sensitization Ø Increases the sensitivity and decreases the threshold or stimulation. Escoto, Kelvin C.E. Apoptosis § Programmed death of a cell § Rate of destruction is equal to the rate of production. § Characterized by overall compaction of a cell and its nucleus and the orderly dissection of the chromatin by endonucleases. § Mediated by proteolytic enzymes called caspases. § Two Phases: Ø Activation phase -Self destruction/suicide Ø Execution phase “eat me” -Markers for phagocytes (macrophages, from monocytes) § Two Distinct Pathways: Ø Extracellular pathway -Involves a death ligand (TNF) Ø Intracellular Pathway -Decreased function of the mitochondria will release the caspases that will cause death of the cell. Ø Whether extra- or intra- cellular, it uses caspses. Ø Erythrocytes are not included since it is anucleated. Escoto, Kelvin C.E. FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology June 2, 2014 Section 1D Homeostasis – maintenance of the constancy of the internal environment; observed changes are controlled by positive & negative feedback regulation Regulating Systems – responsible for bringing conditions back to normal whenever there is an alteration a. Nervous/Neuronial - make use of nerve impulses (action potential) produced by effectively simulated neurons - immediate onset: usually muscles & secretory cells - can be voluntary & involuntary - short duration - localized b. Endocrine/Humoral/Hormonal - make use of agents (hormones) produced by activated endocrine cells - delayed response: cells involved in metabolism like reproductive ability - involuntary - usually long duration - diffuse Cell/Plasma Membrane – made up of lipids & proteins; involved in transport activities *Outer layers: hydrophilic, lipophobic *Central region: hydrophobic, lipophilic - differentially/semi-permeable: capable of allowing transport of only solvent particles - selectively permeable: allows transport of solvent & solute molecules but there is a selection in the transport of solutes DULAY, Arman Carl **Aquaporins – water channels **permeability of the cell can be altered **Osmosis – water molecules move towards an area having greater amount of osmotically active agents Cell Membrane Fxns: - regulate transport - maintain composition of ICF & ECF - cell identification using surface antigens - signal transduction/cell communication - provides cellular stability; anchor for structural proteins - anchoring to neighboring cells & basal lamina - determination of cell shape Activities of the Cell Membrane *Apical Region – absorption and secretion; protection *Lateral Region – cell contact, adhesion, communication - Tight jxns = zonula occludens - Desmosomes = zonula adherens(anchoring) - Gap jxns = connexons(communication) *Basal Region – cell-substratum contact; ion gradient generation - Hemidesmosomes & focal adhesions 1 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology June 2, 2014 Section 1D Composition of the Cell Membrane Lipids: 50-60% Proteins: 40-50% Carbohydrates: negligible amount; usually coupled with a lipid or protein **The presence of carbohydrates in the cell membranes of bacteria allow for recognition as non-self antigen by the immune system A. Lipids - Phospholipids: amphipathic - Cholesterol: “moderator molecule”, provides mechanical stability and flexibility, makes membrane more permeable to lipid particles and less permeable to water & prevents lipid crystallization (fluidity) - Glycolipids B. Proteins - Integral/Transmembrane: amphipathic, utilized as channels, pores or fenestrations - Peripheral: present on the surfaces and does not traverse the membrane *act as channels/carriers *antigenic markers *receptors for hormones/NTA *source of enzymes *skeletal framework *cell stability *transport of water soluble particles needed by the cell DULAY, Arman Carl C. Carbohydrates – present on extracellular surface and never a pure carbohydrate *cell identity markers *agent for communication *some are channels (rare) Cell Membrane Transport *Passive Transport – involves kinetic energy; without energy prod’n from the cell *Active Transport – involves energy produced by the cell Passive Active Not coupled with Coupled with ATP ATP “Downhill” “Uphill” Along the gradient Against the gradient (High to low) (Low to high) Faster Slower No inhibition/nonUndergoes specific inhibition/always specific Bidirectional Unidirectional Stops at equilibrium Continuous but leads to saturation: condition at which carriers are exhausted and rate of transport stops at maximum and no add’l increase Lipid soluble Water soluble partivcles particles Channels Carriers & pumps Channels do not Conformational change change of carriers conformations but can be gated Common energy gradients: concentration, electrical, pressure **In electrical gradients, you have to consider the charge ion present and the electrical charge of the area to which the ion will be transported Like charges repel; unlike charges attract 2 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology June 2, 2014 Section 1D Factors Affecting Transport 1. Nature of Substances (Solubility) - lipid soluble substances=faster transport 2. Size (Molecular Weight of the Substance - Lighter ones are easily transported - Less than 69,000 molecular weight 3. Membrane Thickness - the thicker the membrane, the harder the transport - the thinner the membrane, the faster the transport 4. Area of Transport - the greater the area the greater the trasport 5. Presence of Pores/Channels - the greater the number of pores, the greater the transport 6. Electrical Charge - Opposite charge have easier transport 7. Membrane Permeability - membrane should be permeable to be able to transport - you can change the membrane permeability 8. Time (Duration)/ Length of Exposure - the longer the agent is exposed to the agent, the more the transport. 9. Energy Gradient - Passive = Direct Effect (greater gradient=greater movement) - Active = Indirect Effect (Lesser gradient=lesser effect) 10. Concentration Gradient *Permeability Coefficient – rate of transport/permeability of the membrane is dependent upon the size of the pores *Gradient Time Limitation – combined length of exposure and energy gradient DULAY, Arman Carl 3 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 2 June 3, 2014 Section 1D Membrane Transport Processes PASSIVE TRANSPORT 1. Osmosis: move’t of H2O from less to greater solute conc’n across a semi-permeable membrane : movement of H2O from higher to less H2O conc’n across a semi-permeable membrane *Isotonic/isosmotic – no net mov’t of H2O; amount of solute is identical to the amount of solutes present in body fluids/plasma (0.850.9% NaCl; 5% glucose) - 280-300 milliosmol/L *Hypertonic/hyeperosotic – greater than isotonic; cells will shrink (plasmolysis) *Hypotonic/hypoosmotic – less than isotonic; cells will swell; cell may burst (osmotic lysis) **There are regulatory mechanisms in the human body that preserve cell volume/amt of H20 in cells - Regulatory volume increase – when cells are exposed in slightly hypertonic solutions; cells attract/allow osmolytes to move in - Regulatory volume decrease – when cells are exposed in conditions where the plasma becomes slightly hypotonic; osmolytes are transported out of the cell Osmolytes: Myoinositol, sorbitol, some electrolytes (Na+, K+] **Osmotically active agents are responsible for the movement of water Osmotic Pressure - force that attracts H2O that attracts water towards an area with greater amt of osmotically active agents Van Koft’s Law/Eq’n - osmotic pressure is dependent on th concentration of the sol’n 2. Diffusion: concerned with move’t of both solute and solvent molceules a. Simple – lipid particles; simple penetration of lipid bilayer DULAY, Arman Carl b. Facilitated – water-soluble particles; involves carrier molecules/proteins c. Restricted – water-soluble particles; protein channels are utilized 3. Filtration – transport of solute and solvents involving presence of greater number of pores in the membrane; normally happens in capillaries - selective, depending on the size of the pores *Albuminuria; proteinuria – caused by problems in kidneys Hydrostatic Pressure – force causing filtration of different agents 4. Bulk Flow – move’t of large amount of substances in bulk from higher pressure to lower pressure Left ventricle – highest pressure Right ventricle – lowest pressure Right atrial pressure = central venous pressure 5. Solvent Drag – whatever solutes dissolved/ suspended in the flowing solvent is dragged by the solvent Laminar flow – stream-like, silent, unidirectional flow of blood ACTIVE TRANSPORT A. Carrier-mediated – binding of the agent with a carrier protein 1. Primary – cells produce energy to transport a molecule against its gradient; has its own enzyme to hydrolyse ATP a. Uniport – single agent; single direction (Na+ pump} b. Antiport – exchange transport (Na+-K+ pump) 2. Secondary – one agent is actively transported, the other is transported along its gradient; shares energy with another active transport 1 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 2 June 3, 2014 Section 1D a. Symport – more than one agent in a single direction (Na-glucose co-transport) b. Counter-transport – exchange transport (Na+Ca2+ exchange) **Decreased activity of antiport = decreased activity of symport & counter-transport B. Vesicular – involves the activity of the whole cell; creation of vesicles 1. Phagocytosis Monocytes – most phagocytic WBC 2. Pinocytosis 3. Transcytosis – transport of substances traveling all throughout the cell 3 Steps in Active Transport 1. Association – binding of agent to carrier > conformational changes in carrier 2. Translocation – mov’t towards area where the agent is needed 3. Dissociation – separation of carrier from agent Electrogenic Pump – creates electrical charge due to unequal exchange of charged particles ex. Na+-K+ pump: 3Na outward - 2K inward Non-electrogenic/Electroneutral Pump – equal exchange, ergot no electrical activity/charge is created ex. HCO3-Cl- exchange DULAY, Arman Carl Differences Between Carriers and Channels CARRIERS (Active) Slower (hundreds/sec) Can be regulated (gated channels) Coupled with ATP Uphill Transport Undergo conformational change CHANNELS (Passive) Faster (>10,000/sec) Not coupled with ATP Downhill transport No conformational change (Open and close quickly) Properties of Channels 1. Selectivity – pore size & electrical charge 2. Gating property – regulation/control a. Voltage gated – change in electrical acitivity b. Ligand gated – chemically activated; involves protein activity (guanosine/Gprotein) Excitatory –open Inhibitory - close c. Mechanically gated – stretching of cells d. G-protein mediated 3. Continuously open (partial or complete) – no regulation; passive/leaky channels as in the small intestines **Digitalis – inhibits heart activity; inhibits Na-K pump/ATPase = traps calcium, inotropic activity of heart increases C. Bulk Transport 1. Endocytosis – into the cell a. Phagocytosis – cell eating b. Pinocytosis – cell drinking; fluids 2. Exocytosis/Emeiocytosis – out of the cell 3. Transcytosis – endocytosis coupled immediately with exocytosis happening in different regions of the cell (from apex to base) as in the proximal convoluted tubules of nephrons and intestine 2 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 2 June 3, 2014 Section 1D Endocytosis - ‘docking’/binding of agent to be transported to the cell membrane - vesicle formation by cell membrane coated by CLATHRIN - allows cell to absorb/take in the agent - Clathrin separates from vacuole and returns to cell membrane (recycling) - Can also involve proteins adaptine & tyramine Endocytic Pathways 1. Fluid-phase - non-specific - non-regulated/uncontrolled 2. Receptor Mediated (Absorptive Endocytosis) - chemically regulated usually a hormone that will initiate the transport - no receptor, no transport *cholinergic receptors – muscatinic and nicotinic receptors *adrenergic receptors – alpha and beta receptors DULAY, Arman Carl 3 of 3 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Exocytosis - similar to endocytosis but transports substances out of the cell - explains the ability of cells to secrete or excrete substances Exocytotic Patchway 1. Constitutive Pathway - continuous partially regulated pathway 2. Non-constitutive Pathway - fully regulated pathway using a ligand that will initiate the transport Cell Surface (Membrane) Receptors - affect membrane permeability - common ligands are protein in nature e.g. insulin –alter membrane permeability to glucose, ADH – permeability to water, aldosterone – permeability to sodium 1. Ion channel linked 2. Cytokine linked 3. Catalytic linked (receptor tyrosine kinase) 4. G-protein linked - adenyl cyclase - (camp)phospholipase A2 Second messengers - Transucin pathway - Phospholipase C (IP3) - Can also activate ion channels Intracellular Receptors - found in the cytoplasm and nucelus - ligands are usually lipid-soluble agents ex. Steroid hormones such as cortisone/glucocorticoid, aldosterone/mineralocorticoid (cytoplasmic), estrogen, progesterone, testosterone (nuclear) *Steroid ring - cyclopentanoperhydrophenanthene ring - since the membrane is permeable to lipid-soluble agents, these agents act upon the receptors found inside the cell - alteration due to the effects of these hormones are seen mostly on the nucleus such as the sex hormones [GENE ACTIVATORS] - common changes seen affect nuclear activity and transcription, translation & regulation of gene expression *Thyroid hormone – non-steroid but can exert its effect on nuclear receptors; made up of biogenic amine; tyrosine for the production of the T3 or T4 hormone Effects of the ligands are very dependent on the presence and number of active receptors and are usually direct *Type I Diaabetes Mellitus (insulin Dependent) – no insulin but with receptors *Type II Diabetes Mellitus (Non-insulin Dependent: they have insulin but the insulin receptors are not responsive *Nephrogenic Diabetes Insipidus: there are no receptors for ADH in the kidneys *Diabetes Insipidus: no ADH but no problem with receptors Down-regulation/desensitization – when a ligand is present in excess, the number of active receptors generally decreases. DULAY, Arman Carl Up-regulation – when there is deficiency of a ligand, there is an increase in the number of active receptors *Prolongation of the condition {excess/deficiency of ligands) will cause problems from the effects of the hormone; body cannot maintain the regulation of the condition 1 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Cell Communication/Cell-Signaling/Signal Transduction Transduction – conversion of one form of energy to another 1. Cell to cell – gap junctions; known as nexus in neurons; functional units are connexons 2. Chemical agents – with nearby or distant cells; uses ligands a. Synapses – utilizes neurotransmitters produced by the pre-synaptic nerves; receptor are found in the post-synaptic nerve b. Endocrine – uses hormones; distant cells Ex. Pituitary gland – controls different parts of the body by producing tropic hormones ex. Growth hormone, FSH, LH c. Autocrine – communication with nearby cells of the same cell type exx. Communication between insulin secreting beta cells of the islets of Langerhans in the pancreas d. Paracrine – communication with nearby cells of different cell type ex. Communication of beta cells with gulacogon-secreting alpha cells Steps involved in communication using chemical agents 1. Synthesis of the agent 2. Release 3. Transport towards target cell 4. Interaction with a cellular receptor 5. Change in cellular receptor 6. Change in cellular activity 7. Termination of effects Re-uptake or decomposition of the chemical agents by enzymes; recycling /re-utilizing Acetylcholine – acetylcholine esterase Epinephrine/norepinephrine – monoamine oxidase & catechol-O-methyltransferase Dopamine – dopaminase DULAY, Arman Carl Signal Transduction Extracellular changes are transformed into intracellular messages causing alteration in cellular activity. Initiated by molecules (ligands) interacting with membrane receptors or intracellular receptors activating second messengers and eventually cellular response. Classification of Signaling Molecules 1. Small lipophilic molecules – affect intracellular receptors ex. Steroid hormones 2. Large lipophilic molecules – affect membrane receptors 3. Hydrophilic molecules – affect membrane receptors Characteristics of receptors 1. located in the cytoplasm, nucleus or cell membrane 2. made up mostly of proteins (integral) 3. exhibits high degree of specificity 4. high affinity to a specific signaling molecule *nicotinic receptors – present on all autonomic ganglia; myoneural junction of skeletal muscle *muscatinic receptors – found in parasympathetic neuroeffector junction & sympathetic cholinergic neuroeffector junction *alpha & beta receptors – sympathetic adrenergic neuroeffector junctions *insulin receptors – found in skeletal muscles and adipose tissue 2 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D APOPTOSIS: programmed death of a cell RBC – though unnucleated, it is able to survive because it carries enough energy and nutrients that will last about 120 days - characterized by overall compaction of a cell and its nucleus and the orderly dissection of the chromatin by endonucleases - mediated by proteolytic enzymes called caspases Local potential/local response - Hypopolarizing change/local depolarizing change: electrical change that does not allow a cell to depolarize - local excitatory state of the cell - acute subthreshold potential - negativity of the change becomes less than normal Two Phases 1. Activation phase: self-destruction 2. Execution phase: “eat me” markers for phagocytes Local potentials in the different parts of the body: Receptor potential - local potential developed in sensory receptors - generator potential End plate potential - muscles Excitatory/inhibitory pos-synaptic potential - post-synaptic portion of the neuron Two distinct pathways: 1. Receptor mediated pathway(TNF) – extracellular 2. Mitochondria mediated pathway – intracellular **Whatever amount of cells are destroyed, the same number of new cells are produced by the body. Reticulocytes - youngest red blood cells in circulation Low reticulocytes = developing anemia The presence of the ff. ions in the intracellular and extracellular compartments of the cell are responsible for the electrical activity of the cell: ELECTROPHYSIOLOGY Excitable cells – able to produce electrical activity *Ions are responsible for cell electrical activity. Resting membrane potential (RMP) - negative electrical activity recorded on the inner surface of the membrane - steady potential: constant electrical activity, nonchanging - transmembrane voltage potential: recorded on the membrane Action potential - nerve impulse; arises from effectively stimulated cells - response of excitable cells to threshold intensity - results from depolarization of the cell Threshold – lowest effective stimulus intensity DULAY, Arman Carl Electrochemical balance/equilibrium - achieved by the Gibbs-Donnan effect - due to the presence of ions that are not capable of penetrating the membrane Conductance - membrane permeability to charged particles - when the cell is resting, it has higher conductance to K+ and Cl- and lower conductance for Na+ and no conductance to negatively charged proteins 3 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Leaky or passive channels: continuously open, non-gated channels Nernst Equation - single ion Goldman-Hodgkin-Katz Equation - expresses the same rel’ship as Nernst Equation,but for ALL IONS INVOLVED according to their permeability Effect of concentration gradient K+ will normally move outside the cell, Cl- will tend to move in, Na+ has a tendency to move into the cell Effect of electrical gradient Inside negative condition attracts Na+ to move in via sodium leakage, detains K+ inside the cell (but concentration gradient has greater effect; K= moves out), repels Cl= entry (balanced effect from concentration and electrical gradient; no net flow) Ergo, when the cell is resting, it has a tendency to make the inside more negative, but this never happens because it is always balanced by the Na-K exchange pump. Remember PISO = maintains constant electrical activity. Electrogenic Na-K pump – non-selective ion channel – K is 100x more permeable than Na The higher permeability of K= contributes about 67mV to the magnitude of the RMP. The Na-K pump produces about 3mV. Passive and Active Forces that Establish and Maintain RMP 1. Nature of the cell membrane 2. Unequal distribution of ions 3. Operation of the Na-K pump *Polarized cell = correct term to describe a resting/inactive cell When you effectively stimulate a cell, there is an involvement of other channels other than leak channels like: Voltage gated channels: regulated by the electrical activity of the cell; specific 1. Voltage-gated sodium channels: have 2 gates, inactivation & activation gate The electrical activity of the membrane is more dependent on the permeability of the membrane to K+. Resting electrical activity in the muscle = -90mV nerves = -70mV (smaller diameter); -90mV (bigger diameter) DULAY, Arman Carl 4 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D 2. Voltage-gated potassium channels – has activation gate only This gives the cell the tendency to hyperpolarize or to become more negative than normal. The closure of the activation gates of VG K channels follows coupled by the closure of the activation gates and opening of the inactivation gates of VG Na channels to prepare the cell for another activity. The Na-K exchange pump’s activity increases. Critical Firing Level: also known as the threshold voltage; allows the membrane potential to reach the threshold potential If the cell is resting, there is no activity of the VGC since they are all closed, only leaky channels and carriers are active. In the resting state, the inactivation gates of VG Na channels are open. Upon effective stimulation, the cell will immediately depolarize and the VG Na channel is initially affected causing the opening of the activation gates. Conductance to sodium therefore is increased causing rapid and massive Na influx. This is NOT a continuous change because it will eventually reach equilibrium. This results to the closure VG Na channels by the inactivation gates. VG K channels are used to repolarize the cell. There occurs a fast K+ efflux. Even if the cell reaches the normal (-70mV), it will immediately stop the repolarization. The equilibrium potential for K must also be reached. DULAY, Arman Carl 5 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Exocytosis - similar to endocytosis but transports substances out of the cell - explains the ability of cells to secrete or excrete substances Exocytotic Patchway 1. Constitutive Pathway - continuous partially regulated pathway 2. Non-constitutive Pathway - fully regulated pathway using a ligand that will initiate the transport Cell Surface (Membrane) Receptors - affect membrane permeability - common ligands are protein in nature e.g. insulin –alter membrane permeability to glucose, ADH – permeability to water, aldosterone – permeability to sodium 1. Ion channel linked 2. Cytokine linked 3. Catalytic linked (receptor tyrosine kinase) 4. G-protein linked - adenyl cyclase - (camp)phospholipase A2 Second messengers - Transucin pathway - Phospholipase C (IP3) - Can also activate ion channels Intracellular Receptors - found in the cytoplasm and nucelus - ligands are usually lipid-soluble agents ex. Steroid hormones such as cortisone/glucocorticoid, aldosterone/mineralocorticoid (cytoplasmic), estrogen, progesterone, testosterone (nuclear) *Steroid ring - cyclopentanoperhydrophenanthene ring - since the membrane is permeable to lipid-soluble agents, these agents act upon the receptors found inside the cell - alteration due to the effects of these hormones are seen mostly on the nucleus such as the sex hormones [GENE ACTIVATORS] - common changes seen affect nuclear activity and transcription, translation & regulation of gene expression *Thyroid hormone – non-steroid but can exert its effect on nuclear receptors; made up of biogenic amine; tyrosine for the production of the T3 or T4 hormone Effects of the ligands are very dependent on the presence and number of active receptors and are usually direct *Type I Diaabetes Mellitus (insulin Dependent) – no insulin but with receptors *Type II Diabetes Mellitus (Non-insulin Dependent: they have insulin but the insulin receptors are not responsive *Nephrogenic Diabetes Insipidus: there are no receptors for ADH in the kidneys *Diabetes Insipidus: no ADH but no problem with receptors Down-regulation/desensitization – when a ligand is present in excess, the number of active receptors generally decreases. DULAY, Arman Carl Up-regulation – when there is deficiency of a ligand, there is an increase in the number of active receptors *Prolongation of the condition {excess/deficiency of ligands) will cause problems from the effects of the hormone; body cannot maintain the regulation of the condition 1 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Cell Communication/Cell-Signaling/Signal Transduction Transduction – conversion of one form of energy to another 1. Cell to cell – gap junctions; known as nexus in neurons; functional units are connexons 2. Chemical agents – with nearby or distant cells; uses ligands a. Synapses – utilizes neurotransmitters produced by the pre-synaptic nerves; receptor are found in the post-synaptic nerve b. Endocrine – uses hormones; distant cells Ex. Pituitary gland – controls different parts of the body by producing tropic hormones ex. Growth hormone, FSH, LH c. Autocrine – communication with nearby cells of the same cell type exx. Communication between insulin secreting beta cells of the islets of Langerhans in the pancreas d. Paracrine – communication with nearby cells of different cell type ex. Communication of beta cells with gulacogon-secreting alpha cells Steps involved in communication using chemical agents 1. Synthesis of the agent 2. Release 3. Transport towards target cell 4. Interaction with a cellular receptor 5. Change in cellular receptor 6. Change in cellular activity 7. Termination of effects Re-uptake or decomposition of the chemical agents by enzymes; recycling /re-utilizing Acetylcholine – acetylcholine esterase Epinephrine/norepinephrine – monoamine oxidase & catechol-O-methyltransferase Dopamine – dopaminase DULAY, Arman Carl Signal Transduction Extracellular changes are transformed into intracellular messages causing alteration in cellular activity. Initiated by molecules (ligands) interacting with membrane receptors or intracellular receptors activating second messengers and eventually cellular response. Classification of Signaling Molecules 1. Small lipophilic molecules – affect intracellular receptors ex. Steroid hormones 2. Large lipophilic molecules – affect membrane receptors 3. Hydrophilic molecules – affect membrane receptors Characteristics of receptors 1. located in the cytoplasm, nucleus or cell membrane 2. made up mostly of proteins (integral) 3. exhibits high degree of specificity 4. high affinity to a specific signaling molecule *nicotinic receptors – present on all autonomic ganglia; myoneural junction of skeletal muscle *muscatinic receptors – found in parasympathetic neuroeffector junction & sympathetic cholinergic neuroeffector junction *alpha & beta receptors – sympathetic adrenergic neuroeffector junctions *insulin receptors – found in skeletal muscles and adipose tissue 2 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D APOPTOSIS: programmed death of a cell RBC – though unnucleated, it is able to survive because it carries enough energy and nutrients that will last about 120 days - characterized by overall compaction of a cell and its nucleus and the orderly dissection of the chromatin by endonucleases - mediated by proteolytic enzymes called caspases Local potential/local response - Hypopolarizing change/local depolarizing change: electrical change that does not allow a cell to depolarize - local excitatory state of the cell - acute subthreshold potential - negativity of the change becomes less than normal Two Phases 1. Activation phase: self-destruction 2. Execution phase: “eat me” markers for phagocytes Local potentials in the different parts of the body: Receptor potential - local potential developed in sensory receptors - generator potential End plate potential - muscles Excitatory/inhibitory pos-synaptic potential - post-synaptic portion of the neuron Two distinct pathways: 1. Receptor mediated pathway(TNF) – extracellular 2. Mitochondria mediated pathway – intracellular **Whatever amount of cells are destroyed, the same number of new cells are produced by the body. Reticulocytes - youngest red blood cells in circulation Low reticulocytes = developing anemia The presence of the ff. ions in the intracellular and extracellular compartments of the cell are responsible for the electrical activity of the cell: ELECTROPHYSIOLOGY Excitable cells – able to produce electrical activity *Ions are responsible for cell electrical activity. Resting membrane potential (RMP) - negative electrical activity recorded on the inner surface of the membrane - steady potential: constant electrical activity, nonchanging - transmembrane voltage potential: recorded on the membrane Action potential - nerve impulse; arises from effectively stimulated cells - response of excitable cells to threshold intensity - results from depolarization of the cell Threshold – lowest effective stimulus intensity DULAY, Arman Carl Electrochemical balance/equilibrium - achieved by the Gibbs-Donnan effect - due to the presence of ions that are not capable of penetrating the membrane Conductance - membrane permeability to charged particles - when the cell is resting, it has higher conductance to K+ and Cl- and lower conductance for Na+ and no conductance to negatively charged proteins 3 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D Leaky or passive channels: continuously open, non-gated channels Nernst Equation - single ion Goldman-Hodgkin-Katz Equation - expresses the same rel’ship as Nernst Equation,but for ALL IONS INVOLVED according to their permeability Effect of concentration gradient K+ will normally move outside the cell, Cl- will tend to move in, Na+ has a tendency to move into the cell Effect of electrical gradient Inside negative condition attracts Na+ to move in via sodium leakage, detains K+ inside the cell (but concentration gradient has greater effect; K= moves out), repels Cl= entry (balanced effect from concentration and electrical gradient; no net flow) Ergo, when the cell is resting, it has a tendency to make the inside more negative, but this never happens because it is always balanced by the Na-K exchange pump. Remember PISO = maintains constant electrical activity. Electrogenic Na-K pump – non-selective ion channel – K is 100x more permeable than Na The higher permeability of K= contributes about 67mV to the magnitude of the RMP. The Na-K pump produces about 3mV. Passive and Active Forces that Establish and Maintain RMP 1. Nature of the cell membrane 2. Unequal distribution of ions 3. Operation of the Na-K pump *Polarized cell = correct term to describe a resting/inactive cell When you effectively stimulate a cell, there is an involvement of other channels other than leak channels like: Voltage gated channels: regulated by the electrical activity of the cell; specific 1. Voltage-gated sodium channels: have 2 gates, inactivation & activation gate The electrical activity of the membrane is more dependent on the permeability of the membrane to K+. Resting electrical activity in the muscle = -90mV nerves = -70mV (smaller diameter); -90mV (bigger diameter) DULAY, Arman Carl 4 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Cellular Physiology Part 3 & Electrophysiology June 8, 2014 Section 1D 2. Voltage-gated potassium channels – has activation gate only This gives the cell the tendency to hyperpolarize or to become more negative than normal. The closure of the activation gates of VG K channels follows coupled by the closure of the activation gates and opening of the inactivation gates of VG Na channels to prepare the cell for another activity. The Na-K exchange pump’s activity increases. Critical Firing Level: also known as the threshold voltage; allows the membrane potential to reach the threshold potential If the cell is resting, there is no activity of the VGC since they are all closed, only leaky channels and carriers are active. In the resting state, the inactivation gates of VG Na channels are open. Upon effective stimulation, the cell will immediately depolarize and the VG Na channel is initially affected causing the opening of the activation gates. Conductance to sodium therefore is increased causing rapid and massive Na influx. This is NOT a continuous change because it will eventually reach equilibrium. This results to the closure VG Na channels by the inactivation gates. VG K channels are used to repolarize the cell. There occurs a fast K+ efflux. Even if the cell reaches the normal (-70mV), it will immediately stop the repolarization. The equilibrium potential for K must also be reached. DULAY, Arman Carl 5 of 5 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE PHYSIO B 1.1 RENAL PHYSIOLOGY I Dr. RA Cruz 12-2-2015 1.1.1 Excretory System The excretory system is important for maintaining homeostasis, maintenance of internal environment. We can drink and eat as many food and drinks as we want since the excretory system will function to maintain homeostasis. The excretory system includes the Kidneys, Lungs, GIT, and the Skin. The lungs (Respiratory system) will remove CO2 and water. The GIT removes undigested materials. The skin excretes electrolytes and water. The figure shows the kidney and its parts (Refer to the figure). The renal cortex is the outer region which is isotonic. At the inner region will be the renal medulla which is hypertonic. Within the medulla, the renal pyramids and Renal columns of Bertin are found. The columns of bertin are found in between the pyramids. Found in the renal pyramids are the renal papilla that will give rise to the minor calyces, forming the major calyces. The major calyces forms the renal pelvis connected to the ureter. of these organs in The most important homeostasis is the kidneys. The function of the kidneys includes: ďĄ Excretion of metabolic wastes and foreign chemicals ďĄ Regulation of extracellular H2O, body fluid osmolality, and electrolyte concentrations ďĄ Regulation of arterial pressure (via RAAS) ďĄ Regulation of acid-base balance ďĄ Secretion, metabolism, excretion of hormones ďĄ Endocrine function (Hormones include: Renin, Erythropoeitin, Vitamin D) Good to know: There is a debate whether Renin should be considered a hormone or not since it does not target an organ, instead, it targets a substance, angiotensinogen. ďĄ Gluconeogenesis – production of carbohydrates from non-carbohydrate sources. The kidneys are retroperitoneal organs. The basic unit of the kidneys will be the nephron formed by the blood vessels, renal corpuscles and renal tubules. Blood is filtered in the nephron. The filtrate will form the urine excreted from the body via the urethra. 1.1.2 1.1.3 Functional Anatomy of the Kidneys The kidneys will regulate extracellular osmolarity and volume. Extracellular fluids are regulated where as when the ECF changes, the Intracellular fluid will adjust accordingly. Blood supply The flow below shows the flow of blood from the abdominal aorta to and out of the kidneys back to the Inferior vena cava. SDF Lindo Page 1 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE 1.1.4 Nerve Control The kidneys will only have Sympathetic innervation. Norepinephrine is released resulting to vasoconstriction reducing renal blood flow. The reduction may be as low as <200 ml/min. there are two important conditions to remember, Oliguria and Anuria. In Oliguria, the urine output is 300-500ml/day. In Anuria, usually experienced when a person experiences shock, the urine output is <50ml/day. The normal amount of urine excreted by a person per day is 1 to 1.5L. Another neurotransmitter important in the kidneys will be dopamine which is a vasodilator. Renalase degrades cathecolamine, specificially Norepinephrine and dopamine in the kidneys. 1.1.5 Nephrons (Blood Vessels) the peritubular capillaries and/or vasa recta, both of which are low pressure areas (13-15mmHg). This allows for reabsorption. Good to know: The blood supply in the kidney is unique in a sense that it is the only organ with two arteriolar system, and with two capillary beds. The afferent and efferent arterioles controls the pressure in the glomerulus since they are able to vasoconstrict or vasodilate. This controls hydrostatic pressure in glomerulus. On the other hand, the pressure in the peritubular capillary is controlled by the efferent arteriole only. 1.1.6 Nephron (Tubular cells) The filtrate is collected from the glomerulus to the bowman’s space (bowman’s capsule). It will flow to the PCT (Proximal Convoluted tubule) where majority of the filtered substances are reabsorbed, or majority of wastes substances are secreted. Then the filtrate goes to the loop of henle. This is the nephron. In terms of the blood vessels, this consists of the Afferent arteriole, efferent arteriole, Glomerulus (Capillaries), Peritubular capillaries, and vasa recta. The afferent arterioles is closely associated with the JG cells and Granular cells. The JG cells produce Renin while the Granular cells produce Renin and Erythropoeitin. These two type of cells are part of the Juxtaglomerular complex, which will be discussed later. This complex is important for activation of RAAS. Filtration occurs in the Glomerulus. The hydrostatic pressure in here is three times higher (60100mmHg) than the normal capillary bed (2030mmHg). Since this is a high pressure capillary bed, filtration occurs. The blood filtered from the glomerulus goes now to the efferent arteriole, then to • • The loop of henle has the following parts: Descending limb – where H2O is reabsorbed Ascending limb – solutes are reabsorbed - Further divided to Thick and thin ascending limb. - In the thin ascending limb, solutes are reabsorbed passively. - In the thick ascending limb, solutes are reabsorbed actively. SDF Lindo Page 2 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE In the late portion of the thick ascending limb, the macula densa is found (this is according to Berne and Levy. According to Guyton and Hall, it is in the early part of the DCT). The Macula densa serves as Na+ concentration sensor. It detects the concentration of sodium in the filtrate. This is important in the activation of RAAS. From the loop of henle, the filtrate then flows to the DCT (Distal convoluted tubules), then to the cortical collecting ducts, and the medullary collecting ducts. The distal convoluted tubule and collecting ducts are composed of principal cells and intercalated cells. These are both sensitive to aldosterone. When aldosterone is present, the kidneys wil reabsorb sodium and/or water in exchange for potassium and/or hydrogen. The principal cells handle secretion of potassium, while the intercalated cells will handle secretion of Hydrogen and bicarbonate. 1.1.7 Primary Cilia All tubular cells has primary cilia except for intercalated cells. Polycystic kidney disease There is a defect in the genes encoding for the polycystin 1 and 2 which results to defective primary cilia, resulting to abnormal development of tubular cells resulting into cysts. This results to renal failure. 1.1.8 Juxtaglomerular apparatus This is composed of the Macula densa, granular cells, and mesangium. The Macula densa acts as Sodium sensor such that when Na+ is low, it will signal granular cells to release rennin activating RAAS. Once RAAS is activated, blood pressure increases. The mesangium is composed of mesangial cells and matrix. The apparatus regulates the calibre of the afferent and efferent arterioles affecting blood flow. MD =Macula Densa, EGM = Extraglomerular mesangial cells, G = granular cells The electomicrogram above shows the primary cilia (C). They are primarily composed of Polycystin1 and 2, encoded by pkd1 and pkd2 genes. The cilia acts for sensor for tubular flow. When the fluid flows, the cilia will bend. Calcium channels are opened allowing for calcium influx which then results to secretion of potassium. When calcium is taken in, the cell will initiate calcium dependent pathways including proliferation, differentiation, and apoptosis of tubular cells. 1.1.9 Two types of Nephrons The two types include the superficial / cortical nephron and the juxtamedullary nephron. The cortical nephrons are found in the cortex, surrounded by an isotonic medium. The juxtamedullary nephron’s loop of henle is found in the renal medulla (all other parts are in the cortex), surrounded by a hypertonic medium. Population wise, in every 7 cortical nephrons, there is 1 juxtamedullary nephron. In terms of function, more water is reabsorbed in the juxtamedullary nephron’s loop of henle since it is in a SDF Lindo Page 3 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE hypertonic medium. Therefore, it has a higher concentrating capability. V – urine vol/time P – plasma concentration In addition, the JM nephron is associated with vasa recta while the cortical nephron is associated with the peritubular capillaries. ď§ ď§ For example: Given: 1.1.10 Renal Blood Flow In terms of the amount of blood flowing in the kidneys, its 20-25% of the Cardiac output (5L/min) which is approximately 1.25L/min. With this amount of blood flowing normaly, the normal urine output is 0.5-1ml/kg/hr (Pedia: 1-2 ml/kg/hr), or 30cc/hr. This results to 1-1.5L/day. CNa = ? UNa =700 mEq/L PNa =140 mEq/L V = 1 ml/min Computation: C = UV/P C = (700 x 1)/140 C = 5 ml/min Blood flow is guided by these two laws: Ohm’s law: F = âP/R Where F is Flow, âP is pressure gradient, R is resistance. Such that: ↑ âđ = ↑ đ ↑đ =↓đ Poiuselle’s law (governing resistance): R = 8lη/∏r4 Where R is resistance, l is length of vessel, η is viscosity of blood, r is the radius of the vessel. Such that: ↑ đĽ đ¨đŤ đ§ = ↑ đ ↑ đŤ =↓ đ There are two methods for measuring Renal Blood flow: the direct method (magnetic flow meters) and the indirect method (clearance principle). Therefore, in one minute, there is 5mL of plasma devoid of Sodium. In clearance principle in computing Renal blood flow, PAH (Paramino hippuric acid) clearance is utilized. The subject is infused with PAH and after a while, blood sample is taken and concentration of PAH in urine and blood is determined. The Renal Plasma Flow is equal to the clearance of PAH. CPAH = UPAHV/PPAH With the CPAH given, the RBF (Renal blood flow may be computed by RPF / (1-hct) Take note: RBF through the vasa recta is very minimal making it sluggish. ď§ <2% of RBF ⪠0.7% of RBF Other formulae you need to remember: ďĄ ďĄ F = âP/R F = (Parterial – Pvenous) / renal vascular resistance In the direct method, renal blood vessels are surgically isolated. This is not experimentally practiced since this is too invasive. In the indirect blood and urine sample is collected to determine clearance of a substance. For example in the clearance of Na, Na concentration is determined to compute for the other parameters: (Parterial – Pvenous) is governed by Blood pressure: BP = (SV x HR) x TPR where SV is Stroke volume, HR is heart rate, TPR is Total Peripheral Resistance. C = UV / P C – clearance U – urine concentration Renal Vascular resistance is governed by Pouiselle’ law: ď§ R = 8lη/∏r4 ď§ ď§ ↑ đđ, đđ, đ¨đŤ đđđ = ↑ âP = ↑ đ , SDF Lindo Page 4 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE Renal vascular resistanceis affected by: ď§ Interlobular arteries, afferent and efferent arterioles ď§ Sympathetic activity, hormones (angiotensin for constriction, vasopressin for constriction, endothelin for constriction, NO for dilatation, Prostaglandin for dilatation) ď§ Renal autoregulation ď§ Blood viscosity For blood viscosity, this does not change blood flow that much. Patients who are chronically anemic will have dilute blood, therefore resistance is low, blood flow is high. Those with chronic polycythemia vera, viscosity is high, resistance is high, then blood flow is low. There are other conditions that drastically affect blood flow. In dengue, the blood is so viscous due to increased hemtocrit so resistance is increased and blood flow decreased. 1.1.11 Renal Autoregulation Renal autoregulation affects resistance. The kidneys have intrinsic ability to control blood flow and filtration rate. There is a constant blood flow and filtration rate despite of fluctuations in arterial pressure. The renal autoregulation pressure ranges in 90180mmHg. This means that for as long as arterial blood pressure is within the range, renal blood flow and filtration rate are kept constant; once below 90, renal blood flow decreases, once higher that 180, renal blood flow increases—filtration rate then adjusts accordingly. ⪠UO : 1.5L/day Without Autoregulation BP : 125 mmHg ⪠GFR : 225L/day ⪠Reabsorption : 178.5L/day ⪠UO : 46.5L/day 1.1.12 Tubuloglomerular feedback mechanism Tubular cells will pick up as many Na as possible. When the BP is high, blood flow and filtration rate is also high, therefore, the amount of Na reabsorbed is low due to the increase in speed of flow. Therefore the NaCl concentration in the tubular fluid increases which is then sensed by the Macula densa. Macula densa secretes ATP and adenosine targeting the afferent arteriole increasing it resistance by constriction. The hydrostatic pressure in the glomerules then decreases and filtration also decrease. This offsets the original condition. In order to keep renal blood flow constant, resistance will adjust. Now this phenomenon is governed by the tubuloglomerular feedback and the myogenic mechanism. Renal autoregulation is important since it makes sure that the amount of urine ouput is kept 1.5L/day. In the absence if regulation, say blood pressure is increased to 125 mmHg without, using the computation for urine output, it will result to 46.5L /day which is definitely impossible since blood available is only 5 liters! With Autoregulation: BP : 100 mmHg ⪠GFR : 180L/day ⪠Reabsorption : 178.5L/day Now, when the BP goes down, RBF goes down and GFR also goes down. Flow is slower so more Na is reabsorbed. There will be decreased NaCl sensed by the Macula densa. No ATP and adenosine is release so the afferent arterioles will vasodilate. Macula densa also SDF Lindo Page 5 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE signals JG cells to release renin activating RAAS. Angiotensin II from RAAS signals the efferent arteriole to vasoconstrict increasing resistance. The pressure in the glomerulus then increases, so hydrostatic pressure is increased which increases filtration, offsetting the original condition. In addition, angiontensin II goes to the circulation increasing blood pressure. In myogenic mechanism, the increase in BP and RBF will stretch the blood vessels. This mechanical phenomenon will open mechanical-gated Ca channels allowing for influx. Influx of Ca will then result to constriction of smooth muscles (Reflex constriction), therefore, increasing resistance. This will in turn result to decreased filtration rate. 1.1.14 Vasoconstrictors and Vasodilators The figure above shows how ATP and adenosine interacts with the smooth muscles causing it to vasoconstrict. Increase in carbohydrate and protein intake increases renal blood flow and filtration rate. When intake of protein and carbohydrate increases, the plasma glucose and amino acid levels will increase and are filtered in the glomerulus. The task of the tubular cells is to reabsorb 100% glucose and 100% amino acids. Everytime glucose or amino acids are absorbed, Na is reabsorbed via co-transport. The NaCl level then goes down, sensed by the Macula densa. It activates the tubuloglomerular feedback. Take note: ANP (Atrial Natriuretic Peptide—from the atrium) and BNP (Brain Natriuretic Peptide—from the ventricles) act as constrictors efferent arterioles but dilators in the afferent arteriole. 1.1.13 Myogenic Mechanism The figure shows that PGI1 and PGE2 (prostaglandins) are cause dilation. When we drink pain relievers, Prostaglandin synthesis is decreased affecting renal vasoconst. and dil. When this occurs, chronic constriction occurs, resulting to ischemia, then kidney failure. SDF Lindo Page 6 of 7 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION INSTITUTE OF MEDICINE DOCTOR OF MEDICINE 1.1.15 Micturition Is micturition a voluntary or involuntary act? Some say both. Some say partial. Apparently, impulses are also sent to the higher center, the pons and the cortex. This allows for the assessment of whether it is convenient to urinate or not. The higher centers will modulate the reflex arc. Is the micturition reflex voluntary or involuntary? Involuntary. When reflex is concerned, the micturition act is involuntary. Therefore the following are present: ďĄ ďĄ ďĄ ďĄ ďĄ ďĄ S: stretch receptors AN: pelvic nerves C: S2-3 EN: pelvic nerves E: detrusor muscle, internal urethral sphincter Higher C: pons, cortex The stretch receptors are stimulated when the bladder is distended. Signals are sent via the AN pelvic nerves to center (s1 and s2). The center will send a response to the EN pelvic nerves. Excitatory stimuli are sent to the detrussor muscles so it contracts, while inhibitory stimuli are sent to the internal urethral sphincter for it to relax. This will induce urination. In the figure above, the dotted line represent pressure due to contraction of detrussor muscles. Meanwhile, the solid line represents pressure increase due to increase in volume. The higher centers will modulate the reflex arc so the the detrussor muscle is inhibited now, and the internal urethral sphincter as well. This will allow for the relaxation of the detrussor; the internal urethral sphincter will contract. The pressure then drops. Thru time, the urine volume increases, the bladder is then again distended sending signals again. This will result to micturition reflex, but the higher center will then again modulate. Through time, the intensity for the urge to urinate will increase until a maximum limit. Good to know: Guyton refer to the micturition reflex as selfregenerating. Therefore, the reflex increases thru time. 1.1.16 Clinical correlation Say Patient A suffers from Tertiary Syphilis which later causes destruction of the pelvic nerves, thus, the reflex does not process. The patient does not know when the bladder is full. The pressure is very high resulting to overflow incontinence. Management includes insertion of catheter. Patient B on the other hand has transected spinal cord above the sacral segment. The reflex arc is intact but the higher center cannot control it. Therefore there is still incontinence. For management, the inguinal region’s dermatomal region may be stimulated to allow for controlled micturition. SDF Lindo Page 7 of 7 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY N eurons, aka nerve cells, are the basic unit involved in the Nervous System (NS). NS does not utilize a single nerve only. It needs to activate a certain structure that is initially affected by changes in the body, that is, the sensory nerves (aka afferent neurons). Figure 1. REFLEX ARC (The Functional Working Unit of the NS) (1) If the problem is in the Reflex Arc ď no response; otherwise, there is sensation – effective stimulation of receptors. (2) If the problem is in the SENSORY ARM ď no sensation ď no response (3) If the problem is in the EFFECTOR ARM (and sensory arm is normal) ď with sensation ď no response in the effector arm. *Motor Neuron – aka motor nerve/ efferent nerve/ visceral nerve e.g. visceral tissues such as skeletal muscle, smooth muscle, secretory glands. Parts of a neuron Dendrites – tapering and branching extensions of the soma and generally convey information toward the cell body. Axon – extension of the cell that conveys the output of the cell to the next neuron or, in the case of a motor neuron, to a muscle. In general, each neuron has only one axon. Axon Hillock – usually the site where action potentials are generated because it has a high concentration of the necessary channels. Soma – (perikaryon/ cell body) contains the nucleus and nucleolus of the cell and also possesses a well-developed biosynthetic apparatus for manufacturing membrane constituents, synthetic enzymes, and other chemical substance needed for the specialized functions of nerve cells. (Koeppen and Stanton 2010, ebook) CAYCO ď Page 1 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY AXON TERMINAL makes use of NTA; some are connected to the cell body, but most are connected to the dendrites of the next neuron If stimulated here, transmission would be bidirectional a) towards the axon terminal, and b) towards the dendrites/cell body. But since only a) can produce NTs, impulse transmitted to the cell body will just eventually die out. The Postsynaptic terminal contain receptors (e.g. muscarinic, nicotinic) Orthodromic/ Anterograde = unidirectional transmission Antidromic/ Retrograde = bidirectional; produces local current flow CAYCO ď Page 2 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY Speed of Impulse Transmission 1. Type A neurons – fast transmitting sensory neurons; all type A are myelinated a. α – fastest; large diameter myelinated; >100 m/s to a max of 130m/s b. β c. γ d. δ – slowest; small diameter myelinated; 15m/s 2. Type C neurons – slow transmitting sensory neurons; small diameter, unmyelinated; 0.3 to 0.5 m/s Factors affecting speed of neurons/neuronal activity The following may increase neuronal activity: 1. Slightly increased body temperature ďˇ less than 1oC or 2o to 3oF ďˇ lowers activation threshold of neuron ďˇ results in hypopolarized nerves (more excitable) 2. Neurons with lower threshold ďˇ results in hypopolarized nerves 3. Increased diameter of neurons – lesser resistance to impulse flow 4. Myelinated neurons ďˇ SALTATORY CONDUCTION – myelin is an insulator and current flowing through it is negligible so depolarization in myelinated axons jumps from one node to the next node of Ranvier thereby enhancing neural transmission or neural conduction. Why? There is faster transmission with saltatory conduction making use of the NoR because most of Na+ channels are at the NoR. Production of Myelin Sheath: In the PNS ď Schwann cells In the CNS ď Oligodendroglias Number of Na+ channels per square micrometer of membrane in myelinated nerves: Cell body 50 to 100 Axon hillock 350 to 500 (initial generation of action potential) Surface of myelin Less than 25 Node of Ranvier 2,000 to 12,000 Axon terminal 20 to 75 Axons of unmyelinated nerve 110 Myelination of nerves Autonomic Somatic (muscle nerves) CAYCO ď Preganglionic ď myelinated Postganglionic ď unmyelinated Both myelinated Page 3 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY Synapses Types of Synapses: 1. Chemical – most common; uses neurotransmitters ďˇ Unlike electrical synapses, there is no direct Best known NTs: communication between the cytoplasm of the two cells acetylcholine, norepinephrine, here in chemical synapses. Instead, the cell membranes epinephrine, histamine, gammaare separated by a synaptic cleft of some 20 µm, and aminobutyric acid (GABA), the interaction between the cells occurs via chemical glycine, serotonin, and glutamate intermediaries known as neurotransmitters (Koeppen (Hall 2011, p. 559) and Stanton 2010, ebook) 2. Electrical – uncommon; simply transmit, traversing the synapse, from the pre- to the post- synaptic terminal since sometimes, the space at the cleft is so small it is already negligible. ďˇ Characterized by direct open fluid channels that conduct electricity from one cell to the next. Most of these consist of small protein tubular structures called gap junctions that allow free movement of ions from the interior of one cell to the interior of the next (Hall 2011, p. 559). 3. Conjoint – uncommon; can do both chemical electrical 4. Axosomatic – axon terminal is connected to the cell body 5. Axodendritic – most common; axon terminal is connected to the dendrites 6. Axo-axonal – axon to axon connection ďˇ Serial synapses – axoaxonic synapse is made onto the axon terminal and influences the efficacy of that terminal’s synapse with yet a third element. ďˇ Reciprocal synapses – both cells can release transmitter to influence the other (Koeppen and Stanton 2010, ebook). *Note: according to Koeppen and Stanton (2010), chemical synapses occur between different parts of the neurons, and that, types 4, 5 and 6 mentioned above are actually subtypes of chemical synapses. Aside from these, there are additional types of synapses mentioned in the book that are also under chemical synapses: dendrodendritic (dendrite to dendrite) and dendrosomatic (dendrite to soma). CAYCO ď Page 4 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY COMMUNICATION THROUGH DENDRITES Classes of Neurotransmitters TRANSMITTER Acetylcholine Serotonin (5-hydroxytryptamine or 5-HT) GABA Glutamate Aspartate Glycine Histamine Epinephrine Norepinephrine Dopamine Adenosine Nitric oxide (NO) Neurotransmitter and its receptor TRANSMITTER Acetylcholine Norepinephrine Dopamine GABA Serotonin Adenosine CAYCO ď MOLECULE Choline Tryptophan SITE OF SYNTHESIS CNS, parasympathetic nerves CNS, chromaffin cells of the gut, enteric cells Glutamate CNS CNS CNS Spinal cord Hypothalamus Adrenal medulla, some CNS cells CNS, sympathetic nerves CNS CNS, peripheral nerves CNS, gastrointestinal tract Histidine Tyrosine Tyrosine Tyrosine ATP RECEPTOR Cholinergic Adrenergic Dopaminergic GABA Serotonergic Adenosine Page 5 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY Synthesis and Degradation of Catecholamines Criteria for Neurotransmitters (NTA) 1. Synthesized in a NEURON. 2. Present in the PRE-SYNAPTIC NERVE (stored in vesicles = 5,000 to 10,000 NTs per vesicle) and is released on depolarization in physiologically significant amounts (200 to 300 vesicles per depolarization) ď total: 1 million to 5 million NTs ďˇ If you release less than 1 million NTs ď ineffective stimulation ď will produce local potential ONLY. 3. Has immediate and short-lived effects on the post-synaptic nerve ďˇ Because NTs immediately move away from the receptor or there is immediate reuptake of the NTs back to the presynaptic nerve. 4. A mechanism exists in the neuron or synaptic cleft for the removal of NTA at the receptors. S ignal Transmission at the Synapse 1. Transmitter is synthesized and then stored in vesicles. 2. An action potential invades the presynaptic terminal. 3. Depolarization of presynaptic terminal causes opening of Voltage-gated Ca2+ channels. 4. Influx of Ca2+ through channels ďˇ Involves activity of attachment of Synaptotagmin 5. Ca2+ causes vesicles to fuse with presynaptic membrane CAYCO ď Synaptotagmin = Ca++ sensor that triggers the actual fusion event. Local high Ca++ concentration allows the rapid binding of Ca++ to protein synaptotagmin, and binding causes conformational change in synaptotagmin triggering the fusion of a docked vesicle (Koeppen and Stanton 2010). Page 6 of 12 Physiology A [SY 2013-2014] ďˇ ďˇ NERVE PHYSIOLOGY Involves SNARE proteins: o One Synaptobrevin = v-SNARES or VAMP (vesicle associated membrane protein) o Two Syntaxin = t-SNARES or SNAP-25 (found on the target or presynaptic plasma membrane) Synaptic vesicle docking and fusion in nerve endings: When this happens, it will signal to release NTAs towards synaptic cleft. 6. NTA is released into synaptic cleft via exocytosis ďˇ Botulinum toxin can prevent release of NTA CAYCO ď Page 7 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY 7. Transmitter binds to receptor molecules at the postsynaptic membrane ď causes electrical changes at the post synaptic nerve. A chemical, such as the neurotransmitter Acetylcholine (Ach), triggers a conformational change in the channel protein which allows Na+ ions to enter the cell, causing depolarization. An Ion-Linked Channel Receptor Some NT molucules bind to receptors on ion channels. When a neurotransmitter molecule binds to an ion-channel linked receptor, the channel opens (as in this case) or closes, thereby altering the flow of ions into or out of the neuron. CAYCO ď Page 8 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY 8. Postsynaptic current causes excitatory or inhibitory postsynaptic potential that changes the excitability of the postsynaptic cell ďˇ NTAs acting as ligand activates Na+channels (ligand-gated Na+ channels) at the post synaptic nerve ď initially develop excitatory potential ď initial local depolarizing change ď will eventually open the voltage-gated Na+channels ďˇ If inhibitory, either K+ or Cl- channels will be activated ď causing hyperpolarization. Inhibitory NTs: GABA, glycine, enkephalins, 9. Summation of EPSPs (Excitatory post-synaptic potentials) to generate action potential at the postsynaptic cleft. Why? ORTHRODROMIC TRANSMISSION at the SYNAPSES ďˇ NTs are present only in the pre-synaptic nerve. ďˇ Post-synaptic area is devoid of NTs. ďˇ The absolute refractory period Mechanism of NTA deactivation 1. Re-uptake (by presynaptic terminal) 2. Enzymatic deactivation e.g. Acetylcholine ď Acetylcholinesterase Epinephrine, Norepinephrine, Dopamine ď Cathecol-o-methyltransferase (COMT) Monoamine oxidase (MAO) 3. Diffusion of NTs away from the receptor Desensitization of receptors 1. Homologous desensitization – loss of responsiveness to one transmitter agent 2. Heterologous desensitization – loss of responsiveness to almost all transmitter agents Mechanism of drug effects Agonistic effects (increase NTA effects) ďˇ Increase synthesis of NTA ďˇ Destroy deactivating enzymes ďˇ Increase release of NTA from pre-synaptic cell ďˇ Blocking the inhibitors on NTA release ďˇ Increasing the sensitivity of receptors (to NTA) ďˇ Stimulating the receptors by mimicking the NTA ďˇ Decreasing deactivation/reuptake of NTA CAYCO ď Antagonistic effects (decrease NTA effects) ďˇ Decrease synthesis of NTA ďˇ Destroying NTA inside the pre-synaptic cell ďˇ Blocking the release of NTA from the presynaptic-cell ďˇ Stimulating inhibitors on NTA release ďˇ Decreasing the sensitivity of receptors (to NTA) ďˇ Blocking the receptors Page 9 of 12 Physiology A [SY 2013-2014] Characteristics of Synapses NERVE PHYSIOLOGY Possible Combinations of Temporal Summation 1. Temporal summation (see electrophysiology notes) 2. Spatial summation (see electrophysiology notes) 3. Convergence ďˇ several presynaptic neurons transmitting impulses to a SINGLE postsynaptic nerve ďˇ produces localized potential because it only affects a SINGLE group of cells 4. Divergence ďˇ Single presynaptic nerve to several postsynaptic neurons ďˇ Diffused impulses ď widespread effect in the body ď activity at the sympathetic nervous system CAYCO ď Page 10 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY Possible Combinations of spatial summation 5. Facilitation – occurs when neuronal activation is frequent/prolonged/repetitive; repetitive stimulation of neurons result to enhancement of neuronal activity (e.g. training of athletes) 6. Potentiation – Sustained activity ď keep on releasing neurotransmitter ď activity increases 7. Occlusion ďˇ Response of two neurons simultaneously stimulated is lesser when the two neurons are stimulated separately. Instead of getting a response, impulses cancel out producing no activity (e.g. activation of an inhibitory nerve in the area) ďˇ Note: Renshaw cell inhibition 8. Delay – there is normal delay because of the several steps involved before finally releasing NTA into the synaptic cleft (ie. activation first of synaptogramin ď synaptobrevin and syntaxin connection) 9. Excitation Integration of the synapse 10. Inhibition Summary of Synaptic transmission Excitatory ď EPSP 1. Activation of Ligand-gated Na+channels causing: Hypopolarization ď Depolarization 2. Activation of Voltage-gated Na+channels CAYCO ď Page 11 of 12 Physiology A [SY 2013-2014] NERVE PHYSIOLOGY Inhibitoryď IPSP 1. Activation of Ligand-gated K+ or Cl- channels causing: Hyperpolarization (pre/postsynaptic inhibition) 2. Cl- influx and/or K+ efflux 3. Inactivation of Na+ channels *Seen mostly in the brain: explains our distinction from animals acting only on instinct. Once aware of the presence of stimulus, one can also know the: 1. Quality/nature of the stimulus 2. Intensity of the stimulus Greater intensity (e.g. pressure) ď greater firing of action potential, Lower intensity (e.g. touch) 3. Location of the stimulus ďˇ In the cortex (at the parietal lobe), there are parts representing different parts of the body except for internal organs. The FACE and HANDS are well represented. There are specific receptors for particular area/part of body o Baroreceptor (pressure), photoreceptor (eyes), auditory receptor ď§ eyes ď rods and cones ď optic nerve ď visual cortex of brain at the occipital visual cortex (Brodmann area 17) ď§ Ears ď organ of Corti ď cochlear nerve 4. Timing of stimulus application – timing the stimulus was applied and was removed Additional Vocabulary: Stereognosis – identification of 3D objects via touch Topognosis – identification of localization of stimulus Adaptation of sensory stimulation – exposed to certain type of stimulus for prolonged time Renshaw cell - an inhibitory interneuron in the ventral horn of gray matter of the spinal cord that is held to be reciprocally innervated with a motor neuron so that nerve impulses received by way of processes of the motor neuron stimulate inhibitory impulses back to the motor neuron along an axon of the internuncial cell (MerriamWebster 2013). Renshaw Cell Inhibitory System. Also located in the anterior horns of the spinal cord, in close association with the motor neurons, are a large number of small neurons called Renshaw cells. Almost immediately after the anterior motor neuron axon leaves the body of the neuron, collateral branches from the axon pass to adjacent Renshaw cells. These are inhibitory cells that transmit inhibitory signals to the surrounding motor neurons. Thus, stimulation of each motor neuron tends to inhibit adjacent motor neurons, an effect called lateral inhibition. This effect is important for the following major reason: The motor system uses this lateral inhibition to focus, or sharpen, its signals in the same way that the sensory system uses the same principle—that is, to allow unabated transmission of the primary signal in the desired direction while suppressing (Hall 2011, p. 675). Sources: Lecture of Sir Felipe C. Barbon, M.D. JE HALL, PhD (2011). Guyton and Hall Textbook of Medical Physiology. 12th Edition. Philadelphia: Saunders, Elsevier KOEPPEN, BM and BA STANTON (2010). Berne & Levy Physiology. 6th Edition [Ebook]. CAYCO ď Page 12 of 12 Renal Physiology II: Filtration, Reabsorption and Secretion (Ronald Allan Cruz, MD) ďˇ Gibbs-Donnan effect o Filtrate is similar to plasma except for CHON Nephron ďˇ ďˇ ďˇ Glomerular filtration Tubular reabsorption Tubular secretion ďˇ Urinary excretion = F – R + S As far as secretion is concerned, this is the sum of the three different processes done by the nephrons, so here you have filtration, reabsorption and secretion. Excretion is equal to filtration minus reabsorption plus secretion, so that’s your net excretion. So looking at the diagram, you have your afferent arteriole, glomerulus and efferent arteriole. Magnifying it, you have your filtration barrier composed of three layers from the blood going to the filtrate: the capillary endothelium which is fenestrated and next, you have your glomerular basement membrane then you have your Bowman’s epithelium and then after that, you have your filtrate already. Now your filtering membrane is said to be 100x more permeable to capillaries and it will exhibit the Gibbs-Donnan effect which will be discussed more later. ďˇ Looking at the diagram, you have your glomerulus then your peritubular capillaries, Bowman’s capsule/space, and tubule. In diagram A, this depicts filtration only, such that the substance is filtered, not secreted, not reabsorbed. A typical example would be inulin. For diagram B, the substance is filtered and partially reabsorbed, so some of substance X will go back to the circulation. If you get a urine sample, substance X is still present in the urine sample. A typical substance would be electrolytes: sodium, potassium etc. Filtration barrier o Bowman’s epithelium ď§ Podocytes, filtration slits ď§ Sialoglycoproteins o Basement membrane ď§ Lamina rara externa ď§ Lamina densa ď§ Lamina rara interna ďˇ Trimer of α1-6 collagen IV, laminin, polyanionic proteoglycan, entactin, heparan-SO4, fibronectin o Capillary endothelium ď§ Sialoglycoproteins In diagram C, the substance is filtered and completely reabsorbed such that if you get urine sample, substance X should be absent. A typical example would be proteins, amino acids and glucose. In diagram D, the substance is filtered, but somehow, some of it passes through the efferent arteriole into the peritubular capillaries and this substance is secreted. So this substance is brought to the peritubular cells and then it goes out into the filtrate. A typical example would be creatinine. Glomerular Filtration Filtration barrier ďˇ Bowman’s epithelium ďˇ Basement membrane ďˇ Capillary endothelium ďˇ 100x more permeable than capillaries 1 Shannen Kaye B. Apolinario, RMT Looking at your filtration barrier more closely, this is your electron micrograph of your filtering membrane. So again from the blood to the filtrate, you have your capillary endothelium, the basement membrane and you have your Bowman’s epithelium. First, you have your capillary endothelium. As what we have said earlier, it is fenestrated. One important characteristic of your capillary endothelium is that it contains sialoglycoproteins which are negatively charged. From there, we go to the glomerular basement membrane, again, our direction is from the blood to the filtrate. So the first layer is your lamina rara interna. Next you have your lamina densa and then lastly you have your lamina rara externa. So your glomerular basement membrane would contain important negatively charged proteins like your type 4 collagen, laminin, polyanionic proteoglycan entactin, heparan sulphate and fibronectin. All of them will impart a highly negative basement membrane. Going now to your Bowman’s epithelium, it has slit pores and they will also have foot processes or podocytes. The podocytes interdigitate such that when you look at the top view, it has slit pores. Take note also that the Bowman’s epithelium will also have sialoglycoproteins imparting a negative charge. Because of your negative charge, it will repel negatively charged particles. Because of your slit pores and fenestration, it can allow the easy passage of larger molecules compared to your regular capillary beds found in the systemic circulation. ďˇ barrier is completely permeable to water. If you increase the molecular weight, looking at sodium, glucose and inulin so that is 23, 180 and 5,500 respectively, all of which will have the same filterability which is 1.0. Meaning to say, looking at inulin, inulin is completely filtered. If you increase the molecular weight further, you have your myoglobin which is 17,000 having a filterability of 0.75, this simply means that 75% of myoglobin is filtered. However, with albumin with a larger molecular weight of 69,000, it has a filterability of 0.005. Meaning to say, 0.5% is filtered - there is very little amount of albumin which is filtered. In this table, the larger the molecule, permeability or filterability decreases due to the slit pores and fenestrations. Mesangial cell o Contractile, phagocytic, produces matrix and collagen, biologically active mediators Another important structure within the glomerulus is the mesangial cell. So you have your afferent arteriole, glomerulus, efferent arteriole, and the dark structures are termed as the mesangial cells. These are mesenchymal in origin and they have important functions. They may have contractile properties or phagocytic properties and they produce the matrix that will support the basement membrane. So it produces important proteins like your collagen, entactin, proteoglycan etc. The mesangial cells now will support the filtrate barrier. Also, your mesangial cells are able to produce active mediators like prostaglandin. So you will note that because of prostaglandin which is a vasodilator and because of your contractile elements, the mesangial cell can actually control the blood flow going into the glomerulus. As what was said earlier, one of the important mediators is prostaglandin which is a vasodilator. If you dilate your vessel, blood will flow and long term use of NSAIDs will create renal problems. Looking at this graph, here you have your molecular radius or size of molecule and filterability. What they did is that they utilized dextran: negatively charged polyanionic dextran, neutral and polycationic or positively charged dextran. Given a molecular weight of let’s say 30, you will note that the negatively charged dextran has a low filterability compared to the neutral one having the same size more so with a positively charged dextran. So of the three, the positively charged has the highest filterability. A negatively charged particle will not easily pass through however, in positively charged particle, it can easily pass through. So the filtering barrier permits the passage of small and positively charged molecules. Because of the slit pores and fenestrations, the permeability is said to be 100x more permeable than your regular capillary bed. Because of negatively charged proteins found in your filtering membrane you can observe the Gibbs-Donnan effect. What is Gibbs Donnan effect? Recall that the membrane is highly negative. We said that it will allow the passage of small positively charged molecules. What is left in the blood would be negatively charged particles - large negatively charged particles like albumin. When your plasma is filtered, you concentrate now your albumin so the concentration of albumin goes up and the negative charge of your plasma increases because of albumin. Because of this, if you have let’s say a small positively charged molecule passing along with plasma, it will not be filtered as readily as before because it will now be attracted to the negatively charged albumin. So that s your Gibbs Donnan effect. It is not a general statement that when it a molecule is small and positively charged, it can easily pass through or filtered. It is not as simple as that, it depends on the concentration of albumin. So here you have the filtrate having similar characteristics with plasma except that it will not have plasma proteins. Effective Filtering Pressure Looking at this table, here you have your different substances that are filtered. Water with a molecular weight of 18 will have a filterability of 1.0, meaning to say, it is 100% filtered or the filtering 2 Shannen Kaye B. Apolinario, RMT ďˇ ďˇ PG: 60-70 mmHg ΠG: 32 mmHg ďˇ Effective filtering pressure o (PG + ΠB) – (PB + ΠG) ď§ PG – glomerular hydrostatic pressure ď§ ΠB – Bowman’s oncotic pressure ď§ PB – Bowman’s hydrostatic pressure ď§ ΠG – glomerular oncotic pressure As far as filtration is concerned, just like what you had the lecture in microcirculation, the Starling forces will come into play. Here you have your glomerular hydrostatic pressure of 60-70 mmHg and your glomerular oncotic pressure of around 32 mmHg. These forces will come into play as far as filtration is concerned. So first we need to understand effective filtering pressure or what the net pressure for filtration is. Here you have your Starling’s forces, just like what was discussed before during your cardio lecture, for filtration to occur, you need to get your pro-filtering factors minus your anti-filtering factors. So for the pro-filtering factors, you have glomerular hydrostatic pressure generated by the pumping action of the heart. For ΠB, that is Bowman’s oncotic pressure due to the presence of proteins inside the Bowman’s capsule which is normally 0 in value because proteins are not filtered. However, in certain pathologic conditions like nephrotic syndrome or glomerulonephritis, proteins can pass through increasing the Bowman’s oncotic pressure. The antifiltering factors are Bowman’s hydrostatic pressure due to the presence of fluid inside the Bowman’s space and that is your ultrafiltrate. And lastly, you have glomerular oncotic pressure so that’s the plasma proteins present in the glomerulus. ďˇ Effective filtering pressure = 10 mmHg o (PG + ΠB) – (PB + ΠG) ď§ PG – glomerular hydrostatic pressure = 60 mmHg ď§ ΠB – Bowman’s oncotic pressure = 0 mmHg ď§ PB – Bowman’s hydrostatic pressure = 18 mmHg ď§ ΠG – glomerular oncotic pressure = 32 mmHg Getting now their values, you will have an effective filtering pressure of 10 mmHg. Filtration Coefficient ďˇ ďˇ ďˇ Quantification of Glomerular Filtration ďˇ ďˇ ďˇ ďˇ GFR = C inulin C inulin = (U inulin x V) / P inulin C inulin = (120 mg/mL x 1 mL/hr) / 1mg/mL C inulin = 120 mL/min ďˇ BUN, creatinine estimates GFR In the laboratory, to experimentally measure GFR we utilize the clearance of inulin. How do we do this? The subject is infused with inulin, after achieving steady-state, we utilize the clearance principle. We simply get a urine sample and a blood sample, send it to the laboratory, and know the inulin concentration of both. Let’s say that the inulin concentration of inulin is 120 mg/mL, in plasma is 1mg/mL at steady state. Of course urine flow rate is more or less constant - 1mL. Simply plug in the values and you will get 120 mL/min. It is almost the same with 125 mL/min, so inulin is said to be the gold standard in measuring GFR because the renal handling of inulin is only via filtration, it is neither secreted nor reabsorbed. Filtration is the only one that happens and is the gold standard as far as measuring GFR is concerned. However, in the clinics, not all patients are given inulin because it is expensive and it is not readily available so what we utilize are BUN and creatinine. However, BUN and creatinine will only estimate GFR so it is not an accurate measurement. It will only estimate GFR because BUN (Blood Urea Nitrogen) is from protein metabolism (amino acid metabolism). The problem with BUN is that it is filtered and reabsorbed so BUN underestimates GFR. As far as creatinine is concerned, this is from creatine phosphate. The problem with creatinine is that it is filtered and secreted so that overestimates GFR. Now, you have a range, one that underestimates and the other one overestimates GFR so more or less you know where you will get the values. ďˇ GFR = Kf x EFP o Kf: Filtration coefficient ď§ Permeability ď§ Surface area ď§ Mesangial cell activity o EFP: Effective Filtering Pressure PG o o o GFR = 12.5 mL/min/mmHg x 10 mmHg GFR = 125 mL/min Now to get your glomerular filtration rate, your effective filtering pressure is multiplied with Kf. Kf is your filtration coefficient and the filtration coefficient is dependent on 3 factors: permeability of the membrane, surface area and mesangial cell activity. Let’s look at it one by one. Looking at the permeability of the filtration barrier, of course if you increase the permeability you increase Kf, GFR increases. For example, if the subject or patient has glomerulonephritis meaning to say, that the glomerulus is inflamed or the filtering membrane is thickened, the Kf will go down or decreases, GFR decreases. That’s why patients with glomerulonephritis present with oliguria. As far as surface area is concerned, of course if you increase the surface area, Kf increases, GFR increases. Example, if a patient undergoes partial nephrectomy (a certain portion of the kidney is removed), the surface area goes down, consequently, the GFR will go down. Mesangial cell activity will also alter the Kf. Recall that your mesangial cells will have important functions: contractile properties, produces prostaglandins etc. and all of these will affect Kf. So getting now your Kf of around 12.5 mL/min/mmHg multiply that will effective filtering pressure of 10mmHg, so your GFR now is around 125 mL/min. 3 Shannen Kaye B. Apolinario, RMT ďś ďś ďś ďś Arterial pressure ď§ ↓ pressure: ? GFR ď§ ↑ pressure: ? GFR Afferent arteriole resistance ď§ ↑ resistance: ? GFR Efferent arteriole resistance ď§ ↑ resistance: ? GFR ď§ ↑↑↑ resistance: ? GFR As far as glomerular hydrostatic pressure is concerned: What will happen with glomerular filtration if arterial pressure drops? What will happen with glomerular filtration if arterial pressure goes up? What will happen to GFR if your afferent arterioles constrict? What will happen to GFR if you moderately constrict your efferent arteriole? What will happen to GFR if you severely constrict your efferent arteriole? ďˇ PG o o o Arterial pressure ď§ Renal autoregulation: 80-160 mmHg ď§ ↑ pressure: ↑GFR Afferent arteriole resistance ď§ ↑ resistance: ↓ GFR Efferent arteriole resistance ď§ ↑ resistance: ↑ GFR ď§ ↑↑↑ resistance: ↓ GFR What will happen with glomerular filtration if arterial pressure drops? The question is how high or how low? If you will recall your previous lecture, within autoregulatory range, GFR is constant. Below 80, GFR goes down, above 160, GFR will go up. What will happen to GFR if your afferent arterioles constrict? GFR will go down because the hydrostatic pressure in the glomerulus drops. Filtration is non-selective, if a molecule is small and positively charged, it will be filtered indiscriminately most of the time. However, as far as reabsorption is concerned, reabsorption is selective. What will happen to GFR if you moderately constrict your efferent arterioles? GFR increases because you increase the hydrostatic pressure inside the glomerulus. If we have a GFR of 125 mL without reabsorption, our urine output would be 178 L per day which is physiologically impossible because we only have 5 L of blood and 3 L of plasma. Because of reabsorption, with a GFR of 125 mL/min, our average of urine output is around 1-1.5 L/day and that’s the job of reabsorption – to bring back essential substances into the body. What will happen to GFR if you severely constrict your efferent arteriole? GFR will go down because the blood flow will be curtailed. Initially in the glomerulus, filtration will occur but the thing is, since you severely constrict your efferent arterioles, plasma proteins will not pass through so you will now concentrate your plasma proteins within the glomerulus. Increasing plasma proteins increases oncotic pressure and oncotic pressure will oppose filtration. If oncotic pressure increases, filtration will decrease. Filtration Fraction ďˇ ďˇ ďˇ Extent of fluid loss from plasma Extent to which plasma CHOn is concentrated FF = GFR/RPF o GFR / C PAH o % of plasma flowing through the kidneys that is filtered o 0.16-0.2o Going now to filtration fraction, this is the extent of fluid loss from plasma or the extent to which plasma proteins are being concentrated like severe constriction of the efferent arteriole. The formula for your filtration fraction - GFR divided by renal plasma flow. Take note that renal plasma flow is actually equal to the clearance of PAH. That’s the percent of plasma flowing through the kidneys that is filtered. In this table, here you have your commonly filtered, reabsorbed and sometimes excreted substances. So you have your amount filtered, amount reabsorbed and amount excreted as well as the percent of the filtered load reabsorbed. Looking at it one by one, let’s say if you have plasma glucose of 180 g/day – that’s the amount filtered, this 180 should be reabsorbed such that if you get a urine sample, you should not be finding glucose there. Therefore, you have 100% reabsorption. Looking at your electrolytes for example sodium. In sodium, 25,500 are filtered but the reabsorbed are 25,400 such that the percent filtered is around 99.4% so a certain amount of sodium goes out into the urine. Mechanisms for Reabsorption ďˇ Active Transport o o o ďˇ Looking at this diagram, you have the blood side and filtrate side. As your blood passes through, plasma is filtered; plasma proteins are left behind being concentrated. The higher the fraction, the higher the concentration of your plasma proteins and normally, that’s around .16 to .20. In this graph, you have the afferent end, glomerulus, and efferent end (blood flows in this direction). This is plotted against osmotic/oncotic pressure. Take note that as blood passes through from the afferent side to the glomerulus to the efferent side, your oncotic pressure increases slowly increasing now your filtration fraction. Tubular Reabsorption ďˇ ďˇ ďˇ GFR = 125 mL/min UO = 178 L/day UO = 1-1.5 L/day ďˇ Reabsorption o Selective 4 Shannen Kaye B. Apolinario, RMT Transport maxima ď§ Carrier-dependent ď§ Glucose, amino acids, PO4, SO4, Vitamin C, malate, lactate, aceto-acetate, β-hydroxybutyrate Gradient-time limitation ď§ Depends on the gradient established and the time the fluid is in contact with the epithelium Pinocytosis ď§ CHON Passive transport o Depends on electrochemical and osmotic gradient o H20, urea, Cl- Now let’s talk about the different mechanisms for reabsorption. You have two general processes: active and passive. What’s the difference between the two? The difference is the utilization of energy and gradient: in active – uphill and in passive – downhill. In passive transport, it depends on the electrochemical and osmotic gradient. This is how water, urea and chloride are reabsorbed. It does not utilize energy and goes downhill. Looking at active transport, there are three processes: transport maxima, gradient time limitation and pinocytosis. Pinocytosis, this is how your filtered proteins are being handled. So in the luminal side, you pinocytose your proteins and then it goes to the lateral side then exocytosed going to the blood. So basically that’s trancytosis. Sometimes you pinocytose your protein and within your tubular cell this is digested breaking it into its component amino acids and these amino acids will go into the blood via their respective carriers or channels. When you say transport maxima, this is carrier dependent. It depends upon energy supply and carriers. With that, these are the substances that will need carriers: Glucose, amino acids, PO4, SO4, Vitamin C, malate, lactate, aceto-acetate, β-hydroxybutyrate. So your transport maxima because of carriers, will exhibit saturation. These substances will require carriers so when saturation is achieved, the rate of transport will be constant. If you increase your substrate but you do not saturate your carriers, it will go up. But if you saturate the carriers, it will be constant. Look at glucose, imagine that the patient is diabetic. If you have so much glucose in the filtrate, carriers will reabsorb only a certain amount of glucose and beyond that, if you further increase glucose, it spills out in the urine so if you get the urine sample, it would contain glucose. Gradient-time limitation depends on the gradient established and the time the fluid is in contact with the epithelium and this is how sodium and bicarbonate are being handled by the kidneys. Just like what we have talked about tubule-glomerular feedback, it depends on the gradient established so if the gradient is high, the rate of reabsorption is faster. What about the time the fluid is in contact with the epithelium? For as long as the filtrate is in contact with your tubular cells, tubular cells will be able to reabsorb as much sodium as possible. If the flow of the filtrate is slow, the fluid is in contact with the epithelium for a longer time and it gives the tubular cells time to reabsorb your solutes. Quantification of Tubular Reabsorption ďˇ Quantification of reabsorption o R = filtered – excreted o RX = (GFR x PX) – (UX x V) For the quantification of reabsorption, reabsorption is the amount filtered minus the amount excreted. So the font with the same color will mean the same thing. The amount filtered is equal to GFR times the concentration of that substance in plasma. For the amount excreted, that’s your urine flow rate times the concentration of that substance in the urine. ďˇ Factors affecting tubular reabsorption o Flow rate o Osmotic pressure of the filtrate o Hormone influence ď§ ADH, aldosterone, ANP, angiotensin II ď§ PTH, Vit. D, calcitonin Here are the factors affecting tubular reabsorption, number one is flow rate – if you increase flow rate, reabsorption rate will decrease. Osmotic pressure of the filtrate – if the osmotic pressure of the filtrate is increased, reabsorption will decrease because your oncotic pressure will attract the fluid. Hormonal influences which can alter reabsorption rate. For example, ADH for water reabsorption; aldosterone for sodium; atrial natriuretic peptide (ANP) will decrease reabsorption; Angiotensin II is said to have properties that will permit sodium reabsorption and of course PTH – vitamin D and calcitonin will control calcium and phosphate handling. ďˇ Quantification of reabsorption o R = filtered – excreted o RX = (GFR x PX) – (UX x V) ďˇ If the filtered load > excretion rate, net reabsorption has occurred ďˇ Reabsorption = Kf x NRF o Kf – filtration coefficient ď§ Permeability ď§ Surface area o NRF = (PI + ∏C) – (PC + ∏ I) ď§ PI : interstitial hydrostatic pressure ď§ ∏C: peritubular capillary oncotic pressure ď§ PC : peritubular capillary hydrostatic pressure ď§ ∏I: interstital oncotic pressure 5 Shannen Kaye B. Apolinario, RMT So the filtered load is greater than your excretion rate, net reabsorption has occurred. So just like glomerular filtration, your Starling forces will also play a role. So this is your Net Reabsorptive Force. At first glance, it looks the same with effective filtering pressure but it is not. Your net reabsorptive force is pro-reabsorptive factors minus your antireabsorptive force so the font with the same color would mean the same thing. For pro-reabsorptive factors, you have your interstitial hydrostatic pressure and peritubular capillary oncotic pressure so they will promote reabsorption. For anti-reabsorptive factors you have your peritubular capillary hydrostatic pressure and interstitial oncotic pressure. Starling’s forces will comprise your net reabsorptive force. You multiply that with Kf, Kf is also the concentration coefficient as far as reabsorption is concerned, you only have permeability and surface area to come into play, mesangial cells are not included because we are now in tubular cells not in the filtering barrier. ďˇ Reabsorption = Kf x NRF o Kf – filtration coefficient = 12.4 ml/min/mmHg o NRF = (PI + ∏C) – (PC + ∏I) = 10 mmHg ď§ PI : interstitial hydrostatic pressure = 6mmHg ď§ ∏C: peritubular capillary oncotic pressure = 32mmHg ď§ PC : peritubular capillary hydrostatic pressure = 13 mmHg ď§ ∏I: interstital oncotic pressure = 15 mmHg ďˇ ďˇ ďˇ ďˇ Reabsorption = 12.4 ml/min/mmHg x 10 mmHg Reabsorption = 124 ml/min GFR = 125 mL/min UO = 1 mL/min Plugging in the values, your filtration co-efficient is around 12.4 and your net reabsorptive force is also 10. To get reabsorption rate, 12.4 x 10 = 124 mL/min. If you will recall your GFR, GFR is 125, reabsorption is 124, to get your urine output, you simply subtract so you now have 1 mL/min and that is now your urine flow rate. ďˇ Reabsorption o Powered by pumps o Back-leak This diagram will show the basic mechanism for reabsorption. You have your filtrate, tubular cell, interstitium or blood. There are two processes: active and passive. Everything starts with the Na-K pump. NaK pump will remove sodium so Na goes into the blood. The concentration of Na inside the cell decreases and you now have a concentration gradient between your filtrate and your tubular cell and that will now power your secondary pump. Na from your filtrate goes into cell via secondary pump, secondary pump is able to transport another substance – substance X such that for every transport of Na, substance X will also be reabsorbed. Your Na will go out into the blood via Na-K pump but substance X will go into the blood via other means. Let’s look at substance Y. Let’s say substance Y is an anion like chloride. Na enters, your tubular cell becomes positive because of Na, your filtrate becomes negative because of substance Y causing an electrochemical gradient powering now the passive transport or reabsorption of substance Y. Na goes into the other side and the anion will also go together with it. Substance X, Na and substance Y are solutes, all of them will go into the blood, all of them are reabsorbed and water also goes along. Solutes will now act as osmotic attractants and water will go through aquaporins and is now reabsorbed. Some substances may pass through paracellular route or in between cells. Some substances when reabsorbed may go back into the filtrate and this is your back-leak and it commonly happens with potassium. Segments of the Nephron ďˇ Reabsorbs 67% of filtered H2O, Na, Cl, K ďˇ Early PCT o Na-H antiport o Na-glucose symport o Na-amino acid symport o Na-P symport o Na-lactate symport o H2O reabsorption o Pinocytosis of CHON That’s how you reabsorb certain substances. Although not all transport mechanisms are shown, the mechanism is the same for reabsorption to all of them. You reabsorb now solutes; of course water will be reabsorbed as well. Whatever amount of solute is reabsorbed, the amount of water that will be reabsorbed is the same. Also in early portions of PCT, pinocytosis of proteins is evident but was not shown. So in here, there is reabsorption of filtered proteins. ďˇ Late PCT o Na-H antiport o Paracellular NaCl reabsorption o H2O reabsorption In the late PCT, this is where further reabsorption of water and reabsorption of chloride will occur. Now let’s go the different segments of the nephron. First, you have your proximal convoluted tubule, PCT is divided into two segments: the early PCT and late PCT. In the proximal convoluted tubule, this is where obligatory reabsorption of substances occurs so the filtered water, electrolytes, proteins, amino acids etc. all of them will be reabsorbed in the PCT. In the early PCT, these are the transport mechanisms present: Na-H antiport, Na-glucose symport, Na-amino acid symport, Na-P symport, Na-lactate symport, H2O reabsorption and Pinocytosis of CHON In this diagram, you have filtrate, cell and blood. Everything starts with Na-K pump powering secondary pump which in this case is the Na-H antiport. Na enters, H exits. H will combine with a filtered anion in the filtrate; your H anion complex can easily enter the tubular cell. Once inside the cell, they will dissociate, H will go back out via antiport whereas your anion will go back into the filtrate via another transport mechanism – your chloride anion antiport. Essentially, H will just go round and round. The anion will also go round and round. The net effect, Cl enters together with Na and you now have a net reabsorption of NaCl. Just like what was mentioned earlier, Na can go into the blood via the pump whereas Cl will go out via other means and in this case, you have your K-Cl cotransport and this is a passive process. Because Cl goes downhill, K will also go on downhill mechanism. Also, NaCl can be reabsorbed via paracellular routes or in between cells. A. In this diagram, here you have filtrate, tubular cell and blood. You have your Na-H antiport. Everything begins with Na-K pump creating a gradient for Na that will power the secondary pump which in this case is the Na-H antiport. Na is reabsorbed in exchange for H. B. In this diagram, here you have your Na-glucose cotransport or SGLT 2. Again it starts with Na-K pump powering the secondary active transport. As Na enters, glucose enters. Na exits via primary glucose whereas glucose will exit via other transport mechanism and this is now your GLUT 2. 6 Shannen Kaye B. Apolinario, RMT ďˇ PCT o H2O reabsorption ď§ 67% of filtered H2O o Solvent drag ďˇ Changes in Na reabsorption influence H2O and solute reabsorption So you reabsorb now solutes in the PCT, of course water will follow. So basically in the PCT, 67% of the filtered water is reabsorbed and here you have aquaporins – water channels. Some solutes are reabsorbed via solvent drag specially via paracellular route. For example, the water that passed through via paracellular route, it can bring with it solutes and changes in solute reabsorption will influence water and solute absorption. You will note that in order for us to reabsorb amino acids, glucose, chloride etc., we need to reabsorb sodium with them. So if the sodium concentration in the filtrate is low, the reabsorption rate of other substances would also be low. So you will note your PCT is the site for obligatory reabsorption so it is not influenced by external factors. PCT will require tons of mitochondria because it needs energy. Take note also that as far as solute reabsorption is concerned in the PCT, there is commensurate reabsorption of water – the amount of solutes reabsorbed is also equal to the amount of water that is reabsorbed. Therefore, what is the tonicity of the filtrate when it exits the PCT? It is isotonic. ď ď ď ď ď Thin: passive reabsorption ď Thick: active reabsorption NKCC2 transporter Na-H antiport Claudin-16 Transcellular, paracellular NaCl reabsorption Ascending limb on the other hand, solutes are reabsorbed. Ascending limb is divided into two segments: thin ascending and thick ascending lim. In the thin ascending limb, passive reabsorption of solutes occurs whereas in the thick ascending limb, active reabsorption of solutes occur. So how does that happen? Looking at the diagram, you have the descending, thin and thick ascending limb. In the thin descending limb, water is reabsorbed and the concentration of the filtrate increases or it becomes concentrated. The solutes now being more concentrated will have a concentration gradient. In the thin ascending limb, NaCl are passively reabsorbed. Renal tubular acidosis – defect in sodium-bicarbonate transport. One of its manifestation is acidosis because bicarbonate is not reabsorbed. Cystinuria – defect in basic amino acid transport therefore there is aminoaciduria. ďˇ Loop of Henle o Reabsorption ď§ Thin descending limb ď 15% of the filtered H2O ď AQP1 Now we go to the loop of Henle. The loop of Henle is divided into three segments or two main segments: the descending and ascending limb. In the thick ascending limb, you have your filtrate, cell and blood. Everything begins in the Na-K pump that will power the secondary active transport and one important transport protein is the Na-K to Cl cotransport. It will transport 4 ions: 1 Na, 1 K and 2 Cl molecules. These four molecules are now reabsorbed, Na goes into the blood via the pump, Cl will go into the blood via some other means or it can go with K. Take note that K back-leaks into the filtrate. When K leaks out into the filtrate, the filtrate is imparted with a positive charge. This positive charge will drive other positively charged ions to be reabsorbed via paracelluar routes through Claudin 16 – a tight junction capable of permitting the passage of Mg or Ca. So other cations are now reabsorbed. Take note that in the ascending limb, water is NOT reabsorbed. To emphasize, in the descending limb, water is the only one that is reabsorbed and in the ascending limb, solutes are the only ones that are reabsorbed. So when the filtrate exits the loop of Henle, the tonicity of the filtrate is hypotonic because in the ascending limb, solutes are removed and the one that is left is water making the filtrate hypotonic so the ascending limb of loop of Henle is said to be a diluting segment because it dilutes the filtrate. Descending limb. Specially in the juxtamedullary nephron, when the loop of Henle enters the renal medulla, it is exposed to a hypertonic medium. In the descending limb of the loop of Henle, water reabsorption occurs. Just like in the diagram, water is the only one that is reabsorbed, there is no solute reabsorption. ď§ 7 Ascending limb ď 25% of the filtered NaCl Shannen Kaye B. Apolinario, RMT Looking at an example of a disorder, you have Barter’s syndrome and you have defects like Na-K-Cl symport that is defective. The manifestations are hypokalemia, hyperaldosteronism and metabolic alkalosis. There is hypokalemia because K is not reabsorbed. Because the Na-K-Cl transport is defective, Na is also not reabsorbed so the Na state in the body decreases. When the Na state of the body is low, the effective circulating volume is also decreased and that activates RAAS. There is alkalosis because aldosterone will reabsorb Na in exchange for H so H spills out in the urine and what is left in the body is bicarbonate. ďˇ Early DCT o Reabsorption ď§ 8% of filtered NaCl ď§ Na-Cl symport We will now go to the DCT. Just like in the PCT, DCT is divided into two segments: the early and the late DCT. In the early DCT, 8% of the filtered NaCl is reabsorbed so again everything starts with the Na-K pump powering the secondary pump. Taken note also that in the early portions of DCT, water is NOT reabsorbed therefore in the early segments of DCT, there is also dilute urine so this is also a diluting segment because water is not reabsorbed. ďˇ Late DCT and Collecting Ducts o ADH ď§ 8-17% of filtered H2O o Aldosterone o Principal cells ď§ Na-K pump-ENaC ď§ Paracellular Cl reabsorption ď§ AQP2, AQP3, AQP4 o Intercallated cells ď§ K-H pump Going now to the late DCT and collecting ducts, the DCT and collecting ducts will be influenced by hormones. As far as antidiuretic hormone (ADH) is concerned, it varies. Without ADH, 8% of the filtered water is reabsorbed and with ADH, 17% of the filtered water is reabsorbed. ADH now will permit the formation of aquaporins. As far as aldosterone is concerned, it will target two types of cell present in the DCT and collecting ducts: the principal cells and the intercalated cells. The action of aldosterone is that it will permit or it will increase the activity of Na-K pump. Increasing the activity of Na-K pump permits faster reabsorption of Na and consequently, K is secreted. What happens to K? Looking at the intercalated cells, there is K-H pump so K exits and enters the intercalated cells via K-H pump in exchange for H. And that’s why if a person has hyperaldosteronism, alkalosis occurs because H spills out. So the late DCT and collecting duct is where facultative reabsorption of water occurs because it is influenced by ADH unlike in the PCT. In PCT, it is obligatory, with or without ADH, 67% of water will always be reabsorbed. In distal renal tubular acidosis, there are different defective transport mechanisms. The manifestations include metabolic acidosis, hypokalemia, hypercalciuria and nephrolithiasis. For Liddle’s syndrome, amiloride-sensitive Na channels. The problem with this is there is decrease in Na excretion so Na stays in the body and consequently, there will be hypertension. For example, if there is defect in DCT, will you expect amino acids in the urine? NO, because amino acids are reabsorbed in the PCT. Take note that as far as mitochondria concentration is concerned, the one that needs the greatest amount of mitochondria is the PCT (not so much with the ascending loop of Henle, DCT and collecting tubules) because in the PCT, there is obligatory reabsorption of substances. Tubular Secretion Tubular secretion is a lot like reabsorption, the only difference is the direction of the substance. ďˇ Any substance ↑ concentration to a greater extent than does inulin is secreted Any substance increasing concentration to a greater extent than inulin is excreted. As what was mentioned earlier, inulin is filtered, not secreted and reabsorbed. For example, if you have 100 units of inulin 8 Shannen Kaye B. Apolinario, RMT excreted and if you have a substance X with a urine concentration of 50, what happened was filtration and reabsorption. If substance X is also 100 units, the substance was filtered, not secreted and not reabsorbed. If substance X is 150, it was filtered and secreted. The same is true for a weak base. You have an uncharged base, it goes into the tubular cell and into the filtrate, H ions are secreted by the tubular cell and H ions will interact with the base so the base now becomes positively charged thereby it cannot go back anymore. So these acids and bases are excreted. Mechanisms for Tubular Secretion One practical application for this is salicylic acid (aspirin) poisoning. In salicylic acid poisoning, the urine has to be alkalinized by giving sodium bicarbonate because when salicylic acid goes into the filtrate, the H ion will interact with the filtered bicarbonate and the salicylate now becomes charged and excreted. ďˇ Active secretion o o ďˇ Transport maxima ď§ Carboxylic, sulfonic acids, hippurate, creatinine, penicillin, thiazide, glucoronides, urological contrast ď§ Organic bases, guanidine, thiamine, choline, histamine Gradient-time limited ď§ H, K Segments of the Nephron ďˇ PCT o Na-H antiport Passive secretion o Diffusion trapping ď§ Weak bases, quinine, quinacrine, chloroquine, NH3 ď§ Weak acids, salicylic acid, phenobarbital procaine, Just like in reabsorption, there are also two basic processes: active and passive transport. Active transport utilizes energy and against a gradient and on the other hand, passive transport is downhill and doesn’t utilize energy. In active secretion, just like in reabsorption, there is also transport maxima and gradient-time limited transport. For transport maxima, it also utilizes carriers and the mechanism is the same. The substances that are being handled by transport maxima are listed above. For gradient-time limitation, just like in reabsorption, the principle is the same. It is also dependent on the time and the gradient and this is how H and K are being handled. For passive secretion, there is diffusion trapping this is how qeak bases, quinine, quinacrine, procaine, chloroquine, NH3, weak acids, salicylic acid, and phenobarbital being handled. So how will diffusion trapping work? We will talk about it in a little while. Looking at the different segments of the nephron, in the PCT, you have your Na-H antiport, Na-K pump powering the secondary active transport, H goes out. H is now secreted. o Secretion of organic anions ď§ cAMP, cGMP, hippirates, urates, bile salts, oxalate, PGE, PGF, ascorbate, folate ď§ Anionic drugs, toxins This diagram shows the basic mechanism for secretion. You have the filtrate, the cell and the interstitium or the blood. Everything starts with the Na-K pump that creates Na gradient powering the secondary pumps. Secondary pumps more often are antiports, so for every Na that is reabsorbed from the filtrate, substance X goes out into the filtrate – Na exchanges with substance X, and the mechanism is the same. Weak acids and weak bases in the blood are uncharged so they are unionized. Because they are unionized, they can easily pass through cell membranes and they go the tubular cell and they go into the filtrate. Once in the filtrate, they will return to their ionic form. For example, you have a weak acid that is unionized; it goes into the tubular cell then to the filtrate. Once in the filtrate, this acid will interact with filtered bicarbonate. The H ion will associate itself with the bicarbonate and the acid now becomes negatively charged. Once the acid becomes negatively charged, it now cannot pass through the cell membrane. This is diffusion trapping – the acid now is trapped in the filtrate. 9 Shannen Kaye B. Apolinario, RMT For organic anions, this diagram shows how organic anions are secreted. Na-K pump is activated so Na exits. With the exit of Na, Na inside the cell decreases powering a secondary pump, the NaDC found in the basolateral membrane which permits the re-entry of Na. The entry of Na is coupled with the entry a-ketoglutarate and that will power another transport mechanism: OAT 1,3. a-ketoglutarate inside the cell increases powering OAT4, a-ketoglutarate goes out. OAT 1,3 is able to pump in organic ion. As far as Na and a-ketoglutarate is concerned, both will just go round. The net effect is the entry of organic anion. This organic ion will go to the filtrate via MRP 2 and OAT 4 which is another transport carrier. This is how organic anions are being handled and listed above are the substances that are handled that way. o ďˇ Late DCT and Collecting Ducts o Aldosterone o Principal cells ď§ Na-K pump-ENaC o Intercallated cells ď§ K-H pump ď§ H pump Secretion of organic cations ď§ Creatinine, dopamine, epinephrine, norepinephrine ď§ Cationic drugs, toxins Let’s now go to cations. The principle is almost the same with cations. Everything starts with the Na-K pump. Because of the primary pump, the inner surface of the cell membrane becomes negatively charged. That negative charge will permit the entry of a cation. Cation will enter via diffusion or through a channel or carrier like OCT. When that happens, concentration of cations inside the cell increases and it goes out into the filtrate via MDR1 or OCTN. OCTN is a hydrogen exchanger and a secondary pump so as the cation exits, H enters. The substances that are handled that way are listed above. ďˇ starts with the Na-K pump powering the secondary pump and H is secreted. Loop of Henle o Thick ascending limb ď§ Na-H transport In the late DCT and collecting ducts, aldosterone will exert its influence. Aldosterone will target the principal cells and intercalated cells. With that, aldosterone increases the activity of Na-K pump. Looking at the principal cell, it will handle K and the intercalated cell will handle H. If the activity of primary pump is increased, principal cells will secrete K. with the influence of aldosterone, as far as intercalated cell is concerned, it will secrete H. That’s the influence of aldosterone and here you have the different transport mechanisms responsible. Quantification of Secretion ďˇ Quantification of secretion o S = excreted – filtered o SX = (UX x V) - (GFR x PX) ďˇ If the filtered load < excretion rate, net secretion has occurred For the quantification of secretion, amount secreted is equal to the amount excreted minus amount filtered. Excreted is equal to urine flow rate times the concentration of substance in the urine. Filtered is GFR times the concentration of substance in plasma. If the filtered load is less that the excretion rate, therefore net secretion has occurred. Glomerulotubular Balance ďˇ In the loop of Henle, secretion does not happen in the descending limb because the only thing that happens is water reabsorption. In the ascending limb, we have Na-H antiport. Everything 10 Shannen Kaye B. Apolinario, RMT ↑ reabsorption rate in respone to ↑ tubular load o Prevents overloading of the distal segments with an ↑ GFR o Prevents large changes in fluid flow in the distal tubules brought about by: ď§ Changes in arterial pressure ď§ Disturbances that would create problems in the maintenance of Na and vol homeostasis Tubuloglomerular balance, this is an increase in reabsorption rate in response to an increase in tubular load – if substance X is increased in the filtrate, reabsorption rate will also increase. For example eating a high carbohydrate meal will increase glucose in the plasma and that consequently increases glucose in the filtrate. So that should cause an increase in the reabsorption rate. This prevents the overloading of the distal segments with an increase in glomerular filtration and prevents large changes in fluid flow in the distal tubules brought about by changes in arterial pressure and disturbances that would create problems in the maintenance of Na and volume homeostasis. Calculation of Reabsorption and Secretion Rates ďˇ ďˇ ďˇ ďˇ Filtered load = GFR x PX Excretion rate = V x UX R = filtered – excreted S = excreted – filtered For the calculation of reabsorption and secretion rates: filtered load is GFR times the concentration of X in plasma; excretion rate is urine flow rate times the concentration of X in urine; reabsorption is filtered minus excreted and secretion is excreted minus filtered. “ Not only so, but we also rejoice in our sufferings, because we know that suffering produces perseverance; perseverance, character; and character, hope. And hope does not disappoint us, because God has poured out his love into our hearts by the Holy Spirit, whom he has given us.” -Romans 5:3-5 GOD BLESS YOU ď 11 Shannen Kaye B. Apolinario, RMT Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine 1D – Batch 2020 Renal Physiology II Urine Formation: Filtration, Reabsorption & Secretion Dr. Ronald Allan Cruz – January 10, 2017 NEPHRON Basic Processes of Urine Formation: ďˇ Glomerular filtration ďˇ Tubular reabsorption ďˇ Tubular secretion w Excretion = Filtration – Reabsorption + Secretion AA EA reabsorption rate. This is typical for many of the electrolytes of the body such as Na, Cl- & etc.. The substance in C is FILTERED but COMPLETELY REABSORBED from the tubules back into the blood. When a urine sample is obtained, substance C should be absent. This pattern occur for some of the nutritional substances such as amino acids and glucose, allowing them to be conserved in the body fluids. The substance in D is FILTERED, however, some remains in the blood so this will have to be SECRETED. It goes out from the peritubular capillaries to go to the renal tubule to be excreted. When a urine sample is obtained, substance D should be present. This pattern is true for organic acids and bases, permitting them to be rapidly cleared from the blood and excreted in large amounts in the urine. Example is creatinine. GLOMERULAR FILTRATION ďź Non-selective as long as small and not negativley charged molecule FILTRATION BARRIER Bowman’s Capsule Peritubular capillaries AA Renal Tubule Filtrate side The substance in A is FILTERED ONLY by the glomerular capillaries, it is not secreted and reabsorbed. When a urine sample is obtained, SUBSTANCE A is present. The excretion rate will be same as the one filtered. A classic example is inulin. The substance in B is FILTERED and PARTIALLY REABSORBED from the tubules back into the blood but notice that substance B is also excreted so when a urine sample is obtained, it will be present. In this case, the excretion rate is calculated as filtration rate – Blood side Filtration Barrier consists of: 1. Capillary endothelium ďź First layer from the blood side ďź Has fenestrations (butas butas) ďź Contains sialoglycoproteins 2. Basement membrane ďź Has several layers o Lamina Rara Interna – 1st layer from the blood side o Lamina densa Escoto, KC // Gloriani, KP 1 of 13 o Lamina Rara Externa The proteins present in the basement membrane are: Trimer of α1-6 collagen IV, laminin, polyanionic proteoglycan, agrin, perlecan, entactin, heparan-SO4, fibronectin Bowman’s Epithelium ďź Has podocytes o Finger like projections o Interdigitate to form slits so there will be slit pores in between ďź Has slit pores/ slit diaphragms ďź It also has sialoglycoproteins Clinical Application ďź 3. When the proteins are destroyed, example during glomerulonephritis such that immune complex will destroy the protein present in the filtration barrier, negative charges is lost ďź Since negative particles are lost, proteins easily leak out. ďź Patients with glomerulonephritis will present with proteinuria. Figure: An electron micrograph of the filtration barrier Characteristics of the Filtration Barrier A. Because of the slit pores and the fenestrations, the filtration barrier has a HIGH PERMAEBILITY, greater than the average capillary bed so the substances can easily pass through. ďˇ 100x more permeable than a regular capillaries B. It has A LOT of NEGATIVE CHARGES ďˇ Negative charge proteins present in the filtration barrier. ďˇ Because of this, plasma proteins that are typically negatively charged are not allowed to pass through the filtration barrier C. GIBBS-DONNAD EFFECT ďˇ Since the plasma proteins are not able to pass through, some positively ions will be attracted to the negative charge of the plasma protiens. ďˇ Some negatively charge small particles like anions are repelled by the plasma proteins At the end of the day, the filtrate is said similar to the plasma, except that it will not contain plasma protein. ďź If plasma Na concentration is 145 mEq/L, the amount of Na present in the Bowman’s space would be the same ďź If the plasma glucose level is 200 mg/dL, the amount of glucose present in the Bowman’s space is 200 mg/dL. This table will show the filterability of several substances present in the plasma. ďź Notice that water, Na, Glucose and inulin will have a filterability of one so they are EASILY FILTERED. ďź As the size of the molecule increases, the filterability decreases simply because of the fenestrations and slit pores that they can’t fit through. In the figure above, molar radius or molecular size is plotted against relative filterabilty. Black line = negatively charged particles Blue line = neutral particles Red line = positive particles Given a specific size (30): ďź A molecule with negatively charge at 30 will have low filterability compared to a molecule that is neutral ďź It also has less filterability compared to positively charged molecule with the same Negatively charged particles are not readily filtered because of the charge of the filtration barrier. Escoto, KC // Gloriani, KP 2 of 13 TWO DETERMINANTS AFFECTING FILTERABILITY 1. Size of the particle 2. Charge of the particle MESANGIAL CELL ďź Mesangial cells can affect filtration rate by regulating the RBF because it can alter the capillary surface size. ďź Has contractile properties o Has cytoskeleton elements that allows them to contract and relax o If they contract, they affect the surface area of the glomerulus, affecting also filtration. ďź Has phagocytic properties ďź Produce matrix and collagen ďź Produce biologically active mediators – affects blood flow to the glomerulus o Vasodilators o Vasoconstrictors PHYSICAL PROPERTIES AFFECTING FILTRATION ďˇ STARLING FORCES – necessary for the computation of effective filtering pressure: Green texts = Pro filtering factors Red texts = Anti filtering factors NORMAL VALUES: PG: 60-70 mmHg ∏G: 32 mmHg (PG + ∏B) – (PB + ∏G) ďź ďź ďź ďź PG: glomerular hydrostatic pressure ď§ Presence of fluids present in the glomerulus ď§ Driven by the pumping action of the heart ∏B: Bowman’s oncotic pressure ď§ Proteins present in the Bowman’s space ď§ They will attract fluid thus facilitating filtration ď§ Said to be ZERO mmHg because proteins are not normally filtered. PB: Bowman’s hydrostatic pressure ď§ Presence of fluid present in the Bowman’s space ∏G: glomerular oncotic pressure ď§ Plasma proteins in the glomerulus Effective filtering pressure = 10 mmHg EFP = (PG + ∏B) – (PB + ∏G) = 60 – 50 = 10 ďˇ ďˇ ďˇ ďˇ PG: glomerular hydrostatic pressure = 60 mmHg ∏B: Bowman’s oncotic pressure = 0 mmHg PB: Bowman’s hydrostatic pressure = 18 mmHg ∏G: glomerular oncotic pressure = 32 mmHg By entering the values, you’ll get an effective filling pressure of 10mmHg. Clinical Application Some diseases can alter or change the Starling Forces ďˇ Glomerulonephritis – can increase Bowman’s Oncotic Pressure (∏B). ďˇ Kidney Stones ďź Urine can’t flow to the ureters ďź Bowman’s Hydrostatic pressure (PB) can increase GLOMERULAR FILTRATION RATE There are two formulas discussed by Dr. Cruz and I don’t know which one will be used ď 1st formula According to Berne and Levy, there is a different effective filtering pressure between the arterial side and the venous side. Look at the figure on the right for the values of the efferent and afferent side. To get the GFR according to Berne and Levy: GFR = Kf[(PG-PB) – σ(πG-πB)] σ – reflection coefficient of CHON – this is equal to one so it does not do anything Albumin – most important plasma protein 2nd Formula – I think this is the one that will be used because it is simpler and this the one used in the previous trans but be reminded that this formula is from Guyton and Hall. GFR = Kf x EFP EFP = Effective filtering pressure Kf = Filtration coefficient = Property of the membrane due to: ďˇ Permeability ďź Glomerulus is 100x more permeable than regular capillary bed due to the fenestrations Glomerulonephritis can affect permeability. Due to the inflammation, the filtering barrier thickens so the permeability decreases, Kf goes down, GFR also goes down. So patients with glomerulonephritis also have oliguria. Escoto, KC // Gloriani, KP 3 of 13 ďˇ Surface area ďź The more number of nephrons, the greater the surface area, the greater the Kf, the greater the filtration rate. Patients that undergone Partial Nephrectomy, a portion of kidney is removed. Some nephrons are also removed, decreasing the surface area, decreasing the Kf, GFR decreases. ďˇ Mesangial cell activity ďź The mesangial cell can either relax or contract affecting the surface area ďź It can elaborate vasoactive substances that can alter Starling Forces 2. IMPORTANCE OF DETERMINING GFR ďź Because GFR reflects renal function, we can know if the patient will have renal failure o If GFR is 25% or below, there is a renal failure o So if we have a normal GFR of 120ml/min, then the patient has 30 ml/min GFR, then he has a renal failure and you are a candidate for dialysis ď§ Application: Kf = 12.5ml/min/mmHg EFP = 10 mmHg ď GFR = 12.5ml/min/mmHg x 10 mmHg ď GFR = 125 ml/min NORMAL VALUES: ď M: 90-140 ml/min ď F: 80-125 ml/min TWO METHODS FOR QUANTIFICATION GLOMERULAR FILTRATION RATE 1. Creatinine estimation ďˇ This is the one normally used in the clinics ďˇ Serum Creatinine will estimate GFR Glomerular Hydrostatic Pressure (PG) ďź Arterial pressure o ↓ pressure: ? GFR o ↑ pressure: ? GFR ďź Afferent arteriole resistance o ↑ resistance: ? GFR ďź Efferent arteriole resistance o ↑ resistance: ? GFR o ↑↑↑ resistance: ? GFR As far as glomerular hydrostatic pressure is concerned: OF Use of Inulin ďˇ The gold standard in determining filtration rate ďˇ This is done by getting the clearance of inulin because it is equal to the GFR ďź INULIN IS FILTERED ONLY, not secreted nor reabsorbed ďˇ Infuse the subject with inulin and allow him to be in steady state HOW IT IS DONE: 1. Remember the clearance method: C=UV/P 2. Get a blood and urine sample, determine the plasma and urine concentration of inulin. 3. Plot the values then compute. Example: Cinulin = (120mg/ml x 1ml/min)/1mg/ml Cinulin = 120ml/min 4. If the clearance of Inulin is 120 ml/min, then it is equal to the GFR Inulin is not normally used in the clinic because of its availability and cost. NOTE: BEFORE ANSWERING BE MINDFUL OF THE PREVIOUS TOPIC 1. 2. What will happen to GFR if arterial pressure decreases? What will happen to GFR if arterial pressure increases? For nos. 1 and 2, remember the RENAL AUTOREGULATORY RANGE: at BP of 90 – 180 mmHg, there will be a constant RBF and GFR. Even though you increase and decrease BP so as long as you are within the auto-regulatory range, RBF will be constant or unchanged so as the GFR. So the answer for nos. 1 & 2 is it depends on the BP. So when you are within the range, GFR is constant. BUT IF BEYOND THE RANGE, GFR IS DIRECTLY PROPORTIONAL TO THE BP. 3. What will happen to GFR if afferent arteriole resistance increases? If the afferent arteriole constrict, then GFR decreases and vice versa. 4. 5. What will happen to GFR if efferent arteriole resistance slightly increases? What will happen to GFR if efferent arteriole resistance is maximally constricted? Escoto, KC // Gloriani, KP 4 of 13 For the efferent arteriole, it has a peculiar phenomenon. ď§ Slightly constricted efferent arteriole such that blood can still flow through, GFR increases because the hydrostatic pressure in the glomerulus will go up. ď§ Maximally constricted efferent arteriole such that blood is not easily allowed to pass through, GFR decreases. ďź Plasma protein will increase in glomerulus because blood can’t pass through the glomerulus ďź When Plasma Proteins increase in the glomerulus, glomerular oncotic pressure increases (remember, this is an anti-filtering factor), this will attract fluid back to the glomerulus. FILTRATION FRACTION ďˇ Extent of fluid loss from the plasma ďˇ The extent to which plasma proteins are being concentrated ďˇ This is the percent of plasma going to the kidney that is filtered ďˇ NORMAL VALUES: 0.15 – 0.22 FF = GFR/Renal Plasma Flow Review of Renal 1: GFR = clearance of inulin RPF = clearance of PAH C= U V / P As blood flows from the afferent to efferent side, GLOMERULAR ONCOTIC PRESSURE GRADUALLY INCREASES. TUBULAR REABSORPTION ďˇ Reabsorption is said to be selective unlike filtration ďˇ Tubular cells will have to select certain molecules to be brought back to the body. To understand the concept of reabsorption: Let’s have a GFR = 125 min/ml ďź Without reabsorption, urine output (UO) would be 178 L/day and this is physiologically impossible ďź NORMALLY, UO IS 1-1.5 L/day so this simply means that substances have to be brought back to the body. The blood flows from afferent arteriole to efferent arteriole and in the glomerulus, filtration will occur. As blood flows through the blood vessels in the glomerulus, blood or plasma is filtered some will remain in the glomerulus to go to the efferent arteriole. If filtration fraction is 0.2, this simply means that 20% of plasma is filtered and the other 80% went through the efferent arteriole. The higher the Filtration Fraction, the more concentrated the plasma proteins become. EXAMPLE: FF = 0.5 vs. FF = 0.2 ďˇ ďˇ If FF is 0.5, this simply means that 50% is filtered and 50% went to the efferent arteriole. Between 0.2 and 0.5, it is the blood with 0.5 FF contains the higher amount of proteins because there is a larger amount of water removed. Table shows the different substances commonly seen in the plasma, the amount filtered, amount reabsorbed and the percent of filtered load reabasorbed. ďź ďź Glucose is 100% filtered and 100% reabsorbed so in urine sample, GLUCOSE SHOULD BE ABSENT In electrolytes, they are not 100% reabsorbed. Some will stay in the urine. BASIC PROCESSES IN TUBULAR REABSOPRTION ďˇ Passive Transport ďź Depends on electrical or concentration gradient ďź This is how H20, Chloride and urea are being handled. ďź Do not utilize energy Escoto, KC // Gloriani, KP 5 of 13 ďˇ Active Transport ďź Needs ATP ďź Involves three processes ďź QUANTIFICATION OF REABSOPRTION THREE PROCESSES OF ACTIVE TRANSPORT 1. Transport Maxima (TM) ďź Carrier dependent transport modes ďź Substances handled by transport maxima: i. Glucose (SGLT, GLUT) ii. Amino acids (Na-Amino acid transporters) iii. Phosphate (PO4), Sulfate (SO4) iv. Vit. C v. Malate, lactate, acetoacetate, β-hydroxybutarate ďź Properties of carrier mediated transport are exhibited: i. Saturation – all of the active sites are filled up by substrate ii. Competition/inhibition – an inhibitor can decrease transport rate iii. Specificity – a transporter can only transport specific molecule CLINCAL APPLICATION When you have DM, blood sugar goes up as high as 300 500 mg/dL. Glucose transporters (SGLT and GLUT) are saturated. If the carriers are saturated, the rate of transport becomes constant at maximum rate. Even if the concentration of glucose increases, transport rate will still be the same because transport maxima is reached. Any excess glucose that is not accommodated by carriers will go out in the urine = GLUCOSURIA 2. Gradient-time limitation ďź Depends on the gradient established and the time the fluid is in contact with the epithelium ďź HCO3 and Na are actively transported this way. High concentration gradient = Faster rate of transport especially for HCO3 and Na. When the flow of the filtrate is fast, rate of reabsorption is low because there is less time for the fluid to be in contact with the tubular cells. Slower flow means more time for the tubular cells to pick up ions 3. Pinocytosis ďź Simplest ďź This is how small polypeptides are being handled When polypeptides are filtered, they are pinocytosed by the cells R = filtered – excreted RX = (GFR x PX) – (UX x V) GFR = Glomerular Filtration Rate Px = Plasma concentration of the substance Ux = Urine concentration of the substance V = urine flow rate. FACTORS AFFECTING TUBULAR REABSORPTION 1. 2. 3. Flow rate ďź If flow rate is fast = reabsorption rate is slow Osmotic pressure ďź If the osmotic pressure of the filtrate is high = reabsorption rate decrease o This is because fluid goes to the filtrate Hormonal influence ďź There is a wide variety of hormones that will affect handling wide variety of substances o ADH = water o Aldosterone = Na and H20 and a little bit of K o ANP & Angiotnestin II = Na and H20 o PTH, Vit. D & Calcitonin = Ca and PO4 If the filtered load > excretion rate, net reabsorption has occurred: ďˇ For example, the filtered load if plasma glucose level is 200 mg/dL = the amount of glucose present in the Bowman’s space will be 200 mg / dL so when you get a urine sample, glucose will be zero. o In this FL = 200 and the ER = 0 so FL is greater, therefore glucose is reabsorbed. COMPUTATION FOR REABSORPTION RATE *this is NOT the same with GRF formula so don’t be confused* R = Kf x NRF Kf = filtration coefficient NRF = net reabsorptive force; this are the Starling forces NRF = (PI + ∏C) – (PC + ∏I) PI : interstitial hydrostatic pressure ∏C: peritubular capillary oncotic pressure PC : peritubular capillary hydrostatic pressure ∏I: interstital oncotic pressure Green texts = Pro reabsoprtion factors Red texts = Anti reabsoprtion factors Escoto, KC // Gloriani, KP 6 of 13 PI : interstitial hydrostatic pressure ďˇ due to the fluid present in the interstitial space ďˇ the point of reference is the fluid going back to the blood; FLUID SHOULD GO BACK TO THE BLOOD ďˇ An increase in interstitial hydrostatic pressure (fluid in interstitial space is large), reabsorption increases. ∏C: peritubular capillary oncotic pressure ďˇ due to the plasma proteins present in the blood vessels ďˇ this will attract fluid back in the blood vessels PC : peritubular capillary hydrostatic pressure ďˇ pushes fluid out into the interstitium ďˇ decreases reabsorption ∏I: interstital oncotic pressure ďˇ proteins present in the interstitial space will attract fluid, so fluid will be going to the interstitial space ďˇ decreases reabsorption PROCESS OF REABSORPTION Filtrate Diagram: Basic process of reabsorption; mechanism which absorption take place. This will help you understand the concept of how do we reabsorb. 1. NORMAL VALUES Reabsorption = Kf x NRF ďˇ ďˇ Kf – filtration coefficient = 12.4 ml/min/mmHg NRF = (PI + ∏C) – (PC + ∏I) = 10 mmHg ďź PI : interstitial hydrostatic pressure = 6mmHg ďź ∏C: peritubular capillary oncotic pressure = 32mmHg ďź PC : peritubular capillary hydrostatic pressure = 13 mmHg ďź ∏I: interstital oncotic pressure = 15 mmHg Reabsorption = 12.4 ml/min/mmHg x 10 mmHg Reabsorption Rate = 124 ml/min URINE OUTPUT 2. 3. 4. 5. Recall that the previous computation for GFR is 125 ml/min. Our Reabsorption rate was 124 ml/min If we SUBTRACT THE REABSORPTION RATE FROM THE GFR, WE WILL NOW GET THE URINE FLOW RATE (V). This is the one used for clearance equation. Everything begins here. 6. V = 1 ml/min 7. Everything begins in the Na-K pump (3 Na out & 2 K in). a. Located at the basolateral side, the Na-K pump brings 3 Na back into the blood and 2 K into the tubular cell. b. Since Na is ACTIVELY being pumped out, the amount of sodium inside the tubular cell decreases. In the filtrate, there are tons Na present (145 mEq/L). By concentration gradient, Na from the filtrate in the tubules will enter the cell via a transporter. a. This transporter, other than Na, it also transports another substance. Example is substance X ďź if substance X is glucose, then that transporter is SGLT2 ďź if substance X is an amino acid, the this is a Na-Amino acid transporter. Na enters and GOES TO THE BLOOD via the Na-K pump Substance X enters. a. Inside the cell, its concentration increases b. In the blood, since it is flowing, X in the blood is less in amount. By concentration gradient, Substance X enters the blood via another transporter. a. This transporter will facilitate the transfer of X in the blood. ďź If substance X is glucose then this is GLUT2 Y will represent an anion, an example is Chloride. a. Once Na is reabsorbed, it will impart positive charge on the blood side and a negative charge on the filtrate side. ďź This will drive an anion to diffuse through and reabsorbed back in the blood (Passive transport) Escoto, KC // Gloriani, KP 7 of 13 8. 9. Na, Chloride, Substance X is reabsorbed. a. This molecules will exert OSMOTIC POTENTIAL, attracting water Water will now be reabsorbed via OSMOSIS Back-Leak *will be discussed in detail later* ďź Sometimes, after reabsorbing a substance, the substance can go back to the filtrate ďź This is exhibited by the yellow arrow in the diagram TUBULAR REABSORPTION IN DIFFERENT SEGMENTS OF THE NEPHRON A. PROXIMAL CONVULUTED TUBULE (PCT) This is where majority of reabsorption occurs – 67% of filtered H2O, Na, Cl & K. Na-K pump located in the basolateral membrane is the key element in proximal tubule reabsorption. ďˇ Early segment of PCT o SGLT2, GLUT2 o Na-H antiport o Na-amino acid symport o Na-P symport o Na-lactate symport o H2O reabsorption o Pinocytosis of CHON Diagram: Everything begins at the Na-K pump. Na goes out to the blood forming a concentration gradient between the filtrate and the cell. This will power the entry of Na. If glucose enters with it then it is the SGLT transporter (as seen in B). Na will go to the blood again via Na-K pump and the glucose will go via the GLUT2 transporter. In the first half of the PCT, Na is mostly reabsorbed together with HCO3 and organic solutes than Chloride. This will cause a lower concentration of glucose and amino acids when it enters the late PCT. ďˇ Late segment of PCT o This is where Chloride and H2O will be reabsorbed. o Na-H antiport, Cl-anion antiport o Paracellular NaCl reabsorption o H2O reabsorption ď§ Reabsored solute exerts osmotic potential attracting water. Paracellular reabsorption of NaCl Diagram: 1. Everything begins with the Na-K pump. As Na goes into the blood, this will drive Na-H exchanger / Na-H antiport (NHE3). 2. This NHE3 will allow Na to enter the tubular cell in exchange for H+ to go out to the apical surface. 3. In the filtrate, H+ will complex with an anion. 4. The H-anion complex has neutral charge so it can easily diffuse to the tubular cell due to concentration gradient. 5. Inside the cell, H-anion complex will dissociate ( H+ and anion) 6. The dissocitated H+ from the complex will be acted again by the NHE3 (H+ is recycled) 7. Anion will go out of the cell in exchange for a Cl via the Cl-anion antiport to maintain electrical neutrality. 8. The net transport of H+ and anion is zero (paikot ikot lang) 9. At the end, Na is reabsorbed and goes back into the blood via Na-K pump. 10. Chloride has been reabsorbed and it will go into the blood via the K-Cl symporter / cotransporter. Looking at H20 Reabsoprtion ďˇ Around 67% of filtered water will be reabsorbed Transcellular reabsorption of H20 WATER REABSORPTION ROUTE: 1. Transcellular route 2. Paracellular route SOLVENT DRAG – sometimes passages are large enough such that solute can be reabsorbed with water Changes in Na reabsorption influence H2O and solute reabsorption TAKE NOTE: Filtrate entering the Loop of Henle is ISOTONIC or ISOOSMOTIC B. LOOP OF HENLE ďˇ Descending limb of LOH o Water reabsorption ONLY (15% of filtered H2O) o Via Aquaporin1 (AQP1) in the thin descending limb Escoto, KC // Gloriani, KP 8 of 13 ďˇ Ascending limb of LOH o Only Solutes are reabsorbed (25% of filtered NaCl) o There are two segments: ď§ Thin ascending limb – passive reabsorption ď§ Thick ascending limb – active reabsorption Passive reabsorption in the thin ascending limb ďź Recall that in the descending limb, water is removed via osmosis ďź The concentration of the filtrate increases ďź As it progress in the loop, and as it ascends in the thin ascending limb, there high concentration of solute that will drive passive reabsorption. Active reabsorption in the thick ascending limb ďź NKCC2 is the important transporter o Na-K-2Cl symporter ďź Na-H antiport ďź Claudin-16 ďź Transcellular, paracellular NaCl reabsorption 4. 5. 7. Cl will go to the blood via K-Cl cotransporter. K has two fate: ďź It can go to the blood: K-Cl cotransporter ďź It can go to the filtrate: K leak channel (back leak) When K goes back to the filtrate, the filtrate becomes positively charged The positive charge in the filtrate will drive the reabsorption of other cations through CLAUDIN-16 ďź Remember that the positive charge of the filtrate is the IMPORTANT driving force for several cations (Na, K, Ca++ & MG++) to be reabsorbed through this channel. ďź This is paracellular pathway C. DISTAL CONVULUTED TUBULE (DCT) ďˇ Early segment of DCT o Reabsorption of Na, Cl and Ca o 8% of filtered NaCl o Na-Cl symport o Water is not reabsorbed / impermeable to water 6. NKCC2 CLAUDIN-16 The Ascending limb of LOH and early segment of DCT are the DILUTING SEGMENTS OF THE NEPHRON. Through this segments solutes are only reabsorbed So if solutes are taken out, water is only left in the filtrate so that is why the diluting segment. Figure: transport mechanisms for reabsorption in the thick ascending limb of LOH 1. 2. 3. Everything begins with the Na-K pump, creating a Na gradient that will power the NKCC2 transporter. Na enters together with two Cl, and one K ions. ďź Four ions are reabsorbed through this transporter Na again will go to the blood via that Na-K pump ďˇ Late segment of DCT and Collecting Tubule o Final modification of urine o This segments are responsive to hormones: ď§ ADH – water reabsorption in the DCT and CT increases up to 8 -17% ď§ Aldosterone – if present, modification of K & Escoto, KC // Gloriani, KP 9 of 13 o o handling of H and HCO3 happens Facultative reabsorption in these segments because it needs the presence of ADH for H2O reabsorption This is also composed of two cells: ď§ Principal cells ďź Primarily handles Potassium ďź Affected by aldosterone ďź Na-K pump-ENaC ďź Paracellular Cl reabsorption ďź AQP2, AQP3, AQP4 ď§ Intercalated cells ďź Affected by aldosterone ďź K-H pump / antiporter ďź H pump 5. This concentration gradient is greater than the amount of K in the filtrate so it goes now to the filtrate. Hyperaldosteronism will cause the patient to have hypokalemia because K keeps on going out on the urine. How do intercalated cells work in the presence of Aldosterone? 1. 2. 3. 4. For every K that enters from the filtrate, H will go out to the filtrate. If aldosterone is present and the activity of the Na-K pump increases, more K goes out. And if more K is present in the filtrate, then the K-H antiporter can reabsorb more K in exchange for H+ H+ is excreted Hyperaldosteronism will cause the patient to have alkalosis because of the loss of H+. So in summary, Hyperaldosteronism will manifest in the patient as: ďź Hypokalemia ďź Alkalosis TUBULAR SECRETION This is similar to reabsorption BUT OPPOSITE IN DIRECTION. ďˇ How do principal cells work in the presence of Aldosterone? 1. 2. 3. 4. Aldosterone increases the number and activity of Na-K pump If the pump activity increases, more Na is reabsorbed and more K is pumped into the cell. Because of this, more Na is reabsorbed from the filtrate then it goes into the blood For K, its concentration gradient inside the cell increases due to the increased activity of the pump Any substance ↑ concentration to a greater extent than does inulin is secreted o Example that if there is a particular substance and a urine sample is obtained, if its urine concentration is greater than inulin but they have the same plasma concentration, then this substance is said to be excreted. BASIC PROCESSES IN TUBULAR SECRETION 1. Active secretion ďˇ energy / ATP dependent 2. Passive secretion ďˇ Not energy / ATP dependent ďˇ Process is DIFFUSION TRAPPING Two types of Active Secretion 1. Transport Maxima ďˇ Utilizes transporters / carriers ďˇ Substances handled by transport maxima: i. Carboxylic, sulfonic acids, hippurate, creatinine, penicillin, thiazide, glucoronides, urological contrast ii. Organic bases, guanidine, thiamine, choline, histamine Escoto, KC // Gloriani, KP 10 of 13 2. Gradient-time limitation ďˇ Depends on the concentration gradient and flow rate ďˇ Substances handled: i. H+ ii. K+ DIFFUSION TRAPPING ďˇ A passive secretion process ďˇ Substances handled: i. Weak bases, quinine, quinacrine, procaine, chloroquine, NH3 ii. Weak acids, salicylic acid, phenobarbital BASIC PROCESS OF SECRETION 6. Charged particles can’t cross the cell membrane so this negatively charged particles can’t cross so it will be excreted. a. this is DIFFUSION TRAPPING For Weak Base: 1. If you have, NH3 (Ammonia) 2. The weak base can easily cross the membrane because it is neutral 3. However, when it reaches the filtrate side, it will encounter a H+ 4. H+ binds to the weak base making the molecule positively charge. 5. After binding to a molecule, it can’t cross the membrane thus it is secreted and excreted CLINICAL APPLICATION Filtrate Diagram: General mechanism for secretion 1. 2. 3. 4. Everything begins with a pump ďź It does not have to be the Na-K pump At any case, Na is transported to the blood in exchange of substance X Substance X in the blood will increase in concentration Substance X can go into the filtrate via another transporter ďź A classic example is K. So when K is secreted, a pump will bring K into the cell (Na-K pump) then it goes out into the filtrate. Management of Salicylate toxicity: (too much aspirin during failed suicide attempt) ďˇ Too much aspirin will make the patient experience metabolic acidosis ďˇ If salicylates are high in the blood, intravenous HCO3 is given. ďˇ By giving HCO3, it will be filtered ďˇ As salicylates diffuses through the cell membrane going to the filtrate side, it will encounter the HCO3 ďˇ It will give off its H+ becoming negatively charged then it can’t cross the membrane ďˇ Salicylates are now secreted then secreted. TUBULAR SECRETION IN THE DIFFERENT SEGMENTS OF THE NEPHRON A. PROXIMAL CONVULUTED TUBULE ďˇ Na – H antiporter i. Everything begins with a Na-K pump powering the secondary active transport PASSIVE SECRETION ďˇ Handling of weak acids, weak bases and some anti-malarial drugs ďˇ Refer to the diagram above for discussion For Weak Acid: 1. Acid in the blood is neutral and it can easily cross the cell membrane and it will go out into the filtrate 2. Once in the filtrate, the weak acid will encounter a filtered HCO3 ion 3. Once HCO3 is present, the acid will give of its H+ 4. H+ will go the HCO3 to be buffered 5. Acid now becomes negatively charged and it can no longer cross the cell membrane. Escoto, KC // Gloriani, KP 11 of 13 ďˇ Secretion of organic cations i. Creatinine, dopamine, epinephrine, norepinephrine ii. Cationic drugs, toxins 1. 2. 3. 4. 5. 6. 7. Diagram: How organic cations are secreted 1. 2. 3. 4. 5. ďˇ Everything begins with Na-K pump imparting a negative charge within the cell ďź This is because 3 positively charge Na ions goes out compared to taking in 2 positively charge K ions The negative charge inside the cell will attract a cation from the blood A cation can easily diffuse through or be transported via organic cation transporter (OCT) The number of organic cations in the cell increases; fewer organic cations in the filtrate making a concentration gradient empowering the organic cations to go to the filtrate The organic cations can now go into the filtrate via two transporters: ďź OCTN ďź Multi drug resistant protein 1 (MDR1) 8. Everything begins with Na-K pump. ďź More Na out, less Na inside the cell ďź This will empower Nadicarboxylate transporter Na now a tendency to come inside the cell via NaDC transporter As Na enters, NaDC transports along αketoglutarate with it. The amount of α-ketoglutarate increases inside the cell and less in the blood ďź This will power Organic Anion transporter (OAT1,3) This OAT1,3 will now transport αketoglutarate back into the blood in exchange for an organic anion. ďź So basically, α-ketoglutarate is just going back and forth from blood to cell The net effect is that Na is reabsorbed and organic anion enters the cell. Inside the cell, the anion concentration increases and less is present is in the filtrate ďź Another concentration gradient This will drive the anion to go into the filtrate via: ďź Organic anion transporter 4 (OAT4) ďź Multi-drug resistant protein 2 (MRP2) B. LOOP OF HENLE ďˇ Secretion ONLY occurs at the thick ascending limb ďˇ Na-H antiporter C. LATE DCT and COLLECTING DUCTS ďˇ Aldosterone ďˇ Principal cells i. Na-K pump-ENaC ďˇ Intercalated cells i. K-H pump ii. H pump Secretion of organic anions i. cAMP, cGMP, hippirates, urates, bile salts, oxalate, PGE, PGF, ascorbate, folate ii. Anionic drugs, toxins Diagram: How Organic anions are secreted. This is discussed on the part of reabsorption of DCT so go back to it. Escoto, KC // Gloriani, KP 12 of 13 QUANTIFICATION OF SECRETION S = excreted – filtered SX = (UX x V) - (GFR x PX) So secretion is the amount secreted minus the amount filtered. *binaligtad mo yung formula ng reabsorption* If the filtered load < excretion rate, net secretion has occurred REVIEW: If the filtered load > excretion rate, net reabsorption has occurred and R = filtered – excreted SUMMARY OF FORMULAS FOR REABSORTION AND SECRETION RATES Filtered load = GFR x PX Excretion rate = V x UX R = filtered – excreted S = excreted – filtered GFR = Kf x EFP(starling forces) V = Filtration Rate – Reabsorption Rate GLOMERULARTUBULAR BALANCE ďź An increase in reabsorption rate with an increase in filtered load ďź If you increase the filtered load, reabsorption rate is also increased BUT PERCENT REABSORBED REMAINS THE SAME ďź This will prevent the overloading of the distal segments with an increase in GFR o Most particularly for Na because if GFR is increased, the filtered load of Na also increases and in the late portion of LOH, there is the macula densa o It is sensitive to Na concentration and this glomerulartubular balance will prevent large changes in fluid flow going to the distal segments by: ď§ BP ď§ Disturbances that would create problems in the maintenance of Na and volume homeostasis Example: Na is 99% reabsorbed. Filtered load is 100 Na units (100 units of Na is filtered) How much Na is reabsorbed? ďˇ 99 units of Na Base on glomerulartubular balance, if filtered load is increased, reabsorption rate increases. This is exemplified in this example: Filtered load is 1000 Na units (1000 units of Na is filtered) How much Na is reabsorbed? ďˇ 990 units of Na because 99% is still the % reabsorbed. IT IS ONLY THE REABSORPTION RATE THAT IS CHANGING NOT THE PERCENT REABSORBED DESPITE THE CHANGE IN FILTERED LOAD. Escoto, KC // Gloriani, KP 13 of 13 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology June 16, 2014 Section 1D INJURY/DAMAGE TO THE NERVE - Results to death or degeneration - Some can undergo regeneration mostly happening in the PNS (about 1mm per day) o Growth factors o Plasticity (in the CNS) – remodeling of neurons but alters the behavior of the neuron **Problems in the reflex arc = problems w/ sensation and problems in the response of the body to changes in the env’t MUSCLE PHYSIOLOGY – physiology of effectors particularly of the skeletal muscles Motor neurons/somatic nerves: control the activity of skeletal muscles Neuromuscular/neuromyal/myoneural junctions: terminal end of the motor nerve and the muscle; also considered as a synapse *Motor nerves originate from the ANTERIOR/VENTRAL HORN of the spinal cord. The anterior horn is responsible for generating the impulses of action potentials transmitted by the motor nerves towards the muscle, therefore activating the muscle making it undergo CONTRACTION. *When the motor nerve is destroyed, the muscle undergoes paralysis. *Impulses activating the ventral horn come from the cerebral cortex [primary motor cortex in the frontal lobe: FRONTAL AREA IV/pre-central gyrus] via the corticospinal tract. When motor nerves are activated, entry of extracellular Ca++ ions is observed resulting to the release of neurotransmitters towards the neuromyal junction (REMEMBER NERVE PHYSIOLOGY). • Motor unit - motor neurons connected to the muscles via the muscle fibers MUSCLE TISSUE ORGANIZATION 1. Muscle bundle – made up of muscle fascicles covered by the EPIMYSIUM 2. Fascicle – bundle of fibers covered by PERIMYSIUM 3. Muscle fibers – muscle cell; bundle of myofibrils covered by ENDOMYSIUM/SARCOLEMMA 4. Myofibrils – made up of sarcomeres 5. Sarcomere – made up of interdigitating myofilaments; arranged IN SERIES - The muscle serves as the post-synaptic area. The communication is mostly chemical. - ACETYLCHOLINE: major neurotransmitter - NICOTINIC RECEPTORS: predominant receptors a. Nicotinic 1 [N1] – present in end-plate b. Nicotinic 2 [N2] • End-plate potential – local potential in muscles; happens when the muscle is exposed to a subthreshold potential leading to muscle contraction DULAY, AC 1 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology June 16, 2014 Section 1D MYOFILAMENTS 1. Actin – thin filament - series of G actin molecules; directly attached to the Z disc by actinin and cap Z 2. Myosin – thick filament - series of light and heavy meromyosin - held in position at the center of the sarcomere by titin by firmly connecting the Z disc to the M lines Z disc – boundary of the sarcomere M line – center line of the sarcomere SLIDING FILAMENT MODEL OF CONTRACTION shortening of the muscles as an effect of muscle activation resulting from the ‘sliding’ motion of the actin filaments titin is a collapsible protein allowing actin to slide towards the M line >> shortening of sarcomere - during relaxation, actin moves back to its original position *The muscle does not lengthen when it relaxes, it only returns to its RESTING LENGTH. *When the muscle is inactive (polarized), it is RELAXED. There is no interaction seen between actin & myosin because the TROPONIN-TROPOMYOSIN COMPLEX blocks the myosin-binding site present on the actin filament. *Intracellular Ca++ ions are required to expose the myosin-binding sites *Muscle activation causes the release of stored Ca++ ions and they will bind with the troponin molecule, specifically Troponin C, moving the troponintropomyosin complex exposing the myosin-binding sites. DULAY, AC *Myosin, utilizing the myosin heads, can now interact with the actin filaments by pulling the actin towards the center of the sarcomere developing POWER STROKES or the swiveling motion of the myosin heads requiring the breakdown of ATP IN NORMAL CONDITIONS… Myosin filaments are normally surrounded by six (6), regularly arranged actin filaments There are about 600 myosin heads per thick filament One myosin head can interact with almost two (2) actin molecules (1:1.8) When the muscle is stimulated and there is maximal stimulation, not all myosin heads are able to interact with the myosin filaments; only 2040% of the total myosin heads interact with the myosin filaments during maximal activity of the muscle TROPONIN-TROPOMYOSIN COMPLEX Troponin 1. Troponin I – when the muscle is inactive, it allows the troponin-tropomyosin complex to stay on top of the myosin-binding sites 2. Troponin C – molecule that interacts with Ca++ ions 3. Troponin T – responsible for the firm attachment of the tropomyosin to the actin filament If Ca++ ions are released from the muscle and interacts with Troponin C, it decreases the inhibitory function of Troponin I. 2 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology June 16, 2014 Section 1D Ca++ sensing receptors present in the sarcotubular system – control the activity of voltage-gated Ca++ channels in the cisterns 1. Dihydropyridine receptors – transverse tubules 2. Ryanodine receptors – sarcoplasmic cisternae • Muscle twitch: simplest response of a muscle towards a single stimulation; contractionrelaxation of a muscle MUSCLE CONTRACTION • Normal or healthy motor nerves control the activity of the skeletal muscle. When the nerve is activated, an action potential is generated that activates the muscle. The end-plate of the sarcolemma of the muscle fiber receives the activity. • Motor nerves release Ach, a chemical agent, that interacts with the nicotinic receptors present on the end plate. Ligand-gated Na+ channels are activated upon muscle activation. End-plate potential, therefore, is developed and this can undergo summation if there is continuous transmission of Ach towards the endplate, eventually generating an action potential. • The TRANSVERSE TUBULES & the SARCOPLASMIC RETICULUM (SARCOTUBULAR SYSTEM) are the conducting structures of the muscles used to transmit the action potentials from the endplate to the myofibrils. • T-tubules are connected to the sarcolemma. The invaginations of the sarcolemma allow the action potentials to enter the T-tubules. The T-tubules are directly connected to the SR as well. The sarcotubular system is directly in contact with the sarcomeres. • Upon entrance of the action potentials in the T-tubules, the terminal end/CISTERN of the SR is activated. Ca++ ions are found at the cisternae. Interaction of myosin heads with actin filaments is termed as CROSS-LINKAGE FORMATION. This allows the myosin heads to develop power strokes. The muscle develops tension therefore. **When a muscle develops force, it also develops tension. DULAY, AC STAGES 1. Latent Period – development of action potential; corresponds to the absolute refractory period of the action potential; muscle is not excitable Calsequestrin: protein responsible for holding onto the Ca++ ions in the sarcoplasmic cisternae when the muscle is inactive. Once action potentials reach the terminal ends of the SR, calsequestrin activity decreases causing them to let go of the Ca++ ions that will initiate muscle activity. Effective transmission of action potentials are made possible by the TRIAD arrangement of the T-tubules and SR, where one T-tubule is bound by two sarcoplasmic cisternae. Decreased activity of calsequestrin allows the Ca++ ions to move towards the actin filament where the TropC is, thus removing the inhibitory effect of TropI thereby developing power stroke. Note that energy is required for this activity. ATP is normally stored in the myosin heads in the muscles. The myosin heads also possess the enzyme ATPase. 2. Contraction Period – muscle is at the relative refractory period; muscle is back to normal excitability in the later part of the contraction period • Tetanic contraction: muscle is stimulated while it is still in the contraction period • Incomplete tetanus: let the muscle undergo relaxation before applying a second stimulus 3 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology June 16, 2014 Section 1D 3. Relaxation Period When muscles relax, they simply return to resting length. The energy in the muscle is stored in the myosin heads. The cessation of the action potential will allow the calcium ions’ release to move away from TropC. TropI activity increases that results to the covering of the myosin-binding sites by the troponin-tropomyosin complex, ending the myosinactin interaction. Ca++ ions return to the cisterns. This requires energy since it is an active transport. They are pumped backed to the terminal cisterns using the Ca-Mg ATPase. The antiporter used is Sarcoplasmic Endoplasmic Reticulum Calcium ATPase (SERCA). DULAY, AC 4 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology Part 2 June 22, 2014 Section 1D SERCA: responsible for returning Ca ions back to the terminal cisterns - Ca++ pump, requires energy SARCOMERE STRUCTURE A band: dark bands; total length of the myosin filament including the peripheral ends with actin filaments I band: light band; 2 adjacent sarcomeres devoid of myosin H zone: area not having actin, purely myosin *It is the I band and the H zone that undergoes shortening **Mg+ is required for the immediate hydrolysis of ATP during the development of power strokes/crossbridge formation. **A resting muscle utilizes ATP to maintain RMP (Na-K exchange pump). Rigor mortis: Permanent formation of actin-myosin complex after death Continuous ATP expenditure = continuous production of heat 1. Resting heat – generated at rest; Na-K exchange pump 2. Initial heat – heat produced in excess of resting heat during contraction - Activation heat - Heat of shortening 3. Recovery heat – generated by the metabolic processes that restore the muscle to its precontraction state 4. Relaxation heat – extra heat in addition to recovery heat produced when a muscle returns to its resting length Heat production is greatest during muscle contraction. Latent period – ARP Contraction period – RRP; muscle is excitable Relaxation period – back to normal excitability DULAY, Arman Carl TETANUS: muscle responding while it is in the period of contraction; a form of temporal summation/wave summation/frequency summation - exposure of muscle to frequent stimulation 1. Incomplete – muscle is stimulated when it is about to relax; periods of relaxation are observed - increasing frequency of stimulation 2. Complete – stimulating the muscle while in the state of contraction; fused tetanus - not allowing the muscle to relax Tetanizing frequency: high frequency of stimulation; frequent release of Ach = continuous generation of end-plate potentials QUANTAL SUMMATION: exposing muscles to gradually increasing stimulus intensity >> gradual increase in the magnitude of response - graded response or multiple unit summation - explained by recruitment of motor units 1 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology Part 2 June 22, 2014 Section 1D Size principle: recruitment starts with the slower, weaker fibers and later on, the bigger, faster fibers Maximum response = activation of all muscle fibers TYPES of MUSCLE FIBERS 1. Slow-twitch – initially activated; weaker, small motor units become more vascularized when frequently stimulated for stamina and endurance The response of a slow-twitch fiber is already its maximum response 2. Fast-twitch – bigger, faster, stronger fibers Hypertrophy: increase in size Hyperplasia: increase in number of fibers Angiogenesis: formation of blood vessels Greater length-less tension…why? Normally, an ideal space should be present in the region of the myosin (M line) during rest. When the sarcomere is stretched, actin filaments are pulled away from each other (away from the myosin filament). For the muscle to react, the myosin heads should interact with the myosin filamanets. Lesser myosin heads are able to effectively interact with the actin filaments if they are pulled away from each other. If there is excessive stretch, actin filaments are really moved away from myosin, the developed tension is equal to zero. Less length-less tension… why> Overlapping of actin filaments is observed during compression of the sarcomere. Some actin filaments are covering other acting filaments. The myosin heads are not able to interact with all the available myosin-binding sites. Maximal intensity: initial maximum response of a muscle Submaximal: summation is observed Supramaximal: response is siimlar to maximal LENGTH-TENSION RELATIONSHIP Ideal length of the muscle = resting length When muscle is stimulated at lesser ideal resting length, there is less development of tension/force/pressure DULAY, Arman Carl FORCE-VELOCITY RELATIONSHIP As you increase the load, the velocity of muscle response decreases. Effect of increasing load to work performance: A change in distance should be observed. No load=no work Lighter load=greater work Increasing the load during maximum work will result to decrease in muscle performance 2 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology Part 2 June 22, 2014 Section 1D Isometric: muscle contracting without load; no change in length; static response; no work done; also observed when trying to lift a very heavy load Ex. Maintenance of posture Isotonic: work performance during contraction with a change in distance a. Concentric: increasing work; lighter load b. Eccentric: decreasing work heavier load Isotonic contractions utilize more ATP but are more efficient. Isokinetic: constant rate of activity; essential in the development of muscles - Dystropin: allow firm contact with intracellular structures and extracellular components present in the muscle fibers maintains normal shape of muscle loss of dystropin results to dystrophy: muscle rupture Fatigue: if there is continuous activation of the muscle; muscle performance gradually decreases - no change in frequency & intensity Dev’t of Fatigue - Factors: - there is a decrease of available energy source - body’s protective response to limit muscle activation and prevent injury a. ATP b. Creatin phosphate c. Glycogen - increase in body temperature - increase of lactic acid concentration due to anaerobic metabolism - continuous activation of motor neurons - TropC insensitivity - Increase ADP - Leaky channels: Ca & K out of the cell - Lack of Ach - Free radicals *Treppe: increasing magnitude of contraction with same intensity of stimulation; pre-fatigue Aerobic activities: utilizes glycogen and fats in the presence of O2 Anaerobic activities: glycogen DULAY, Arman Carl 3 of 4 FAR EASTERN UNIVERSITY – DR. NICANOR REYES MEDICAL FOUNDATION Physiology – Dr. F.C. Barbon Muscle Physiology Part 2 June 22, 2014 Section 1D DULAY, Arman Carl 4 of 4 Renal Physiology III: Regulation of Plasma and Water Volume, and Osmotic Equilibrium and Optimal Ionic Balance in the Plasma (Ronald Allan Cruz, MD) Regulation of Plasma and Water Volume Plasma and Water Volume As what we’ve been discussing, the job of the excretory system is to maintain homeostasis. This has a plasma osmolality of 282 mOsm/L. So the job of the excretory system first and foremost is to maintain plasma osmolality of 282 mOsm/L. With that, having a wide variety of intake in the diet, it is now the job of the kidneys to conserve fluid and excretes solutes. We’ve already mentioned that in the maintenance of homeostasis what is more important is what we excrete, not what we take in so it is the job of the kidneys is to excrete solutes. ďˇ Kidneys o Conserve fluids o Excrete solutes o 50-1400 mOsm/L urine o Sp gr: 1.002-1.400 o UO: 0.5-1 ml/kg/min ďˇ Blood: 5L o Plasma: 3L ď§ 282 mOsm/L o Formed elements: 2L plasma osmolality is isotonic, but the blood volume is low, ADH will still be released. The job your ADH is for water reabsorption particularly in the DCT and collecting ducts. It promotes the synthesis of aquaporins for water reabsorption but other than aquaporins, there are also other transport mechanisms that will increase. You have your UT-A1, UT-A3 so these are your urea transporters, your NKCC2 (sodium-potassium to chloride transporter), sodium-chloride symporter, and ENaC (epithelial sodium channel). All of these will promote solute reabsorption and with solute, water will go along with them. In the antero-ventral portion of the 3rd ventricle, this is where your osmoreceptors reside so they will indirectly detect plasma tonicity. When plasma tonicity increases, it will affect the tonicity of the cerebrospinal fluid such that water within the CSF will go out into the vascular compartment so the tonicity of CSF increases. Your CSF surrounds the omoreceptors so when its tonicity increases, water inside the osmoreceptors will go out and the osmoreceptors will shrink. When your osomoreceptors shrink, they will now stimulate your supraoptic and paraventricular nuclei for the synthesis of ADH and they will stimulate your posterior pituitary for the release of ADH. Other important receptors found in within the vascular system, you have your baroeceptors and your cardiopulmonary reflex whose job is to detect blood volume or pressure. Other important structures in the CNS, you have your subfornical region and organum vasculosum of lamina terminalis and their primary function is to regulate thirst. Here you have the range of urine osmolality, it could be as low as 50 mOsm/L so that’s a dilute urine, having a specific gravity of 1.002 or it can be concentrated having an osmolality of 1,200-1,400 mOsm/L and a specific gravity of 1.400. With specific gravity, this is a comparison of the solute concentration of a particular fluid with plasma so if the specific gravity of a fluid is 1, it is identical with plasma. This is your urine now and with the function of the kidney, urine output averages to around 0.5-1 mL/kg/min. So the job of the kidney is to conserve fluids and excrete solutes so that plasma osmolality is maintained at 282 mOsm/L. Antidiuretic Hormone ďˇ ďˇ ďˇ ďˇ Produced in the supraoptic nuclei and paraventricular nuclei Released by the posterior pituitary o ↑ plasma tonicity o ↓ blood vol ↑ H2O reabsorption o ďŁ AQP2 o ďŁ UT-A1, UT-A3, NKCC2, Na-Cl symporter, ENaC AV3V o Osmoreceptors o Median preoptic nucleus ď§ Baroreceptors, cardiopulmonary reflexes o Subfornical region o Organum vasculosum of the lamina terminalis One of the more important hormones that will control osmolality or plasma osmolality is your ADH or antidiuretic hormone produced in the supraoptic and paraventricular nuclei within the hypothalamus. Your ADH now via your axonal transport will go to the posterior pituitary for storage and release. So the site where ADH synthesis occurs is within the hypothalamus but storage is in your posterior pituitary and so is its release. The two stimuli that will trigger release of ADH is at least 1 percent increase in plasma osmolality or a 10% decrease in blood volume or blood pressure. On a day to day basis, plasma osmolality supersedes blood volume. Just like now, under physiologic conditions, the release of ADH is more sensitive with regard to increase in plasma tonicity so if the plasma osmolality increases, ADH is released. However during pathologic states like shock or haemorrhage, a drop in blood volume supersedes plasma osmolality. Meaning to say, even if 1 Shannen Kaye B. Apolinario, RMT So here you have your hypothalamus. When magnified, you have your osmoreceptors. Once plasma tonicity increases, CSF tonicity increases, osmoreceptors will detect tonicity. They will now stimulate supraoptic and paraventricular nuclei for the synthesis of ADH and subsequent release of ADH from posterior pituitary. ADH now is released targeting DCT and collecting ducts for the reabsorption of water. Take note also you have your baroreceptors and cardiopulmonary receptors that will in turn stimulate your supraoptic and paraventricular nuclei. In this table, you have here the stimuli that will either increase or decrease ADH release. So for ADH release, 1% increase in plasma osmolality or at least a 10% drop in blood volume or blood pressure. In the decrease for ADH, it is the opposite. You also have various drugs that will either increase or decrease ADH release. ďˇ ADH: regulates plasma osmolality ADH promotes reabsorption of water, aldosterone promotes reabsorption of sodium. This is a common misconception among medical students that because ADH reabsorbs water, students would initially think it will regulate volume. Since aldosterone reabsorbs solutes, it will regulate tonicity. Actually, it is the opposite. The job of ADH is to regulate tonicity and the job of aldosterone is to regulate volume. Why? The primary stimuli for ADH is an increase in tonicity so we need to reabsorb water in order to bring tonicity back to 282 mOsm/L, it is its only job. The job of aldosterone is to reabsorb solutes but together with solutes, you have corresponding reabsorption water so basically you are reabsorbing isotonic fluid. So ADH regulates tonicity whereas aldosterone regulates volume. A. This is plasma osmolality plotted against plasma ADH. Take note that when plasma osmolality is 280 or 282 mOsm/L less, release of ADH is zero. However, beyond 280 or 282 mOsm/L, as you increase plasma osmolality, ADH secretion increases. In this diagram, here you will take note the action of ADH when water intake is low. So when water intake is low, plasma tonicity increases stimulating now the osmoreceptors. Your osmoreceptors will then trigger ADH release and together with that, you have stimulation for thirst. Your ADH will target the DCT and collecting ducts for the production of aquaporins as well as production of other transport mechanisms promoting reabsorption of urea and solutes like NaCl. You now promote water reabsorption so with that; you have an increase in urine osmolality and a decrease in urine volume. Water is retained in the body therefore plasma osmolality goes back to normal offsetting the initial condition. Consequently, if you have increased water intake, plasma osmolality goes down. Stimulation going to the osmoreceptors is cut off therefore osmoreceptors are not stimulated, you do not release ADH, you decrease the production of aquaporins therefore water is not reabsorbed; it goes out into the urine. Urine therefore will have a decrease in osmolality (dilute urine) and an increase in urine volume. Consequently, plasma osmolality goes back up to normal offsetting the initial condition. 2 Shannen Kaye B. Apolinario, RMT B. This is percent change in blood pressure/volume plotted against ADH release. Take note that if you have zero change in pressure or if pressure increases, ADH release is zero. However, if pressure or volume drops, ADH release increases accordingly. Looking at this graph, you have plasma osmolality and ADH release. The green line is the same as this one (red line in the graph above) and it is 280 or 282 mOsm. Above 280 or 282 mOsm, ADH release increases. In this graph however, this will show to us the effect of chronic changes in blood pressure. When we have chronic changes in blood pressure, the set off point for ADH release adjusts. If you look at the red line, here you have chronic 10% decrease in pressure or volume – chronic hypotension. Take note that the set off point is from 280 to 270, it went down. At 270 below, ADH release is zero but greater than 270, ADH release increases. The same is true for chronic hypertension; here you have a 10% chronic increase in volume or pressure. The set off point is from 280 to 290, so it increased. Below 290, ADH release is zero, above 290, ADH release increases. 1 2 Looking at diabetes insipidus, you have two types: central and nephrogenic. When you say central DI, there is a decrease in ADH. The more common pathology would be a decrease in neurophysin. Neurophysin shuttles the ADH from the hypothalamus to the pituitary gland (its like a school bus) so if there is a decrease in neurophysin, ADH will not be transported to the posterior pituitary therefore it will not be released. For nephrogenic DI, ADH may be present, the receptors are absent. Even if you have ADH but no receptors, still, water cannot be reabsorbed. For your central and nephrogenic, symptomatology would be similar – polydipsia and polyuria. Why is there polydipsia? Because plasma tonicity is always high, stimulating the thirst center. Why is there polyuria? Because you cannot reabsorb water and water will be excreted. Thirst ďˇ ďˇ In this diagram, this will show to us the action of ADH in the tubular cell. So this you have your filtrate, tubular cell in the DCT or in the collecting duct, interstitium or blood. 1. Here you have ADH, it will attach to V2 receptor. When activated, it is coupled with G protein activating now your adenylyl cyclase. That increases your cAMP, activating protein kinase A. Protein kinase A will facilitate exocytosis of aquaporin 2 as represented by the circles. 2. Here you have exocytosis of aquaporin; your AQP2 is now incorporated on the luminal side of the membrane. It is not shown here but in the basolateral surface, you have AQP 3 or 4 which are always there. So your AQP 3 and 4, this is constitutively produced, meaning to say, it is always there. But your aquaporin 2, they are regulated depending on the presence of ADH. With that, water will be reabsorbed going through aquaporin 2 from luminal side then it will go into the blood via aquaporins 3 and 4. When ADH is absent, there is the endocytosis of aquaporin channels on the luminal side. Aquaporins can either be degraded or they may be recycled. • SIADH o ďŁ ADH ď§ H2O retention ď§ Hypoosmotic body fluids ď§ Hyperosmotic urine • Nephrogenic syndrome of inapproriate antidiuresis o ďŁ V2 receptor activation o ď¤ ADH • Diabetic insipidus o ď¤ ADH: central ď§ ď¤ neurophysin o ď¤ V2 receptors: nephrogenic ď§ ď¤AQP2 o Polydipsia, polyuria Looking at several disorders, you have Syndrome of Inappropriate Antidiuretic Hormone (SIADH). Here you have an increase in ADH. Because of that, you have water retention therefore you have a hypoosmotic body fluid – low tonicity and a hypertonic osmotic urine – concentrated urine. In nephrogenic syndrome of inappropriate antidiuresis, this is where you have an increase in V2 receptors. So even though ADH is absent, your receptors are always active resulting to continuous stimulation of adenylyl cyclase producing aquaporins and continuous reabsorption of water. You will note that for nephrogenic syndrome of inappropriate diuresis, since you have continuous production of aquaporins and continuous reabsorption of water, manifestation will be similar as SIADH so the plasma is hypoosmotic and urine is hyperosmotic. Take note both will have similar manifestations but their etiologies are different. 3 Shannen Kaye B. Apolinario, RMT ďˇ ďˇ ďˇ 2-3% ďŁ plasma osmolality 10-15% ď¤ bood vol or pressure o Thirst threshold > threshold for ADH secretion ď§ Thirst: 295 mOsm/kg H2O ď§ ADH: 285 mOsm/kg H2O Angiotensin II: ďŁ thirst + oropharyngeal, upper GIT receptors: ď¤ thirst Correction of plasma osmolality, blood vol and pressure: ď¤ thirst For your thirst mechanism, the thirst center is stimulated when you have a 2-3% increase in plasma osmolality or a 10-15% decrease in blood volume. So take note that the threshold for thirst is higher than the threshold for ADH release. Here you have tonicity for plasma that will stimulate thirst. This is the tonicity of plasma for ADH release so if you could notice, thirst is higher compared to ADH release. Practical application is that if you feel thirsty, this simply means that ADH release has already occurred. Other important stimuli for thirst, you have angiotensin II so that increases thirst, stimulation of oropharyngeal and upper GIT receptors will decrease thirst. Notice that if you feel thirsty and you drank water, water is not yet absorbed by the gastrointestinal tract but you don’t feel thirsty anymore and this is your oropharyngeal and GI receptors. Coke Story: this is where your soda will be backing on its marketing strategy. If it is hot and you feel thirsty, it very appetizing to drink an iced cold coke. You drank Coke and you feel satisfied - you are not thirsty anymore. But mind you that Coke contains solutes. Later on you will notice that you feel thirsty again and you will drink Coke again. Because of this physiologic phenomenon, Coca-Cola is getting richer and richer :D Correction of plasma osmolality and blood volume and pressure decreases thirst. Reabsorption of Water ďˇ ďˇ ďˇ ďˇ ďˇ PCT - 65% of H2O is reabsorbed LOH: descending limb – 20% of H2O is reabsorbed LOH: ascending limb – solutes are reabsorbed DCT – H2O permeability is ADH-dependent CT – H2O permeability is ADH-dependent ďˇ ďˇ Plasma: 282 mOsm/L Urine: 50-1400 mOsm/L Looking at the different segments of the nephron, in the PCT here you have obligatory water reabsorption; next in descending limb, only water is reabsorbed so that’s 20% of the filtered water; in the ascending limb, solutes only are reabsorbed. Looking at DCT and collecting ducts, the percentage of water reabsorbed varies depending on the presence of ADH. Without ADH, water reabsorption is around 8% but with the presence of ADH, it is as high as 13%. Of course, the job of the nephron is to maintain plasma osmolality giving us a urine osmolality that varies; it can either be concentrated or diluted. ďˇ Obligatory urine volume o Minimal vol of urine that must be excreted o Excretion: 600 mOsm/day o Concentrating ability : 1200 mOsm/L o 600 mOsm/day / 1200 mOsm/L o 0.5 L/day Now let’s look at obligatory urine volume. This is the minimal volume of urine that must be excreted. Remember that the job of the kidney is to excrete solutes in order to maintain plasma tonicity. This solute must be dissolved in some medium (or else you’ll be urinating rock salt). It has to be suspended in a medium and this medium is your minimal volume of urine so that’s your obligatory urine volume. How do we get this? Let’s say you want to remove 600 mOsm from your body. The concentrating ability of the kidney at maximum is around 1200 mOsm. Why is it 1200 mOsm? Because it is the tonicity of the renal medulla. So to get your obligatory urine volume, simply divide 1200 to 600 and you will get 0.5 L. This simply means that within the day, if you want to remove 600 mOsm of solute, you need to remove 500 mL of fluid. o o o o Sea water: 2400 mOsm/L Concentrating ability : 1200 mOsm/L 2400 mOsm/day / 1200 mOsm/L 2L/day Practical application: let’s say you quit medschool and have decided to join Survivor. There’s no water and you decided to drink sea water instead. You take in 1 L of sea water with a tonicity of 2,400 mOsm. 2,400 divided by 1,200 you will get 2 L. This simply means that to remove your 2,400 mOsm, 2 L of fluid is excreted. Take note that you only took 1L so this simply underlines the fact that if you drink hypertonic solutions, you aggravate dehydration. ďˇ Countercurrent Mechanism Concentrating the urine o ADH o Hypertonic renal medulla: 1200-1400 mOsm/L ď§ Countercurrent mechanism ď§ Recycling of urea ď§ Function of the vasa recta Looking at the concentrating ability of the kidney, we’ve already discussed ADH. With the action of ADH, water is reabsorbed because via osmosis, the hypertonic medulla will attract water. The question is: how does the medulla become hypertonic? The tonicity of the medulla is around 1200-1400 mOsm. These are the mechanisms by which we create a hypertonic medulla: your counter-current mechanism and recycling of urea contributes to the tonicity of the medulla. Your countercurrent mechanism will add NaCl to the renal medulla contributing around 600 mOsm. Urea which is a by-product of protein metabolism will contribute another 600 mOsm in the renal medulla (600 + 600 =1,200). These two mechanisms will create a hypertonic medulla. Your vasa recta on the other hand will not create a hypertonic medulla but it will maintain the tonicity of the medulla. 4 Shannen Kaye B. Apolinario, RMT How do we create a hypertonic medulla? First you have counter-current mechanism. This is your PCT, loop of Henle, DCT. Let’s say everything is isotonic. Your filtrate will go from PCT to descending limb. In the descending limb supposed to be, water will be reabsorbed but water will NOT be reabsorbed because everything is isotonic. Then your filtrate will go up into the ascending limb, in here you have active reabsorption of solutes, you have your NKCC2 co-transport. Solutes are reabsorbed. The tonicity of the medulla now increases. Batch 2 of filtrate comes along. Since the tonicity of the medulla has increased, water is reabsorbed. When water is reabsorbed, the tonicity of the filtrate goes up. This batch, when it ascends the loop of Henle, since it is concentrated, more solutes will be pumped into the interstitium. The first one to increase will increase even further. Since the tonicity further increased, when batch 3 comes along, more water will be reabsorbed, the tonicity of the filtrate further increases, when it ascends more solutes will be reabsorbed more than batch 2 and 1. You will notice that the tonicity of renal medulla gradually increases until you established your osmotic gradient. Concentrating the Urine Looking at this diagram, this is your loop of Henle, DCT, collecting ducts. The blue background will represent renal interstitium and you have the cortex which is isotonic and the medulla which is hypertonic. The red structures will represent the vasa recta. Without ADH water is simply excreted but with the presence of ADH as represented by the yellow circles, water is reabsorbed, it goes into the interstitium and then it will go into the vasa recta. You will note that water will not stay in the renal medulla; it will go into the vasa recta. Why will it go to the vasa recta? Because of plasma proteins. So water now exits your renal interstitium, it goes back into the circulation via vasa recta maintaining now the tonicity of the medulla. Take note the vasa recta will not contribute solutes but it will maintain the tonicity of the medulla. Without vasa recta, the water that has been reabsorbed will stay into the interstitium diluting the renal medulla. Recycling of Urea like any capillary bed, this is where filtration will also occur such that fluid will go from plasma it goes now into the interstitium because of hydrostatic pressure and more so because of the tonicity of the medulla. In your arterial side also, you have a small amount of solutes entering your vasa recta. Now looking at the U-shaped configuration of vasa recta, the amount of water that went out has the same amount of water that will go back in. Why will it enter? Because of plasma proteins. When water enters the venous side of vasa recta, that increases hydrostatic pressure inside the vessel permitting the exit of solutes. ďˇ ďˇ ďˇ This is your loop of Henle, DCT, collecting ducts. The number in front of you will represent concentration for urea. In the PCT and descending limb of loop of Henle, water is reabsorbed therefore urea concentration increases. Then it goes up in the ascending limb and into the DCT. The DCT and the early portions of collecting ducts are impermeable to urea as represented by the dark lines. It means that urea is NOT able to permeate the cell membrane. It will just pass through and the concentration is maintained. However, your ADH as represented by yellow circles will promote reabsorption of water in DCT and collecting ducts so water is reabsorbed and the concentration of urea increases. Take note in the early portions of collecting tubule, it is impermeable but once it reaches the medullary collecting ducts, your medullary collecting ducts are now permeable now to urea so it can now pass through. Since urea concentration has increased, you now have a gradient. Urea diffuses out and it goes back into the ascending limb because of concentration gradient. Then it goes up again going to DCT and collecting ducts. You will notice that urea will just go around. Urea now contributes around 600 mOsm of solute in your renal medulla. Practical application: patients with chronic protein malnutrition have decreased urea production. Patients with protein malnutrition will have weaker concentrating capability so their urine is always diluted. ďˇ ďˇ + ADH o + 600mOsm/L in the medulla - ADH o Medulla < 1400 mOsm/L The action of urea is mediated by ADH. Without ADH, you will not be able to concentrate urea in the collecting ducts therefore you do not have a gradient that will permit recycling of urea. So that’s the action of ADH. Vasa Recta This is your arterial side and venous side. The numbers will represent tonicity. when your vasa recta flows to the arterial side, just 5 Shannen Kaye B. Apolinario, RMT U-shaped Blood flow is low Serves as countercurrent exchangers o Minimizes solute loss o ↑ medullary renal blood flow, ↑ solute washout, ↓ concentrating ability Notice that the amount of solute that entered, the same amount will exit. The amount of water that exited, the same amount of water will enter. So that’s the importance of U-shaped vasa recta. If it were a straight capillary bed, the water the water that went out cannot go back in so that is why your vasa recta is U-shaped and it parallels the loop of Henle. This serves as your counter current exchanger. It is called counter current exchanger because when it acts in concert with your loop of Henle, they are the only ones exchanging solutes. So your vasa recta now will minimize solute loss in medullary interstitium. If you increase your medullary renal blood flow, that increases solute wash out decreasing now the concentrating ability of the kidney so you can just imagine if blood flow is fast, solutes will be washed out faster so the tonicity of the medulla decreases. If you will recall the very first lecture, it was mentioned that the blood flow going to the renal medulla is sluggish. Concentrating Ability of the Kidney ďˇ H2O diuresis o – ADH o Dilute urine * Antidiuresis - + ADH - Concentrated urine Looking at diuresis and anti-diuresis, this is a simplified diagram. Your vasa recta here should superimpose your loop of Henle. In the absence of ADH, we produce dilute urine, water stays in the tubules and it exits. However with the presence of ADH we produce concentrated urine. This will provoke water reabsorption and the water that went out will go back into the vasa recta. It will go back into the circulation because of plasma proteins. With that, you maintain the tonicity of the medulla even if water is reabsorbed. ďˇ ďˇ ďˇ ADH Corticopapillary osmotic gradient o Countercurrent mechanism o Recycling of urea o Role of the vasa recta Hypertonic medulla o Active transport of solutes in the ascending limb of LOH o Active transport of ions form the CT o Urea o ↓ osmosis from the medullary tubules into the interstitium Again, for the concentrating ability of the kidney: first is ADH and it was already mentioned earlier, second is your corticopapillary osmotic gradient. Your cortex will have a tonicity of 300. Your papilla or medulla will have a tonicity of 1,200 so here you have your osmotic gradient. This is due to your counter-current mechanism, recycling of urea and the role of vasa recta. For your hypertonic medulla, take note there is active transport of solutes in the ascending limb and active transport of ions in the collecting ducts. You also have the role of urea and a drop in osmosis from the medullary tubules into the interstitium. Countercurrent Mechanism down because there is solute wash off; there is increase in solute loss. If the flow is very high, the flow is able to bring the solutes with it so the medulla decreases its tonicity. If you increase ADH, what will happen to the osmotic gradient? ADH or vasopressin is a vasoconstrictor if you constrict your renal arteries or arterioles, GFR decreases. If GFR decreases, filtrate formation and filtrate flow is low. We are talking about solutes particularly NaCl and renal handling of NaCl is via time gradient limitation. So if flow rate is slow, it gives time for renal tubules to reabsorb solutes therefore solute increases in the renal medulla so that increases osmotic gradient. If you increase urea, what will happen to the osmotic gradient? For urea, the more urea you have, the greater the osmotic gradient. Free Water Clearance ďˇ ďˇ ďˇ Estimates the ability to concentrate or dilute the urine Rate at which solute-free water is excreted Free H2O o Produced in the diluting segments of the kidney o +CH2O: -ADH o -CH2O: +ADH Now we’ll go to water clearance. So your free water clearance estimates the ability to concentrate or dilute the urine or the rate at which solute free water is excreted. Free water is being produced in the diluting segments of the kidney such that if you have positive water clearance, water is excreted, so ADH is absent. If you have a negative water clearance, ADH is present, water is conserved. ďˇ CH2O = V – Cosm o CH2O – free H2O clearance o V – urine flow rate o Cosm – osmolar clearance ď§ Uosm x V / Posm ďˇ Anatomy (Question) o ↑ length of LOH: ? osmotic gradient o ↑ juxtamedullary nephrons: ? osmotic gradient ďˇ Anatomy (Answer) o ↑ length of LOH, ↑ osmotic gradient o ↑ juxtamedullary nephrons, ↑ osmotic gradient ďˇ ďˇ ďˇ V: 1 ml/min Uosm: 600 mOsm/L Posm: 300 mOsm/L If you increase the length of the loop of Henle, what will happen to the osmotic gradient? When the length of the loop of Henle increases, osmotic gradient increases. If you have a long loop of Henle, more solutes are pumped into the interstitium. If you look at the loop of Henle of dessert animals like camel and Meer cat, they have longer loops of Henle so that they will be able to conserve water more. ďˇ ďˇ ďˇ CH2O = V – Cosm CH2O = 1 – [(600 x 1)/300] -1 ml/min o +ADH o H2O is conserved If the juxtamedullary nephrons increased in number, what will happen to the osmotic gradient? If you increase the number of juxtamedullary nephrons, more solutes will be entering the renal medulla. ďˇ Physiology (Question) o ↑ flow rate in the LOH: ? osmotic gradient o ↑ flow rate in the vasa recta: ? osmotic gradient o ↑ ADH: ? osmotic gradient o ↑ urea: ? osmotic gradient ďˇ Physiology (Answer) o ↑ flow rate in the LOH: ↓ osmotic gradient ď§ ↑ solute loss o ↑ flow rate in the vasa recta: ↓ osmotic gradient ď§ ↑ solute loss o ↑ ADH: ↑ osmotic gradient ď§ Vasoconstrictor, ↓ blood flow, ↓ solute loss o ↑ urea: ↑ osmotic gradient ď§ +600 mOsm/L to the medulla If you increase the flow rate in the loop of Henle, what will happen to the osmotic gradient? If you increase the flow rate in the vasa recta, what will happen to the osmotic gradient? Osmotic gradient goes 6 Shannen Kaye B. Apolinario, RMT To get your free water clearance, it is equal to urine flow rate minus osmolar clearance. You will take note that your osmolar clearance is actually your clearance principle. So how do we use this? Urine flow rate is around 1mL/min so that’s more or less constant. You get urine osmolality – get a urine sample and send it to the lab and the result is 600 mOsm. You get your plasma osmolality – get a blood sample and send it to the lab and the result is 300 mOsm. With this plasma osmolality, is the patient dehydrated or has plasma tonicity increased? It increased because the normal is 282 mOsm, So what would you expect? There is ADH release. Having your values now, plug them in so 1 minus 600 x 1 / 300, you’ll get negative 1 mL/min therefore you stimulate ADH release which actually supports a hypertonic plasma. Take note that an increase in the negativity this simply means an increase in ADH release meaning to say, the more the negative your value is, the higher the amount of ADH released. Water now is conserved. So we have mentioned earlier that the more negative your water clearance is, the greater the amount of ADH; the more positive your water clearance is, more water is excreted. ďˇ ďˇ ďˇ + CH2O: -ADH - CH2O: +ADH 0 CH2O: +loop diuretic o Urine is not diluted: the diluting segment is inhibited o Urine is not concentrated: the corticopapillary osmotic gradient is abolished What if the free water clearance is zero? This happens when we use loop diuretics. Diuretics like furosemide etc. The action of loop diuretic is to inhibit the NKCC2 pump in the thick ascending limb. If you inhibit your NKCC2 pump in the loop of Henle, what happens to the tonicity of the medulla is that it will decrease. Rigorous use of loop diuretics will produce and isotonic medulla because the solutes are not pumped into the interstitium so when your filtrate flows, water will stay in the tubules. So urine is neither concentrated nor diluted. That’s your zero free water clearance. Water Reabsorption So here you have your PCT, the site for obligatory water reabsorption so that’s 65-67% reabsorbed and take note that your hormones will not be influencing reabsorption rate for PCT. However, for your DCT and collecting ducts where facultative water reabsorption occurs, reabsorption of water is influenced by hormones particularly ADH. They are also influenced by hydration status of the individual so without ADH, we’ve mentioned that water reabsorption is around 8% and in the presence of ADH, it is around 13%. Segment Percentage of Filtrate Reabsorbed Mechanism of Water Reabsorption Proximal tubule 67% Passive Loop of Henle 15% Descending thin limb only, passive None Distal tubule 0% No water reabsorption None Late distal tubule and collecting duct ≈8%-17% Passive ADH, ANP, BNP` Regulation of Osmotic Equlibrium and Ionic Balance in the Plasma As far Na and K handling are concerned, aldosterone will play an important role but the role of aldosterone will be more extensive on the adrenal lecture. As far as Ca and phosphate are concerned, this will be handled more extensively in PTH, vit.D and calcitonin or the endocrine lecture. Shannen Kaye B. Apolinario, RMT ďˇ ďˇ ďˇ Most abundant extracellular cation Determines the ECF vol DCT and CT reabsorption is concerned with acid-base balance Na is the most abundant extracellular cation and it will determine your extracellular fluid volume. Together with Na, you have your corresponding anions like bicarbonate and Cl, so all of these will determine ECF volume. Take note in the DCT and collecting tubules, reabsorption of Na goes hand in hand with acid base balance. In this diagram, this will show the percentage of solute or Na being reabsorbed in the different segments of the nephron. Hormones That Regulate Water Permeability None In this table, you have the different segments of your nephron. You have the percentage of filtrate being reabsorbed and of course the hormones that will regulate reabsorption rate. Take note that only in the late DCT and collecting ducts wherein your hormones will exert their effects. The other segments are not influenced by hormones. So that’s regulation of water. 7 Sodium In this graph, you have your Na intake and ECF volume. Let’s say you had an eat-all-you-can in Mcdonald’s, so there is a sudden increase in Na intake. The job of the kidney to maintain a constant plasma osmolality and to excrete solutes therefore there is a corresponding increase in excretion of NaCl. Because of the high intake in Na, where Na goes water follows. You now have an increase in blood volume or ECF volume. That’s why we are prohibiting hypertensive patients in taking in a lot of salts because this aggravates their hypertension. If you sustain a high salt diet, ECF volume is increased so the blood volume is really high. Then you have decided to have a healthy living so solute intake drops. Correspondingly, solute excretion decreases also in order to maintain plasma osmolality and with that, blood volume or ECF volume goes back to base line. ďˇ Angiotensin II o ď¤ ECF vol, ďŁ RAAS o PCT: ďŁ NaCl reabsorption ď§ ďŁ Na-H antiport o o ďˇ ď§ Starling forces adjustment LOH, DCT, CD: ďŁ Na reabsorption ďŁ sensitivity of the tubuloglomerular feedback Other effects: o Aldosterone release o Weak vasoconstrictor – renal artery, afferent arteriole o Strong vasoconstrictor – efferent arteriole o Mesangial cell contraction: ď¤ Kf due to ď¤ surface area Let’s look at the different substances that will regulate renal handling of Na. first you have your angiotensin II. When your ECF volume drops or when RAAS is activated, angiotensin II increases. Angiotensin II will target PCT increasing Na reabsorption via increasing your Na-H antiport and it will affect your Starling forces. Angiotensin II will also target the loop of Henle, DCT and in the collecting ducts increasing Na reabsorption and it will also increase the sensitivity of tubuloglomerular feedback. Other effects of angiotensin II, we all know that via RAAS it will stimulate aldosterone release. Angiotensin II is a vasoconstrictor so it will weakly constrict the renal artery in the afferent arteriole but it is a strong vasoconstrictor in the efferent arteriole. It will also potentiate mesangial cell contraction altering Kf, decreasing its surface area. So basically angiotensin II will also change GFR. ďˇ Aldosterone o ECV regulation o ďŁ: RAAS, hyperkalemia o ď¤: natiuretic peptides, hypokalemia o ďŁ Na reabsorption ď§ ďŁ Na-Cl symport ď§ ďŁ Na-K pump ď§ ďŁ ENaC ď§ ďŁ Sgk1 ď§ ďŁ CAP1, prostatin o LOH, DCT, CD: ďŁ NaCl reabsorption o DCT, CD: ďŁ K secretion o Paracellular Cl reabsorption o H2O reabsorption Aldosterone is important for ECF volume regulation. So it regulates fluid volume because when it reabsorbs solutes, there is a commensurate reabsorption of water so basically you reabsorb isotonic fluids. RAAS and hyperkalemia will increase aldosterone release. Your ANP and hypokalemia will decrease aldosterone release. The function of aldosterone is to increase reabsorption of NaCl via increasing the different activities of transport mechanisms. Your aldosterone will target the loop of Henle, DCT and collecting ducts to increase NaCl reabsorption and in the collecting ducts and DCT, when it targets your principal cells it will potentiate K secretion. You also potentiate paracellular Cl reabsorption because when you reabsorb a positive Na ion, a negative ion like Cl goes along with it. You also have reabsorption of water. This is your RAAS. In the kidneys, you will produce renin. In the liver you will produce angiotensinogen. Renin will activate your angiotensinogen forming angiotensin I. Angiotensin converting enzyme (ACE) found in the lungs and kidneys will activate angiotensin I to angiotensin II which is the most potent form. It was already mentioned earlier the effects of angiotensin II: it potentiates sympathetic activity. When your sympathetics are activated, renal vessels constrict and GFR goes down. If GFR goes down, formation of filtrate is down; the flow of the filtrate is down. By virtue of your gradient time limitation, Na reabsorption increases. Angiotensin II will reabsorb your NaCl and your angiotensin II will potentiate the release of aldosterone permitting now reabsorption of NaCl and excretion of K. Angiotensin II is a vasoconstrictor and it will also potentiate the release of ADH. ďˇ ANP, BNP o ď¤ NaCl and H2O reabsorption in the CD o ď¤ total peripheral resistance o ď¤ ADH secretion, ADH-mediated H2O reabsorption ďˇ Uroguanylin, guanylin o Released by neuroendocrine cells of the GIT, kidneys o ď¤ NaCl, H2O reabsorption o ďŁ Na excretion ď§ PCT: ď¤ Na-K pump, Na-H anitport ď§ DCT, CT: ď¤ ROMK Your atrial natriuretic peptide (ANP) is produced in the atrium. Your brain natriuretic peptide (BNP) is produced in the ventricles although initially it was isolated in the brain but as far as in the general circulation is concerned, it is being produced in the ventricles. Basically, your natriuretic peptides will decrease NaCl and water reabsorption in the collecting ducts, they also decrease the total peripheral resistance and they will decrease ADH secretion and ADH mediated water reabsorption. Uroguanylin and guanylin are produced in the GIT and in the kidneys when we have a high salt diet. A high salt diet will permit the release of uroguanylin and guanylin increasing now excretion of your solutes so there is a decrease in NaCl and water reabsorption and the function of uroguanylin and guanylin is to target the PCT decreasing NaK pump and Na-H antiport. They will also target your DCT and CD decreasing now your ROMK which is a K channel. ďˇ Epinephrine, norepinephrine o ďŁ: ď¤ ECF vol o ďŁ NaCl, H2O reabsorption with ď¤ ECF vol o ďŁ RAAS ďˇ Dopamine o ďŁ: ďŁ ECF vol o ď¤ NaCl, H2O reabsorption ďˇ Adrenomedullin o ďŁ: CHF, ďŁ BP o ďŁ RBF, GFR o ď¤ NaCl, H2O reabsorption ďˇ Urodilantin o Kidneys o ďŁ: ďŁ BP, ECV o ď¤ NaCl and H2O reabsorption in the CD Your sympathetics on the other hand, when the effective circulating volume or ECF volume decreases, that increases your sympathtics increasing now NaCl and water reabsorption. Again RAAS will potentiate sympathetic effects. For dopamine, if ECF increases there is an increase in dopamine. The role of dopamine is to decrease NaCl and water reabsorption. Adrenomedullin and urodilantin are being produced by the kidneys. When an individual has a CHF or long standing hypertension, you increase the release of adrenomedullin whose job is to increase renal blood flow and GFR which decreases NaCl and water reabsorption. For 8 Shannen Kaye B. Apolinario, RMT urodilantin, long standing hypertension or an increase in ECF volume increases urodilantin, decreasing salt and water reabsorption. o o ďˇ Cortisol o ↑ Na reabsorption o ↑ GFR, ↓ Na reabsorption if filtered load > reabsorption Renal blood flow o Redistribution to deeper renal tissues, ↑ Na retention Physical factors o Efferent arteriole o ďŁ resistance, ď¤ Ppc, ď¤ back-leak of NaCl and H2O, ďŁ solute and H2O reabsorption o ↑ PG, ↑ GFR, ↑ ∏C, ↑ H2O reabsorption in the PCT Cortisol is a glucocorticoid being produced by the adrenal gland. Glucocorticoids will have some mineralocorticoid effects and your mineralocorticoid like aldosterone will have some glucocorticoid effects. So with cortisol, you generally have an increase in Na reabsorption. However, cortisol will increase GFR. In that regard, there is a decrease in Na reabsorption if the filtered load is greater than reabsorption rate. For renal blood flow, redistribution to deeper renal tissues would permit Na retention. Meaning to say, if your tubules will go deep to the renal medulla, more solutes will be pumped into the interstitium promoting Na retention. Now we go to Starling forces particularly the action of efferent arteriole. If your efferent arteriole constricts, the hydrostatic pressure in the peritubular capillaries will decrease. That will decrease the back leak of NaCl and water into the tubular fluid. With that, you now have an increase in solute and water retention or reabsorption. Let’s say you have your peritubular capillary, interstitium/blood and tubules. The efferent arteriole constricts, therefore the blood flow going to the peritubular capillaries decreases. The hydrostatic pressure in the peritubular capillaries decreases and if it decreased, it will promote reabsorption so the solutes will not go to the tubules and that’s your back leak. So the solutes will go to the blood, increase solute and water reabsorption. An increase in glomerular hydrostatic pressure increases your GFR. If GFR increases, you concentrate your plasma proteins so oncotic pressure increases promoting reabsorption of water. o ďˇ Glomerulotubular balance o Filtered load = GFR x Na in filtrate o ďŁ GFR, filtered load, ďŁ reabsorption of Na and H2O ď§ ďŁ GFR, ďŁ FF, ďŁ plasma CHON concentration, ďŁ πpc, ďŁ solute and H2O reabsorption ď§ ďŁ filtered CHO, amino acids, ďŁ Na reabsorption at PCT o Reabsorption of Na and H2O increases in proportion to increase in GFR and filtered load of Na Tubuloglomerular feedback o RBF, GFR are kept constant despite changes in BP For glomerulotubul;ar balance, we all know that if you increase GFR and filtered load, rate of reabsorption increases. If the filtered load of Na is increased, the reabsorption of Na must also be increased. This is the formula for filtered load: GFR times the Na concentration in the filtrate. How does that happen? If GFR increases, you increase your filtration fraction. Filtration fraction reflects the concentration of plasma proteins thus increasing oncotic pressure. If you increase oncotic pressure, you reabsorb water. Via solvent drag, you also reabsorb solutes. If you have a high carbohydrate or protein diet, you increase also sodium reabsorption in the PCT in order to reabsorb carbohydrates and amino acids. So reabsorption of Na and water increases in proportion to increase in GFR and filtered load of Na. 9 Shannen Kaye B. Apolinario, RMT For your tubuloglomerular feedback, renal blood flow and GFR are kept constant for as long arterial pressure range is within autoregulatory range. Segment Percentage of Filtrate Reabsorbed Mechanism of Na+ Entry across the Apical Membrane Major Regulatory Hormones Proximal tubule 67% Na+-H+ antiporter, Na+ symporter with amino acids and organic solutes, 1Na+-1H+-2Cl--anion antiporter, paracellular Angiotensin II Norepinephrine Epinephrine Dopamine Loop of Henle 25% 1Na+-1K+-2Clsymporter Aldosterone Angiotensin II Distal tubule ≈5% NaCl symporter (early) Na+ channels (late) Aldosterone Angiotensin II Collecting duct ≈3% Na+ channels Aldosterone, ANP, BNP, urodilatin, uroguanylin, guanylin, angiotensin II In this table, you have the different segments of your nephron, the percentage of Na being reabsorbed and the different transport mechanisms. You also have your regulatory hormones that will affect reabsorption of Na. Potassium ďˇ ďˇ ďˇ ďˇ ďˇ K secretion depends on Na availability in the distal tubules Filtered Reabsorbed o PCT: 67% o LOH: 20% o DCT, CT Secreted o DCT, CT Regulation of K excretion is via regulation of K secretion o Principal cells o ↓ K secretion ď§ ↓ Na at the distal tubules ď§ ↑ H secretion For K, K secretion depends on Na availability. If you will recall the mechanism of K secretion, for every K that will be secreted, Na must be reabsorbed - it will just exchange. For renal handling of K, K is filtered, it is reabsorbed, it may be secreted. In the PT, 67% of K is reabsorbed; in the loop of Henle you have NaKCC2 pump and 20% of K is reabsorbed. In the DCT and collecting tubules, it will depend on the presence of aldosterone. Regulation of K excretion is via regulation of K secretion by the principal cells so aldosterone will target the principal cells. In this case, if you have a decrease in Na in the renal tubules, K secretion decreases (if there is low amount of Na available, the amount of K that will be excreted is also low.) Also, if you have high H ion concentration, you have a decrease in K secretion and this is now the role of your intercalated cells. Intercalated cells with the action of aldosterone, aldosterone will promote secretion of K or H. If H is high in the body just like acidosis, what your intercalated cells will do is they will rather lose H maintaining K. One of the primary regulators for K secretion or excretion is plasma K. ďˇ Regulation of plasma K o Epinephrine ď§ ďŁα stimulation: ďŁ K release from cells, liver ď§ ďŁβ2 stimulation: ďŁ K uptake of cells o Insulin ď§ ďŁ K uptake of cells o Aldosterone ď§ ďŁ K uptake of cells ď§ ďŁ K excretion ď§ Hyperkalemia: ďŁ K secretion – ďŁ Na-K pump – ďŁ K permeability in the apical membrane – ďŁ aldosterone – ďŁ tubular flow rate So here, we’ll look at effects of different substances in plasma K. First you have epinephrine. Depending on the receptor, if you stimulate α receptors, that will promote K release particularly in the liver so that’s hyperkalemia. But if you stimulate your β2 receptors, you promote K uptake – hypokalemia. Aldosterone ď§ DCT, CT: ďŁ K secretion – Principal cells – ďŁ Na-K pump, ENaC, SGK1, K channel activation, prostatin, apical membrane permeability to K ď§ ďŁ: ďŁ angiotensin II, plasma K ď§ ď¤: ď¤ plasma K, natiuretic peptides For insulin, you increase K intake together with glucose. Aldosterone will promote hypokalemia. For aldosterone, it will decrease K uptake and increase K secretion or excretion. Regulation of K reabsorption and secretion. One of the main factors that will dictate renal handling of K is plasma K. So if you have hyperkalemia, you potentiate K secretion via these mechanisms. o Metabolic acidosis: ďŁ plasma K o Metabolic alkalosis, Respiratory alkalosis: ď¤ plasma K ď§ ↓ H secretion ď§ ↑ K secretion o Respiratory acidosis: no effect o ďŁ plasma osmolality: ďŁ plasma K ď§ ď¤ ICF vol o Cell lysis: ďŁ plasma K ď§ Tumor lysis syndrome ď§ Rhabdomyolysis ď§ GI ulcers o For metabolic alkalosis and respiratory alkalosis, just the opposite effects of the above mentioned. For respiratory acidosis, there are no effects but the reason as to why is still unknown. Increasing plasma osmolality increases plasma K. If plasma tonicity increases, water inside the cell will go out. If water inside the cell will go out, the concentration of K inside the cell increases so K will go out. For cell lysis, you increase your plasma K. Tumour lysis syndrome is commonly observed among cancer patients undergoing chemotherapy. When the cell dies, K released. Rhabomyolysis: if the skeletal muscles are damaged during trauma, that increases K in the plasma. For GI ulcers or bleeding ulcers, blood or red blood cells will be digested in the GI tract releasing K. K is absorbed in the GIT that increases K. Strenuous exercise increases plasma K. Skeletal muscles are excitable cells. If you keep on stimulating them, you always have an action potential. If you have an action potential, Na enters and K goes out. It also increases lactic acid – metabolic acidosis. Regulation of K reabsorption and secretion o Plasma K 10 Aldosterone would target the DCT and collecting tubules promoting K secretion so in the principal cells you activate these transport mechanisms. When angiotensin II increases, you increase aldosterone. If you increase plasma K, you also increase aldosterone. If plasma K goes down or with the presence of natriuretic peptide, you decrease aldosterone. o ADH ď§ Principal cells – ďŁ Na uptake, ďŁ electochemical driving force for exit of K across the apical membrane, ďŁ K secretion – ď¤ tubular flow, ď¤ K secretion – Net effect: constant K excretion o ďŁ filtrate flow rate ď§ ďŁ K secretion at DCT, CT ď§ ďŁ activation of PKD1/PKD2 Ca conducting channel complex – ďŁ activation of K channels ď§ ďŁ Na in the filtrate, ďŁ Na uptake, ďŁ electrochemical driving force for K exit ďŁ exercise: ďŁ plasma K ď§ Lactic acid For metabolic acidosis, this increases plasma K. if you have high amounts of H+ in the body, you have a concentration gradient between ECF and ICF compartment with regards to H+. H+ enters the cell. H+ being a positive ion, another positive ion must go out. The most abundant intracellular cation is K so it will go out in order to maintain electrical neutrality. Another effect of acidosis is that your H+ will inhibit your NaK pump. If your NaK is inhibited, during repolarization, K will not enter. ďˇ o Shannen Kaye B. Apolinario, RMT ADH targets the principal cells increasing Na uptake. If you increase Na uptake, that will increase the electrochemical driving force for the exit of K across the apical membrane because you reabsorb a positive ion. To maintain electroneutrality, another positive ion should go out so that’s K therefore you increase K secretion. However as far as ADH is concerned, you also reabsorb water. So if you reabsorb water, the flow rate decreases. Remember as far as renal handling of K is concerned, this is via gradient time limitation so when tubular flow decreases, the concentration gradient for K is low therefore K secretion goes down. You will note that as far as ADH is concerned, it has two opposite effects but at the end of the day, the net effect is constant K secretion or excretion. If you increase your filtrate flow rate, you increase K secretion. You also increase the activation of PKD1 and 2 Ca conducting channels. What these channels do is to permit the entry of Ca. Ca will activate the intracellular machinery increasing activation of K channels so K goes out. Also you increase the Na in the filtrate increasing Na uptake and that increases the electrochemical driving force for the exit of K. o Glucocorticoids ď§ ďŁ K excretion – ďŁ GFR – ďŁ SGK1 activity, ďŁ ENaC, K channel activation o Acid-base balance ď§ Acidosis – ď¤ K secretion – ď¤ Na-K pump, electochemical driving force for K exit, ďŁ filtrate flow – ď¤ apical permeability for K – ď¤ Na-K pump, ďŁ Na excretion, ďŁ aldosterone ď§ Alkalosis – ďŁ K secretion For glucocorticoids, it promotes K excretion and it also permit an increase in GFR rate and increase in several transport mechanism. For acid base balance, during acidosis, there is a decrease in K secretion. If you have acidosis, your intercalated cells would rather remove H to retain K. There is a decrease in NaK pump, your electrochemical driving force for K exit and you also have an increase in filtrate low. You also decrease the permeability for K and by decreasing NaK pump; you increase Na excretion that will promote aldosterone release. So aldosterone will promote H excretion. For alkalosis, the opposite effects. This is K secretion by the DCT and collecting ducts. If the individual has hyperkalemia, the increase in plasma K has a direct effect on the DCT and collecting tubule increasing its secretion. Hyperkalemia will also increase flow rate. So net effect is K excretion – it goes out. Looking at the effect of aldosterone. In acute, aldosterone will target DCT and collecting ducts promoting K secretion that’s why K secretion goes up. However with the reabsorption of water, flow rate decreases. As far as flow rate is concerned, since renal handling of K is gradient time dependent, in this regard, K excretion decreases. Here you have an increase in K secretion and decrease in K secretion and the net effect is no change. Calcium ďˇ ďˇ ďˇ ďˇ ďˇ CHON-bound is not filtered Excretion is low ↑ PTH, ↑ Ca reabsorption ↑ Vit D, ↑ Ca reabsorption ↑ calcitonin, ↓ Ca reabsorption For Ca and phosphate, they are primarily being regulated by three important hormones: PTH, vitamin D and calcitonin. For Ca, they may exist as ionized or protein bound. If Ca is protein bound, it will not be filtered by the kidneys so only the ionized Ca is filtered by the kidneys. Your PTH and vitamin D increase Ca reabsorption but calcitonin will decrease Ca reabsorption. Phosphate ďˇ ďˇ ďˇ ďˇ Buffers the renal tubules ↑ PTH, ↓ PO4 reabsorption ↑ Vit D, ↑ PO4 reabsorption ↑ calcitonin, ↓ PO4 reabsorption For phosphate, they will act as buffers. Again, three hormones will also regulate renal handling of phosphate: PTH, vitamin D and calcitonin. Take note that PTH and calcitonin decreases phosphate reabsorption but vitamin D will increase phosphate reabsorption. Chloride ďˇ Reabsorption is associated with handling of Na and H2O Magnesium Here you have metabolic acidosis. When you have acute metabolic acidosis, you inhibit your NaK pump. Inhibiting NaK pump decreases K excretion. During acute metabolic acidosis, K excretion goes down. You therefore accumulate K in the body, plasma K increases. When plasma K increases, that will permit the release of aldosterone. If aldosterone is released, K excretion increases. So during acute metabolic acidosis, K excretion goes down. For chronic metabolic acidosis, K excretion goes up. ďˇ K secretion by the DCT and CD ďˇ ďˇ CHON-bound is not filtered Filtered Mg are reabsorbed Sulfates ďˇ Tm: 0.06mM/min For Cl reabsorption, it is associated with handling of Na and water via passive transport or simple diffusion. For Mg, protein bound Mg is not filtered and your filtered Mg are reabsorbed through Clodin 16 in the ascending limb. For your sulfate, they are actively transported, transport maxima is 0.6. Ammonia, Hydrogen, Bicarbonate ďˇ NH3 and H participates in acid-base regulation ďˇ ďˇ ďˇ HCO3 participates in acid-base balance All filtered HCO3 is reabsorbeed Alkalosis o ↓ HCO3 reabsorption Acidosis o ↑ HCO3 reabsorption ďˇ 11 Shannen Kaye B. Apolinario, RMT For ammonia and hydrogen together with bicarbonate, they will participate in acid base balance. Take note that all of filtered bicarbonate is reabsorbed. When a patient has alkalosis, there is a decrease in bicarbonate reabsorption but if a patient has acidosis, there is an increase in bicarbonate reabsorption. Glucose, Amino Acids • Glucose o Tm: 320 mg/min o Renal threshold: 220 mg/min • Amino acids o Different amino acids will have various carriers o Tm: 1.5 mM/min For glucose and amino acids, both are actively reabsorbed. For glucose the transport maxima is 320 but the renal threshold is 220. Renal threshold is the amount of glucose present in plasma wherein it will appear in the urine. You will note that the renal threshold is less than transport maxima. Transport maximais the concentration wherein you saturate your carriers. For example, if glucose concentration exceeds renal threshold but lower than the transport maxima, it will still appear in the urine. Why is that even if the concentration of glucose is lower than the transport maxima, it still appeared in the urine? The reason for this is that not all nephrons will have the same amount of carriers. For amino acids, different amino acids will have different carriers and transport maxima is 1.5. Vitamin C. Urea, Uric Acid ďˇ Vit C o Filtered, reabsorbed, and secreted o Tm: 2 mg/min o ↑ adrenal steroids, ↑ vit C secretion o ↑ filtered load of Na, ↑ vit C secretion ďˇ Urea o Filtered and reabsorbed at varying degrees o Reabsorption depends on ADH ďˇ Uric acid o Tm: 15 mg/min Vitamin C is filtered, reabsorbed and secreted. Transport maxima is 2. If you have an increase in adrenal steroids or an increase in the filtered load of Na, that increases vitamin C secretion. For urea, it is filtered and reabsorbed at varying degrees depending on ADH. For uric acid, this is actively secreted and transport maxima is 15. Creatine, Creatinine ďˇ Creatine o Filtered and reabsorbed o No Tm has been demonstrated ďˇ Creatinine o Tm: 16 mg/min Creatine is an essential energy source for the muscle so it is filtered and reabsorbed, no transport maxima exhibited. But for creatinine, a by-product of creatine, it is secreted actively, transport maxima is 16. “The fear of the Lord is the beginning of wisdom, the knowledge of the Holy One is understanding.” -Proverbs 9:10 GOD BLESS YOU ď 12 Shannen Kaye B. Apolinario, RMT Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine 1D – Batch 2020 Renal Physiology III Regulation of Plasma and Water Volume, and Osmotic Equilibrium and Optimal Ionic Balance in the Plasma Dr. Ronald Allan Cruz – January 17, 2017 NORMAL PHYSILOGIC CONDTION: MORE IMPORTANT is AN INCREASE IN PLASMA TONICITY than the drop in blood volume. ďź Should are plasma tonicity increases by 1-2%, it will already stimulate the release of ADH. REGULATION OF PLASMA AND WATER VOLUME Normal Blood Volume: 5L Formed Elements in the blood: 2L NORMAL PLASMA VOLUME: 3L NORMAL PLASMA OSMOLALITY: 280-285 mOsm/L (282 mOsm/L) to be exact Average Specific Gravity of Plasma: 1.008 – 1.010 These are what the kidneys do in order to maintain to a CONSTANT PLASMA VOLUME and PLASMA TONICITY: 1. 2. 3. 4. 5. Conserve fluids Excrete solutes 50-1200 mOsm/L of urine Sp gr: 1.002-1.400 UO: 0.5-18 l/day ďź UO: 0.5-1 ml/kg/hr Kidneys can excrete and reabsorb water such that urine can be DILUTED or CONCENTRATED. Diluted urine ďź As low as 50 mOsm/L of urine ďź Specific gravity of 1.002 Concentrated urine ďź 1200 -1400 mOsm/L of urine ďź Specific gravity of 1.400 SPECIFIC GRAVITY ďź Comparison of fluid to distilled water ďź Water : distilled ratio ďź Sp gr of 1 = it is distilled water ďź Higher sp gra, the more solute it contains and the more concentrated the fluid is UNDER CERTAIN PATHOLOGIC CONDITON: DROP IN BLOOD VOLUME supersedes plasma tonicity. ďź A drop in blood volume of 5-10% even if the plasma tonicity is 282 mOsm/L, ADH will be released. ďź Example: Gunshot wound (profusely bleeding) ď BP drops ď decreased blood volume with constant plasma tonicity ď ADH release. ADH increases the activity of these transporters: 1. UT – A1 & UT – A3 = urea transporters 2. NKCC2 = 3. ENaC = epithelial sodium channel 4. Na-Cl symporter OTHER FACTORS AFFECTING ADH RELEASE: 1. Osmoreceptors ďź Located at the antero-ventral portion of the 3rd ventricle (AV3V) ďź Detects tonicity of the surrounding fluid o Example: when plasma tonicity increases, fluid in the CNS (CSF) will move into the plasma via osmosis. o This will increase the tonicity of the CSF. o If osmoreceptors surrounded by hypertonic medium, they will shrink because water from the cell will go out via osmosis. o This will trigger generation of AP by osmoreceptors to be sent to the supraoptic and paraventricular nuclei for the production of ADH and for the release of ADH by the neurohypophysis. How is this done by the kidneys? ANTIDIURETIC HORMONE (ADH) / VASOPRESSIN ďź A neurohormone ďź Produced in the hypothalamus specifically: o Supraoptic nuclei o Paraventricular nuclei ďź Transported via AXONAL TRANSPORT down to the posterior pituitary gland to be stored. ďź Stimulus for ADH release o 1-2% increase in Plasma tonicity o 5-10% decrease in blood volume ďź Increased water reabsorption especially in the late DCT and collecting tubules (go back to renal II for further explanation) Signals from osmoreceptors will also go to the SUBFORNICAL REGION and ORGANO VASCULOSUM OF LAMINA TERMINALIS (both are centers) ďź These centers when stimulated, will trigger the THIRST MECHANISM 2. BARORECEPTORS and CARDIOPULMONARY REFLEXES will send signals to the median preoptic nuclei which in turn, it will send signals to the supraoptic and paraventricular nuclei to increase the synthesis and release of ADH. Escoto, KC // Gloriani, KP 1 of 16 3. ALCOHOL ďź Inhibits the release of ADH ďź This why we pee a lot when we consume alchol TAKE NOTE: ADH reabsorbs water only BUT it regulates Plasma Osmolality. Aldosterone reabsorbs water together with Na BUT it is the one that regulates Plasma volume. Diagram: 1. 2. 3. 4. Shown is hypothalamus which is magnified. a. Seen is the supraoptic and paraventricular nuclei of the hypothalamus You can also see the osmoreceptors, baroreceptors and cardiopulmonary receptors. a. Impulses from these regions will now send impulses to supraoptic and paraventricular nuclei ADH is produced then transported to the posterior pituitary gland It will be released in the bloodstream, targeting the DCT and collecting ducts to increase water reabsorption Table: Factors increasing and decreasing ADH production and release Diagram: 1. If water intake is decreased, plasma osmolality increases and osmoreceptors will be stimulated. 2. ADH will be release 3. This will target the DCT and Collecting tubule for increase water reabsorption a. Water will go back to the body 4. The net effects are: a. Urine volume decreases b. Urine concentration /osmolality increases (hypertonic urine) c. Decreased plasma osmolality, bringing it back to 282 mOsm/L. Diagram: 1. If water intake is increased, plasma osmolality decreases and osmoreceptors are NOT stimulated 2. There will be no release of ADH 3. AQP2 activity in the DCT and CT decreases 4. Decrease H2O reabsorption 5. The net effects: Escoto, KC // Gloriani, KP 2 of 16 a. b. c. Increase Urine volume Decrease urine concentration / tonicity ( hypoosmotic urine) Increase plasma osmolality back to the normal average TAKE NOTE: ADH’s MAIN EFFECT REABSORPTION. IS TO INCREASE H2O Graph: Plasma osmolality Vs. ADH release. Combination of the 2 previous graphs 1. 2. 3. The green line is same as the red line in the previous two graphs (A and B). As we can see, increased plasma osmolality, the amount of ADH release also increases but take into account the BP. We can see that: a. LOWER BP: The threshold for ADH release decreases b. HIGHER BP: The threshold for ADH release increases This graph will show the effect of chronic changes in BP because at different changes in BP, the set off point for ADH release adjusts. CHRONIC HYPOTENSION: From 280 mOsm/kg H2O set off point, ADH is now released at 270 mOsm/kg H20 CHRONIC HYPERTENSION: Below 290 mOsm/kg H20, there is no release of ADH. The set off point is increased to 290 mOsm/kg H2O. A. B. Plasma osmolality Vs. ADH ďź As the plasma tonicity increases, beyond 282MOsm/L, ADH levels go up. Blood Pressure Vs. ADH ďź The lower the blood volume or BP, ADH released is increased Figure: this will be the tubular cells in the DCT and CT. 1. ADH will activate V2 receptors 2. These V2 receptors will activate a G protein increasing the activity of adenylyl cyclase. Escoto, KC // Gloriani, KP 3 of 16 3. 4. 5. 6. 7. 8. Cyclic AMP now increases cAMP being a secondary messenger will increase Protein Kinase A Protein Kinase A will have two effects: a. Activate genetic machinery, increasing the synthesis of AQP2 b. More importantly, it can also phosphorylate AQP2 Once phosphorylated, AQP2 will now be inserted into the apical surface of the cell. a. Not shown but there are also AQP in the basolateral membrane Water can now be reabsorbed. If phosphate group is removed, AQP2 will now be endocytosed: a. It can now be degraded b. Or it can be recycled CLINICAL APPLICATION Syndrome of Inappropriate ADH (SIADH) ďź Increase ADH production o Due to some CNS lesions or trauma that the hypothalamus keeps on producing ADH ďź Outcomes: o Increased H2O retention because water is reabsorbed continuously. o Hypoosmotic body fluid o Hyperosmotic urine (concentrated) Nephrogenic Syndrome of Inappropriate Antiduiresis ďź Normal or less ADH levels ďź A problem in V2 receptor o V2 receptors are CONSTANTLY activated even without the presence of ADH o So the effects are similar: continuous reabsorption of H2O Diabetes Insipidus ďź Has two types o Central DI ď§ Decrease in ADH ď§ And usually, a decrease in Nuerophysin (substance that transports ADH down to the neurohypophysis) so ADH is not transported so ADH will be less ď§ Hypoosmotic urine ď§ Increase urine volume ď§ Increase in plasma tonicity o Nephrogenic DI ď§ Similar to NSIA ď§ V2 receptors defect ďˇ Less receptors ď§ Hypoosmotic urine ď§ Increase urine volume ď§ Hypertonic plasma ADH also acts as a vasoconstrictor, so patients with Nephrogenic DI have a higher BP compared to patients with Central DI because V1 receptors in BVs are present and functional. ADH when attached to V1 receptors cause systemic vasoconstriction. THIRST MECHANISM ďź Thirst is triggered by: o 2-3% increase in plasma tonicity o 10-15% decrease in blood volume ďź Thirst HAS A GREATER THRESHOLD than ADH secretion ADH threshold o 295 mOsm/kg H2O thirst = 285 mOsm/L threshold o This simply means that when plasma tonicity hits 285 mOsm/kg H2O, ADH will be released however the sensation of thirst is still absent o So when plasma tonicity hits 295, ADH is also released but it is only then we will experience thirst ď§ When a person feels the feeling of thirst, he/she is already dehydrated A person must be able to consume around 1.5 – 3L of water every day to be hydrated. FACTORS AFFECTING THIRST A. B. Angiotensin ii ďź Increases thirst sensation Receptors present in the Oropharyngeal area and Upper GIT ďź Decreases Thirst but that doesn’t mean that a person is adequately hydrated Example: When we experience thirst, any fluid that we take will stimulate the oropharyngeal and Upper GIT receptors decreasing the sensation of thirst but that doesn’t mean we become well hydrated. If we are taking in Coke, we feel thirsty a little bit later. So the best thirst quencher is water. REABSORPTION OF WATER IN THE DIFFERENT PART OF THE NEPHRONS ďˇ ďˇ ďˇ ďˇ ďˇ PCT – 65% of H2O is reabsorbed (MAJORITY) LOH: descending limb – 20% of H2O is reabsorbed LOH: ascending limb – solutes are reabsorbed DCT – H2O permeability is ADH-dependent CT – H2O permeability is ADH-dependent DCT and CT are responsive to ADH. In these segments, this is where FINAL MODIFICATION OF URINE will occur depending on the needs Escoto, KC //should Gloriani, KP of the body such that plasma tonicity be maintain to 282 4 of mOsm/L so with that urine osmolality, urine can16 be diluted or concentrated. OBLIGATORY URINE VOLUME ďź Minimum amount of fluid that must be excreted with solutes o Excretion: 600 mOsm/day o Concentrating ability : 1200 mOsm/L o 600 mOsm/day / 1200 mOsm/L o 0.5 L/day Let’s say that we want to secrete 600 mOsm in a day. This amount of solute must be suspended in a fluid because we urinate in liquid form not solid. The amount of fluid must be excreted together with these amount of solute is the obligatory urine volume. How is this done? ďź If we want to remove 600 mOsm in a day ďź The maximum concentrating ability of the kidney is 1200 mOsm o This is from the tonicity of the renal medulla ďź To get the obligatory urine volume: o Divide: 600 mOsm / 1200 mOsm o The answer will be 0.5 L of water is needed to dissolve 600 mOsm of solutes to be excreted. THREE FACTORS MAKING THE RENAL MEDULLA HYPERTONIC 1. 2. 3. A. Countercurrent mechanism ďź Contributes solute to the renal interstitium ďź Increasing the activity of NKCC2 ďź Contributes 600 mOsm of NaCl to the interstitium Recycling of Urea ďź Contributes solute to the renal interstitium Function of the Vasa Recta ďź it will not add solutes to the interstitium BUT it will maintain the tonicity of the renal medulla COUNTERCURRENT MECHANISM PCT DCT NKCC2 Practical Application ďˇ ďˇ ďˇ ďˇ Sea water: 2400 mOsm/L Concentrating ability : 1200 mOsm/L 2400 mOsm/day / 1200 mOsm/L 2L/day Seawater has a tonicity of 2400 mOsm/L. When we drink seawater, we want to remove that 2400 mOsm of solutes. To get the obligatory urine volume: 2400 / 1200 = 2 L This means that 2L of water is needed to dissolve 2400 mOsm of solutes to be excreted. We can see that you only drank 1 L but excreted 2L of water. This means that drinking hypertonic solution will make a person more dehydrated. HOW DO WE CONENTRATE THE URINE? 1. ADH 2. Hypertonic Renal Medula ďź 1200 mOsm/L ďź Once the filtrate flows through the Loop of Henle, water will be reabsorb due to the tonicity of the renal medulla; increasing the tonicity of the urine AQP1 LOH Figure: Numbers represent tonicity Batch 1: Filtrate in isotonic environment 1. Let’s say everything first is isotonic at 300 mOsm. Following the flow of the solute: 2. If the filtrate is passing through the descending limb and the filtrate is isotonic, water will not be reabsorb. 3. The filtrate will now go the ascending limb 4. Solutes will now be reabsorb in the thick ascending limb due to the presence of NKKC2 ďź NKCC2 will actively pump solutes into the interstitium ďź This will now increase the tonicity of the interstitium Batch 2 of filtrate: 1. As filtrate is now going through the descending limb, water will now be reabsorb ďź This is due to the increased tonicity in the interstitium Escoto, KC // Gloriani, KP 5 of 16 2. 3. The tonicity of the filtrate goes up because water is removed. When it ascends the ascending limb, more solutes is pumped to the interstitum since the tonicity of the filtrate is higher. ďź This will increase the tonicity of the interstitium more. VASA RECTA Venous Arterial DCT PCT DCT PCT CD NKCC2 LOH AQP1 LOH ďź Batch 3 of filtrate 1. With the third batch, more water will be reabsorbed in the descending limb 2. And as it goes to the ascending limb, more solutes will be pumped into the interstitium a. Increasing its tonicity once again ďź Countercurrent multiplier – the tonicity of the interstitium that keeps on increasing. ďź This will now in turn give the corticopapillary osmotic gradient ďź ‘ Figure: Process of Countercurrent Mechanism. This summarizes on what is discussed above. ďź ďź As you can see, the flow of the blood and the flow of the filtrate is anti-parallel Majority of water is reabsorbed in the PCT (67%) 15% of the water is reabsorbed in the descending limb. Water that is reabsorbed from the tubules will not stay in the interstitium so it will not affect the tonicity of the medulla. Water will now go to the vasa recta due to the presence of the Plasma proteins inside. o Plasma proteins exerts osmotic potential, attracting water to blood vessels TAKE NOTE: Reabsorbed water from the PCT and descending Limb of LOH directly goes to the venous side to be brought back immediately to the general circulation. Diagram: Shows the effect of ADH (yellow circles) ďź When ADH is present, water will be reabsorb, increasing the concentration of urine. ďź Water will not stay in the interstitium, it will go to the vasa recta due to the osmotic potential generated by the plasma proteins. Escoto, KC // Gloriani, KP 6 of 16 B. UREA RECYCLING TAKE NOTE: The net effect of urea is just to stay in the kidneys but some urea will be excreted and that depends on ADH. DCT For Urea recycling to be most efficient, ADH must be present; otherwise, the tonicity of urea remains low. PCT CD LOW ADH ď LOW UREA CONCENTRATION GRADIENT ď UREA CAN’T GO OUT OF CD so it is basically excreted. ďź If ADH is chronically absent, the tonicity of renal medulla is still hypertonic because 600mOsm will come from NKCC2. C. Figure: The numbers represent the concentration of Urea 1. In the PCT and descending limb of LOH, water is reabsorbed 2. Once water is reabsorbed, concentration of urea increases 3. In the DCT and early portion of CD, the cell membrane is impermeable to urea. (as represented by the black borders) 4. When the filtrate reaches the DCT and CD, ADH is present 5. Once ADH is present, water is reabsorbed a. The concentration of urea increases 6. In the later portion of CD, cell membrane becomes permeable to urea 7. There will be a concentration gradient for urea 8. Urea in the late CD will go out 9. Then it will go back again in to the ascending limb then out again at the late CD 10. So basically, it is just going in and out. 1200mOsm of solutes ďź Maximum concentrating ability of the kidneys ďź This from: o UREA = 600 mOsm of solutes additional to the interstitium o NaCl = 600 mOsm of solutes additional to the interstitium ďź This is the tonicity of the renal medulla VASA RECTA ďź Another factor that makes the renal medulla hypertonic ďź Will not add solutes but it will maintain the tonicity of the renal medulla ďź Has a unique configuration: U SHAPE ďź Low blood flow ď§ Constitutes 7% of Renal blood flow ďź Acts as solute exchangers / countercurrent exchangers ď§ It minimizes solute loss ďź If RBF is increased and more blood enters the vasa recta (increasing medullary renal blood flow), this will increase solute washout. ď§ Instead of solutes coming back, more are washed away ď§ The tonicity of renal medulla decreases; decreasing the concentrating ability of the kidney ďź Delivers O2 and nutrients ďź Delivers substances for secretion ďź Pathway to return reabsorbed substances to the circulatory system. ď§ When we reabsorb glucose and amino acids, they are brought into the vasa recta ďź Concentrates or dilutes the urine ď§ Concentration of the venous side is higher because you already reabsorb from the filtrate (AA, solutes, etc) TAKE NOTE: If the vasa recta is a straight blood vessel, the water that goes out can’t go back. EFFECTS OF CHRONIC TAKING OF PAIN RELIEVERS: If blood flow going to the vasa recta is further decreased, this will constrict the blood vessels. O2 and nutrients delivery to the tubular cells decreases. They become ischemic and you now have renal injury. Escoto, KC // Gloriani, KP 7 of 16 Arterial Venous B. Figure: the numbers represent tonicity 1. 2. 3. 4. 5. 6. 7. In the arterial side of the vasa recta, just like any other capillary bed, this is where FILTRATION OCCURS. ďź This is due to the presence of hydrostatic pressure Water will now go out into the interstitium from the arterial side. As water goes out, the concentration of plasma increases Since the vasa recta has a unique configuration which is U shape, the effects are: ďź As blood goes to the venous side, the concentration of plasma is high exerting osmotic potential ďź Water that went out, will also come back in Notice in the venous side, there is a higher concentration of solute. This will drive the solute out from the venous side Then the solutes will go back to the arterial side. CONCENTRATING ABILITY OF THE KIDNEYS A. Dilute urine / H2O diuresis ďź Absent ADH, diluted urine is formed • Water is secreted ďź Tonicity of renal medulla = 600 mOsm/L • Due to NaCl given by NKCC2 Concentrated urine / Antidiuresis ďź ADH is present, concentrated urine is formed • Water is reabsorbed from the DCT and CD • ADH enhances urea recycling ďź Tonicity of renal medulla = 1200 mOsm / L • This is from NaCl and Urea TWO FACTORS IN THE FORMATION OF CONCENTRATED URINE 1. 2. ADH CORTICOPAPILLARY OSMOTIC GRADIENT or THE HYPERTONIC RENAL MEDULLA 3 FACTORS IN THE HYPERTONICITY OF RENAL MEDULLA 1. 2. 3. Countercurrent exchanger – add solutes Urea recycling – add solutes Role of Vasa Recta – maintains tonicity HYPERTONICITY OF RENAL MEDULLA PRODUCTION: 1. 2. 3. 4. Active transport of solutes in the thick ascending limb of LOH (NKCC2) Active transport of ions from the CT Urea ↓ osmosis from the medullary tubules into the interstitium FACTORS AFFECTING THE COUNTERCURRENT MECHANISM ANATOMICAL FACTORS ďź ↑ length of LOH: ? osmotic gradient ďˇ The longer the LOH, the longer the thick ascending limb, more NKCC2, more solutes can be added to the interstitium ďˇ Increasing the osmotic gradient Escoto, KC // Gloriani, KP 8 of 16 ďź ↑ juxtamedullary nephrons: ? osmotic gradient ďˇ More NKCC2, more solutes are pumped into the interstitium ďˇ Increasing the osmotic gradient PHSYIOLOGICAL FACTORS ďź ↑ flow rate in the LOH: ? osmotic gradient ďˇ The faster the flow, more solute washout, increasing solute loss ďˇ Decreasing the osmotic gradient ďź ↑ flow rate in the vasa recta: ? osmotic gradient ďˇ The higher the blood flow, more solute washout, increasing solute loss ďˇ Decreasing the osmotic gradient ďź ďź ↑ ADH: ? osmotic gradient ďˇ One effect of ADH other than it enhances urea recycling, it acts as vasoconstrictor ďˇ Constrict blood vessels, blood flow drops, decreasing solute wash out ďˇ Increasing the osmotic gradient ↑ urea: ? osmotic gradient ďˇ Increasing the osmotic gradient FREE WATER CLEARANCE ďź Ability to concentrate or dilute the urine ďź Rate at which solute-free water is excreted ďź We can equate this to excretion: o When something is cleared from the body, this simply means it goes out of the body ďź CLEARANCE OF H20 (+) / +CH2O = water is excreted o Absent ADH ďź CLEARANCE OF H20 (-) / -CH2O = water is NOT excreted, it stays in the body o ADH is present Quantification of Free Water Clearance CH2O = V – Cosm CH2O = free H2O clearance V = urine flow rate Cosm = osmolar clearance ďź Uosm x V / Posm CH2O = V – Cosm CH2O = 1 – [(600 x 1)/300] -1 ml/min • This means that ADH is present so H2O is conserve • The higher the numerical value, the greater the degree of reabsorption or secretion of water If 0CH2O / clearance of free water is zero: ďź The patient is taking loop diuretics o Loop diuretics inhibits NKCC2 o No solutes are added into the interstitium ďź The tonicity of the renal medulla gradually decreases up to isotonicity o If the filtrate flows through the LOH, water is not reabsorbed due to isotonicity o Water is not added to the filtrate ďź The urine is NOT diluted ďź The urine is NOT concentrated PCT ďź ďź ďź ďź Obligatory H2O reabsorption occurs It is not influenced by hydration status It is not influenced by ADH Whether you are not dehydrated or not, it will always absorb 65 – 67% of the filtered water. DCT and CT ďź Facultative H2O reabsorption occurs ďź This will depend on ADH o Increased ADH ď increased H2O reabsorption as high as 17% ďź Affected by the hydration status o Dehydration ď increased H2O reabsorption Uosm = get the urine osmolality Posm = get the plasma osmolality Application: • V: 1 ml/min • Uosm: 600 mOsm/L • Posm: 300 mOsm/L Escoto, KC // Gloriani, KP 9 of 16 WATER REABSORPTION IN SEGMENTS OF THE NEPHRON THE DIFFERENTS QUESTION: If the tonicity of renal medulla is high, what will be the urine tonicity? C. If the renal medulla’s tonicity is high, it will reabsorb water D. If water is reabsorbed, you basically remove water from the filtrate E. By removing water from the filtrate, what stays in the filtrate is solutes ďź This makes the urine concentrated There are also other factors like ADH, hydration status, aldosterone. For hydration status: ďź You can have a dilute urine if well hydrated ďź A concentrated urine if dehydrated WATER and Na REABSORPTION ADH ďź ďź ďź ďź REGULATION OF OSMOTIC EQUILIBRIUM AND IONIC BALANCE IN THE PLASMA – RENAL HANDLING OF SOLUTES ďź Movements of other components of the filtrate (solutes) ďź Secretion, reabsorption of substances like glucose, K, Na and etc. Reabsorbs H2O Regulate tonicity In response to ďŁ osmolarity In response to ď¤ ECF vol ALDOSTERONE ďź Reabsorbs Na o Together with Na, water follows ďź Regulate volume ďź In response to ď¤ ECV In the diagram, you’ll see the extracellular compartment and the intracellular compartment together with the ions present there. The two are separated by the cell membrane. Take note that Na and Cl are located more extracellularly whereas you K, PO4 and proteins are located intracellularly. Remember that the kidneys can only alter the extracellular compartment. The intracellular compartment will follow afterwards. Escoto, KC // Gloriani, KP 10 of 16 SODIUM ďź Most abundant extracellular cation ďź Determines the ECF volume ďź In the PCT: o majority of Na is reabsorbed ďź DCT and CD; o Na reabsorption is connected with acid-base balance ďź This is the reason why hypertensive patients are advised to decreased salty foods. Should the patient decrease Na intake, there is also a drop in Na excretion. Na loss will decrease ECF volume 1. Humoral Factors o ďź ďź ďź ↓ Na reabsorption, ↓ H secretion o Recall that you have the NaH exchanger present in the tubules o Decreasing Na reabsorption, H ion secretion is also decreased because once Na is reabsorbed, H goes out. ↑ Na reabsorption, ↑ K secretion o This through the principal cells o Increased activity of Na-K pump, more Na is reabsorbed in exchange for K. Diagram: Amount of Na reabsorbed in the different segments of the nephron FACTORS AFFECTING SODIUM HANDLING (REABSOPRTION AND SECRETION) – water also follows Table: Substances that affect Na reabsorption. Diagram: ďź If Na intake increases, to maintain homeostasis, the kidneys must excrete the same amount of Na ď increased Na excretion o The shaded part represents Na retention ďź With Na retention, we all know that where Na goes, water follows ď ECF volume increases 2. Sympathetics ďź Potentiate RAAS o RAAS will increase angiotensin II and aldosterone 3. Cortisol – dual effects ďź Mineralocorticoid effects o Increase Na reabsorption ďź Increases GFR so decreased Na reabsorption o If GFR increases, Na reabsorption decreases o Filtered load > reabsorption rate o By increasing GFR, the flow of filtrate is fast so Na reabsorption is less Escoto, KC // Gloriani, KP 11 of 16 4. 5. Renal Blood Flow ďź Blood going to the deeper renal tissues in the deeper medulla that will promote Na retention o Countercurrent mechanism Physical Factor ďź Starling forces DIAGRAM: RAAS 1. 2. 3. 4. Renin is produced in the kidney Renin converts angiotensinogen to angiotensin I in the liver Angiotensin I goes to the lungs ACE converts angiotensin I to angiotensin II EFFECTS OF ANGIOTENSIN II - ↑ H2O & Na reabsorb.. Ex. Decrease resistance of afferent arteriole (dilate) ↓ Hydrostatic pressure in the peritubular capillaries increases ↓ Increase Na back leak ↓ Fluid in the peritubular capillaries can go out to the renal tubule ↓ Decrease reabsorption of Na Ex. a) b) c) d) e) Increase glomerular hydrostatic pressure ↓ Increases filtration rate ↓ Increase filtration fraction ↓ Increase oncotic pressure in the peritubular capillaries ↓ Water is attracted – decreasing Na backflow ↓ Increase water reabsorption ↓ Na is also reabsorbed in the PCT – solvent drag Diagram: RAAS; effects of angiotensin II Potentiates sympathetic activity ďź Increase Na reabsorption Increase Na reabsorption in the tubules Potentiates the release of aldosterone ďź Aldosterone will increase Na reabsorption Acts as a vasoconstrictor ďź Decreasing the blood flow ďź Weak vasoconstrictor: afferent arteriole and renal artery ďź Strong vasoconstrictor: efferent arteriole Potentiates ADH release ANGIOTENSIN II ďź released when effective circulation volume drops ďź part of RAAS ďź at the PCT, this will increase Na reabsorption o Na-H antiport ďź LOH, DCT & C: increases Na reabsorption ďź Increases the sensitivity of tubulogolmerular feed back ďź Helps in the contraction of mesangial cells o Decreasing Kf ď decreasing surface area ALDOSTERONE ďź Regulate effective circulating volume ďź When RAAS activated or when we have hyperkalemia o Increases the release of aldosterone ďź Natriuretic peptide and hypokalemia o Decrease aldosterone ďź Hyperkalemia is the more potent for the stimulation of aldosterone release o Hyperkalemia supersedes RAAS ďź Increase Na reabsorption o ↑ Na-Cl symport o ↑ Na-K pump o ↑ ENaC o ↑Sgk1 o ↑CAP1, prostatin ďź Targets DCT, CD and a little bit of LOH for increased NaCl reabsorption ďź Increase K secretion in the DCT and CD N NATRIURETIC PEPTIDE ďź Opposite effects to aldosterone ďź Increase Na clearance o Na goes out together with H2O Escoto, KC // Gloriani, KP 12 of 16 UROGUANYLIN, GUANYLIN ďź Released by GIT and kidneys ďź Decrease Na reabsorption SYMPATETHICS (NOREPINEPHRINE AND EPINEPHRINE) ďź Decrease effective circulating volume drops – activating sympatethics o Increase NaCl and H2O reabsorption ďź Potentiated by RAAS DOPAMINE ďź Increase ECV ď dopamine goes up ďź Decrease NaCl and H2O reabsorption ADRENOMEDULIN ďź Produced by the kidneys ďź When a patient has a congestive heart failure (CHF) or long standing hypertension ď adrenomedulin inreases ďź Increase RBF and GFR ďź Decrease NaCl and H2O reabsorption URODILATIN ďź Produced by the kidney ďź Long standing hypertension & increase ECF volume ď increases urodilatin production ďź Decreases NaCl and H2O reabsorption GLOMERULOTUBLAR BALANCE ďź Increase filtered load ď increase reabsorption rate of Na Increased GFR ↓ ↑ Filtration fraction ↓ ↑ oncotic pressure in the peritubular capillaries due to plasma CHON ↓ Water goes back to peritubular capillaries ↓ Solute is also reabsorbed via solvent drag Increased CHO and Amino acid intake (all of them must be reabsorbed), this will increase Na reabsorption. In Tubuloglormerular / glomerulotubular feedback ď RBF and GFR should be constant. This is also regulated by glomerulotubular balance because it determines the amount of Na going to the macula densa and the macula densa is the one responsible in activating tubuloglomerular feedback. Table: Different segments of your nephron, the percentage of Na being reabsorbed and the different transport mechanisms. You also have your regulatory hormones that will affect reabsorption of Na. RED TEXT – increase reabsorption BLUE TEXT – decrease reabsorption POTASSIUM ďź K secretion depends on Na availability o If Na is available then K will secreted ďź Majority of K reabsorption occurs in PCT ďź K is secreted in the late DCT and CD o Via the principal cells o This is how you regulate K excretion Na not available ↓ Decreased K secretion NOTE: When Na is reabsorbed, K will be secreted in the principal cell For intercalated cells: Metabolic Acidosis – the body will have the preference of secreting H+ instead of K ↓ K secretion decreases (increased plasma K) hyperkalemia EFFECTS OF SYMPATETHICS on K – dual effect ďź Alpha receptor stimulation o Promote K release ďź Beta2 receptor stimulation o Promote K uptake EFFECT OF INSULIN on K ďź Increase K uptake together with glucose EFFECTS OF ALDOSTERONE ďź Increase K secretion ďź Decrease K uptake EFFECT OF METABOLIC & RESPIRATORY ALKALOSIS ďź Opposite to metab acidosis, ↓ plasma K Escoto, KC // Gloriani, KP 13 of 16 RESPIRATORY ACIDOSIS ďź no effect in K homeostasis simply because the lungs will try to correct acid-base disorders CONDITIONS THAT ďŁ PLASMA K ďź Acidosis ďź ↑ plasma osmolality o Decrease in intracellular fluid volume ďź Cell lysis o Potassium goes out of the cell increasing plasma K ďź Exercise o Transient increase in plasma K due to Action potentials o When we produce AP, when we depolarize, Na enters and everytime we repolarize, K goes out increasing plasma K. FACTORS THAT ďŁ K SECRETION ďź Hyperkalemia o Will increase aldestorone production o Aldosterone increases K secretion ďź Aldosterone o Increases K secretion in the DCT and CT o Increase in angiotensin II and plasma K ď increases aldosterone o Decrease in plasma K and natriuretic peptides ď decreases aldosterone ďź ADH o Other than reabsorbing water, it also acts as vasoconstrictors ď§ When BVs are constricted ď ↓GFR ď decreased tubular flow ď decreases K secretion. o In the principal cells, you increase the electrochemical driving force for the exit of K ď increases K secretion o Net effect of K is zero = constant K secretion and excretion ďź ↑ flow of tubular fluid / flow of the filtrate o Increases K secretion o Activates primary cilia ď§ Activates K channels, K goes out o Increase Na in the filtrate ď increase Na uptake ď increased electrochemical driving force for K to exit ďź Glucocorticoids o Mineralocorticoid effects of cortisol (increase Na reabsorption) o Promotes K excretion ďź Acid-base balance o See earlier discussion of alkalosis and acidosis Figure: Potassium handling in the phase of metabolic acidosis where in you have acute and chronic. Acute Metabolic acidosis ďź Decreased in K excretion o The principal cells and intercalated cells will rather retain K and excrete H+ ďź The body will reabsorb K and removes H+ Evolution to Chronic Metabolic Acidosis ďź With a decrease in K excretion, you now slowly goes to chronic metabolic acidosis o This will increase plasma K (hyperkalemia) ďź This will trigger the release of aldosterone o Aldosterone will now promote the release of K from the principal cells ďź So in chronic MA, K goes out Table: Few conditions and how K handling happens. *not discussed by Dr. RAC but he said go over it so I grabbed texts from Apolinario’s trans* Escoto, KC // Gloriani, KP 14 of 16 This is K secretion by the DCT and collecting ducts. If the individual has hyperkalemia, the increase in plasma K has a direct effect on the DCT and collecting tubule increasing its secretion. Hyperkalemia will also increase flow rate. So net effect is K excretion – it goes out. Looking at the effect of aldosterone. In acute, aldosterone will target DCT and collecting ducts promoting K secretion that’s why K secretion goes up. However with the reabsorption of water, flow rate decreases. As far as flow rate is concerned, since renal handling of K is gradient time dependent, in this regard, K excretion decreases. Here you have an increase in K secretion and decrease in K secretion and the net effect is no change. CALCIUM and PHOSPHATE ďź Three hormones will come into play o PTH o Vit. D o Calcitonin ďź Sulphate ďź majority is reabsorbed in PCT ďź Transport Maxima (Tm) = 0.06 mM/min Ammonia (NH3) and Hydrogen ďź Participates in the acid-base regulation ďź NH3 participates in Glutamine metabolism o When Glutamine is metabolized, 2 moles of HCO3 is added into the blood that will participate in acidbase balance Bicarbonate ďź HCO3 participates in acid-base balance. ďź All filtered HCO3 are reabsorbed o Since all HCO3 is reabsorbed, there is excess H compared to HCO3 making the urine acidic ďź Alkalosis: decreased HCO3 reabsorption ďź Acidosis: Increased HCO3 reabsorption Glucose ďź ďź ďź ďź Calcium ďź Protein bound are not filtered ďź Only ionized Ca is filtered and reabsorbed Phosphate ďź Acts as buffers CHLORIDE, MAGNESIUM & SULFATE ďź All are reabsorbed Chloride ďź majority is reabsorbed in PCT ďź passively reabsorbed ďź reabsorption is associated with handling of Na and H2O Magnesium ďź Free Mg is filtered and reabsorbed ďź Reabsorbed through Claudin-16 due to back leak Protein-bound Mg is not filtered Actively reabsorbed (transport maxima) o Maximum rate of absorption TM: 375 mg/min Renal Threshold for reabsorption rate: 220 mg/min Renal Threshold for plasma glucose = 200 mg / dL o If blood glucose levels will exceed 200 mg / dL, it will now start to appear in the urine (glucosuria) Application: (1:31:00) ďˇ If plasma glucose level = 200mg/dL, the amount of glucose being filtered is 200 mg/min ďˇ The reabsorption rate is 220 mg/min ďˇ At this rate, glucose will already start to appear in the urine o Notice that it is much less in the transport maxima How come glucose will start to appear in the urine even though transporter are not saturated? ďˇ Let’s have two side containing nephrons o First side = nephrons containing 300 transporters (300 mg /min of glucose) o 2nd side = 200 transporters (200 mg / min) o TM will be at 300 because that is the maximum transport rate ďˇ A plasma will contain 150 mg of glucose and all of the nephrons will be given 150 mg of glucose o 150 mg of glucose will be reabsorbed by both sides leaving no glucose in the urine Escoto, KC // Gloriani, KP 15 of 16 ďˇ ďˇ ďˇ Another plasma comes and contains 200 mg of glucose o 200 mg of glucose will be reabsorbed by both sides leaving no glucose in the urine Another plasma again comes and contains 250 mg of glucose o The 2nd side will reabsorb 200 mg of glucose o The first side will reabsorb 250 mg of glucose o 50 mg of urine will be left in the urine even though TM is not reached So the answer is NOT ALL NEPHRON CONTAINS THE SAME NUMBER OF TRANSPORTERS o That is why we want to maintain blood glucose level at less than 200 mg/dL Amino acids ďź Different amino acids will have various carriers ďź Tm: 1.5 mM/min Vitamin C ďź Filtered, reabsorbed, and secreted o Depending on the concentration ďź Tm: 2 mg/min ďź ↑ adrenal steroids, ↑ vit c secretion ďź ↑ filtered load of Na, ↑ vit c secretion Urea ďź ďź Filtered and reabsorbed at varying degrees Reabsorption depends on ADH Uric acid ďź Reabsorbed ďź Tm: 15 mg/min Creatine ďź Filtered and REABSORBED ďź No Tm has been demonstrated Creatinine ďź Filtered and SECRETED ďź Tm: 16 mg/min Escoto, KC // Gloriani, KP 16 of 16 Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Autonomic Nervous System (defn) Structures of the nervous system 12 Pairs of Cranial Nerves Portion of the nervous system which controls the visceral functions of the body 1. Cardiac function 2. Blood pressure 3. Respiration 4. Glandular activity 1. Brain 2. Spinal Cord 3. Cranial Nerves 4. Spinal Nerves 5. Ganglia 6. Enteric Plexus 7. Sensory Receptors Mnemonic: Oh Oh Oh To Touch And Feel Very Green Vegetables AH I. Olfactory II. Optic III. Oculomotor IV. V. VI. Trochlear Trigeminal (Opthalmic/Maxillary/Mandibular) Abducens VII. Facial VIII. Vestibulocochlear IX. Glossopharyngeal X. Vagus Nerve 31 Pairs of Spinal Nerves XI. Accessory Nerve XII. Hypoglossal Nerve Note: Cranial Nerves that are part of ANS – III, VII, IX, X 8 Cervical Nerves (C1-C8) 12 Thoracic Nerves (T1-T12) (Note: highlighted - part of ANS) 5 Lumbar Nerves (L1-L5) 5 Sacral Nerves (S1-S5) 5 Components of a Reflex Arc Reflex Arc Activity Sensory Receptors 4 Types of Nerve Fibers Afferent (Sensory) Efferent (Motor) Divisions of the Peripheral Nervous System CPalafox (1A) Cervical Plexus Brachial Plexus Intercostal/Thoracic Nerves Subcostal nerve Lumbar Plexus Sacral Plexus 1 Pair of Coccygeal Nerves/Roots 1. Sensory receptors 2. Afferent nerve – is a sensory nerve, transmits sensory impulses from the sensory receptors to the center 3. Center – CNS (brain and spinal cord) 4. Efferent nerve - is a motor nerve, transmits motor impulses from the center to the different effector cells 5. Effector Cells – four types (Skeletal, cardiac, smooth muscle, glands) 1. Receptor potential – local potential generated by sensory receptors when stimulated. 2. If threshold voltage, Local Potential Action Potential / Sensory Impulse - Transmitted by an afferent nerve to the center. 3. The center will analyze the sensory impulse, and then generate a motor impulse. 4. Motor impulse will be transmitted by efferent nerve to the different effector cells/organs. 5. Effector cells perform the function, as dictated by the motor impulse. Sensory receptors are specialized structures located in almost all parts of the body, stimulated by changes inside/outside the body. 1. Mechanoreceptors (ex. intestinal walls, stretching of walls because of retained food) 2. Thermoreceptors (ex. skin, changes in temperature) 3. Photoreceptors (ex. eyes, changes in the wavelength of light) 4. Chemoreceptors (ex. mouth, chemical composition of food) 5. Baroreceptors (ex. blood vessels, arterial wall is stretched during BP increase) 6. Nociceptors (ex. Free nerve endings – for pain) Somatic Visceral 1. Somatic Afferent (Sensory) 2. Visceral Afferent (Sensory) From: To: From: To: Head CNS Viscera (Internal organs) CNS Body wall Extremeties 3. Somatic Efferent (Motor) 4. Visceral Efferent (Motor) From: To: From: To: CNS Striated Voluntary CNS Internal Organs Muscles (Skeletal Glands Muscles) Smooth and Cardiac (Involuntary) Muscles SOMATIC NERVOUS SYSTEM AUTONOMIC NERVOUS SYSTEM Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Peripheral Nervous System 1. 2. Central Nervous System 1. 2. Difference between Somatic and Autonomic Nervous System PERIPHERAL NERVOUS SYSTEM 12 pairs Cranial Nerves and its branches (originating from the brain stem) 31 pairs Spinal Nerves and its branches (originating from the segments of the spinal cord) CENTRAL NERVOUS SYSTEM Brain Spinal Cord Somatic Autonomic Reflexes VOLUNTARY MOVEMENT / CONSCIOUS / DELIBERATE RESPONSE Function Orients individual to the external environment; bring about movement for locomotion Located in the head, body wall, extremeties • Somatic senses (tactile, thermal, pain and proprioceptive sensations) and • Special senses (vision, hearing, taste, smell and equilibrium) • One-neuron fiber, directly forms a link with the effector cell at the neuromuscular junction (NMJ) Sensory Input/ Receptors Structure of the Efferent Nerve / Fibers single Somatic Efferent Fiber ONE NEURON PATHWAY: • Main Center Effector Cell / Innervation NTA Inhibit or Block transmission of motor impulses Effect if innervation is cut • Excitation / Inhibition • Subdivisions of ANS Enteric NS 1. 2. 3. 4. 5. Anatomical Differences between SNS and PSNS Origin of Pre-ganglionic fiber CPalafox (1A) • Visceral Efferent Fibers divided by the peripheral ganglion (PG) TWO NEURON PATHWAY • Preganglionic (CNS- Preganglion-PG) • Postganglionic (PG-PostganglionEffector) Exception: Adrenal Medulla (CNS-AM) fiber is identical to autonomic preganglionic fibers; cells of AM are identical to autonomic postganglionic fibers CNS - Somatic Efferent Fiber Effector Cell ) Mainly by Cerebral cortex; lesser by basal ganglia, cerebellum, spinal cord Skeletal striated muscle Acetylcholine At 2 locations: Center and NMJ junction • INVOLUNTARY MOVEMENT / UNCONSCIOUS / AUTOMATIC INSTANTANEOUS RESPONSES Note: some are mostly involuntary/partly voluntary (respiration, micturation, defecation) Regulates functions of different internal organs; involved in constancy of internal env. of the body (HOMEOSTASIS) Located in internal organs Associated with interoceptors (sensory receptors in blood vessels, visceral organs, muscles and nervous system) that monitor conditions in the internal environment • Two-neuron fiber, synapse first with peripheral/autonomic ganglion • Autonomic ganglion – neuron outside the CNS; located at the center. No contraction if nerve is cut; complete paralysis, atrophy NON AUTOMATIC cell – ex. Skeletal muscle cell Always leads to excitation of the muscles (Contraction of the skeletal muscle) Hypothalamus, brain stem, spinal cord Visceral/ Smooth, cardiac muscle, or gland cells Acetylcholine and Norepinephrine At 3 locations: Center, Peripheral Ganglia, Neuroeffector Junctions • Can maintain activity • Cardiac – has automatic cell; ex. synoatrial node • Visceral cells also have automatic cells. • AUTOMATIC cell – capable of generating its own action potential spontaneously, independent of stimulation. • Can lead to excitation or inhibition of the effector cells Smooth Muscle: contraction or relaxation; Cardiac: increased or decreased rate and force of contraction; Glands: Increased or decreased secretion of glands) 1. Enteric NS 2. Sympathetic NS (SNS) 3. Parasympathetic NS (PSNS) GIT Has its own nervous system Neurons lie in the GIT wall (esophagus to anus): a. Myenteric or Auerbach Plexus – GIT motor b. Meissner’s plexus regulate secretory activity of GIT Can regulate activities GIT activities but ENTERIC activities are regulated by SNS and PNS. SYMPA postganglionic fibers will synapse with GIT neurons. Indirectly innervates the organs of the GIT. SYMPA stimulation will decrease GIT motor and secretory activities PARASYMPA preganglionic fibers that will synapse with the Enteric NS (like a peripheral ganglion). PARASYMPA stimulation will increase GIT motor and secretory activities SNS PSNS Thoracolumbar division • Craniosacral division Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio 1. Innervates Location of the Peripheral Ganglion (See Fig. 15.2 15.3 of Tortora) Originate from the spinal cord (T1-L3) T1-T2: Head and Neck; smooth muscle of eye and salivary glands 2. T3-T5: Thoracic region; heart, lungs and bronchi 3. T6-T12: Enteric NS; stomach, small intestine, proximal half of large intestine, liver, pancreas and gall bladder 4. L1-L3: distal half of large intestine, rectum, anus, genitourinary system 5. T1-L3: sweat glands and the vascular smooth muscle SYMPATHETIC AND PREVERTEBRAL GANGLIA Near the center and far from effector cells 1. sympathetic chain - 22 pairs of ganglion (beside vertebral column: paravertebral location) • Superior cervical ganglion • Middle cervical ganglion • Stellate ganglion 2. collateral ganglia -3 pairs of ganglion (Abdominal/pelvic region, in front of vertebral column: prevertebral) • Celiac ganglion • Superior mesenteric • Inferior mesenteric 1. 2. 1. TERMINAL GANGLIA A. Ganglia far from the center but near the effector cells 1. III Oculomotor: celiary ganglion: smooth muscle of the eye 2. VII Facial: a. pterigopalatine ganglion: nasal and lacrimal glands b. Submandibular ganglion: submandibular glands 3. IX Glossopharyngeal: otic ganglion: parotid glands B. 4. Length Branching of Preganglionic fibers Neurotransmitter Agent Locations where NTAs are released Steps in Biochemical Transmission CPalafox (1A) Ganglia far from the center and inside the effector cell X Vagus, Sacral parasympathetic nerves (pelvic nerves) a. Vagus nerve: • Thoracic cavity (heart, lungs, bronchi) • Abdomen (Esophagus, stomach, small intestine, proximal half of the large intestine, Liver, pancreas, gall bladder) b. Pelvic nerves: Distal half of large intestine, rectum, anus, genitourinary system • • • • • Preganglionic fiber < Postganglionic fiber Short Pre Long Post Extensive branching 1 Pre : 20post Sympathetic effects are more widespread and diffuse 1. 2. 1. 2. 1. Cholinergic Transmission – mediated by Acetylcholine (Ach) Noradrenergic or Adrenergic transmission – by Norepinephrine (Nor) Somatic Efferent : NMJ Autonomic Efferent: region of peripheral ganglion and neuroeffector junction Synthesis and Storage of neurotransmitter agent – synthesis in the ribosomes; stored in secretory vesicles Release of NTA at the synaptic cleft – motor impulse reaches nerve ending; highly permeable to Calcium ions (influx); interaction of membrane proteins - Syntaxin and synaptobrevin – cause vesicles to fuse with nerve terminal membrane; exocytose the NTA into the synaptic cleft Interaction - NTA binds with receptors and elicits a physiologic response from effector cell Deactivation of NTA – unbinding from the receptor Ligand-activated / Ion channels 2. G-Protein coupled receptor NTA + Receptor Opens specific ion channels NTA + Receptor activate G-proteins bound to a. If Na+ channels, Na+ influx, depolarization the inner surface of the cell membrane will lead to excitation Activate specific intracellular (I/C) enzymes b. If K+ channels, K+ efflux, hyperpolarization that will lead to formation of intracellular will lead to inhibition ligands (aka Second Messengers), which c. If channels are on effector cell, elicit an will mediate the action of the NTA on the immediate but short-lived response from effector cell. the effector cell. Produces a delayed response but longer Ex. Ach binding to nicotinic receptors on duration that persists even if NTA is no membrane of skeletal muscle cell longer present Ach+Nicotinic: Ligand-gated channel a. NTA + Receptor activate G-Proteins activate enzyme system, (+) Adenylyl cyclase formation of ↑cAMP (cyclic 2. INTERACTION STEP / Membrane Receptors Some originate from brain stem (CN III, VII, IX, X) Some originate from spinal cord (S2-S4) 3. 4. 1. • • • • • Preganglionic fiber > Postganglionic fiber Long Pre Short Post Limited branching 1Pre : 1Post PS Effects are more localized except those of the vagus nerve Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio b. Deactivation of NTA Cholinergic transmission is present in: Adrenergic transmission is present in: adenosyl monophosphate is the I/C ligand or second messenger) activate (+) protein kinase A phosphorylation of other enzymes that will elicit specific responses from the cell Ex. Catecholamines (Nor, EP) + beta receptors; Acetylcholine + muscarinic receptors beta receptors and muscarinic receptors are G-protein coupled receptors NTA + Receptor activate G-Proteins activate enzyme system, (+) phospholipase C breakdown of phosphoinositol biphosphate PIP2, forming 2 products: i. Inositol triphosphate IP3 increase I/C Ca2+; Calcium can function as second messenger ii. Diacyl glycerol DAG (+) Protein kinase C causes phosphorylation of I/C proteins stimulate specific biochemical responses from the cell Ex. Catecholamines + alpha receptors; Acetylcholine + muscarinic receptors (depending on the location in the body) Enzymatic deactivation - deactivation by enzymes in the synaptic cleft Ex. Ach deactivation by acetylcholinesterase 1. Cholinergic effects short in duration Re-uptake Ex. Deactivation of norepinephrine 1. After unbinding from the receptor 2. Actively transported back in the terminal but will not be stored in vesicles. These will be destroyed by monoamineoxidase 3. Other NEP: circulated in the blood and transported to the liver, where NEP is deactivated by enzyme catechol-O-methyl transferase (COMT) 1. All somatic neuromuscular junction (Somatic to skeletal muscle) 2. All autonomic ganglia (all preganglionic to all postganglionic in both SNS and PSNS) 3. All parasympathetic neuroeffector junctions (all PS effects to internal organs; biochemically, PSNS is referred as Cholinergic division; PSNS division is craniosacral (anatomically) and cholinergic (biochemically)) 4. Sympathetic cholinergic neuroeffector junctions, only if effectors are sweat glands and vascular smooth muscles present in skeletal muscles. 5. All sympathetic adrenergic neuroeffector junction. (all sympathetic effects to internal organs) Sympathetic division is thoracolumbar (anatomically) and noradrenergic (biochemically). Somatic NS Parasympathetic NS Sympathetic Cholinergic Sympathetic Adrenergic (Syncholinergic) NS (Synadrenergic) NS C C C Ach EC Ach PG PG Ach Ach EC C Ach EC ** Only in sweat glands and vascular smooth muscles present in skeletal muscles Cholinergic Transmission CPalafox (1A) Ach PG NEP EC ** most sympathetic effects to internal organs are mediated by NEP Transmission mediated by Acetylcholine 1. Synthesis of Acetylcholine: Choline + Acetyl CoA Ach, catalyzed by choline acetyl transferase. It will be stored temporarily in vesicles located at the nerve ending. 2. (Release) When an AP reaches the nerve ending, there will be Ca2+ influx, which will cause Ach to be released into the synaptic cleft. 3. (Interaction) Ach binds to membrane receptors (cholinergic receptor) on the effector cell. 4. (Deactivation) Main mechanism is enzymatic destruction/deactivation by acetylcholinesterase, which is Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio also present in the synaptic cleft, where it can immediately deactivate acetylcholine. This makes cholinergic or Parasympathetic effects short in duration. 1. Nicotinic – can also be stimulated by small dose 2. Muscarinic – can be stimulated by small doses of nicotine of muscarine a. Present in all somatic neuromuscular a. all parasympathetic neuroeffector junction junction (membrane of skeletal muscle b. all sympathetic cholinergic neuroeffector cells contain Nicotinic receptors) junction (sweat glands, vascular smooth b. Present in all autonomic peripheral muscle present in the skeletal muscle Subdivided into M1-M5: ganglia c. c. Mainly made of proteins, classified as • M1 – brain, stomach (if M1 receptors Ligand-gated receptor: (+) open Na+ in stomach is stimulated, increase in channel gastric secretion) d. Always elicits an excitatory reaction • M2 – most abundant heart and visceral smooth muscles • M3 – visceral smooth muscles and glands • M4 – visceral smooth muscles and glands • M5 – least abundant; present only in sphincter muscles of the iris, esophagus, parotid glands, cerebral blood vessels d. G-protein coupled receptor response may be either excitatory or inhibitors Transmission mediated by NEP 1. Synthesis of NEP: a. Steps: phenylalanine β tyrosine, catalyzed by phenylalanine hydroxylase. β tyrosine DOPA, catalyzed by tyrosine hydroxylase. DOPA Dopamine, catalyzed by DOPA decarboxylase. Dopamine Norepinephrine, catalyzed by dopamine β-hydroxylase. b. Location: at the nerve ending of sympathetic adrenergic efferent / postganglionic nerve endings. c. Regulation: by a negative feedback mechanism; if there is an excess of dopamine and norepinephrine, it will cause inhibition of the enzyme tyrosine hydroxylase. d. A sagittal section of adrenal glands reveals 2 parts: outer part: adrenal cortex (secretes steroid hormones) and inner part: adrenal medulla (converts norepinephrine epinephrine, catalyzed by phenylethanolamine-N-methyl transferase). e. Sympathetic adrenergic postganglionic nerve endings can synthesize/release NEP only. Adrenal medulla can synthesize/release both NEP and EP (collectively known as catecholamines). 2. (Release) When an AP reaches the nerve ending, there will be Ca2+ influx, which will cause NEP to be released into the synaptic cleft. 3. (Interaction) NEP or EP binds to membrane receptors (noradrenergic or adrenergic receptors) on the effector cell. 4. (Deactivation) Main mechanism is reuptake. Actively transported back in the terminal but will not be stored in vesicles. These will be destroyed by monoamineoxidase. Other NEP: circulated in the blood and transported to the liver, where NEP is deactivated by enzyme catechol-O-methyl transferase (COMT). This makes adrenergic or Parasympathetic effects short in duration. Types of Cholinergic receptors Adrenergic Transmission 4 Types of Adrenergic receptors 1. α1 a. 2. • • Organ Heart CPalafox (1A) 4. α2 a. b. • 3. Present in visceral smooth muscles and glands Present only at nerve terminal NEP+ α2 NEP inhibition Negative feedback mechanism, inhibit further release of norepinephrine Alpha receptors when stimulated, mostly elicit excitatory reaction (exemptions below) Examples: NEP+ α1 Radial muscle of iris, muscle contracts (excitatory) = increase in pupillary size; EP+ α1 vascular smooth muscle, muscle contracts (excitatory) = vasoconstriction Exemptions: Digestive system, pancreatic islets, bronchial gland, effects are inhibitory Cholinergic M2 • • • β1 a. Only in heart β2 a. Present in visceral smooth muscles and glands Beta receptors when stimulated, elicit mostly inhibitory reaction (exemptions below) Examples: NEP + smooth muscle receptors in Bronchial wall, smooth muscles relax = broncodilation; EP+ β2 Vascular smooth muscle, muscle relaxes = vasodilation Exemptions: heart, bronchial glands, pancreatic islets, effects are excitatory Adrenergic: β1 Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Salivary glands Intestinal wall Bronchial Adrenal Medulla: Differentiate from other visceral organs in the body: Difference from the rest of the sympathetic adrenergic system: M3-M4 M2-M3-M4 M3-M4 Sympathetic: innervated by postganglionic fibers Sympathetic adrenergic: release NEP to immediate vicinity of neuroeffectors α1, β2 α1, β2 α1, β2 Adrenal Medulla AM is innervated by pre-ganglionic fibers.Cells of AM are histologically similar to a sympathethic ganglion • When the sympathetic division is stimulated, the AM is also stimulated, which causes it to release NEP and EP. These NTA are released and circulated in the blood stream, and are distributed to sympathetic neuroeffector junctions in all parts of the body. • Reinforces/potentiates the sympathetic adrenergic effects. • AM considered a part of sympathetic adrenergic nervous system Sympathetic preganglionic fibers Ach (N) Adrenal Medulla NEP + EP *** Circulation (+)α1, β1, β2 receptors *** ↑sympathetic adrenergic effects *** Comparison between the effects of NEP and EP • NEP is a strong stimulator of α and β1 receptors but is a weak stimulator of β2. • EP is a strong stimulator of α1, β1, β2 receptors. Dual Innervation and Antagonistic Effects Physiologic/Functional Differences between Sympathetic and Parasympathetic Nerves Energy Duration Effects CPalafox (1A) • Sympathetic NS and PSNS are PHYSIOLOGIC ANTAGONISTS, produces opposite effects. 1. Dual innervation of the SAME structure of the SAME organ produces OPPOSITE effects. Ex. Heart Sympathetic N (↑HR) SA Node ď Vagus/CNX, Parasympathetic (↓HR) 2. Dual innervation of 2 DIFFERENT structures in the SAME organ produces OPPOSITE effects. Ex. Eyeball – Pupil regulates the amount of light entering the eye Iris: radial muscle (Sympathetic): absence of light pupil dilates Sphincter muscle (Oculomotor CN3 parasympathetic): presence of light pupil constricts 3. Dual innervation of 2 DIFFERENT structures in the SAME organ produces SYNERGISTIC effects. Ex. Salivary gland Para: profuse increase in salivary secretion: loose, watery secretion Sympa: mild moderate increase in salivary secretion: viscous secretion 4. Single innervations No parasympathetic innervation. Sympathetic innervation only. Ex. Kidneys, sweat gland, pilo arrector muscle in skin, vascular smooth muscle SyNS PSNS Catabolic Longer, Prolonged duration Reason: Norepinephrine at NEJ that is not immediately deactivated; additionally mediated by norepinephrine and epinephrine in the blood stream Fight-or-Flight Stimulation of sympathetic nerves enables individuals to cope or withstand stressful conditions Anabolic Short duration Reason: Mediated by Ach, immediately deactivated Rest/Digest Conservation/restoration of the body’s processes Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Fight-or-Flight (Catabolic) ↑HR ↑BP Nor Epi Response Timing Center Rest/Digest (Anabolic) ↓HR ↓BP β1 Peripheral Vasoconstriction α1 M2, M3 Peripheral Vasodilation Ach ↑Lipid Breakdown β2 ↓Lipid Breakdown Coronary Dilation Bronchial Dilation β2 Bronchoconstriction Glycogen Glucose β2 Generalized, diffuse response Reason: extensive branching of the preganglionic fibers Coordinated; response occurs at the same time Muscarinic receptor Nicotinic receptors M3 M3 Glucose Glycogen Localized response, except for Vagus nerve Reason: limited branching, except for Vagus nerve Coordinated; but some processes do not have to occur at the same time (ex. micturation, defecation, erection) Head ganglion of the ANS – Hypothalamus • Anterior hypothalamus – coordinates Cholinergic activities • Posterior/ Lateral hypothalamus – coordinates Adrenergic activities Example: Baroreceptor Reflex Increased Arterial Blood Pressure (ABP) stretch arterial walls (+) Baroreceptor (-)/inhibit Vasomotor center (medulla) Decrease sympathetic outflow Increase parasympathetic outflow Vasodilation Decrease cardiac activity Decrease cardiac activity Decrease ABP Decrease ABP Pharmacological Differences A. B. CPalafox (1A) Parasympathetic Cholinergic ↑ / Potentiate cholinergic or parasympathetic effect ↑ synthesis of Ach ↑ release of Ach ↑ interaction between Ach and cholinergic receptor (-) deactivation of Ach PARASYMPATHOMIMETIC –mimics the effects of parasympathetic stimulation Anticholinergic ↓ / Block cholinergic or parasympathetic effect synthesis of Ach ↓ release of Ach Block interaction between Ach and cholinergic receptor ↑ inactivation of Ach PARASYMPATHOLYTIC A. B. Sympathetic Adrenergic Adrenergic ↑ / Potentiate adrenergic or sympathetic effect ↑ synthesis of NEP ↑ release of NEP ↑ interaction between NEP and adrenergic receptor (-) inactivation of NEP SYMPATHOMIMETIC –mimics the effects of sympathetic stimulation Antiadrenergic ↓ / Block adrenergic or sympathetic effect synthesis of NEP ↓ release of NEP Block interaction between NEP and adrenergic receptor ↑ deactivation of NEP SYMPATHOLYTIC Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Autonomic Nervous System (defn) Structures of the nervous system 12 Pairs of Cranial Nerves Portion of the nervous system which controls the visceral functions of the body 1. Cardiac function 2. Blood pressure 3. Respiration 4. Glandular activity 1. Brain 2. Spinal Cord 3. Cranial Nerves 4. Spinal Nerves 5. Ganglia 6. Enteric Plexus 7. Sensory Receptors Mnemonic: Oh Oh Oh To Touch And Feel Very Green Vegetables AH I. Olfactory II. Optic III. Oculomotor IV. V. VI. Trochlear Trigeminal (Opthalmic/Maxillary/Mandibular) Abducens VII. Facial VIII. Vestibulocochlear IX. Glossopharyngeal X. Vagus Nerve 31 Pairs of Spinal Nerves XI. Accessory Nerve XII. Hypoglossal Nerve Note: Cranial Nerves that are part of ANS – III, VII, IX, X 8 Cervical Nerves (C1-C8) 12 Thoracic Nerves (T1-T12) (Note: highlighted - part of ANS) 5 Lumbar Nerves (L1-L5) 5 Sacral Nerves (S1-S5) 5 Components of a Reflex Arc Reflex Arc Activity Sensory Receptors 4 Types of Nerve Fibers Afferent (Sensory) Efferent (Motor) Divisions of the Peripheral Nervous System CPalafox (1A) Cervical Plexus Brachial Plexus Intercostal/Thoracic Nerves Subcostal nerve Lumbar Plexus Sacral Plexus 1 Pair of Coccygeal Nerves/Roots 1. Sensory receptors 2. Afferent nerve – is a sensory nerve, transmits sensory impulses from the sensory receptors to the center 3. Center – CNS (brain and spinal cord) 4. Efferent nerve - is a motor nerve, transmits motor impulses from the center to the different effector cells 5. Effector Cells – four types (Skeletal, cardiac, smooth muscle, glands) 1. Receptor potential – local potential generated by sensory receptors when stimulated. 2. If threshold voltage, Local Potential Action Potential / Sensory Impulse - Transmitted by an afferent nerve to the center. 3. The center will analyze the sensory impulse, and then generate a motor impulse. 4. Motor impulse will be transmitted by efferent nerve to the different effector cells/organs. 5. Effector cells perform the function, as dictated by the motor impulse. Sensory receptors are specialized structures located in almost all parts of the body, stimulated by changes inside/outside the body. 1. Mechanoreceptors (ex. intestinal walls, stretching of walls because of retained food) 2. Thermoreceptors (ex. skin, changes in temperature) 3. Photoreceptors (ex. eyes, changes in the wavelength of light) 4. Chemoreceptors (ex. mouth, chemical composition of food) 5. Baroreceptors (ex. blood vessels, arterial wall is stretched during BP increase) 6. Nociceptors (ex. Free nerve endings – for pain) Somatic Visceral 1. Somatic Afferent (Sensory) 2. Visceral Afferent (Sensory) From: To: From: To: Head CNS Viscera (Internal organs) CNS Body wall Extremeties 3. Somatic Efferent (Motor) 4. Visceral Efferent (Motor) From: To: From: To: CNS Striated Voluntary CNS Internal Organs Muscles (Skeletal Glands Muscles) Smooth and Cardiac (Involuntary) Muscles SOMATIC NERVOUS SYSTEM AUTONOMIC NERVOUS SYSTEM Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Peripheral Nervous System 1. 2. Central Nervous System 1. 2. Difference between Somatic and Autonomic Nervous System PERIPHERAL NERVOUS SYSTEM 12 pairs Cranial Nerves and its branches (originating from the brain stem) 31 pairs Spinal Nerves and its branches (originating from the segments of the spinal cord) CENTRAL NERVOUS SYSTEM Brain Spinal Cord Somatic Autonomic Reflexes VOLUNTARY MOVEMENT / CONSCIOUS / DELIBERATE RESPONSE Function Orients individual to the external environment; bring about movement for locomotion Located in the head, body wall, extremeties • Somatic senses (tactile, thermal, pain and proprioceptive sensations) and • Special senses (vision, hearing, taste, smell and equilibrium) • One-neuron fiber, directly forms a link with the effector cell at the neuromuscular junction (NMJ) Sensory Input/ Receptors Structure of the Efferent Nerve / Fibers single Somatic Efferent Fiber ONE NEURON PATHWAY: • Main Center Effector Cell / Innervation NTA Inhibit or Block transmission of motor impulses Effect if innervation is cut • Excitation / Inhibition • Subdivisions of ANS Enteric NS 1. 2. 3. 4. 5. Anatomical Differences between SNS and PSNS Origin of Pre-ganglionic fiber CPalafox (1A) • Visceral Efferent Fibers divided by the peripheral ganglion (PG) TWO NEURON PATHWAY • Preganglionic (CNS- Preganglion-PG) • Postganglionic (PG-PostganglionEffector) Exception: Adrenal Medulla (CNS-AM) fiber is identical to autonomic preganglionic fibers; cells of AM are identical to autonomic postganglionic fibers CNS - Somatic Efferent Fiber Effector Cell ) Mainly by Cerebral cortex; lesser by basal ganglia, cerebellum, spinal cord Skeletal striated muscle Acetylcholine At 2 locations: Center and NMJ junction • INVOLUNTARY MOVEMENT / UNCONSCIOUS / AUTOMATIC INSTANTANEOUS RESPONSES Note: some are mostly involuntary/partly voluntary (respiration, micturation, defecation) Regulates functions of different internal organs; involved in constancy of internal env. of the body (HOMEOSTASIS) Located in internal organs Associated with interoceptors (sensory receptors in blood vessels, visceral organs, muscles and nervous system) that monitor conditions in the internal environment • Two-neuron fiber, synapse first with peripheral/autonomic ganglion • Autonomic ganglion – neuron outside the CNS; located at the center. No contraction if nerve is cut; complete paralysis, atrophy NON AUTOMATIC cell – ex. Skeletal muscle cell Always leads to excitation of the muscles (Contraction of the skeletal muscle) Hypothalamus, brain stem, spinal cord Visceral/ Smooth, cardiac muscle, or gland cells Acetylcholine and Norepinephrine At 3 locations: Center, Peripheral Ganglia, Neuroeffector Junctions • Can maintain activity • Cardiac – has automatic cell; ex. synoatrial node • Visceral cells also have automatic cells. • AUTOMATIC cell – capable of generating its own action potential spontaneously, independent of stimulation. • Can lead to excitation or inhibition of the effector cells Smooth Muscle: contraction or relaxation; Cardiac: increased or decreased rate and force of contraction; Glands: Increased or decreased secretion of glands) 1. Enteric NS 2. Sympathetic NS (SNS) 3. Parasympathetic NS (PSNS) GIT Has its own nervous system Neurons lie in the GIT wall (esophagus to anus): a. Myenteric or Auerbach Plexus – GIT motor b. Meissner’s plexus regulate secretory activity of GIT Can regulate activities GIT activities but ENTERIC activities are regulated by SNS and PNS. SYMPA postganglionic fibers will synapse with GIT neurons. Indirectly innervates the organs of the GIT. SYMPA stimulation will decrease GIT motor and secretory activities PARASYMPA preganglionic fibers that will synapse with the Enteric NS (like a peripheral ganglion). PARASYMPA stimulation will increase GIT motor and secretory activities SNS PSNS Thoracolumbar division • Craniosacral division Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio 1. Innervates Location of the Peripheral Ganglion (See Fig. 15.2 15.3 of Tortora) Originate from the spinal cord (T1-L3) T1-T2: Head and Neck; smooth muscle of eye and salivary glands 2. T3-T5: Thoracic region; heart, lungs and bronchi 3. T6-T12: Enteric NS; stomach, small intestine, proximal half of large intestine, liver, pancreas and gall bladder 4. L1-L3: distal half of large intestine, rectum, anus, genitourinary system 5. T1-L3: sweat glands and the vascular smooth muscle SYMPATHETIC AND PREVERTEBRAL GANGLIA Near the center and far from effector cells 1. sympathetic chain - 22 pairs of ganglion (beside vertebral column: paravertebral location) • Superior cervical ganglion • Middle cervical ganglion • Stellate ganglion 2. collateral ganglia -3 pairs of ganglion (Abdominal/pelvic region, in front of vertebral column: prevertebral) • Celiac ganglion • Superior mesenteric • Inferior mesenteric 1. 2. 1. TERMINAL GANGLIA A. Ganglia far from the center but near the effector cells 1. III Oculomotor: celiary ganglion: smooth muscle of the eye 2. VII Facial: a. pterigopalatine ganglion: nasal and lacrimal glands b. Submandibular ganglion: submandibular glands 3. IX Glossopharyngeal: otic ganglion: parotid glands B. 4. Length Branching of Preganglionic fibers Neurotransmitter Agent Locations where NTAs are released Steps in Biochemical Transmission CPalafox (1A) Ganglia far from the center and inside the effector cell X Vagus, Sacral parasympathetic nerves (pelvic nerves) a. Vagus nerve: • Thoracic cavity (heart, lungs, bronchi) • Abdomen (Esophagus, stomach, small intestine, proximal half of the large intestine, Liver, pancreas, gall bladder) b. Pelvic nerves: Distal half of large intestine, rectum, anus, genitourinary system • • • • • Preganglionic fiber < Postganglionic fiber Short Pre Long Post Extensive branching 1 Pre : 20post Sympathetic effects are more widespread and diffuse 1. 2. 1. 2. 1. Cholinergic Transmission – mediated by Acetylcholine (Ach) Noradrenergic or Adrenergic transmission – by Norepinephrine (Nor) Somatic Efferent : NMJ Autonomic Efferent: region of peripheral ganglion and neuroeffector junction Synthesis and Storage of neurotransmitter agent – synthesis in the ribosomes; stored in secretory vesicles Release of NTA at the synaptic cleft – motor impulse reaches nerve ending; highly permeable to Calcium ions (influx); interaction of membrane proteins - Syntaxin and synaptobrevin – cause vesicles to fuse with nerve terminal membrane; exocytose the NTA into the synaptic cleft Interaction - NTA binds with receptors and elicits a physiologic response from effector cell Deactivation of NTA – unbinding from the receptor Ligand-activated / Ion channels 2. G-Protein coupled receptor NTA + Receptor Opens specific ion channels NTA + Receptor activate G-proteins bound to a. If Na+ channels, Na+ influx, depolarization the inner surface of the cell membrane will lead to excitation Activate specific intracellular (I/C) enzymes b. If K+ channels, K+ efflux, hyperpolarization that will lead to formation of intracellular will lead to inhibition ligands (aka Second Messengers), which c. If channels are on effector cell, elicit an will mediate the action of the NTA on the immediate but short-lived response from effector cell. the effector cell. Produces a delayed response but longer Ex. Ach binding to nicotinic receptors on duration that persists even if NTA is no membrane of skeletal muscle cell longer present Ach+Nicotinic: Ligand-gated channel a. NTA + Receptor activate G-Proteins activate enzyme system, (+) Adenylyl cyclase formation of ↑cAMP (cyclic 2. INTERACTION STEP / Membrane Receptors Some originate from brain stem (CN III, VII, IX, X) Some originate from spinal cord (S2-S4) 3. 4. 1. • • • • • Preganglionic fiber > Postganglionic fiber Long Pre Short Post Limited branching 1Pre : 1Post PS Effects are more localized except those of the vagus nerve Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio b. Deactivation of NTA Cholinergic transmission is present in: Adrenergic transmission is present in: adenosyl monophosphate is the I/C ligand or second messenger) activate (+) protein kinase A phosphorylation of other enzymes that will elicit specific responses from the cell Ex. Catecholamines (Nor, EP) + beta receptors; Acetylcholine + muscarinic receptors beta receptors and muscarinic receptors are G-protein coupled receptors NTA + Receptor activate G-Proteins activate enzyme system, (+) phospholipase C breakdown of phosphoinositol biphosphate PIP2, forming 2 products: i. Inositol triphosphate IP3 increase I/C Ca2+; Calcium can function as second messenger ii. Diacyl glycerol DAG (+) Protein kinase C causes phosphorylation of I/C proteins stimulate specific biochemical responses from the cell Ex. Catecholamines + alpha receptors; Acetylcholine + muscarinic receptors (depending on the location in the body) Enzymatic deactivation - deactivation by enzymes in the synaptic cleft Ex. Ach deactivation by acetylcholinesterase 1. Cholinergic effects short in duration Re-uptake Ex. Deactivation of norepinephrine 1. After unbinding from the receptor 2. Actively transported back in the terminal but will not be stored in vesicles. These will be destroyed by monoamineoxidase 3. Other NEP: circulated in the blood and transported to the liver, where NEP is deactivated by enzyme catechol-O-methyl transferase (COMT) 1. All somatic neuromuscular junction (Somatic to skeletal muscle) 2. All autonomic ganglia (all preganglionic to all postganglionic in both SNS and PSNS) 3. All parasympathetic neuroeffector junctions (all PS effects to internal organs; biochemically, PSNS is referred as Cholinergic division; PSNS division is craniosacral (anatomically) and cholinergic (biochemically)) 4. Sympathetic cholinergic neuroeffector junctions, only if effectors are sweat glands and vascular smooth muscles present in skeletal muscles. 5. All sympathetic adrenergic neuroeffector junction. (all sympathetic effects to internal organs) Sympathetic division is thoracolumbar (anatomically) and noradrenergic (biochemically). Somatic NS Parasympathetic NS Sympathetic Cholinergic Sympathetic Adrenergic (Syncholinergic) NS (Synadrenergic) NS C C C Ach EC Ach PG PG Ach Ach EC C Ach EC ** Only in sweat glands and vascular smooth muscles present in skeletal muscles Cholinergic Transmission CPalafox (1A) Ach PG NEP EC ** most sympathetic effects to internal organs are mediated by NEP Transmission mediated by Acetylcholine 1. Synthesis of Acetylcholine: Choline + Acetyl CoA Ach, catalyzed by choline acetyl transferase. It will be stored temporarily in vesicles located at the nerve ending. 2. (Release) When an AP reaches the nerve ending, there will be Ca2+ influx, which will cause Ach to be released into the synaptic cleft. 3. (Interaction) Ach binds to membrane receptors (cholinergic receptor) on the effector cell. 4. (Deactivation) Main mechanism is enzymatic destruction/deactivation by acetylcholinesterase, which is Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio also present in the synaptic cleft, where it can immediately deactivate acetylcholine. This makes cholinergic or Parasympathetic effects short in duration. 1. Nicotinic – can also be stimulated by small dose 2. Muscarinic – can be stimulated by small doses of nicotine of muscarine a. Present in all somatic neuromuscular a. all parasympathetic neuroeffector junction junction (membrane of skeletal muscle b. all sympathetic cholinergic neuroeffector cells contain Nicotinic receptors) junction (sweat glands, vascular smooth b. Present in all autonomic peripheral muscle present in the skeletal muscle Subdivided into M1-M5: ganglia c. c. Mainly made of proteins, classified as • M1 – brain, stomach (if M1 receptors Ligand-gated receptor: (+) open Na+ in stomach is stimulated, increase in channel gastric secretion) d. Always elicits an excitatory reaction • M2 – most abundant heart and visceral smooth muscles • M3 – visceral smooth muscles and glands • M4 – visceral smooth muscles and glands • M5 – least abundant; present only in sphincter muscles of the iris, esophagus, parotid glands, cerebral blood vessels d. G-protein coupled receptor response may be either excitatory or inhibitors Transmission mediated by NEP 1. Synthesis of NEP: a. Steps: phenylalanine β tyrosine, catalyzed by phenylalanine hydroxylase. β tyrosine DOPA, catalyzed by tyrosine hydroxylase. DOPA Dopamine, catalyzed by DOPA decarboxylase. Dopamine Norepinephrine, catalyzed by dopamine β-hydroxylase. b. Location: at the nerve ending of sympathetic adrenergic efferent / postganglionic nerve endings. c. Regulation: by a negative feedback mechanism; if there is an excess of dopamine and norepinephrine, it will cause inhibition of the enzyme tyrosine hydroxylase. d. A sagittal section of adrenal glands reveals 2 parts: outer part: adrenal cortex (secretes steroid hormones) and inner part: adrenal medulla (converts norepinephrine epinephrine, catalyzed by phenylethanolamine-N-methyl transferase). e. Sympathetic adrenergic postganglionic nerve endings can synthesize/release NEP only. Adrenal medulla can synthesize/release both NEP and EP (collectively known as catecholamines). 2. (Release) When an AP reaches the nerve ending, there will be Ca2+ influx, which will cause NEP to be released into the synaptic cleft. 3. (Interaction) NEP or EP binds to membrane receptors (noradrenergic or adrenergic receptors) on the effector cell. 4. (Deactivation) Main mechanism is reuptake. Actively transported back in the terminal but will not be stored in vesicles. These will be destroyed by monoamineoxidase. Other NEP: circulated in the blood and transported to the liver, where NEP is deactivated by enzyme catechol-O-methyl transferase (COMT). This makes adrenergic or Parasympathetic effects short in duration. Types of Cholinergic receptors Adrenergic Transmission 4 Types of Adrenergic receptors 1. α1 a. 2. • • Organ Heart CPalafox (1A) 4. α2 a. b. • 3. Present in visceral smooth muscles and glands Present only at nerve terminal NEP+ α2 NEP inhibition Negative feedback mechanism, inhibit further release of norepinephrine Alpha receptors when stimulated, mostly elicit excitatory reaction (exemptions below) Examples: NEP+ α1 Radial muscle of iris, muscle contracts (excitatory) = increase in pupillary size; EP+ α1 vascular smooth muscle, muscle contracts (excitatory) = vasoconstriction Exemptions: Digestive system, pancreatic islets, bronchial gland, effects are inhibitory Cholinergic M2 • • • β1 a. Only in heart β2 a. Present in visceral smooth muscles and glands Beta receptors when stimulated, elicit mostly inhibitory reaction (exemptions below) Examples: NEP + smooth muscle receptors in Bronchial wall, smooth muscles relax = broncodilation; EP+ β2 Vascular smooth muscle, muscle relaxes = vasodilation Exemptions: heart, bronchial glands, pancreatic islets, effects are excitatory Adrenergic: β1 Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Salivary glands Intestinal wall Bronchial Adrenal Medulla: Differentiate from other visceral organs in the body: Difference from the rest of the sympathetic adrenergic system: M3-M4 M2-M3-M4 M3-M4 Sympathetic: innervated by postganglionic fibers Sympathetic adrenergic: release NEP to immediate vicinity of neuroeffectors α1, β2 α1, β2 α1, β2 Adrenal Medulla AM is innervated by pre-ganglionic fibers.Cells of AM are histologically similar to a sympathethic ganglion • When the sympathetic division is stimulated, the AM is also stimulated, which causes it to release NEP and EP. These NTA are released and circulated in the blood stream, and are distributed to sympathetic neuroeffector junctions in all parts of the body. • Reinforces/potentiates the sympathetic adrenergic effects. • AM considered a part of sympathetic adrenergic nervous system Sympathetic preganglionic fibers Ach (N) Adrenal Medulla NEP + EP *** Circulation (+)α1, β1, β2 receptors *** ↑sympathetic adrenergic effects *** Comparison between the effects of NEP and EP • NEP is a strong stimulator of α and β1 receptors but is a weak stimulator of β2. • EP is a strong stimulator of α1, β1, β2 receptors. Dual Innervation and Antagonistic Effects Physiologic/Functional Differences between Sympathetic and Parasympathetic Nerves Energy Duration Effects CPalafox (1A) • Sympathetic NS and PSNS are PHYSIOLOGIC ANTAGONISTS, produces opposite effects. 1. Dual innervation of the SAME structure of the SAME organ produces OPPOSITE effects. Ex. Heart Sympathetic N (↑HR) SA Node ď Vagus/CNX, Parasympathetic (↓HR) 2. Dual innervation of 2 DIFFERENT structures in the SAME organ produces OPPOSITE effects. Ex. Eyeball – Pupil regulates the amount of light entering the eye Iris: radial muscle (Sympathetic): absence of light pupil dilates Sphincter muscle (Oculomotor CN3 parasympathetic): presence of light pupil constricts 3. Dual innervation of 2 DIFFERENT structures in the SAME organ produces SYNERGISTIC effects. Ex. Salivary gland Para: profuse increase in salivary secretion: loose, watery secretion Sympa: mild moderate increase in salivary secretion: viscous secretion 4. Single innervations No parasympathetic innervation. Sympathetic innervation only. Ex. Kidneys, sweat gland, pilo arrector muscle in skin, vascular smooth muscle SyNS PSNS Catabolic Longer, Prolonged duration Reason: Norepinephrine at NEJ that is not immediately deactivated; additionally mediated by norepinephrine and epinephrine in the blood stream Fight-or-Flight Stimulation of sympathetic nerves enables individuals to cope or withstand stressful conditions Anabolic Short duration Reason: Mediated by Ach, immediately deactivated Rest/Digest Conservation/restoration of the body’s processes Physiology A: AUTONOMIC NERVOUS SYSTEM Lectured by: Dr. Valerio Fight-or-Flight (Catabolic) ↑HR ↑BP Nor Epi Response Timing Center Rest/Digest (Anabolic) ↓HR ↓BP β1 Peripheral Vasoconstriction α1 M2, M3 Peripheral Vasodilation Ach ↑Lipid Breakdown β2 ↓Lipid Breakdown Coronary Dilation Bronchial Dilation β2 Bronchoconstriction Glycogen Glucose β2 Generalized, diffuse response Reason: extensive branching of the preganglionic fibers Coordinated; response occurs at the same time Muscarinic receptor Nicotinic receptors M3 M3 Glucose Glycogen Localized response, except for Vagus nerve Reason: limited branching, except for Vagus nerve Coordinated; but some processes do not have to occur at the same time (ex. micturation, defecation, erection) Head ganglion of the ANS – Hypothalamus • Anterior hypothalamus – coordinates Cholinergic activities • Posterior/ Lateral hypothalamus – coordinates Adrenergic activities Example: Baroreceptor Reflex Increased Arterial Blood Pressure (ABP) stretch arterial walls (+) Baroreceptor (-)/inhibit Vasomotor center (medulla) Decrease sympathetic outflow Increase parasympathetic outflow Vasodilation Decrease cardiac activity Decrease cardiac activity Decrease ABP Decrease ABP Pharmacological Differences A. B. CPalafox (1A) Parasympathetic Cholinergic ↑ / Potentiate cholinergic or parasympathetic effect ↑ synthesis of Ach ↑ release of Ach ↑ interaction between Ach and cholinergic receptor (-) deactivation of Ach PARASYMPATHOMIMETIC –mimics the effects of parasympathetic stimulation Anticholinergic ↓ / Block cholinergic or parasympathetic effect synthesis of Ach ↓ release of Ach Block interaction between Ach and cholinergic receptor ↑ inactivation of Ach PARASYMPATHOLYTIC A. B. Sympathetic Adrenergic Adrenergic ↑ / Potentiate adrenergic or sympathetic effect ↑ synthesis of NEP ↑ release of NEP ↑ interaction between NEP and adrenergic receptor (-) inactivation of NEP SYMPATHOMIMETIC –mimics the effects of sympathetic stimulation Antiadrenergic ↓ / Block adrenergic or sympathetic effect synthesis of NEP ↓ release of NEP Block interaction between NEP and adrenergic receptor ↑ deactivation of NEP SYMPATHOLYTIC Renal Physiology IV: Body Fluids and Acid-Base Balance (Ronald Allan Cruz, MD) Body Fluids plasma is 60% and formed elements are 40%. Take note that your 40% will actually be your haematocrit. ď ď H2O intake: 2.3L/day o 2100 ml intake o 200 ml CHO oxidation ď H2O loss: 2.3L/day o 7o0 ml insensible loss ď§ 350 ml evaporation from skin ď§ 350 ml respiration o 100 ml sweat o 100 ml feces o 1400 ml urine Basically the average man would have a 2.3 L of water intake per day and of course the same amount of urine will have to go out. On the average, it is around 2.1 L, this is our oral intake so this is the supposed average intake of water and around 200 mL will be coming from the oxidation of carbohydrates – when glucose is broken down you have water and CO2. You have an average of 2.3 L per day but it varies depending on the means of that person but whatever amount that was taken in should have the same amount that will go out. Capillary membrane o Donnan effect In this diagram, the dark line will represent the capillary membrane. This actually separates your plasma from the interstitial compartment. Your capillary membrane will not permit the passage of plasma proteins so your plasma proteins will be located within the plasma. Since plasma proteins are highly negative, they will attract cations and repel anions. Because of this set up, you can also observe the Donnan effect within the capillary membrane. Water losses would be 2.3 L per day also. This is lost by several means. Around 7oo mL would be from insensible water losses. This is from evaporation of water from the skin and around 350 mL from respiration. As far as evaporation from the skin is concerned, the cornified layer of the skin actually prevents rapid evaporation of fluids so in this layer, particularly cholesterol and lipid membranes on the skin, if this layer is lost you actually increase the evaporative process – lose more water. Typical example would be burnt victims because their epidermal layer was lost, water losses would also be faster. Part of the management of burns is fluid administration. Around 100 mL is lost from the sweat although this varies depending on the physical activity and environmental temperature. 100 mL would be going out via the stool and this will also vary. In cases of diarrhoea, more water will be lost. Around 1.4 L will be coming out through the urine. 70 kg man ď 60% of body weight is H2O ď 42 L ď ď ď Extracellular fluid: 20% o Interstitial fluid: 15% o Plasma: 5% Transcellular fluid Intracellular fluid: 40% ď ď ď 14 L ď 11 L ď 3L 1-2 L 28 L In this diagram, the horizontal line here will represent the cell membrane separating the extracellular from the intracellular compartment. And in this graph, you’ll take note of your anions and cations. As far as extracellular compartment is concerned, this is primarily composed of Na, Cl and bicarbonate whereas in the intracellular compartment, you have your K, phosphates and proteins. The most abundant substance in the body is water. So 60% of our body weight is basically water and this is divided into two compartments: extracellular and intracellular compartment. 40% of our body weight would be intracellular water so much of the water that we have is actually located within the cell. Your extracellular fluid which is around 20% of our body weight is divided into two basic compartments: interstitial fluid and plasma. A specialized compartment is termed as transcellular fluid – a specialized extracellular compartments like synovial fluid, CSF, pericardial fluid, peritoneal fluid etc. and is around 2L. ď Blood o Blood volume: 7% ď§ Plasma: 60% ď§ Formed elements: 40% 70 kg man ď 5L ď 3L ď 2L Given a 70 kg man, here you can see the distribution of water in the different compartments. Looking at blood, 7% of our body weight would be blood so given a 70 kg man, that is around 5 L. Blood is a specialized compartment such that it will contain extracellular and intracellular fluid. Extracellular fluid would be plasma and the water within your formed elements is the intracellular fluid. You will note that 1 Shannen Kaye B. Apolinario, RMT In this table, this shows the different solutes found in the different compartments in the body particularly in plasma, the interstitial space and the intracellular space. The substances highlighted in red are particularly located extracellularly and the substances highlighted in blue are located intracellularly. In here you also have your total osmolarity. Indicator-Dilution Principle ď ď ď ď Measurement of fluid volumes in different compartments CA x V A = C B x VB VB = 10mg/ml x 1ml 0.01 mg/ml = 1000 ml First let us talk about the indicator dilution principle. The indicator dilution principle basically allows us to measure these compartments. How is this done? First is you utilize the formula: concentration of A times volume of A is equal to the concentration of B times the volume of B. minus the ECF volume. To get your total blood volume, that’s plasma divided by one minus haematocrit or you can utilize a radiolabeled RBC. Osmotic Equilibria Between Extracellular and Intracellular Fluid ď ď ď Plasma and interstitial fluid volume o Hydrostatic pressure o Colloid osmotic pressure Extracellular and intracellular fluid volume o Osmotic effect of solutes Intracellular fluid is isotonic with the extracellular fluid Let’s look at equilibration of compartments. For your plasma and interstitial fluid volume, this is being separated by capillary membrane. As far as equilibration is concerned, Starling forces will play a major role to the hydrostatic pressure and osmotic pressure present in the two compartments – vascular (plasma) and interstitial compartments. When it comes to intracellular compartments, the cell membrane will limit this such that the osmotic effects of solutes now will determine equilibration for the two compartments. Take note that the ECF is isotonic. Osmosis and Osmotic Pressure For example, if you have this set up, you have a fluid here with an unknown volume and you want to know. What you do is to inject or administer a dye or indicator with a known concentration and known volume and allow it to disperse. Get a sample and check for the concentration then you will be able to get the volume of compartment. For example you want to determine the volume of B. You administer the indicator having a concentration of 10 mg/mL and having a volume of 1 mL. Allow it to disperse and get a sample. The concentration of the sample is 0.01. Mathematically, you can get the volume of container which is 1 L. This indicator dilution principle is being used to measure the different compartments in the body so what we need now to know is what are the appropriate indicators that are going to be used. In selecting an indicator, you need three criteria: first, this indicator has to disperse evenly within the volume you want to measure (even distribution); second, this indicator should stay in the compartment you want to measure; thirdly, it should not be metabolized by the cell. These are the three criteria in selecting an appropriate indicator. ď ď ď ď Total body H2O: 3H2O, 2H2O Extracellular vol: inulin, 22Na o Plasma vol: 125I-albumin o Interstitial vol = extracellular vol – plasma vol Intracellular vol = total H2O – extracellular vol Total blood vol = plasma/ (1-hct) 51Cr-labeled RBC Here you have the different indicators that are utilized to measure certain compartments. For your total body water we utilize heavy water – tritium or deuterium. Since it is water, it will go to all the compartments. ď Osmoles o Total number of osmotically active particles in a solution o 1 osm = 1 mol = 6.02x1023 particles o 1 mOsm = 0.001 osm ď Osmolality o Osm/kg of H2O ď Osmolarity o Osm/L of H2O Osmoles is the total number of osmotically active particles in a solution such that one mole of a substance is actually one osm or 6.02x10 23 particles (Avogadro’s number). Translating this to mOsm, simply move the decimal point so that’s .001 osm. Osmolality is osm per mass of water. Osmolarity is osm per volume of water. Chemically speaking, osmolality is more accurate than osmolarity. Osmoles per kilogram is more accurate than osmoles per liter even though 1 L is 1 kg of water. Why? Because osmolarity being volume is affected by temperature. The higher the temperature, the greater the volume; the lower the temperature, the volume contracts. Your mass stays the same regardless of temperature. However in the human body or physiologically speaking, both may be interchanged since the human body has a relatively constant body temperature of 37oC. Even if you have a fever, the volume of water will not expand. ď ď ď 1 mole/L of glucose = 1 osm/L 1 mole/L of NaCl = 2 osm/L 1 mole/L of Na2So4 = 3 osm/L So here you have the number of osmotically active particles by different substances. If you have 1 mole/L of glucose, that’s actually 1 osm per L. However when you have salts, salts in solution will ionize easily. For example if you have NaCl placed in water, it will dissociate into Na and Cl therefore 1 mole/L of salt is actually 2 osm per L since it dissociated into two. When there are three ionisable particles like Na2SO4, placed in a solution, you will have 2 ions of Na and 1 sulfate – there are 3 ionizable particles. For extracellular fluid volume, we utilize inulin and an isotope of Na. If you want to measure the plasma volume, you can have radiolabeled albumin because albumin stays in the plasma. ď Osmotic pressure o The pressure required to oppose osmosis o Indirectly measures H2O and solute concentrations To get interstitial volume, simply get your ECF volume minus the plasma volume. For your intracellular volume, you have total water ď ďŁ osmotically active particles, ďŁ osmotic pressure o Independent of the size of the particle 2 Shannen Kaye B. Apolinario, RMT o Na2SO4 > NaCl > albumin = glucose be multiplied with van’t Hoff’s law getting now 5,519.8 mmHg. And this is now the actual osmotic pressure of NSS. When you say osmotic pressure, this is the pressure required to oppose osmosis and indirectly measures water and solute concentration such that if a solution has a high osmotic pressure it means that the solution or solute concentration is high. It indirectly reflects solute concentration. The higher the osmotically active particles, the greater the osmotic pressure. If you have a lot of ionisable particles or the greater the number of particles, the greater the osmotic pressure is. In this case, Na2SO4 having 3 ions will have a greater osmotic potential than NaCl having only 2 ions and both of which will have greater osmotic potential comparing it to glucose and albumin because both glucose and albumin is not ionisable. As far as size is concerned, osmosis is NOT directed on size. Osmotic potential is the same even if its size is big or small. For example albumin and glucose, albumin is a much bigger molecule compared to glucose however both of their osmotic potential is the same. ď van‘t Hoff’s law o π=CRT ď§ π – mmHg ď§ C – concentration of solutes in osm/L ď§ R – ideal gas constant ď§ T – temperature, 310 kelvin ď ď 1 osm/L = 19300 mmHg 1 mosm/L = 19.3 mmHg In measuring osmotic pressure, we utilize van’t Hoff’s law. This is pressure equal to the concentration of solutes times gas constant times temperature. Using your van’t Hoff’s law, 1 osm per liter is actually 19,3oo mmHg. Because it is quite big, what we use in physiology and medicine is mOsm. In 1 mOsm per liter of solute, you have 19.3 mmHg pressure. ď ď 1 osm/L = 19300 mmHg 1 mosm/L = 19.3 mmHg ď 0.9%NaCl = 5944 mmHg o 0.9 g/100 ml o 9 g/L o 9 g/L / 58.5 g/mol = 0.154 mol/L o o o 0.154 mol/L x 2 = 0.308 osm/L 308 mosm/L 308 mosm/L x 19.3 mmHg/mosm/L = 5944 mmHg How is van’t Hoff’s used? For example you have 0.9% NSS. How high is its osmotic pressure? 0.9% is actually 9 g per 100 mL. To get similar units, we utilize 9 g/L and your 9 g/L is divided to the molecular weight of NaCl (58.5 g/mol). You will get 0.154 mol/L. 0.154 mol/L will be multiplied by two since you have two ionisable particles then you will get 0.308 osm per liter then change it to mOsm by simply moving the decimal point and then multiply it with van’t Hoff’s law. You will be able to get 5,944 mmHg and so this is the osmotic pressure of NSS. ď Osmotic coeffecient o Correction factor ď§ NaCl: 0.93 o Looking at the interstitial and intracellular compartments, your interstitial and intracellular compartment will have the same osmotic pressure. You would notice that their corrected osmolar activity is both 281, pressure is both 5,420. However if you will compare it with plasma, osmotic pressure of plasma is higher – 5,440 because of plasma proteins. 308 mosm/L x 0.93 = 286 mosm/L But that’s not the end since we need to take into account a correction factor or osmotic coefficient because when NaCl is placed in a solution, majority of solutes or salt will dissociate or ionize. However, Na is a positive ion and Cl is a negative ion so some of these particles may NOT dissociate because of ionic attraction. Not all will dissociate completely. With that, if your Na and Cl will stick together, they count as one particle only. With that, you need to take into account the correction factor for NaCl so that’s 0.93. This simply means only 93% of NaCl will dissociate in the solution. From your 308 mOsm/L, you multiply that with your correction factor to get 286 mOsm. 286 now here is the one that will 3 Again, you have the different substances. Take note a lot of them are ions and because of that, cations will still be attracted to anions that’s why you have to have correction factors. If you will look at the bottom portion of the table, this is computed total mOsm and this is now your corrected osmolar activity. You will notice that it is lower because some cations will be associated with an anion – they will not dissociate 100%. Your 282 here is the one that you will multiply with van’t Hoff’s law giving you 5443 mmHg for your plasma. Shannen Kaye B. Apolinario, RMT ď 1 mosm/L = 19.3 mmHg ď ď ď Hypotonic solutions Isotonic solutions: 0.9%NaCl, PLR Hypertonic solutions When we say isotonic, what does that mean? Isotonic means that the solute will have the same osmotic pressure with plasma. It is not about concentration. If you look at an isotonic solution like NSS, it is not about concentration because NSS would contain NaCl. Plasma would contain Na, Cl, K, Mg, Ca, plasma proteins etc., it is about osmotic pressure. When we say isotonic solution, these are solutions that will have the same osmotic potential as plasma. Meaning to say, it has the same ability to attract water regardless of the particles. Here we have isotonic solutions, NSS and PLR. Both will not have the same concentration as plasma. A lot of students will say that D5 water is an isotonic solution. D5 water is NOT isotonic, it is isoosmotic. Why? Your glucose does not act like lactate or sodium. Lactate and sodium stays outside the cell but glucose enters the cell. When glucose enters the cell, D5 water will behave as hypotonic solution because some glucose are removed in the extracellular compartment (it entered the cell) and more water is outside the cell. Glucose or D5 water technically speaking is not isotonic, it is isoosmotic. When osmotic potential is higher, that’s your hypertonic solution. If your osmotic potential is lower, that’s hypotonic solution. Glucose and Other Solutions ď ď Glucose Amino acids o o o Adjusted to isotonicity Administered slowly Metabolized by the body, excess H2O is excreted With regards to fluids with glucose and amino acids, as what we’ve mentioned, glucose and amino acids will enter the cell thus they are ineffective osmoles. That’s why when we have a patient that is in shock, we do not give D5 water, we give NSS to increase the blood volume. Things to take note of with regards to these substances: they must be adjusted to isotonicity – “toxic” or hard to make because you have to take into account your glucose or amino acids entering the cell and they must be administered slowly. Volumes and Osmolalities of Extracellular and Intracellular Fluid in Abnormal States Clinical Abnormalities of Fluid Volume Regulation Fluid Compartments Hyponatremia In calculating changes in intracellular and extracellular fluid volumes o H2O moves rapidly across the cell membrane o Cell membranes are almost completely impermeable to solutes ď ď¤ NaCl: hypoosmotic dehyreation o Electrolyte, H2O loss o Diarrhea, vomiting o Diuretics o Addison’s disease In calculating changes in the ICF and ECF volumes, take note that water moves rapidly across the cell membrane. Recall that the cell membrane is a semi permeable membrane permitting the passage of water but not solutes. ď ďŁ H2O: hypoosmotic overhydration o SIADH ď Adding Saline Solution to the Extracellular Fluid Hypernatremia ď ď ďŁ NaCl ď¤ H2O ď Hyperosmotic dehydration o DI o Excessive sweating ď Hyperosmotic overhydration o Conn’s syndrome o 2o hyperaldosteronism For clinical abnormalities of fluid volume and regulation this is your hypo and hypernatremia. ***read on this*** When we say hyponatremia, it means decreased Na and hypernatremia means increased Na and this doesn’t necessarily mean you have derangements in Na. For example, if you have hyponatremia, a lot of times Na is not really low but actually water is increased. Edema Intracellular Edema ď In this diagram, you have your volume, osmolarity and intracellular and extracellular compartment. When you add an isotonic solution tonicity is the same. However your extracellular compartment volume increases whereas your intracellular compartment stays the same. If you add a hypotonic solution, the tonicity decreases. Water will enter the cell therefore the volume of the intracellular compartment increases and the volume of extracellular compartment increases as well. When you add a hypertonic solution, tonicity increases. Water inside the cell will go out via osmosis so your intracellular volume decreases and your extracellular volume increases. 4 Shannen Kaye B. Apolinario, RMT Intracellular swelling o ď¤ metabolism o ď¤ nutrition o ď¤ ion pump activity o ďŁ osmosis o Inflammation There are two types of edema – intracellular and extracellular edema. Intracellular edema means that water accumulates within the cell due to a decrease in metabolism, decreased nutrition because you decrease your ion pump activity. Because of that, Na cannot go out so it stays inside the cell and water follows or goes with it so it increases osmosis then your cell becomes inflamed. Typical example would be cerebrovascular accident infarct. With that, you decrease blood supply going to CNS. Neurons are excitable and highly dependent on Na K pump. If your NaK pump will not work, Na stays inside the cell, water enters the cell, your brain swells. That’s why stroke patients if infarct, most likely, intracranial pressure increases. Safety Factors That Prevent Edema ď Extracellular Edema ď ďŁ fluid in the interstitial space o Plasma leakage o Failure of the lymphatic drainage When we say extracellular edema you have accumulation of fluid in the interstitial compartment. It may be due to plasma leakage or failure of lymphatic drainage and the forces that will affect extracellular edema is you have your filtration rate. ď F = Kf x [(Pc+πi)-(Pi+πc)] o F – filtration rate o Kf – filtration coefficient o Pc – capillary hydrostatic pressure o πi – interstitial oncotic pressure o Pi – interstitial hydrostatic pressure o πc – capillary oncotic pressure ď ď Normally we do not instantly would have edema because we have safety factors that will prevent edema. We have three: low compliance of the interstitium, increased lymph flow and wash down of interstitial proteins. Low of the Interstitium ď ď ď ď So here you have your filtration coefficient and Starling forces. If you will recall, these are the factors that will affect the amount of water going into the interstitium. ď F = Kf x [(Pc+πi)-(Pi+πc)] o F – filtration rate o Kf – filtration coefficient o Pc – capillary hydrostatic pressure o πi – interstitial oncotic pressure o Pi – interstitial hydrostatic pressure o πc – capillary oncotic pressure o Low compliance of the interstitium o Negative pressure o Interstitial gel o Proteoglycan and collagen filaments Increased lymph flow 10-50x Washdown on interstitial fluid CHON -3 mmHg 12L As long as pressure is negative, small changes in fluid vol are associated with large changes in Pi Low compliance o C=ď˛V/ď˛P The low compliance of the interstitium is due to three factors: the negative pressure in the interstitial compartment, the interstitial gel, proteoglycans and collagen filaments. So first you have the negative pressure in the interstitium. The interstitial compartment is said to have a pressure of -3 so it has a vacuum effect. And in the interstitial compartment, we have around 12 L of fluid. Lymphatic drainage For edema to occur you have four important factors to take note of and they are highlighted in red. The font highlighted in red, when they are deranged then extracellular edema will occur. For example changes in your filtration coefficient, capillary hydrostatic, capillary oncotic pressure and lymphatic drainage. For each factor you have several examples. In this table you have the different factors: increased capillary pressure, decreased plasma proteins, increased capillary permeability and blockage of lymphatics. All of these will result to extracellular edema. 5 Shannen Kaye B. Apolinario, RMT Looking at this graph, you have your pressure and fluid volume. Looking at the normal pressure in the interstitium of -3, we have around 12 L of water in the interstitial compartment. As long as the pressure is in the negative range, small changes of fluid are associated with large changes in your interstitial hydrostatic pressure. If hydrostatic pressure increases, this will oppose filtration so less water will go into the interstitial compartment. We have mentioned that because of the -3 pressure, there is a vacuum effect creating a rigid structure within your interstitial compartment – it is like having a glass bottle filled with water to the brim then it has a rubber stopper. This is a closed system with a fixed volume of fluid. If you injected a small amount of water, the pressure inside increases and that pressure is your interstitial hydrostatic pressure so if you try to push more water into the bottle, it is harder because the hydrostatic pressure increases further. Because also of the negative pressure, there is low compliance in the interstitial compartment. Compliance is equal to the change in volume per change in pressure or expansibility, its opposite is elasticity. Interstitial compartment has a low compliance just like a rigid glass bottle. But take note this is only true your pressure is in the negative range. ď Interstitial gel o Prevents flow of fluid o Offers elastic resistance to compression o Compact “brush pile” o Interstitial fluid vol does not change greatly Another factor for the low compliance of the interstitial compartment is the gel. The interstitial gel prevents flow of fluid and it will offer elastic resistance to compression. You have a compact brush pile and the interstitial fluid does not change greatly. Because of your negative pressure (suction or vacuum effect) your interstitial gel will compact such that it will prevent the flow of water. Water from the upper portions of the body because of your compact gel does not easily go to the lower extremities. ď Proteoglycan filaments o Acts as spacer o Modulates flow of fluid o Flow of nutrients and metabolites are not compromised Thirdly, you have your proteoglycan filaments. If your gel prevents the flow of water, your proteoglycan filaments will act as spacers in between such that they modulate the flow of water but more importantly its job is to permit the flow of nutrients and metabolites. Interstitium ď ď ď ď ď ď Looking at this graph, based on mathematical extrapolation, they looked on what will be the volume of the interstitium if it becomes positive. Based on their computation, there will be a modest increase in fluid but actually their observation was: a small increase in pressure will have a great increase in volume because your interstitial compartment increases its compliance already. So it is very important that the pressure is -3. The safety factor is 3 mmHg before reaching zero. This is the graph extrapolated mathematically and this is the graph actually observed. Increased Lymph Flow ď ď ď The second factor is the lymph flow. This returns the fluid and proteins into the circulation. An increase in lymph flow up to 10-15x; that better drains your interstitial compartment such that if you increase your filtered fluid, you increase your interstitial hydrostatic pressure consequently increasing lymph flow – drainage is higher. Here you have a safety factor of 7 mmHg. Washdown of the Interstitial Fluid Protein ď ď ď > 0 mmHg ďŁ compliance Fluid accumulates, ďŁ free fluid “Brush pile” is pulled apart ď¤ gel form ďŁ spaces between cells If the pressure becomes positive or beyond zero, compliance now increases so fluid now will accumulate. Since the pressure has become positive, you lose the vacuum effect – everything will disperse and there will be larger spaces in between allowing water to flow freely resulting to edema. Lymphatics are permeable to CHON Interstitial fluid CHON is carried by lymph flow o ďŁ lymph flow, ď¤ interstitial CHON, ď¤ πi 7 mmHg The third factor is the wash down of proteins. Lymphatics are permeable to proteins and interstitial fluid proteins will be carried by lymph. With that, you decrease now the interstitial oncotic pressure. That adds another 7 mmHg. Safety Factors That Prevent Edema ď ď Here you have the brush pile being pulled apart. You have a decrease in your gel form and increased spaces in between. It is important that your interstitial compartment be within the negative range. Returns fluid and CHON to the circulation ďŁ lymph flow: 10-50x o ďŁ filtered fluid, ďŁ Pi, ďŁ lymph flow 7 mmHg ď Low compliance of the interstitium o Negative pressure o Interstitial gel o Proteoglycan and collagen fillaments o 3 mmHg Increased lymph flow 10-50x o 7 mmHg Washdown on interstitial fluid CHON o 7 mmHg Taking into account all of these factors: compliance is 3 mmHg, lymph flow is 7 mmHg and protein wash down is 7 mmHg for a total of 17 mmHg pressure as a safety factor. What does that mean? For edema to occur, your capillary pressure or hydrostatic pressure should exceed 17 mmHg so you have a net filtration and that’s the time where the fluid will accumulate within the interstitial compartment. Fluids in the Potential Spaces of the Body Potential Spaces 6 Shannen Kaye B. Apolinario, RMT ď ď ď ď Pleural cavity Peritoneal cavity Pericardial cavity Synovial cavity ď Fluid is present to reduce friction ď Fluid is exchanges between capillaries and the potential space ď Lymphatics drain fluid from potential space ď Negative fluid pressure Basically, the transcellular compartments are specialized compartments: synovial, pericardial, peritoneal, pleural fluid etc. and the purpose of the fluid are to reduce friction during movement. Just like any extracellular compartment, fluid is exchanged between capillaries and potential space and of course lymphatics will also drain these spaces. Concentration ď ď ď Take note also that these compartments will also have a negative pressure. For example in the pleural cavity it is -7 to -8, pericardial: -3 to -5, joint spaces: -5 to -6. If pressure becomes positive just like the interstitial compartment, fluid will accumulate. If in the pleural cavity that is pleural effusion, in the abdomen it is ascites, in the pericardial fluid it is tamponade. Acid-Base Balance Hydrogen Ion ď Extracellular concentration: 0.00004 mEq/L ď ď ď pH = -log [H] pH = - log [0.00000004 Eq/L] pH = 7.4 ď pH: 7.35-7.45 The extracellular concentration of H in the body will determine pH or body pH. Here you have 0.00004 mEq/L of H+ present in the body. To get the pH, pH is –log times the H ion concentration. Plugging the values in, you will have 7.4 and this is the normal pH of the body. In the clinics, it is in a range: 7.35-7.45. Chemical buffer systems o Intracellular o Extracellular Respiratory system Renal system As far as controlling H ion concentration in the body, you have the buffers: kidneys and the lungs. These are the systems that will control body pH. Your chemical buffer systems are primarily located intracellularly and extracellularly. In acidosis, there is hyperventilation to release carbonic acid so blood pH will go back to normal. Your respiratory system will comprise of around 30-40% of the entire acidbase balance. The most important is the renal system. When we have derangements in pH, the chemical buffer system instantaneously or it is the first one to react to bring pH back to normal. Within minutes, respiratory system (around 3-15 minutes) will kick in via hyperventilation or hypoventilation in an attempt to correct pH. However the disadvantage of the respiratory system is that it will only handle volatile acids most importantly carbonic acid because carbonic acid is the only acid that will be converted into a gas – CO2. Your respiratory system will only handle volatile acids. The kidneys are the most important not only will they handle non-volatile acids but they will also handle bases but the disadvantage of the renal system that it takes a very long time. If the chemical buffer system is instantaneous, respiratory system within minutes, the renal system will take days such that full compensation can be achieved within 3 to 5 days. Intracellular Buffers ď Intracellular CHON o H + Hgb ď˘ HďHgb ď pK: 7.4 Chemical buffer systems particularly intracellular buffers will be done by intracellular proteins. Haemoglobin will act as a buffer such that it is able to bind a H ion or it can release H depending on the situation. Recall the oxygen dissociation curve: if H+ is increased, it will give off oxygen because it is now the H+ that will “ride” with haemoglobin. Haemoglobin will act as a buffer having a pK of 7.4. What does a pK of 7.4 mean? This means that around this pH value you have maximum buffering capacity. Chemical Buffer System In this table here you have the different compartments in the body with their corresponding H ion concentration and pH. Take note arterial blood is 7.4, venous blood is a little bit acidic which is 7.35 because of carbonic acid. Gastric HCl will have a pH of 0.8. Take note as far as urine is concerned; it can either be acidic or alkaline. In the clinics, it is not abnormal to find alkaline urine. More commonly in the laboratory, the normal urine samples usually are acidic but just like what was mentioned earlier, if the urine sample is alkaline it is not always an abnormal result. Ask the patient as to why their urine sample is alkaline. Is the patient taking in drugs, eating a lot of grape fruit or cranberries? These fruits will alkalanize urine so alkaline urine may be a normal finding. ď ď Acid: releases H ions Base: accepts H ions o H2CO3 ďŽ H + HCO3 Acid releases H ion while a base accepts the H ion. For example, in this chemical reaction of carbonic acid dissociating into H and bicarbonate, your carbonic acid is the conjugate acid while the bicarbonate is the conjugate base. Take note the reaction is reversible – it can either go forward or backward. 7 Shannen Kaye B. Apolinario, RMT ď Buffer + H ďŽ BufferďH ď ď Intracellular buffers Extracellular buffers o HCO3 buffer system o PO4 buffer system Other chemical buffer systems are bicarbonate buffer system and phosphate buffer system and both are simple reactions. So you have your buffer biding to H+ and you have now buffer-H+ complex and this is reversible. Bicarbonate Buffer System ď H2CO3 o CO2 + H2O ďŽ H2CO3 NaHCO3 o H2CO3 ďŽ H + HCO3 o Na + HCO3 ďŽ NaHCO3 ďˇ ďˇ CO2 + H2O ďŽ H2CO3 ďŽ H + HCO3 Na + HCO3 ďŽ NaHCO3 ď The bicarbonate buffer system is an important extracellular buffer. Given the equation, how is NaHCO3 is formed? CO2 plus water is carbonic acid. Carbonic acid dissociates. Your Na now will combine with bicarbonate forming NaHCO3. Taking all of these and creating one equation, again CO2 + H2o is carbonic acid. With your carbonic anhydrase, ions will dissociate, Na will combine to bicarbonate to form sodium bicarbonate. ď ď CO2 + H2O ďŽ H2CO3 ďŽ H + HCO3 Na + HCO3 ďŽ NaHCO3 o Add lactic acid If you add an acid like lactic acid, you increase your H+ facilitating the backward reaction. When H+ increases by adding lactic acid, your reaction will favour the formation of carbonic acid and this will dissociate or reconstitute CO2 and H2O so you now have neutral substances. ď ď CO2 + H2O ďŽ H2CO3 ďŽ H + HCO3 Na + HCO3 ďŽ NaHCO3 o Add NaOH If you put an alkaline like sodium hydroxide, it will favour the forward reaction. H+ will combine to one of the H+ from carbonic acid forming water so that creates your bicarbonate and this will combine with Na forming sodium bicarbonate. wherein the system will have maximum buffering capacity. Meaning to say from 6.1, even if you add an acid or base, the changes in pH is minimal. Bicarbonate buffer system is an extracellular buffer. Phosphate Buffer System ď ď ď ď ď H2PO4, HPO4 Intracellular buffer Renal tubular buffer HCl + Na2HPO4 ď˘ NaH2PO4 + NaCl NaOH + NaH2PO4 ď˘ Na2HPO4 + H2O ď pK: 6.8 The phosphate buffer system is an important intracellular buffer together with intracellular proteins and it is an important buffer in the renal tubules. This is a simple chemical reaction for your phosphate buffer. For example, if you add an acid, your HCl will react with Na2HPO4 giving us NaH2PO4 and salt. You will note that they just exchanged ions giving now a neutral compound. If you add a base like sodium hydroxide, it will react to NaH2PO4 giving you Na2HPO4 and water and again, it is a neutral compound. Its pK is around 6.8 Isohydric principle. ď H = K1 x (HA1/A1) = K2 x (HA2/A2) = K3 x (HA3/A3) ď Any condition that changes the balance of one system also changes the balance of the others Quantitative Dynamics ď H2CO3 ďŽ H + HCO3 ď Dissociation constant K o K = (K x [HCO3])/[H2CO3] o H = K x [H2CO3]/[HCO3] o H = K x [CO2]/[HCO3] o H = K x (0.03mmol/mmHg x PCO2)/[HCO3] o ď ď pH = -log K H = K x (0.03mmol/mmHg x PCO2)/[HCO3] pK = -log K o -log H = -log K -log (0.03 x PCO2)/[HCO3] o pH = pK -log (0.03 x PCO2)/[HCO3] o pH = pK +log [HCO3]/(0.03 x PCO2) o pH = 6.1 +log [HCO3]/(0.03 x PCO2) For quantitative dynamics, this simply explains the Henderson-Hasselbach equation so it will compute for pH given a known concentration of bicarbonate and CO2. In the laboratory, bicarbonate and CO2 amounts in the blood are taken from the ABG (arterial blood gas). With this, you can actually compute for the blood pH. Bicarbonate Buffer System Here you have your H+ concentration equal to the HendersonHasselbach equation of one system, equal to the equation of system two, equal to the equation of system three. When we say isohydric principle, any change in the H+ concentration or blood pH, all three systems will adjust simultaneously. For example, the first system will represent intracellular buffers, the second system will be bicarbonate, the third system will be the phosphate buffer. If the pH of the body changes, all of these will adjust simultaneously. In the same manner, if one system becomes deranged, for example bicarbonate system – it increased or decreased in the body, your first and the third system will adjust accordingly in order to maintain pH. Respiratory System ď ď ď ď Controls extracellular CO2 o H2CO3: volatile acid Alveolar ventilation modulates PCO2 50-75% effectiveness 1-2x buffering power than the chemical buffer systems Basically, the respiratory system will control CO2 and carbonic acid so this is now your volatile acid. Alveolar ventilation will modulate your pCO2 – it depends if you will hypo or hyperventilate. It is said to be 50-75% effective having a buffering power around 1 to 2 times greater than the chemical buffer system. The respiratory system will act within minutes. Renal System This is now the pK of your buffer system which is around 6.1. You have your pH, acid, bicarbonate. When we say pK, this is the pH 8 Shannen Kaye B. Apolinario, RMT ď ď ď Excretes acidic or basic urine 4320 mEq/day HCO3 is filtered 4400 mEq/day of H is secreted o 4320 mEq of H secreted to reabsorb HCO3 o 80 mEq of H excreted as non-volatile acids ď Acid-base balance o Secretion of H ions o Reabsorption of HCO3 o Generation of new HCO3 The renal system is the most important component in controlling blood pH because they will primarily handle acids and bases. Around 4,320 mEq of bicarbonate is filtered and 4,400 mEq of H+ is secreted by the renal tubules. From your 4,400, 4,320 of H+ secreted will go to your bicarbonate for reabsorption. So, if 4,320 goes to bicarbonate for reabsorption, you will have an excess of 80 (4,400-4,320 = 80). This 80 mEq of H+ are the non-volatile acids or acids that are not handled by the lungs like uric acid, lactic acid etc. That’s why when you get a urine sample, more commonly it is acidic. Take note that for acid-base balance to occur you need several processes: secretion of H+, reabsorption of bicarbonate, and production of a new bicarbonate. Hydrogen Ion Secretion ď ď ď ď Na-H counter transport To reabsorb HCO3, H must be secreted o 4320 mEq/day: filtered HCO3 o 4400 mEq/day: secreted H ď§ 4320 mEq/day H: HCO3 ď§ 80 mEq/day H: non-volatile acids H2PO4, HPO4, NH3, urate, citrate buffers HCO3 reabsorption This are the different segments of the nephron. The numbers represent bicarbonate filtration and the percent reabsorbed. Take note that here you have 4,320 mEq filtered and from there, 85% will be reabsorbed from the PCT. So majority of the bicarbonate is reabsorbed within the PCT and 10% in the thick ascending limb and around 4.9% in the DCT and collecting ducts. 4,320 filtered and 4,400 is H+ secretion and take note that around 4,300 of H+ will bind with bicarbonate and 80 mEq of H+ will bind with non-volatile acids like phosphate, ammonia, uric and citrate buffers. dissociates. Bicarbonate is reabsorbed. Here you have your H+. Because of primary pump, it will power the secondary pump. In the urine, sodium bicarbonate is filtered (4,300+) this dissociates and Na will enter via secondary pump, H+ will exit via secondary pump. H+ will combine with bicarbonate reconstituting carbonic acid. Carbonic acid reverts back to H20 and CO2. CO2 can easily diffuse into the cell membrane and again the same process occurs. Take note that to reabsorb bicarbonate, you need a H+ so that you form carbonic acid and CO2. Without H+, sodium bicarbonate goes out into the urine. Take note that you have one to one correspondence – for every 1 bicarbonate, you need 1 H+. Take note also that bicarbonate reabsorbed here is NOT the same bicarbonate that is filtered however you have one to one correspondence for as long as there is one H+ present. For as long as this reaction continuous to take place, bicarbonate inside the cell accumulates creating now a gradient in the blood, bicarbonate goes out. DCT, CT Intercalated cell: Hydrogen Ion Secretion Let us now look at the DCT and collecting ducts particularly the intercalated cell. Here you have secretion of H+. Again, CO2 produce carbonic acid, bicarbonate and H+. Your H+ will be pumped out via H+ pump. Bicarbonate will go out into the blood using a bicarbonate-Cl counter transport. This is your intercalated cell, take note that you generate a new bicarbonate molecule. DCT, CT Intercalated cell: Phosphate Buffer Bicarbonate Reabsorption For your phosphate buffer, it is an important buffer for the renal tubules. Bicarbonate buffer system is reabsorbed while the phosphate buffer is not reabsorbed so it bears the burden of controlling pH within the tubules. This is now your tubular cell more importantly in the PCT. This is your interstitial compartment or blood, tubular cell and filtrate. How can we reabsorb bicarbonate? Your tubular cells will produce CO2. From there it combines with water forming carbonic acid. Carbonic acid 9 Shannen Kaye B. Apolinario, RMT This is your Na-PO4 buffer and you have here your renal tubules. The same reaction: CO2 + H2O -> carbonic acid, bicarbonate and H+. Primary pump will power the secondary pump. The Na from phosphate buffer will enter the cell and H+ exits. H+ will combine with phosphate buffer now then this exits via the urine. Take note that you produce a new bicarbonate. Basically we are now talking on how we are producing a new bicarbonate. Other buffer systems can also act within the tubular cells like ammonia, urate and citrate. So all of these can actually bind with secreted H+ ion. When that happens, a new bicarbonate is produced. For glutamine, when it is metabolized, ammonium is produced and 2 molecules of bicarbonate are also produced. So the NH3Cl is excreted as well in the urine. ď Titration of H in the tubular lumen o H + HCO3: reabsorption of HCO3 o H + buffers: generation of a new HCO3 ď Acidosis: excess H o Reabsorption of all filtered HCO3 o Generation of new HCO3 DCT, CT Intercalated cell: Aldosterone Effect To reabsorb bicarbonate, H+ is needed. To generate a new bicarbonate, H+ will combine to non-bicarbonate buffers. During acidosis, there is excess H+ so here you have reabsorption of all of the filtered bicarbonate because if you want to reabsorb one bicarbonate, you need to have H+. So if the H+ is in excess, all bicarbonate will be reabsorbed. The excess H+ will combine to a nonbicarbonate buffer generating new bicarbonate. Hydrogen Ion Secretion ď For aldosterone effect, basically it increases the action of NaK pump increasing the secondary pump, more H+ will go out therefore more bicarbonate goes out into the blood. That is why if we have hyperaldosteronism, the manifestation is alkalosis. Stimuli for secretion of H ions o ďŁ PCO2 o ď¤ extracellular pH o Excess aldosterone ď§ ďŁ loss of H, NH4, titratable acids ď§ ďŁ HCO3 DCT, CT Intercalated cell: Ammonia Buffer Ammonia buffer is almost the same with the principle behind. You produce your carbonic acid, bicarbonate and H+. H+ is pumped out via H+ pump. Ammonia is due to amino acid metabolism and it can easily diffuse out of the cell. NH3 becomes ammonium. It will combine to a filtered anion like Cl- so here you have ammonium chloride then it goes out into the urine. Again, new bicarbonate is produced. For the stimuli of secretion of H+ ions, here are the conditions: if CO2 within the body increases (respiratory acidosis), blood pH drops or when you have an increased aldosterone. We have already mentioned that as far as aldosterone is concerned, it powers the primary pump for facilitation H+ secretion. Quantifying Acid-Base Excretion ď HCO3 excretion o V x UHCO3 ď§ Removal of HCO3 from the blood, or the addition of H into the blood ďˇ NH4 excretion o V x UNH3 ď§ Amount of new HCO3 added into the blood ď§ Titratable acids o Non-HCO3, non-NH4 buffer excreted o Measured via titration with NaOH ď§ PO4, organic buffers Generation of New Bicarbonate In quantification of acid-base secretion, we want to know how much H+ is excreted out of the body. To get the value, three components are needed: bicarbonate excretion, ammonium excretion and titratable acids. 10 Shannen Kaye B. Apolinario, RMT Your bicarbonate excretion is your urine flow rate times the concentration of bicarbonate in the urine. This simply measures the removal of bicarbonate from the blood or the additional of H+ in the blood. ď Ammonium excretion is urine flow rate times the concentration of ammonia in the urine and this measures the amount of new bicarbonate added into the blood. Titratable acids are non-bicarbonate and non-ammonium buffer excreted like the phosphate, citrate, urate buffers and this is measured via titration via NaOH. Using a urine sample, you use a pipette and it is titrated in the laboratory. If the solution turns pink, it is the amount of NaOH consumed therefore that is the amount of H+ present. When we say acidosis, you have an excess H+ and your H+ is greater than bicarbonate therefore H+ is excreted resulting to an acidic urine and 100% of bicarbonate is reabsorbed. You also produce a new bicarbonate via non-bicarbonate buffers like ammonium excretion and of course the patient is hyperventilating. ď ď Net acid excretion o (NH4 excretion + urinary titratable acid) – HCO3 excretion ď Acid-base balance o Net acid excretion = non-volatile acid production o Acidosis: ďŁ H excretion, ďŁ NH4 excretion, ďŁ HCO4 addition into the blood o Alkalosis: no NH4 and titratable acid excretion, ďŁ HCO4 excretion, no new HCO3 generated Once the three variables are there, net acid excretion can now be computed – how much H+ are excreted in the body. Here you have NH4 excretion plus urinary titratable acids minus bicarbonate. To maintain acid-base balance, net excretion should equal to non-volatile acid production. Non-volatile acid production is used like uric acid, lactic acid because your non-volatile acid is being handled by the kidneys while volatile acids are being handled by the lungs. Acidosis: excess H o H > HCO3 o H is excreted, acidic urine o Reabsorption of all filtered HCO3 o Generation of new HCO3 o ďŁ NH4 excretion o Lungs: ďŁ ventilation Alkalosis: excess HCO3 o HCO3 > H o HCO3 is excreted, alkaline urine o ď¤ H secretion o NH4 and titratable acids are not excreted o No new HCO3 o Lungs: ď¤ ventilation In alkalosis, excess bicarbonate greater than H+. Because of the excess bicarbonate, not all will be reabsorbed. Bicarbonate is excreted producing an alkaline urine. You have less H+ secretion and ammonium and titratable acids will NOT be excreted. Take note we do not generate a new bicarbonate and as far as the lungs are concerned, there is hypoventilation. If the individual has acidosis, you have an increase in H+ excretion, increased ammonium excretion and increased bicarbonate addition into the blood. In alkalosis, there is no NH4 and titratable acids excretion, you have increased bicarbonate secretion and no new bicarbonate is generated. Acid-Base Disorders ď pH = 6.1 +log [HCO3]/(0.03 x PCO2) Here you have the different substances or parameters that are measured in an ABG sample. Your H+, O2, CO2 and bicarbonate. The values will represent normal values (memorize!!!). In simple interpretation of ABG, we take note of the pH, CO2 and bicarbonate levels. Why is H+ and O2 are taken? H+ and O2 are important for the management because H+ will determine how much bicarbonate should be given to correct the problem. O2 will determine if the patient is hypoxic specially if he is having respiratory acidosis - to know if the patient has to have cannula, mask or intubated. But as far as diagnosis is concerned, CO2 and bicarbonate is important. These are your primary acid-base disturbances: respiratory acidosis or alkalosis, metabolic acidosis or alkalosis, and their corresponding derangements. 11 Shannen Kaye B. Apolinario, RMT ď Mixed acid-base disorders ď Respiratory and renal adjustments have occurred In the assessment of primary acid-base disorder, the first thing to look at is the pH to know if it acidosis or alkalosis and then bicarbonate and CO2 to know if it is metabolic or respiratory disorder. The problem more often than not, there are complex acid-base disorders so with that, acid-base nomogram is used. It is used when there is a respiratory and renal adjustment. Because of that, utilizing your acid-base nomogram is not really ideal at the onset of the disorder because the chemical buffer system acts instantaneously, the lungs in minutes but the lungs acts for days. For example, if a patient had an asthma attack and an ABG was taken, this may not reflect the same ABG three days from now because there will still be renal adjustments. Your acid-base nomogram is most ideal to use when the kidneys and the lungs have adjusted. ďˇ ďˇ ďˇ pH: 7.3 HCO3: 12 mEq/L PCO2: 25 mmHg ďˇ Metabolic acidosis What is this anion gap? In the body, to maintain electrical neutrality, the number of cations should equal the number of anions and this are the more common ions present in the body – Na, Cl and bicarbonate. To get the anion gap, this is simply cations (Na) minus anions (Cl and bicarbonate). If you have normal values for this, the normal anion gap would be around 8-10 or 10-12 depending on the laboratory. Take note that you also have other anions and cations present in the plasma like K, Mg, Ca, albumin, PO4 and sulfates. Your anion gap is most useful when we have metabolic acidosis. If you have metabolic acidosis, what will happen to your bicarbonate? It will decrease. When Na and Cl will not change their values, you have a drop in your bicarbonate, anion gap increases. The normal anion gap would be 8-10 so in order to maintain electric neutrality, if bicarbonate becomes low, for the anion gap to be normal either Cl will increase or the unmeasured anions will increase. That is why if we have metabolic acidosis and the anion gap is computed and the anion gap is deranged then Cl is decreased, we have to request other anions. In the graph above, you have your blood pH, bicarbonate concentration and the red lines or values will represent CO2 concentration. For example, you have a pH of 7.3, bicarbonate of 12, pCO2 of 25. First look at the pH – acidosis. If you look at bicarbonate, it is decreased – metabolic acidosis but looking at CO2, it is decreased – respiratory alkalosis. It is mixed acid-base disorder so we use now the nomogram. Simply plug in the values. ďˇ ďˇ ďˇ pH: 7.15 HCO3: 7 mEq/L PCO2: 50 mmHg ďˇ Metabolic acidosis with respiratory component If you plug the values, you will have 2 points. Your primary disorder is metabolic acidosis. You have a respiratory component by looking at the value of CO2 which is acidosis because higher than 45 CO2 is acidosis. Your primary disorder is metabolic in origin so you need to investigate what is the main problem. It is possible that patient has ketoacidosis and the lungs are already decompensated that’s why he is having a respiratory acidosis. Here you have an increased anion gap, the Cl levels are normal. This simply means that unmeasured anions increased. Here are the different conditions (table above). If the anion gap is normal but Cl- increased in response to a drop in bicarbonate, here are your conditions (table above). So this helps us in the differential diagnosis of the patient. ďˇ ďˇ ďˇ pH: 7.40 HCO3: 30 mEq/L PCO2: 60 mmHg ď Correct the underlying cause ď ďˇ Chronic respiratory acidosis with renal compensation ď Alkalosis o NH4Cl, lysine monohydrochloride Acidosis o NaHCO3, Na-lactate, Na-gluconate Anion Gap ď ď ď ď ď Plasma: cations = anions Na, Cl, HCO3 are measured Plasma anion gap = Na – HCO3 – Cl Plasma anion gap = 144 – 24 – 108 Plasma anion gap = 10 mEq/L When we have patients with an acid-base disorder, it is also important to get their electrolytes like Na, Cl and bicarbonate. It is important to get these values for us to get the anion gap. ď ď ď Plasma anion gap = Na – HCO3 – Cl Plasma anion gap: 8-10 mEq/L o Used to diagnose metabolic acidosis o Electric neutrality: ďŁ Cl or unmeasured anion ďŁ anion gap o ďŁ anions: PO4, SO4, albumin, organic anions o ď¤ cations : Ca, Mg, K 12 Shannen Kaye B. Apolinario, RMT In the correction of acid-base disorders, it is important to correct the primary problem first. If the patient is having respiratory acidosis due to asthma or COPD, correct the asthma or COPD first, do not give bicarbonate right away. Same is true if the patient is having ketoacidosis, correct glucose derangements first. For alkalosis, these are the drugs used: ammonium chloride, lysine monohydrochloride which is more commonly used because it is safer. For acidosis, sodium bicarbonate, sodium lactate and sodium gluconate are used. Among the three, the safest to use are the sodium lactate and sodium gluconate. Micturition Micturition is both a conscious and unconscious action. There are some cortical control with regards to micturition. Micturition Reflex ď ď ď R: stretch receptors Aff: pelvic nerves C: S2-3 ď ď Eff: pelvic nerves E: detrusor muscle, internal urethral sphincter micturition reflex, inhibitory impulses then relaxation. So that is how we control the bladder – “toilet training”. ď Cerebral cortex, pons You will know that as the volume increases within the urinary bladder, the pressure being generated by your micturition reflex increases because the micturition reflex is said to be self-regenerating. Why? When the volume increases, the pressure inside increases and this is detected by stretch receptors. When the detrusor muscle contracts, pressure will further increase, stimulating the receptors more, so it will further increase. There will come a point wherein the pressure in the urinary bladder is not able to be controlled by the cerebral cortex because your cerebral cortex primarily controls skeletal muscles that’s your external urethral sphincter. If your micturition reflex allows relaxation of internal urethral sphincter and the pressure is too great, higher than your external urethral sphincter, no matter how you try to control or stop from urinating, it will still go out. ___“Nahuli? May tanong?”___ When we say micturition, it can either be conscious or unconscious but when we say micturition reflex, it is unconscious. Because this is a reflex, the components of the reflex arc should be present. Present in the urinary bladder are the stretch receptors. When stimulated by stretch, they will send impulses into the pelvic nerves (afferent), the center is S2 to S3 (some books would say S2 to S4). The center will be sending impulses going to the pelvic nerves affecting now the effectors and the detrusor muscles contracts whereas the internal urethral sphincter relaxes. But the activity of the arc is modulated by higher centers – cortex and the pons. If you look at you reflex arc, stimulation of stretch receptors will illicit contraction of the urinary bladder and relaxation of internal urethral sphincter. This is your urine or fluid volume and pressure. If the bladder is empty – 0 volume and 0 pressure. fluid slowly accumulates, the bladder distends stimulating now the stretch receptors. The stretch receptors will send impulses via pelvic nerves going to C3 and C4. C3 and C4 will be sending impulses via the same pelvic nerves for the contraction of the detrusor muscles and relaxation of internal urethral sphincter. When your detrusor muscles contracts the pressure inside will increase but that is not the end. Impulses will also ascend to the pons and the cerebral cortex. The cerebral cortex will assess if voiding is convenient. Your cerebral cortex will send inhibitory impulses down to C3 and C4 inhibiting the center. When the center is inhibited, no excitatory impulses will go to detrusor muscles and the internal urethral sphincter remains contracted and the pressure decreases. Urine will accumulate so the process will repeat – fluid accumulates, stimulation of stretch receptors eliciting a 13 Shannen Kaye B. Apolinario, RMT “And we know that in all things God works for the good of those who love Him – for those who have been called according to His purpose.” -Romans 8:28 GOD BLESS YOU ď Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine 1D – Batch 2020 Renal Physiology IV Body Fluids and Acid-Base Balance Dr. Ronald Allan Cruz – January 16, 2017 BODY FLUIDS ďˇ 60% of our body weight is water o So if you have a 70kg man, 42L is water The 60% of our body fluids are subdivided into two: 1. Extracellular fluid – 20% (14L) Divided into two: a. Interstitial fluid : 15% (11L) b. Plasma : 5% (3L) 2. Intracellular fluid – 40% (28L) Transcellular fluid – 1-2L ďˇ The 3rd space ďˇ A specialized compartment ďˇ Collection of fluids within specialized compartments like: o CSF o Pericardial fluid o Pleural fluid o Peritoneal fluid o Synovial fluid , etc. Blood ďˇ ďˇ Water Loss ďˇ It should equal water intake so it should be 2.3L also ďˇ Further subdivided into: o 700 mL – insensible losses ď§ Water that we lose and we are not aware of it ď§ 350 mL for evaporation from skin ď§ 350mL from respiration o 100mL from sweat ď§ Varies depending on temperature and physical activity o 100 mL from feces ď§ Varies if there is a diarrhea o 1400 mL from urine Certain conditions can alter the volume: Patient with burns: ďˇ The protective layer of the skin is removed (epidermis and dermis) ďˇ Increase loss of water via evaporation ďˇ So one of the cornerstone for the management of burns would be fluid replacement EXCHANGE OF FLUIDS BETWEEN COMPARTMENTS 7% of our body weight is basically blood It is said to be a special compartment because it contains both extracellular and intracellular water o Plasma ď§ The extracellular water ď§ 60% of blood volume is plasma (3L) o Formed elements ď§ the intracellular water ď§ RBC, platelets, WBC, etc. that contain water ď§ 40% of blood volume (2L) ď§ This is reflected in the clinic as hematrocrit Water intake ďˇ This is to maintain fluid homeostasis intake should be equal to output ďˇ On the average we take in around 2.3L per day o 2100 mL comes from the fluids that we drink o 200 mL comes from the breakdown of glucose / CHO oxidation ď§ We all know that when glucose is metabolized, CO2 and H2O are one of the products Diagram: represents the different ions from the intracellular and extracellular compartment. Take note of the various ions present in the both compartments. The line represents the cell membrane. ďˇ Its job is to regulate the flux of water between two compartments The Great Escoto 1 of 17 Diagram: Represents the extracellular compartment that is divided into two: Plasma & interstitial compartment. The black line represents the endothelial capillary wall/membrane which separates the two. ENDOTHELIAL CAPILLARY WALL/MEMBRANE ďˇ will not allow plasma proteins to enter the interstitial compartment ďˇ and since PP are negatively charge, GIBBS DONNAD EFFECT is observed o some cations are attracted to Plasma proteins o some anions are more present at the interstitial compartment due to ionic repulsion For example, you have this container with an unknown volume and you want to determine its volume. What you would do is to administer an indicator with a known volume and concentration. ďˇ ďˇ ďˇ ďˇ For example: you have an indicator whose concentration is 10mg/mL and you administer 1mL of that indicator You place that indicator inside the system Allow it to go steady state and determine the concentration of the system Let’s say it is 0.01 mg/mL Application using the formula: CA= 10mg/mL VA = 1mL CB = 0.01 mg/mL VB = ? Table: the different substances present in the different compartments: Plasma, interstitial and intracellular compartment. Highlighted in red – located extracellularly Highlighted in blue – located intracellularly At the bottom portion, the one highlighted in green, it is the total osmolality, the total osmolar activity and the total osmotic pressure INDICATOR-DILUTION PRINCIPLE ďˇ used in measuring specific volumes ďˇ Measurement of fluid volumes in different compartments CA x VA = CB x VB CA = Concentration of indicator VA = volume of indicator CB = concentration of the system VB = volume of system VB = 10mg/ml x 1ml 1.01 mg/ml VB = 1000 ml Nasundan paano nakuha yon? You got that? – Dr. Cruz In determining specific volumes in the body, we need to utilize an appropriate indicator. So for in measuring: 1. Total Body H2O – we utilize radio labeled water or hard water or heavy water a. 3H2O, 2H2O 2. Extracellular fluid volume – we utilize inulin or radio labeled Na (22Na) a. Plasma volume – we utilize radio labeled albumin (125I-albumin) b. Interstitial volume – subtract the plasma volume from extracellular The Great Escoto 2 of 17 3. 4. volume (extracellular volume – plasma volume) Intracellular volume = Total H2O minus extracellular volume Total blood volume = you can use: a. Plasma / (1-hct) b. Or you can use radio labeled RBC (51Cr-labeled RBC) In employing an appropriate indicator, you need to fulfill three important criteria: 1. 2. 3. Your indicator must stay in the compartment you want to measure a. If your indicator goes out, you can’t use it The indicator must be dispersed evenly in the compartment you want to measure Your indicator must not be metabolized within the compartment you want to measure Once these criteria are fulfilled, only then you can use the indicator to measure the particular volume for a particular compartment. Osmotic Equilibria Between Extracellular and Intracellular Fluid ď ď Plasma and interstitial fluid volume ďź Recall that between the intravascular and the interstitial space, it is separated by the endothelial wall or capillary wall. ďź Starling forces regulates the flow of H2O between these two structures: ď Hydrostatic pressure ď Colloid osmotic pressure Extracellular and intracellular fluid volume ďź The two compartments are separated by the cell membrane ďź What determine the movement of water is the: Osmotic effects of solutes ď Specifically Na because it determines the volume of the extracellular fluid ALWAYS TAKE NOTE: The intracellular compartment is said to be isotonic with the extracellular compartment. Recall of some concepts: Osmosis – movement of water from low solute concentration to a high solute concentration Osmotic pressure – this is the pressure that is required to stop osmosis. Osmoles ďˇ The total number of osmotically active particles in a solution o These are the substances that will attract water ďˇ 1osm = 1 mol of a substance = 6.02x1023 particles (Avogadro’s number) ďˇ 1mOsm = 0.001 osm Osmolality ďˇ This is the osm/kg of H2O Osmolarity ďˇ This is the osm/L of H2O Chemically speaking ďˇ They are different. ďˇ Osmolality is more accurate because volume is affected by temperature o By increasing the temperature, you increase the volume but mass stay the same Medically speaking ďˇ They are interchangeable o Simply because our body does not reach 100oC – we have a stable body temperature. ď§ We reached up to 40o when we are in fever but that does not change the volume drastically. The number of osmotically active particles by different substances: ď 1 mole/L of glucose = 1 osm/L ď 1 mole/L of NaCl = 2 osm/L ď 1 mole/L of Na2So4 = 3 osm/L If you have the same concentration of glucose, NaCl, Na2SO4, we all know that Na2SO4 when placed in water will dissociate into three particles: 2 Na and 1 SO4 ions. Thus it will exert a greater osmotic pressure compare to one mole of glucose. Osmotic pressure ďˇ The pressure required to oppose osmosis ďˇ It is an indirect measure of the number of solute within the fluid. o The greater the concentration of the fluid, the greater the osmotic potential ďˇ What is more important is the number of ionizable particles: o Increase osmotically active particles = increase osmotic pressure o It is independent to the size of the particles Example: Na2SO4 > NaCl > albumin = glucose A Na2SO4 exerting a greater osmotic potential than albumin. Though albumin is a large molecule, given a same concentration with Na2SO4, it will have a less osmotic potential. The Great Escoto 3 of 17 VAN’t HOFF’s Law o Computes for osmotic pressure o The unit is the mmHg 9. It is this 286 mOsm that you will multiply to 19.3 to get your corrected osmotic pressure. 10. So the corrected osmotic pressure is: π=CRT π – mmHg C – concentration of solutes in osm/L R – ideal gas constant T – temperature, 310 kelvin 286 mosm/L x 19.3 mmHg/mosm/L = 5519.8 mmHg of NSS 1osm/L = 19300mmHg 1mOsm/L = 19.3mmHg 1 mOsm of a substance per liter is able to exert a pressure of 19.3mmHg APPLICATION Let’s say we have 0.9% NSS (NaCl). So basically, what is the pressure exerted by NSS? 1. 2. Here you have 0.9% NaCl which is equivalent to 0.9g/100mL H2O a. It is also equal to 9g/L of H2O To get the number of moles, you simply divided that to the molecular weight of NaCL which is 58.5 g/mol 9 g/L ÷ 58.5 g/mol = 0.154 mol/L 3. Then we multiply it by 2 because if we place NaCl in water, it dissociates into Na and Cl. Nasundan? a. So if it was Na2SO4, multiply it to 3. Malinaw? Table: In the body, here are the different substances present in the different compartments (plasma, interstitium and intracellular compartment. All of these substances will exert osmotic potential. They will attract water. 0.154 mol/L x 2 = 0.308 osm/L 4. 5. Convert that to mOsm by moving the decimal point so = 308 mosm/L. nasusundan so far? To get the pressure, you simply multiply the mOsm to 19.3mmHg/mOsm/L 308 mosm/L x 19.3 mmHg/mosm/L = 5944 mmHg of NSS 6. 7. So NSS will have a pressure of 5944 mmHg. But that doesn’t stop there a. You need to take into account the correction factor of NaCl. Correction factor of NaCL = 0.93 so if you place NaCL in water, only 93% of NaCl will dissociate into Na and Cl. The other 7% will stick as NaCl. This is because Na is positive and Cl is negative, they will always have some ionic attraction between the two. 8. So from 308 mOsm/L, you multiply it to the correction factor Table: Magnified bottom part of the above table ďˇ ďˇ ďˇ This now the total osmolarity but you always need to take into account the corrected factor for each ion. By taking into account the correction factor for all the ions, the corrected osmolar activity are presented on the second row. o You will notice that they are ALMOST equal with one another. To get the pressure now, you multiply the corrected osmolar activity by 19.3 mmHg Take note: All three compartments are said to be isotonic with one another. You will also notice that the plasma has a higher osmotic pressure compared to the two, this is due to the presence of Plasma Proteins. 308 mosm/L x 0.93 = 286 mosm/L The Great Escoto 4 of 17 Isotonic fluid ďź It means that the solution has the same osmotic pressure /potential NOT the same concentration. o It is said to be that the 0.9NaCl (NSS) is isotonic with plasma, IT DOES NOT HAVE THE SAME CONCENTRATION WITH PLASMA because it contains Na and Cl while plasma contains NaCL, K, Mg, SO4 etc. o What is the same between the two is the ability to attract water or osmotic potential ďź Examples are NSS and PLR Hypotonic solutions ďź The solution has a lower ability to attract water. Hypertonic solutions ďź The solutions has a higher ability to attract water TAKE NOTE: Dextrose 5% water (D5 water) is NOT isotonic. It is ISOOSMOTIC. ďź It has the same ability to attract water ďź It is not the same with isotonic even though it has the same ability to attract water like plasma ďź If you place cells within D5 water, glucose is an INEFFECTIVE osmole because glucose will readily enter the cell. o once glucose enters the cell, this will decrease the glucose concentration of the medium, rendering your fluid HYPOTONIC. Sensors that will detect Effective Circulating Volume 1. Vascular low-pressure volume sensors ďź Located within the atria and pulmonary vessels ďź They detect venous return Example: When you decrease venous return, you decrease the filling of atria and the pulmonary vessels ď this will be detected by the receptros ď activates sympathetics and ADH ď ↑ volume Increase venous return ď increase filling ď sympathetics go down ď ANP and BNP are released ď excrete water or ↓ volume ďź 2. Vascular high-pressure volume sensors ďź These are the barorecpetors (aortic and carotid sinus) and afferent arterioles ďź They detect cardiac output Example: When CO is low ď ↓ decrease BP ď inhibit baroreceptors ď increase sympathetics to heart and blood vessels ď increase BP ď increase blood volume But for kidneys since BP is low ď RBF goes down ď GFR goes down ď activating JG apparatus ď increasing RAAS ď increases volume ďź Hepatic sensors ďź Hepatic blood vessels contain volume and Na sensors ďź Increase Na or volume ď decrease sympathetic activity ď increase Na excretion (we all know that where Na goes, water follows) 4. CNS Average Blood Volume = 5L Under certain conditions, 5L may not be enough to perfuse body tissues for the body organs. Effective circulating volume ďˇ The volume that will effectively perfuse tissues ďˇ Keep in mind that volume is Na dependent Extracellular volume = Plasma + interstitial fluid If you have a 5-10% change in volume, that will evoke a response 3. EFFECTIVE CIRCULATING VOLUME A classic example is Septic Shock ďź even if the patient has 5L of blood, if he is suffering from septic shock, all of the blood vessels will dilate. o This will increase the capacitance of blood vessels ďź Although Blood volume is 5L, this will not ensure that the different organs are properly perfused so that’s why we have the concept effective circulating volume. If you have a 5-10% change in volume, that will evoke a response ďź ďź ďź in the hypothalamus contains Na sensors this detects the Na content of CSF or carotid perfusion increase in Carotid or CSF Na ď increase Natriuretic peptides and angiotensin IIď increase Na excretion VOLUME EXPANSION ďź the body would have to remove excess Na ďź Na excretion ďź The effects are: o ď¤ renal sympathetic effects o ďŁ ANP, BNP, urodilantin o ď¤ ADH, renin, RAAS The Great Escoto 5 of 17 VOLUME CONTRACTION ďź Because the volume goes down, the body would have to reabsorb Na ďź Na Reabsorption ďź the effects are: o ďŁ renal sympathetic effects o ď¤ ANP, BNP, urodilantin o ďŁ ADH, renin, RAAS Take note: they are just opposites. VOLUMES AND OSMOLALITIES OF EXTRACELLULAR AND INTRACELLULAR FLUID IN ABNORMAL STATES Fluid Compartments ďź In calculating intracellular and extracellular fluid volume: o Water moves rapidly across cell membrane o Cell membranes are almost completely impermeable to solutes ď§ Solutes are not able to pass through C: Adding a hypertonic solution, water inside the cell will go out ďź the Intracellular volume goes down ďź ECF volume increases ďź The tonicity of both compartments both increases. Other than NSS and PLR, we also have other fluids available in the clinic: 1. Glucose 2. Amino Acids Sometimes we incorporate medications with the fluid and that will change the tonicity of the fluid. So all of these fluids must be adjusted to isotonicty and they must be administered slowly. For example: Common fluids can contain glucose (D5 NSS) or they may contain Amino Acids for nutritional build up. Glucose and AA are ineffective osmoles, they readily enter the cell and we all know that when these substances enter the cell, they will render the fluid hypotonic. So we do not administer these substances in fast drip so the body can excrete excess water. CLINICAL ABNORMALITIES OF FLUID VOLUME REGULATION Diagram: Volume is plotted against osmolarity showing the intracellular and extracellular volume. A: Adding an isotonic solution, the volume of the cell will not change ďź volume of the intracellular compartment is the same ďź since you are adding an isotonic solution, the extracellular fluid volume increases ďź the tonicity will be the same B: Adding a hypotonic solution, water will enter the cell ďź the volume of the cell (intracellular compartment) increases ďź the volume of the ECF increases since you are adding a hypotonic fluid ďź both their tonicity will go down HYPONATREMIA – we all know that Na basically detects ECF volume ďˇ Hypoosmotic dehydration o water goes down with decrease Na o Clinical conditions: ď§ Electrolyte, H2O loss ď§ Diarrhea, vomiting ď§ Diuretics ď§ Addison’s disease ďˇ Hypoosmotic overhydration o Water goes up with decrease Na o Clinical conditons: ď§ SIADH You should read on this daw. Why Na is low while water is increased or decreased. HYPERNATREMIA ďˇ Hyperosmotic dehydration o Water goes down with increase Na o Clinical conditions: ď§ DI ď§ Excessive sweating ďˇ Hyperosmotic overhydration o Water goes up with increase Na o Clinical conditions: ď§ Conn’s syndrome (1o hyperaldosteronism) ď§ 2o hyperaldosteronism The Great Escoto 6 of 17 NON ISOTONIC CELL VOLUME REGULATION ďź the body has a defense mechanism by which the cells will regulate its own volume so that it won’t expand or won’t shrink even if you give a hypertonic or a hypotonic solution. Cell Shrinking ďź this will happen when you administer a hypertonic solution because water inside the cell will go out ďź what it will do is to undergo regulatory volume increase response o the cell will start to produce its osmolytes o when the cell shrinks, you have the cytoskeleton which will modify the volume of the cell. o Once the cell shrinks and the cytoskeleton is activated, osmolytes production are activated. o Osmolytes are located more intracellularly and exerts osmotic potential o water will not go out so water is maintained & cell volume is more or less maintained. Cell Swelling ďź this will happen when you administer a hypotonic solution because water outside the cell will go in ďź the swelling will be detected by cytoskeletal elements and it will undergo regulatory volume decrease response o again the cell will synthesize the osmolytes but o the osmolytes will be pumped extracellularly because you administer a hypotonic solution o this will increase osmotic potential extracellularly preventing water from entering the cell. o The volume of the cell is maintained. Osmolytes ďź Ions, amino acids o Na, Cl, K o Taurine, glutamate, Ala ďź Polyols o Sorbitol, myoinositol ďź Methylamines o Glycerophosphoryl-choline, betaine Osmotic demyelinization syndrome ďź A condtion in which occurs in patient with decrease Na and you rapidly correct Na o So in correcting Na, you need to slowly adjust it. How does this happen? (as explained by Dr. Cruz) When you have a patient with hyponatremia, Na outside the cell is less so it is hypoosmotic therefore there is a tendency for water to enter the cell causing the swelling. But then you activate the regulatory decrease response synthesizing osmolytes and pumping it out of the cell. More osmolytes are found extracellularly. When Na is rapidly increased, the cell will start to shrink. You do not give proper time to the cell to synthesize osmolytes intracellularly. So H2O now goes out causing shrinking of the cell. The more susceptible cells would be the neurons in the white matter and in the pons. ďź ďź Myelin sheath is destroyed The condition is irreversible. So in correcting Na especially in hyponatremia, it should be slow for the cell to synthesize enough osmolytes. EDEMA Accumulation of fluid 2 types: o Intracellular edema/swelling o Extracellular edema/ swelling Intracellular edema ďź Water accumulates within the cell ďź Manifestation is non-pitting edema o Depression does not persist after pressing ďź Pathology: o ď¤ metabolism o ď¤ nutrition o ď¤ ion pump activity o ďŁ osmosis o Inflammation Extracellular edema ďź Water accumulates in the interstitial space ďź Manifestation is Pitting edema o Depression persist even after pressing ďź Pathology: o Plasma leakage o Failure of the lymphatic drainage The Great Escoto 7 of 17 So here you have your filtration coefficient and Starling forces. If you will recall, these are the factors that will affect the amount of water going into the interstitium. F = Kf x [(Pc+πi)-(Pi+πc)] F – filtration rate Kf – filtration coefficient Pc – capillary hydrostatic pressure πi – interstitial oncotic pressure Pi – interstitial hydrostatic pressure πc – capillary oncotic pressure Lymphatic drainage For edema to occur you have four important factors to take note of and they are highlighted in red. Any problems with the four will cause edema. For example changes in your filtration coefficient, capillary hydrostatic, capillary oncotic pressure and lymphatic drainage. For each factor you have several examples. Table: You have the four factors that can cause edema. Any condition that will cause edema can fall under one or more categories. Example: 1. Congestive heart failure ďź It can cause edema primarily because you increase the capillary hydrostatic pressure. 2. Burned Patient ďź When you damaged the skin due to burns, blood vessels are also damaged. ďź When BVs are damaged, Plasma proteins are decreased due to leak out o Capillary oncotic pressure drops ďź Burns is also under the increased Kf because if BVs are destroyed, capillary permeability is increased. SAFETY FACTORS THAT PREVENT EDEMA The body has some way in protecting us from edema 3 factors: o Low compliance of the interstitium o Increased lymph flow 10-50x o Washdown on interstitial fluid CHON 1. Low compliance of the interstitium ďź Primarily due to the presence of these in the interstitial space: o Negative pressure o Interstitial gel o Proteoglycans and collagen filaments *let’s look at it one by one* A. Negative pressure ďź The pressure in the interstitium is said to be -3mmHg Table: If the pressure is -3mmHg, the volume of the interstitial compartment is around 11-12L and that is the amount of fluid present in the interstitial space. You can equate this in a vacuum seal because the pressure inside a vacuum seal is negative. ďź As long as pressure is in the negative side, small changes in fluid volume are associated The Great Escoto 8 of 17 ďź with large changes in interstitial hydrostatic pressure o For as long as the pressure is in 3mmHg, the slightest increase in water in the interstitial compartment, drastically increases the interstitial hydrostatic pressure. o We all know that increasing the interstitial hydrostatic pressure pushes the fluid back to the blood vessels, preventing edema. For as long as your pressure is in the negative range ď COMPLIANCE IS LOW o C= âV / âP o Compliance is expansibility so when you have a negative pressure, you can’t expand it easily. B. Interstitial gel ďź The function is to prevent the flow of fluid ďź Offers elastic resistance to compression ďź Compact brush pile o This will not allow the flow of water because the gell is compacted together due to the negative pressure (like a vacuum seal) o Water from the upper portion of the body can’t easily go to the lower extremities due to compact brush pile ďź The interstitial fluid vol does not change greatly. C. Proteglycan Filaments ďź Although the gel are compacted together, the proteoglycan filaments are located in between the gel that acts as a spaces. ďź Modulates the flow of fluid ďź Permits the flow of other substances like the nutrients and metabolites o Nutrients and metabolites can readily go through the interstitium but it will not allow the passage of water. Increased Compliance of the Interstitium What happens when the interstitium becomes positive? Looking at the graph: ďź If the interstitium becomes positive ď there is a drastic increase in fluid volume It’s like a hole in the vacuum seal allowing air to enter that increases the pressure within the package ďź Compliance will increase o You can now separate the layers ďź Increases the volume because water enters ďź All of the gel present will be dispersed / the brush pile is pulled apart ďź The spaces in between will now be occupied with water 2. Increased lymph flow 10-50x / Lymphatic drainage ďź If water is allowed to enter the interstitial compartment, that will increasing the interstitial hydrostatic pressure o And by increasing it, this will facilitate lympathic drainage. ďź Safety facto is 7mmHg 3. Washdown on interstitial fluid CHON / drainage of interstitial proteins ďź Once Pi increases (facilitates lympathic drainage), at the same time, some of the interstitial CHON will be carried into the lymphatics and brought back to the blood ďź This decreases the interstitial oncotic pressure ďź Safety factor of 7mmHg ď Low compliance of the interstitium ďź Negative pressure ďź Interstitial gel ďź Proteoglycan and collagen fillaments ďź 3 mmHg Increased lymph flow 10-50x ďź 7 mmHg Washdown on interstitial fluid CHON ďź 7 mmHg ď ď Looking at the three factors, highlighted in red are the safety factors. The total safety factor would be 17mmHg. ďź For edema to occur, the effective filtering pressure must EXCEED 17mmHg. FLUIDS IN THE POTENTIAL SPACES OF THE BODY / TRANSCELLULAR FLUIDS Potential Spaces – specialized cavities ď Pleural cavity ď Peritoneal cavity ď Pericardial cavity ď Synovial cavity The fluid there is serve to prevent/reduce friction. ďź ďź ďź Fluids exchange between capillaries and the potential space just like the interstitium Lymphatics drain fluid from potential space It also has negative fluid pressure Table: Shows the negative pressure inside the spaces. The Great Escoto 9 of 17 Just like the interstitium, if these negative pressure becomes positive: ďź Fluid will accumulate ďź Example: pleural effusion, ascites, or tamponade ďź The safety factors are their range of pressures. 2. ACID-BASE BALANCE 3. Some Normal Values: Extracellular concentration of H+ ions in the body ď 0.00004 mEq/L To get the pH ď -log of the H+ concentration ďˇ So you’ll have a value of 7.4 ďˇ In the clinics, the range is from 7.35 – 7.45 ďˇ Intracellular ďˇ Extracellular Respiratory System ď§ reacting from minutes to hours ď§ 2nd most important ď§ Handles H2CO2 or volatile acid Renal System ď§ reacting within days (3-5 days) ď§ Most important and most powerful regulators of pH because it can handle a wide variety of acid and bases Intracellular Buffers ďź H moves in or out of the cell ďź Intracellular buffers 1. HCO3 2. PO4 3. Histidine ďź Intracellular CHON 1. H + Hgb ď˘ HďHgb ď§ Hemglobin can acts as abuffer because H+ can combine with hemoglobin ď§ pK of hgb = 7.4 pK ďź ďź Table: different compartments in the body with their H+ ion concentration with their pH. When you speak of an acid ď will donate a proton When you speak of a base ď will accept a proton Example: H2CO3 ďŽ H + HCO3 ďˇ This is your carbonic acid giving in a H+ and HCO3 ďˇ Carbonic acid is the conjugate acid of HCO3 ďˇ HCO3 is the conjugate base of the H2CO3 ďˇ The reaction is reversible Control of Hydrogen Ion Concentration ďź To regulate the pH, there are three mechanisms: 1. Chemical Buffer systems ď§ 1st to react when pH becomes deranged ď§ Least potent ď§ Divided into: dissociation constant at around this pH value, you have maximum buffering capacity Extracellular buffers ďź HCO3 buffer system o More important ďź PO4 buffer system o This is basically a buffer of the renal tubule and inside the cell Bicarbonate Buffer System How do we produce HCO3 now? 1. CO2 combines with H2O with the action of carbonic anhydrase forming carbonic acid CO2 + H2O ďŽ H2CO3 2. Carbonic acid dissociates into hydrogen and HCO3 H2CO3 ďŽ H + HCO3 3. HCO3 combines with Na present in the extracellular compartment forming SodiumBicarbonate Na + HCO3 ďŽ NaHCO3 4. Combining all of the equations: CO2 + H2O ďŽ H2CO3 ďŽ H + HCO3 Na + HCO3 ďŽ NaHCO3 The Great Escoto 10 of 17 ďź By adding acid into the system (lactic acid is example): o You increase the H+ concentration o H+ ion will combine with HCO3, shifting the reaction to the left (reactant’s side) pK ďź By adding base (specifically NaOH) o NaOH will react to carbonic acid o That will shift the reaction to the product side Henderson Hasselback equation; ďź Compute for pH given a known concentration of HCO3 and CO2. ďź H = K x (0.03mmol/mmHg x PCO2)/[HCO3] ďź pK = -log K o -log H = -log K -log (0.03 x PCO2)/[HCO3] o pH = pK -log (0.03 x PCO2)/[HCO3] o pH = pK +log [HCO3]/(0.03 x PCO2) o pH = 6.1 +log [HCO3]/(0.03 x PCO2) *not required to be memorized but you need to be familiar with the equation* In utilizing the Henderson Hasselbach’s eqution you need: 1. the concentration of HCO3 in the blood ďź determined by ABG 2. the concentration of CO2 in the blood ďź determined by ABG Once you have the BG values, you can now compute for the pH. The pK for HCO3 buffer system = 6.1 ďź ďź at this pH, there is an equal amount of protonated and unprotonated species. o So at 6.1 pK in the HCO3 buffer system, you have an equal amount of protonated and unprotonated species. Around this pH, this is the maximum buffering capacity o So at 6.1 pH, that is for HCO3 o So any changes in pH, the HCO3 buffer system, it will try to bring it back to 6.1 The normal pH of the body is 7.35 – 7.45: ďˇ Remember that the HCO3 buffer system will try to bring the pH to 6.1 but the pH of our body is 7.4 ďˇ This is why the buffer system are the weakest so it is now the job of the lungs and the kidneys to bring the pH to 7.35 – 7.45 Phosphate Buffer System ďˇ These are: o H2PO4 o HPO4 ďˇ They are more important as: o Intracellular buffer o Buffer in the renal tubules ďˇ pK = 6.8 Example: ďź If you add an acid into the system, it will react into Na2HPO4 producing NaH2PO4 and NaCL HCl + Na2HPO4 ď˘ NaH2PO4 + NaCl ďź If you add a base into the system, it will react into NaH2PO4 producing NaHPO4 and water NaOH + NaH2PO4 ď˘ Na2HPO4 + H2O The Great Escoto 11 of 17 Isohydric Principle ď H = K1 x (HA1/A1) = K2 x (HA2/A2) = K3 x (HA3/A3) ďź This is your H+ that is equal to the various buffer system in the body acting simultaneously ďź For example K1 will represent intracellular protein, K2 will be HCO3 buffer & K3 will be the PO4 buffer system ď If you change your H+ concentration or you change the pH, all three systems will act simultaneously ď If you change one system (example the third system), the other system will adjust as well to maintain the hydrogen ion concentration HYDROGEN ION SECRETION ďź Via Na-H countertransport / exchanger o Secretion of H+ is dependent on Na availability o Whenever Na enters, H is pumped out ďź To reabsorb HCO3, 1 H+ must be secreted o The excess 70 mEq of H+ in the renal tubules would have to be buffered by the tubular buffers: ď§ H2PO4, HPO4, NH3, urate, citrate buffers Respiratory System ďź Controls extracellular CO2 o It can only handle H2CO3, a volatile acid ďź Alveolar ventilation modulates PCO2 ďź 50-75% effective ďź 1-2x buffering power greater than te chemical buffer system ďź It will act within minutes ďź When pH is high, this will inhibit the respiratory center, decreasing ventilation ďź When pH is low, it stimulates the respiratory center, increasing ventilation Renal System ďź Handles wide variety of acids and bases o Excretes acidic or basic urine ďź Around 4320 mEq/day of HCO3 is filtered o The body would have to reabsorbe HCO3 (ideally) ď§ To reabsorb HCO3, 1 H+ must be secreted ďź Around 4390 mEq/day of H is secreted o 4320 mEq of H is secreted due to HCO3 reabsorption ď§ So it is said that at this point, all of the HCO3 reabsorbed o 70 mEq of H is excreted as nonvolatile, titratable acids ď§ These are the excess from HCO3 reabsorption ď§ This is why our urine is normally acidic. In order to maintain acid-base balance: 1. Secretion of H ions 2. Reabsorption of HCO3 3. Generation of new HCO3 Diagram: this will show the HCO3 reabsorption. Take note that major reabsorption of NaHCO3 happens in the PCT. For the DCT and CD, it is where acid-base regulation happens. 1. 2. 3. 4. When there is a filtered HCO3, we need to reabsorb it. Within the cell, you have CO2 and water being produced With CA, you produced carbonic acid Carbonic acid dissociates to HCO3 and H+ The Great Escoto 12 of 17 5. 6. 7. 8. H+ ion will be pumped out ďź In the diagram, it is the Na-H antiport ďź Another is the H+ pump (as exemplified by the purple circle with ATP label) H+ will combine to the filtered HCO3 forming H2CO3 H2CO3 will be acted upon by CA producing water and CO2 CO2 can freely enter the cell and goes again through the same process DCT, CT INTERCALATED CELL: NON-HCO3 BUFFER Filtrate So in order for us to reabsorb this HCO3, H+ must be secreted. If H+ is not present, the HCO3 in the filtrate will not become a carbonic acid nor CO2 therefore, it can’t enter the cell and excreted. DCT, CT Alpha AND Beta INTERCALATED CELL: H AND HCO3 SECRETION Acidosis (alpha intercalated cells because it primarily handles H+ secretion) ďź During acidosis alpha intercalated cells increases its activity promoting H+ secretion 1. 2. 3. 4. 5. 1. Same process as what is discussed previously Alkalosis (beta intercalated cells because it primarily handles HCO3) ďź During alkalosis, increased activity of beta intercalated cells promoting HCO3 excretion 1. 2. 3. In the cell you have CO2 combining with water forming H2C03 This will dissociate to HCO3 and H+ HCO3 goes to the filtrate and H+ goes into the blood. CO2 combines with water forming H2CO3 H2CO3 dissociates into HCO3 and H+ ďź HCO3 goes into the blood H+ ion is secreted via Na-H antiport H+ will now combine with non-HCO3 buffer, in this case a phosphate buffer (NaHPO4-) ďź H+ ion can combine with any of these as long as it is not HCO3: i. NH3 ii. Urate iii. Citrate When it combine with a non-HCO3 buffer, the H+ is excreted ďź Take note that the HCO3 is added to the system. So there is a net gain of HCO3 for every H+ secreted. ďź Another thing to take note is that if your H+ here combines with a HCO3, you simply reabsorb it, you do not add it to the system. (di ko gets haha) DCT, CT INTERCALATED CELL: ALDOSTERONE EFFECT 1. 2. Increased Na-pump promoting H+ ion secretion Promoting HCO3 reabsorption a. That is why in hyperaldosteronism, alkalosis occurs. The Great Escoto 13 of 17 DCT, CT INTERCALATED CELL: NH3 BUFFER ďź This is due to the breakdown of amino acid 2. 3. 4. 5. One in the filtrate, NH3 will combine with H+ so it becomes NH4, ammonium ďź Since it is already charged, it can’t cross the membrane (diffusion trapping) In the distal segments, the mechanism are the same NH3 can easily cross the cell membrane ďź Once in the filtrate it will combine with H+ forming NH4+ ďź It will now be excreted Going down, you’ll have an antiporter ďź It will pump NH4 into the cell and out into the filtrate in exchange for H+ o NH4+ exchanger GENERATION OF NEW BICARBONATE 1. 2. 3. 4. 5. 6. Water combines with CO2 forming H2CO3 H2CO3 dissociates to HCO3 and H+ H+ geos out via H+ pump NH3 can easily cross cell membrane and combine with H+ ions a. this will make the NH3 to have a charge ď NH4+ (diffusion trapping) NH4+ can combine with Cl- to be excreted Since your hydrogen ion is buffered by a nonHCO3 buffer, a HCO3 is gained into the system. TAKE NOTE: In the DCT andCD, as long as you secrete H+ and as long as it binds to a NON-HCO3 BUFFER, you will gain a NEW HCO3 into the system. NH4 PRODUCTION, TRANSPORT, EXCRETION ďź ďź ďź ďź 4 5 In generation of new HCO3, you metabolize gulatmine The breakdown of glutamine will produce 2 moles of HCO3 and 2 moles of NH4 NH4+ is pumped out into the filtrate to be excrted There will be a net gain of HCO3 into the system Titration of H in the tubular lumen ďź If H combines with HCO3 (H + HCO3): o HCO3 is reabsorbed ďź If H combines with non-HCO3 buffers o A new HCO3 is added into the system /generation of a new HCO3 During Acidosis: Excess H ďź All of HCO3 is 100% reabsorbed ďź And there will be generation of new HCO3 o This will attempt to correct acid-base disorder HYDROGEN ION SECRETION 1. In early segments, NH3 can: ďź Easily go out into the filtrate ďź Or pumped out via Na-NH3 exchanger Stimuli for H+ secretion 1. ďŁ PCO2 a. Excess CO2 within the body will cause respiratory acidosis 2. ď¤ extracellular pH The Great Escoto 14 of 17 3. Excess aldosterone (we all know that it powers H+ secretion) a. ďŁ loss of H, NH4, titratable acids b. ďŁ HCO3 During Acidosis: ďź Favorable cell-to-tubular fluid H gradient o More H+ ions in the body compared to the filtrate favoring H+ secretion ďź Allosteric changes in transport CHON o For example is albumin ďź Regulation of number of transporters: o Na-H antiporter (H+ secretion) o Na-HCO3 symporter (HCO3 reabsorption) ďź ET-1, cortisol o It will be increased and its effect is to increase the transporter Volume Contraction: ďź Increase in H+ ion secretion o Increased Na-H antiport, Na-3HCO3 symport o RAAS o Increased intercalated cell secretion o Changes in Starling forces that favors Na reabsorption Volume Expansion: ďź Decrease in H+ secretion o Decreased Na-H antiport, Na-3HCO3 symport o deccreased intercalated cell secretion o Changes in Starling forces that antagonizes Na reabsorption i. If the solution turns pink, it is the amount of NaOH consumed therefore that is the amount of H+ present Net Acid excretion = (NH4 excretion + urinary titratable acid) – HCO3 excretion In order to maintain acid-base balance: ďź net acid excretion must be equal to nonvolatile acid production o acids other than carbonic acid like lactic acid etc. ďź During acidosis: o Increased H+ secetion, NH4 excretion increases and new HCO3 is added to the blood ďź During alkalosis o No NH4 and titratable acid excretion ď increased HCO3 excretion ď no new HCO3 is generated ACID-BASE DISORDERS Simple acid-base disorders pH = 6.1 +log [HCO3]/(0.03 x PCO2) QUANTIFYING ACID-BASE SECRETION What we need to determine in the lab are: 1. HCO3 Excretion ďź V x UHCO3 V = urine flow rate UHCO3 = urine bicarb concentration ďź 2. NH4 Excretion ďź V x UNH3 V= urine flow rate UNH3 = urine NH3 concnetration ďź 3. This measures the removal of HCO3 from the blood or the additional of H+ in the blood Measures the amount of new HCO3 added into the blood Titratable acids ďź Non-HCO3 and non-NH4 buffer excreted like phosphate , citrate, urate buffers. ďź Measured via titration with NaOH During Acidosis: ďź There is excess H+ ion ďź Manifestations: o H > HCO3 o H excreted, acidic urine o Reabsorption of all filtered HCO3 o ďŁ Na-H antiport, 1Na-3HCO3 symport, ET-1, cortisol o Generation of new HCO3 o ďŁ NH4 excretion o Lungs: ďŁ ventilation due to decrease pH The Great Escoto 15 of 17 During Alkalosis: ďź There is excess HCO3 ďź Manifestations: o HCO3 > H o HCO3 excreted, alkaline urine o ď¤ H secretion o ď¤ Na-H antiport, 1Na-3HCO3 symport, ET-1, cortisol o NH4 and titratable acids are not excreted o No new HCO3 o Lungs: ď¤ ventilation due to increase pH Application: ABG of: pH: 7.3 ď acid HCO3: 12 mEq/L ď acid PCO2: 25 mmHg ď base 1. 2. 3. COMPLEX ACID-BASE DISORDERS Acid- base nomogram This is utilized when you have complex acid-base disorders. In using this, you must take into account the pulmonary and renal correction. You don’t use this immediately because the kidneys will take days to function in correcting acid-base disorders. You need to allow pulmonary and renal compensation first before using this. The red lines are PCO2, x axis is arterial bood pH and y axis is the PlasmaHCO3 concentration Plot the values When you trace, you will be pointed to metabolic acidosis ABG of: pH: 7.15 ď acid HCO3: 7 mEq/L ď acid PCO2: 50 mmHg ď acid ďź ďź ďź In this you have two points. You need to analyze the ABG o This is not a simple metabolic acidosis An accurate diagnosis is metabolic acidosis with respiratory component o You can’t write metabolic acidosis only because when you will refer this The Great Escoto 16 of 17 ďź patient, the clinician might miss out the respiratory component This could be a combination of disease entities o Example you have diabetic patient with ketoacidosis and this patient has COPD which can cause acidosis ABG of: pH: 7.40 ď normal HCO3: 30 mEq/L ď base PCO2: 60 mmHg ď acid Anion Gap ďź It is basically utilized when there is metabolic acidosis o When the patient has metabolic acidosis, looking at the equation for the anion gap, HCO3 is deranged (goes down) o There will be a wide anion gap, it increases during metabolic acidosis ďź Plasma anion gap: 8-10 mEq/L o So for the anion gap to be normal when there is low HCO3, Cl needs to increase or other umeasured anion o If we have metabolic acidosis and the anion gap is deranged, Cl is also decreased, you need to request for other anions. When the anion gap increases = > 10mEq/L ďź You should now investigate for other electrolytes o There could be an increase in anions ď§ PO4, SO4, albumin, organic anions o There could be a decrease in cations ď§ Ca, Mg, K Application: Diagnosis: Chronic respiratory acidosis with renal compensation ďź If the pH was 7.3 ď the diagnosis would be chronic respiratory acidosis with partial renal compensation ANION GAP ďź Another laboratory procedure ďź To maintain electrical neutrality: o PLASMA CATIONS must be EQUAL to PLASMA ANIONS ďź Normally, when there is acid-base disorders, what is usually obtained is the level of: o Na o Cl o HCO3 ďź To get the plasma anion gap, this is cations – anions o Na – HCO3 – Cl levels o Done by obtaining a blood sample: o Example is: 144 – 24 – 108 = 10 mEq/L We only request this depending on the condition of the patient There is a metabolic acidosis and the anion gap increases and you are thinking there is a problem in Calcium so you request for ionized calcium When you find out that you ionized calcium decreases, then you should be able to correct calcium, otherwise tetany will happen. Or you want to find out K ď hypokalemia can cause arrhythmia, then you should be able to correct the K levels. In correcting acid-base disorder, always keep in mind to address the primary problem first. If you are having diabetic ketoacidosis, you have to correct sugar level first. During alkalosis: ďź NH4Cl, lysine monohydrochloride are given During acidosis: ďź NaHCO3, Na-lactate, Na-gluconate are given We rarely administer NH4Cl and NaHCO3 simply because these two substances have narrow therapeutic details. The Great Escoto 17 of 17 Far Eastern University Nicanor Reyes Medical Foundation Institute of Medicine 1D – Batch 2020 Physiology A – Blood Physiology (Part 3) Dr. Endymion Ervin M. Tan LEUKOCYTES / WBCs è Formed in the bone marrow (majority) and some are in lymph tissues (spleen, lymph nodes, adenoids, tonsils, etc.) è 6 types; 2 branches GRANULOCYTES AGRANULOCYTES Basophils Monocytes Eosinophils Lymphocytes Neutrophils *ALL THE GRANULOCYTES and SOME LYMPHOCYTES are manufactured in the BONE MARROW *MAJORITY OF LYMPHOCYTES are manufactured in the LYMPH TISSUES *according din to kay Guyton* ARRANGEMENT OF WBC ACCORDING TO NUMBER (descending) 1. Neutrophils –marker for acute infection 2. Lymphocytes – marker for chronic infection 3. Monocytes – marker for chronic infection 4. Eosinophils 5. Basophils Morphogenesis of WBCs 1. All the blood cells came from the Pluripotent Hematopoietic Stem Cell 2. Differentiate to MYELOID & LYMPHOID PROGENITOR CELLS 3. Then it will be destined to become the granulocytes and lymphocytes, respectively. GENERAL CHARACTERISTICS OF WBCs • LIFE SPAN o GRANULOCYTES: 4-8 hrs in blood and 4-5 days in tissues o MONOCYTES: 10-20 hrs in the blood and MONTHS in tissues *MONOCYTES can RESIDE in the tissues, grow bigger and BECOME MACROPHAGES, even if there is no infection, they will thrive in the tissues. • MATURITY o NEUTROPHILS: mature cells so once they are in the blood, they can perform their functions as a PHAGOCYTOTIC AGENTS [this is the reason why they are the markers for acute infection] o MONOCYTES: not mature enough to perform their functions if they are in the bloodstream, IT SHOULD TAKE SOME TIME TO GROW AND BECOME MACROPHAGES • DIAPEDESIS – squeezing action of the neutrophils, monocytes, Escoto,KC//Gloriani,KP 1 of 12 macrophage ACROSS THE INTACT BLOOD VESSEL WALL going to the CHEMOTACTIC SOURCE • CHEMOTAXIS o Migration of the macrophages, neutrophils, etc. to the chemotactic source/substance. Chemotactic substances can be viral/bacterial toxins, products of inflamed tissues like prostaglandin, histamine, etc., products of the Complement (proteins that help the immune system to fight or destroy invading organisms) complex, products of plasma clotting NEUTROPHILS Mature Phagocytic agent Secretes PROTEOLYTIC ENZYME Secretes BACTERICIDAL AGENTS Less potent; can digest only 3-8 bacteria ONLY BACTERIA LESS DURABLE; After phagocytosis, it will die MACROPHAGES Immature Phagocytic agent Secretes PROTEOLYTIC ENZYME Secretes LIPASES Secretes BACTERICIDAL AGENTS More potent; can digest up to 100 bacteria Bacteria, RBC, Virus, Fungi, Parasites (ex. Malaria, Ascaris, etc.) MORE DURABLE; can stay in the tissue to perform another phagocytosis Normal Cells o has smooth surface o has a PROTEIN COAT to prevent them from being phagocytose o NO ANTIBODIES; it is not an antigen Abnormal cells/BACTERIA/FOREIGN CELLS/INVADING ORGANISMS o rougher surface o no PROTEIN COAT o Antibodies are the COATING OPSONIZATION à abnormal cells/invading cells/ foreign cells are COATED WITH ANTIBODIES to become more palatable and be phagocytose. **sabi nga ni Dr. Tan, pinapasarap J** NEUTROPHIL o Presence of 3 to 5 lobes of nuclei o Very pinkish PHAGOCYTOSIS o cell eating How do phagocytosis work? 1. The neutrophil will form a PSEUDOPODIA, an arm that will embrace the bacteria 2. All the bacteria will be embraced inside the neutrophil and will be contained in the PHAGOSOME, or the DIGESTIVE VESICLE 3. Neutrophil has a lysosome, the digestive system of the cell, which will bind to the phagosome 4. The lysosome will secrete an enzyme, lysozyme, that will digest/destroy the bacteria inside 5. Debris that is not capable to be digested will be left, and nutrients left will be absorbed and will be used as energy Escoto,KC//Gloriani,KP 2 of 12 **LYSOZYME is an example of PROTEOLYTIC ENZYME** PROTEOLYTIC ENZYME à destroys the protein of the bacteria Lipases à destroys the fatty cell wall of bacteria or invasive organisms *some bacteria causes prolonged chronic infection like tuberculosis* Peroxisomes o A bactericidal agent o Secretes free oxygen radicals from hydrogen peroxide that directly destroys the bacteria MONOCYTE MACROPHAGE CELL SYSTEM o Also known as Reticulum Endothelial System (RES) o A working immune system that protects our body form bact, vi. etc Histiocytes o Also called as Langerhans cell o Macrophages in the skin Alveolar Macrophages o Found in the lungs (ex. Destroys the TB bacilli) Gut Associated Lymphoid Tissue (GALT) o Destroys the bacteria that reached the GIT o If the bacteria escape the gut, it will go to the liver Portal vein – main blood supply to the liver (2/3) Hepatic artery – 1/3 of the blood supply to the liver Kupffer cells – macrophages of the liver *if the Kupffer cells FAILED to perform its functions, all the bacteria will go to the spleen through the splenic artery going to the capillaries Venous sinuses – lined with macrophages and found in the capillaries that destroys the bacteria so the blood going out through the splenic vein is clean and filtered Lymph Nodes o Where the bacteria flowing in the lymph vessels will pass through o It has SINUSES that contains macrophages that will destroy the flowing bacteria o Clean filtered blood is the product Escoto,KC//Gloriani,KP 3 of 12 Cardinal Signs of Infection 1. Vasodilation Ø More blood flow = increased filtration rate; increased capillary hydrostatic pressure so the plasma will be pushed out of the blood vessel (manifests edema, swelling etc. at the site of inflammation) 2. Walling-off effect Ø The fibrinogen will clot the plasma, so the inflamed area is tender, hard and painful. Ø This will serve as the protective mechanism to prevent the spread of bacteria in the infected part Tissue Macrophages – 1st line of defense Neutrophil Invasion – 2nd line of defense *will cause Neutrophilia – increase number of neutrophils *normal count: 60* How Diapedesis and Chemotaxis work? 1. Neutrophils are rolling/flowing in the blood vessel 2. The chemotactic source attracts the neutrophils 3. There will be an increase in ICAM-(intracellular adhesion molecule- 1) and will attach to the neutrophil 4. SELECTINS would also increase and binds to the neutrophils [it has two attachments] 5. The neutrophil would go to the Blood Vessels (MARGINATION/PIGMENTING) 6. The BVs will be looser; there will be a small gap 7. The neutrophil will do the Diapedesis in the gap that is made by the Blood Vessel 8. The neutrophil will undergo Migration/Chemotaxis to the chemotactic source 2nd Macrophage invasion – 3rd line of defense Macrophages will serve as the FEEDBACK CONTROL releasing growth factors that will stimulate the bone marrow Stimulation of Bone Marrow – 4th line of defense; the bone marrow will secrete more cells PUS – viscous fluid, build up of WBCs and proteinaceous substances. It will just be reabsorb by the body after the infection Escoto,KC//Gloriani,KP 4 of 12 EOSINOPHILS o 2% only o They are weak phagocytes because it only destroys PARASITES o Secretes HYDROLYTIC ENZYMES, REACTIVE Oxygen SPECIES, MAJOR BASIC PROTEINS (MOST IMPORTANT because it directly destroys the parasites) o Plays in the important role of allergic reaction (see basophils discussion) Some example are malaria, ascaris, etc. Leukopenia o Decrease in the amount of WBCs o Radiation injuries causes DROP in the AMOUNT OF WBC *WBCs are more susceptible to radiation reaction so the bone marrow production is affected* *PAG NAKITA MO ATOMIUM AUTOMATIC LEUKOPENIA YUN J* o Drugs that induces Leukopenia: o Chloramphenicol antibiotic o Thiouracil – use to treat hyperthyrodism o Barbiturates Leukemia BASOPHILS o Large and heavily granulated cells o Function: same as the mast cell o Releases HEPARIN (anticoagulant), histamine, bradykinin, serotonin that participates in allergic reaction o IgE is involved in allergic reaction o Binding with IgE will tend to rupture the basophils or mast cells and secretes the EOSINOPHIL CHEMOTACTIC FACTORS EOSINOPHIL CHEMOTACTIC FACTORS – attracts the eosinophils where there is allergic reactions o Increased number/abnormal production of WBCs but they are immature cells/ blast cells o Myeogenous and Lymphocytic o Patients can undergo severe infection due to SURGE OF ABNORMAL CELLS which are useless. *abnormal cells can lodge in the bones also in the vascular organs so some patients have the nose bleedings because it invades the blood vessel wall causing erotion. o SEQUELAE: end point of leukemia o There will be negative nitrogen balance because the nutrients will Escoto,KC//Gloriani,KP 5 of 12 be absorbed by the abnormal cells resulting to being cachectic Thymus gland à main organ where tcell is being pre-processed; FATE: NONE, involution, atresia If the stem cell is destined to be a Tlymphocyte, the t-cell 1 will go to Thymus for pre-processing assigning it to different functions. T cells exhibits EXTREME DIVERSITY to fight different antigens T-cell IMMUNITY o Has two branches o Innate Immunity – we have it when we were born o Acquired/adaptive immunity – something that is needed to be exposed to before being protected Innate Immunity o These are: o Digestive enzymes o Intact skin o Tissue macrophages Acquired Immunity o Vaccinations o Two types o T-cell : Cell mediated immunity o B-cell : Humoral immunity B- cell Cell mediated immunity Humoral immunity Exhibits extreme diversity More diverse than t-cells Responsible for transplant rejection Exhibits lymphocyte cloning Exhibits lymphocyte cloning Antigens – foreign substances that would react to the body; PROTEINACEOUS LONG CHAIN CARBOHYDRATES substances that are very potent to reaction when exposed to the body Haptens – Incompetent to cause a disease; small molecular substances Bursa – organ responsible for preprocessing of B-lymphocytes Lymphocytes – responsible for the immunity, the B-cell, T-cell Mnemonics: Take Care Be Happy Escoto,KC//Gloriani,KP 6 of 12 Early fetal life to mid fetal life Late fetal life until birth, now • • T-cell • • • • Stem cell is destined to be a T-cell, goes out of the bone marrow and go to the thymus The thymus will be producing a lot of T-cells with great variety The thymus will release the T-lymphocyte and will reside in the lymphoid tissue With the presence of antigen, it will be activated to become T-lymphocytes *WHY IS IT CELL MEDIATED?** - it started as a whole cell and ended as a whole cell B-cell • • Stem cell is destined to be a B-cell B-cell will be preprocessed in the fetal LIVER and bone marrow • • • LIVER is the primary organ for the pre processing of B-cell Bone marrow More versatile than Tcell, around 1000 different kind. Starts as B-cell ends antibodies B-lymphocytes resides at the lymphoid tissue and reacts with an antigen Will grow into a PLASMA CELL It will become the ANTIBODY For patients who will undergo transplant, THE T-cell should be suppressed because it will destroys the donor’s organ [STRONG IMMUNOSUPPRESION] Lymphocyte Clone - formed when exposed to a virus/disease to protect the body or a memory cell [can be a lifelong protection] Gene Segments – the bone marrow and thymus can manufacture a lot of a different patterns and different combinations because of this; Scientists found out that in the body we have different gene segments so the body will have different patterns to react to an antigen Macrophages has IL-1(interleukin-1) which is important for the stimulation of Escoto,KC//Gloriani,KP 7 of 12 the bone marrow to produce more WBCs B cells (B lymphocytes à lymphoblasts à plasmablasts à plasma cells à Antibodies • Memory Cells o When exposed to the same disease, antigen, bacteria, virus, you have an immunity to the disease o Example: Hepa-B vaccine “ANTIGEN IS INJECTED TO STIMULATE THE PRODCUTION OF LYMPHOCYTE CLONE” st 1. 1 dose: - Latent period: VERY LONG - Antibody production: NOT ROBUST - Duration: VERY SHORT 2. 2nd dose after 1 month - Latent period: SHORTER - Antibody production: ROBUST - Duration: LONG; or LIFETIME That is why in some diseases, vaccination are given at a schedule of 0,1 and 6 months. • Antibodies (immunoglobulin) o IgG, IgM, IgA, IgD,IgE o The response is not strong so the COMPLEMENT is needed Mechanism of Action 1. Can kill and inactivate the foreign body by AGGLUTINATION; the binding of antibody & antigen can clump the antigen, rendering it as non-infectious 2. PRECIPITATION – it can bind into the antigen making it a very big molecule, very heavy so it will just drop and precipitates, rendering it as non-infectious 3. NEUTRALIZATION – example: patient with cobra venom, giving him anti cobra venom so it will be neutralized by the antivenin, rendering the venom noninfectious 4. LYSIS – the antibody can destroy the antigen. IgA, seminal fluids because it can kill organisms IgG IgM Most numbered Biggest Immunoglobulin Small, crosses the placenta Does not cross the placenta Secondary antigenic stimulus / previous exposure Primary antigenic stimulus / new exposure Previous exposure to Zika Virus, the blood should be Zike virus IgG positive First time exposure to dengue, the blood should be Dengue IgM positive IgG: Gamit na gamit Escoto,KC//Gloriani,KP 8 of 12 Example: Dengue IgG is positive, Dengue IgM is negative: OLD INFECTION Zika IgM positive, Zika IgG negative: NEW INFECTION Dengue IgG positive, Dengue IgM positive: ACUTE INFECTION ON TOP OF AN OLD INFECTION Antibodies Functions IgA Secretory Ig secreted by the exocrine gland (colostrum, saliva, vaginal fluid, semen, etc.) IgD Least in amount and the function is unknown IgE CONSTANT PORTION à tells the PROPERTY and DIFFUSING CAPABILITY of the antibody à MOST IMPORTANT FUNCTION: binding in to the COMPLEMENTS COMPLEMENTS Ø Ø Ø Ø Ø Allergic reaction High affinity to basophils and mast cells Ø Proteins that serve in the antigen-antibody response Made up of 20 different proteins in the blood INACTIVE PROTEINS Starts from C1, forming cascade, recruiting more and more complements from a small beginning to become a massive complex for a robust response Complements are numbered base on the sequence on how they are discovered; but the cascades are number according to the number of complement that would be recruited first 2 pathways Classical Pathway o Stimulated by the antigen antibody complex o Starts at C1 Properdin Pathway o Alternative pathway o Simulated by MICROBIAL VARIABLE PORTION à Binds to DIFFERENT antigens SURFACES/MICROORGANISMS o Starts at C3 Escoto,KC//Gloriani,KP 9 of 12 • Lysis/Membrane Attack Complex(MAC) *MOST IMPORTANT* : C5b6789 ü This is the one that destroys the bacteria, lacking of these will result to inability to kill the bacteria and non-resolving infection According to Recruitment According to Invention C1 – 1ST C1 – 1st C4 C2 C2 C3 C3 C4 C5 C5 C6 C6 C7 C7 C8 C8 C9 – last C9 – last Functions of each complexes • Opsonization & Phagocytosis : C3b • Chemotaxis: C5a (anaphylatoxin) • Activation of Basophils & Mast Cells : C3a4a5a T- cells are like girls: very delicate and choosy. It needs ANTIGEN PRESENTING CELLS o Macrophages o B-lymphocytes o Dendritic cells Different type of T-cells 1. T helper cells Ø Secretes a lot of LYMPHOKINES, GROWTH FACTORS that will stimulate the production of B-cells and T- cells Ø CD4 cells 2. T suppressor 3. Cytotoxic cells Ø CD8 cells Ø Natural killer cells Ø Has PERFORINS, hole punching proteins Ø It will punch holes around the infected cells, and Escoto,KC//Gloriani,KP 10 of 12 migrate away to kill other cells. Once holes are around the cell, fluid will go around the cell, causing it to swell and burst (lysis) Ø It can also destroy the normal cell but the body does not allow it so the thymus produces abnormal cells (10%) so the CD8 cells will destroy it rather than the normal cells Ø Additional Info: CD means Cluster of Differentation J T-cells need a receptor, (Major Histocompatibility Complex) MHC PROTEIN 2 types: 1. MHC1 à CD8 2. MHC2 à CD4 *how to remember by Dr.Tan à 4x2 =8 so 4:2 and 8:1 J CD4 cells will release lymphokines, colony stimulating factors that help in the proliferation and differentiation of Bcells, cytotoxic cells, suppressor cells. In HIV, CD4 cells are the one affected HIV will destroy CD4 cells causing the depletion of the entire arm of the immune system, the patient becomes very immunocompromised *We have IMMUNE TOLERANCE (the body can tolerate our immune system) so we the body won’t destroy its own cells. However, losing it will cause autoimmune diseases like o Rheumatic fevers – heart valves and kidneys are affected o Glomerulonephritis – streptochocal infection forming antigen-antibody response that destroys the kidney o Myesthenia gravis – affects the post-synaptic membranes especially the receptors o Systemic Lupus Erythematosus – Rheumatologic disease that can affect the bones, skin. Manifestation: butterfly/malar rashes IMMUNIZATION 2 types 1. Active Immunity a. Vaccine will ask your body to produce protection b. Live attenuated (weakened in force/effect) virus is given but it will not cause disease and causes the body to form protection against it c. A dead antigen can also be administered so the body will form immunization d. LONGER DURATION OF PROTECTION – may be lifetime 2. Passive Immunity a. Immunoglobulin – preformed protection Escoto,KC//Gloriani,KP 11 of 12 b. The body will not produced its own protection because of the administration of immunoglobulin c. For IMMEDIATE protection ALLERGY AND HYPERSENSITIVITY A. Atopic allergies o Drugs: Antihistamines o IgE mediated B. Anaphylaxis o Allergen is inside the bloodstream o Triggered when you’ve eaten something o Causes bronchoconstriction etc. o Production of slow reacting substances of anaphylaxis o Drugs: Ephinephrine C. Urticaria o Due to histamine o Hives (pantal in tagalog) D. Hay Fever o Pollen/dust allergies E. Asthma o Bronchiocronstriction o Drugs: simulate sympathetic like salbutamol(Beta2 agonist) and irpatropium (parasympatholitic drug) Escoto,KC//Gloriani,KP 12 of 12 BLOOD PHYSIOLOGY By Dr. Olivar Functions of the BLOOD • Homeostasis (regulates internal environment) • Respiratory (transport of oxygen) • Nutritive (carrier of nutrients) • Excretory (carrier of waste products) • Endocrinology (transporter of secretions) • Helps maintain acid-­âbase balance • Maintenance of water and electrolyte balance and regulation of total osmotic pressure • Immunity to diseases (WBC) • Regulation of body temperature Normal Blood Volume Commonly: Males would have 5 liters Females would have 4.5 liters *Regardless of this, blood should be 60% Plasma, 40% Formed elements. *When centrifuged: -­â-­âupper portion is plasma -­â-­âwhite substance a.k.a. “buffy coat” contains WBC and Platelets -­â-­âRed portion is the red blood cells Composition of Blood Plasma— water -­â 91 – 92% Plasma protein – albumin, globulin, fibrinogen, prothrombin Functions of Plasma Proteins • Maintenance of water balance between the intravascular compartment and extra vascular spaces (proteins serve as solutes that attract plasma inside the blood vessel) Ex. Decreased Plasma Protein con.—higher plasma con.ď plasma exits into the interstitial space HIGHER TO -­â-­â-­â-­â-­â-­âď LOWER CONCENTRATION Clinical Correlation: Patients with liver diseases manifest with “Edema” because the liver is where proteins are synthesized. With a liver problem, plasma protein may be depleted. In such situation, the plasma will be pushed toward the interstitial space. • • • • • • Imparts viscosity to the blood Source of antibodies Necessary for coagulation Maintains acid-­âbase balance Determines specific gravity of plasma Formation of enzymes; transport of hormones and enzymes Other contents-­â-­â-­â 1. Water 2. Plasma proteins 3. Blood sugar – glucose 4. Lipids – cholesterol, phospholipids, neutral fats 5. Salts – Na, K, Cl, bicarbonates, phosphates 6. Gases – O2, CO2, Nitrogen 7. Special plasma substances – hormones, enzymes, antibodies RBC, WBC, PLATELETS-­â all come from a single cell in the bone marrow called the pluripotent hematopoietic stem cells RED BLOOD CELLS • Not spherical; biconcave discs; 2.5 um thick, 7.5 – 8 um in diameter • Very deformable • Carries hemoglobin in the circulation –1gm of Hgb ď 1.34 ml of O2 • Non-­ânucleated in the circulating blood Anemia-­â any value lower than normal limit of Hgb and RBC Polycytemia-­â any value higher than normal limit of Hgb and RBC RBC count: Hemoglobin: Men: 5-­â6 x 10 (12)/L Men: 14 – 17 g/dL Women: 4-­â5 x 10(12)/L Women: 12 – 15 g/dL Infants: 6-­â5 x 10(12)/L Hematocrit: Men: 0.40 – 0.50 Women: 0.38 – 0.48 RED CELL Production Stage of Life 8 weeks of embryonic life or first 2 months Middle trimester of pregnancy rd 3 trimester of pregnancy 20 years and above Organ Responsible for RED CELL production Yolk sac Liver, spleen, lymph nodes The bone marrow then takes over Bone marrow of skull, vertebrae, ribs, sternum Erythropoiesis-­â is the process of red cell production Proerythroblast Early Erythroblast Late Erythroblast Normoblast What happens during intermediate phase? • Hemoglobin is incorporated into the cell. • The nucleus condenses so that it is released from the cell even before the cell is extruded from the bone marrow. • First cell released is called Reticulocyte. Reticulocyte-­â still colors blue because of cytoplasmic materials -­âafter 2 days, the cytoplasmic materials are gone and mature non-­ânucleated erythrocytes are produced *Vit.B12 and Folic Acid are essential for RBC maturation. *Without VitB12 and Folic Acid, • DNA synthesis is impaired • With a problem in DNA synthesis, erythropoiesis proceeds slowly • Intermediate cells are released into the circulation as Macrocytes, which are flimsy and easily rupture. • Structural abnormalities Megaloblastic Anemia-­â is described as macrocytic and hyperchromatic Pernicious Anemia-­â is a condition characterized by the absence of parietal glands in the stomach which are needed for the secretion of Intrinsic Factors (IF). -­âIntrinsic factors (IF) aid in the absorption of Vit B12 Absence of IF ď malabsorption of B12 ď B12 deficiency ď Pernicious Anemia ď Megaloblastic Anemia Sprue-­â also causes megaloblastic anemia due to decreased intestinal absorption of Folic acid and Vit B12 Control of RBC Production 1. Stimulated by hypoxia. 2. Inhibited by rise in circulating RBC levels 3. Controlled by circulating hormone called erythropoietin. Example—Living in high altitudes where oxygen is not as abundant as in low lands-­â-­â-­âmore RBC is produced. -­â-­âPatients with tuberculosis have normal blood levels and oxygen levels in blood, but suffer from impaired oxygen absorption in the lungs. Thus, the body is triggered to produce more blood. Erythropoietin-­â is a glycoprotein hormone that controls RBC production by stimulating bone marrow -­âsynthesized by both kidneys (90%) and the liver (10%) -­âincreases production of PROERYTHROBLASTS Destruction of RBC Life span-­â-­â-­â 120 days Destruction-­â-­â-­â 1% of red cells is replaced daily Total red cell volume is replaced every 4 months Site-­â-­â-­â Spleen * The number of red cells in the circulation is determined by the balance between production and destruction. Hypertonic solution-­â causes shrinkage of RBC Hypotonic solution-­â causes swelling of cell and eventual rupturing Isotonic solution-­â no change; equilibrium; 0.9% NaCl; 5% dextrose Hemoglobin Formation I. 2 succinyl Coa + 2 glycine ď pyrrole molecule II. 4 pyrroles ď protoporphyrin IX III. Protoporphyrin IX + Fe ď Heme IV. Heme + globin ď Hemoglobin chain (a or B) V. 2 a chains + 2 B chains ď Hemoglobin *Each hemoglobin molecule has 4 Fe molecules. One Fe can hold one oxygen at a time. *The primary function of RBC is to transport hemoglobin, which in turn carries oxygen from the lungs to the tissues and the carbon dioxide back from the tissues to the lungs. *97% of oxygen is carried to the tissues in combination with hemoglobin. Only 3% is dissolved in cells. *CO2 may combine with hemoglobin for it to be transported back to the lungs for excretion. Sickle cell anemia • is an abnormality in the B-­âchain of Hemoglobin • upon exposure to O2, the Hgb forms elongated crystals • prone to hemolysis or easily ruptures IRON • 5 grams in the human body • majority is in the form of Hemoglobin (65%) • 15 – 30 percent ferritin (Storage form in the liver) • 4% myoglobin (hemoglobin in the muscle) • 1% other heme compounds • 0.1 with transferrin • primary source is red meat Absorption of IRON <Duodenum> 1. Liver produces apotransferrinď secreted into the BILEď apotransferrin + Feď Transferrin (plasma) ď blood ď transferrin donates Fe to RBCď Hemoglobin is produced 2. Transferrin I Iď excess Feď Tissues ď Ferritin Destruction of Hgb • RBC ruptures after 120 days • Hemoglobin is released and broken down to bilirubin • Fe is never wasted. It is liberated and brought back to the iron stores. Women: are prone to IRON deficiency anemia due to menstruation. Should take supplements at least once a day. Anemias— are brought about by deficiency of Hgb • Too rapid loss / too slow production • Blood loss; Fe deficiency Clinical Correlation: When a patient presents with severe palor (anemia), the physician will usually request for a peripheral blood smear. Result: If the RBCs are microcytic hypochromic, the cause of anemia is IRON DEFICIENCY. If the RBCs are microcytic hyperchromic, the cause of anemia is Vit B12 / FOLIC ACID DEFICIENCY. Aplastic Anemia-­â is a bone marrow disorder, where all blood cells are not produced Hereditary Spherocytosis-­â is a situation where the RBCs are spherical instead of bi-­âconcave *Plasma causes oncotic pressure, while RBC renders viscosity to blood. Anemia’s effect to the heart is INCREASED WORK LOAD. • Anemia causes decrease in viscosity of blood; decrease in resistance to blood flow. • Thus, more blood goes to the tissues and flows back to the heart. • Anemia causes hypoxia. Blood vessels will dilate. Thus, more blood returns to the heart. *Will cause increased heart rate. *Younger individuals can usually tolerate anemia. *Older individuals (60-­â70) should not be left without treatment because anemia may cause cardiac arrest to individuals with weaker hearts. POLYCYTEMIA nd 2 Degree Polycytemia-­â ex. Living in high altitudes, smoking, having pulmonary diseases Polycytemia VERA-­â a genetic aberration; increase in RBC does not inhibit further production of erythropoietin -­âblood viscosity is increased; resistance to blood flow is increased; blood is prone to clotting episodes -­âtreated by performing phlebotomy BLOOD TYPES TYPE A TYPE B TYPE AB TYPE O A agglutinogens B agglutinogens A and B agglutinogens No agglutinogens B agglutinin A agglutinin No agglutinin A and B agglutinin Agglutination is the end point of transfusion reaction Reaction: <Agglutination> <Hemolysis> Antibodyď Antigenď RBC will clumpď WBCs attack RBC Immediate Transfusion Reaction— IgM ď immediate hemolysis Delayed Transfusion Reaction— a result of secondary immune response BLOOD COMPATIBILITY Donor Cell-­â refers to the antigen Patient’s serum-­â refers to antibody Donor’s Cell TYPE A Patient’s Serum TYPE B Result Antigen – A Antigen – B (Orange) Minor reaction= (+) Antibody – B *Blood types are incompatible. Donor’s Cell TYPE O Antibody – A (Red) Major reaction= (+) Patient’s Serum TYPE B Result Antigen – NONE Antigen – B (Orange) Minor reaction= (+) Antibody – AB Antibody – A (Red) Major reaction= (-­â) *May proceed with transfusion. Patient may suffer slight itchiness as reaction to small amounts of antibodies from Donor cell, which will easily be diluted in Patient’s blood plasma. *Type O is a universal Donor. Donor’s Cell TYPE A Patient’s Serum TYPE AB Result Antigen – A Antigen – AB (Orange) Minor reaction= (+) Antibody – B Antibody – NONE (Red) Major reaction= (-­â) *May proceed with transfusion. Patient may suffer slight itchiness as reaction to small amounts of antibodies from Donor cell, which will easily be diluted in Patient’s serum. *Type AB is universal recipient. Error in blood transfusion may result in: • Agglutination • Destruction of RBC membrane by phagocytosis or antibodies ď Hemolysis =Jaundice • Severe hemolysis/decreased amt. of RBCď circulatory shockď redistribution of blood to more important organs, ex. Brainď Kidneys are bypassedď Renal vasoconstrictionď hemolyzed cells flow to the kidneys and block the renal tubulesď RENAL SHUTDOWN RH BLOOD GROUP-­âantigens are C, D, E, c, d, e • Rh – (+)-­â-­â-­â-­âď the sign is shown on the blood type. Example: A+ means Blood type A and RH (+) • The most important factor is the result of the “D” antigen. • Rh antigens are not immediately developed after blood transfusion from RH (+) to RH (-­â). It takes 2-­â4 months. After developing antigen, subsequent transfusions will be fatal. • Rh (-­â) to Rh (+) transfusions do not result in undesirable reaction. Erythroblastosis Fetalis (HDN) st 1 CASE Mother is Rh (-­â) and Father is Rh (+) Baby Rh (+) • Baby’s blood mixes with mother’s blood • Mother will develop anti-­âRh IgG • Mother’s anti-­âIgG will attack the fetal RBC • Baby suffers from fetal anemia (Baby’s heart may fail) • Blood backflows; increases capillary hydrostatic pressureď hydrops, ascites, pleural effusion, and scalp edema. • Spleen and liver are enlarged • There will be blasts in the peripheral smear because immature cells are secreted (erythroblastosis fetalis) • Increased hemolysis of blood resulting in high bilirubin levels • Bilirubin accumulates in the brain (kernicterus) • Commonly the baby dies (prevention is better than cure) Treatment to Hydrops: • Exchange transfusion o Rh (+) blood is removed during birth also to remove the antibodies, then replaced with Rh (-­â) blood to stop interaction of antibodies with (+) o Then the baby is allowed to produce its own Rh (+) blood • Rho-­âgam (Rh immunoglobulin) o Rho-­âgam will coat the fetal RBC so that the maternal blood will not identify it and will not produce antibodies th th o Rho-­âgam is administered on the 28 week or 7 month (during which time the mother’s blood mixes with the baby’s) *First baby is not affected because the sensitization will take several months. st *Rho-­âgam should be given on the 1 pregnancy to prevent mother’s sensitization. *Only IgG can penetrate the placenta because of its small size. nd 2 CASE Mother is Rh (+) and Father is Rh (-­â) Baby Rh (-­â) • The baby and the mother are unaffected because no reaction will occur. • The baby cannot produce antibodies during this stage. Prepared by: M.A. Pamular BLOOD PHYSIOLOGY PART 1: RBC’s and Blood groups Lectured by: Dr. Olivar Functions of the blood: 1. Keeps the internal environment of the body constant (homeostasis) 2. Transports 02 from the lungs to the tissues and CO2 from the tissues to the lungs (respiratory) 3. Carries nutritive materials form the intestines to all parts of the body (nutritive) 4. Carries waste products of tissue metabolism to the kidneys (excretory) 5. Transports internal secretions from glands to the tissues on which the effects are exerted (endocrinology) 6. Helps maintain acid-base balance 7. Maintenance of water and electrolyte balance and in the regulation of total osmotic pressure 8. Immunity to diseases (WBCs) 9. Regulation of body temperature I. Blood volume A. Normal Blood volume ď A normal 7 kg male will usually have approx. 5 L of blood. ď Women, because of their short stature, will usually have a lower volume of blood = 4.5 L ď Regardless of the volume, the blood will always be divided into two major parts: 1. Plasma ď 60% = 3000 ml 2. Formed elements ď 40% = 2000 ml B. Composition of blood We can separate the components of the blood by CENTRIFUGATION. ď The RBCs will be the most dense so it will settle at the bottom of the haematocrit. ď Middle: platelets and WBCs (have intermediate densities) = Buffy coat ď Upper portion: Plasma C. Regulation of blood volume When the heart contracts, it creates a pressure inside the blood vessel = HYDROSTATIC PRESSURE (HP) ď HP tends to push the plasma into the interstitial space but normally it does not happen because of an opposing force that keeps the plasma inside the blood vessel = ONCOTIC PRESSURE ď ď Important factors in the regulation of formed elements: o Bone marrow production o Destruction/Wear and tear II. Composition of blood A. Formed elements ď Components: RBC, WBC, Platelet B. Plasma ď Predominantly WATER ď Plasma protein: albumin, globulin, coagulation factors (fibrinogen, prothrombin), antibodies ď blood sugar: glucose ď lipids: cholesterol, phospholipids, neutral fats ď salts: Na, K, Cl, bicarbonates, phosphates ď gases: O2, CO2, nitrogen ď special plasma substances: hormones, enzymes, antibodies ď Functions of plasma: 1. Maintain normal balance between the intravascular compartment and extravascular space (oncotic pressure) ď 2. 3. 4. 5. 6. 7. 8. Oncotic pressure is comparable to Osmosis (movement of solvent form area of lesser solute concentration to an area of higher solute concentration; going where the solutes are) ď Inside the blood vessel :Plasma CHONs (solute) ď dec. plasma CHONs ď dec oncotic pressure ď hydrostatic pressure predominates ď plasma will go into the interstitial space ď EDEMA ď Liver (produces plasma CHONs): Liver disease ď dec plasma CHONs ď edema ď§ Ex: Cirrhosis of the liver ď liver can no longer produce plasma CHONs ď Kidney (allows CHONs to go to the urine) ď dec plasma CHONs ď edema Viscosity of the blood is primarily determined by the RBCs but somehow, plasma CHONs also contribute to the viscosity of the blood Source of antibodies Necessary for coagulation Maintenance of acid-base balance Determines the specific gravity of the plasma (1.028) Formation of enzymes Transport of hormones and enzymes 1|CKRP RED BLOOD CELL ď ď ď ď Biconcave discs, 2.5 um thick, 7.5 – 8 um in diameter; 1 um at the center Very deformable: due to excess cell membrane Non-nucleated in the circulating blood Primary function: carry haemoglobin ď carries O2 in the circulation (1 gm of Hgb: 1.34 ml of O2) ď During adulthood, in the rare case that the bone marrow fails to produce RBCs, liver and spleen can produce RBCs again = EXTRAMEDULLARY HEMATOPOIESIS Ex: Aplastic anemia (bone marrow failure) ď Liver and spleen must produce RBCs in exaggerated way ď Enlargement of liver and spleen ď HEPATOSPLENOMEGALY D. Erythropoiesis: process of RBC production A. Hematopoiesis: process by which formed elements are produced o All blood cells originate in the BONE MARROW o Multipotent/Pluripotent cells ď can give rise to different types of cells o Stem cells are not only seen in the bone marrow. There are also stem cells present in the umbilical cord (can be harvested during childbirth and stored in the blood bank for future purposes; could be beneficial if the child would develop blood disease) B. Normal values: o RBC count 1. men: 5-6 x 1012/ L 2. women: 4-5 x 1012/ L 3. infants: 6.5 x 1012/ L < NV = ANEMIA > NV = POLYCYTHEMIA o Hemoglobin 1. men: 14 – 17 g/dL 2. women: 12 – 15 g/dL o Hematocrit 1. men: 0.40 – 0.50 2. women: 0.38 – 0.48 C. RBC production: begins IN UTERO a. Yolk sac of the embryo st ďˇ Produce RBCs during the 1 few weeks of embryonic life ďˇ nourish the embryo st ďˇ 1 site of hematopoiesis b. Liver, spleen, lymph nodes ďˇ middle trimester of pregnancy c. Bone marrow ďˇ 3rd trimester of pregnancy – 5 y/o d. Bone marrow of axial skeleton (skull, vertebral column, ribs, sternum, pelvic bone) ďˇ 20 y/o and above ď Why are the long bones no longer capable of producing RBCs during adulthood? It is because the long bones become infiltrated with yellow marrow. ď Multipotential/Pluripotential Hemopoietic stem cell: HEMOCYTOBLAST 1. All the cells in the circulating blood are derived from this cell. ď Committed stem cell: PROERYTHROBLAST 1. Intermediate-stage cell 2. They have already become committed to a particular line of cells; produce specific type of blood cells 3. Formed from COLONY-FORMING UNIT ERYTHROCYTE (CFU-E) ď During the production of the mature RBC, the haemoglobin is incorporated into the RBC and the nucleus condenses until it is finally extruded from the cell st ď Reticulocyte: 1 cell released into the circulation Peripheral blood smear: feathery edge E. ď (remains blue because they still contain cytoplasmic and nuclear remnants) (after 2 days, they become reddish, non-nucleated RBCs) Hemoglobin The primary function of red blood cells is to transport hemoglobin, which in turn carries oxygen from the lungs to the tissues and the carbon dioxide back from the tissues to the lungs 2|CKRP ď ď Formation of Hgb: o 2 succinyl CoA + 2 glycine ď pyrrole molecule o 4 pyrroles ď protoporphyrin IX o Protoporphyrin IX + Fe ď Heme o Heme + globin ď Hemoglobin chain (alpha or beta) o 2 alpha chains + 2 beta chains ď Hemoglobin A 1. 1 chain = 1 Fe 2. Adult Hgb = 4 Fe 3. 1 Fe = bind to 1 O2 molecule 4. Sickle cell anemia Abnormal beta chain: valine is substituted to glutamic acid in each of two beta chains upon exposure to O2, the Hgb forms, elongated crystals ď spiked ends rupture the cell membrane hemolysis ď Fe in the body exist in the following forms: o RBC: Hemoglobin (majority) ď 65% o Muscle: Myoglobin ď 4% o Tissues in GIT (Reticuloendothelial system and liver parenchymal cells): Ferritin ď 15 to 30% o Participate in enzymatic reaction: Cytochrome enzymes ď ď Source of Fe: glandular organs, beef, pork, chicken, oyster Absorption of Fe from GIT: Transport of O2 in the blood is primarily due to the combination of Hgb to O2 o 97% of O2 – combine with Hgb o 3% of O2 – dissolved in plasma and cells o Attachment of Hgb to O2 is a REVERSIBLE combination Liver produces apotransferrin ď secreted to the bile ď duodenum (does not readily go to the blood): ď If Fe content is adequate, Fe will just be stored in the mucosal cells of duodenum as FERRITIN (storage form of Fe) ď§ Fe + Apoferritin ď Ferritin ď If Fe is already needed in the bone marrow for the production of RBCs (when the quantity of Fe in the plasma falls low), Fe in the form of TRANSFERRIN (transfer form of Fe) will be delivered to the bone marrow for erythropoiesis ď§ Fe + Apotransferrin ď Transferrin o o o ď In the lungs, when the O2 content is VERY HIGH, O2 readily ATTACHES to Hgb In the tissues, when the O2 content is VERY LOW, O2 is readily RELEASED by the Hgb Transport of CO2 in the blood is predominantly via bicarbonate. ď Iron Metabolism o RBC released in circulation ď 120 days ď RBCs will be destroyed in the liver and spleen (RETICULOENDOTHELIAL SYSTEM) by KUPFFER CELLS of the liver and MACROPHAGES of spleen and bone marrow ď Hgb is released ď Liver ď release Fe and porphyrin ď bilirubin and Fe is brought back to the bone marrow to be reused again in erythropoiesis o o ď Hence, we don’t need Fe that much because the Fe used in the erythropoietic period is just recycled and the mechanism by which our body eliminates Fe is very limited = It’s harmful to take Fe as a multivitamin everyday Fe as multivitamin taken every day ď Fe overload ď Destroy organs An adult individual, depending on the gender and habit, has 4-6 g. of Fe 3|CKRP o ď§ (-) intrinsic factor: For the Vit. B12 to be absorbed, the stomach does not only produce acid. The parietal cells of the stomach also release an intrinsic factor which facilitates absorption of Vit. B12. Therefore, if the intrinsic factor is not present, Vit B12 will not be absorbed ď§ Treatment: give Vit B12 through SHOT not through tablet; direct to the blood vessels Fe supplements are only recommended for females with menstrual problems (heavy menstrual bleeding) and pregnant women - Folic acid Deficiency: SPRUE ď§ decreased intestinal absorption of folic acid and B12 G. Control of RBC production o to ensure that there will be enough RBC that would carry O2 from the lungs to the tissues o too many RBC ď RBCs overcrowd the vessels ď impede blood flow ď ď Elimination of Iron: o Bile o Urine o Feces o Menstruation ď Tissue oxygenation o Primary stimulus for RBC control o Dec RBC = HYPOXIA ď§ Dec. blood flow and blood volume ď§ Inc. altitude and pulmonary diseases = In people living in high places, they are not anemic and they have adequate RBC but the amount of O2 is decreased in high altitude = In people with pulmonary diseases, O2 cannot traverse the pulmonary system ď O2 can’t go to the blood ď dec O2 in tissues o production of RBC is not dependent on the number of RBC ď§ RBC production can be stimulated when RBC number is low but it can also be stimulated even if the RBC number is normal as long as the tissues are hypoxic ď Erythropoietin F. Maturation of RBC Vitamin B12 (Cyanocobalamin) and Folic acid (Pteroylglutamic acid) - Essential for synthesis of DNA - Without them, erythropoiesis will proceed slowly; abnormal and diminished DNA ď failure of nuclear maturation and cell division - Blast cells are released into the circulation due to slow DNA synthesis = Macrocytes: rupture easily ď MEGALOBLASTIC ANEMIA “megalo” = big “blastic” = produce blast cells “anemia” = RBCs rupture easily - Vitamin B12 Deficiency: PERNICIOUS ANEMIA ď§ atrophic gastric mucosa: stomach is devoid of any cell and gland ď cannot produce intrinsic factor and normal gastric secretions 4|CKRP o o o 90% is produced by the kidney and the remainder is mainly produced by the liver Stimulate production of proerythroblast ď inc RBC ď Inc O2 Cause cells to pass more rapidly through the different erythroblastic stages than they normally do = speeding up production of new RBCs I. Anemias: deficiency of Hgb; too rapid loss or too slow production Blood loss – due to hemorrhage Iron deficiency anemia o In PBS, smaller in size and paler in color o MICROCYTIC HYPOCHROMIC RBCs ď§ Hypochromic = RBCs contain much less haemoglobin than normal ď Aplastic anemia – bone marrow failure; due to chemotherapy, toxic chemicals, autoimmune disorders ď§ Idiopathic aplastic anemia – aplastic anemia cases wherein the cause is unknown ď Megaloblastic anemia o Vit B12 and Folic acid deficiency o MACROCYTIC HYPERCHROMIC RBCs ď Hemolytic anemia o Hereditary spherocytosis ď ď ď¨ When your Hgb synthesis is already normal and O2 transport is already adequate, the kidney and liver will stop further production of erythropoietin ď to inhibit ď¨ RBCs are spherical in shape not biconcave ď¨ These cells cannot withstand compression forces because overcrowding of RBC they do not have the normal bag-like cell membrane structure of biconcave discs H. RBC destruction ď¨ The cell membrane does not have a functional Na-K pump ď 1% of red cells replaced daily total red cell volume replaced every 4 months ď Na+ are not pumped out of the cell ď H20 continuously ď Site of destruction: SPLEEN go inside of the cell ď Cell becomes spherical (swell) until it ď “The number of red cell in the circulation at any time is determined by the balance ruptures between production and destruction ” o o ď ď ď POLYCYTHEMIA = overproduction ANEMIA = underproduction/over-destruction Isotonic solution o 0.9% Nacl; 5% dextrose o No movement of water Hypertonic solution o Greater concentration of solute in the solution than in the RBC o crenation Hypotonic solution o Lower concentration of solute in the solution than in the RBC o Spherical ď rupture ď hemolysis Effects of anemia on the circulatory system: ď Dec viscosity ď Dec resistance to flow o Viscosity of the blood is due to RBCs o Dec RBC ď Dec viscosity ď greater blood flow ď greater volume of blood goes to the heart ď INCREASE CARDIAC OUTPUT ď INCREASE WORKLOAD (Anemia makes the heart work faster and harder) o In young people, it’s still okay to have anemia because the heart muscle is still strong o In old people, too much pumping of the heart ď heart failure o Since there’s a decreased amount of RBC, the heart needs to pump harder to supply adequate amount of O2 to the tissues ď Polycythemia o Primary o Secondary ď§ Normal number of RBC but since an individual is living in a high place, smoking, or has pulmonary diseases ď Tissue 5|CKRP hypoxia ď Inc RBC ď Inc viscosity ď sluggish flow of blood ď high probability of forming clot within blood vessels which blocks the blood flow ď§ Treatment: Therapeutic phlebotomy (every 2 or 3 months, removal/extraction of blood to decrease the amount of RBCs) o ď Effect of polycythemia in circulatory system ď§ Increase in blood viscosity ď DECREASE rate of venous return to the heart ď§ Increase in blood volume ď INCREASE rate of venous return to the heart ď§ Hence, the effect is NORMAL because the two factors normalize each other Polycythemia vera o Genetic aberration in the hemocytoblastic cells o Negative inhibition to the liver and kidneys to control production of erythropoietin does not occur so even if the number of RBCs was already increased, there is still sustained production of RBC o It affects not only the RBCs but also WBCs (total blood volume increases) unlike in secondary polycythemia wherein only the RBCs will increase. ď ď Agglutination process in transfusion reactions o Immediate: IgM ď complement system (release proteolytic enzymes that ruptures the cell membrane) ď HEMOLYSIS o Delayed: IgG +Ag ď AGGLUTINATION ď HEMOLYSIS Blood typing: ABO BLOOD GROUP ď Antigens o Aka Agglutinogens because they often cause blood cell agglutination o Ag: A, AB, B, O o Genetic determination of agglutinogens: ď ď Antibodies o Aka Agglutinins o Ab: IgG, IgM Cross-matching : to know the compatibility of the blood o Recipient: patient who will receive the blood o Donor: donates blood to the recipient o Cross match the CELL (antigen) present in the blood of the donor with the PLASMA (antibodies) present in the recipient = MAJOR REACTION o MINOR REACTION: Reaction between the PLASMA of the donor with the recipient’s CELL o In a packed RBC, plasma in the blood is removed leaving only the RBCs. 6|CKRP ď ď ď ď During haemorrhage, blood transfusion can save the patient’s life but if the blood is transfused in the wrong way can also lead to the death of the patient. Error in blood transfusion may result in: o agglutination o destruction of RBC membrane by antibodies = hemolysis o renal shutdown Acute renal failure occurs whenever there is error in blood transfusion. Causes of Renal shutdown: o hemolyzing blood releases toxic substances that cause severe renal arteriolar vasoconstriction o circulatory shock ď arterial blood pressure falls very low ď decreased renal blood flow and urine output o increase free hemoglobin ď block the renal tubules RH BLOOD GROUP CROSSMATCHING MAJOR REACTION MINOR REACTION DONOR RECIPIENT Cell -Antigen Plasma -Antibodies Plasma -Antibodies Cell -Antigen ďˇ Case 1: Donor (Type A) and Recipient (Type B) CROSSMATCHING MAJOR REACTION MINOR REACTION DONOR RECIPIENT RESULTS A antigen Anti -A Reactive (Agglutination) Anti-B B-antigen Reactive ďˇ Case 2: Donor (Type O) and Recipient (Type B) CROSSDONOR RECIPIENT RESULTS MATCHING MAJOR No antigen Anti –A Non-Reactive REACTION MINOR Anti-A and B-antigen Reactive REACTION Anti-B ď¨ Even if the minor reaction is reactive, the amount of blood donated (Blood bag: ~250 cc) is much lesser than the blood present in the patient’s body (~3 L) so the plasma of the recipient will just be degraded; manifested by some reactions like itching. ď¨ Type O = UNIVERSAL DONOR ď¨ Type AB = UNIVERSAL RECIPIENT (it does not contain antibodies) ď ď Rh Antigens: C D E c d e Rh + if the patient has D antigen (type D antigen is more widely prevalent and more antigenic than other Rh antigens) ď Transfusion reactions: o ABO is IMMEDIATE because the antibodies are IgM o Rh is DELAYED because the antibodies are IgG ď Formation of Anti-Rh agglutinins o Usually occurs when an Rh (-) individual receives a blood that is Rh (+) o Initially, nothing will happen to the recipient because the generation of antibodies is delayed. o (+) anti- Rh will develop in 2-4 months o After 2-4 months and the recipient receive an Rh (+) blood again ď Agglutination = Fatal because antibodies have already formed ď Hemolytic disease of the newborn: o If the baby is Rh (+) and the mother is Rh (-), the blood of the baby can mix with the blood of the mother and the mother will develop an immune response to produce antibodies against the fetal RBCs 7|CKRP o If the fetal RBCs are destroyed by the maternal antibodies ď ERYTHROBLASTOSIS FETALIS ď§ “Erythroblastosis” – because of rapid production of red cells, many early forms of RBCs like nucleated blastic forms go into the circulation o o o o ď ď Components of Erythroblastosis fetalis: o The baby develops ANEMIA ď Inc. workload ď heart failure o Severe anemia ď Backflow of blood ď dec blood in the tissues o Congestion relatively around the heart, abdomen ď FETAL HYDROP o In Anemia (hematopoietic tissues attempt to replaced hemolyzed RBCs) ď Enlarged spleen and liver ď Extramedullary hematopoiesis ď Inc blood ď bilirubin is produced ď bilirubin is deposited in the brain ď§ Kernicterus – permanent mental impairment or damage to motor areas of the brain because of precipitation of bilirubin in the neuronal cells causing destruction o Inc capillary hydrostatic pressure ď hydrops, ascites, pleural effusion, scalp edema Management of Rh Incompatibility 1. Rho-gam o Rh immunoglobulin globin – Anti-D antibody o Incidence of erythroblastosis fetalis has decreased a lot because of RHOGAM o Before it was introduced, Rh (-) pregnant women have 99% chance of delivering a newborn with haemolytic disease, manifesting anemia and erythroblastosis fetalis o Rh (+) blood is given to a donor (usually male) who is Rh (-) ď production of antibodies ď antibodies will be taken = Rho-gam o Male donors of Rho-gam would no longer have a chance to receive Rh (+) blood again because they are already sensitized to Rh (+) o Donors usually have high circulating levels of Anti-D o Rho-gam covers fetal RBCs and prevents the fetal RBCs to be recognized by the maternal immune system Routine Antenatal Prophylaxis: th ď§ Rho-gam is given to pregnant women at around 28 week of pregnancy, intramuscular (mixing of the blood of the mother and baby th usually occur around the 28 week of pregnancy) - a single dose of 300 ug ď§ The effectivity of Rho-gam is only 12 weeks so if the mother have not nd yet delivered by 40 weeks, the 2 dose of Anti-D Ig should be given Postnatal prophylaxis: nd ď§ If the mother had already delivered before 40 weeks and the 2 dose nd is not yet given, the 2 dose (single dose of 300 ug) should be given within 72 hours following the delivery of an Rh (+) infant (if the nd newborn is found to be Rh – then there’s no point of giving the 2 dose) The first thing to do upon discovering that the pregnant woman is Rh (-) is to get the blood type of the partner because if the partner is also Rh (-), Rhoth gam is not given at 28 week Rho-gam is given during the first pregnancy because even if the development st of the antibodies is delayed and the 1 pregnancy is not affected, the mother should not be immunized and should not develop antibodies that might react nd during the 2 pregnancy 2. Exchange transfusion o Getting the blood of the baby and transfuse an Rh (-) blood to prevent destruction and when the antibodies have already been removed then the transfusion is stopped o The baby will still produce Rh (+) blood but the main purpose of exchange transfusion is to remove the antibodies ď How would we know if the baby is Rh (+) while an Rh (-) mother is still pregnant? o Invasive: pierce through the uterus and get blood form the umbilical cord; but there are many complication possible through this method o So, we don’t necessarily have to do the invasive method as long as we know that the mother is Rh (-) and the partner is Rh (+) because there is a high chance that the baby will be Rh (+) ď Why are we not as concerned with ABO blood reaction as Rh reactions? o It is not a concern because in ABO blood groups, the antibodies are IgM which are too large to cross the placenta; In Rh blood groups it is IgG 8|CKRP BLOOD PHYSIOLOGY o PART 2: Platelets, Hemostasis, and Blood Coagulation Lectured by: Dr. Olivar ď Platelets/ Thrombocytes o Small, non-nucleated, colorless bodies, ranging in size from 1-4 um o Formed in the bone marrow from megakaryocytes o Normal value: ~ 150,000 – 300,000 o Half-life in the blood: 8-12 days o Thrombocytopenia – lower than the normal values o Thrombocytosis – higher than the normal values o The primary function is to achieve HEMOSTASIS ď§ Formation of the platelet plug ď§ Participates in blood coagulation ď§ Release thromboxane A2 and serotonin ď Local vasoconstriction ď§ Release thrombostenin ď Clot retraction o Functional characteristics: ď§ Actin and myosin molecules ď contractile protein ď§ Thrombosthenin ď contractile protein ď§ RER and Golgi complex ď synthesize enzymes and store large quantities of Ca ď§ Mitochondria ď ATP and ADP ď§ Prostaglandins ď local hormone that cause many vascular and other local tissue reactions ď§ Fibrin-stabilizing factor ď blood coagulation ď§ Growth factor ď cellular growth that will eventually help repair damaged vascular walls ď§ Glycoproteins ď in cell membrane; adherence to injured areas of vessel wall ď§ Phospholipid ď in cell membrane; activate multiple stages in bloodclotting process Platelets secrete thromboxane A2 and serotonin which helps in the vasoconstriction B. PLATELET PLUG FORMATION o Whenever the collagen on the blood vessels is exposed due to damage in the blood vessels ď platelets are attracted to the area ď platelet plug o Platelets + Collagen fibers ď§ Swell ď§ Numerous pseudopods protruding ď§ Release of granules with multiple active factors ď§ Sticky (to adhere to collagen and von Willebrand factor) ď§ Secrete ADP ď§ Form thromboxane A2 o If the damage is only small, the platelet plug formation is already enough ď hemostasis o Importance: closing minute ruptures in very small blood vessels that occur many thousand of times daily o Dec platelet or Adequate amount of platelet but the quality is poor ď Manifestations of multiple lesions: Purpura (bigger) and Petechiae o IDIOPATHIC THROMBOCYTOPENIC PURPURA – dec platelet; autoimmune disease; have several hematoma in the body C. BLOOD COAGULATION o Occurs during severe trauma: 15 – 20 seconds o Minor trauma: 1-2 minutes o Procoagulant: promote coagulation; predominated in blood stream o Anticoagulant: inhibit coagulation; dominate and activated in damaged tissue ď Mechanism of coagulation: HEMOSTASIS - prevention of blood loss ď 3 mechanisms: o Local vasoconstriction o Platelet plug o Blood coagulation o Eventual growth of fibrous tissue into the blood clot to close the hole in the vessel permanently A. LOCAL VASOCONSTRICTION o a reflex response from local myogenic contraction of the blood vessel st o 1 line in hemostasis o o Formation of prothrombin activator or prothrombin converting enzyme ď§ Rate-limiting factor Prothrombin ď Thrombin 9|CKRP o o ď ď§ with sufficient amount of CA++ ď§ Prothrombin is formed by the liver ď§ Vit K: required by the liver for normal production of prothrombin and other clotting factors Fibrinogen ď Fibrinogen monomer (not a stable clot due to weak non covalent hydrogen bond) ď polymerization through a coagulation factor called factor XIII ď Fibrin polymer (covalent bonds and multiple crosslinkages) ď§ Clot is composed of meshwork of fibrin fibers with trapped RBCs, platelets and plasma ď§ Fibrinogen is also formed by the liver Clot retraction ď§ Activation of thrombostenin, actin, and myosin ď§ Edges of broken blood vessels are pulled together ď Hemostasis Initiation of clotting process: o Extrinsic pathway ď§ trauma to the vascular wall and adjacent tissues o Intrinsic pathway (true pathways by which you can actually stimulate the clot to form) ď§ contact of the blood with damaged endothelial cells / collagen ď§ trauma to the blood ď¨ most are inactive forms of proteolytic enzymes ď¨ concerted to active forms ď successive, cascading reaction of clotting process ď ď¨ common pathway: formation of prothrombin activator Extrinsic pathway (coagulation is easily formed) 1. Trauma in the vascular wall or tissue ď release of tissue factor (Factor III Thromboplastin) o With PHOSPHOLIPIDS in the membrane o With LIPOPROTEIN COMPLEX – proteolytic enzyme 2. Factor VII ď activated Factor VII 10 | C K R P 3. Thromboplastin (lipoprotein complex) + activated Factor VII + presence of Ca++: Factor X ď activated Factor X 4. activated Factor X + thromboplastin (phospholipid) + Factor V: Prothrombin activator 5. Platelet phospholipid + presence of Ca++: Prothrombin ď Thrombin 6. Inactive Factor V + Thrombin ď Acitvated Factor V (accelerator of Prothrombin activation) 7. Fibrinogen ď Fibrin * It is the Factor Xa that is considered as the Prothrombin activator ď ď Roles of Ca++ and platelets: o serve as cofactor for the coagulation pathways o Even if the coagulation factors are adequate in number, but the platelet count is decreased or platelets have poor quality or the Ca++ is decreased ď clot will not be produced o Principle behind anticoagulants used in laboratory: ď§ Citrate (blue top): de-ionizes Ca++ ď§ Oxalate (gray top): precipitates Ca++ ď§ Anticoagulants remove Ca++ from the blood sample ď§ Reducing the Ca++ concentration below the threshold level for clotting ď Clot retraction Intrinsic pathway (coagulation proceeds much slower) 1. Blood trauma or exposure of blood to collagen: Factor XII ď Factor XIIa o Simultaneously, platelets are damaged ď release of platelet phospholipids w/ platelet factor 3 2. Factor XI ď Factor XIa o Requires HMW (high molecular weight) Kininogen o Accelerated by Prekallikrein 3. Factor IX ď Factor IXa 4. Factor IXa + Factor VIII + platelet phospholipids: Factor X ď Factor Xa o Platelet phospholipids are from the traumatized platelets o Factor VIII: ANTIHEMOPHILIC FACTOR o Hemophilia: absence of factor VIII 5. Factor Xa + Factor V + Platelet phospholipid ď Prothrombin activator 6. Prothrombin ď Thrombin 7. Fibrinogen ď FIbrin o o ď “As the clot retracts, the edges of the broken blood vessel are pulled together, thus possibly or probably contributing to the ultimate state of hemostasis ” Platelets contact ď vessels are pulled together ď re-epithelize ď hemostasis Lysis of blood clot: o Plasminogen/Profibrinolysin (inactive form) ď Plasmin/Fibrinolysin o by Tissue plasminogen activator (t-PA) - released by the endothelial cells of the damaged blood vessel o In commercial substances called Streptokinase which are given to patients that suffered from heart attack or myocardial infarction (blood clot blocked one of the major coronaries that supplies the heart) ď lysis of the clot and normal perfusion is maintained due to PLASMIN and not streptokinase 11 | C K R P o o ď§ Plasmin dissolved the clot; Streptokinase immediately converts plasminogen to plasmin Plasmin can only lyse/dissolve the clot if the clot had not yet stabilized. If the clot is already stabilized, even if Streptokinase is given and plasmin is produced ď clot would no longer be dissolved ď Functions of Plasmin: o digest fibrin fibers o digest fibrinogen, Factor V, VIII, XII and prothrombin o “to remove clots from the vessels that eventually would become occluded were there’s no way to clean them” ď Prevention of Blood Clotting in the Normal Vascular System – The Intravascular Anticoagulants: o endothelial surface factors ď§ smoothness of the endothelial cell surface ď prevent contact activation of the intrinsic clotting system ď§ glycocalyx ď prevents clotting factors from attaching ď§ thrombomodulin ď binds thrombin ď thrombomodulinthrombin complex activates protein C ď inactivates Factor Va and VIIIa; present only in an intact endothelium o anti-thrombin action of fibrin and anti-thrombin III ď§ 85-90% of thrombin becomes absorbed to the fibrin fibers ď§ anti-thrombin III: blocks the effect of thrombin to fibrinogen and inactivates them o Heparin ď§ By itself it has no or little anticoagulant properties but when combined with antithrombin III ď greatly increases the effectiveness in removing thrombin ď§ Formed by basophilic mast cells 2. Coagulation Disorders A. Coagulation deficiencies 1. Bleeding caused by Vit K deficiency ď§ Vit K is continuously synthesized by intestinal bacteria ď§ Liver produces Factors IX, X, VII, II, protein C through carboxylation (liver carboxylase) aided by Vit K ď§ Once the coagulation factors are already carboxylated ď Vit K becomes inactive ď§ Vitamin K epoxide reductase complex 1 (VCOR c1) ď reduces Vit K back to its active form ď§ One of the fat soluble vitamins: can only be absorbed in the presence of fat ď§ Fats cannot be absorbed in the intestine without bile because bile emulsifies fat 3. Vit K deficiency may be due to failure of the liver to secrete bile or obstruction of bile duct caused by liver diseases ď§ If a patient has gallstones ď removal of gall bladder ď no Vit K deficiency because bile is secreted from the liver and goes directly to the intestines; gall bladder is just a storage of bile ď§ When the common bile duct is cut ď bile will not be delivered ď§ If the common bile duct is accidentally cut during surgery, duodenum is attached to the liver so that there will be supply of bile ď§ In newborn, initially they don’t have intestinal bacterial flora ď Vit K injection is administered Hemophilia ď§ sex-linked disease: only manifested in males but from the chromosomes of female carriers ď§ 85%: absence of Factor VIII = HEMOPHILIA A or CLASSIC HEMOPHILIA ď§ 15%: absence of Factor IX ď§ Treatment: Recombinant Factor VIII Thrombocytopenia ď§ Presence of very low number of platelets in the circulating blood ď§ Treatment: fresh whole blood transfusion with large numbers of platelets and splenectomy B. Coagulation excess ď¨ Artherosclerotic plaque ď Hypertension (dec diameter of blood vessels) ď¨ Rupture in the lumen of blood vessels ď collagen is exposed ď abnormal thrombus formation ď myocardial infarction ď¨ Treatment: genetically-engineered T-PA ď dissolve intravascular clot 1. 2. Thrombus ď§ an abnormal clot that develops in a blood vessel Emboli ď§ freely flowing clots ď§ due to roughened endothelial surface of vessel 12 | C K R P ď§ ď§ ď§ ď§ ď§ ď§ ď§ 3. 4. o o o exemplified by formation of clot coming from the deep veins of the leg ď Pulmonary embolism left side of the heart ď Stroke due to slow blood flow ď clot forms and settles in the valves ď clot is thrown by the blood flow into distal areas ď Embolus ď goes up to block pulmonary capillaries ď PULMONARY EMBOLISM It usually occurs in capillaries rather that in arteries because of the small diameter of capillaries Theoretically (under normal condition), it is not possible to see a clot that originated from the deep vein of the leg go into the left side of the heart because once it has blocked the pulmonary capillaries it can no longer go on and proceed to the left side of the heart However it is still possible when there is communication between the chambers of the heart = Ventricular septal defect It is also possible in tetralogy of fallot wherein the right ventricular pressure is greater than the left; bidirectional flow ď Blood will flow from right to left Infarct ď§ tissue devoid of blood supply Disseminated Intravascular Coagulation clotting mechanism becomes activated in widespread areas of the circulation Sepsis ď§ Bacteria release toxins (endotoxins) ď activate blood clotting mechanisms ď§ Treatment: antibiotics Abruptio placenta ď§ If there is clot, plasmin will dissolve it ď placenta and bacteria will produce clot again ď it will be dissolved again by the placenta ď coagulation factors are already consumed ď CONSUMPTIVE coagulopathy ď§ Treatment: Antibiotic or removal of placenta ď Anticoagulants for clinical use: 1. Heparin o Mode of action: potentiates the action of antithrombin III o Heparin-antithrombin III complex blocks factors XII, XI, IX, X and II o Antidote: protamine sulphate o Action lasts for 1.5 to 4 hrs and then destroyed in the blood by HEPARINASE 2. Coumarin/ warfarin o Mechanism of action: blocks the action of vitamin K o Inactivates VCOR C1 ď Vit K will not be reduced back to its active form ď Coagulation factors will not be activated ď Blood coagulation tests 1. Bleeding time o pierce the tip of the finger or lobe of the ear o bleeding ordinarily lasts for 1 to 6 minutes o Prolonged bleeding time: Lack of any one of several of the clotting factors and lack of platelets. o Inaccurate because it is operator-dependent 13 | C K R P o TEST for QUALITY of PLATELETS: if platelets are of good quality, they will perform platelet plug formation ď bleeding will stop 2. Clotting time o Collect blood in a chemically clean glass test tube and then to tip the tube back and forth about every 30 seconds until the blood has clotted o time needed for blood to clot o NV: 6 - 10 minutes o test for clotting factors 3. Prothrombin time o test for quantity of prothrombin in the blood (E) o NV: 12 seconds 4. Partial thrombolastin time o Test the intrinsic pathway of coagulation God looks down from heaven on the entire human race to see if anyone is truly wise. And the truly wise person is the one who seeks Him. = Psalm 53:2= 14 | C K R P BLOOD PHYSIOLOGY PART 1: RBC’s and Blood groups Lectured by: Dr. Olivar Functions of the blood: 1. Keeps the internal environment of the body constant (homeostasis) 2. Transports 02 from the lungs to the tissues and CO2 from the tissues to the lungs (respiratory) 3. Carries nutritive materials form the intestines to all parts of the body (nutritive) 4. Carries waste products of tissue metabolism to the kidneys (excretory) 5. Transports internal secretions from glands to the tissues on which the effects are exerted (endocrinology) 6. Helps maintain acid-base balance 7. Maintenance of water and electrolyte balance and in the regulation of total osmotic pressure 8. Immunity to diseases (WBCs) 9. Regulation of body temperature I. Blood volume A. Normal Blood volume ď A normal 7 kg male will usually have approx. 5 L of blood. ď Women, because of their short stature, will usually have a lower volume of blood = 4.5 L ď Regardless of the volume, the blood will always be divided into two major parts: 1. Plasma ď 60% = 3000 ml 2. Formed elements ď 40% = 2000 ml B. Composition of blood We can separate the components of the blood by CENTRIFUGATION. ď The RBCs will be the most dense so it will settle at the bottom of the haematocrit. ď Middle: platelets and WBCs (have intermediate densities) = Buffy coat ď Upper portion: Plasma C. Regulation of blood volume When the heart contracts, it creates a pressure inside the blood vessel = HYDROSTATIC PRESSURE (HP) ď HP tends to push the plasma into the interstitial space but normally it does not happen because of an opposing force that keeps the plasma inside the blood vessel = ONCOTIC PRESSURE ď ď Important factors in the regulation of formed elements: o Bone marrow production o Destruction/Wear and tear II. Composition of blood A. Formed elements ď Components: RBC, WBC, Platelet B. Plasma ď Predominantly WATER ď Plasma protein: albumin, globulin, coagulation factors (fibrinogen, prothrombin), antibodies ď blood sugar: glucose ď lipids: cholesterol, phospholipids, neutral fats ď salts: Na, K, Cl, bicarbonates, phosphates ď gases: O2, CO2, nitrogen ď special plasma substances: hormones, enzymes, antibodies ď Functions of plasma: 1. Maintain normal balance between the intravascular compartment and extravascular space (oncotic pressure) ď 2. 3. 4. 5. 6. 7. 8. Oncotic pressure is comparable to Osmosis (movement of solvent form area of lesser solute concentration to an area of higher solute concentration; going where the solutes are) ď Inside the blood vessel :Plasma CHONs (solute) ď dec. plasma CHONs ď dec oncotic pressure ď hydrostatic pressure predominates ď plasma will go into the interstitial space ď EDEMA ď Liver (produces plasma CHONs): Liver disease ď dec plasma CHONs ď edema ď§ Ex: Cirrhosis of the liver ď liver can no longer produce plasma CHONs ď Kidney (allows CHONs to go to the urine) ď dec plasma CHONs ď edema Viscosity of the blood is primarily determined by the RBCs but somehow, plasma CHONs also contribute to the viscosity of the blood Source of antibodies Necessary for coagulation Maintenance of acid-base balance Determines the specific gravity of the plasma (1.028) Formation of enzymes Transport of hormones and enzymes 1|CKRP RED BLOOD CELL ď ď ď ď Biconcave discs, 2.5 um thick, 7.5 – 8 um in diameter; 1 um at the center Very deformable: due to excess cell membrane Non-nucleated in the circulating blood Primary function: carry haemoglobin ď carries O2 in the circulation (1 gm of Hgb: 1.34 ml of O2) ď During adulthood, in the rare case that the bone marrow fails to produce RBCs, liver and spleen can produce RBCs again = EXTRAMEDULLARY HEMATOPOIESIS Ex: Aplastic anemia (bone marrow failure) ď Liver and spleen must produce RBCs in exaggerated way ď Enlargement of liver and spleen ď HEPATOSPLENOMEGALY D. Erythropoiesis: process of RBC production A. Hematopoiesis: process by which formed elements are produced o All blood cells originate in the BONE MARROW o Multipotent/Pluripotent cells ď can give rise to different types of cells o Stem cells are not only seen in the bone marrow. There are also stem cells present in the umbilical cord (can be harvested during childbirth and stored in the blood bank for future purposes; could be beneficial if the child would develop blood disease) B. Normal values: o RBC count 1. men: 5-6 x 1012/ L 2. women: 4-5 x 1012/ L 3. infants: 6.5 x 1012/ L < NV = ANEMIA > NV = POLYCYTHEMIA o Hemoglobin 1. men: 14 – 17 g/dL 2. women: 12 – 15 g/dL o Hematocrit 1. men: 0.40 – 0.50 2. women: 0.38 – 0.48 C. RBC production: begins IN UTERO a. Yolk sac of the embryo st ďˇ Produce RBCs during the 1 few weeks of embryonic life ďˇ nourish the embryo st ďˇ 1 site of hematopoiesis b. Liver, spleen, lymph nodes ďˇ middle trimester of pregnancy c. Bone marrow ďˇ 3rd trimester of pregnancy – 5 y/o d. Bone marrow of axial skeleton (skull, vertebral column, ribs, sternum, pelvic bone) ďˇ 20 y/o and above ď Why are the long bones no longer capable of producing RBCs during adulthood? It is because the long bones become infiltrated with yellow marrow. ď Multipotential/Pluripotential Hemopoietic stem cell: HEMOCYTOBLAST 1. All the cells in the circulating blood are derived from this cell. ď Committed stem cell: PROERYTHROBLAST 1. Intermediate-stage cell 2. They have already become committed to a particular line of cells; produce specific type of blood cells 3. Formed from COLONY-FORMING UNIT ERYTHROCYTE (CFU-E) ď During the production of the mature RBC, the haemoglobin is incorporated into the RBC and the nucleus condenses until it is finally extruded from the cell st ď Reticulocyte: 1 cell released into the circulation Peripheral blood smear: feathery edge E. ď (remains blue because they still contain cytoplasmic and nuclear remnants) (after 2 days, they become reddish, non-nucleated RBCs) Hemoglobin The primary function of red blood cells is to transport hemoglobin, which in turn carries oxygen from the lungs to the tissues and the carbon dioxide back from the tissues to the lungs 2|CKRP ď ď Formation of Hgb: o 2 succinyl CoA + 2 glycine ď pyrrole molecule o 4 pyrroles ď protoporphyrin IX o Protoporphyrin IX + Fe ď Heme o Heme + globin ď Hemoglobin chain (alpha or beta) o 2 alpha chains + 2 beta chains ď Hemoglobin A 1. 1 chain = 1 Fe 2. Adult Hgb = 4 Fe 3. 1 Fe = bind to 1 O2 molecule 4. Sickle cell anemia Abnormal beta chain: valine is substituted to glutamic acid in each of two beta chains upon exposure to O2, the Hgb forms, elongated crystals ď spiked ends rupture the cell membrane hemolysis ď Fe in the body exist in the following forms: o RBC: Hemoglobin (majority) ď 65% o Muscle: Myoglobin ď 4% o Tissues in GIT (Reticuloendothelial system and liver parenchymal cells): Ferritin ď 15 to 30% o Participate in enzymatic reaction: Cytochrome enzymes ď ď Source of Fe: glandular organs, beef, pork, chicken, oyster Absorption of Fe from GIT: Transport of O2 in the blood is primarily due to the combination of Hgb to O2 o 97% of O2 – combine with Hgb o 3% of O2 – dissolved in plasma and cells o Attachment of Hgb to O2 is a REVERSIBLE combination Liver produces apotransferrin ď secreted to the bile ď duodenum (does not readily go to the blood): ď If Fe content is adequate, Fe will just be stored in the mucosal cells of duodenum as FERRITIN (storage form of Fe) ď§ Fe + Apoferritin ď Ferritin ď If Fe is already needed in the bone marrow for the production of RBCs (when the quantity of Fe in the plasma falls low), Fe in the form of TRANSFERRIN (transfer form of Fe) will be delivered to the bone marrow for erythropoiesis ď§ Fe + Apotransferrin ď Transferrin o o o ď In the lungs, when the O2 content is VERY HIGH, O2 readily ATTACHES to Hgb In the tissues, when the O2 content is VERY LOW, O2 is readily RELEASED by the Hgb Transport of CO2 in the blood is predominantly via bicarbonate. ď Iron Metabolism o RBC released in circulation ď 120 days ď RBCs will be destroyed in the liver and spleen (RETICULOENDOTHELIAL SYSTEM) by KUPFFER CELLS of the liver and MACROPHAGES of spleen and bone marrow ď Hgb is released ď Liver ď release Fe and porphyrin ď bilirubin and Fe is brought back to the bone marrow to be reused again in erythropoiesis o o ď Hence, we don’t need Fe that much because the Fe used in the erythropoietic period is just recycled and the mechanism by which our body eliminates Fe is very limited = It’s harmful to take Fe as a multivitamin everyday Fe as multivitamin taken every day ď Fe overload ď Destroy organs An adult individual, depending on the gender and habit, has 4-6 g. of Fe 3|CKRP o ď§ (-) intrinsic factor: For the Vit. B12 to be absorbed, the stomach does not only produce acid. The parietal cells of the stomach also release an intrinsic factor which facilitates absorption of Vit. B12. Therefore, if the intrinsic factor is not present, Vit B12 will not be absorbed ď§ Treatment: give Vit B12 through SHOT not through tablet; direct to the blood vessels Fe supplements are only recommended for females with menstrual problems (heavy menstrual bleeding) and pregnant women - Folic acid Deficiency: SPRUE ď§ decreased intestinal absorption of folic acid and B12 G. Control of RBC production o to ensure that there will be enough RBC that would carry O2 from the lungs to the tissues o too many RBC ď RBCs overcrowd the vessels ď impede blood flow ď ď Elimination of Iron: o Bile o Urine o Feces o Menstruation ď Tissue oxygenation o Primary stimulus for RBC control o Dec RBC = HYPOXIA ď§ Dec. blood flow and blood volume ď§ Inc. altitude and pulmonary diseases = In people living in high places, they are not anemic and they have adequate RBC but the amount of O2 is decreased in high altitude = In people with pulmonary diseases, O2 cannot traverse the pulmonary system ď O2 can’t go to the blood ď dec O2 in tissues o production of RBC is not dependent on the number of RBC ď§ RBC production can be stimulated when RBC number is low but it can also be stimulated even if the RBC number is normal as long as the tissues are hypoxic ď Erythropoietin F. Maturation of RBC Vitamin B12 (Cyanocobalamin) and Folic acid (Pteroylglutamic acid) - Essential for synthesis of DNA - Without them, erythropoiesis will proceed slowly; abnormal and diminished DNA ď failure of nuclear maturation and cell division - Blast cells are released into the circulation due to slow DNA synthesis = Macrocytes: rupture easily ď MEGALOBLASTIC ANEMIA “megalo” = big “blastic” = produce blast cells “anemia” = RBCs rupture easily - Vitamin B12 Deficiency: PERNICIOUS ANEMIA ď§ atrophic gastric mucosa: stomach is devoid of any cell and gland ď cannot produce intrinsic factor and normal gastric secretions 4|CKRP o o o 90% is produced by the kidney and the remainder is mainly produced by the liver Stimulate production of proerythroblast ď inc RBC ď Inc O2 Cause cells to pass more rapidly through the different erythroblastic stages than they normally do = speeding up production of new RBCs I. Anemias: deficiency of Hgb; too rapid loss or too slow production Blood loss – due to hemorrhage Iron deficiency anemia o In PBS, smaller in size and paler in color o MICROCYTIC HYPOCHROMIC RBCs ď§ Hypochromic = RBCs contain much less haemoglobin than normal ď Aplastic anemia – bone marrow failure; due to chemotherapy, toxic chemicals, autoimmune disorders ď§ Idiopathic aplastic anemia – aplastic anemia cases wherein the cause is unknown ď Megaloblastic anemia o Vit B12 and Folic acid deficiency o MACROCYTIC HYPERCHROMIC RBCs ď Hemolytic anemia o Hereditary spherocytosis ď ď ď¨ When your Hgb synthesis is already normal and O2 transport is already adequate, the kidney and liver will stop further production of erythropoietin ď to inhibit ď¨ RBCs are spherical in shape not biconcave ď¨ These cells cannot withstand compression forces because overcrowding of RBC they do not have the normal bag-like cell membrane structure of biconcave discs H. RBC destruction ď¨ The cell membrane does not have a functional Na-K pump ď 1% of red cells replaced daily total red cell volume replaced every 4 months ď Na+ are not pumped out of the cell ď H20 continuously ď Site of destruction: SPLEEN go inside of the cell ď Cell becomes spherical (swell) until it ď “The number of red cell in the circulation at any time is determined by the balance ruptures between production and destruction ” o o ď ď ď POLYCYTHEMIA = overproduction ANEMIA = underproduction/over-destruction Isotonic solution o 0.9% Nacl; 5% dextrose o No movement of water Hypertonic solution o Greater concentration of solute in the solution than in the RBC o crenation Hypotonic solution o Lower concentration of solute in the solution than in the RBC o Spherical ď rupture ď hemolysis Effects of anemia on the circulatory system: ď Dec viscosity ď Dec resistance to flow o Viscosity of the blood is due to RBCs o Dec RBC ď Dec viscosity ď greater blood flow ď greater volume of blood goes to the heart ď INCREASE CARDIAC OUTPUT ď INCREASE WORKLOAD (Anemia makes the heart work faster and harder) o In young people, it’s still okay to have anemia because the heart muscle is still strong o In old people, too much pumping of the heart ď heart failure o Since there’s a decreased amount of RBC, the heart needs to pump harder to supply adequate amount of O2 to the tissues ď Polycythemia o Primary o Secondary ď§ Normal number of RBC but since an individual is living in a high place, smoking, or has pulmonary diseases ď Tissue 5|CKRP hypoxia ď Inc RBC ď Inc viscosity ď sluggish flow of blood ď high probability of forming clot within blood vessels which blocks the blood flow ď§ Treatment: Therapeutic phlebotomy (every 2 or 3 months, removal/extraction of blood to decrease the amount of RBCs) o ď Effect of polycythemia in circulatory system ď§ Increase in blood viscosity ď DECREASE rate of venous return to the heart ď§ Increase in blood volume ď INCREASE rate of venous return to the heart ď§ Hence, the effect is NORMAL because the two factors normalize each other Polycythemia vera o Genetic aberration in the hemocytoblastic cells o Negative inhibition to the liver and kidneys to control production of erythropoietin does not occur so even if the number of RBCs was already increased, there is still sustained production of RBC o It affects not only the RBCs but also WBCs (total blood volume increases) unlike in secondary polycythemia wherein only the RBCs will increase. ď ď Agglutination process in transfusion reactions o Immediate: IgM ď complement system (release proteolytic enzymes that ruptures the cell membrane) ď HEMOLYSIS o Delayed: IgG +Ag ď AGGLUTINATION ď HEMOLYSIS Blood typing: ABO BLOOD GROUP ď Antigens o Aka Agglutinogens because they often cause blood cell agglutination o Ag: A, AB, B, O o Genetic determination of agglutinogens: ď ď Antibodies o Aka Agglutinins o Ab: IgG, IgM Cross-matching : to know the compatibility of the blood o Recipient: patient who will receive the blood o Donor: donates blood to the recipient o Cross match the CELL (antigen) present in the blood of the donor with the PLASMA (antibodies) present in the recipient = MAJOR REACTION o MINOR REACTION: Reaction between the PLASMA of the donor with the recipient’s CELL o In a packed RBC, plasma in the blood is removed leaving only the RBCs. 6|CKRP ď ď ď ď During haemorrhage, blood transfusion can save the patient’s life but if the blood is transfused in the wrong way can also lead to the death of the patient. Error in blood transfusion may result in: o agglutination o destruction of RBC membrane by antibodies = hemolysis o renal shutdown Acute renal failure occurs whenever there is error in blood transfusion. Causes of Renal shutdown: o hemolyzing blood releases toxic substances that cause severe renal arteriolar vasoconstriction o circulatory shock ď arterial blood pressure falls very low ď decreased renal blood flow and urine output o increase free hemoglobin ď block the renal tubules RH BLOOD GROUP CROSSMATCHING MAJOR REACTION MINOR REACTION DONOR RECIPIENT Cell -Antigen Plasma -Antibodies Plasma -Antibodies Cell -Antigen ďˇ Case 1: Donor (Type A) and Recipient (Type B) CROSSMATCHING MAJOR REACTION MINOR REACTION DONOR RECIPIENT RESULTS A antigen Anti -A Reactive (Agglutination) Anti-B B-antigen Reactive ďˇ Case 2: Donor (Type O) and Recipient (Type B) CROSSDONOR RECIPIENT RESULTS MATCHING MAJOR No antigen Anti –A Non-Reactive REACTION MINOR Anti-A and B-antigen Reactive REACTION Anti-B ď¨ Even if the minor reaction is reactive, the amount of blood donated (Blood bag: ~250 cc) is much lesser than the blood present in the patient’s body (~3 L) so the plasma of the recipient will just be degraded; manifested by some reactions like itching. ď¨ Type O = UNIVERSAL DONOR ď¨ Type AB = UNIVERSAL RECIPIENT (it does not contain antibodies) ď ď Rh Antigens: C D E c d e Rh + if the patient has D antigen (type D antigen is more widely prevalent and more antigenic than other Rh antigens) ď Transfusion reactions: o ABO is IMMEDIATE because the antibodies are IgM o Rh is DELAYED because the antibodies are IgG ď Formation of Anti-Rh agglutinins o Usually occurs when an Rh (-) individual receives a blood that is Rh (+) o Initially, nothing will happen to the recipient because the generation of antibodies is delayed. o (+) anti- Rh will develop in 2-4 months o After 2-4 months and the recipient receive an Rh (+) blood again ď Agglutination = Fatal because antibodies have already formed ď Hemolytic disease of the newborn: o If the baby is Rh (+) and the mother is Rh (-), the blood of the baby can mix with the blood of the mother and the mother will develop an immune response to produce antibodies against the fetal RBCs 7|CKRP o If the fetal RBCs are destroyed by the maternal antibodies ď ERYTHROBLASTOSIS FETALIS ď§ “Erythroblastosis” – because of rapid production of red cells, many early forms of RBCs like nucleated blastic forms go into the circulation o o o o ď ď Components of Erythroblastosis fetalis: o The baby develops ANEMIA ď Inc. workload ď heart failure o Severe anemia ď Backflow of blood ď dec blood in the tissues o Congestion relatively around the heart, abdomen ď FETAL HYDROP o In Anemia (hematopoietic tissues attempt to replaced hemolyzed RBCs) ď Enlarged spleen and liver ď Extramedullary hematopoiesis ď Inc blood ď bilirubin is produced ď bilirubin is deposited in the brain ď§ Kernicterus – permanent mental impairment or damage to motor areas of the brain because of precipitation of bilirubin in the neuronal cells causing destruction o Inc capillary hydrostatic pressure ď hydrops, ascites, pleural effusion, scalp edema Management of Rh Incompatibility 1. Rho-gam o Rh immunoglobulin globin – Anti-D antibody o Incidence of erythroblastosis fetalis has decreased a lot because of RHOGAM o Before it was introduced, Rh (-) pregnant women have 99% chance of delivering a newborn with haemolytic disease, manifesting anemia and erythroblastosis fetalis o Rh (+) blood is given to a donor (usually male) who is Rh (-) ď production of antibodies ď antibodies will be taken = Rho-gam o Male donors of Rho-gam would no longer have a chance to receive Rh (+) blood again because they are already sensitized to Rh (+) o Donors usually have high circulating levels of Anti-D o Rho-gam covers fetal RBCs and prevents the fetal RBCs to be recognized by the maternal immune system Routine Antenatal Prophylaxis: th ď§ Rho-gam is given to pregnant women at around 28 week of pregnancy, intramuscular (mixing of the blood of the mother and baby th usually occur around the 28 week of pregnancy) - a single dose of 300 ug ď§ The effectivity of Rho-gam is only 12 weeks so if the mother have not nd yet delivered by 40 weeks, the 2 dose of Anti-D Ig should be given Postnatal prophylaxis: nd ď§ If the mother had already delivered before 40 weeks and the 2 dose nd is not yet given, the 2 dose (single dose of 300 ug) should be given within 72 hours following the delivery of an Rh (+) infant (if the nd newborn is found to be Rh – then there’s no point of giving the 2 dose) The first thing to do upon discovering that the pregnant woman is Rh (-) is to get the blood type of the partner because if the partner is also Rh (-), Rhoth gam is not given at 28 week Rho-gam is given during the first pregnancy because even if the development st of the antibodies is delayed and the 1 pregnancy is not affected, the mother should not be immunized and should not develop antibodies that might react nd during the 2 pregnancy 2. Exchange transfusion o Getting the blood of the baby and transfuse an Rh (-) blood to prevent destruction and when the antibodies have already been removed then the transfusion is stopped o The baby will still produce Rh (+) blood but the main purpose of exchange transfusion is to remove the antibodies ď How would we know if the baby is Rh (+) while an Rh (-) mother is still pregnant? o Invasive: pierce through the uterus and get blood form the umbilical cord; but there are many complication possible through this method o So, we don’t necessarily have to do the invasive method as long as we know that the mother is Rh (-) and the partner is Rh (+) because there is a high chance that the baby will be Rh (+) ď Why are we not as concerned with ABO blood reaction as Rh reactions? o It is not a concern because in ABO blood groups, the antibodies are IgM which are too large to cross the placenta; In Rh blood groups it is IgG 8|CKRP BLOOD PHYSIOLOGY o PART 2: Platelets, Hemostasis, and Blood Coagulation Lectured by: Dr. Olivar ď Platelets/ Thrombocytes o Small, non-nucleated, colorless bodies, ranging in size from 1-4 um o Formed in the bone marrow from megakaryocytes o Normal value: ~ 150,000 – 300,000 o Half-life in the blood: 8-12 days o Thrombocytopenia – lower than the normal values o Thrombocytosis – higher than the normal values o The primary function is to achieve HEMOSTASIS ď§ Formation of the platelet plug ď§ Participates in blood coagulation ď§ Release thromboxane A2 and serotonin ď Local vasoconstriction ď§ Release thrombostenin ď Clot retraction o Functional characteristics: ď§ Actin and myosin molecules ď contractile protein ď§ Thrombosthenin ď contractile protein ď§ RER and Golgi complex ď synthesize enzymes and store large quantities of Ca ď§ Mitochondria ď ATP and ADP ď§ Prostaglandins ď local hormone that cause many vascular and other local tissue reactions ď§ Fibrin-stabilizing factor ď blood coagulation ď§ Growth factor ď cellular growth that will eventually help repair damaged vascular walls ď§ Glycoproteins ď in cell membrane; adherence to injured areas of vessel wall ď§ Phospholipid ď in cell membrane; activate multiple stages in bloodclotting process Platelets secrete thromboxane A2 and serotonin which helps in the vasoconstriction B. PLATELET PLUG FORMATION o Whenever the collagen on the blood vessels is exposed due to damage in the blood vessels ď platelets are attracted to the area ď platelet plug o Platelets + Collagen fibers ď§ Swell ď§ Numerous pseudopods protruding ď§ Release of granules with multiple active factors ď§ Sticky (to adhere to collagen and von Willebrand factor) ď§ Secrete ADP ď§ Form thromboxane A2 o If the damage is only small, the platelet plug formation is already enough ď hemostasis o Importance: closing minute ruptures in very small blood vessels that occur many thousand of times daily o Dec platelet or Adequate amount of platelet but the quality is poor ď Manifestations of multiple lesions: Purpura (bigger) and Petechiae o IDIOPATHIC THROMBOCYTOPENIC PURPURA – dec platelet; autoimmune disease; have several hematoma in the body C. BLOOD COAGULATION o Occurs during severe trauma: 15 – 20 seconds o Minor trauma: 1-2 minutes o Procoagulant: promote coagulation; predominated in blood stream o Anticoagulant: inhibit coagulation; dominate and activated in damaged tissue ď Mechanism of coagulation: HEMOSTASIS - prevention of blood loss ď 3 mechanisms: o Local vasoconstriction o Platelet plug o Blood coagulation o Eventual growth of fibrous tissue into the blood clot to close the hole in the vessel permanently A. LOCAL VASOCONSTRICTION o a reflex response from local myogenic contraction of the blood vessel st o 1 line in hemostasis o o Formation of prothrombin activator or prothrombin converting enzyme ď§ Rate-limiting factor Prothrombin ď Thrombin 9|CKRP o o ď ď§ with sufficient amount of CA++ ď§ Prothrombin is formed by the liver ď§ Vit K: required by the liver for normal production of prothrombin and other clotting factors Fibrinogen ď Fibrinogen monomer (not a stable clot due to weak non covalent hydrogen bond) ď polymerization through a coagulation factor called factor XIII ď Fibrin polymer (covalent bonds and multiple crosslinkages) ď§ Clot is composed of meshwork of fibrin fibers with trapped RBCs, platelets and plasma ď§ Fibrinogen is also formed by the liver Clot retraction ď§ Activation of thrombostenin, actin, and myosin ď§ Edges of broken blood vessels are pulled together ď Hemostasis Initiation of clotting process: o Extrinsic pathway ď§ trauma to the vascular wall and adjacent tissues o Intrinsic pathway (true pathways by which you can actually stimulate the clot to form) ď§ contact of the blood with damaged endothelial cells / collagen ď§ trauma to the blood ď¨ most are inactive forms of proteolytic enzymes ď¨ concerted to active forms ď successive, cascading reaction of clotting process ď ď¨ common pathway: formation of prothrombin activator Extrinsic pathway (coagulation is easily formed) 1. Trauma in the vascular wall or tissue ď release of tissue factor (Factor III Thromboplastin) o With PHOSPHOLIPIDS in the membrane o With LIPOPROTEIN COMPLEX – proteolytic enzyme 2. Factor VII ď activated Factor VII 10 | C K R P 3. Thromboplastin (lipoprotein complex) + activated Factor VII + presence of Ca++: Factor X ď activated Factor X 4. activated Factor X + thromboplastin (phospholipid) + Factor V: Prothrombin activator 5. Platelet phospholipid + presence of Ca++: Prothrombin ď Thrombin 6. Inactive Factor V + Thrombin ď Acitvated Factor V (accelerator of Prothrombin activation) 7. Fibrinogen ď Fibrin * It is the Factor Xa that is considered as the Prothrombin activator ď ď Roles of Ca++ and platelets: o serve as cofactor for the coagulation pathways o Even if the coagulation factors are adequate in number, but the platelet count is decreased or platelets have poor quality or the Ca++ is decreased ď clot will not be produced o Principle behind anticoagulants used in laboratory: ď§ Citrate (blue top): de-ionizes Ca++ ď§ Oxalate (gray top): precipitates Ca++ ď§ Anticoagulants remove Ca++ from the blood sample ď§ Reducing the Ca++ concentration below the threshold level for clotting ď Clot retraction Intrinsic pathway (coagulation proceeds much slower) 1. Blood trauma or exposure of blood to collagen: Factor XII ď Factor XIIa o Simultaneously, platelets are damaged ď release of platelet phospholipids w/ platelet factor 3 2. Factor XI ď Factor XIa o Requires HMW (high molecular weight) Kininogen o Accelerated by Prekallikrein 3. Factor IX ď Factor IXa 4. Factor IXa + Factor VIII + platelet phospholipids: Factor X ď Factor Xa o Platelet phospholipids are from the traumatized platelets o Factor VIII: ANTIHEMOPHILIC FACTOR o Hemophilia: absence of factor VIII 5. Factor Xa + Factor V + Platelet phospholipid ď Prothrombin activator 6. Prothrombin ď Thrombin 7. Fibrinogen ď FIbrin o o ď “As the clot retracts, the edges of the broken blood vessel are pulled together, thus possibly or probably contributing to the ultimate state of hemostasis ” Platelets contact ď vessels are pulled together ď re-epithelize ď hemostasis Lysis of blood clot: o Plasminogen/Profibrinolysin (inactive form) ď Plasmin/Fibrinolysin o by Tissue plasminogen activator (t-PA) - released by the endothelial cells of the damaged blood vessel o In commercial substances called Streptokinase which are given to patients that suffered from heart attack or myocardial infarction (blood clot blocked one of the major coronaries that supplies the heart) ď lysis of the clot and normal perfusion is maintained due to PLASMIN and not streptokinase 11 | C K R P o o ď§ Plasmin dissolved the clot; Streptokinase immediately converts plasminogen to plasmin Plasmin can only lyse/dissolve the clot if the clot had not yet stabilized. If the clot is already stabilized, even if Streptokinase is given and plasmin is produced ď clot would no longer be dissolved ď Functions of Plasmin: o digest fibrin fibers o digest fibrinogen, Factor V, VIII, XII and prothrombin o “to remove clots from the vessels that eventually would become occluded were there’s no way to clean them” ď Prevention of Blood Clotting in the Normal Vascular System – The Intravascular Anticoagulants: o endothelial surface factors ď§ smoothness of the endothelial cell surface ď prevent contact activation of the intrinsic clotting system ď§ glycocalyx ď prevents clotting factors from attaching ď§ thrombomodulin ď binds thrombin ď thrombomodulinthrombin complex activates protein C ď inactivates Factor Va and VIIIa; present only in an intact endothelium o anti-thrombin action of fibrin and anti-thrombin III ď§ 85-90% of thrombin becomes absorbed to the fibrin fibers ď§ anti-thrombin III: blocks the effect of thrombin to fibrinogen and inactivates them o Heparin ď§ By itself it has no or little anticoagulant properties but when combined with antithrombin III ď greatly increases the effectiveness in removing thrombin ď§ Formed by basophilic mast cells 2. Coagulation Disorders A. Coagulation deficiencies 1. Bleeding caused by Vit K deficiency ď§ Vit K is continuously synthesized by intestinal bacteria ď§ Liver produces Factors IX, X, VII, II, protein C through carboxylation (liver carboxylase) aided by Vit K ď§ Once the coagulation factors are already carboxylated ď Vit K becomes inactive ď§ Vitamin K epoxide reductase complex 1 (VCOR c1) ď reduces Vit K back to its active form ď§ One of the fat soluble vitamins: can only be absorbed in the presence of fat ď§ Fats cannot be absorbed in the intestine without bile because bile emulsifies fat 3. Vit K deficiency may be due to failure of the liver to secrete bile or obstruction of bile duct caused by liver diseases ď§ If a patient has gallstones ď removal of gall bladder ď no Vit K deficiency because bile is secreted from the liver and goes directly to the intestines; gall bladder is just a storage of bile ď§ When the common bile duct is cut ď bile will not be delivered ď§ If the common bile duct is accidentally cut during surgery, duodenum is attached to the liver so that there will be supply of bile ď§ In newborn, initially they don’t have intestinal bacterial flora ď Vit K injection is administered Hemophilia ď§ sex-linked disease: only manifested in males but from the chromosomes of female carriers ď§ 85%: absence of Factor VIII = HEMOPHILIA A or CLASSIC HEMOPHILIA ď§ 15%: absence of Factor IX ď§ Treatment: Recombinant Factor VIII Thrombocytopenia ď§ Presence of very low number of platelets in the circulating blood ď§ Treatment: fresh whole blood transfusion with large numbers of platelets and splenectomy B. Coagulation excess ď¨ Artherosclerotic plaque ď Hypertension (dec diameter of blood vessels) ď¨ Rupture in the lumen of blood vessels ď collagen is exposed ď abnormal thrombus formation ď myocardial infarction ď¨ Treatment: genetically-engineered T-PA ď dissolve intravascular clot 1. 2. Thrombus ď§ an abnormal clot that develops in a blood vessel Emboli ď§ freely flowing clots ď§ due to roughened endothelial surface of vessel 12 | C K R P ď§ ď§ ď§ ď§ ď§ ď§ ď§ 3. 4. o o o exemplified by formation of clot coming from the deep veins of the leg ď Pulmonary embolism left side of the heart ď Stroke due to slow blood flow ď clot forms and settles in the valves ď clot is thrown by the blood flow into distal areas ď Embolus ď goes up to block pulmonary capillaries ď PULMONARY EMBOLISM It usually occurs in capillaries rather that in arteries because of the small diameter of capillaries Theoretically (under normal condition), it is not possible to see a clot that originated from the deep vein of the leg go into the left side of the heart because once it has blocked the pulmonary capillaries it can no longer go on and proceed to the left side of the heart However it is still possible when there is communication between the chambers of the heart = Ventricular septal defect It is also possible in tetralogy of fallot wherein the right ventricular pressure is greater than the left; bidirectional flow ď Blood will flow from right to left Infarct ď§ tissue devoid of blood supply Disseminated Intravascular Coagulation clotting mechanism becomes activated in widespread areas of the circulation Sepsis ď§ Bacteria release toxins (endotoxins) ď activate blood clotting mechanisms ď§ Treatment: antibiotics Abruptio placenta ď§ If there is clot, plasmin will dissolve it ď placenta and bacteria will produce clot again ď it will be dissolved again by the placenta ď coagulation factors are already consumed ď CONSUMPTIVE coagulopathy ď§ Treatment: Antibiotic or removal of placenta ď Anticoagulants for clinical use: 1. Heparin o Mode of action: potentiates the action of antithrombin III o Heparin-antithrombin III complex blocks factors XII, XI, IX, X and II o Antidote: protamine sulphate o Action lasts for 1.5 to 4 hrs and then destroyed in the blood by HEPARINASE 2. Coumarin/ warfarin o Mechanism of action: blocks the action of vitamin K o Inactivates VCOR C1 ď Vit K will not be reduced back to its active form ď Coagulation factors will not be activated ď Blood coagulation tests 1. Bleeding time o pierce the tip of the finger or lobe of the ear o bleeding ordinarily lasts for 1 to 6 minutes o Prolonged bleeding time: Lack of any one of several of the clotting factors and lack of platelets. o Inaccurate because it is operator-dependent 13 | C K R P o TEST for QUALITY of PLATELETS: if platelets are of good quality, they will perform platelet plug formation ď bleeding will stop 2. Clotting time o Collect blood in a chemically clean glass test tube and then to tip the tube back and forth about every 30 seconds until the blood has clotted o time needed for blood to clot o NV: 6 - 10 minutes o test for clotting factors 3. Prothrombin time o test for quantity of prothrombin in the blood (E) o NV: 12 seconds 4. Partial thrombolastin time o Test the intrinsic pathway of coagulation God looks down from heaven on the entire human race to see if anyone is truly wise. And the truly wise person is the one who seeks Him. = Psalm 53:2= 14 | C K R P PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) I. Functions of the Blood 1. Keeps the internal environment of the body constant (Homeostasis) 2. Transport O2 from lungs to the tissues and CO2 from the tissues to the lungs (Respiratory) 3. Carries nutritive materials from intestines to all parts of the body (Nutritive) 4. Carries waste products of tissue metabolism to the kidneys (Excretory) 5. Transports Internal secretions from endocrine glands to the tissues on which the effects are exerted (Endocrinology) 6. Acid base balance maintenance 7. Water and electrolyte balance and total osmotic pressure regulation 8. Immunity to diseases 9. Body temperature regulation II. Normal Blood volume ďˇ Commonly: Males- 5 liters, Females- 4.5 liters ďˇ Composition: 60% Plasma, 40% Formed elements ďˇ Centrifuged: o Upper portion- Plasma o Buffy coat/ White substance- contains WBC and Platelets o Bottom – RBC, most dense III. Composition of Blood A. Plasma ďˇ Water: 91-92% ďˇ Plasma proteins o Albumin: responsible for maintaining osmotic pressure, transport of bilirubin and other drugs o Alpha Globulin & Beta Globulin: antibodies; some are transport proteins o Y- Globulin: immunoglobulins o Fibrinogen: participates in blood coagulation o Complement proteins: important inflammation & destruction of organisms ďˇ Blood sugar: Glucose ďˇ Lipids: Cholesterol, Phospholipids, Neutral fats ďˇ Salts: Na, K, Cl, HCO3, Phosphates ďˇ Gases: O2, CO2, Nitrogen ďˇ Special Plasma Substances: Hormones, Enzymes, Antibodies Functions of Plasma 1. Maintenance of Water balance between intravascular compartment and extravascular spaces (Proteins serves as solutes that maintains plasma inside blood vessel) Example: ↓Plasma proteins inside blood vessel = Higher PP in the interstitial space, Plasma will exit in the interstitial spaces (Osmosis) Clinical Correlation: Edema (due to depleted plasma proteins secondary to liver disease) Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 Lec 10 - 20 Aug 2015 2. 3. 4. 5. 6. 7. Contributes mainly in the Blood viscosity Source of Antibodies Necessary for coagulation Maintains acid-base balance Determines specific gravity of plasma Formation of enzymes; transport hormones and enzymes of B. Buffy Coat ďˇ Thin gray- white layer between plasma and hematocrit ďˇ Makes up 1 % of blood sample ďˇ Leukocytes and platelets C. Serum ďˇ Liquid portion of clotted blood ďˇ Contains growth factors and other proteins released from platelets D. Formed Elements ďˇ RBCs (Erythrocytes) ďˇ WBCs (Leukocytes) ďˇ Platelets ( Thromobocytes) o Came from same pluripotent hematopoietic stem cell ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ IV. Erythrocytes (RBC) 50% protein , 40 % lipids, 10 % carbohydrates Biconcave, non- nucleated, not spherical, 2.5um thick, 7.58um in diameter, 0.74 thick at center Pliable/very deformable Carries hemoglobin (Hgb) in the circulation (primary function) o 1gm of Hgb →1.34 ml of O2 Non-nucleated in the circulating blood o RBC Count 12 1. Men: 5-6 x 10 /L 12 2. Women: 4-5 x10 /L 12 3. Infants: 6.5x10 /L o Hgb Normal Values 1. Men- 14 to 17g/dl 2. Women- 12 to 15 g/dl o Hematocrit (Hct) Normal Values 1. Men- 0.40 to 0.50 2. Women- 0.38 to 0.48 Anemia: Any value lower than normal limit of RBC and Hgb Polycythemia: Any value higher than limit of RBC and Hgb RBC Formation ďˇ Genesis of red blood cells in various parts of the body as a person progresses through different life stages ďˇ Extramedullary hematopoiesis o The body attempts to maintain erythrogenesis in response to an alteration in the normal production of RBC Page 1 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) ďˇ Table 1. Red cell production Stage Of Life Organ Responsible For Red Cell Production 8 weeks of embryonic life or first 2 months Yolk sac (primitive ad nucleated RBC are produced) Middle trimester of pregnancy Liver- main organ for production of RBC Spleen Lymph node rd 3 trimester of pregnancy and after birth Bone marrow takes over 20 years and above Vertebrae, ribs, sternum, ilia, bone marrow of the skull Figure 1. Relative rate od RBC prod in bone marrows at different ages. ďˇ ďˇ ďˇ Lec 10 - 20 Aug 2015 Pluripotential hematopoietic stem cell o all the cells of the circulating blood are eventually derived Proerythroblast o committed stem cell to become RBC Basophil erythroblast o “first generation cells” o Contains basic dyes Reticulocyte o first cell to release in the circulation o After 2 days the cytoplasmic materials are gone and mature non-nucleated erythrocytes are produced. o During this stage the cell pass from the bone marrow into the blood capillaries by diapedesis. ďˇ Erythrocyte o no nucleus ď nucleus extruded ďˇ Erythropoiesis o process of red cell production RBC Maturation ďˇ Vitamin B12 and Folic Acid (Pteroylglutamic Acid) o Important for final maturation of RBC o essential for the synthesis of DNA(required for the formation of thymidine triphosphate) o Lack of VitB12 and Folic acid 1. abnormal DNA 2. failure of nuclear maturation and cell division 3. erythropoiesis proceeds slowly 4. macrocytes 5. structural abnormalities ďˇ Pernicious Anemia o Poor absorption of Vit B12 in the GI Tract o Atrophic mucosa that fails to produce normal gastric secretion o Lack of intrinsic factor Absence of IF ď malabsorption of B12 ď B12 deficiency ď Pernicious Anemia ď Megaloblastic Anemia ďˇ Sprue o ď˘ intestinal absorption of folic acid and vitamin B12 Control Of Red Cell Production 1. Stimulation by Hypoxia ď§ anemia ď§ ↓ Blood flow ď§ Poor blood flow ď§ ↓ Altitude ď§ Pulmonary diseases 2. Inhibition by rise in circulating RBCs 3. Control by circulating hormone called erythropoietin ď§ Synthesized by both kidneys (90%) and liver (10%) ď§ principal stimulus for RBC production ď§ increases production of proerythroblast Figure 2. Stages in RBC formation. Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 Page 2 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) Ensures an adequate number of red cells is always available to provide sufficient transport of oxygen Cells must not become too numerous that they impede blood flow ďˇ ďˇ ďˇ ďˇ Example: ďˇ Living in high altitudes where oxygen is not as abundant as in low lands ď more RBC is produced ďˇ Patients with TB have normal blood levels and oxygen levels in blood but suffer from impaired oxygen absorption in the lungs. Thus, the body triggered to produce more blood Note: Tissue Oxygenation—most essential regulator of RBC production ďˇ ď§ ď§ RBC Destruction ďˇ Life Span: 120 days ďˇ Destruction: 1% red cells replaced daily o Total red cell volume replaced every 4 months ďˇ Site of destruction: Spleen ďˇ Hypertonic solution: causes shrinkage of RBC ďˇ Hypotonic solution- causes swelling and rupturing ďˇ Isotonic solution- no change; equilibrium; 0.9% NaCl, 5% Dextrose Lec 10 - 20 Aug 2015 15-30% in the form of ferritin (storage form in the liver) 4% in the form of myoglobin (hemoglobin in the muscle) 1% other heme compounds Primary source is from the diet: Organ meat, Red meat, Oysters Diet: 1mg of Fe/day Figure 4. Absorption of Iron from GIT ďˇ ďˇ Formation of Hgb ďˇ ďˇ Liver secretes apotransferrin into the bile, which flows through the bile duct into the duodenum. In the Duodenum apotransferrin binds with Iron to form transferrin and is released into the blood Apotransferrin from the liver combines with in the small intestine and they are usually absorbed in the duodenum. Cases: o Iron Replete ď§ Person has plenty of Iron in the blood (Iron is stored in the intestinal mucosa) o Hemoglobin content is Depleted or Person is anemic ď§ Iron is immediately combined to form transferrin and transferrin readily donates Iron to form hemoglobin o Iron supplementation ď§ only needed by persons who need it ex. Anemic Women are prone to Fe deficiency anemia due to menstruation Elimination of Iron Figure 3. Hemoglobin formation. ďˇ ďˇ The primary function of red blood cells is to transport Hgb which in turn carries oxygen from the lungs to the tissues and the carbon dioxide back from the tissues to the lungs There are 4 iron molecule in 1 Hemoglobin (2 beta, 2 alpha) Iron ďˇ ďˇ ďˇ ďˇ Essential for the formation of hemoglobin and other essential elements There are 4 Fe in one adult Hemoglobin Approximately 4-6 grams in the human body Majority is in the form of hemoglobin (65% or 2/3) Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 ďˇ ďˇ Only 1mg of Iron is eliminated per day Elimination via: o Stool: trace amounts are lost in the bile o Urine o Sweat o Menstruation Clinical Correlations ďˇ Underproduction/ Over Desctruction of RBC= Anemia ďˇ Over production of RBC= Polycytemia ďˇ A person found in the emergency room complains of difficulty in breathing presents with severe palor (anemia) Page 3 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) o For you to correct the anemia you have to find the cause o Physician will usually request a peripheral blood smear (PBS) Results: o Iron Deficiency= RBC’s are Microcytic Hypochromic o Vit. B12/ Folic Acid Deficiency= RBC’s are Macrocytic Hyperchromic Anemia ďˇ Deficiency of RBC ďˇ Too rapid loss/ slow production of RBC ďˇ Blood loss/ Fe deficiency 1. Aplastic Anemia ďˇ Bone marrow disorder (Cannot produce blood cells) 2. Megaloblastic Anemia ďˇ Macrocytic and Hyperchromatic (Vit. B12 & Folic acid Deficiency) ďˇ Pernicious Anemia o condition characterized by absence of parietal glands in the stomach, which is needed for the secretion of Intrinsic Factors (IF helps in the absorption of Vit. B12) ďˇ Sprue o due to decrease intestinal absorption/ malabsorption of Folic Acid and Vit. B12 3. Hemolytic Anemia ďˇ RBC’s rupture prematurely ďˇ Hereditary Spherocytosis o RBC’s are spherical because SodiumPotassium Pump is not functioning. + + + o Function of Na -K Pump is to bring Na out of the cell’s membrane. In Hereditary + Spherocytosis Na stays inside the cell causing more water to go into the cell, causing the spherical shape of the cell. 4. Sickle Cell Anemia ďˇ RBC’s are sickle shaped ďˇ Abnormal type of hemoglobin: Hemoglobin S ďˇ Prone to hemolysis Effects of Anemia on Circulatory System 1. Decreased viscosity of blood; Decreased resistance = rapid blood flow 2. Hypoxia; Vasodilation of Blood Vessels=more blood goes to the heart 3. Will cause increased heart rate/ increased workload on the heart Note: ďˇ Younger individuals can tolerate anemia ďˇ Older individuals (60-70) should not be left without treatment because anemia may cause cardiac arrest to individuals with weaker hearts. Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 Lec 10 - 20 Aug 2015 Polycythemia ďˇ Over Production of RBC o Second Degree Polycythemia ď§ Normal individual but situation dictates to produce more RBC ď§ Ex: Living in high altitudes, smoking, having pulmonary diseases o Polycythemia Vera ď§ genetic aberration ď§ No inhibition of erythropoietin ď§ No inhibition of hemoglobin production ď§ Increase in RBC does not inhibit production 3 ď§ Blood count: 7to 8 Million/mm ď§ Blood viscosity is increased; resistance is increases= sluggish blood flow ď§ Prone to clotting ď§ Decreased heart workload ď§ Treated by frequent Phlebotomy (Removal of 500cc of blood every other month) A. V. The ABO System Inheritance of the ABO Blood groups ďˇ An individual inherits one ABO gene from each parent and that these two genes determine which ABO antigens are present on the RBC membrane ďˇ ABO is codominant in expression ďˇ O gene is considered a silent gene or an amorph as no detectable antigen is produced in response to inheritance of these gene ďˇ An individual who has a phenotype A can have a genotype AA or AO. An individual who has a phenotype B can have a genotype BB or BO. In case of O individual, both phenotype and genotype are the same (OO) because that individual would have to be homozygous for the O gene. The phenotype and genotype are also the same in an AB individual because of the inheritance of both A and B gene. (Harmening, 2005) Figure 4. Blood type Punnett Square for offspring Page 4 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) Lec 10 - 20 Aug 2015 VI. Blood Typing / Blood Matching B. ABO Antibodies – Agglutinins ďˇ Present in serum/plasma ďˇ naturally occuring antibodies directed against A and/or B antigen(s) absent from their RBCs. ďˇ Predominantly IgM ďˇ Titer: at birth, quantity of agglutinins are almost zero. An infant begins to produce agglutins 2-8 months after birth. Maximum titer is usually reached at 8-10 years of age and gradually declines throughout the remaining years of life. (Guyton, 2016) C. A and B Antigens – Agglutinogens ďˇ present on the surfaces of RBCs ďˇ Two antigens (type A and type B) are present on the surfaces of RBCs (Guyton, 2016) ďˇ Often cause blood cell agglutination Procedure 1. RBCs are first separated from the plasma and diluted with saline solution 2. One portion is then mixed with anti-A agglutinin and another portion with anti-B agglutinin 3. After several minutes, mixtures are observed under a microscope. 4. Results: Positive Result: With agglutination; RBCs have become clumped= Ab-Ag reaction has resulted Negative Result: without agglutination; homogenous mixture (macroscopically) Figure 6. Positive demonstrations. ďˇ Figure 5. ABO Blood System Antigens and Antibodies. Table 2. ABO antigens and antibodies. BLOOD TYPE A B AB O Note: ďˇ ďˇ ďˇ Agglutinogen Agglutinin (Antigen) (Antibody) present in Red present in Cell Plasma A Anti – B B Anti – A AB none UNIVERSAL RECIPIENT none Anti - A, Anti-B UNIVERSAL DONOR and negative (L) Agglutination Direct/Forward Blood Typing o known anti-A and anti-B typing antiserums for testing unknown RBCs o Patient RBCs mixed with commercial antisera A and B Indirect/Reverse Blood Typing o Patient serum is mixed with blood that is known to be either type A or B and observed for agglutination reaction Table 3. Reactions in DIRECT/FORWARD blood typing Blood Type Anti – A Sera Anti – B Sera A + + - + + - B AB O In the RBC surface: Antigen(s) is/are present which determines the individual’s blood type In plasma/serum: Antiboby is present which is directed against the antigen present in the RBC surface. ďˇ ďˇ Galolo, Matias, Viacrusis, Zaragoza (R) MD-1C 2019 Errors in blood transfusion may result in: 1. Agglutination 2. Hemolysis - destruction of RBC membrane by phagocytes and antibodies 3. Renal shutdown High-standard precautions exist to prevent errors in blood transfusion since even marginal errors may prove to be fatal for the patient receiving the blood. Page 5 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) Lec 10 - 20 Aug 2015 Formation of Anti-Rh Agglutinins Donor Rh (+) 1. 2. 3. Recipient Rh (-) Recipient (+) anti-Rh in 2-4 months Donor’s blood containing Rh factor is injected into a person whose blood does not contain the Rh factor. Anti-Rh agglutinins develops slowly on recipient’s blood, reaching maximum concentration of agglutinins about 2-4 months later. Rh-negative individual eventually becomes strongly “sensitized” to Rh factor Erythroblastosis Fetalis ďˇ Hemolytic disease of the Newborn (HDN) ďˇ Disease of the fetus and newborn child characterized by agglutination and phagocytosis of the fetus’s RBCs Baby’s blood Rh (+) Mother’s blood Rh (-) Anti-Rh IgG’s ATTACK ďˇ Figure 7. Results in direct or forward blood typing ďˇ ďˇ VII. The Rh System Primary cause of hemolytic disease of the newborn, also known as Erythroblastosis fetalis and significant cause of hemolytic transfusion reactions (Harmening, 2005 Rh Antigens o Six (6) common types of Rh antigens called Rh factor C, D, E, c, d, e o ďˇ A person with C antigen does not have c antigen (same with D-d and E-e antigens) o Each person has one of each of the three pairs of antigens o D antigen – more antigenic than the other Rh antigens o Rh positive: individual with D antigen o Rh negative: without D antigen Rh Antibodies ďˇ IgG in nature, can cross the placenta ďˇ Produced following exposure of the individual’s immune system to foreign RBCs, through either transfusion or or pregnancy. ďˇ Highly immunogenic D > c > E >C > e Note: Immunogenicity of common Rh antigens; D is the most potent Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 This occurs when o Mother: Rh negative o Father: Rh positive o Child: Rh positive 1. Baby’s blood (which is Rh positive) mixes with the mother’s blood (Rh negative) 2. Mother will be sensitized, producing anti-Rh antibodies 3. Anti-Rh Abs (which are IgG in nature) will diffuse through the placenta into the fetus and cause HDN Clinical picture of HDN/ Erythroblastosis fetalis ďˇ Anemic at birth ďˇ Liver and spleen become greatly enlarged ďˇ Presence of nucleated blastic forms of RBCs in peripheral blood smear (thus the name erythroblastosis felatis) ďˇ Kernicterus – permanent mental impairment because of precipitation of bilirubin in the neuronal cells Management of Rh incompatibility 1. Exchange Transfusion ďˇ Rh (+) antibodies present in blood are removed during birth, then replaced with Rh (-) blood to stop interaction of antibodies with Rh (+) cells ďˇ Baby is allowed to produce its own Rh (+) antibodies 2. Administration of Rho-gam ( Rh immunoglobulin) ďˇ Anti-D antibody that is administered to the expectant mother starting at 28 to 30 weeks of gestation. ďˇ Also administered in Rh negative women who deliver Rh positive babies to prevent sensitization of the mother to D antigen. Page 6 of 7 PHYSIOLOGY – A Blood Physiology pt. 1 Dr. Joseph U. Olivar (JUO) Table 4. Summary of the difference between ABO system and Rh System ABO Mostly IgM Antibodies are naturally occuring Rh IgG Person must first be massively exposed to an Rh antigen to cause a significant transfusion reaction to develop Plasma agglutinins responsible for causing transfusion reactions develop spontaneously Spontaneous agglutinins almost never occur Table 5. Differences between ABO and Rh HDN ABO HDN Mother: Type O Father: Type A/B/AB Child: Type A or B First pregnancy is affected Destruction of fetal RBCs leading to severe anemia is rare Bilirubin at birth is in normal range Rh HDN Mother: Rh negative Father: Rh positive Child: Rh positive First born infant is unaffected because the mother has not yet been immunized; succeding children are affected (if rhogam is not administered during the first pregnancy) Anemia is common Bilirubin at birth is elevated ** In case the mother is Rh positive and baby is Rh negative, the baby and the mother are unaffected because no reaction will occur. The baby cannot produce antibody during this stage. Blood Compatibility ďˇ Present in Red Cell: antigen ďˇ Present in Serum: antibody Major Crossmatch ďˇ PSDR: Patient’s Serum + Donor’s Red Cells Minor Crossmatch ďˇ PRDS: Patient’s Red Cells + Donor’s Serum VIII. Transfusion Sample Cases Case 1: Type B patient x Type A donor ďˇ Present in patient RBC: B antigen ďˇ Present in patient serum: Anti-A ďˇ Present in donor RBC: A antigen ďˇ Present in donor serum: Anti-B Galolo, Matias, Viacrusis, Zaragoza MD-1C 2019 ď Lec 10 - 20 Aug 2015 Major Crossmatch: PSDR: Anti-A Ab in serum of patient + A Ag in red cell of Donor Result: (+) Agglutination = incompatible Minor Crossmatch: PRDS: B Ag in red cell of patient + Anti-B Ab in serum of donor Result: (+) Agglutination = incompatible In case 1, the blood types are incompatible. Do not proceed with the transfusion. Case 2: Type B patient x Type O donor ďˇ Present in patient RBC: B antigen ďˇ Present in patient serum: Anti-A ďˇ Present in donor RBC: none ďˇ Present in donor serum: Anti-A and Anti-B Major Crossmatch: PSDR: Anti-A Ab in serum of patient + No Ag in red cell of Donor Result: (-) Agglutination = compatible Minor Crossmatch: PRDS: B Ag in red cell of patient + Anti-A and Anti-B Abs in serum of donor Result: (+) Agglutination = incompatible ď In Case 2, you may proceed with transfusion. Patient may suffer slight itchiness as reaction to small amounts of antibodies from donor cell, which will easily be diluted in patient’s serum. Type O is the universal donor. Case 3: Type AB patient x Type A donor ďˇ Present in patient RBC: A and B antigens ďˇ Present in patient serum: none ďˇ Present in donor RBC: A antigen ďˇ Present in donor serum: Anti-B Major Crossmatch: PSDR: No Abs in serum of patient + A Ag in red cell of Donor Result: (-) Agglutination = compatible Minor Crossmatch: PRDS: A and B Ags in red cell of patient + Anti-B Ab in serum of donor Result: (+) Agglutination = incompatible ď In Case 3, you may proceed with transfusion. you may proceed with transfusion. Patient may suffer slight itchiness as reaction to small amounts of antibodies from donor cell, which will easily be diluted in patient’s serum. Type AB is the universal recipient. REFERENCES Old transes Hall, J. E., & Guyton, A. C. (2011). Blood cells, Immunity and Blood coagulation. Guyton and Hall textbook of medical physiology., PPT by Dr. Olivar Harmening, Modern Blood Bank and Transfusion practice. Laboratory Manual and Lecture guide in Physiology (20122013). Page 7 of 7 BLOOD (PLATELETS) Dr. Olivar PLATELETS (THROMBOCYTES) -just like RBC, the main sources of platelets are the Pluripotent Hematopoietic Stem Cell (PHSC) in the bone marrow. -The precursor of platelets is called MEGAKARYOCYTES. -very big cells which fragments to minute platelets. PLATELETS -DESCRIPTION: small, non-nucleated, colorless bodies -main function: to achieve hemostasis -Size: 1-4 um. -Normal Values: 150,000 – 300,000 ↓ = Thrombocytopenia (more important) -decreased platelets = abnormal bleeding -ex: Dengue ↑ = Thrombocytosis FUNCTIONS: Hemostasis 1. Releases thromboxane A2 ď LOCAL VASOCONSTRICTION 2. Formation of PLATELET PLUG 3. Participates in BLOOD COAGULATION 4. Clot Retraction (by secreting “Thrombosthenin") HEMOSTASIS –prevention of blood loss 3 Mechanisms: ď§ LOCAL VASOCONSTRICITON -a reflex response from local myogenic contraction of the blood vessel -1st line in hemostasis -to prevent blood loss *PLEASE REMEMBER* Substances released by PLATELETS aiding in local vasoconstriction: a. Thromboxane A2 b. Serotonin * the 2 substances that helps the blood vessels to constrict in the 1 st line of hemostasis c. Factor 13: Fibrin Stabilizing Factor (FSF) ď§ PLATELET PLUG FORMATION Damaged vascular surface (exposed collagen from endothelium) ↓ Platelets are attracted to the area ↓ Platelets swell, grow pseudopods, sticky, forms thromboxane A2 ↓ PLATELET PLUG FORMATION -important in controlling/closing numerous minute fractures in many small blood vessels that may occur many times daily -They don’t have enough platelets that can perform the function of platelet plug formation. ď§ BLOOD COAGULATION -3rd mechanism for hemostasis -GOAL: to form a CLOT Mechanism of Coagulation 3 Essential Steps: 1. The formation of PROTHROMBIN-CONVERTING ENZYME or prothrombin activator -readily converts prothrombin to thrombin -(*RATE-LIMITING STEP*; PROTHROMBIN ACTIVATOR is the RATE LIMITING ENZYME) -once formed, Step 2,3 will automatically occur ď fibrin (clot) -with the help of CALCIUM and PLATELET PHOSPHOLIPIDS ď Step2 2. The conversion of PROTHROMBIN to THROMBIN by this agent. -thrombin readily converts fibrinogen to fibrin 3. The conversion of FIBRINOGEN to FIBRIN clots thru the action of THROMBIN. PROTHROMBIN ACTIVATOR is generated ↓ Prothrombin is readily converted to thrombin under the help of calcium and platelet phospholipid ↓ Thrombin once generated, will convert fibrinogen to fibrin * the first fibrin generated from this reaction is just a fibrin monomer (not a stable clot) ↓ The fibrin monomer must polymerize as fibrin polymer through FIBRIN STABILIZING FACTOR (Factor XIII) -released by platelet -activated by thrombin ↓ Once polymerized, it forms CLOT (composed of fibrin polymers running in all directions trapping within RBC’s, PLATELETS and PLASMA) ↓ STOP BLEEDING -IDIOPATHIC THROMBOCYTOPENIC PURPURA (ITP): decreased platelet counts -Manifestations: multiple lesions/hemorrhages -Petechiae (smaller) -Purpura (bigger) 1 BLOOD (PLATELETS) Dr. Olivar CLOTTING FACTORS IN THE BLOOD AND THEIR SYNONYMS CLOTTING SYNONYMS FACTOR Factor I Fibrinogen Factor II Prothrombin Factor III Tissue Factor, Thromboplastin Factor IV Calcium Proaccelerin, Labile Factor, Ac-globulin Factor V (Ac-G) Serum prothrombin conversion Factor VII accelerator (SPCA), Proconvertin, Stable Factor Antihemophilic factor A, Antihemophilic Factor VIII factor (AHF); antihemophilic globulin (AHG) Antihemophilic factor B, Plasma Factor IX thromboplastin component (PTC), Christmas factor Factor X Stuart-Power Factor Antihemophilic factor C, Plasma Factor XI thromboplastin antecedent (PTA) Factor XII Hageman Factor, Contact Factor Factor XIII Fibrin Stabilizing Factor (FSF) Prekallikrein Fletcher Factor Fitzgerald Factor, HMWK (high-molecularHMMK weight kininogen) platelet *MEMORIZE! *NO FACTOR VI -these coagulation factors are plasma proteins; they are synthesized mostly in the liver. -they exist in blood vessel (plasma) in INACTIVE FORM. -whenever the vessel is damaged, and one of the factors is stimulated, they are converted to ACTIVE ENZYMES ď eventually forms the clot by converting fibrinogen to fibrin ď§ EVENTUAL GROWTH OF FIBROUS TISSUE INTO THE BLOOD CLOT TO CLOSE THE HOLE IN THE VESSEL PERMANENTLY INITIATION OF THE CLOTTING PROCESS ď§ Trauma to the vascular wall and adjacent tissues (EXTRINSIC) ď§ Contact of the blood with damaged endothelial cells/ collagen (INTRINSIC) ď§ Trauma to the blood (INTRINSIC) * EXTRINSIC and INTRINSIC pathways generate the PROTHROMBIN ACTIVATOR. EXTRINSIC PATHWAY Stimulated by trauma to the vascular wall and adjacent tissues ↓ Starts with the release of Factor 3 (Tissue Factor/ Thromboplastin) combines with Factor7 ↓ F3 + F7 = activates Factor 10 to ACTIVATED FACTOR 10A ↓ Activated F10A converts Prothrombin to Thrombin ↓ Thrombin converts Fibrinogen to Fibrin ↓ Hence, the PROTHROMBIN ACTIVATOR is ACTIVATED FACTOR 10A ↓ FACTOR 5 accelerates the action of activated Factor 10A in converting Prothrombin to Thrombin * The action of F5 is possible if it is stimulated by THROMBIN - significance: the extrinsic pathway to begin with is very slow until the first thrombin is generated ↓ once generated, it activates F5 ↓ action of prothrombin activator is enhanced (factor 10) ď§ ď§ Extrinsic pathway only makes two factors: Factor3 and Factor7 to generate the prothrombin activator. Extrinsic factor is short because tissue trauma is the one stimulating this. 2 BLOOD (PLATELETS) Dr. Olivar INTRINSIC PATHWAY *When blood is placed in these test tubes, the blood will not clot because Ca++ is removed. Without Ca++, both extrinsic and intrinsic pathways will not occur. ď NO CLOT FORMATION. *Purpose of ANTI-COAGULANTS. REVIEW/OVERVIEW: PLATELETS. FUNCTIONS: Hemostasis 1. LOCAL VASOCONSTRICTION 2. Formation of PLATELET PLUG 3. Participates in BLOOD COAGULATION 4. Clot Retraction (by secreting “Thrombosthenin") ď§ It is stimulated by contact of the blood with damaged endothelial cells/ collagen; trauma to the blood ↓ Starts with Factor12 ↓ Activates Factor11 ↓ Activates Factor9 ↓ Activated F9 + Activated F8 = converts F10 to Activated Factor10A ↓ Again, Activated Factor10A is the Prothrombin Activator HEMOPHILIA ď§ Lacks FACTOR8. ď§ Without F8, nothing can combine with F9 ď cannot convert F10 to Activated F10A. ď§ Makes them prone to bleeding. BOTH IN EXTRINSIC AND INTRINSIC PATHWAY, CALCIUM AND PLATELETS ARE INVOLVED IN THE REACTION. ď§ Even if the coagulation factors are complete, WITHOUT CALCIUM AND PLATELETS, the coagulation pathways will NOT OCCUR or will be impaired ď bleeding ď§ It is rare to decrease the Calcium level in the blood. However, we can remove the Calcium from the blood by placing it in a tube with anticoagulant. ďˇ BLUE TOP: contains CITRATE - de-ionizes Calcium ďˇ GRAY TOP: contains OXALATE – precipitates Calcium CLOT RETRACTION -4th function of platelets. -Serum When blood is placed in a tube that does not contain an anticoagulant, soon it will clot. After sometime, the clot will retract and it will extrude the serum. ↓ The blood clot that retracted, all coagulation factors are included. Serum has no coagulation factor. ďˇ ďˇ ďˇ ďˇ Clot retraction is a function of platelets because platelets secrete a substance called THROMBOSTHENIN. Platelets also have actin and myosin causing the platelets to contract. When the clot retracts, the serum is extruded and all the coagulation factors are in that clot. The SERUM CANNOT CLOT because the clotting factors are all trapped in the clot. COMPARED WITH PLASMA If plasma is placed in a tube with anti-coagulant and placed in a centrifuge, plasma will separate with RBC’s. ↓ Plasma contains coagulation factors, plasma can CLOT. * SERUM cannot clot; produced by putting in a plain tube * PLASMA can clot; produced if the blood is anticoagulated 3 BLOOD (PLATELETS) Dr. Olivar “As the clot retracts, the edges of the broken blood vessel are pulled together, thus contributing still further to hemostasis.” When clot is formed – no bleeding; but vessel is still damaged ↓ Clot needs to retract so the edges will be pulled together to reepithelialize = purpose of Clot Retraction = function of Platelets ↓ Purpose of clot in a damaged vessel: PREVENT BLOOD LOSS Purpose of clot in a repaired vessel: NONE ↓ CLOT SHOULD BE LYSED ď§ LYSIS OF BLOOD CLOT INTRAVASCULAR ANTICOAGULANTS: 1. Endothelial Surface Factors ďˇ Because the endothelium of blood vessels is smooth due to the layer of glycocalyx, there is no clotting because the clotting factors are repelled by the glycocalyx. Thrombin in the circulation ↓ Function of Thrombomodulin: binds to any Thrombin that is circulating ď inactivates thrombin Thrombomodulin + Thrombin = Protein C (another anticoagulant) ď deactivates Factor5, Factor8 * When blood vessels are smooth, it will not clot because it will repel the coagulation factors Plasminogen (INACTIVE in plasma) ↓ Once the vessel has repaired itself, t-PA is released by the damaged endothelial cells converting plasminogen to PLASMIN ↓ Plasmin will dissolve the clot *When the smoothness of the endothelium is damaged, the glycocalyx and thrombomodulin factors are negated, thus clot occurs * Once collagen is exposed, it stimulates Intrinsic Pathway beginning with Factor12 ď forms thrombus 2. Anti-thrombin action of fibrin and anti-thrombin III ďˇ FIBRIN itself deactivates the THROMBIN formed. ďˇ Anti-thrombin III, together with Heparin = causes the blood not to clot. FUNCTIONS OF PLASMIN: ď§ Digest fibrin fibers ď§ Digest fibrinogen, Factor 5, 8, 12 and prothrombin 3. Heparin *PLASMIN dissolves the clot *t-PA only accelerates the conversion of plasminogen to plasmin 1. PURPOSE OF PLASMIN: ď§ to dissolve the fibrin fibers including coagulation factors ď§ to remove clots from the vessels Tissue Plasminogen Activator: ex. Streptokinase, Urokinase o CASE: Heart attack - cause: clot develops in major coronary supply of the heart ď blocks the blood flow - if given with Streptokinase ď immediately converts plasminogen to plasmin ď plasmin will dissolve the clot ď re-establish blood flow COAGULATION DISORDERS: COAGULATION DEFICIENCY- bleeding a. Bleeding caused by Vitamin K deficiency VITAMIN K: continuously synthesized by the normal flora in the intestine. ď§ Factors 9, 10, 7, 2 = dependent on VitK for them to be produced ď§ Protein C “to remove the clots from the vessels that eventually would become occluded where there is no way to clean them.” ď§ ď§ Clotting does not occur normally because of the presence of intravascular anti-coagulants. In normal conditions (blood vessels are not damaged, anticoagulants pre-dominate more than pro-coagulants. Liver produces plasma proteins or the coagulation factors. But for Factors 9,10,7,2 to be activated, LIVER CARBOXYLASE enzyme uses VitaminK. ONCE the factors ACTIVATED, VITAMIN K is oxidized and rendered NON-FUNCTIONAL. 4 BLOOD (PLATELETS) Dr. Olivar Vitamin K Epoxide Reductase Complex1 (VCOR c1) reduces back VitK to its functional form. ď§ ď§ ATHEROSCLEROTIC PLAQUE -accumulation of cholesterol crystals beneath the intimal layer of the blood vessel. VitK is a fat-soluble vitamin ď§ For it to be absorbed, it has to be absorbed with fat ď§ To absorb fat, bile is needed from the liver ď§ NO bile ď NO fat absorption ď NO vitK absorption -Manifestations: Hypertension – because the blood vessel diameter is decreased. -Danger: atherosclerosis can rupture ↓ breaks into the lumen of the blood vessel ↓ collagen is exposes ↓ stimulates Intrinsic Pathway (F12) ↓ formation of clot ↓ blocks blood flow ↓ infracted tissue CAUSES OF VITAMIN K DEFICIENCY: ď§ Liver diseases - cannot synthesize plasma proteins - cannot secrete bile ď cannot absorb fat ď cannot absorb vitK ď§ ď§ Seen among newborns - GIT is still sterile - 1st: dry the baby; 2nd: inject vitK - to prevent intracerebral hemorrhage among newborns b. Hemophilia - lacks Factor8 (85%); Factor9 (15%) - Male ONLY; sex-linked disease - Disease resides in the X-chromosome - FEMALE are never affected because they have two (XX); the other X can compensate; CARRIERS ONLY - MALE offspring are affected because they only have one (XY); once affected, patient manifest hemophilia - TREATMENT: give RECOMBINANT FACTOR8 (very expensive) c. 2. Blockage in the production of bile - If gall bladder is removed, there will be NO bleeding problems because LIVER is the one producing BILE - Problems in bleeding will only arise if common hepatic duct is cut ď bile cannot flow to the intestine ď no fat absorption ď no vitK absorption ď bleeding problems. Thrombocytopenia COAGULATION EXCESS- abnormal clotting a. Thrombus: an abnormal clot that develops in a blood vessel -When clots are carried away by the blood flow ď embolus b. Emboli: freely flowing clots -blocks blood flow; tissue is devoid of blood flow ď infarcted c. Infarct: tissue devoid of blood supply Blood Vessel Layers: - Tunica Intima: location of atherosclerotic plaque- SUB-INTIMAL layer - Tunica Media - Tunica Adventitia ď§ EMBOLISM - exemplified by a clot developing on the deep veins of the leg - accumulation of thrombus can be carried away by the blood ď embolus - travels up to the main vessels ď inferior vena cava ď lungs ď PULMONARY EMBOLISM - usual origin of pulmonary embolism: DEEP VEINS of the legs - it will lodge on the PULMONARY CAPILLARIES because the vessels are VERY SMALL - after OR, early ambulation is necessary because tasis of blood can cause formation of clots * Any clot originating from the deep vein of the legs, is it possible to see the clot on the left side of the heart? - in normal conditions: No, because clot will just be stuck in the pulmonary artery - in Tetralogy of Fallot: Yes, there is reversal of flow; R ventricular pressure is greater than the L ventricle - in Atrial Fibrillation: spontaneously a clot can be developed in the mitral valve Activated Factor10A that can be stimulated by intrinsic and extrinsic pathway ↓ Both pathways can activate the prothrombin activator ↓ Cleaves factor2 to thrombin ↓ Cleaves factor1 to fibrin ↓ st 1 result is a fibrin monomer; must polymerize to become a stable clot which is brought about by factor13 ↓ Fibrin polymers trap within are RBC, platelets, plasma ↓ The clot formed in the mitral valve can be thrown again as an embolus ↓ CEREBRAL VESSELS most common cause of stroke 5 BLOOD (PLATELETS) Dr. Olivar * Deep vein ď Pulmunory embolism * Left side of the heart ď Stroke ď§ 2. DISSEMINATED INTRAVASCULAR COAGULATION - a clotting mechanism which becomes activated in widespread areas of the circulation - CAUSES: a. Sepsis - cause: bacterial toxins - when there is overwhelming infection, the toxins generated by the bacteria can stimulate the clotting mechanism ď clotting widespread in the circulation - TREATMENT: massive antibiotics b. Abruptio placenta - premature detachment of placenta - placenta is a tissue; a good source of “Tissue Factor” or Factor3 which can stimulates Extrinsic Pathway ď D.I.C. - Pathophysiology: widespread stimulation of the coagulation pathway which will produce clots in the circulation ↓ body will sense it and produce massive PLASMIN (fibrinolysin) to lyse the clot ↓ but since the placenta is still present, it will generate another widespread clotting ↓ plasmin will lyse again (VISCIOUS CYCLE of clot-lysis) ↓ until coagulation factors are already consumed ↓ results to bleeding = D.I.C. aka “CONSUMPTIVE COAGULOPATHY” -TREATMENT: - remove the PLACENTA - supportive transfusions: (coagulation factors in the form of:) fresh frozen plasma, cryoprecipitate - anti-coagulants must NOT be given in DIC because giving of anti-coagulants will accelerate death due to bleeding ANTI-COAGULANTS FOR CLINICAL USE 1. HEPARIN - produced naturally by basophils - MODE OF ACTION: potentiates the action of ANTITHROMBIN III - in itself is not a good anti-coagulant; if combined with naturally-occurring ANTI-THROMBIN III (Heparin-Antithrombin Complex) ď blocks FACTORS 12, 11, 9, 10, 2 - ANTIDOTE: PROTAMINE SULFATE COUMADIN/ WARFARIN -MODE OF ACTION: block the action of Vitamin K Blocks the action of VCOR c1 enzyme ↓ Vitamin K will not be reduced back to its functional form ↓ NO VitK = NO coagulation factors will be produced BLOOD COAGULATION TESTS: to assess the coagulation competency of an individual. 1. BLEEDING TIME - fingertip is pricked - time bleeding lasts (when the bleeding will stop) - Normal Value: 1-6 minutes - Operator-dependent; this method was abandoned; no longer used * TEST for QUALITY of PLATELETS: if platelets are of good quality, they will perform platelet plug formation ď bleeding will stop * TEST for QUANTITY of PLATELETS: Platelet Count (CBC) 2. CLOTTING TIME - putting blood in a non-anticoagulated test tube (plain tube) - time needed for blood to clot is assessed - Normal Value: 6-10 minutes *TEST FOR CLOTTING FACTORS 3. PROTHROMBIN TIME (PT) - TEST for QUANTITY of PROTHROMBIN in the blood (EXTRINSIC PATHWAY) - Normal Value: 12 seconds [PET] 4. PARTIAL THROMBOPLASTIN TIME (PTT) - TESTS the INTRINSIC PATHWAY of coagulation [PITT] 6 PHYSIOLOGY – A Blood Physio pt. 2 ďˇ ďˇ ďˇ Dr. Joseph U. Olivar (JUO) I. Platelets (Thrombocytes) Platelets (also called thrombocytes) are minute discs 1 to 4 micrometers in diameter. They are formed in the bone marrow from megakaryocytes, The normal concentration of platelets in the blood is between 150,000 and 300,000 per microliter. Characteristics Platelets have many functional characteristics of whole cells: ďˇ Non- nucleated, small, colorless bodies ďˇ Minute discs, 1-4 micrometer in diameter ďˇ Originates from the bone marrow o Exists in the form of megakaryoctes and will fragment to form platelets before being released to blood circulation ďˇ Normal value: 150,000- 300,000 ďˇ Thrombocytopenia: < 150,000 o at risk for bleeding due to lack of clotting factors which are platelets o Dengue Hemorrhagic Fever ďˇ Thrombocytosis: > 300,000 Functions ďˇ Actin and Myosin molecules, which are contractile proteins and thrombosthenin, that can cause the platelets to contract ďˇ Residuals of both the endoplasmic reticulum and the Golgi apparatus that synthesize various enzymes storage of large quantities of calcium ions. ďˇ Mitochondria and enzyme systems that are capable of forming adenosine triphosphate (ATP) and adenosine diphosphate (ADP) ďˇ Enzyme systems that synthesize prostaglandins, an important protein called fibrin-stabilizing factor. o A growth factor that causes vascular endothelial cells, vascular smooth muscle cells, o Fibroblast: helps repair damaged vascular walls. ďˇ Hemostasis – blood loss prevention o The arrest of bleeding. Three processes acts to stem the flow of blood: vasoconstriction, platelet aggregation and blood coagulation ďˇ ďˇ ďˇ ďˇ II. Platelet Aggregation and Clotting Damage to the endothelium of a blood vessel causes platelets to adhere to the site of injury. The adherent platelets release adenosine diphosphate and thromboxane A2, which cause additional platelets to adhere. Platelets are prevented from aggregating along the length of a normal vessel by the anti-aggregation action of prostacyclin. Also release serotonin which enhances vasoconstriction and thromboplastin which hastens blood coagulation. When the platelet count is low, as in thrombolytopenic purpura, tiny hemorrhages (petechiae) or large Mejia, Racho, Sanico, Villaflores MD-1C 2019 Lec 11 - 25 Aug 2015 hemorrhages (ecchymoses) may appear in the skin and mucous membranes. Vasoconstriction ďˇ Immediately after a blood vessel has been cut, the trauma to the vessel wall causes the smooth muscle in the wall to contract; this instantaneously reduces the flow of blood from the ruptured vessel. ďˇ The contraction results from 1. Local myogenic spasm 2. Local autacoid factors from the traumatized tissues and blood platelets, 3. Nervous reflexes; initiated by pain nerve impulses or other sensory impulses that originate from the traumatized vessel or nearby tissues. ďˇ Responsible for much of the vasoconstriction by releasing a vasoconstrictor substance, thromboxane A2. ďˇ The more severely a vessel is traumatized, the greater the degree of vascular spasm. ďˇ Platelets come in contact to the vascular wall, the platelets immediately change and they begin to swell; their contractile proteins contract forcefully and cause the release of granules that contain multiple active factors; become sticky so that they adhere to collagen in the tissues and to a protein called von Willebrand factor ďˇ ADP and thromboxane – activates nearby platelets, and adds to the stickiness of these additional platelets ďˇ During blood coagulation, fibrin threads form. These attach tightly to the platelets, thus constructing an unyielding plug. The Cell Membrane ďˇ Its surface is a coat of glycoproteins that repulses adherence to normal endothelium and yet causes adherence to injured areas of the vessel wall, especially to injured endothelial cells and even more so to any exposed collagen from deep within the vessel wall. What is a clot? ďˇ mesh of fibrin polymers that trap RBC (red blood cells) and platelets to prevent loss of blood Steps in Blood Clotting 1. Local vasoconstriction/vascular spasm o First line of defense o Physical injury to a blood vessel elicits a contractile response of the vascular smooth muscle and thus narrowing of the vessel. o Platelet secretion: thromboxane a2 and serotonin 2. Platelet plug formation o Second line of defense o The platelet membrane contains large amounts of phospholipids that activate multiple stages in the blood-clotting process Page 1 of 4 PHYSIOLOGY – A Blood Physio pt. 2 o o 3. Dr. Joseph U. Olivar (JUO) When endothelium of vessel is damaged, collagen is exposed, therefore attracting platelets to form a plug. Petechiae (small) and purpura (multiple hemorrhages found on the skin) Lec 11 - 25 Aug 2015 reactions. Therefore, in the absence of calcium ions, blood clotting does not occur. Blood Coagulation o Third line of defense o Bleeding stops; closure of injured vessel occurs o Begins to develop in 15 to 20 seconds if the trauma to the vascular wall has been severe, and in 1 to 2 minutes if the trauma has been minor. 2+ Anticoagulants – remove Ca from blood which causes no clotting of blood o Citrate (deionize Calcium) o Oxalate (precipitate Calcium) Note: in transfusion, give patient CALCIUM to prevent bleeding. Intrinsic Mechanism for Initiating Clotting 1. Blood trauma causes activation of Factor XII and release of platelet phospholipids. o Trauma to the blood or exposure to vascular wall collagen alters two important clotting factors in the blood: Factor XII and the platelets. 2. Activation of Factor XI o The activated Factor XII acts enzymatically on Factor XI to activate this as well, which is the second step in intrinsic pathway. This reaction also requires HMW (High molecular weight) kininogen and is accelerated by prekallikrein. 3. Activation of Factor IX o The activated Factor XI then acts enzymatically on Factor IX to activate this factor also. 4. Activation of Factor X – role of Factor VIII o The activated Factor IX, acting in concert with activated Factor VIII and with the platelet phospholipids and factor 3 from traumatized platelets, activates Factor X. 5. Action of activated Factor X to form prothrombin activator – role of Factor V o Activated Factor X combines with Factor V and platelet or tissue phospholipids to form the complex called prothrombin activator. The prothrombin activator in turn initiates within seconds the cleavage of prothrombin to form thrombin, thereby setting into motion the final clotting process. Role of Calcium Ions in the Intrinsic and Extrinsic pathway ďˇ Except for the first 2 steps in the Intrinsic pathway, calcium ions are required for promotion or acceleration of all the Mejia, Racho, Sanico, Villaflores MD-1C 2019 Figure 1. Blood clotting. ďˇ The key step in blood clotting is the conversion of fibrinogen to fibrin by thrombin. The clot formed by this reaction consists of a dense network of fibrin strands in which blood cells and plasma are trapped. Clot Lysis ďˇ Blood clots may be liquefied by a proteolytic enzyme called plasmin. ďˇ Normal blood contains plasminogen, an inactive precursor of plasmin. ďˇ Activators of the conversion of plasminogen to plasmin are found in tissues, plasma and urine (urokinase). Rate-Limiting Steps ďˇ Formation of prothrombin activator/ prothrombin converting enzyme ďˇ Prothrombin converted to thrombin (via Prothrombin activator which is an enzyme) ďˇ Thrombin converts fibrinogen to fibrin (forms unstable clot) ďˇ Fibrin monomer – will polymerize via factor XIII or Fibrin Stabilizing Factor Table 1. Clotting Factors In the Blood And Their Synonyms Factor I II III IV V VII VIII Synonyms Fibrinogen Prothrombin Tissue Factor/ Thromboplastin Calcium Labile factor; Proaccelerin Stable factor; Proconvertin Antihemophilic factor Page 2 of 4 PHYSIOLOGY – A Blood Physio pt. 2 IX X XI HMW Kininogen Platelets Dr. Joseph U. Olivar (JUO) ďˇ ďˇ Antihemophilic B factor; Christmas factor Stuart factor Plasma Thromboplastin Antecedent Fitzgerald Factor III. Coagulation Pathways Production of prothrombin factors ďˇ The 2 coagulation pathways converge on the activation of factor X, which catalyzes the cleavage of prothrombin to thrombin. Intrinsic Pathway ďˇ Is initiated by exposure of the blood to a damage endothelium or a negatively charged surface. ďˇ When the endothelium of blood vessels is damage, blood comes into contact with collagen. Outside the body, clotting can occur when blood comes into contact with negatively charged surfaces such as glass. ďˇ After a clot is formed, the actin and myosin of the platelets trapped in the fibrin mesh interact in a manner similar to that in muscle. The resultant contraction pulls the fibrin strands towards the platelets, and thereby extrudes the serum (plasma without the fibrinogen) and shrinks the clot. This process is called clot retraction. ďˇ Several cofactors are required for blood coagulation; the most important is calcium. If the calcium ions in the blood are removed or bound, coagulation will not occur. 1. 2. 3. 4. 5. 6. 7. 8. Figure 2. Coagulation cascade demonstrating intrinsic, extrinsic, and common pathways. 9. The Extrinsic Pathway ďˇ Extrinsic pathway only makes two factors: Factor 3 and Factor 7 to generate the prothrombin activator. ďˇ Extrinsic factor is short because tissue trauma is the one that stimulates its occurrence o Initiated by tissue damage and the release of tissue thromboplastin ďˇ Stimulated by trauma to the vascular wall and adjacent tissues ďˇ Starts with the release of Factor 3 (Tissue Factor/ Thromboplastin) + Factor 7 ďˇ F3 + F7 = activates Factor 10 to activated factor 10A ďˇ Activated F10A converts Prothrombin to Thrombin ďˇ Thrombin converts Fibrinogen to Fibrin ďˇ Note: Prothrombin Activator = Activated Factor 10A ďˇ Factor 5 accelerates the action of activated Factor 10A in converting Prothrombin to Thrombin o The action of F5 is possible if it is stimulated by thrombin Significance ďˇ The extrinsic pathway to begin with is very slow until the first thrombin is generated ďˇ ďˇ Mejia, Racho, Sanico, Villaflores MD-1C 2019 Lec 11 - 25 Aug 2015 Once generated, it activates F5 Action of prothrombin activator is enhanced (factor 10) ďˇ ďˇ Blood trauma or contact with collagen: activates Factor XII Factor XII → XIIa Factor XI → XIa Factor IX → IXa Factor VIII → VIIIa Factor VII → VIIa Factor VII with Factor III will convert Factor X → Xa Xa (Prothrombin Coverting Factor) o Splits prothrombin → thrombin o Thrombin (Factor II → IIa) Thrombin converts Fibrinogen → Fibrin IV. Clot Retraction and Lysis Thrombosthenin from platelets causes clot retraction Serum: cannot clot ( due to coagulating factors trapped in hematocrit layer) Plasma: can clot (coagulating factors present) Final event in clot repair → Lysis of clot o How? ď§ Plasminogen → Plasmin via TPA or Tissue Plasminogen Factor Anticoagulation Mechanisms in Cells ďˇ Glycocalyx – repels coagulation factors ďˇ Thrombomodulin – prevents coagulation o Activates Protein C: deactivates FACTOR V and VIII ďˇ Fibrin – natural occurring anticoagulant and has antithrombin functions ďˇ Anti-thrombin 3 – combines with heparin resulting to a potent anticoagulant Page 3 of 4 PHYSIOLOGY – A Blood Physio pt. 2 A. B. Dr. Joseph U. Olivar (JUO) Lec 11 - 25 Aug 2015 IV. Clinical Correlations Coagulation deficiencies ďˇ Greater risk of bleeding ďˇ Vitamin K: synthesized by the intestinal flora; a fat soluble vitamin ďˇ Vitamin K-dependent Factors: II, VII, IX, X o (synthesized in the liver through the enzyme liver carboxylase, Vitamin K will be oxidized and becomes useless) 1. Vitamin K epoxide reductase complex o Reactivates Vitamin K to its functional form 2. Interventricular Hemorrhage o No intestinal flora to produce Vitamin K; seen in newborns 3. Hemophilia o No Factor VIII and IX 4. Thrombocytopenia o Lack of platelets causing bleeding disorder Anticoagulants in Use ďˇ Heparin o potentiates the action of anti- thrombin 3 to block factors XII, XI, IX, X, II o Antidote: Protamine Sulfate ďˇ Coumadin/Warfarin o inhibits Vitamin K epoxide reductase → no production of factors II, VII, IX, X o imitates VCOR1 o Antidote: Vitamin K Coagulation excess ďˇ Formation of unnecessary clots 1. Thrombus o Abnormal clot formation 2. Embolus o Traveling thrombus o Can cause infarction o Can dislodge in the smallest capillaries in the lungs producing pulmonary embolism o Usually formed in the lower extremities since stasis is very common in this area o Can cause stroke when thrombus dislodges in the mitral valve (left side of the heart) which can dislodge and go to the cerebral vessels 3. Atherosclerosis o Rupture in the tunica intima of the blood vessels causing activation of the intrinsic pathway o Can cause heart failure since it can impede blood circulation o Factor XIII – stabilizes clot ď§ (Once clot has stabilized, giving medications such as streptokinase is rendered useless) 4. Disseminated Intravascular Coagulation o Results from widespread sepsis 5. Abruptio Placenta o Results from sepsis during pregnancy; detachment of placenta from the uterus o Treatment: removal of the cause ď§ antibiotics or remove placenta 3. Mejia, Racho, Sanico, Villaflores MD-1C 2019 Note: Blood coagulation can be prevented in vitro by the addition of citrate or oxalate, which removes the calcium ions from solution. 1. 2. V. Clinical Procedures and Tests Bleeding Time o Test for platelet quality o Normal value: 1-6 minutes Platelet count o Test for platelet quantity Clotting Time o Test for clotting factors o Normal value: 6-10 minutes a. Prothrombin Time (PeT) o test for extrinsic pathway b. Partial Thromboplastin Time (PiTT) o test for intrinsic pathway References Blood Physio PPT Adarve, Normel C. (RMT, ASCP), Guide Notes & Laboratory Workbook on Hematology, 2011. Hall, John E. Guyton and Hall Textbook of Medical Physiology. Twelfth. Philadelphia: Saunders Elsevier, 2011. Page 4 of 4 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar WHITE BLOOD CELLS (WBC) / LUEKOCYTES ď§ Unlike RBC’s and platelets, WBC’s are NUCLEATED. ď§ Based on presence of granules: GRANULOCYTES and AGRANULOCYTES ď§ GRANULOCYTES: ďź Neutrophils: engulf bacteria and cellular debris (phagocytosis) ďź Basophils: weak phagocytes; HYPERSENSITIVITY; release histamine; secretes naturally-occurring anticoagulant, HEPARIN ďź Eosinophils: weak phagocytes; PARASITIC INFECTIONS; allergic response ď§ AGRANULOCYTES: ďź Lymphocytes: B, T-lymphocytes (IMMUNOLOGY) ďź Monocytes: engulf cellular debris (phagocytosis); antigen processing ď§ Normal Values: WBC- 5-10 x 109/L ďˇ Leukocytosis: abnormal ↑ in the no. of WBC’s; (+) infection ďˇ Leukopenia: WBC count less than normal ďˇ In an overwhelming SEPSIS, WBC’s are called to action and all are consumed =↓WBC count DENGUE: characteristic WBC is leukopenia ďˇ ď§ Also arise from the Pluripotent Hematopoietic Stem Cell (PHSC) in the bone marrow. LOCATION GRANULOCYTES MONOCYTES LYMPHOCYTES Originate in the bone marrow; Found in the circulation Originate in the bone marrow; Placed in lymphoid tissues (lymph nodes, tonsils, spleen, thymus, appendix, peyer’s patches) 3. “Third, the immune system of the body develops antibodies against infectious agents such as bacteria. The antibodies then adhere to the bacterial membranes and thereby make the bacteria especially susceptible to phagocytosis. To do this, the antibody molecule also combines with the C3 product of the complement cascade. The C3 molecules, in turn, attach to receptors on the phagocyte membrane, thus initiating phagocytosis. This selection and phagocytosis process is called OPSONIZATION.” How does phagocytosis occur? [video] PHAGOCYTES: 1. NEUTROPHILS - phagocytic - active in the blood - constantly formed in the bone marrow where they develop and mature - mature neutrophils circulate in the blood for 3-12 hours; then, they move to other tissues where they will survive for only 2-3 days - acts as surveillance cells searching for infections - contains lysosomes that degrades bacteria - after digesting the bacteria, neutrophil shrinks in size - a single neutrophil can usually phagocytize 3 to 20 bacteria before the neutrophil itself becomes inactivated and dies - SECOND LINE against invading microorganisms because it degenerates after killing the bacteria - ACUTE INFECTIONS 2. FUNCTIONS OF THE LEUKOCYTES: Combat Infection ď§ Destroy the invading agents by phagocytosis ď§ Form antibodies and sensitized lymphocytes PHAGOCYTOSIS (Cellular Ingestion) - Phagocytes must be selective of the material that is phagocytized; otherwise, normal cells and structures of the body might be ingested - Normal tissues are not ingested because: 1. Most normal tissues have smooth surfaces - which resist phagocytosis - but if the surface is rough, the likelihood of phagocytosis is increased 2. Most natural substances of the body has protective protein coats - repels phagocytes - conversely, most dead tissues and foreign particles are rough and have no protective coats, which make them subject to phagocytosis. Foreign Ag + antibodies + C3 - when a foreign antigen enters the body, we mount an immune system by producing an antibody = stimulates the COMPLEMENT SYSTEM - complement system brings the Antigen-Antibody complex near the phagocyte - phagocyte destroys the combination - the process where the complement brings the antigenantibody complex near a phagocyte is called OPSONIZATION. MACROPHAGE - phagocytic - inactive monocytes in the blood - monocytes must first arrive in the tissue and transform to become MACROPHAGES before it can perform phagocytosis - active macrophages in tissues - they do not die in the tissues; they survive after doing their function - FIRST LINE OF DEFENSE - ACUTE/CHRONIC INFECTIONS MONOCYTE MACROPHAGE CELL SYSTEM (RETICULOENDOTHELIAL SYSTEM) ď§ strategically placed in PORTALS OF ENTRIES of microorganisms ďˇ Tissue macrophage in the SKIN and SUBCUTANEOUS TISSUES (Histiocytes) ďˇ Macrophages in the LYMPH NODES ďˇ Alveolar Macrophages in the LUNGS ďˇ Macrophages (Kupffer cells) in the LIVER sinusoids ďˇ Macrophages of the SPLEEN and BONE MARROW ď§ Both NEUTROPHILS and MACROPHAGES can kill bacteria by releasing BACTERICIDAL AGENTS: 1 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar BACTERICIDAL AGENTS Superoxide O2Hydrogen Peroxide H2O2 Hydroxyl ions OHH2O2 + Cl- -> (myeloperoxidase) -> hypochlorite “When tissue injury occurs, whether caused by bacteria, trauma, chemicals, heat, or any other phenomenon, multiple substances are released by the injured tissues and cause dramatic secondary changes in the surrounding uninjured tissues. This entire complex of tissue changes is called INFLAMMATION.” INFLAMMATION is characterized by: 1. Vasodilatation of the local blood vessels with consequent excess local blood flow. 2. Increased permeability of the capillaries. 3. Clotting of fluid in the interstitial spaces. -because the plasma is being pushed into the interstitial space -Plasma contains coagulation factors; thus, it can form a clot 4. Migration of large number of neutrophils and monocytes into the tissue. 5. Swelling of the tissue. 5 Cardinal Signs of INFLAMMATION: ďź the area inflamed will appear RED (RUBOR) ďź due to vasodilatation, there is release of HEAT (KALOR) ďź release of painful substances, causing PAIN (DOLOR) ďź increased permeability of the capillaries ď EDEMA (TUMOR) ďź LOSS OF FUNCTION What is the purpose of the inflammatory process? ď§ One of the first results of inflammation is to "wall off" the area of injury from the remaining tissues. The tissue spaces and the lymphatics in the inflamed area are blocked by fibrinogen clots so that after a while, fluid barely flows through the spaces. ď§ This walling-off process delays the spread of bacteria or toxic products. ď§ When neutrophils and macrophages engulf large numbers of bacteria and necrotic tissue, essentially all the neutrophils and many, if not most, of the macrophages eventually die. After several days, a cavity is often excavated in the inflamed tissues. It contains varying portions of necrotic tissue, dead neutrophils, dead macrophages, and tissue fluid. This mixture is commonly known as PUS. “The intensity of the inflammatory process is usually proportional to the degree of tissue injury.” RESPONSE DURING INFLAMMATION: ď§ Tissue MACROPHAGE is the FIRST LINE of defense against infection. because within minutes, the macrophages present in the Reticulo-endothelial system (RES) will be activated. ď§ NEUTROPHIL invasion of the inflamed area is a SECOND LINE of defense because within the first hour after the inflammatory process, INFLAMMATORY CYTOKINES (Tumor Necrosis Factor and Interleukin-1 - chemoattractants) will be secreted MARGINATION: process where the WBC’s attach to the walls of the endothelium. DIAPEDESIS: WBC’s squeeze through the pores of the capillaries. CHEMOTAXIS: inflamed tissues release chemicals that attract neutrophils and macrophages. ↓ FINAL EVENT: PHAGOCYTOSIS - ď§ TNF and IL-1 will attract the neutrophils to go to the inflamed area TNF and IL-1 also increase the expression of adhesion molecules in the endothelium called SELECTIN and IntraCellular Adhesion Molecule (ICAM) Selectin and ICAM binds to NEUTROPHIL causing the neutrophil to MARGINATE followed by Diapedesis, then Chemotaxis The second macrophage invasion into the inflamed tissue is the THIRD LINE of defense. ď§ BONE MARROW – increases its production of monocyte ď§ Monocytes ď go to the CIRCULATION ď then to the tissue as TISSUE MACROPHAGES 2 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar ď§ Increased production of granulocytes and monocytes by the bone marrow is the FOURTH LINE of defense. ďˇ Within 3-4 days, greatly increased production of neutrophils and monocytes by the bone marrow. ďˇ Activated Macrophage secrete cytokines: TNF, IL-1, GCSF, M-CSF (Granulocyte; Monocyte Colony Stimulating Factor) ďˇ Cytokines stimulate the bone marrow ď ↑production of WBC - Therapeutic Radiation procedures: radiotherapy for cancer (radiation is too much, enough to suppress the bone marrow ď (leukopenia) - Drugs: chlorampenicol (antibiotic), thiouracil (given to hyperthyroid), chemotherapeutic agents LEUKEMIA: uncontrolled production of WBC cancerous mutation of a myelogenous and lymphogenous cell (AML, ALL) Effects of Leukemia in the body: - metastatic growth of leukemic cells in abnormal areas of the body - WBC’s should only be in the BONE MARROW or in the BLOOD - Metastasis: WBC’s are found infiltrating the BONE - infections, severe anemia, bleeding - although WBC’s are excessively increased, they are IMMATURE - because of the over proliferation of the WBC’s in the bone marrow, RBC’s and platelets are displaced ď patient suffers from severe anemia and bleeding - metabolic starvation - cancer cells utilizing all the energy and nutrients of the body 3. CASE: 4. EOSINOPHILS - weak phagocytes - important role in ALLERGIC REACTIONS - role in PARASITIC INFECTIONS (WORMS) ↑Eosinophil count = Parasitic infection ↑Neutrophil = Bacterial infection BASOPHILS/ MAST CELLS - releases HEPARIN: prevents blood coagulation - releases HISTAMINE: involved in ALLERGIC REACTIONS PLEASE REMEMBER! Basophil and Mast Cells are associated closely with an immunoglobulin (IgE) Basophil + IgE (with antigen) = histamine (Histamine mediates allergic reactions) ďˇ When the specific antigen for the specific IgE antibody subsequently reacts with the antibody, the resulting attachment of antigen to antibody causes the mast cell or basophil to rupture and release large quantities of histamine, bradykinin, serotonin, heparin, slow-reacting substance of anaphylaxis, and a number of lysosomal enzymes. ďˇ These cause local vascular and tissue reactions that cause many, if not most, of the allergic manifestations. CLINICAL CORRELATION: LEUKOPENIA: ↓WBC count CAUSES: - massive infection - irradiation PLEASE REMEMBER! - Diagnostic Radiation (x-ray, CT-scan, MRI) is NOT enough to suppress the bone marrow and cause leukopenia 3 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar IMMUNOLOGY I. INNATE IMMUNITY “Early defense against infections” The INVADERS: - Bacteria - Viruses - Parasites (such as fungi, protista, worms) IMMUNITY ability of the human body to resist almost all types of organisms or toxins that tend to damage the tissues or organs ANTIGEN (Ag): antibody generation any molecule that can bind to the components of the specific immune response Components of Innate Immunity: i. Epithelial barriers - provides physical barrier to infection - killing of microbes by locally produced antibiotics - killing of microbes and infected cells by intraepithelial lymphocytes ii. Phagocytes - Neutrophils - Monocytes/Macrophages iii. ANTIBODY (Ab) family of defensive proteins the body makes when stimulated by an antigen CYTOKINES - substances, mostly proteins, secreted by cells affecting the behavior of nearby cells - ex: interleukins (IL); interferons (INF) - can be produced either by: ďź INNATE IMMUNITY o Macrophages, Natural Killer (NK) cells o Both secrete cytokines ďź ACQUIRED IMMUNITY o T lymphocytes INNATE IMMUNITY ď§ Phagocytosis by WBC’s and macrophages ď§ Skin ď§ Acid secretion of stomach ď§ Presence in the blood of certain compouns that attach to foreign substances and destroy them ď§ Lysozymes ď§ Complement system ď§ NK cells *already present, ready to protect you even on first encounter ACQUIRED IMMUNITY (Adaptive Immunity) ď§ Immunity developed due to previous exposure to invading agents such as bacteria, viruses, toxins, foreign tissues *lymphocytes are not ready protect you on first encounter *you have to be sick first; but once you have developed the protection, the immunity is extremely powerful that you might not even experience the second disease (chickenpox) or you might not even experience the disease at all (vaccination) Dendritic Cells - cells present in the skin; considered as bridge between innate and adaptive immunity - MECHANISM: organism traversed the skin ↓ dendritic cells (cannot destroy the bacterium) will carry the organism ↓ presents the organism to the lymphocyte in the lymphoid tissue (thus, bridging innate and adaptive immunity) iv. Natural Killer Cells are a class of lymphocytes that recognize infected cells, respond by: o killing these cells or o by secreting the macrophage activating cytokine interferon gamma (IFN-ϒ) When a macrophage ingested a microbe, macrophage cannot degrade the organism ↓ Macrophage will secrete cytokine interleukin-12 (IL-12) ↓ Attracts natural killer (NK) cell; it will sense macrophage needs help; secretes IFN-ϒ ↓ IFN-ϒ activates the macrophage (ACTIVATED MACROPHAGE: secretes TNF, IL-1 ď attracts neutrophils from the blood) ↓ Kills the phagocytized microbe (*Cytokines: interleukin-12; interferon gamma) 4 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar v. The Complement System - series of about 20 proteins, existing in a proenzyme form (INACTIVE) - once activated by the microorganism or antigen-antibody complex, it can eliminate the invading microorganism COMPLEMENT SYSTEM ď§ Once the microbe has escaped humoral immunity and has entered the cell, cell-mediated immunity will now take over o Two most predominant cells: ď§ Cytotoxic T-cell - directly kill the infected cell ď§ Helper T-cell - does not have the capability to degrade the cell - however, once activated, it can release cytokines which can: o activate macrophage ď cause inflammation o proliferation of B lymphocytes and cytotoxic T-cell and perform their actions ď§ Lymphocytes are also coming from the stem cell ď§ Once produced by the bone marrow, they are stored in the lymphoid tissues ď§ But before birth, stored in the lymphoid tissues and processed first in two organs: - THYMUS ď T-lymphocytes - FETAL BONE MARROW ď B-lymphocytes ď§ TWO PURPOSES OF PRE-PROCESSING OF THE LYMPHOCYTES IN THE THYMUS, FETAL LIVER AND BONE MARROW: 1. To achieve SPECIFICITY ď§ 1 antigen will react with only 1 lymphocyte or antibody ď§ Two Ways to activate: o MICROORGANISM activates C3 -INNATE IMMUNITY o ď§ Lymphocytes in the thymus and bone marrow are presented with thousands of antigens ď producing thousands of lymphocytes ď§ 1 antigen : 1 lymphocyte ANTIGEN-ANTIBODY COMPLEX activates C1 -ACQUIRED/ADAPTIVE IMMUNITY 2. Cytokines present in Innate Immunity Interleukin 12 (IL-12) Interferon gamma (IFN-ϒ) Interleukin 1 (IL-1) Tumor Necrosis Factor (TNF) To achieve TOLERANCE ď§ The lymphocytes and antibodies must not react with own cells ď§ Lymphocytes in the thymus and bone marrow are presented with own cells expected reaction: lymphocytes must not react Once the lymphocytes react with own cells, it will be destroyed II. ACQUIRED IMMUNITY a property of lymphocytes (T, B lymphocytes) TWO BASIC TYPES OF ACQUIRED IMMUNITY 1. CELL-MEDIATED IMMUNITY (T lymphocytes) = Activated lymphocytes ď§ Process of tolerance is only 90% perfect - explains the occurrence of AUTOIMMUNE DISEASES 2. HUMORAL IMMUNITY (B lymphocytes) = Antibodies MICROBE RESPONDING LYMPHOCYTES EFFECTOR MECHANISM FUNCTIONS HUMORAL IMMUNITY Extracellular microbes B lymphocytes Secretes antibody ď§ Block infections ď§ Eliminate extracellular microbes CELL-MEDIATED IMMUNITY Phagocytosed microbes in macrophage Helper T lymphocyte Intracellular microbes (ex. viruses) replicating within infected cell Cytotoxic T lymphocyte Activate macrophages to kill phagocytosed microbes Kill infected cells and eliminate reservoirs of infection 5 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar ď§ TWO BASIC TYPES OF ACQUIRED IMMUNITY CELL-MEDIATED IMMUNITY HUMORAL IMMUNITY (T lymphocytes) (B lymphocytes) ↓ ↓ Activated Lymphocytes Antibodies (directly kills the Helper T-cells (CD4) microbes; activation of - LYMPHOKINES/CYTOKINES complement system) - stimulation of growth and proliferation of cytotoxic T-cells and suppressor T-cells *upon recognition of - stimulation of B-cell growth and antigen, differentiation to form plasma B-lymphocytes cells and antibodies proliferate then - activation of macrophage differentiate to become: system - stimulatory effect on the helper ď§ Plasma cells T-cells (secretes antibodies) ď§ Cytotoxic T-cells (CD8) - directly attacks the cell ď§ ď§ Suppressor T-cells - subtype of helper T-cells - regulate/suppressive function on both cytotoxic (CD8) and helper T-cells (CD4) ď§ Memory T-cells - cause more rapid response on subsequent exposure to the same antigen *In both immunities, MEMORY CELLS are produced Memory B-cells i. CELL MEDIATED IMMUNITY: involves T-lymphocytes CD8 (Cytotoxic T-cell) - directly kills the infected cell ď§ Cytotoxic T-cells (CD8) and Helper T-cells (CD4) do not have the capability to recognize the antigen directly ď§ A cell must be presented first by an ANTIGEN PRESENTING CELL ď§ ANTIGEN PRESENTING CELLS: Dendritic cells, Macrophages, Blymphocytes o once the antigen presenting cell presents the antigen to either CD4 or CD8, both T-cells will proliferate, undergoing clonal expansion and the effector mechanism will proceed o CD8 – directly kills the organism o CD4 – produces cytokines that can stimulate B-lymphocyte, macrophage, cytotoxic T-cell ď§ Every time that B & T-lymphocyte undergo clonal expansion, memory cells are produced ď§ Once recognized by the T-cell, it will destroy both the antigen and antigen-presenting cell CD4 (Helper T-cell) - cannot kill the cell - releases Lymphokines/Cytokines = B lypmhocytes proliferate to produce antibody = antibody will kill the cell - Function of Lymphokines/Cytokines: o can activate the macrophage system, thus activating the inflammatory reaction o can stimulate the B-lymphocyte to differentiate into plasma cells and produce antibodies o can stimulate the growth and proliferation of both Cytotoxic T and Suppresor T cells o has stimulatory effect on the Helper T-cells themselves ď§ The CYTOKINES released by HELPER T-CELLS modulate the whole immune response. Without them, the whole immune system will be paralyzed. CASE: HIV/AIDS - attacks CD4 (Helper T-cells) - full blown AIDS patient usually dies from overwhelming infection because their immune system is paralyzed due to the absence of cytokines coming from the helper T-cells [(Immu1)video- 16:23-17:50] 6 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar CYTOKINES OF ACQUIRED IMMUNITY: produced by T lymphocytes - Interferon gamma (IFN-ϒ): produced by NK cells; also produced by CD4, CD8 T-cells - Interleukin-2 (IL-2) - Interleukin-4 (IL-4) - Interleukin-5 (IL-5) ii. HUMORAL IMMUNITY: involves B-lymphocytes ď§ Unlike T lymphocytes, B lymphocytes can distinguish a microbe or an antigen ď§ If B lymphocytes react with the microbe or an antigen, it is only activated ď§ It needs cytokines released by Helper T-cells (CD4) before they can proliferate as plasma cells ď produce antibody, memory Bcells -activates the complement system - cytolytic (can destroy the cell) - crosses the placenta (anti-RH IgG) CASE: Hepatitis - jaundiced, (+)HBS antigen - IgM, IgG titers to determine whether it is acute or chronic ď§ If ACUTE, the patient will get well even if without medication; self-limiting ď§ If CHRONIC, patient can suffer with liver cancer or cirrhosis IgA: second most abundant - chief immunoglobulin in EXOCRINE secretions (breast milk) IgE: mediates certain allergic reactions - attached to basophils and mast cells IgD: very small amount - attaches to surface of B-lymphocyte - helps in antigen recognition by B-cells MECHANISM OF ACTION OF ANTIBODIES: 1. Direct attack on the invaders through ď§ Agglutination ď§ Precipitation ď§ Neutralization ď§ Lysis * If not enough, the complement system is activated 2. Activation of the complement system Configuration of an antibody ď§ COMPLEMENT SYSTEM VARIABLE PORTION - the portion that attaches specifically to a particular type of antigen - it varies according to the antigen to which the antibody will react EXAMPLE: IgM antibody for chicken pox; IgM antibody for measles - the variable portion for chicken pox, is different from the variable portion for measles - but they are both IgM ď§ CONSTANT PORTION - it is used in its attachment to the complement system - diffusivity of antibody to tissues - adherence of antibody to tissues - attachment to the complement (most important function) CLASSES OF ANTIBODIES: o IgM: first to appear in ACUTE INFECTION/ 1 antigen stimulus - activates the complement system - cytolytic (can destroy the cell) - does NOT cross the placenta o IgG: first to appear in CHRONIC INFECTION/2 antigen stimulus -most abundant (75%) ď§ Antigen-antibody complex stimulates C1 =products are produced resulting to elimination of the infection via: - Lysis of cells - Chemotaxis of WBC’s - Activation of inflammation - Opsonization - Ag-Ab complex causes the complement -> complement brings the complex to the phagocyte -> phagocytosis Question: What part of the antibody stimulates the Complement System? Answer: “Constant” 7 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar MEMORY B-CELLS ď§ FIRST EXPOSURE (blue): mounting of immune response is delayed and level is low ď§ SECOND EXPOSURE (red): since memory cells are already developed, response is rapid, level is high, long-lasting; - at second exposure, patient might not even manifest the disease because at the onset, he is already protected - PRINCIPLE being used in VACCINES ď§ ď§ ď§ ď§ ACQUIRED IMMUNITY ACTIVE IMMUNITY PASSIVE IMMUNITY Produced by individuals in ď§ Antibodies derived from response to natural or another either by natural artificial stimulation transfer or by injection Generates own antibodies ď§ Given pre-formed antibodies Chickenpox infection ď§ Newborn MMR vaccination ď§ Immunoglobulins ADVANTAGE: immunity is lifelong once produced DISADVANTAGE: it takes time before you are protected; you get the disease first before producing the antibodies ď§ ď§ On first exposure, produces a response. On second exposure, response is greater INFECTIONS CELL-MEDIATED HUMORAL IMMUNITY IMMUNITY (B lymphocytes) (T lymphocytes) ď§ Transplant rejection ď§ Antibodies against bacteria ď§ Destruction of cancer and viruses cells ď§ Fungi, viruses, Ex. Measles, Mumps, Chicken parasites, bacteria (ex. pox TB –most common) ADVANTAGE: immediately protected DISADVANTAGE: the pre-formed antibody is short-lived ď§ We do not get diseases from the vaccine because the virus is INACTIVATED. AUTOIMMUNE DISEASES - because the process of immune tolerance is not perfect (90%) - some individuals generate autoimmune antibodies CASE: Myasthenia Gravis - Acetylcholine receptors are destroyed - Cannot generate an end-plate potential =weakness Allergy/Hypersensitivity ACUTE: due to IgE CHRONIC: due to cytotoxic T-cells (CD8) -Urticaria -Allergic Rhinitis -Bronchial Asthma 8 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar WHITE BLOOD CELLS (WBC) / LUEKOCYTES ď§ Unlike RBC’s and platelets, WBC’s are NUCLEATED. ď§ Based on presence of granules: GRANULOCYTES and AGRANULOCYTES ď§ GRANULOCYTES: ďź Neutrophils: engulf bacteria and cellular debris (phagocytosis) ďź Basophils: weak phagocytes; HYPERSENSITIVITY; release histamine; secretes naturally-occurring anticoagulant, HEPARIN ďź Eosinophils: weak phagocytes; PARASITIC INFECTIONS; allergic response ď§ AGRANULOCYTES: ďź Lymphocytes: B, T-lymphocytes (IMMUNOLOGY) ďź Monocytes: engulf cellular debris (phagocytosis); antigen processing ď§ Normal Values: WBC- 5-10 x 109/L ďˇ Leukocytosis: abnormal ↑ in the no. of WBC’s; (+) infection ďˇ Leukopenia: WBC count less than normal ďˇ In an overwhelming SEPSIS, WBC’s are called to action and all are consumed =↓WBC count DENGUE: characteristic WBC is leukopenia ďˇ ď§ Also arise from the Pluripotent Hematopoietic Stem Cell (PHSC) in the bone marrow. LOCATION GRANULOCYTES MONOCYTES LYMPHOCYTES Originate in the bone marrow; Found in the circulation Originate in the bone marrow; Placed in lymphoid tissues (lymph nodes, tonsils, spleen, thymus, appendix, peyer’s patches) 3. “Third, the immune system of the body develops antibodies against infectious agents such as bacteria. The antibodies then adhere to the bacterial membranes and thereby make the bacteria especially susceptible to phagocytosis. To do this, the antibody molecule also combines with the C3 product of the complement cascade. The C3 molecules, in turn, attach to receptors on the phagocyte membrane, thus initiating phagocytosis. This selection and phagocytosis process is called OPSONIZATION.” How does phagocytosis occur? [video] PHAGOCYTES: 1. NEUTROPHILS - phagocytic - active in the blood - constantly formed in the bone marrow where they develop and mature - mature neutrophils circulate in the blood for 3-12 hours; then, they move to other tissues where they will survive for only 2-3 days - acts as surveillance cells searching for infections - contains lysosomes that degrades bacteria - after digesting the bacteria, neutrophil shrinks in size - a single neutrophil can usually phagocytize 3 to 20 bacteria before the neutrophil itself becomes inactivated and dies - SECOND LINE against invading microorganisms because it degenerates after killing the bacteria - ACUTE INFECTIONS 2. FUNCTIONS OF THE LEUKOCYTES: Combat Infection ď§ Destroy the invading agents by phagocytosis ď§ Form antibodies and sensitized lymphocytes PHAGOCYTOSIS (Cellular Ingestion) - Phagocytes must be selective of the material that is phagocytized; otherwise, normal cells and structures of the body might be ingested - Normal tissues are not ingested because: 1. Most normal tissues have smooth surfaces - which resist phagocytosis - but if the surface is rough, the likelihood of phagocytosis is increased 2. Most natural substances of the body has protective protein coats - repels phagocytes - conversely, most dead tissues and foreign particles are rough and have no protective coats, which make them subject to phagocytosis. Foreign Ag + antibodies + C3 - when a foreign antigen enters the body, we mount an immune system by producing an antibody = stimulates the COMPLEMENT SYSTEM - complement system brings the Antigen-Antibody complex near the phagocyte - phagocyte destroys the combination - the process where the complement brings the antigenantibody complex near a phagocyte is called OPSONIZATION. MACROPHAGE - phagocytic - inactive monocytes in the blood - monocytes must first arrive in the tissue and transform to become MACROPHAGES before it can perform phagocytosis - active macrophages in tissues - they do not die in the tissues; they survive after doing their function - FIRST LINE OF DEFENSE - ACUTE/CHRONIC INFECTIONS MONOCYTE MACROPHAGE CELL SYSTEM (RETICULOENDOTHELIAL SYSTEM) ď§ strategically placed in PORTALS OF ENTRIES of microorganisms ďˇ Tissue macrophage in the SKIN and SUBCUTANEOUS TISSUES (Histiocytes) ďˇ Macrophages in the LYMPH NODES ďˇ Alveolar Macrophages in the LUNGS ďˇ Macrophages (Kupffer cells) in the LIVER sinusoids ďˇ Macrophages of the SPLEEN and BONE MARROW ď§ Both NEUTROPHILS and MACROPHAGES can kill bacteria by releasing BACTERICIDAL AGENTS: 1 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar BACTERICIDAL AGENTS Superoxide O2Hydrogen Peroxide H2O2 Hydroxyl ions OHH2O2 + Cl- -> (myeloperoxidase) -> hypochlorite “When tissue injury occurs, whether caused by bacteria, trauma, chemicals, heat, or any other phenomenon, multiple substances are released by the injured tissues and cause dramatic secondary changes in the surrounding uninjured tissues. This entire complex of tissue changes is called INFLAMMATION.” INFLAMMATION is characterized by: 1. Vasodilatation of the local blood vessels with consequent excess local blood flow. 2. Increased permeability of the capillaries. 3. Clotting of fluid in the interstitial spaces. -because the plasma is being pushed into the interstitial space -Plasma contains coagulation factors; thus, it can form a clot 4. Migration of large number of neutrophils and monocytes into the tissue. 5. Swelling of the tissue. 5 Cardinal Signs of INFLAMMATION: ďź the area inflamed will appear RED (RUBOR) ďź due to vasodilatation, there is release of HEAT (KALOR) ďź release of painful substances, causing PAIN (DOLOR) ďź increased permeability of the capillaries ď EDEMA (TUMOR) ďź LOSS OF FUNCTION What is the purpose of the inflammatory process? ď§ One of the first results of inflammation is to "wall off" the area of injury from the remaining tissues. The tissue spaces and the lymphatics in the inflamed area are blocked by fibrinogen clots so that after a while, fluid barely flows through the spaces. ď§ This walling-off process delays the spread of bacteria or toxic products. ď§ When neutrophils and macrophages engulf large numbers of bacteria and necrotic tissue, essentially all the neutrophils and many, if not most, of the macrophages eventually die. After several days, a cavity is often excavated in the inflamed tissues. It contains varying portions of necrotic tissue, dead neutrophils, dead macrophages, and tissue fluid. This mixture is commonly known as PUS. “The intensity of the inflammatory process is usually proportional to the degree of tissue injury.” RESPONSE DURING INFLAMMATION: ď§ Tissue MACROPHAGE is the FIRST LINE of defense against infection. because within minutes, the macrophages present in the Reticulo-endothelial system (RES) will be activated. ď§ NEUTROPHIL invasion of the inflamed area is a SECOND LINE of defense because within the first hour after the inflammatory process, INFLAMMATORY CYTOKINES (Tumor Necrosis Factor and Interleukin-1 - chemoattractants) will be secreted MARGINATION: process where the WBC’s attach to the walls of the endothelium. DIAPEDESIS: WBC’s squeeze through the pores of the capillaries. CHEMOTAXIS: inflamed tissues release chemicals that attract neutrophils and macrophages. ↓ FINAL EVENT: PHAGOCYTOSIS - ď§ TNF and IL-1 will attract the neutrophils to go to the inflamed area TNF and IL-1 also increase the expression of adhesion molecules in the endothelium called SELECTIN and IntraCellular Adhesion Molecule (ICAM) Selectin and ICAM binds to NEUTROPHIL causing the neutrophil to MARGINATE followed by Diapedesis, then Chemotaxis The second macrophage invasion into the inflamed tissue is the THIRD LINE of defense. ď§ BONE MARROW – increases its production of monocyte ď§ Monocytes ď go to the CIRCULATION ď then to the tissue as TISSUE MACROPHAGES 2 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar ď§ Increased production of granulocytes and monocytes by the bone marrow is the FOURTH LINE of defense. ďˇ Within 3-4 days, greatly increased production of neutrophils and monocytes by the bone marrow. ďˇ Activated Macrophage secrete cytokines: TNF, IL-1, GCSF, M-CSF (Granulocyte; Monocyte Colony Stimulating Factor) ďˇ Cytokines stimulate the bone marrow ď ↑production of WBC - Therapeutic Radiation procedures: radiotherapy for cancer (radiation is too much, enough to suppress the bone marrow ď (leukopenia) - Drugs: chlorampenicol (antibiotic), thiouracil (given to hyperthyroid), chemotherapeutic agents LEUKEMIA: uncontrolled production of WBC cancerous mutation of a myelogenous and lymphogenous cell (AML, ALL) Effects of Leukemia in the body: - metastatic growth of leukemic cells in abnormal areas of the body - WBC’s should only be in the BONE MARROW or in the BLOOD - Metastasis: WBC’s are found infiltrating the BONE - infections, severe anemia, bleeding - although WBC’s are excessively increased, they are IMMATURE - because of the over proliferation of the WBC’s in the bone marrow, RBC’s and platelets are displaced ď patient suffers from severe anemia and bleeding - metabolic starvation - cancer cells utilizing all the energy and nutrients of the body 3. CASE: 4. EOSINOPHILS - weak phagocytes - important role in ALLERGIC REACTIONS - role in PARASITIC INFECTIONS (WORMS) ↑Eosinophil count = Parasitic infection ↑Neutrophil = Bacterial infection BASOPHILS/ MAST CELLS - releases HEPARIN: prevents blood coagulation - releases HISTAMINE: involved in ALLERGIC REACTIONS PLEASE REMEMBER! Basophil and Mast Cells are associated closely with an immunoglobulin (IgE) Basophil + IgE (with antigen) = histamine (Histamine mediates allergic reactions) ďˇ When the specific antigen for the specific IgE antibody subsequently reacts with the antibody, the resulting attachment of antigen to antibody causes the mast cell or basophil to rupture and release large quantities of histamine, bradykinin, serotonin, heparin, slow-reacting substance of anaphylaxis, and a number of lysosomal enzymes. ďˇ These cause local vascular and tissue reactions that cause many, if not most, of the allergic manifestations. CLINICAL CORRELATION: LEUKOPENIA: ↓WBC count CAUSES: - massive infection - irradiation PLEASE REMEMBER! - Diagnostic Radiation (x-ray, CT-scan, MRI) is NOT enough to suppress the bone marrow and cause leukopenia 3 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar IMMUNOLOGY I. INNATE IMMUNITY “Early defense against infections” The INVADERS: - Bacteria - Viruses - Parasites (such as fungi, protista, worms) IMMUNITY ability of the human body to resist almost all types of organisms or toxins that tend to damage the tissues or organs ANTIGEN (Ag): antibody generation any molecule that can bind to the components of the specific immune response Components of Innate Immunity: i. Epithelial barriers - provides physical barrier to infection - killing of microbes by locally produced antibiotics - killing of microbes and infected cells by intraepithelial lymphocytes ii. Phagocytes - Neutrophils - Monocytes/Macrophages iii. ANTIBODY (Ab) family of defensive proteins the body makes when stimulated by an antigen CYTOKINES - substances, mostly proteins, secreted by cells affecting the behavior of nearby cells - ex: interleukins (IL); interferons (INF) - can be produced either by: ďź INNATE IMMUNITY o Macrophages, Natural Killer (NK) cells o Both secrete cytokines ďź ACQUIRED IMMUNITY o T lymphocytes INNATE IMMUNITY ď§ Phagocytosis by WBC’s and macrophages ď§ Skin ď§ Acid secretion of stomach ď§ Presence in the blood of certain compouns that attach to foreign substances and destroy them ď§ Lysozymes ď§ Complement system ď§ NK cells *already present, ready to protect you even on first encounter ACQUIRED IMMUNITY (Adaptive Immunity) ď§ Immunity developed due to previous exposure to invading agents such as bacteria, viruses, toxins, foreign tissues *lymphocytes are not ready protect you on first encounter *you have to be sick first; but once you have developed the protection, the immunity is extremely powerful that you might not even experience the second disease (chickenpox) or you might not even experience the disease at all (vaccination) Dendritic Cells - cells present in the skin; considered as bridge between innate and adaptive immunity - MECHANISM: organism traversed the skin ↓ dendritic cells (cannot destroy the bacterium) will carry the organism ↓ presents the organism to the lymphocyte in the lymphoid tissue (thus, bridging innate and adaptive immunity) iv. Natural Killer Cells are a class of lymphocytes that recognize infected cells, respond by: o killing these cells or o by secreting the macrophage activating cytokine interferon gamma (IFN-ϒ) When a macrophage ingested a microbe, macrophage cannot degrade the organism ↓ Macrophage will secrete cytokine interleukin-12 (IL-12) ↓ Attracts natural killer (NK) cell; it will sense macrophage needs help; secretes IFN-ϒ ↓ IFN-ϒ activates the macrophage (ACTIVATED MACROPHAGE: secretes TNF, IL-1 ď attracts neutrophils from the blood) ↓ Kills the phagocytized microbe (*Cytokines: interleukin-12; interferon gamma) 4 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar v. The Complement System - series of about 20 proteins, existing in a proenzyme form (INACTIVE) - once activated by the microorganism or antigen-antibody complex, it can eliminate the invading microorganism COMPLEMENT SYSTEM ď§ Once the microbe has escaped humoral immunity and has entered the cell, cell-mediated immunity will now take over o Two most predominant cells: ď§ Cytotoxic T-cell - directly kill the infected cell ď§ Helper T-cell - does not have the capability to degrade the cell - however, once activated, it can release cytokines which can: o activate macrophage ď cause inflammation o proliferation of B lymphocytes and cytotoxic T-cell and perform their actions ď§ Lymphocytes are also coming from the stem cell ď§ Once produced by the bone marrow, they are stored in the lymphoid tissues ď§ But before birth, stored in the lymphoid tissues and processed first in two organs: - THYMUS ď T-lymphocytes - FETAL BONE MARROW ď B-lymphocytes ď§ TWO PURPOSES OF PRE-PROCESSING OF THE LYMPHOCYTES IN THE THYMUS, FETAL LIVER AND BONE MARROW: 1. To achieve SPECIFICITY ď§ 1 antigen will react with only 1 lymphocyte or antibody ď§ Two Ways to activate: o MICROORGANISM activates C3 -INNATE IMMUNITY o ď§ Lymphocytes in the thymus and bone marrow are presented with thousands of antigens ď producing thousands of lymphocytes ď§ 1 antigen : 1 lymphocyte ANTIGEN-ANTIBODY COMPLEX activates C1 -ACQUIRED/ADAPTIVE IMMUNITY 2. Cytokines present in Innate Immunity Interleukin 12 (IL-12) Interferon gamma (IFN-ϒ) Interleukin 1 (IL-1) Tumor Necrosis Factor (TNF) To achieve TOLERANCE ď§ The lymphocytes and antibodies must not react with own cells ď§ Lymphocytes in the thymus and bone marrow are presented with own cells expected reaction: lymphocytes must not react Once the lymphocytes react with own cells, it will be destroyed II. ACQUIRED IMMUNITY a property of lymphocytes (T, B lymphocytes) TWO BASIC TYPES OF ACQUIRED IMMUNITY 1. CELL-MEDIATED IMMUNITY (T lymphocytes) = Activated lymphocytes ď§ Process of tolerance is only 90% perfect - explains the occurrence of AUTOIMMUNE DISEASES 2. HUMORAL IMMUNITY (B lymphocytes) = Antibodies MICROBE RESPONDING LYMPHOCYTES EFFECTOR MECHANISM FUNCTIONS HUMORAL IMMUNITY Extracellular microbes B lymphocytes Secretes antibody ď§ Block infections ď§ Eliminate extracellular microbes CELL-MEDIATED IMMUNITY Phagocytosed microbes in macrophage Helper T lymphocyte Intracellular microbes (ex. viruses) replicating within infected cell Cytotoxic T lymphocyte Activate macrophages to kill phagocytosed microbes Kill infected cells and eliminate reservoirs of infection 5 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar ď§ TWO BASIC TYPES OF ACQUIRED IMMUNITY CELL-MEDIATED IMMUNITY HUMORAL IMMUNITY (T lymphocytes) (B lymphocytes) ↓ ↓ Activated Lymphocytes Antibodies (directly kills the Helper T-cells (CD4) microbes; activation of - LYMPHOKINES/CYTOKINES complement system) - stimulation of growth and proliferation of cytotoxic T-cells and suppressor T-cells *upon recognition of - stimulation of B-cell growth and antigen, differentiation to form plasma B-lymphocytes cells and antibodies proliferate then - activation of macrophage differentiate to become: system - stimulatory effect on the helper ď§ Plasma cells T-cells (secretes antibodies) ď§ Cytotoxic T-cells (CD8) - directly attacks the cell ď§ ď§ Suppressor T-cells - subtype of helper T-cells - regulate/suppressive function on both cytotoxic (CD8) and helper T-cells (CD4) ď§ Memory T-cells - cause more rapid response on subsequent exposure to the same antigen *In both immunities, MEMORY CELLS are produced Memory B-cells i. CELL MEDIATED IMMUNITY: involves T-lymphocytes CD8 (Cytotoxic T-cell) - directly kills the infected cell ď§ Cytotoxic T-cells (CD8) and Helper T-cells (CD4) do not have the capability to recognize the antigen directly ď§ A cell must be presented first by an ANTIGEN PRESENTING CELL ď§ ANTIGEN PRESENTING CELLS: Dendritic cells, Macrophages, Blymphocytes o once the antigen presenting cell presents the antigen to either CD4 or CD8, both T-cells will proliferate, undergoing clonal expansion and the effector mechanism will proceed o CD8 – directly kills the organism o CD4 – produces cytokines that can stimulate B-lymphocyte, macrophage, cytotoxic T-cell ď§ Every time that B & T-lymphocyte undergo clonal expansion, memory cells are produced ď§ Once recognized by the T-cell, it will destroy both the antigen and antigen-presenting cell CD4 (Helper T-cell) - cannot kill the cell - releases Lymphokines/Cytokines = B lypmhocytes proliferate to produce antibody = antibody will kill the cell - Function of Lymphokines/Cytokines: o can activate the macrophage system, thus activating the inflammatory reaction o can stimulate the B-lymphocyte to differentiate into plasma cells and produce antibodies o can stimulate the growth and proliferation of both Cytotoxic T and Suppresor T cells o has stimulatory effect on the Helper T-cells themselves ď§ The CYTOKINES released by HELPER T-CELLS modulate the whole immune response. Without them, the whole immune system will be paralyzed. CASE: HIV/AIDS - attacks CD4 (Helper T-cells) - full blown AIDS patient usually dies from overwhelming infection because their immune system is paralyzed due to the absence of cytokines coming from the helper T-cells [(Immu1)video- 16:23-17:50] 6 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar CYTOKINES OF ACQUIRED IMMUNITY: produced by T lymphocytes - Interferon gamma (IFN-ϒ): produced by NK cells; also produced by CD4, CD8 T-cells - Interleukin-2 (IL-2) - Interleukin-4 (IL-4) - Interleukin-5 (IL-5) ii. HUMORAL IMMUNITY: involves B-lymphocytes ď§ Unlike T lymphocytes, B lymphocytes can distinguish a microbe or an antigen ď§ If B lymphocytes react with the microbe or an antigen, it is only activated ď§ It needs cytokines released by Helper T-cells (CD4) before they can proliferate as plasma cells ď produce antibody, memory Bcells -activates the complement system - cytolytic (can destroy the cell) - crosses the placenta (anti-RH IgG) CASE: Hepatitis - jaundiced, (+)HBS antigen - IgM, IgG titers to determine whether it is acute or chronic ď§ If ACUTE, the patient will get well even if without medication; self-limiting ď§ If CHRONIC, patient can suffer with liver cancer or cirrhosis IgA: second most abundant - chief immunoglobulin in EXOCRINE secretions (breast milk) IgE: mediates certain allergic reactions - attached to basophils and mast cells IgD: very small amount - attaches to surface of B-lymphocyte - helps in antigen recognition by B-cells MECHANISM OF ACTION OF ANTIBODIES: 1. Direct attack on the invaders through ď§ Agglutination ď§ Precipitation ď§ Neutralization ď§ Lysis * If not enough, the complement system is activated 2. Activation of the complement system Configuration of an antibody ď§ COMPLEMENT SYSTEM VARIABLE PORTION - the portion that attaches specifically to a particular type of antigen - it varies according to the antigen to which the antibody will react EXAMPLE: IgM antibody for chicken pox; IgM antibody for measles - the variable portion for chicken pox, is different from the variable portion for measles - but they are both IgM ď§ CONSTANT PORTION - it is used in its attachment to the complement system - diffusivity of antibody to tissues - adherence of antibody to tissues - attachment to the complement (most important function) CLASSES OF ANTIBODIES: o IgM: first to appear in ACUTE INFECTION/ 1 antigen stimulus - activates the complement system - cytolytic (can destroy the cell) - does NOT cross the placenta o IgG: first to appear in CHRONIC INFECTION/2 antigen stimulus -most abundant (75%) ď§ Antigen-antibody complex stimulates C1 =products are produced resulting to elimination of the infection via: - Lysis of cells - Chemotaxis of WBC’s - Activation of inflammation - Opsonization - Ag-Ab complex causes the complement -> complement brings the complex to the phagocyte -> phagocytosis Question: What part of the antibody stimulates the Complement System? Answer: “Constant” 7 BLOOD (WBC & IMMUNOLOGY) Dr. Olivar MEMORY B-CELLS ď§ FIRST EXPOSURE (blue): mounting of immune response is delayed and level is low ď§ SECOND EXPOSURE (red): since memory cells are already developed, response is rapid, level is high, long-lasting; - at second exposure, patient might not even manifest the disease because at the onset, he is already protected - PRINCIPLE being used in VACCINES ď§ ď§ ď§ ď§ ACQUIRED IMMUNITY ACTIVE IMMUNITY PASSIVE IMMUNITY Produced by individuals in ď§ Antibodies derived from response to natural or another either by natural artificial stimulation transfer or by injection Generates own antibodies ď§ Given pre-formed antibodies Chickenpox infection ď§ Newborn MMR vaccination ď§ Immunoglobulins ADVANTAGE: immunity is lifelong once produced DISADVANTAGE: it takes time before you are protected; you get the disease first before producing the antibodies ď§ ď§ On first exposure, produces a response. On second exposure, response is greater INFECTIONS CELL-MEDIATED HUMORAL IMMUNITY IMMUNITY (B lymphocytes) (T lymphocytes) ď§ Transplant rejection ď§ Antibodies against bacteria ď§ Destruction of cancer and viruses cells ď§ Fungi, viruses, Ex. Measles, Mumps, Chicken parasites, bacteria (ex. pox TB –most common) ADVANTAGE: immediately protected DISADVANTAGE: the pre-formed antibody is short-lived ď§ We do not get diseases from the vaccine because the virus is INACTIVATED. AUTOIMMUNE DISEASES - because the process of immune tolerance is not perfect (90%) - some individuals generate autoimmune antibodies CASE: Myasthenia Gravis - Acetylcholine receptors are destroyed - Cannot generate an end-plate potential =weakness Allergy/Hypersensitivity ACUTE: due to IgE CHRONIC: due to cytotoxic T-cells (CD8) -Urticaria -Allergic Rhinitis -Bronchial Asthma 8 PHYSIOLOGY – A Blood Physio pt. 3 ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ Dr. Vienna Blessie N. Baloloy (VBNB) I. Intro to the Immune System Components Our bodies have a special system for combating the different infectious and toxic agents. This system is composed of blood leukocytes (WBC) & tissue cells derived from WBC. They work together in two ways to prevent disease: o Destroying invading bacteria or viruses by phagocytosis o Forming antibodies and sensitized lymphocytes which may destroy or inactivate the invader Function of Leukocytes o Destroy invading agents via phagocytosis o Formation of antibodies and sensitizing lymphocytes – parts of our bodies are always exposed to bacteria or invading agents Types of invaders: o Bacteria o Viruses o Parasties such as fungi, protista & worms II. White Blood Cells (WBCs) Also known as leukocytes Cells which protect our bodies from invading agents Located in blood Type ďˇ ďˇ Description Polymorphonuclear Neutrophils Polymorphonuclear Eosinophils Polymorphonuclear Basophils Monocytes Lymphocytes Plasma Cells Normal Percentage 62.0% Granulocytes and are called “Polys” (multiple nuclei) 2.3% 0.4% 5.3% 30.0% Table 3. Location of WBCs Granulocytes & Monocytes Lymphocytes Lymph Nodes (commonly found here); Location Bone marrow and the Tonsils; Thymus; Circulations Appedix; Peyer’s patches (packets in the GIT) ďˇ ďˇ Table 1. Main Classes of WBC Granulocytes Agranulocytes resposible in procduces engulfing antibodies; bacteria and Neutrophils Lymphocytes regulates cellular debris; the immune most numerous resoponse in the blood capable of hypersensitivity Plasma Basophils reaction and Cells release of histamine phagocytic involved in cells; parasitic antigenic Eosinophils Monocytes infection; cells Allergic (antigen response processing) Lec 12 - 27 Aug 2015 Table 2. Six Types of WBCs and their Percentage ďˇ ďˇ ďˇ ďˇ Leukocytes protect us from infection by o Phagocytosis o Formation of antibodies & sensitizing the lymphocytes Lymphocytes in general o Mostly stored in various lymphoid tissues, except for a small number that are temporarily being transported in the blood. Granulocytes and monocytes o protect body against invading organisms mainly by ingesting them (Phagocytosis) o Formed only in the bone marrow o They are stored within the marrow until they are needed in the circulatory system Lymphocytes and plasma cells o Formed mainly in various lymphogenous tissues (lymph glands, spleen, thymus, tonsils, Peyer’s patches [at gut wall], etc.) III. Genesis of WBCs Myelocytic Lineage o Begins with Myeloblast (1) Lymphocytic Lineage o Begins with Lymphoblast Normal WBC Count:5-10 x 109/L; A normal adult human being has ~7000 WBC per microliter of blood o Leukocytosis – abnormal increase in the number of WBC’s o Leukopenia – WBC count less than normal Blood cells all came from the bone marrow which contains the pluripotent hematopoietic stem cells which will eventually differentiate into different types of cells such as your granulocytes, monocytes and lymphocytes. Figure 1. Promyelocyte and its descendant cells. Mari, Merene MD-1C 2019 Page 1 of 13 PHYSIOLOGY – A Blood Physio pt. 3 ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ Dr. Vienna Blessie N. Baloloy (VBNB) III. Life Span of the WBC Granulocytes o 4-8 hrs circulating the blood o 4 to 5 days in tissues where they are needed o Can be shortened secondary to serious tissue infections because granulocytesproceed evem more rapidly to the infected area, perform their function, and in the process, are themselves destroyed Monocytes o 10 to 20 hrs in blood before going to tissues o They swell and become larger in size, once they are in the tissue and becomes the tissue macrophagesthat can live for months unless destroyed during phagocytic response IV. Neutrophil and Macrophage Defense Both attack and destroy invading bacteria, viruses, and other injurious agents. Neutrophils are mature cells that can attack and destroy bacteria even in the circulationg blood, while tissue macrophages begin life as blood monocyes (immature cells) wth little ability to fight infectious agents at that time Margination – Lining up to the capillary walls Diapedesis – the way of passing through blood capillaries even it is smaller than the neutrophils and monocytes Amoeboid motion – movement of both neutrophil and macrophages through the tissues Chemotaxis – chemical attraction of both neutrophil and macrophages to move to the source (inflamed tissue areas). It depends on concentration gradient of the chemotactic substance. o Caused by: ď§ Bacterial or viral toxins ď§ Degenerative products of the inflamed tissues themselves ď§ Several reaction products of the complement complex activated in inflamed tissues ď§ Several reaction products caused by plasma clotting in inflamed area Lec 12 - 27 Aug 2015 Phagocytosis ďˇ Is a specific process ďˇ Most important function of neutrophils and macrophages ďˇ Selective of the material that is phagocytised ďˇ The body’s cells is protected from intracellular digestion because: o Most normal tissues have a smooth surface which resists phagocytosis o Most natural substance of the body has a protective protein coat which repels the cells involved in phagocytosis o Ehancement of phagocytosis by the Forgein Antigen + Antibodies + Complements (Opsonization) ď§ Antibodies adheres to the infectious agents membrane that makes it susceptible to phagocytosis Table 4. Phagocytosis by neutrophils vs phagocytosis by macrophages Phagocytosis by neutrophils Enter tissues as mature cells already Immediately begin phagocytosis Phagosomes (freefloating phagocytic vesicle) but not capable of engulfing larger particles 1neutrophil : 3 to 20 bacteria before it becomes inactivated and die Phagocytosis by macrophages Enter tissues as immature monocytes Stronger than neutrophil once activated by immune system Has the ability to engulf bigger/ larger particles (such as whole RBCs, malarial parasites) 1 macrophage : up to 100 or more bacteria, they can extrude residual products and often survive and function for many more months Figure 3. Phagocytes. Neutrophils ďˇ Considered as a phagocytic cell; it can ingest up to 3-5 bacterial molecule, which is its maximum capacity; eventually they will die ďˇ Active in the blood ďˇ It is the body’s 2nd line of defense against invading microorganisms ďˇ Commonly seen during actude infection ďˇ Hypersegmented/ Lobulated nucleus Figure 2. Defense mechanism of tissue or vessel injury. Mari, Merene MD-1C 2019 Page 2 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) ďˇ Your macrophages is known as the monocytes once they are in the blood, however once these monocytes migrate into the infected tissue they eventually enlarged and become macrophages Macrophages ďˇ First line of defense during infection ďˇ Usually active also in the blood, but once in the tissue it can engulf more bacteria as compared to the neutrophils o Up to 100 bacterial cells before cell death ďˇ Can ingest larger cellular debris/particles Reticuloendothelial System ďˇ Also known as the Monocyte-Macrophage Cell System ďˇ A collective term for the combination of the special endothelial cells found in the thymus together with the other fixed tissue macrophages and the mobile macrophages ďˇ Numerous parts of the body contain macrophages, this explains why when we are exposed to bacteria we do not immediately get sick o Langerhans cells in the skin and subcutaneous tissue o Sinus histiocytes in the lymph nodes o Alveolar Macrophages/ Dust cells in the lungs o Von Kuppfer cells in the liver sinusoids o Monocytes in the Bone Marrow ďˇ Once the neutrophils and macrophages ingest invading agents their intracellular enzymes kill the bacteria. When lysosomal enzymes fail, bactricidal agents such as superoxides kills most bacteria. These include hydrogen peroxide, hydroxyl ions, and myeloperoxidase. V. Inflammation ďˇ Series or complex of tissue changes that occur in the instance of injury caused by bacteria, trauma, chemicals, heat or any other phenomenon. ďˇ Trauma can lead to local vasodilation, which increases blood flow and capillary permeability, allowing some fluid in the blood to diffuse into the tissues ďˇ Vasodilation would lead to an increase in blood flow thus a higher number of neutrophils and monocytes o There will then be the presence of margination, and because of increase capillary permeability there would be enough space for the monocytes and neutrophils to pass through the membrane (diapedesis). Once outside these cells migrated towards the site of infection (chemotaxis). ďˇ Usually these responses to trauma are localized because of fibrinogens ďˇ Some fluid contents of the blood such as the plasma also leak out. The plasma contains antibodies, proteins, and clotting factors such as fibrinogens. Once these fibrinogens become activated, the tissue injury is isolated (“walled off”) and the spread of the bacteria and toxic products is delayed. ďˇ Products that cause inflammation: o Histamine Mari, Merene MD-1C 2019 ďˇ ďˇ ďˇ Lec 12 - 27 Aug 2015 o Bradykinin o Serotonin o Prostaglandins o Reaction products of complement system o Reaction products of blood clotting system o Lymphokines (released by sensitized T cells) Pus – contains dead tissue cells, dead phagocytic cells The intensity of the inflammatory process is proportional to tissue injury In summary, inflammation is characterized by: 1. Vasodilatation of the local blood vessels with consequent increase local blood flow 2. Increase permeability of the capillaries 3. Clotting of fluid in the interstitial spaces 4. Migration of large number of neutrophils and monocytes into the tissue 5. Swelling of the tissue cells Cells involved in Inflammation 1. Tissue Macrophage ďˇ first line of defense against infection ďˇ Within minutes after inflammation begins, these macrophages are activated to control the invading agent; after an hour or so the neutrophils would then migrate to the site of infection via the release of inflammatory cytokines. ďˇ Number are not great, but they are lifesaving ďˇ Effects o Rapid enlargement of each cell o Break loose from their attachments and become mobile 2. Neutrophils ďˇ Act within first hour or so ďˇ Large in number, invading the inflamed area (caused by the inflammatory cytokines) ďˇ Reactions: o Increase in the expression of selectin and intracellular adhesion molecules found in the capillary walls or in the endothelial walls; these molecules have a high capacity in binding with the interleukin-8 receptors found in the neutrophils. o Once there is numerous selectin & intracellular adhesion molecules they will induce margination. o Loosening of the attachment of each endothelial cell, allowing passage of the neutrophils (diapedesis) o Invasion of infected tissue via chemotaxis Page 3 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) Lec 12 - 27 Aug 2015 VI. Clinical Correlations ďˇ Figure 4. Migration of Neutrophils 3. 4. 5. 6. Second Macrophage Invasion ďˇ Third line of defense ďˇ buildup of macrophages in the inflamed tissue area is much slower than that of neutrophils Increased Granulocyte and Monocyte Production ďˇ Fourth line of defense ďˇ Only noticeable after the 3rd of 4th day from the time of inflammation; here there is a marked increase in the number of leukocytes and monocytes (takes 3 to 4 days to mature and leave the bone marrow) ďˇ Activated macrophage releases a cytokinase called TNF (tumor necrotic factor) and interleukin-1 together with other colony stimulating factors, the bone marrow will be stimulated to produce more leukocytes and monocytes. Eosinophils ďˇ Release hydrolytic enzymes from their granules (which are modified lysosomes) ďˇ Release highly reactive forms of oxygen that are lethal to parasites ďˇ Release highly larvicidal polypeptide “major basic protein” ďˇ But doubtful that they are significant in protecting against the usual types of infection ďˇ Trichinosis – parasitic diseases that causes eosinophilia. Results from invasion of the body’s muscles by the Trichinella parasite (“pork worm”) after eating undercooked infested pork Basophils or Mast Cells ďˇ Similar to monocytes o Basophil in blood, mast cells in tissue ďˇ They release heparin, histamine, bradykinin, and serotonin o Heparin – are responsible for the anticoagulant factor; they prevent the coagulation of the blood o Histamine – incharge of the allergic reaction Mari, Merene MD-1C 2019 Leukopenia o WBC count less than normal o Bone marrow produces very few WBC o Leaves the body unprotected against many bacteria o Occurs due to frequent exposure to irradiation (gamma or x-rays) o Exposure to drugs such as : chlorampehnicol (antibiotic) or usahe of thiouracil (for hyperthyroidism) ďˇ Leukemia o increased production of WBC o uncontrolled production of WBC secondary to the cancerous mutation of a myelogenous or lymphogenous cells o Types a) Lymphocytic Leukemia ďˇ Caused by cancerous production of lymphoid cells ďˇ Beginning the spread from a lymph node or other lymphocytic tissue and spreading to other areas of the body b) Myelogenous Leukemia ďˇ Caused by cancerous production of young myelogenous cells in the bone marrow and then spreads throughout the body so hat WBC are produced in many extramedullary tissues (especially lymph nodes, spleen and liver) ďˇ The cancerous process occasionally produces partially differentiated cells, resulting in what might be called o Neutrophilic leukemia o Eosinophilic leukemia o Basophilic leukemia o Monocytic leukemia Note: The more undifferentiated the cell the more acute is the leukemia, often leading to death within a few months if untreated. Consequences and Effects of Leukemia ďˇ Severe bone pain ďˇ Prone to infection due to the fact that the released cells are undifferentiated or immature thus nonfunctional (this determines how acute the leukemia is) ďˇ Severe anemia ďˇ Metastatic growth of leukemic cells in abnormal areas of the body ďˇ Displacement of bone marrow and lymphoid cells by the non-functional leukemic cells ďˇ Development of infection, severe anemia ďˇ Bleeding tendency caused by thrombocytopenia Page 4 of 13 PHYSIOLOGY – A Blood Physio pt. 3 ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ Dr. Vienna Blessie N. Baloloy (VBNB) IMPORTANT EFFECT: excessive use of metabolic substrates by the growing cancerous cells that reproduce new cells so rapidly = metabolic starvation (thinness) Energy of patient is then greatly depleted, Excessive utilization of amino acid by the leukemic cells causes rapid deterioration of normal protein tissues of the body VII. Immunology Immunity – it is the ability of the human body to resist almost all types of organisms or toxins that tend to damage the tissue or organs Antigen (Ag) – antibody-generating cells o Any molecule that can bind to the components of the specific immune response Antibody (Ab) – formed by two heavy chains and two light chains o A family of defensive proteins the body makes when stimulated by an antigen Cytokines – are substances, mostly composed of proteins, secreted by cells affecting the behavior of nearby cells o Examples: Tumor Necrotic Factor (TNF) & Interleukins (IL) secreted by activated macrophages, which induce the bone marrow to produce more leukocytes and monocytes; Interferons (INF) Lec 12 - 27 Aug 2015 o o o Acts as a physical barrier to infection Also produce locally produce antibiotics which kills the microbes Contain intraepithelial lymphocytes which kills microbes and infected cells Figure 6. Epithelial barriers. 2. Acquired or Adaptive Immunity ďˇ Results from exposure to antigenic material (bacteria, toxins, etc) ďˇ Engages the action of T lymphocytes ďˇ After exposure normally our bodies will develop antibodies or activate T lymphocytes into effector T cells ďˇ Often requiring weeks or months to develop immunity ďˇ Caused by a special immune system that forms antibodies and/or activated lymphocytes that attack and destroy the specific invading organism or toxin. ďˇ Immunization – treatment process to protect human beings against disease and toxins Figure 5. Parts of an antibody molecule. Types of Immunity 1. Innate Immunity ďˇ Inborn immunity ďˇ Utilizes macrophages and natural killer cells ďˇ In charge during early stages of defense against infection ďˇ Phagocytosis by WBC’s and macrophages ďˇ Skin ďˇ Acid secretion of stomach ďˇ Presence in the blood of certain compounds that attach to foreign substances and destroys them o Lysozymes o Complement System o Natural Killer Cells ďˇ Includes epithelial barriers Mari, Merene MD-1C 2019 Figure 7. Innate vs. acquired immunity VIII. Acquired Immunity Humoral Acquired Immunity ďˇ B-cell immunity (because B lymphocytes produce the antibodies) ďˇ Development of circulating antibodies, which are globulin molecules in the blood plasma that are capable of attacking the invading agent. ďˇ Once the invading cells are presented to the B lymphocytes they then would further differentiate into Page 5 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) plasma cells and would the produce or secrete antibodies which can block the infection and eliminate those invading agents Cell-Mediated Acquired Immunity ďˇ T-cell immunity (because activated lymphocytes are T Lymphocytes) ďˇ Once the T lymphocytes are exposed to the different macrophages or invading cells, these naive lyphocytes would be activated or become effector agents o Helper T cells – activated macrophages which kills phagocytosed microbes; the all so activates reproduction of same cells o Cytotoxic T cells – kill directly the infected cells and elimates the source of your infection ďˇ Achieved through the formation of large numbers of activated T lymphocytes that are specifically crafted in the lymph nodes to destroy the foreign agent ďˇ Lec 12 - 27 Aug 2015 Both react highly specifically against specific antigens o Role of Lymphocyte Clones o Exposure to antigen will become activated T and B lymphocytes which in turn react highly specifically against the particular types of antigens that initiated their development o Clone of lymphocyte – general term used to all different lymphocytes that are capable of forming one specific antibody or T cells that are activated by a specific antigen. o Each clone of lymphocyte is responsive to only a single type of antigen (or to several similar antigens that are almost exactly the same stereochemical characteristics) Figure 9. Lymphocyte differentiation Figure 8. Basic Types of Acwuired Immunity Lymphocytes ďˇ Located mostly extensively in the lymph nodes, but they are also found in special lymphoid tissues such as spleen, submucosal areas of GIT, thymus, bone marrow. o Lymphoid tissue of GIT – immediately exposed to antigens invading from the gut o Lymphoid tissue of the throat and pharynx (tonsils and adenoids) – are located to intercept antigens that enter upper respiratory tranct o Lymphoid tissue in the lymph nodes – exposed to antigens that invade the peripheral tissues of the body o Lymphoid tissue of spleen, thymus, bone marrow – plays the specific role of intercepting antigenic agents that have succeeded in reaching the circulating blood ďˇ Both are derived originally in embryo from pluripotent hematopoietic stem cells that form common lymphoid progenitor cells as their most important offspring as they differentiate. Mari, Merene MD-1C 2019 T Lymphocytes ďˇ Responsible for forming the activated lymphocytes that provide “cell-mediated” immunity ďˇ Formation o Originate from bone marrow o Lymphoid progenitor cells first migrate to Thymus gland o Preprocessed in Thymus gland o Designate the role of the Thymus (cell mediated immunity) ďˇ The thymus makes certain that any T lymphocytes leaving the thymus will not react against proteins or other antigens that are present in the body’s own tissues HOW? thymus selects which T lymphocytes will be released by first mixing them with virtually all the specific “self-antigens” from the body’s own tissues. If a T lymphocyte reacts, it is destroyed and phagocytised (90% of the cells) instead of being released to the blood. ďˇ Have surface receptor proteins (aka T-cell markers) o Acts like antibodies of B lymphocytes which are also highly specific for one specified activating antigen. ďˇ Role of the T Cells in activation of the B Lymphocytes o Most antigens activate both T and B lymphocytes o Some of the T cells formed are called: ď§ Helper T Cells ď§ Secretes specific substance : lymphokines ď§ Activate the specific B lymphocytes Page 6 of 13 PHYSIOLOGY – A Blood Physio pt. 3 ďˇ Dr. Vienna Blessie N. Baloloy (VBNB) Special Attributes of the T-Lymphocyte System - Activated T Cells and Cell-Mediated Immunity o Release of activated T cells from lymphoid tissue and formation of memory cells ď§ Instead of releasing antibodies, whole activated T cells formed and released into the lymph. ď§ T Lymphocyte memory cells are formed in same way as B memory cells in the antibody system Lec 12 - 27 Aug 2015 Nice to know: Three Major types on antigen presenting cells 1. Macrophages 2. B Lymphocytes 3. Dendritic cells (most potent of the 3), only action is to present antigens to T cells Antigen Presenting cells (epithelium) Antigens Lymphoid Tissues T Lymphocytes ďˇ Figure 10. Activation of T Cells ďˇ Antigen-Presenting Cells, MHC Proteins, and Antigen Receptors on the T Lymphocytes o Antigenic specific o Acquired immune responses usually require assistance from T cells to begin the process. o T cells play a major role in actually helping to eliminate invading pathogens o T lymphocytes only respond to antigens when they are bound to specific molecule MHC proteins on the surface of antigen-presenting cells. ďˇ Dendritic Cells – called as antigen presenting cells because these cells in the spleen will engulf the invading cells which then migrate and mature, ultimately presenting the antigen in the lymphoid tissue which then would activate the T cells. Natural Killer Cells – a class of lymphocytes that recognize infected cells, and respond by killing these cells and by secreting the macrophage activating cytokine IFN-Ë o Can kill infected cells o Produce or relaese IFN - Ë which enhances other phagocytic cell function Figure 12. Dendritic cells. Figure 11. Pivot Role of Helper T cells. Major Histocompatibility Complex (MHC) Mari, Merene MD-1C 2019 Several Types of T cells and their functions ďˇ Regulatory T cells o Helper T cells ď§ Most numerous 3/4th of all the 3 types Page 7 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) Lec 12 - 27 Aug 2015 ď§ o o Serve as major regulatory of virtually all immune functions ď§ Lymphokines ďˇ Stimulation of growth and proliferation of ďˇ Cytotoxic T cells and suppressor T cells ďˇ Stimulation of B cell growth and differentiation to form plasma cells and antibodies ďˇ Activation of the macrophage system ďˇ Stimulatory effect on the Helper T cells ďˇ Interleukin-2 (strong stimulator effect in causing growth and proliferation of both cytotoxic and suppressor T cells) ďˇ Interleukin-3 ďˇ Interleukin-4, 5 and 6 (potent effects on the B cells that they have been called B-cell stimulating factors or B-cell growth factors) ďˇ Granulocyte-monocyte colony-stimulating factor ďˇ Interferon ÉŁ Suppressor T cells ď§ Capable of suppressing the functions of both cytotoxic and helper T cells ď§ Has an important role in limiting the ability of the immune system to attack a person’s own body tissues – immune tolerance Cytotoxic T cells ď§ Direct-attack cell that is capable of killing microorganisms ď§ At times, kill even some of the body’s own cells ď§ After killing the attacked cell, they pull away from it and kill more cells ď§ Perforins = literally produces punch round holes in the membrane of the attacked cell ď§ Immune regulator Figure 14. Direct destruction by cytotoxic T cells. ď§ o T Cells CD4 is a direct attack cell; once this cell is attacked to the antigen presenting cell these T cells will secrete a protein call perforin. These proteins perforate the walls of the antigen, which would induce cell lysis. Memory T cells ď§ Causes more rapid response on subsequent exposure to the same antigen Figure 15. Cytokines or Acquired Immunity Figure 13. Helper and Cytotoixic T cells. Trivia: In HIV we check the levels of CD4 & CD8.When we monitor HIV we focus on the levels of CD4, since the body can no longer produce antibodies and CD4 acts to boost the ability of other phagocytic cells and its own selfreproduction. Once the levels of CD4 drops, the HIV patient becomes more susceptible to infection, thus they develop autoimmune diseases. Mari, Merene MD-1C 2019 B Lymphocytes ďˇ Responsible for forming antibodies that provide “humoral” immunity ďˇ Formation o Lymphoid progenitor cells first migrate and preprocessed at liver during mid-fetal life then in the Bone marrow in late fetal life and after birth ďˇ Actively secrete antibodies that are the reactive agents. ďˇ Reactive agents – large protein molecules capable of combining with and destroying the antigenic substance ďˇ Have greater diversity than T lymphocytes Trivia: It was first discovered in birds, which have a special preprocessing organ called the bursa of Fabricius. = reason that they are called “B” Lymphocytes to designate the role of the bursa. ďˇ Plasma cells form the antibodies through an antigen that activate only the lymphocytes that have cell surface Page 8 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) receptors that are complementary and recognize a specific antigen. o HOW: B lymphocytes specific for the antigen immediately enlarge and take on the appearance of lymphoblasts. Some of these lymphoblasts further differentiate to form plasmablasts which are precursors of plasma cells. ď§ Mature plasma cell – produces gamma globulin antibodies which are then secreted into the lymph and carried to the circulating blood ďˇ ďˇ Lec 12 - 27 Aug 2015 Role of Macrophages in the activation process of B Lymphocytes o Most invading organisms are first phagocytised and partially digested by the macrophages, and the antigenic products are liberated into the macrophage cytosol o These macrophages then pass the antigens by cellto-cell contact directly to the lymphocytes, thus leading to activation of the specified lymphocytic clones. o Secretes activating substance interleukin-1, that promotes still further growth and reproduction of the specific lymphocytes Nature of the Antibodies o They are gamma globulins called immunoglobulin (Ig) o Constitute about 20% of plasma proteins o Composed of combination of light and heavy polypeptide chains. ď§ Most are two light and two heavy chains ď§ Variable portion – the portion that attached specifically to a particular type of antigen ď§ constant portion o Diffusivity of Ab to tissues o Adherence of Ab to tissues o Attachment to the complement (activating) o Each heavy chain is paralleled by a light chain at one of its ends, forming a heavy-light pair Figure 16. Formation of specific antibodies from specific antigen. Difference Between Primary Response and Secondary Response ďˇ Other lymphoblasts formed by activation of a clone of B lymphocytes do not become plasmablasts. They become new B Lymphocytes similar to those of the original clone but are greatly enhanced. o These are called memory cells which remain dormant until activated once again by a new set but same antigen. ďˇ Secondary response is then more rapid and more potent antibody response as compared to the primary response. Figure 18. The Nature of an Antibody ďˇ Specificity of Antibodies o Secondary to unique structural organization of amino acids in variable portions of both the light and heavy chains ď§ HOW: amino acid organization has a different steric shape for each antigen specificity, so whe an antigen comes in contact with it, multiple prosthetic groups of the antigen fit as a mirror image with those of the antibody, thus allowing rapid and tight bonding between the antibody and the antigen. ď§ Hydrophobic bonding ď§ Hydrogen bonding ď§ Ionic attraction ď§ Van der waals forces Figure 17. Primary vs. Secondary response. Mari, Merene MD-1C 2019 Page 9 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) Lec 12 - 27 Aug 2015 Where Ka = affinity constant or measure of high tightly the antibody binds with the antigen Table 5. Classes of Antibodies Ab IgM IgG IgA IgD IgE ďˇ Properties Large share of antibodies formed during the primary response are of this type; pentamer have 10 binding sites that make them exceedingly effective in protecting body even there are not many IgM; (recent/acute infection) st 1 to appear in 1° antigen stimulus/ acute activates the complement system cytolytic does not cross the placenta Bivalent antibody and constitute about 75% of antibodies of normal person (most abundant; previous infection) smaller st 1 to appear in 2° antigen stimulus / chronic activates the complement system cytolytic crosses the placenta For mucosal immunity nd - 2 most abundant - chief Ig in exocrine secretions (saliva; semen; vaginal fluid; colostrum in breast milk) 1% only, usually coexpressed with another cell surface antibody (IgM); binds to basophils and mast cells (antimicrobial factors to respiratory immunity) - helps in Ag recognition by B-cells Constitutes only a small percentage of the antibodies but is especially involved in allergy - high propensity to attach to mast cells, which are responsible for the body’s hypersensitivity reactions Mechanism of Action of Antibodies o By direct attack on the invader o Activation of the “complement system” that has multiple means of destroying the invader Table 6. Direct Action of Antibodies on Invading Agents Agglutination Multiple large particles with antigen on their surfaces are bound together into a clump Precipitation Molecular complex of soluble antigen and antibody becomes large that it is rendered insoluble and precipitates Neutralization The antibodies cover the toxic sites of the antigenic agent Lysis Some antibodies occasionally capable of directly attacking membranes of cellular agents that cause rupture of the agent Mari, Merene MD-1C 2019 Figure 19. Attachment of specific antigens and specific antibodies Complement System for Antibody Action ďˇ is a made up of 20 proteins ďˇ usually seen in our plasma ďˇ Once there is antigen-antibody complex reaction this system would be activated (classical pathway): o C3B: will increase optimation or the phagocytic cells o C3a, C4a, C5a: will activate the mast cells and neutrophils ď§ Important because these cells when they rupture would release histamine which can cause vasodilatation increaseing WBC migration o C5b C7, C8, C9: causes rupture or lysis of cells Figure 20. Classic Pathway of Complement ďˇ Classic Pathway o Initiated by an antigen-antibody reaction o Activation of the proenzyme C1 o Formation of Enzyme C1 o From a small beginning, an extremely large “amplified” reaction occurs. Multiple end products are formed and several of these cause important effects that help to prevent damage to the body’s tissues caused by the invading organism or toxin. o Important Effects: ď§ Opsonization and phagocytosis ďˇ C3b strongly activates phagocytosis by both neutrophils and macrophages, causing these Page 10 of 13 PHYSIOLOGY – A Blood Physio pt. 3 ď§ ď§ ď§ ď§ ď§ ď§ ďˇ Dr. Vienna Blessie N. Baloloy (VBNB) cells to engulf the bacteria to which the antigen-antibody complexes are attached. (opsonization) Lysis ďˇ One of the most important of all the products of the complement cascade is the lytic complex, whis is combination of multiple complement factors and designated C5b6789. ďˇ Has direct effect of rupturing the cell membranes of bacteria or other invading organisms Agglutination ďˇ Complement products also change the surfaces of invading organisms, causing them to adhere to one another promoting agglutination Neutralization of viruses ďˇ Complement enzymes and other complement products attack the structures of some viruses that render them nonvirulent Chemotaxis ďˇ C5a initiates chemotaxis of neutrophils and macrophages Activation of mast cells and basophils ďˇ C3a, C4a, C5a activate mast cells and basophils ďˇ Release of histamine, heparin, etc into the local fluid ďˇ Causes increase local blood flow, increase leakage of fluid and plasma protein into tissue, inactivatation or immobilization of the antigenic agent. Inflammatory Effects ďˇ The already increased blood flow to increase still further ďˇ Capillary leakage of proteins are increased ďˇ Interstitial fluid proteins coagulate in tissue spaces, thus preventing movement of invading organism through the tissues Figure 21. Phases of Adaptive Immune Responses Table 7. Basic Types of Acquired Immunity and their responses Cell Mediated Immunity Humoral Immunity (T Lymphocytes) (B Lymphocytes) Activated Lymphocytes Antibodies ďˇ Fungi, Viruses, Parasites, ďˇ Antibodies against Bacteria e.g. TB bacteria and viruses e.g. ďˇ Destruction of Cancer measles; mumps and; Cells chicken pox ďˇ Transplant Rejection Table 8. Acquired Immunity. Active Immunity ďˇ Produced by individuals in response to natural or artificial stimulation ďˇ Chickenpox infection ďˇ MMR vaccination ďˇ ďˇ Memory B Cells o Initial/primary antigen exposure there is a delayed reaction, weaker in potency and shorter duration o Once the memory B cells are formed; upon exposure to the antigen there is an immediate, antibodyantibody reaction, higher potency and longer duration o Explains the principle of immunization ďˇ Mari, Merene MD-1C 2019 Lec 12 - 27 Aug 2015 Passive Immunity ďˇ Antibodies are derived from another either by natural transfer (maternal) or by injection ďˇ Newborn ďˇ Immunoglobin IX. Allergy and Hypersensitivity An important undesirable side effect of immunity is development, under some conditions, of allergy or other types of immune hypersensitivity Allergy caused by Activated T Cells o Delayed – Reaction Allergy o Caused by activated T cells and not by antibodies o Example: poison ivy ď§ Toxin in itself does not cause much harm to the tissues, however on repeated exposure to the toxin within a day or so, the activated T cells diffuse from the circulating blood in large numbers into the skin to respond to the poison ivy toxin Allergies in the “Allergic” Person Who Has Excess IgE Antibodies o Atopic allergies – caused by nonordinary response of immune system o Genetically passed from parents to child Page 11 of 13 PHYSIOLOGY – A Blood Physio pt. 3 o o o o o o Dr. Vienna Blessie N. Baloloy (VBNB) Presensce of large quantities of IgE in the blood ď§ Reagins / sensitizing antibodies that distinguishes them from the more common IgG antibodies ď§ IgE reagins is a strong propensity to attach to mast cells and basophils Allergen – antigen reacts specifically to IgE reagin antibody Anaphylaxis ď§ Widespread allergic reaction occurring throughout the vascular system and closely associated tissues. ď§ Hstamine is released into the circulation and causes body-wide vasodilation, as well as increased permeability of the capillaries with resultant marked loss of plasma from the circulation. ď§ Slow-reacting substance of anaphylaxis if released can cause spasm of smooth muscle of the bronchioles, eliciting an asthma like attack, sometimes causing death by suffocation Urticaria ď§ Results from antigen entering specific skin areas and causing localized anaphylactoid reactions. ď§ Histamine released locally causes: ďˇ Vasodilation induces red flare ďˇ Increased local permeability of the capillaries leading to local circumscribed areas of swelling of skin called hives Hay Fever ď§ Allergen-reagin reaction occurs in the nose ď§ Histamine released in response to the reaction causes local intranasal vascular dilation, with resultant incread capillary pressure and increased capillary permeability Asthma ď§ Often occurs in the “allergic” type of person ď§ The allergen-reagin reaction occurs in the bronchioles of the lungs ď§ Sloe-reacting substance of anaphylaxis – causes spasm of the bronchial smooth muscle ď§ Person then has difficulty breathing until the reactive products of the allergic reaction have been removed. Lec 12 - 27 Aug 2015 X. References Blood Physio Part 3 ppt Hall, John E. Guyton and Hall Textbook of Medical Physiology. Twelfth. Philadelphia: Saunders Elsevier, 2011. APPENDIX Figure 22. Acquired Immunity Mari, Merene MD-1C 2019 Page 12 of 13 PHYSIOLOGY – A Blood Physio pt. 3 Dr. Vienna Blessie N. Baloloy (VBNB) Lec 12 - 27 Aug 2015 Figure 23. Immune response. Figure 24 Woohoo sa wakas! Cytokines of Innate Immunity. Mari, Merene MD-1C 2019 Page 13 of 13 CARDIOVASCULAR PHYSIOLOGY (Gloria Marie M. Valerio, MD) Outline: 1. 2. 3. 4. 5. 6. 7. 8. Functional Anatomy of the Heart Properties of the Myocardial Cells Electrical Events Cardiodynamics Characterics, Properties, Functions of the Different Types of Blood Vessels Hemodynamics Microcirculation Mechanisms that Regulate Cardiovascular Function Functional Anatomy of the Heart The normal position of the heart inside the thoracic cavity is slightly tilted to the left, pointing downwards. When the heart contracts, it has a wringing action, meaning to say, when the heart contracts, it rotates slightly to the right and that will now expose the cardiac apex, so that when you place the diaphragm of the stethoscope over the chest wall particularly on the fifth intercostal space, left mid-clavicular line, that is where you will heartbeat the loudest called apex beat or point of maximum impulse. Fifth intercostal space: Start palpating below the clavicle and first rib – the second intercostal space, and move three spaces down. The midclavicular line: left of the left clavicle, take note of the mid-point then move five spaces below. In males, it is easily located because it is exactly below the left nipple. In females, the location may be variable so you need to palpate. the different organs of the body. This is made possible by the pumping action of the heart, so when the heart contracts, it will pump blood to the arteries. The arteries in turn will distribute blood at a high pressure to the different organs of the body. And from the different organs of the body, blood then will be collected by the veins and returned to the heart. So the arteries are distributing blood vessels while the veins are collecting blood vessels. The capillaries will allow the exchange of fluid and solutes between intravascular and interstitial fluid compartments. The human heart is divided into two pumps: right and left and they are connected in series. The left heart pumps blood to the systemic or peripheral circulation by way of the aorta. The right heart pumps blood to the pulmonary circulation by way of the pulmonary artery. Systemic or peripheral circulation includes blood flow to all organ systems of the body except for the lungs. When the cells of the systemic or peripheral circulation are metabolizing, they consume oxygen and produce carbon dioxide that will now be collected by the veins and will have a low oxygen tension and a high carbon dioxide tension called unoxygenated/deoxygenated/venous blood. This blood will be emptied by way of vena cava to the right side of the heart. When the right heart contracts, this same blood will be ejected to the pulmonary circulation by way of pulmonary artery. Unlike the other arteries of the body, the pulmonary artery carries deoxygenated or venous blood. This same blood will then reach the pulmonary capillaries and this is where exchange of gases will take place between the alveoli in the lungs and blood in pulmonary capillary across respiratory membrane. The blood from the pulmonary capillaries will come from the right side of the heart – low oxygen tension, high carbon dioxide tension. The opposite is true with regards to air in alveoli - increase oxygen tension, low carbon dioxide tension. Movement or transport of these gases across the respiratory membrane is a passive process. It occurs by simple diffusion brought about by pressure gradient. So the transport of movement of oxygen will take place from alveoli to pulmonary capillary, the carbon dioxide goes in opposite direction. So the blood that will enter the Alveoli Increase pO2 Decrease pCO2 Decrease pO2 Increase pCO2 Pulmonary capillary pulmonary vein is already oxygenated. Unlike the other veins in the body, the pulmonary vein carries oxygenated or arterial blood which will then be emptied on the left side of the heart which means the left heart pumps blood to the systemic circulation and receives blood from the pulmonary circulation while the right heart pumps blood to the pulmonary circulation and receives blood from the systemic circulation. The circulatory system is a closed system – whatever amount of blood will be pumped by the blood per minute will be equal to the volume of blood that will return to the heart per minute. Structures of the Human Heart PHOTO: Schematic diagram of the parallel and series arrangement of the vessels composing the circulatory system. The capillary beds are represented by thin lines connecting the arteries (on the right) with the veins (on the left). The crescent-shaped thickenings proximal to the capillary beds represent the arterioles (resistance vessels). The cardiovascular system consists of the heart at the center and the different blood vessels which are arranged in parallel and in series with each other. The red are the arteries, the blue are the veins, and the capillaries are the smallest vessels in the body. The major function of the cardiovascular system is to transport nutrients including oxygen to the different organs of the body and to remove the waste products of metabolism including carbon dioxide from 1 Shannen Kaye B. Apolinario, RMT The heart is divided into two pumps: the right and the left. The two pumps in turn are made up of two chambers: atrium and ventricle. The right heart is made up of the right atrium and right ventricle while the left heart is made up of the left atrium and left ventricle. The two atria are separated by a band of connective tissue forming the interatrial septum. The two ventricles are also separated by a band of connective tissue forming the interventricular septum. The two atria are separated from the two ventricles by a mass of connective tissue. The four chambers of the heart are separated by connective tissues. Other important structures in the heart are the valves and there are two sets of cardiac valves. Between the atria and ventricles are the atrioventricular valves - tricuspid valve on the right side and mitral valve on the left side. The tricuspid valve is between the right atrium and right ventricle while the mitral valve is between the left atrium and left ventricle. The other sets of cardiac valves are between the ventricles and the arteries – the pulmonary valve between the right ventricle and pulmonary artery; the aortic valve between the left ventricle and aorta. Functions of the valves: first, when they open, they allow blood to flow from one chamber of the heart to another – when the atrioventricular valves are open, blood flow from the atria to the ventricles and when the semilunar valves are open, blood ejects from the ventricles to the arteries. When they close, they will prevent regurgitation or backflow of blood. However, there are no cardiac valves between the atria and veins so when there is atrial contraction, small amount of blood backflows to the veins. There is only small amount of backflow because when the atria contracts, there is increase in pressure and the tendency is to push blood downwards to the ventricles and at the same time, when it contracts, the orifice of the veins becomes smaller. Structure of Cardiac Valves The wall of the atria and ventricles is made up of cardiac muscle. The atrial wall/musculature is thinner compared to the ventricular wall or musculature. The two atria functions as a primer pumps for the ventricles and as conduits of blood from veins to ventricles. It is therefore the ventricles with the thicker wall that are the major pumps in the heart with the left ventricular wall thicker than the right ventricular wall. The left ventricular wall is thicker because it pumps blood to the systemic circulation with an average pressure of 70-130 mmHg. On the other hand, the right ventricle will pump blood to the pulmonary circulation with an average pressure of only 4-25 mmHg. The left ventricle will have to pump blood against a higher pressure resistance in the systemic circulation compared to the right ventricle that will pump blood against a lower pressure in the pulmonary circulation. Since the opposing force is higher in the left ventricle, the tendency is to contract more forcefully because of increased workload resulting to hypertrophy of the muscle fibers. Although the left ventricular wall is thicker, contract more forcefully, higher workload and higher opposing force than the right, the output of the two ventricles is the same. Whatever amount will be ejected by the left ventricle per minute is the same with the amount of blood ejected by the right ventricle per minute. Aside from the cardiac muscles, the atrial and ventricular wall also contains a fair amount of elastic tissues that will enable the different chambers of the heart to dilate when the volume of the blood inside increases. Also present in the atrial and ventricular wall is a fair amount of connective tissue and this connective tissue in turn will prevent overstretching or distension of cardiac muscles when the cardiac size increases. PHOTO: Four cardiac valves as viewed from the base of the heart. Note how the leaflets overlap in the closed valves. 2 Shannen Kaye B. Apolinario, RMT PHOTO: Drawing of a heart split perpendicular to the interventricular septum to illustrate the anatomic leaflets of the atrioventricular and aortic valves. The three cardiac valves – tricuspid, pulmonary and aortic contains three cusps. It is only the mitral valve that contains only two cusps. For the atrioventricular valve, the cusps are attached by strong ligaments called chordae tendinae to the papillary muscle and the papillary muscle arises from the ventricular wall. Mitral valve has two cusps attached by the chordae tendinae to the papillary muscle. The semilunar valve – aortic valve has no chordae tendinae. Tricuspid valve has chordae tendinae attached to the papillary muscle and arises from the ventricular wall. Each cusp has an orifice or opening covered by leaflets which are made up of loose fibrous tissue. One end of the leaflets is attached to the border of the orifice while the central part is freely movable. Since it is thin and freely movable, it can open. However when they close, they close completely because there is extensive overlapping of the leaflets that cover the orifice of the cusp. Opening and closing of the cardiac valve is a passive process brought about by pressure differences between the two chambers of the heart. In the case of tricuspid valve for example, if the right atrium is contracting, the right ventricle is in a relaxed state. When the right atrium is contracting, the pressure increases and that will push open the tricuspid valve so that blood will flow from the right atrium and right ventricle. On the other hand, if it now the right ventricle contracting and the right atrium is relaxed, the high pressure in the right ventricle will close the tricuspid valve to prevent back flow of blood to the right atrium. It is also a passive process due to the pressure gradient. Same things happen with regards to the mitral valve as well as to the semilunar valves. When the ventricle is contracting, the papillary muscle also contracts but the contraction of the papillary muscle is not essential in closing the atrioventricular valves. Remember that when the ventricle is contracting due to the thick musculature, the pressure is high. So the high pressure will tend to push the AV valves to bulge into the atria however, when the papillary muscle contracts, it will pull the chordae tendinae to prevent eversion or over-bulging of the AV valves during ventricular contraction. the leaflets. In insufficient or incompetent cardiac valve, the leaflets do not close completely allowing back flow of the blood either from the ventricles to the atria or from the arteries to the ventricles. In normal mitral valve, when the left atrium is contracting, that is the amount of blood that will be ejected to the left ventricle. In stenotic mitral valve, even if the left atrium is contracting, there will be less amount of blood that will be ejected to the left ventricle. There will be now pooling of blood in the left atrium causing the left atrium to dilate. In stenotic aortic valve, the leaflets hardened so that during contraction, the amount of blood ejected in the aorta will be decreased. There will be pooling of blood in the left ventricle causing the left ventricle to dilate. An example of an insufficient or incompetent cardiac valve is a prolapsed mitral valve. When the left ventricles contract, it does not close even if there is blood ejected in the aorta, it will be lessened because of the backflow of blood in the left atrium. Presence of a stenotic or an incompetent cardiac valve will produce abnormal heart sounds called a murmur. PHOTO: Mitral and aortic valves (the left ventricular valves) Heart Sounds Aortic Closing of the cardiac valves will produce the normal heart sounds. The first heart sound is at the onset of ventricular contraction with closing of AV valve. That closing of AV valve produces the first heart sound. Compared to the second heart sound, closing of the AV valve is said to be louder and longer in duration. The sound produced by the closing of the tricuspid valve is heard best on the fifth intercostal space, left of the sternum while the sound produced by closing of the mitral valve is heard best on the fifth intercostal space at the cardiac apex - left mid-clavicular line. The second heart sound occurs at the onset of ventricular relaxation with closing of the semilunar valves. And because of the pressure in the arterial system, when the semilunar valves close, they close abruptly and that will make the duration of the heart sound shorter. The sound produced by the closing of the pulmonary valve is heard best on the second intercostal space left of the sternum while the sound produced by the closing of the aortic valve is heard best on the second intercostal space right of the sternum. The quality of the second heart sound can be affected by respiratory phase – expiration and inspiration. During expiration, you will hear only one second heart sound – there is simultaneous closure of the aortic and pulmonary valves. During inspiration, there is a physiological splitting of the second sound with closing of the aortic valve occurring a little ahead of the pulmonary valve and the sound produced by closing of aortic valve is louder than that produced of the closing of the pulmonary valve except in patients with pulmonary hypertension. The pressure inside the thoracic cavity is negative or below atmospheric pressure – causing a suction effect on structures that can be dilated. (In positive or above atmospheric pressure, it will compress the structures in the thoracic cavity.) The more negative the intra-thoracic pressure is, the more the heart and lungs are dilated. When the heart is dilated, it allows more blood to return especially to the right heart – more blood will return from the systemic circulation. There will be an increase volume of blood to the right heart causing a delay of the closing of the pulmonary valve during inspiration. In children with thin chest wall or patients suffering from left ventricular failure, a third heart sound can be heard and that will coincide with filling of blood in the ventricles. Rarely, there is a fourth heart sound that can be heard and that will coincide with atrial contraction. In some abnormal conditions, the third and fourth heart sounds may be accentuated so that what you will hear in the stethoscope will be triplets of sounds resembling the sound that is produced by galloping horses called a gallop rhythm. Certain abnormal conditions like an infection in the heart may damage the cardiac valves and there are two types of lesions that may occur in the cardiac valve: stenosis and incompetent cardiac valve. In stenosis, the valve cannot open completely because of the hardening of 3 Valve Mitral Shannen Kaye B. Apolinario, RMT Type of lesion Stenosis Incompetent Stenosis Incompetent Timing of murmur Diastole Systole Systole Diastole Diastole – ventricular relaxation Systole – ventricular contraction The Pericardium Pericardial fluid Parietal pericardium Visceral pericardium The heart is covered by a membrane which is made up of connective tissue – the pericardial sac or pericardium. This connective tissue that makes up the pericardium is less distensible. Presence of this will also prevent overstretching of the cardiac muscle when the cardiac size increases. The pericardium is made up of two membranes: visceral and parietal pericardium. The visceral pericardium is the membrane directly attached to the anterior surface of the myocardium. When the visceral pericardium is reflected back, it forms the parietal pericardium. The space in between the two membranes is filled with 30cc of pericardial fluid. The importance of the pericardial fluid is to lubricate the heart facilitating the movement of the heart when it contracts. (2) Groups of Myocardial Cells 1. Automatic Cells An automatic cell is a cell that is capable of spontaneously generating its own action potential independent of extrinsic nervous stimulation. In the case of myocardial cells, it is independent of automatic stimulation. Aside from generating its own action potential, the cells of the heart are capable of transmitting or conduction action potentials throughout the heart. Structures that make up the hearts’ conduction system: ďˇ Synoatrial (SA) node = located at the junction of superior vena cava and right atrium. ďˇ Atrioventricular (AV) node = located posteriorly on the right side of interatrial septum. It is divided into three zones: o Atrionodal (AN) zone – most proximal zone, a transitional zone between the right atrium and AV node o Nodal (N) zone - middle o ďˇ 1 Nodal His (NH) zone – most distal, connects with the bundle of His Purkinie system/ventricular conduction system = made up of bundle of HIS and purkinje fibers o Bundle of HIS – located at the interventricular septum. The bundle of HIS forms right and left bundle branches. The left bundle branch will divide to form the posterior and anterior fascicles. The left posterior and anterior fascicles as well as the right bundle branch will then connect with the Purkinje fibers that are present mostly at the apex of the heart. 2 0 -90 mv 4 3 Skeletal muscle action potential: 5-30 millisecond Phase 4 – Resting Membrane Potential (-90mv) – membrane is highly permeable to potassium because of the presence of many potassium leak channels. Since there are many potassium leak channels on the membrane of the skeletal muscle and there is a concentration gradient for potassium, the tendency is for potassium to move out – decreasing the amount of positively charged ions inside. Also present inside the cell are negatively charged molecules including proteins which are large molecules so they remain inside. The main extracellular cation is sodium, there is a concentration gradient for sodium but the membrane is only slightly permeable to sodium ions because of there are only few sodium leak channels – most sodium will remain outside. The membrane is permeable to chloride at rest, it allows the chloride ions to move in but because of the presence of the negatively charged ions inside the cell, chloride will eventually get out. To maintain the concentration of Na and K inside the cell, you have the activity Na-K pump (3 Na out, 2 K in). These things stabilize the RMP of the cell to -90mv. PHOTO: The cardiac conduction system All of these cells are automatic cells and can generate own action potential. But in a normally functioning heart, all action potentials are generated by the sinoatrial (SA) node and is referred as the primary pacemaker of the heart while the other automatic cells are latent pacemakers. They are called latent pacemakers because although they do not normally generate action potential, in some abnormal conditions, they can be stimulated to generate their own action potential. The primary pacemaker of heart is the one that determines the heart rate – number of heart beats per minute. The average heart beats per minute is 75-80 beats per minute. The SA node is the primary pacemaker of the heart because it is the fastest that can generate an action potential. Overdrive suppression is the increase frequency of discharge of an action potential from an automatic cell will diminish the automaticity of other automatic cells. The SA node will fire at a high rate of 75-80 beats per minute with each action potential that will depolarize other automatic cells. With each depolarization, a certain amount of sodium ions will enter the cell that will create a concentration gradient for sodium that will activate the Na-K exchange pump. The Na-K pump will extrude sodium ions. The more frequent the other automatic cells are depolarized, the more sodium ions will enter the cell, the more Na-K pump will be activated, the more sodium ions will be extruded from the cell that would cause the cell to be hyperpolarized. If the other automatic cells are hyperpolarized, they will become less excitable. When the overdrive stops, the activity of Na-K pump will not stop immediately; it will remain active, continuing to extrude sodium ions, the more the other automatic cells will become hyperpolarized, the more they will become less excitable, and the more their automaticity will be diminished. (44m) Intracellular Increase K+ Negatively charged proteins Decrease Na+ Decrease Cl- Extracellular Decrease K+ Increase Na+ Increase Cl- Resting Membrane Potentials: ďˇ Neurons = -70mv ďˇ Skeletal muscle = -90 mv ďˇ SA node = -60mv ďˇ Ventricular muscle = -90mv ďˇ Gastrointestinal smooth muscle = -60mv The resting membrane potential is different in each cells because of the potassium leak channels. The more potassium leak channels present on the membrane, more K+ will move out of the cell, making the membrane potential more negative and vice versa. Phase O – depolarization – opening of fast voltage gated Na+ channels Phase 1,2,3 – repolarization – re-establishing the RMP, brought about by the closure of fast voltage gated Na channels and opening of slow voltage gated K channels. Since these K channels are slow, they remain open for a long time allowing K+ to continuously move out so that at some point, the MP will go below the resting level = hyperpolarization. When the K+ gated are closed, the RMP will be restored Automatic Fiber Action Potential Non-automatic cells Non-automatic cells cannot generate own AP and are specialized mainly for contraction. The presence of non-automatic cells in the heart, even if you cut the automatic innervation to the cardiac muscle, it can still contract. Non-automatic cells are the cardiac muscle cells present in the atrial wall and ventricular wall. 1 2. 0 4 Properties of Myocardial Cells 1st Property: Automaticity – generation of action potentials 4 Shannen Kaye B. Apolinario, RMT 2 3 4 -60 mv 250-300 milliseconds hyperpolarization Action potential of an automatic cell- SA node Difference from the AP of skeletal muscle: ďˇ Duration is longer – 250-300 millisecond ďˇ RMP is less negative - -60 mv Non-automatic Fiber Action Potential (ventricular muscle) Phase 4 – slow rise in membrane potential and is unstable. The slow rise in membrane potential is called the pre-potential or slow diastolic depolarization. There is more Na leak channels, membrane potential increases. Phase 0 – Depolarization. Somewhat inclined, depolarization occurs slowly Phase 1,2,3 –Repolarization. Inclined, occurs slowly, there is hyperpolarization like in the skeletal muscle ďˇ The increase in sodium leakage and a decrease in the membrane permeability to potassium will account for the automaticity of the SA node. Activation of slow (inclined) voltage gated long lasting Ca++ channels allowing Ca influx with some Na influx = MP will become less negative Voltage gated K channels will open allowing K efflux. But repolarization cannot occur rapidly because of the long lasting Ca channels are still open. Ca influx and K efflux Midway of repo: Ca channels close, K channels open -40 mv Na leakage, Decrease K -50 mv Hyper: prolonged opening of K channels -60 mv 250-300 milliseconds Action potential of an automatic cell (same thing happens in SA node, AV node, bundle of HIS) With parasympathetic or vagal stimulation, the neurotransmitter released (NTA) released is acetylcholine (Ache). When Ache binds with muscarinic 2 receptors in the SA node, it increases permeability to K+, allowing more K+ efflux. Parasympathetic or vagal stimulation will hyperpolarize the SA node. If it is hyperpolarized, it is less excitable and the duration of the membrane pre-potential is longer or delayed generation of action potential. In parasympathetic or cholinergic stimulation, SA node is inhibited, heart rate decreases. The opposite happens with sympathetic stimulation, norepinephrine released by sympathetic nerves will bind with the B1 receptor in the SA node resulting to an increased permeability to Na and Ca causing hypopolarization of the SA node, making it more excitable and the heart rate increases. PHOTO: Action potential of the SA node 5 Shannen Kaye B. Apolinario, RMT PHOTO: Action potential in the ventricle (250-300 milliseconds) RMP - -90, straight line, it is stable Phase 0 – depolarization, straight line. Occurs rapidly due to opening of fast voltage-gated Na channels = Na influx then reaches the threshold voltage of -60 mv resulting to depolarization. When the membrane potential reaches -20 mv, it will open up slow, long lasting voltage gated Ca channels = Ca influx. (The main factor responsible for depolarization is Na influx) Peak of the spike – Na channels closes, K channels open. Ca++ channels are still open Phase 1 – initial phase of repolarization – brought about mainly by slow voltage gated K+ channels Phase 2 – plateau – the amount of K+ that goes out is equal to the amount of Ca++ that goes in. no electrical activity. At the end of the plateau, the Ca++ channels will close leaving only the K+ channels open that will bring about the final phase of repolarization Phase 3 – final phase of repolarization Phase 4 - -90 RMP is re-established. The increase membrane permeability to potassium is responsible for the -90 mv RMP. No hyperpolarization –Although the K+ channels can remain open for a long time, because of the plateau, it is open for a long period of time thus it does not reach hyperpolarization Similarities and differences with the action potential of skeletal and cardiac muscles: ďˇ Similarities: -90 mv RMP, fast-paced depolarization ďˇ Differences: repolarization, no hyperpolarization, duration PHOTO: Action potential of the atrium Similarities and differences between the ventricle and atrium: ďˇ Similarities: same, RMP, depolarization, phase 1 ďˇ Differences: o phase 2 – plateau. In the atrium, the membrane is more permeable to K+ than to Ca++. More K+ conductance than Ca++ conductance that will make the duration of the plateau shorter and not sustained as compared to that of the ventricle. o Repolarization phase is shorter in atrium than in the ventricle Periods of Refractoriness ARP RRP The importance of prolonged duration of refractoriness is for the ventricles to be filled with blood resulting to a more effective pumping action, no fatigue, no tetanic contractions. One cannot elicit successive action potentials or contractions without tetanic or sustained contractions in the cardiac muscle = allow more time for ventricular filling. The musculature of the ventricle is thick so when it contracts, it compresses the coronary arteries. The coronary arteries supply blood and oxygen to the cardiac muscle thus when it is compressed, there is poor perfusion of cardiac muscle and less oxygen supply, this happens if there is tetanic contractions but in the cardiac muscle, there are no tetanic contractions. There is longer period of relaxation, when the ventricles are relaxed, there will be better perfusion of the cardiac muscle. Duration Action potential ARP RRP In Absolute or Effective Refractory Period (ARP), no amount of stimulus intensity will be able to re-excite the membrane of that cell. It covers the whole of depolarization until 1/3 of the repolarization phase. At phase 0, it is absolute refractory because all the voltage gated sodium channels are open and it is not able to re-open the already open sodium channels. In phases 1 and 2, the Na channels are already close but it is still absolute refractory because Na channels are voltage gated and they only open at a certain voltage or membrane potential near the critical firing level of about -60mv more so if the membrane potential is at its resting level. It is far from the CFL. In Relative Refractory Period (RRP), its level is near the critical firing level and resting level, the membrane becomes more excitable so that a stronger than threshold stimulus can be able to open up the voltage gated sodium channels and elicit a second action potential. Heart rate of 75 beats per min 0.25 sec 0.20 sec 0.05 sec Heart rate 200/min 0.55 sec 0.13 sec 0.02 sec Skeletal muscle 0.005 sec 0.004 sec 0.001 sec PHOTO: Changes in action potential amplitude and upstroke slope as action potentials are initiated at different stages of the relative refractory period of the preceding excitation As the membrane potential reaches the relative refractory period as well as the RMP, if there is stimulus later in the RRP, that will open up more and more voltage gated Na channels so that its depolarization increases its amplitude, same thing happens in the SA node. 2nd Property: Rhythmicity It is said that the SA node generates the action potentials at regualr intervals. Even if the heart rate increases, if the impulses are still generated at regular intervals, that is still called the sinus rhythm. Photo: Normal sinus rhythm PHOTO: Relationship between action potential and contraction in the ventricle A contraction cannot be elicited unless the ventricle is almost completely relaxed. Photo: Normal ECG 6 Shannen Kaye B. Apolinario, RMT P wave – represents atrial depolarization QRS complex – represents ventricular depolarization When seeing a normal sinus rhythm, take note of the interval between successive P waves – regular interval, take note of the interval between successive QRS complex – regular interval. Photo: Sinus tachycardia The heart rate may increase with sympathetic stimulation, during moderate to heavy exercise, and increase temperature during fever. In these three conditions, the heart rate will increase but if the impulses are generated at regular intervals, that is still sinus rhythm. But since the rate will increase, it is now called sinus tachycardia. With regards to the right and left atrium, transmission of impulses can occur locally through gap junctions. When the impulse reaches the AV node, there is a delay in the transmission of impulses so the velocity of conduction decreases at the AV node and this is called the AV nodal delay. Most of the delay will take place between the AN and N zones of the AV node. There is a delay in the transmission of impulses in the AV node because it has a small fiber diameter and few gap junctions – spaces or channels between the membranes of the muscle fibers that will allow ions to flow freely from one muscle fiber to the next. The smaller fiber diameter and fewer gap junction causes increased resistance to impulse conduction - the AV nodal delay. The importance of AV nodal delay is for the ventricles to remain in a relaxed state for a longer period of time allowing more time for the ventricular filling and to ensure that the atria and ventricles will not contract simultaneously. From the AV node, the impulse will then travel to the bundle of His then to the left and right bundle branches then to the Purkinje fibers then it would stop (from antero-basal ď apex ď end). Transmission of impulse in heart: antero-basal ď apex ď postero-basal The part of the heart that will depolarize last is the posterobasal. Conduction Speed in Cardiac Tissue Photo: Sinus bradycardia On the other hand, in cold temperatures or if there is vagal over stimulation that inhibits the SA node, the rate of firing will decrease but if the impulses are generated at regular intervals, that is still sinus rhythm but this time, it is now called sinus bradycardia. If there is no rhythm or if it is irregular, it is now called arrhythmia. SA node Atrial muscle AV node Bundle of His Purkinje fibers Ventricular muscle Conduction rate (m/sec) 0.05 1 0.05 1 4 1 Conduction speed is lowest in the AV node (not in the SA node because it is generation). Fastest is in the Purkinje fibers because of the large fiber diameter. In the atria and ventricles, conduction of impulses may occur locally through gap junctions. Reentry 3rd Property: Conductivity Photo: Transmission of the cardiac impulse through the heart, showing the time of appearance (in fractions of a second after initial appearance at the sinoatrial node) in different parts of the heart. All impulses from a normal functioning heart will come from the SA node. From the SA node, the impulse will be transmitted to the AV node and transmission of impulses from the SA node to the AV node is facilitated by means of three internodal tracts: anterior internodal tract of Bachmann, middle internodal tract of Wenckeback and posterior internodal tract of Thorel. Take note that the tips of the fibers of the SA node are directly connected to the right atrial muscle cells so there is direct transmission of impulses from the SA node to the right atrium. 7 Shannen Kaye B. Apolinario, RMT Photo: The role of unidirectional block in re-entry. In A, an excitation wave traveling down a single bundle (S) of fibers of continues down the left (L) and right (R) branches. The depolarization wave enters the connecting branch (C) from both ends and is extinguished at the zone of collision. In B, the wave is blocked in the L and R branches. In C, a bidirectional block exists in branch R. in D, a unidirectional block exists in branch R. the antegrade impulse is blocked, but the retrograde impulse is conducted through and re-enters bundle S. A – Normal direction. Coming from the SA node to the AV node to the bundle of His. From the bundle of His, the impulse will be transmitted to the left and right bundle branches. From the left and right bundle branches to the apex of the heart but there is a connecting fiber between the right and left bundle branches. B – Both left and right bundle branches are blocked so there is no impulse transmission to the apex of the heart as well as to the connecting fiber. C – Only one bundle branch is blocked (right bundle branch). The impulse that is supposed to go the right bundle branch is blocked but the left bundle branch goes to its normal route – to the apex and to the connecting fiber. The one that goes to the connecting fiber can now go to the apex but can also go back to the area that is blocked; this is called reentry or circus movement. D – Since the right bundle branch is blocked, the transmission of impulse is blocked while that coming from the left will re-enter the area where the impulse came from, it goes round and round that’s why it is called circus movement. Reentry or circus movement is possible because the distance travelled by this impulse is longer compared to other one which is blocked so it becomes refractory. Since the distance is longer, when it reaches the area that is blocked, it becomes out of refractory/out of refractoriness so it can go back. Because of this phenomenon, this is the path that is responsible for atrial or ventricular fibrillation/flatter. In the synchronised contraction, the whole atria or the whole ventricle, there is an area that will contract and there is an area that will relax. Ectopic Tachycardias Atrial contraction Ventricular contraction AV nodal delay Most of the blocks takes place in the AV node so that it will produce the 1st degree, 2nd degree and 3rd degree heart block, all of these are abnormal conditions. The normal ratio between atrial and ventricular depolarization is 1:1, so that during atrial and ventricular contraction, if the atria will contract three times, the ventricles will also contracts three times but atrial contraction happens first than ventricular contraction causing an AV nodal delay. 1st degree heart block – Incomplete heart block. All impulses from the SA node can still be transmitted to the ventricles. Based on the spacings in the photo, there is atrioventricular depolarization happening. The ratio of ventricular depolarization is still 1:1. So that when it contracts – three contractions in the atria, there will also be three contractions in the ventricles. The difference from the normal is that it has a longer duration of the AV nodal delay. 2nd degree heart block – Not all impulses from the SA node will reach the ventricles. What happens is P-P-QRS, P-P-QRS. This time, the ratio of the atrial to ventricular depolarization is 2:1 or 3:1. Not all the impulses reach the ventricles but since there are impulses that can reach the ventricles, this is still an incomplete heart block. 3rd degree heart block – Complete heart block. No impulses from the SA node will be able to reach the ventricles. What happens is P-P-P-P. The atria will be contracting normally at a rate that is dictated by the SA node; that is 75 beats per minute. Initially, the ventricle will not contract because no impulses will reach the ventricles but there are pacemaker cells in the ventricles – the bundle of His and Purkinje fibers. The two are latent pacemakers and they are also automatic cells. For 20 seconds, there will be no impulse coming from the SA node, the latent pacemaker in the ventricle specifically the Purkinje fibers will be activated, it will escape from the overdrive suppression and this is called the ventricular escape. When activated, the Purkinje fibers will generate its own impulse causing the ventricles to contract at a rate that is dictated by the Purkinje fibers. If the contraction in the atria is 75 beats per minute, in the ventricle, it is 30-40 beats per minute. The firing of Purkinje fibers is slower than the SA node. Another abnormal condition is the presence of a premature contraction or an extrasystole wherein another contraction happens in response from an impulse that will not come from the SA node. For example, there is atrial contraction that is initiated by the impulse from the SA node, other parts of the atria will be activated, and there will be an ectopic fossi – impulse coming from other sources. So when it contracts, if there is another impulse, there will be another contraction and this is premature contraction or extrasystole. PHOTO: Frequency summation and tetanization In wave summation in the skeletal muscles, if three maximal stimuli is applied successively, the magnitude of the 2nd contraction is higher than the first because in the muscle, calcium ions have not yet returned to the sarcoplasmic reticulum and when another stimuli is applied, there will be more releasing of calcium ions that will increase the force of contraction. PHOTO: AV blocks. A, First-degree block; the PR interval is 0.28 second (normal: <0.20 sec). B, Second-degree block (2:1). C, Third-degree block; note the dissociation between the P waves and the QRS complexes 8 Shannen Kaye B. Apolinario, RMT In cardiac muscle, the magnitude of the 2nd contraction is lower than the first. Take note that extrasystole can only be elicited during the mid or late diastole. It is not able to elicit an extrasystole during systole or early diastole because of the long duration of the Absolute Refractory Period. Another contraction can be produced only during the mid or late diastole when the muscle is almost completely relaxed (Note: “almost” but not yet relaxed). Remember that one of the important factors that will determine the force of cardiac muscle contraction is the volume of blood that will stretch the muscle before contraction. The longer the relaxation phase, the more blood will be filled in the ventricles, the greater the stretch of the cardiac muscle will be and the greater the force of contraction will be. ďˇ There is a decrease in the magnitude of the 2nd contraction because the relaxation phase is not yet complete so the filling of the blood is less resulting to less stretch of the muscle and less force of contraction. Elastic tissue. Fair amount of elastic tissue that will enable the chambers of the heart to dilate to accommodate a greater volume of blood. ďˇ Connective tissue. Presence of connective tissue that will prevent over distension or overstretching of a cardiac muscle when the cardiac size increases. ďˇ More mitochondria and active capillaries. Compared to the skeletal muscle, there are more mitochondria as well as active capillaries in the cardiac muscle and that is important because the main source of energy for cardiac muscle contraction is oxidative metabolism. ďˇ Sarcoplasmic reticulum. The sarcoplasmic reticulum in the cardiac muscle is less well developed. Meaning to say, it can’t store large quantities of calcium ions that will provide for full contraction so there has to be another source of Ca++ for the cardiac muscle contraction and that is the extracellular fluid (ECF). And because the transverse tubular system in the cardiac muscle is more developed – it has a bigger diameter; it can allow more Ca++ from the ECF to enter the cardiac muscle cell. ďź ďź ďź ďź 4th Property: Contractility Important characteristic of a cardiac muscle: ďˇ Involuntary. Activity of the heart is not controlled by the cerebral cortex, it is controlled by the autonomic nervous system although there are automatic cells present in the heart. ďˇ Smaller. Compared to skeletal muscle cell, the cardiac muscle cell is smaller ďˇ Either binucleated or mononucleated ďˇ Striated. Just like the skeletal muscle cell, the cardiac muscle is striated. Striated means that the muscle fibers are distinctly separated from one another. What separates the individual muscle fibers is the Z line that is why the area between two Z lines will form a sarcomere. The difference between the skeletal and cardiac muscle cell is that the membrane of the cardiac muscle branches out to reconnect with the membrane of the next muscle fiber so that the force generated with one muscle fiber can be transmitted to the other muscle fibers as well. Nebulin – forms the scaffold of the thin filament α actinin – will connect the thin filament to the Z line Titin – connects the thick filament to the Z line Tropomodulin – regulates the length of the thin filament PHOTO: “Syncytial,” interconnecting nature of cardiac muscle fibers. ďˇ ďˇ Presence of the intercalated disk. The intercalated disk is present on the Z line. Its function is to separate one muscle fiber from another but at the same time, to connect one muscle fiber to another by means of gap junctions. Present in the intercalated disk are channels that will allow ions to flow freely from one muscle fiber to the next so that when an action potential is generated anywhere in a bundle, it can be transmitted rapidly causing the whole bundle to be depolarized at the same time and to contract as a single unit and this is called a syncytial type of arrangement of muscle fibers. The cardiac muscle cell anatomically is striated but functionally or physiologically, it is a syncytium. The syncytial arrangement of muscle fibers is important because it will provide synchronized contraction of the atria and ventricles that is important for the pumping action of the heart. It will also provide synchronized relaxation of the atria and ventricles that is important for filling of blood in the different chambers of the heart. Contractile proteins present: ďź Thick filament - myosin ďź Thin filament – actin, troponin, tropomyosin ďź Meromyosin, C protein – forms the scaffold or suport of the thick filament 9 Shannen Kaye B. Apolinario, RMT PHOTO: Cardiac muscle (panel A) has high resistance to stretch when compared with skeletal muscle (panel B). When either cardiac or skeletal muscle is stretched, there is an increase in resting tension (RT). If the muscle is then stimulated to contract maximally, it generates more tension (termed total tension – TT). The difference between total tension and resting tension at any given length is the force produced by contraction (e.g. active tension – AT). The bell-shaped dependence of active tension on muscle length is consistent with the sliding filament theory of cardiac and skeletal muscle. It is, however, difficult to stretch cardiac muscle beyond its optimal sarcomere length, as evidenced by the rapid rise in resting tension in the middle of the bell-shaped AT curve. Above is a graph that shows the importance of the presence of elastic tissue in the cardiac muscle. The blue line represents the resting tension – tension that develops in the muscle before contraction. The red line represents active tension – tension that develops in the muscle during contraction. Because of the many elastic tissue in the cardiac muscle, even in the resting state or resting length, passive tension increases in the muscle and it can dilate so that when the cardiac muscle fiber contracts, the difference between active and passive tension is smaller compared to skeletal muscle. The importance of that is the different chambers of the heart can accommodate a large volume of blood with little increase in pressure. Excitation-Contraction Coupling potassium ions pumped into the cell so that it will create a concentration gradient for sodium – increased concentration outside, low concentration on the inside. That will now activate the sodium-calcium exchange pump that will pump three Na+ in, in exchange for one Ca++ that is pumped out of the cell and that is the main means by which Ca++ is extruded from the cardiac muscle cell. In patients suffering from heart failure, the main problem is poor force of contraction of the ventricle. This poor force of contraction has to be made strong by giving cardiac glycosides (e.g. digitalis). The main mechanism of action of cardiac glycosides is to inhibit the sodiumpotassium pump. If this pump is inhibited, Na+ will not be extruded so that will not create a concentration gradient for Na+. If there is no concentration gradient for Na+, nothing will activate the sodium-calcium pump so Ca++ will remain inside the cell and that can be utilize to increase the force of ventricular contraction. Arrangement of Muscle Fibers When the heart contracts, it rotates slightly to the right and that will expose the cardiac apex. The heart can rotate when it contracts because of the arrangement of muscle fibers. The arrangement of muscle fibers is synospiral and bulbospiral. Autonomic Innervation of the Heart How does the Autonomic Nervous System (ANS) regulates the cardiac activity? Sympathetic: T3 T4 T5 PHOTO: Excitation-contraction coupling in the heart requires Ca++ influx through L-type Ca++ channels in the sarcolemma and T tubules. Present on the membrane or sarcolemma is a calcium pump, calcium-sodium exchange pump, sodium-potassium exchange pump and the last two are antiporters. Invagination of the sarcolemma will form the T-tubules. Present on the membrane of the T-tubules are voltage-gated calcium channels. Inside the cell, there are myofilament and sarcoplasmic reticulum (SR). On the membrane of the sarcoplasmic reticulum is another calcium pump. Also on the membrane of SR are ryanodine receptors and these receptors are calcium-gated calcium channels. What happens is when a membrane is depolarized, this will activate the voltage-gated calcium channels of the membrane of the T tubule and that will allow Ca++ to enter from the extracellular fluid (ECF) to the inside of the cardiac muscle cell. Some of this Ca++ will immediately bind with troponin C forming the calcium-troponin C complex that will initiate muscle contraction but some of the Ca++ will bind with the ryanodine receptors on the membrane of SR activating the calcium-gated calcium channels that will allow Ca++ to move out from the SR to the cytoplasm to bind with troponin C. The difference of this from the skeletal muscle is that the Ca++ from the SR will not move out unless there is a trigger that will cause the Ca++ to move out. The trigger is also Ca++ from the ECF that will bind with ryanodine receptors hence it is called calcium-gated calcium channels. It needs Ca++ from ECF to trigger movement of Ca++ from SR into the cytoplasm. That is why it has two sources of Ca++ compared to skeletal muscle – the SR and ECF. If there are already many Ca++, the force of contraction is stronger. With repolarization, it is expected that the muscle will relax but for the muscle relax; Ca++ has to be removed. Ca++ is removed by the activity of calcium pump on the membrane of the SR that will actively transport Ca++ back into the SR. Another means to remove Ca++ is through the activity of the calcium pump on the sarcolemma that will actively transport Ca++ back into the ECF. But the most important means by which calcium is extruded from the cardiac muscle cell is through the activity of the sodium-calcium antiporter. Initially, with repolarization, the sodium-potassium pump is activated that will pump three sodium ions out in exchange for two 10 Shannen Kaye B. Apolinario, RMT Norepinephrine + β1 receptor SA node AV node Purkinje system Atrial muscle Ventricular muscle First, the sympathetic nerves that innervate the heart originate from T3, T4, and T5 segments (T = thoracic). Pre-ganglionic fibers from T3, T4 and T5 will synapse with the sympathetic ganglia and this is called the sympathetic chain. Post-ganglionic fibers from the sympathetic chain will bind with β1 receptors in the heart and the neurotransmitter agent (NTA) released by these sympathetic nerves is norepinephrine (NE). The effect of NE at the myocardial cells is to increase membrane permeability to Ca++ and Na+ so that will make the myocardial cell more excitable and therefore increased cardiac activity. Sympathetic nerves innervate ALL structures in the heart either automatic and non-automatic so that will include the sinoatrial (SA) node, atrioventricular (AV) node, ventricular conduction system or the Purkinje system as well as the atrial and ventricular muscle. Parasympathetic: CN 10 Acetylcholine + M2 SAN AVN Atrial muscle On the other hand, parasympathetic innervation to the heart is carried by the vagus nerve which originates from the medulla. So the vagus nerve will bind with muscarinic 2 receptors in the heart and the NTA released is acetylcholine (Ache). The effect of Ache on the myocardial cells is to increase membrane permeability to K+ so that will hyperpolarize the myocardial cells inhibiting them or decreasing cardiac activity. The structures in the heart that receive parasympathetic or vagal innervation are the SA node, AV node, only the proximal part of the bundle of His, atrial muscle, and there is very little, if any, vagal innervation to the ventricles. Chronotropic regulation: Sympathetic Increased frequency of discharge of the SA node Increased the heart rate Parasympathetic Decreased frequency of discharge by the SA node Decreased the heart rate In relation to this, let’s look at how the autonomics regulate cardiac activity: First, regulation of heart rate is called chonotropic regulation. The sympathetic nervous system will increase the activity of the SA node so that this stimulation will increase the frequency of discharge of action potentials from the SA node, increasing the heart rate. On the other hand, parasympathetic or vagal stimulation will inhibit the SA node, decreasing the heart rate. Dromotropic regulation Sympathetic Increased velocity of conduction Decreased duration of AV nodal delay Parasympathetic Decreased velocity of conduction Increased duration AV nodal delay Lead I represent electrical potential difference between electrodes that are placed on the right arm and on the left arm. In lead I, the electrode that is on the right arm is the negative electrode that of the left arm is the positive electrode. Lead II represents electrical potential difference between electrodes that are placed on the right arm and on the left leg. The electrode of the right arm is designated as the negative electrode that of the left leg as the positive electrode. Lead III represents electrical potential difference between electrodes that are placed on the left arm and on the left leg. The electrode of the left arm is designated as the negative electrode that of the left leg as the positive electrode. Regulation of the velocity of conduction of impulses in the heart is called dromotropic regulation. Sympathetic stimulation will increase the velocity of conduction of impulses in the heart so it will decrease the duration of the AV nodal delay. In contrast, parasympathetic stimulation decreases the velocity of conduction of impulses in the heart prolonging the duration of the AV nodal delay. *** In parasympathetic or VAGAL stimulation, buma-VAGAL ang heart rate and velocity of conduction. ď Inotropic regulation Sympathetic Increased force of atrial and ventricular contraction Parasympathetic Decreased force of atrial contraction Regulation of the force contraction of the myocardial cells or inotropic regulation is by increasing membrane permeability to Ca++. Sympathetic stimulation increases the force of contraction of both the atria and ventricles. As for parasympathetic stimulation, it decreases the force of atrial contraction and it has no direct effect on the force of ventricular contraction. It has no direct effect but it has an indirect effect, that is, parasympathetic stimulation will prolong the duration of the AV nodal delay allowing more time for ventricular filling so the more the ventricles are filled with blood, the more the ventricular wall is stretched, and the greater will be the force of ventricular contraction. Cardiac Cycle Cardiac cycle is the sequence of events - electrical and mechanical events taking place in the heart from the beginning of one heart beat initiated by an impulse from the SA node to the beginning of the next heart beat also initiated by an impulse from the SA node. Electrical events – depolarization, repolarization of the atria and depolarization and repolarization of the ventricle Mechanical events – contraction or relaxation of the atria and ventricles Electrical events The electrical events will precede the mechanical events. All the electrical events taking place in the heart can be recorded by the electrocardiogram (ECG). To get an ECG tracing, electrodes are placed on the four extremities of the subject as well as on different locations on the chest wall. This electrodes act as sensors so that it will be able to pick up electrical potentials produced by the myocardial cells so that what is seen on the ECG tracing will represent electrical potentials and electrical activities of the myocardial cell. PHOTO: Einthoven triangle illustrating the electrocardiographic connections for standard limb leads I, II, and III. The electrode that is placed on the right arm is always negative and on the left leg, it is always positive. In one lead, the electrode is positive when it is located nearer on the apex of the heart. Lead II will approximate the direction of impulse transmission in the heart. So that when asked to measure the duration of the different ECG waves, the amplitude of the different ECG waves, it is preferable to use lead II because it approximates the direction of impulse transmission in the heart – right arm is negative, left leg is positive (from base to apex). Right arm (negative) By placing electrodes particularly on the four extremities, bipolar limb leads are formed or standard limb leads. There are three bipolar limb leads – Lead I, II and III. These leads will represent electrical potential difference between two electrodes placed on two different extremities. In order to have an electrical potential difference between two electrodes, one electrode is arbitrarily designated as the negative electrode and the other one is the positive electrode. Left leg (positive) Lead II 11 Shannen Kaye B. Apolinario, RMT repolarization, it will appear as a downward or negative deflection because the direction of repolarization in the atria follows the direction of depolarization – repolarization is toward a positive electrode. This means that in the atria, the first part to depolarize is also the first part to repolarize and the last to depolarize is also the last part to repolarize. P-R segment (isoelectric) S-T segment (isoelectric) When the impulse reaches the AV node, there will an AV nodal delay ad that is represented by the straight line called a P-Q or P-R segment. The P-R segment starts at the end of P up to the beginning of the QRS complex. It is a straight or isoelectric line because of the delay on the impulse transmission at the AV node. From the beginning of P to the beginning of the QRS complex is the P-R interval. The P-R interval will cover the P wave representing atrial depolarization and the P-R segment that represents AV nodal delay. PHOTO: Depolarization of interventricular septum from the left to right bundle branch PHOTO: Important deflections and intervals of a typical scalar ECG. Above is an example of an ECG tracing that shows electrical events in the heart in one cardiac cycle. The P wave represents atrial depolarization, QRS wave or complex represents ventricular depolarization, and T wave represents ventricular repolarization. ECG Rules: Depolarization (+) electrode = upward Depolarization away from (+) electrode = downward Repolarization (+) electrode = downward Repolarization away from (+) electrode = upward Why is there an upward or positive deflection and a downward or negative deflection? The rule in ECG is that if depolarization will move towards a positive electrode, it is recorded as an upward or positive deflection. On the other hand, if depolarization will move away from a positive electrode, it is recorded as a downward or negative deflection. In repolarization, if the electrode moves toward a positive electrode, it is recorded as negative or downward deflection and if repolarization will move away from a positive electrode, it is recorded as an upward or positive deflection. Remember that in lead II, the positive electrode is on the left leg. P wave P wave - atrial depolarization, it is a positive deflection. Remember that the impulse is generated from the SA node transmitted to the AV node so the direction of impulse transmission in the atria is it moves towards a positive electrode. That is why the P wave is recorded as an upward deflection. There is no ECG wave that represents atrial repolarization because atrial repolarization occurs simultaneously with ventricular depolarization. If ever there is an ECG wave that will represent atrial 12 Shannen Kaye B. Apolinario, RMT QRS complex will represent ventricular depolarization. It is a complex made up of three waves. In the QRS complex, there is an initial negative or downward deflection that represents depolarization of the interventricular septum which will occur from left bundle branch to right bundle branch. The positive electrode is in the left leg [it is moving from the left to right bundle branch] so it is moving away from a positive electrode that is why the Q wave which represents the depolarization of the interventricular septum and is recorded as a downward or negative deflection. R wave is a very high positive deflection that represents depolarization of the cardiac apex that is definitely towards a positive electrode. Then there is a second downward deflection which is the S wave. So which part of the heart will depolarize last? Usually it goes from the anterobasal ď apex ď posterobasal so when the wave of depolarization moves from the apex to posterobasal part, again it is moving away from a positive electrode so the S wave which represents depolarization of the posterobasal part of the ventricle is recorded as negative or downward deflection. T wave is only a part of ventricular repolarization because ventricular repolarization starts at the end of QRS complex. So from the end of S wave to the beginning of T wave, there is an isoelectric line or the S-T segment. Recall the action potential generated in the ventricle, the phase of repolarization that represents the S-T segment is the plateau or phase II. There is a straight line because of the equal conductance of Ca+ and K+; there is no change in membrane potential. The T wave will represent only the phase III of repolarization or the final phase of repolarization and it is a positive or upward deflection. In the ventricles, the repolarization does not follow the direction of depolarization, unlike in the atria. Repolarization will occur in the opposite direction: from posterobasal ď apex ď anterobasal. It is moving away from a positive electrode because from the apex, it will go up hence it is recorded as an upward or positive deflection. So in the ventricles the first part of the ventricles that will depolarize is the last part to repolarize and the last part to depolarize will be the first part to repolarize. So when it is said ventricular repolarization, it is actually the S-T interval, from the end of S to the end of T, not just the T wave. Mechanical events Following depolarization, the atrial and ventricular muscles will contract and it is called the systole. During systolic phase of the cardiac cycle, blood is ejected from the different chambers of the heart. Following repolarization, the muscles will relax and it is called diastole. During diastolic phase, there will be filling of blood in the different chambers of the heart. The average duration of one cardiac cycle is 0.8 second. The duration of the systolic phase is 0.27 second and that of the diastolic phase is longer which 0.53 of a second and this happens at the heart rate of 75 beats per minute. When the heart rate increases, the duration of the cardiac cycle will decrease so the duration of the systole and diastolic phases is also decreased. But there is a greater decrease in the duration of the diastolic phase and there is a constant duration in the systolic phase when the heart rate increases. Correlation of the Electrical and Mechanical Events in the Heart in One Cardiac Cycle SAN atr. depo (P wave) AVN VCS atr. systole delay (P-R segment) 20% VF inc. AP (a wave) inc. VF vent. depo (QRS) atr. repo vent. systole inc. VP atr. diastole dec. AP VP > AP close AV valves (1st heart sound) isovolemic contractions: slight inc. AP (C wave) VP > 80 mmHg open SL valves rapid ejection reduced ejection; atrial filling vent. repo vent. diastole dec. VP (S-T interval) AP > VP protodiastole close SL valves (2nd heart sound) isovolemic relaxation; inc. atr. filling; inc. AP (V wave) AP > VP open AV valves rapid inflow diastasis – reduced inflow of blood to the ventricles atr. – atrial AV - antrioventricular AVN – atrioventricular node dec. - decrease depo – depolarization inc. - increase repo – repolarization SAN – sinoatrial node SL - semilunar vent. – ventricular/ventricle VF- ventricular filling VP – ventricular pressure At the beginning of one cardiac cycle, before an impulse is generated from the sinoatrial (SA) node, the atrium and ventricles are all relaxed – atrial systole and ventricular diastole. The semilunar (SL) valves are closed but the atrioventricular (AV) valves are open so that will allow blood to flow from the atria to the ventricles. In fact, 80% of ventricular filling (VF) takes place when all four chambers of the heart are in a relaxed state. It is not needed for the atria to contract to have ventricular filling because its contraction is weak – “primer pump”, so whenever the AV valves are open, there is 80% of ventricular filling. 13 Shannen Kaye B. Apolinario, RMT An impulse will be generated from the SA node transmitted to the AV node. Transmission of the impulse from the SA node to the AV node is facilitated by the three internodal tracts: Bachman, Wenckeback and Thorel. In the process, the atria will undergo depolarization recorded in the ECG as the P wave. The response of the atrial muscle to depolarization is to contract so there will be atrial systole. When the atria contracts, although it is a weak pump, there is still blood ejected to the ventricles and that will account for only 20% of ventricular filling. When the atria are contracting, atrial pressure increases and remember that there are no cardiac valves between the atria and veins so that any increase in atrial pressure can be transmitted to the veins so that in the recording of the jugular venous pressure curve will show increase atrial pressure during atrial systole and this is called A wave. A wave is not an ECG tracing, it is only a label to the increase atrial pressure during atrial systole. When the impulse reaches the AV node, there will be a delay called the AV nodal delay, in the ECG that is recorded as the P-R segment. The importance of the AV nodal delay is that it will provide more time for ventricular filling. From the AV node, the impulse will now be transmitted to the ventricular conduction system (VCS) or Purkinje system and that will cause ventricular depolarization in the ECG recorded as the QRS complex. The response of the ventricular muscle to depolarization is to contract so following ventricular depolarization will be ventricular systole. When the ventricles contract, the ventricular pressure increases. Simultaneous with ventricular depolarization is atrial repolarization and no ECG wave represents atrial repolarization. The response of the atrial muscle to repolarization is to relax so atrial diastole happens. Since the atria is relaxed, there will be a decrease in the atrial pressure. When the ventricular pressure exceeds atrial pressure, there will be a pressure gradient and that will now close the AV valves therefore the first heart sound will be heard. There will be a condition wherein the SL are still closed and the AV valves are now closed, there is no change in ventricular volume because all the cardiac valves are closed but since the ventricles are contracting, there is increase in ventricular pressure and this is called isovolumic or isovolumetric contraction phase of the cardiac cycle. When the ventricles are contracting, ventricular pressure still increases and this high pressure may push the AV valves to bulge into the atria and that will cause a slight increase in atrial pressure which is now called the C wave. But remember that the AV valves does not over-bulge into the atria when the ventricular pressure is increased because when the ventricles contract, the papillary muscles will contract pulling the chordae tendinae which will prevent over-bulging of the AV valves into the atria resulting to only a slight increase in the atrial pressure. When ventricular pressure exceeds 80 mmHg, this will push open the SL valves and following the opening of the SL valves is the period of rapid ejection of blood from the ventricles to the arteries: aorta and pulmonary arteries. But when it is ejecting more and more blood, the volume of the blood in the ventricles as well as ventricular pressure will start to decrease. So the period of rapid ejection will now be followed by a period of reduce ejection of blood from the ventricles to the arteries and at the same time, the blood that is contained in the aorta will drop off to the arteries to the different organs of the body and the veins are also collecting blood so that little by little, there will be atrial filling. The ventricles will undergo repolarization so this is the S-T interval in the ECG. The response of the ventricular muscle to repolarization is to relax so there will be ventricular diastole therefore ventricular pressure will start to decrease. Pressure in the aorta or in the arterial system is always high so that when arterial or aortic pressure now exceeds ventricular pressure, this will close the semilunar valves and that will produce the second heart sound. But there is a short interval of time between ventricular diastole and closure of SL valves which is called protodiastole. There will be a condition again wherein the SL valves are now closed, the AV valves are still closed so there is no change in ventricular volume but since the ventricles are in a relaxed state, ventricular pressure decreases and this is called isovolumic relaxation. At the same time as isovolumic relaxation, the atrial filling increases which will again increase atrial pressure and is called the V wave. When atrial pressure exceeds ventricular pressure, this will now open the AV valves which will be followed by a period of rapid inflow of blood to the ventricles and this event will account for the 80% of ventricular filling. When there is more blood filled in the ventricle, it will be slightly stabilized so that the period of rapid inflow will be followed by a period of reduced inflow of blood to the ventricles called diastasis. From that, there will be another impulse from the SA node beginning another cycle. All of these events take place in the heart for 0.8 second. Ventricular pressure is initially low. It will increase slightly during atrial systole because of the additional volume of blood that will be ejected by the atria to the ventricles. Ventricular pressure will actually increase during isovolumic contraction and still high during the period of ejection of blood. But as the volume of blood in the ventricles decreases, ventricular pressure will also decrease. It will continue to decrease during the period of isovolumic relaxation. It will remain low during the periods of rapid inflow of blood to the ventricles and diastasis. Again, slight increase with atrial systole because of the additional volume of blood ejected from the atria to the ventricles. Closing of the AV valves will mark the onset of isovolumic contraction. Remember that in isovolumic contraction, all the cardiac valves are closed so there will be no change in the volume of ventricles. So that means at that point, the first heart sound will be heard. Cardiac Cycle Opening of the AV valves mark the end of isovolumic relaxation so there will be period of ventricular filling. What will happen at the end of isovolumic contraction? There will be opening of the SL valves. While at the beginning of isovolumic relaxation, the SL valves close so the second heart sound will be heard. Atrial Pressure Curve incisura Phases: as – atrial systole ic – isovolumic contraction ejection – rapid and reduced ejection phase ir – isovolumic relaxation R inflow – rapid inflow of blood to the venticles diastasis as – atrial systole The period of ventricular systole covers from the beginning of isovolumic contraction until the end of the ejection phase while the ventricular diastole will start with isovolumic relaxation up to the end of atrial systole. Ventricular Pressure Curve SL valves open SL valves close – 2nd heart sound ***Atrial pressure curve – yellow dotted line Aortic pressure or arterial pressure is always high. It will continually increase during the period of rapid ejection because of the increased volume that will be ejected from the ventricle to the aorta. So if the volume of blood in the aorta is greater, there will be greater force exerted by that volume of blood on the aortic wall. During the period of reduced ejection, the aortic pressure decreases because there will be peripheral run-off blood, meaning to say, blood that is contained in the aorta will now be distributed to the arteries, to the arterioles, and to the different organs of the body so the volume of blood in the aorta will decrease and that will now cause the aortic wall to recoil. When the aortic wall recoils, there is a slight vibration of blood inside so there will be slight increase again in aortic pressure which is called a dichotic notch or incisura. All throughout the period of ventricular diastole, the aortic pressure is stable and is slightly low but it is still higher compared to the ventricular pressure. *** Ventricular pressure curve – green line 1st heart sound 14 AV valves open Shannen Kaye B. Apolinario, RMT The pressure difference between the aorta and the ventricles will cause the closing of the SL valves when aortic pressure exceeds ventricular pressure. Ventricular Volume Curve The 3rd heart sound heard in abnormal conditions is due to ventricular filling. There is an increase in ventricular filling coinciding with the appearance of the 3rd heart sound. At the start, there is additional increase in volume with atrial systole – additional 20% of ventricular filling. During isovolumic contraction, all cardiac valves are closed so there is no change in the ventricular volume. During period of rapid ejection, blood is ejected from the ventricles so the ventricular volume will decrease. In the period of isovolumic relaxation, all cardiac valves are closed so there is no change in ventricular volume. During the period of rapid inflow, there is a very high increase in ventricular volume. It is somewhat stabilized in diastasis and a slight increase again during atrial systole. Atrial Pressure or Central Venous Pressure (CVP) Curve a c c v PHOTO: Left atrial, aortic, and left ventricular pressure pulses correlated in time with aortic flow, ventricular volume, heart sounds, venous pulse, and the electrocardiogram for a complete cardiac cycle. Ventricular Volume Pressure Curve (Ejection Loop) A wave is increase in atrial pressure during atrial systole. C wave is slightly increased in atrial pressure during isovolumic contraction when the increased ventricular pressure pushes the AV valves to bulge into the atria. The V wave is increase atrial pressure during isovolumic relaxation where it is simultaneous with the increase in atrial filling. Heart Sounds The 1st heart sound is due to closure of the AV valves. Closure of the AV valves will mark the onset of the period of isovolumic contraction so when seen at the ventricular volume curve, it is a straight line – no change in ventricular volume. The 2nd heart sound is due to the closure of the SL valves that will now mark the onset of the period of isovolumic relaxation. Again, there is no change in the ventricular volume. 15 Shannen Kaye B. Apolinario, RMT PHOTO: Relationship between left ventricular volume and intraventricular pressure during diastole and systole. Also shown by the heavy red lines is the “volume-pressure diagram,” demonstrating changes in intraventricular volume and pressure during the normal cardiac cycle. EW, net external work. Reduced ejection Volume of blood remain on ventricles after contraction Rapid ejection PHOTO: Pressure-volume loop The vertical axis will represent changes in ventricular pressure, the unit is mmHg. The horizontal axis represents changes in ventricular volume and the unit is either cc or mL. In relation to changes in ventricular volume and pressure, the cardiac cycle is divided into four phases. The letters represent each point. Point A - ventricular volume is 50 mL. This 50 mL is actually the volume of blood remaining in the ventricles after contraction. At 50 mL, the pressure is low – a little above 0 mmHg. At point A, the atrioventricular valves open. Phase I – from 50 mL, the volume of blood in the ventricles increased to 120 or 130 mL but there is little increase in pressure. Phase I is ventricular filling. Point B - the volume of blood is 130 mL. There is closing of the AV valves so the first heart sound is heard. Phase II – the volume of blood is 130 mL and the pressure continues to increase. At phase II, there is period of isovolumic contraction. Point C – opening of SL valves. When the SL valves open, the ventricular pressure still increases but the volume is already decreasing. From C prime, it is the period of rapid ejection. Phase III – in the latter part of Phase III – the volume decreases and the pressure decreases, this is now the reduced ejection. Point D – closing of the SL valves so the second heart sound is heard. Phase IV – the volume of blood is still 50 mL but the pressure is decreasing and decreasing. This is isovolumic relaxation. 16 Shannen Kaye B. Apolinario, RMT “ I can do EVERYTHING through Him who gives me strength” -Philippians 4:13 GOD BLESS YOU! ď Cardiodynamics (Gloria Marie M. Valerio, MD) Definition of Terms: Cardiac Output (CO) is the amount/quantity/volume of blood ejected by each ventricle per minute CO = SV x HR Normal Value: 5 L/min 5, 000 mL/min * Although the left ventricle will pump blood against a higher pressure of resistance in the systemic circulation compared to the right ventricle, although the workload of the left ventricle is greater than that of the right ventricle, although the left ventricular wall or musculature is thicker than that of the right ventricle, the output of the two ventricles are the same. Heart Rate (HR) the number of contractions/heart beats/cardiac cycles per minute Normal Value (normal resting adult): 75 beats per min. Correlation of SV, EDV, ESV with the Ejection Loop From point D to point A, the volume of blood increases in the ventricles with little increase in pressure, this is the ventricular filing time. At point A, the atrioventricular (AV) valves will close so that whatever amount of blood will be present in the ventricles before closure of the AV valves, that is now the end diastolic volume (EDV) which is a little less than 150 mL, average of 130 mL. From point A to point B, the ventricles will now start to contract, but since all the valves are closed, there will be no change in ventricular volume. From point B to C, that is the period of ejection of blood from the ventricles so the EDV will be decreased and the amount that will be ejected is the stroke volume. At point C, the semilunar (SL) valves will close, the ventricles will start to relax and the volume of blood that is now in the ventricles is the end systolic volume (ESV). Stroke volume is equal to EDV minus ESV or ESV + SV will be the EDV. CO = SV x HR * In a normally functioning heart, the heart rate and rhythm are determined by the activity of the SA node. Stroke Volume (SV) is the amount/quantity/volume of blood ejected by each ventricle per contraction/per heartbeat/per cardiac cycle SV = EDV – ESV Normal Value: 70 mL The stroke volume of the left ventricle is the same of that of the right ventricle. End Diastolic Volume (EDV) is the amount/quantity/volume of blood in the ventricles at the end of diastole, before systole = PRELOAD Normal Value: 110-130 mL * Whatever amount of blood that will be present in the ventricles after the ventricular filling time, before contraction of the ventricle; that is the end diastolic volume. It is the EDV that will exert force on the ventricular wall stretching the ventricular wall before it contracts thus it is called preload or the load of the ventricle that is needed to be ejected. End Systolic Volume (ESV) is the volume of blood in the ventricles at the end of systole Normal Value: 45-50 mL * ESV is the amount/quantity/volume of blood remaining in the ventricles after contraction. No matter how strong the force of ventricular contraction is, there will always be a certain amount of blood that will remain in the ventricles. EDV – ESV Whatever factor that will affect EDV and ESV will also affect the SV. Whatever factor that will affect the SV and HR will affect the CO. As for the SV, this is determined mainly by the force of myocardial contraction. So if the force of myocardial contraction increases, the SV will increase. On the other hand, if the force of myocardial contraction decreases, the SV will also decrease. We can therefore say that the HR, SV as a reflection of the force of myocardial contraction are factors intrinsic to the heart that will affect the cardiac output. But aside from factors intrinsic to the heart, there are also factors outside the heart called peripheral factors that may also affect the cardiac output. What are the factors outside the heart that may affect the cardiac output? 1. Total blood volume 2. Status of the venous sytem that will deter blood back to the heart 3. Status of the arterial system which is the opposing force to ventricular contraction All of these factors make up the vascular or circulatory system so that means that the activity of the heart is dependent on the status of the vascular system and vice versa – the status of the vascular system is also dependent on the activity of the heart. The heart and the vascular system are actually inter-dependent and that is because of the close nature of the cardiovascular system. End Diastolic Volume (EDV) What are the factors that will influence the EDV? EDV is the volume of blood in the ventricles after the relaxation phase, before contraction. PHOTO: Preload 1 Shannen Kaye B. Apolinario, RMT| Take note of where the black arrows are directed. These black arrows represent the EDV. It is directed towards the ventricular wall so the greater the volume or EDV, the greater the force that will be exerted on the ventricular wall. If the force exerted on the ventricular wall is greater, that will now stretch the ventricular wall and if the ventricular wall is stretched, that will now increase the force of myocardial contraction. So in other words, the greater the EDV, the more the ventricular wall is stretched, the greater will be the force of contraction. And if the force of contraction is increases, stroke volume increases, cardiac output increases. So EDV is directly related to cardiac output. Factors Affecting EDV 1. Effective filling time Filling time refers to the duration of the diastolic or relaxation phase because that is when the ventricles are filled with blood. FT ď EDV ď SV ď FT ď EDV ď SV ď FT ď EDV ď SV ď When the heart rate increases from 180 beats per minute and above, the duration of the filling time is now severely compromised. And sympathetic stimulation can no longer compensate on the very short duration of filling time. So the increase in heart rate is now less than the decrease in stroke volume so the cardiac output will now decrease. There is a range wherein the cardiac output will start to decrease with an increase in heart rate. CO One factor that will influence the duration of the filling time is heart rate. When the heart rate increases, the duration of the filling time will decrease – less time for ventricular filling so the EDV will decrease and so will the SV and CO. HR ď When the heart rate increases from 60-180 beats per minute, the duration of the filling time is quite affected but still, the ventricles can still be filled with blood because from 60-180 beats per minute, the increase in heart rate is equal to the decrease in stroke volume so that the cardiac output is maintained at a constant level. CO If the duration of filling time increases, there will be enough time for the ventricles to accommodate a larger volume of blood so the EDV increases. Again, if the EDV is greater, the greater the ventricular wall is stretched, the greater the force of contraction so the SV as well as the CO increases. All are directly directed. HR ď Both of the equations are true but there is a range of heart rate. The horizontal axis on the graph represents heart rate while the vertical axis represents cardiac output. Based on the graph, when the heart rate increases from 0–60 beats per minute, there is a corresponding increase in cardiac output. They are directly related because when the heart rate increases from 0-60, the duration of filling time is not yet compromised because the normal heart rate is 75 beats per minute so that means that the ventricles can still be filled with blood adequately so the cardiac output increases. In the first phase, sympathetic stimulation increases the heart rate. Sympathetic stimulation increases not only the heart rate but also the force of contraction. When the heart rate increases, the stroke volume increases therefore the cardiac output increases. CO The reverse is also true that when the HR decreases, the duration of the filling time will increase, more EDV, SV and CO. Increased HR decreases the CO and decreased HR increases the CO but going back to the formula: CO = SV x HR, heart rate is directly related to CO, meaning to say that an increase in HR will increase the CO. Which among the formula is true? In the formula, it is directly related and of course that is true. If the HR increases, there will be an increase in the frequency of depolarization on the sarcolemma of the cardiac muscle cell. So the more the cardiac muscle is depolarized, the more Ca++ enters the cell and if more Ca++ enters the cell, the greater the force of contraction, the more the stroke volume increases, increased cardiac output. That is how an increase in HR will increase the CO. What about the other equation? If you will recall, if the heart rate is 75 beats per minute, the duration of one cardiac cycle is 0.8 sec, the duration of the systolic phase is 0.27 sec, and much longer is the duration of the diastolic phase which is 0.53 sec. The longer duration of the diastolic phase is important because it is during the diastole that the ventricles are filled with blood and at the same time, it is during diastole that perfusion of oxygen supply to the cardiac muscle is better. Cardiac Cycle Duration with Heart Rate Duration Heart Rate 75 beats/min Cardiac cycle 0.80 sec Systole 0.27 sec Diastole 0.53 sec Heart Rate 200 beats/min 0.30 sec 0.16 sec 0.14 sec When the heart rate increases to 200 beats per minute, the duration of cardiac cycle will decrease from 0.8 to only 0.3 sec but if you will compare the decrease in the duration of systole and diastole, diastole is more affected (bigger decrease in duration of diastole) from 0.53 to 0.14 sec which means that the filling time is really compromised and the EDV is severely decreased. 2. Effective filling pressure EFP = CVP – ITP EFP - effective filling pressure CVP – central venous pressure ITP – intra-thoracic pressure Aside from the duration of the filling time, another factor that may influence the diastolic volume is the effective filling pressure or transmural pressure - pressure difference between the inside and outside of the heart. Pressure inside the heart is the central venous pressure while outside is the intra-thoracic pressure. The greater the difference between the pressure inside and outside of the heart, the greater the effective filling pressure. And when the effective filling pressure is greater, that will now distend the ventricles, allowing the ventricles to accommodate a larger EDP. The intra-thoracic pressure is always negative or below atmospheric pressure and that will enable the heart as well as the other dilatable structures in the thoracic cavity to be distended so it can accommodate greater volume. 2 Shannen Kaye B. Apolinario, RMT| 3. Myocardial compliance All elastic structures have the property of compliance and that is the measure of distensibility or stretchability of an elastic structure. C=âV âP Compliance is equal to change in volume over change in pressure. For a structure to have an increase in compliance, the change in volume should be higher or greater compared to the change in pressure. And this is true for the ventricles, remember that the ventricles can accommodate a large volume of blood with little increase in pressure and that is because of the presence of the elastic tissue in the cardiac muscle that will enable the ventricles to distend. 4. Venous return VR = CO 5 L/min The most important factor that determines the EDV is the volume of blood returning to the heart per minute and that is venous return. Because of the closed nature of the cardiovascular system, whatever volume of blood that will return to heart per minute, will be effectively ejected or pumped by the heart per minute so that means venous return is equal to cardiac output. The average venous return is also 5 L or 5,000 mL per minute. End Systolic Volume (ESV) What is the major factor that will affect the volume of blood remaining in the ventricles after contraction or ESV? It is the force of contraction. So if the force of myocardial contraction increases, SV will increase, ESV will decrease. If the force of myocardial contraction decreases, SV will decrease, ESV will increase. In other words, force of myocardial contraction is inversely related to the end systolic volume (ESV). Within physiologic limits, the force of myocardial contraction will be determined by the initial muscle length that means resting length of the cardiac muscle or length of the cardiac muscle before it contracts. The force of contraction will depend on the length of the cardiac muscle before it contracts so what will stretch the cardiac muscle before it contract ? The force that will be exerted by the EDV. the greater the EDV, the greater will be the force exerted on ventricular wall, the more the ventricular wall will be stretched and that will now increase the force of contraction and this is called heterometric autoregulation. Autoregulation means that the heart itself can regulate its own force of contraction. Metric is the length. Hetero - changes. So the change in the length of cardiac muscle will enable the heart to regulate its own force of contraction. Remember that this only happens within physiologic limits – it does not stretch continuously when the EDV is increasing and more and more powerful the force contraction becomes. There is a limit because when the cardiac muscle is overstretched or distended, there will be less overlapping between thin filaments and thick filaments so there will be less myosin length that will bind on the actin active site so when it contracts, it becomes weak. Actin filament Myosin filament But remember that overstretching or overdistention of the cardiac muscle does not occur in the first place because of the presence of connective tissue. The connective tissue on the cardiac muscle and on the pericardium prevents overdistention when the cardiac size increases because connective tissue is less distensible while the elastic tissue allows distension. Factors that affect cardiac muscle length: ďˇ Stronger atrial contraction. Remember that most of the ventricular filling will take place when the ventricles as well as the atria are in a relaxed state. But during atrial systole, there is an additional amount of blood that will be ejected to the ventricles so the EDV increases. If the force of contraction in the atria is greater, there will be more than the 20% that will be added in the ventricular filing, the EDV will be more increased. ďˇ Increased total blood volume. Total blood volume is actually one factor that will affect venous return. So if the total blood volume increases, venous return will increase, EDV will also increase so that will stretch the ventricular wall. ďˇ Increased venous tone. One property of smooth muscle cells present in the vascular wall as well as in the visceral wall is the tone. For example, the stomach and the small intestinal wall have a tone, the same is also true with blood vessels, arteries and veins - their wall has a tone. When the smooth muscle layer in the veins contract, there will be veno-constriction, the blood cannot go back to the heart. The veins are called capacitance vessels because the smooth muscle layer is thin and it has elastic tissue so the venous wall is highly distensible so it can accommodate large volume of blood. If the venous wall is in a relaxed state, the blood in the veins cannot go back to the heart. So what is venous tone? Tone means state of partial contraction. One property of smooth muscle is they can remain partially contracted for a long time. If the wall of the veins is partially contracted, there will be less capacity to accommodate blood so the blood will go back to the heart thus increasing venous return and EDV and that will stretch the cardiac muscle cell. The normal systolic volume (red line) is about 70 mL but if the force of myocardial contraction increases, SV increases so the remaining part becomes smaller. Since the force of myocardial contraction will affect the ESV, what now are the factors that will influence the force of myocardial contraction? What is the EDV and the relationship between EDV and force of myocardial contraction is reflected in the Frank starling’s Law. Factors Affecting ESV a. Force of myocardial contraction 1. Frank Starling’s Law 3 Shannen Kaye B. Apolinario, RMT| ďˇ Increased pumping of skeletal muscle. When you remain in a standing position for a long time, blood pools in the veins of the lower extremities. So again, if there is pooling of blood in the veins of the lower extremities, the venous return will decrease, EDV will decrease, and the cardiac muscle will not be stretched. But once you move, the skeletal muscle will contract and that will compress the veins. When the veins are compressed, that will open up the venous valves. The opening of the valves is directed toward the heart. So when the veins are compressed by skeletal muscle contraction, venous valves will open and blood will return to the heart. * The three factors: increased total blood volume, increased venous tone and increased pumping of the skeletal muscle will first influence venous return. Venous return will then influence EDV, EDV is the one that will exert force on the ventricular muscle to stretch the ventricular muscle. ďˇ Increased negative intrathoracic pressure. Increased negative intrathoracic pressure allows the ventricles to distend, so that will stretch the ventricular muscle. All of these are factors will affect cardiac muscle length before contraction. So if these factors will increase, cardiac muscle length will increase before contraction so that during contraction, the force of myocardial contraction will increase. 2. Autonomics Aside from cardiac muscle length another factor that will influence the force of myocardial contraction is the autonomic innervations: sympathetic that will release catecholamine, norepinephrine, epinephrine; and parasympathetic that will release acetylcholine. Sympathetic stimulation will increase the force of contraction of both the atria and ventricles primarily because norepinephrine binds with β1 receptors will increase membrane permeability to calcium allowing more Ca++ to enter myocardial cell and that will increase the force of contraction. But aside from this, sympathetic stimulation can also increase the heart rate so the more frequent the myocardial cell is depolarized, again, the more Ca++ will enter the myocardial cell and that will increase the force of contraction. In contrast, vagal or parasympathetic stimulation by releasing acetylcholine will decrease the force of atrial contraction. It has no direct effect on the force of ventricular contraction because there is very little, if any parasympathetic or vagal innervation to the ventricles. But that is not the end of sympathetic effects. It does not allow Ca++ to always enter the cell because when it always depolarizes, more Ca++ will enter the cell. But hidni dun nagtatapos ang sympathetic effects. Hindi lang basta nagpapapasok ng ca kasi malimit magdepolarize, mas madaming ca na papasok Another action of sympathetics is when norepinephrine and epinephrine bind with β1 receptors in the heart, this will cause activation of G-proteins. Activated G-proteins will activate the enzyme system adenylyl cylcase that will lead to the formation of an intracellular ligand or a second messenger that is cyclic AMP (cAMP). As a second messenger, cAMP will mediate the actions of catecholamines on the cardiac muscle cell and one action of cAMP is to cause activation of another intracellular enzyme that is protein kinase A (cAMP-PK). One action cAMP-PK is to phosphorylate the Ca++ channels on the sarcolemma. When it is phosphorylated, that will allow more Ca++ to enter that will increase the force of myocardial contraction. But take note that sympathetic stimulation will increase not only the force of contraction; it will also facilitate relaxation of the cardiac muscle by the action of cAMP-PK. So another action of cAMP-PK is to phosphorylate troponin I so that troponin cannot bind with Ca++. If troponin cannot bind with Ca++, the muscle will relax because troponintropomyosin complex will go back to cover the active site of actin due to absence of troponin-Ca++ complex. Another action of cAMP-PK is to phosphorylate an intracellular protein called phospholamban. The normal action of phospholamban is to inhibit the Ca++ pump on the sarcoplasmic reticulum. If the Ca++ pump is inhibited, Ca++ will not return – it will remain bound to troponin C so there will still be muscle contraction. But once phosphorylated by cAMPPK, the inhibitory effect of phospholamban will decrease so the Ca++ pump will be activated and when activated, it will actively transport Ca++ back to the sarcoplasmic reticulum so there will be no Ca++ that is attached to troponin and the muscle will relax. So again, aside from increasing the force of myocardial contraction, sympathetic stimulation can also facilitate relaxation of the cardiac muscle. 3. Calcium Another important factor that will affect the force of myocardial contraction will be the amount Ca++ available that will bind with troponin C. In contrast to the skeletal muscle, there are two sources of Ca++ for myocardial contraction: sarcoplasmic reticulum and ECF. That means that the plasma Ca++ level will have an effect on the force of myocardial contraction. 4. Adequate coronary flow Another factor is adequacy of the coronary arteries. Remember that the coronary arteries supply blood and oxygen to the cardiac muscle itself. So when there is an obstruction (e.g. thrombus or embolus) in one of the branches of coronary arteries, there will be an area of that myocardium that will be deprived of oxygen supply so the area will be ischemic. If the ischemic area is not corrected, it will cause necrosis to the tissue developing an infarct and that infarcted area cannot contract anymore. Since there is an area in the myocardium that is not contracting, the overall force of contraction will decrease and that will predispose to ventricular or heart failure. 5. PHOTO: Schematic diagram of the movement of calcium in excitation-contraction coupling in cardiac muscle. Influx of Ca++ from interstitial fluid during excitation triggers release of Ca++ form the sarcoplasmic reticulum (SR). The free cytosolic Ca++ activates contraction of the myofilaments (systole). Relaxation(diastole) occurs as a result of uptake of Ca++ by the SR, by extrusion of intracellular Ca++ by the 3 Na+-1 Ca++ antiporter, and to a limited degree by the Ca++-ATPase pump. βR, β-adrenergic receptor: cAMP-PK, cAMP-dependent protein kinase. 4 Shannen Kaye B. Apolinario, RMT| Heart rate The force of myocardial contraction can also be influenced by heart rate. It is mentioned earlier that when the heart rate increases, the depolarization of cardiac muscle will be more frequent and remember that with each depolarization, it allows more Ca++ to enter and that will increase the force of contraction. Factors that influence or regulate heart rate: ďˇ Autonomics. The most important factor. Sympathetic nerves innervating the SA node and the effect of norepinephrine is to increase membrane permeability to Na+ and Ca++ that will make the SA node more excitable so the heart rate will increase. On the other hand, parasympathetic or vagal stimulation will make the SA node more permeable to K+ so that will hyperpolarize the SA node making it less excitable, decreasing the heart rate. ďˇ Hormones. Aside from the neurotransmitters released by the autonomic nerves, heart rate can also be affected by several hormones one of which is cortisol - corticosteroids from the adrenal cortex. The effect of cortisol is to potentiate the effect of epinephrine so that means increased corticosteroids may increase the heart rate. 7. Afterload Afterload is the aortic pressure load, opposing force to left ventricular contraction. Why in the aortic artery only and not in pulmonary artery? Because remember that there is low/no pressure area in the pulmonary circulation, not much resistance to right ventricular contraction unless there is pulmonary hypertension. More of the resistance happens in the left ventricle because there is high pressure area in the arterial system. So when we say afterload, it is the pressure in the aorta. Other hormones are T3 and T4 – thyroid hormones. Thyroid hormones directly stimulate the SA node so that one clinical manifestation of hyperthyroidism is tachycardia. ďˇ ďˇ 6. Neural reflexes. Heart rate can also be influenced by neural reflexes that are centered on the medulla and that will include reflexes that actually regulate arterial blood pressure: the baroreceptor reflex and the chemoreceptor reflex. These reflexes that regulate arterial blood pressure can also regulate heart rate. Bainbridge reflex. This time, when venous return increases, the volume of blood in the right atrium will increase and that will stretch the right atrial wall where you have the SA node. When the right atrial wall is stretched, the SA node is stimulated and that will increase the heart rate. So this Bainbridge reflex is sensitive to an increase in blood volume that will return to the right atrium. ďˇ Exercise. During exercise, heart rate increases for two reasons: increased metabolism and increased sympathetic stimulation. ďˇ Excitement and anxiety. Emotions like excitement and anxiety will also increase the heart rate partly because of increased sympathetic stimulation. ďˇ Temperature. Increased environmental temperature can also increase the heart rate. Not only environmental temperature but also body temperature so when there is fever, heart rate increases. PHOTO: Afterload Remember the photo on preload, the arrows are directed on the ventricular wall because the EDV exerts force on the ventricular wall to increase the force of contraction. When the ventricles contract, the blood or EDV goes in the aorta so the direction is directed towards the aorta but the pressure in the aorta counteracts the EDV so when the pressure is greater on the aorte, EDV will have a hard time to go out. So if the aortic pressure increases, stroke volume decreases, end systolic volume increases and this is shown on the photo below: Cardiac glycosides Cardiac glycosides are given to patient suffering from congestive heart failure. The main purpose of giving cardiac glycosides is to increase the force of myocardial contraction. When the muscle is relaxed, the Na-K pump is activated. Na-K pump will extrude 3 Na+ in exchange for 2 K+ transported into the cell creating a concentration gradient for Na that will now activate the Na+Ca++ pump. If the Na+-Ca++ pump is activated, 3 Na+ will go inside and Ca+ will go outside decreasing the concentration of Ca+ inside the cell and that is not ideal if there is congestive heart failure. It is needed for the Ca++ to remain inside the cell to have an increased force of contraction. So what the cardiac glycosides do is to inhibit the Na-K pump so there will be no concentration for Na+ and that will not activate the Na-Ca pump. If the Na-Ca pump is not activated, there will be no increase concentration of Ca++ that will go out of the cell or Ca++ will remain inside the cell so the force of contraction is increased. The normal stroke volume is still represented by the red line. When the aortic pressure increases, the tendency of the ventricles is to increase its contraction because the pressure against it is stronger. That’s why the pressure in the ventricles is increasing and increasing but because the opposing force is greater, stroke volume is decreased and the end systolic volume is increased. So what is the consequence of that? There is much left so in every venous return, what will happen in the EDV? There is much left but 5 Shannen Kaye B. Apolinario, RMT| even if there is less amount that goes out, some will still go back to the heart, so what will happen to the EDV? EDV will increase because there is much [blood] left and there was an additional amount added during the relaxation phase. When the EDV is increased, the ventricular wall will be stretched; its contraction will be increased. But even if the contraction is increased but there is persistent increase in aortic pressure, less will still be ejected so that eventually there will be pulling of blood in the left ventricle and that will cause the left ventricle to dilate. Since the SV is less, eventually the venous return will also be lessened because there is a decrease in the amount ejected so less will go back or return to the heart. To summarize the factors that will determine the cardiac output, there are factors intrinsic to the heart and there are factors outside the heart. Factors intrinsic to the heart will include the heart rate and the force of myocardial contraction. Factors outside the heart or peripheral/coupling factors will include the preload (factors that will affect EDV) and afterload or aortic pressure load. These are the major factors that will determine cardiac output Effects of Various Conditions on Cardiac Output Increase: - Anxiety or excitement (50-100%) – partly because of sympathetic stimulation. - Eating (30%) – eating increases blood flow to the gastrointestinal tract. Increase in blood flow increases venous return and increases cardiac output. - Exercise (up to 700%) – increased metabolism, sympathetic stimulation. - Increased environmental temperature - Pregnancy – due to increased blood volume that will increase venous return. - Epinephrine Decrease: PHOTO: Pressure-Volume Loop. Cardiac output is the volume of blood pumped by the heart each minute. In the steady state the output from both the right and left ventricles is the same. The pressure-volume loop for the left ventricle is depicted here. The cardiac output is calculated as: Cardiac output = Heart rate x stroke volume where: stroke volume = end-diastolic volume – end systolic volume Increases in venous return (increased preload) increase the stroke volume and thus cardiac output. Increases in arterial pressure (increased afterload) decrease stroke volume and thus cardiac output (lower panel). 8. Sitting or lying down from a standing position (20-30%) - Rapid arrhythmias – heart rate of 200 beats per minute that will severely compromise the duration of the filling time so that will decrease the cardiac output. - Heart diseases – examples are congestive heart failure, myocardial infarction, cardiac valve diseases, arrhythmias, chronic hypertension all of these factors that will decrease the force of myocardial contraction. No change - Sleep - Moderate change in environmental temperature Ejection Fraction (EF) Stenosis Another condition that will increase aortic pressure is stenotic aortic valve. If the aortic valve hardens, even if the ventricular pressure is greatly increased, the SV and cardiac output will still be diminished. Blood will again accumulate in the left ventricle and eventually, the left ventricle will dilate so the force contraction will decrease. Cardiac factors: Coupling factors: Heart rate Preload Cardiac Output Myocardial contractility - Percentage of the EDV is ejected by the left ventricle per contraction EF = SV x 100 EDV Normal value: 65-70% The volume of blood that should be ejected per contraction should be 65-70% of 130 mL that is why the average stroke volume is 70 mL. Determinants of Cardiac Output 6 - Afterload Shannen Kaye B. Apolinario, RMT| In patients suspected of having congestive heart failure, one procedure that is requested is 2-D echocardiogram to determine the ejection fraction (EF). Because if the EF falls below what is normal, it means that the SV is decreased and it is decreased because the ventricular contraction is weak. Cardiac Index - Cardiac output per square meter or body surface area Normal value: 3L/min/m2 of body surface area Another factor that may influence cardiac output is body surface area and the normal cardiac index is 3L/min/m2. It means that in the elderly where the physical activity is less, the skeletal muscles atrophy so the body surface area decreases and the cardiac output and cardiac index is decreased. Compared to the athletes who have welldeveloped muscles, they have a bigger body surface area so the CO and cardiac index is increased because what happens is that when there is increased need (bigger muscles) to be supplied with blood, the heart compensates so the CO increases. Cardiac Reserve - Maximum percentage that cardiac output can increase above normal (300-600%) In certain conditions, the CO may be increased from 5L to 1315 L per minute and that is called a hypereffective heart. Hypereffective because the heart can pump blood a volume that is greater than what is normal. Hypereffective heart happens if there is sympathetic stimulation and parasympathetic inhibition, during moderate to heavy exercise or during athletic activities that will involve endurance (e.g. marathon races). The opposite is a hypoeffective heart –the heart pumps blood that is less than normal and that is brought about by cardiac diseases (e.g. congestive heart failure, rapid arrhythmia, cardiac valvular diseases). “Ask and it will be given to you; seek and you will find; knock and the door will be opened to you. For everyone who asks receives; he who seeks finds; and to him who knocks, the door will be opened.” -Matthew 7:7-8 GOD BLESS YOU ď 7 Shannen Kaye B. Apolinario, RMT| Circulatory or Vascular System (Gloria Marie M. Valerio, MD) The Circulatory System or Vascular System is made up of different types of blood vessels that are arranged either parallel or in series with one another forming a closed system of conduits or tubes that will transport blood to and from the heart. Take note that the blood vessels are not rigid tubes, they are distensible. The primary function of the circulatory system is to service the needs of the tissues that is - by transporting blood, it will transport essential substances like oxygen and nutrients to the tissues and at the same time it will transport the waste products of metabolism away from the tissues. As what we have learned from the previous lecture, the circulatory system is divided into two – pulmonary and systemic circulation. The pulmonary circulation receives unoxygenated or venous blood from the right heart and supplies blood to the lungs. On the other hand, the systemic circulation receives arterial or oxygenated blood from the left heart and supplies blood to almost all organs of the body except for the lungs. Since the systemic circulation will supply blood to almost all organs of the body, it is also called peripheral or greater circulation. Blood Vessels In the different organs of the body, the arteries will divide into smaller branches forming the arterioles. This time, the wall of the arterioles contains more smooth muscle fibers than elastic tissue. In fact, among all the different types of blood vessels, the arteriolar wall has the thickest muscular layer so that when the smooth muscle layer of the arteriolar wall contracts or if there is vasoconstriction, that will decrease tremendously blood flow to the capillaries and to the tissues. On the other hand, when the smooth muscle layer of the arteriolar wall relaxes or if there is vasodilatation, that will now increase tremendously blood flow to the capillaries and to the tissues. So one important function of the arterioles is to regulate blood flow to the capillaries and to the tissues and also because of its thick muscular layer, resistance to blood flow is highest in the arterioles so the arterioles are called resistance vessels. The smallest blood vessels are the capillaries. The capillary wall is thin and porous - it allows exchange of fluids and some solutes between intravascular and interstitial fluid compartments. The capillaries are known as exchange vessels. From the capillaries, blood will be collected by the venules which will then coalesce to form the bigger veins. Comparing the wall of the vein to that of an artery, the venous wall is thinner and more distensible that is why the veins can accommodate a large volume of blood with little increase in pressure and the volume of blood that is contained in the veins is what we call unstressed blood volume because of the low pressure area of the venous system. It means that the vascular capacity is bigger and veins are also called capacitance vessels. There are two functions of veins: one is to act as blood reservoir and another one is to return blood back to the heart. In the veins of the limbs or extremities, there are venous valves present with openings of which are directed towards the heart. So that when you move your limbs and the skeletal muscles contract that will open up the venous valves and facilitate venous return. Layers of the Blood Vessel 1. 2. 3. Tunica intima Tunica media Tunica adventitia PHOTO: Schematic diagram of the parallel and series arrangement of the vessels composing the circulatory system. The capillary beds are represented by thin lines connecting the arteries (on the right) with the veins (on the left). The crescent-shaped thickenings proximal to the capillary beds represent the arterioles (resistance vessels). On the right is the arterial system or distributing vessels. On the left is the venous system or collecting vessels. When the left ventricle contracts, blood is ejected to the aorta and from the aorta to the arteries. The wall of the aorta and arteries is strong and thick so it is able to transport oxygenated blood under high pressure to the different organs of the body and we call the blood volume that is contained in the arterial system as stressed blood volume. One important characteristic of the aortic as well as arterial wall is that it contains more elastic tissue than smooth muscle fibers. So that will make the aortic and arterial wall highly distensible so during ventricular systole, when blood is ejected to the aorta, the aortic wall will distend to accommodate the large volume of blood. On the other hand, during ventricular diastole, the aortic and arterial wall will recoil on the contained blood. 1 Shannen Kaye B. Apolinario, RMT| Except for the capillaries, the wall of the different blood vessels is made up of the same structure. There are three layers of the vascular wall. The innermost layer is the tunica intima which is made up of the endothelium and basement membrane. The middle layer is the tunica media which is made up of smooth muscle fibers. The outermost layer is the tunica adventitia which is made up of connective tissue. Just like in the heart, the presence of connective tissue in the vascular wall will prevent overstretching or over distension of the vascular wall when blood volume as well as blood pressure increases. Properties and Characteristic of the Vascular Smooth Muscle 6. 2 types of Smooth Muscle 1. 2. Multiunit Single unit PHOTO: Control systems of smooth muscle. Contraction (or inhibition of contraction) of smooth muscles can be initiated by (1) the intrinsic activity of pacemaker cells, (2) neutrally released transmitters, or (3) circulating or locally generated hormones or signalling molecules. The combination of a neurotransmitter, hormone, or drug with specific receptors activates contraction by increasing cell Ca++. The response of the cells depends on the concentration of the transmitters or hormones at the cell membrane and the nature of the receptors present. Hormone concentrations depend on diffusion distance, release, uptake, and catabolism. Consequently, cells lacking close neuromuscular contacts will have a limited response to neural activity unless they are electrically coupled so that depolarization is transmitted from cell to cell. A. Multiunit smooth muscles resemble striated muscles in that there is no electrical coupling and neural regulation is important. B. Single-unit smooth muscles are like cardiac muscle, and electrical activity is propagated throughout the tissue. Most smooth muscles probably lie between the two ends of the single unit-multiunit spectrum. structures which are called calveolae. However, this calveolae are actually analogous to the T-tubules. Few mitochondria. There are fewer mitochondria in the smooth muscle and the main source of energy for contraction is glycolysis. 7. Sarcoplasmic Reticulum. The sarcoplasmic reticulum is less welldeveloped so that means it is not able to store large quantities of calcium ions just like in the cardiac muscle cell so in order to contract, there has to be another source of calcium ions and that is the extracellular fluid (ECF). Also present on the membrane of the sarcoplasmic reticulum are ryanodine receptors that will bind with calcium coming from the ECF and there is also a calcium pump. 8. Contractile Proteins. Contractile proteins are also present that will include actin, myosin and tropomyosin but there is no troponin so in order to contract, calcium will bind with another protein and that is calmodulin so you have a calcium-calmodulin complex that will initiate vascular smooth muscle contraction. 9. Stimuli. Stimuli that will cause contraction of the vascular smooth muscle. Remember that in the skeletal muscle, the primary stimulus will be neural or nervous. You have an action potential for a somatic nerve transmitted to the skeletal muscle cell that will depolarize the skeletal muscle cell and that will now initiate the excitationcontraction coupling. In vascular smooth muscle, there are different types of stimuli that can stimulate the vascular smooth muscle: a. The neurotransmitter agent that is released by sympathetic nerves is norepinephrine. You also have norepinephrine and epinephrine from the adrenal medulla so that when either norepinephrine or epinephrine binds with alpha-1 receptors that will cause contraction of the vascular smooth muscle so there will be vasoconstriction. On the other hand, when either norepinephrine or epinephrine binds with beta-2 receptors, that will cause relaxation of the vascular smooth muscle so there will be vasodilatation. Remember in relation to beta-2 receptors, epinephrine has a greater effect than norepinephrine. There are two types of smooth muscles in the body: multi-unit smooth muscle and single unit smooth muscle. In the visceral wall as well as the vascular wall, the type of smooth muscle fibers present is mostly the single unit type. Characteristics of Smooth Muscle 1. Smaller. Compared to the skeletal muscle cell, the smooth muscle cell is smaller 2. Involuntary. The activity of the vascular smooth muscle is not regulated by the cerebral cortex. 3. 4. 5. Resting Membrane Potential. The RMP is less negative, it is also unstable. It ranges from -50 to -60 mv. The action potential generated is brought mainly by opening of slow calcium channels so that will make the duration of the vascular smooth muscle action potential longer than that in the skeletal muscle. So that the duration of the contraction-relaxation cycle in the vascular smooth muscle is also longer. Tonic contraction. Another important property of the vascular smooth muscle - it can remain partially contracted for a long time with little expenditure of energy and that is what we call tonic contraction. Sarcolemma. The vascular smooth muscle cell is also surrounded by the sarcolemma and present on the sarcolemma are voltagegated as well as ligand-gated calcium channels. Also present is a calcium pump, a sodium-potassium anti-porter, and a sodiumcalcium anti-porter. However, invaginations of the sarcolemma will not form the T-tubules; instead the invaginations will form cave-like 2 Shannen Kaye B. Apolinario, RMT| Neural. First is again neural so we have autonomic innervation and the vascular smooth muscle is innervated mainly by the sympathetic nervous system so you have sympathetic adrenergic and sympathetic cholinergic. Sympathetic adrenergic nerves innervate the blood vessels in the skin and viscera while sympathetic cholinergic nerves innervate the blood vessels in the skeletal muscle. In sympathetic cholinergic, you have acetylcholine binding with muscarinic receptors that will also relax the vascular smooth muscle in the skeletal muscle so there will be vasodilatation. b. Hormones. Aside from neural, the vascular smooth muscle can also be stimulated by circulating hormones which could either be vasoconstrictors or vasodilators. Among the circulating vasoconstrictors are angiotensin 2 and vasopressin or antidiuretic hormone (ADH). Among the circulating vasodilators are bradykinin and histamine. c. Stretch. Stretch of the muscle will initiate a reflex action. For example, when the blood volume and blood pressure increased, that will now stretch the arterial wall that will initiate a reflex action that will cause vasoconstriction. d. Local factors. Local factors for example actively metabolizing tissue so there will be oxygen consumption and production of carbon dioxide. So that oxygen tension (pO 2) will decrease and pO2 pCO2 carbon dioxide tension (pCO 2) will increase, these two factors will also cause vasodilatation. pH = H+ Other local factors that will cause vasodilatation will include a decrease in plasma pH so increase hydrogen, increase lactic acid concentration. Increase potassium, increase adenosine, all of these will produce vasodilatation. Latch-Bridge Mechanism Repolarization Ca++ ď out There are several factors that can either stimulate or inhibit the vascular smooth muscle. Myosin phosphatase Dephosphorylation of myosin ď relax Contraction-Relaxation Cycle M+A On the other hand, with repolarization, Ca++ will be removed either through the activity of the Ca++ pump on the sarcoplasmic reticulum, Ca++ pump on the sarcolemma or Ca++-Na+ antiporter. In the skeletal muscle as well as in the cardiac muscle, once Ca++ is unbound from troponin, it is expected to relax but in this case, even if Ca++ is removed from calmodulin, the vascular smooth muscle will remain contracted that is why it is capable of tonic contraction with little expenditure of energy. It will take some time before the muscle will relax by activation of another intracellular enzyme called myosin phosphatase. When activated, myosin phosphatase will cause dephosphorylation of myosin. When myosin is dephosphorylated, it will be unbound from actin and that will bring about relaxation and this is called the latch-bridge mechanism. Smooth Muscle Fiber PHOTO: Regulation of smooth muscle myosin interactions with actin by Ca++stimulated phosphorylation. In the relaxed state, cross-bridges are present as highenergy myosin-ADP-Pi complex in the presence of ATP. Attachment to actin depends on phosphorylation of the cross-bridge by a Ca++-calmodulin-dependent myosin-lightchain kinase (MLCK). Phosphorylated cross-bridges cycle until they are dephosphorylated by myosin phosphatase. Note that cross-bridge phosphorylation at a specific site on a myosin regulatory light chain requires ATP in addition to that used in each cyclic interaction with actin. Depolarization Ca + calmodulin Myosin light-chain kinase Phosphorylation of myosin Increased ATPase M+A contraction If the membrane is depolarized, that will allow Ca++ to enter the vascular smooth muscle cell. When the Ca++ enters, it will bind with calmodulin which will now initiate the contraction process. What happens is that the calcium-calmodulin complex will activate an intracellular enzyme that is myosin light chain kinase. When activated, myosin light chain kinase will cause phosphorylation of myosin which will then increase the activity of ATPase. With increased activity of ATPase, myosin will now form cross bridges with actin and that will bring about contraction. 3 Shannen Kaye B. Apolinario, RMT| PHOTO: Apparent organization of cell-to-cell contacts, cytoskeleton, and myofilaments in smooth muscle cells. Small contractile elements functionally equivalent to a sarcomere underlie the similarities in mechanisms between smooth and skeletal muscle. Linkages consisting of specialized junctions or interstitial fibrillar material functionally couple the contractile apparatus of adjacent cells. Smooth muscle is non-striated. There is no regular arrangement of the actin and myosin filaments so that when you observe the smooth muscle under the microscope, alternating thick and thin filaments and alternating light and dark bands will not be seen. The structure of a smooth muscle fiber is usually arranged in bundles. Another characteristic, there is no Z line, instead of the Z line, there are dense bodies attached to the membrane of the smooth muscle which will also provide an attachment between the membrane of the individual muscle fibers. So that force generated in one muscle fiber can be transmitted to other muscle fibers as well. Also, there are gap junctions present in the membrane allowing ions to flow freely from one muscle fiber to the next so that when an action potential is generated anywhere in a bundle, it can be transmitted readily and that will cause the whole bundle to depolarize and to contract as a single unit and that arrangement of the muscle fiber is called synctitium. That is why the type of the smooth muscle is singleunit smooth muscle. Attached to the dense bodies are the actin filaments and interspersed within the actin filaments are the myosin filaments. And the myosin filaments here form what we call side-polar crossbridges – myosin on one side is attached to actin and it is attached to actin on the other side. When activated, that means myosin can pull the actin filament on one side in one direction at the same time pulling the other actin filament on the other side in the opposite direction. capillaries which is slower because it is numerous and smaller and that is why the velocity is inversely related to the cross-sectional area. As to radius, the vena cava actually has a bigger radius than the aorta but the aorta has the thickest wall. Composition of the vascular wall you have elastin, smooth muscle, collagen. Elastin and collagen component is highest in the aorta but take note the smooth muscle component is most abundant in arterioles. The capillary wall has no elastin, no smooth muscle, and no collagen. Differentiation of the Blood Vessels Char. Aorta Arteriole Capillary Venules Vena cava Number in body 1 109 1010 3 x 108 2 4.5 300 5,000 4,000 18 12 0.010 0.004 0.02 17 Wall thickness (microns) 2 0.02 0.001 0.002 1.5 Elastin +++ + 0 + + Smooth muscle ++ +++ 0 + ++ Collagen +++ + 0 + + 110 70 20 10 5 50 0.3 0.017 0.02 4.6 Crosssectional area Radius (mm) Trasmural pressure (mmHg) Peak velocity (cm/s) As for transmural pressure, this is difference in the pressure between the inside and outside of a blood vessel and the transmural pressure is highest in the aorta, lowest in the vena cava. It is mentioned earlier that the arterial system is a high pressure area while the venous system is a low pressure area. PHOTO: Internal diameter, wall thickness, and relative amounts of the principal components of the vessel walls of the various blood vessels that compose the circulatory system. Cross sections of the vessels are not drawn to scale because of the huge range from the aorta and venae cavae to capillary. Let us now differentiate the blood vessels that make up the circulatory system so you have the aorta, arterioles, capillaries, venules and vena cava. Number in the body: there is only 1 aorta, 2 vena cava – superior and inferior, millions of arterioles, millions of venules, and billions of capillaries. As to cross-sectional area, you will notice that although the aorta is the biggest artery in the body, its cross-sectional area is small. Compare it to the smallest blood vessel in the body which is the capillary, it has the biggest cross-sectional area. What does cross-sectional area mean? If you put the blood vessels side by side, there is one aorta, two vena cava and billions of capillaries and if you spread all of those, which among those blood vessels would occupy the most space. When we say cross-sectional area, that is not the size of the blood vessel - you put the blood vessels side by side then spread it, which among the blood vessels will occupy the biggest space and of course that will be the most numerous even though it is the smallest and that will be the capillaries. Correlate it with the velocity of the blood flow. When we say velocity of blood flow, that is the distance travelled by a volume of blood per unit of time. As you can see, cross-sectional area is inversely related to velocity. The aorta which has a small cross-sectional area has the highest velocity of blood flow, in contrast, the capillaries with the biggest cross sectional area has the lowest velocity of blood flow. Why did that happen? You will learn later on that again because of the closed nature of the circulatory system, blood flow is equal to cardiac output equal to venous return so that means the blood flow in every blood vessel per unit of time is the same. So if blood flow is 5L/min, in a big blood vessel like the aorta, it can easily fill up 5 L. What about the capillaries? It is small and numerous, it is slower to fill up the 5L so although the volume is the same in both, the blood flow in the aorta is faster compared to the 4 Shannen Kaye B. Apolinario, RMT| PHOTO: Phasic pressure, velocity of flow, and cross-sectional area of the systemic circulation. The important features are the inverse relationship between velocity and cross-sectional area, the major pressure drop across the small arteries and arterioles, and the maximal cross-sectional area and minimal flow rate in the capillaries. AO, aorta; ART, arterioles; CAP, capillaries; LA, large arteries; LV, large veins; SA, small arteries; SV, small veins; VC, venae cavae; VEN, venules. This graph will show you again the relationship between crosssectional area and velocity of blood flow. So to summarize, cross-sectional area increases from the aorta to the capillaries, it decreases from the capillaries to the vena cava. For the velocity of blood flow, it is highest in the aorta so it decreases from the aorta to the capillaries; it increases from the capillaries to the vena cava. As to pressure, again, pressure is high in the arterial system, highest in the aorta and then it progressively decreases towards the vena cava but the biggest drop in pressure is in the arterioles. Velocity ď V=D T The formula for velocity is distance over time and the unit is centimetres per second. As said earlier, when we say velocity, that is the distance that is travelled by a volume of blood in a blood vessel. V=Q X Where: Q = blood flow X = area What is the difference between velocity and blood flow because the two are directly related? Velocity is equal to blood flow over cross-sectional area. The two are directly related so if the blood flow is increased, velocity is also increased. When you say velocity, again, that is the distance that a volume of blood will travel per unit of time in a blood vessel (unit: cm/s). But when you say blood flow that is the volume/quantity/amount of blood that will pass through a blood vessel per unit of time (unit: mL/unit of time). And again, the two are directly related. We already explained why velocity is inversely related to crosssectional area. Distribution of Blood Volume How much quantity of blood that can be stored in a given portion the circulation for each millimeter of mercury pressure rise. How come that the venous system can accommodate large volume of blood with little increase in pressure? When we say compliance or vascular capacity or capacitance, that is the measure of the degree of stretching or distensibility of an elastic structure. So a structure can be distensible because of the presence of elastic tissue and compliance is equal to change in volume over change in pressure or how much blood can be accommodated in a blood vessel for every mmHg increase in pressure. Vascular Distensibility Which of the two will have more elastic tissue, artery or vein? Arteries have more elastic tissue and the elastic tissue is responsible for the distensibility of a blood vessel. Which is more distensible, artery or vein? It is supposed to be the artery but the arteries are 8x less distensible than the veins. So how did that happen? The artery has more elastic tissue so we expect it to be more distensible than the vein but how come that it is 8x less distensible? The veins has higher vascular capacity, it can accommodate a large volume of blood compared to the artery. There are more elastic tissue in the arterial wall than in the venous wall but the venous wall is thinner. Meaning to say, if you have an artery and a vein of the same size, both can accommodate the same volume of blood but in order to stretch the arterial wall which is thick and strong, that volume of blood will exert a greater pressure or force. Compare it to the same volume of blood in the vein, whose wall is thin and also distensible so the same volume of blood will exert less force or pressure to distend the venous wall. So the venous wall being thinner that also has elastic tissue, it is more distensible, it can accommodate a large volume of blood with little increase in pressure. Arteries are 8x less distensible than the veins i.e. a given increase in pressure causes about 8x as much increase in blood in a vein as in on artery of comparable size. Veins = increase V little P Arteries = increase V higher P In the case of the veins, increase in volume but there is only little increase in pressure. In the arteries, same volume and increase in pressure. So the compliance is higher in veins. ď PHOTO: Distribution of blood (in percentage of total blood) in the different parts of the circulatory system. Percentage 39 % 25 % 8% 5% 2% 5% 7% 9% Parts of circulatory system Large veins Small veins and venules Large arteries Small arteries Arterioles Capillaries Heart Pulmonary circulation At any point in a cardiac cycle, about 65% of the blood is contained in the venous system, 13% in the arteries, 2% in the arterioles, 5% in the capillaries, 7% in the heart and 9% in the pulmonary circulation. Vascular Compliance or Capacitance Where: C=ΔV ΔP Δ V = change in volume Δ P = change in pressure 5 Shannen Kaye B. Apolinario, RMT| PHOTO: A to D, When the arteries are normally compliant, blood flows through the capillaries throughout the cardiac cycle. When the arteries are rigid, blood flows through the capillaries during systole, but flow ceases during diastole. At the top, is a normal artery or aorta. Below, you have a rigid aorta or artery. Still we are discussing compliance or stretchability of the arterial or aortic wall. A - During ventricular systole, blood will be ejected to the aorta so that the volume of blood in the aorta will increase and under normal conditions, the aortic wall will distend. At the same time, during ventricular systole, that volume of blood will be transported under high pressure to the arteries, to the arterioles, capillaries and therefore to the tissues. B - Now, during ventricular diastole (ventricles are not ejecting), the aortic wall being distensible, it can now recoil on the contained blood. And because of the recoil of the aortic wall, that will still push blood to the arteries, arterioles, capillaries and to the tissues so that means although the ejection of blood from the ventricles to the arterial system is pulsatile, the transport of blood to the tissues is continuous so there is still transport of blood to the tissues during diastole. C - What will happen if the arterial wall becomes rigid for example there is atherosclerosis which is common in the elderly. So that will make the arterial wall less distensible. During ventricular systole, blood will be ejected to the aorta, it can still be transported under high pressure to the arteries, arterioles, capillaries and to the tissues but as you can see here, it is not distended anymore. . . D - So that during ventricular diastole, because the walls are already rigid, it can no longer recoil. Nothing will push the blood towards the arteries, arterioles, capillaries and tissues so that means if the arterial wall becomes rigid i.e. atherosclerosis, that will already compromise blood supply to the tissues during ventricular diastole. Large artery Capillary In the case of the capillary, there is less tension on the wall so that means less pressure is needed to balance the tension on the wall so its transmural pressure is also less. That is why the capillary wall is not prone to rupture. Compare it to a large artery, its wall is strong, so the wall tension is high so that the pressure needed to balance the wall tension is also high so that will make the transmural pressure high also that is why a large blood vessel like an artery or aorta is more prone to rupture. Blood Flow ď Volume of blood that passes through a specific point in the circulatory system per minute ď Approximately equal to CO and VR Blood flow is the amount/quantity/volume of blood that will pass through a specific point in the circulatory minute per minute. It is equal to cardiac output and venous return so that means the average blood flow is 5,000 mL or 5L/min. Ohms Law Volume flow = Δ Pressure Resistance Laplace equation According to Ohms law, blood flow is equal to pressure gradient over resistance. A PHOTO: Diagram of a small blood vessel to illustrate the law of Laplace: T = Pr, where P = intraluminal pressure, r = radius of the vessel, and T = wall tension as the force per unit length tangenital to the vessel wall. wall tension acts to prevent rupture along a theoretical longitudinal slit in the vessel. T=Pr Where: T = tension on the wall P = transmural pressure (pressure inside blood vessel) r = radius of the vessel Laplace equation that is wall tension is equal to the product of distending pressure and radius of a blood vessel. Tension is tension on the wall and pressure is inside a blood vessel. So they are directly related. How come a small blood vessel like a capillary is less prone to rupture while in large vessel i.e. artery or aorta is more prone to rupture. B Let’s say this (above) is a blood vessel with point A and point B. So for blood to flow from point A to point B, there has to be difference in pressure between point A and point B. the greater the difference in pressure, the greater will be the blood flow so that if the pressure in point A is equal to that in point B, there will be no blood flow, it becomes stagnant. As for resistance, that is the impediment to blood flow and there are two types of resistance depending on the arrangement of the blood vessels. For example, there are blood vessels arranged in series or arranged in parallel with one another. Series: artery arteriole capillary venule vein TR = T resistance P P = distending pressure T = wall tension T 6 Shannen Kaye B. Apolinario, RMT| In in series arrangement, let’s say you have an artery connected to an arteriole, connected to a capillary and then you have a venule and finally a vein. If the arteriole will constrict, resistance to blood flow will increase and so will resistance in the capillaries, venules, and vein because no blood will flow. So that means that when the blood vessels are arranged in series, the total resistance is equal to the sum of all the resistances in individual blood vessels. Parallel: resistance TR < On the other hand, an artery will give rise to several arterioles arranged in parallel with one another. Each arteriole can function independently of the others so that if one arteriole will constrict, the resistance will increase only in this (arrow) arteriole so the total resistance this time will become less than the resistance in one blood vessel. One type of blood flow is laminar flow wherein blood flows at a constant rate. When we say laminar flow, the layer of blood that is in close contact with the vascular wall hardly moves. The next layer which is a little farther away from the vascular wall will flow at a low velocity. The next layer will move at a higher velocity. That means the highest velocity will be at the center and that will be the direction, that will be the rate along a blood vessel meaning to say, when the blood reaches the end of the blood vessel it cannot be that the one in contact with the blood vessel wall will have the highest velocity and the one at the center will have the lowest velocity. The direction is straight at a constant rate so that laminar flow is also called stream line and this type of blood flow is silent, it creates no sound. 2. Turbulent Flow The sum of all the resistances to blood flow in the systemic or peripheral circulation is what we call total peripheral resistance (TPR). Factors that will increase resistance to blood flow: Poiseuille’s Equation Resistance = Length x Viscosity x 8 Π r4 Factors that will increase resistance to blood flow are expressed in Poiseuille’s equation. So resistance is directly related to length of a blood vessel. The longer the blood vessel is, the higher the resistance to blood flow. It also related to blood viscosity. Remember that blood is 3-4x more viscous than water and there are two factors that make blood viscous: haematocrit/concentration of red blood cells and concentration of plasma proteins. In polycythemic patients, there is increase RBC production, increase RBC count, increase haematocrit that will make blood more viscous so resistance to blood flow is increased. On the other hand, the opposite is true to anaemic patients, decrease RBC count, decrease haematocrit that will make blood less viscous so that the rate of blood flow increases. When blood flows in different directions, it creates a sound and that is what we call a turbulent flow and the sound that is produced by turbulent flow is a bruit. In the heart, the abnormal sound is a murmur; in the blood vessel it is called a bruit. What are the conditions that will predispose to a turbulent type of blood flow? Another important factor related to resistance but this time inversely related is the radius of a blood vessel and not just the radius, radius to the 4th so that will make it a very important factor. Meaning to say, during vasoconstriction, if the lumen of a blood vessel will decrease twice its normal size, that means blood flow will decrease 4x. or if during vasodilatation, the lumen or the radius of a blood vessel will increase twice its normal size, that means blood flow will increase 4x normal. So the radius of the blood vessel is very important in regulating resistance to blood flow. 1. If the velocity of blood flow increases. 2. If the blood passes over a rough surface. Remember that endothelial lining of a blood vessel is smooth. But if there will an injury on the blood vessel wall or if there will be atherosclerotic plaques deposited on the blood vessel wall, that will make the endothelial lining rough and when blood passes over a rough surface, the direction of blood flow is disturbed. 3. If there is an obstruction. So along a blood vessel, blood flows laminar then suddenly there is a thrombus, that will again change the direction and the rate of blood flow will be disturbed 4. When the blood vessel makes a sharp angle, that will again predispose to a turbulent type of blood flow. Reynold’s Number 2 Types of Blood Flow 1. Re = Diameter x Velocity x Density Viscosity Laminar Flow The factors that will increase the tendency of blood flow to become turbulent are expressed in Reynold’s number. The factors that are directly related to the Reynold’s number are diameter of blood vessel, velocity of blood flow, and density of the fluid or medium whereas blood viscosity is inversely related to the Reynold’s number. When will turbulent flow occur? If the Reynold’s number is below 2,000, blood flow is laminar and there is very little turbulence but it will easily die out. Between 2,000 to 3000 is the transition from laminar to turbulent flow but above 3000, blood flow is definitely turbulent 0 1 Velocity 2 PHOTO: When flow is laminar, all elements of the fluid move in streamlines that are parallel to the axis of the tube; the fluid does not move in a radial or circumferential direction. The layer of fluid in contact with the wall is motionless; the fluid that moves along the central axis of the tube has the maximal velocity. 7 Shannen Kaye B. Apolinario, RMT| Venous Return ď ď Volume of blood that goes back to the heart per minute 5,000 mL/min Venous return is the amount/quantity/volume of blood that will return to the heart per minute. It is equal to cardiac output and equal to blood flow so it is 5,000 mL or 5L/min. long time, there will be pulling of blood on the lower extremities. Since the venous return cannot be facilitated because of the damaged venous valves, the accumulation of blood in the lower extremities will now cause stretching or distension on the wall of the veins and that will cause varicosities. Factors that Regulate Venous Return VR = MCSFP – CVP RV Where: MCSFP = Mean Circulatory Static Filling Pressure CVP = Central Venous Pressure RV = resistance in veins Venous return is equal to mean circulatory static filling pressure (MCSFP) – the measure of the degree of filling of the systemic or circulatory system. Meaning to say, when blood blow in the systemic circulation stops the pressure exerted by the volume of blood in the systemic circulation is what we call MCSFP – how much blood is present in the systemic circulation when blood flow stops. It is actually directly related to the total blood volume (TBV). Where: MCSFP = TBV VC TBV = total blood volume VC = vascular capacity So increase in the total blood volume will increase the MCSFP and therefore increase the venous return but it is inversely related to vascular capacity. Remember there is increase capacitance if the venous wall is in a relaxed state because the veins will accommodate a large volume of blood and that blood will not return to the heart so with sympathetic stimulation, you increase the tone of the venous wall that will now increase the veins vascular capacity and therefore increase venous return. So, sympathetic stimulation increase venous tone, decrease vascular capacity, and increase venous return. CVP is central venous pressure or more specifically pressure in the right atrium which is normally 0 mmHg. For venous return to increase, CVP should be lower than the pressure in the venous system. When will the right atrial pressure or CVP increase? There are factors: 1. Rate of venous return increases. When the rate of venous return increases above normal so that will easily fill up the right atrium so that is increased volume blood in the right atrium will increase the CVP. 2. Pumping capacity of heart. The other factor is the pumping ability of the heart. If the pumping ability of the heart is normal, the volume of blood in the right atrium will be ejected to the right ventricle and on to the pulmonary circulation. What if there is right-sided heart failure? So the pumping ability of the right heart is depressed so the blood in the right atrium will back up in the venous system and that will now increase the venous pressure so that one clinical manifestation of right-sided heart failure will be distension of the neck veins. 3. Resistance in veins. Next is resistance in the veins which is quite low because remember that the veins are low pressure area but resistance may increase if the intra- abdominal pressure increases because for example during pregnancy or if there is tumor in the abdominal cavity or if there is ascites (accumulation of fluid in the abdominal cavity), that will now compress the veins so the resistance in the veins will increase and that will decrease venous return. 4. 5. Venous pump. Other factors that may influence venous return will be the venous pump or activity of the venous valves. We all know that when you move your limbs, the venous valves will open and that will facilitate venous return. What will happen when the venous valves are damaged? When you stand for a 8 Shannen Kaye B. Apolinario, RMT| Negative intra-thoracic pressure. A negative intra-thoracic pressure that will allow the veins and the heart to dilate so that will facilitate venous return and allow more blood to be accommodated in the heart. Arterial Blood Pressure ď Force exerted by the volume of blood on the arterial wall When you get your BP: 120/80, what does that mean? What do you mean by arterial blood pressure? That is the force exerted by the volume of blood on the arterial wall. It is expressed as systolic pressure over diastolic pressure. Blood Pressure: Systolic Pressure (SP) = is the highest pressure in the aorta at systole Systolic pressure is the highest pressure recorded in the aorta during ventricular systole. Why will the pressure in the aorta increase during ventricular systole? Because when blood is ejected into the aorta, the volume of blood in the aorta will increase and that will exert pressure on the aortic wall to distend the aortic wall. in the elderly, systolic pressure is usually high (higher than normal – 130, 140 and the average is 120 mmHg) because of atherosclerosis that will cause hardening of the aortic wall so the volume of blood ejected by the left ventricle will have to exert a greater force to stretch the already rigid aortic wall. Diastolic Pressure (DP) = is the lowest pressure in the aorta at diastole Diastolic pressure is the lowest pressure recorded in the aorta during ventricular diastole. Why will pressure in the aorta decease during ventricular diastole? Because there is no more ejection of blood from the ventricles and the volume of blood that is present in the aorta will drop off to the arteries, arterioles, capillaries and tissues and the aortic wall will recoil. PHOTO: Arterial systolic, diastolic, pulse, and mean pressure. Mean arterial pressure (Pa) represents the area under the arterial pressure curve. Pulse Pressure = SP – DP Where: SP = systolic pressure DP = diastolic pressure The difference between the systolic pressure and diastolic pressure is the pulse pressure. Again, in the elderly with atherosclerosis, what will happen to the pulse pressure? It will increase because the systolic pressure, the diastolic pressure will not change so that will now increase the pulse pressure. recoils, the volume of blood is still high and that will increase the diastolic pressure. What about during moderate to heavy exercise? The sympathetic nervous system is stimulated so that will increase the heart rate, increase the stroke volume, and increase the cardiac output. When the cardiac output increases, the systolic pressure increases. What happens to the diastolic pressure? During exercise, with increased metabolism, there is increase heat production. Increase heat production will cause vasodilatation decreasing the total peripheral resistance (TPR). With a decrease in TPR, diastolic pressure decreases so that will widen the pulse pressure. To summarize, here are the factors that affect the arterial blood pressure: The pulse pressure can actually be influenced by two factors: one is stroke volume – greater stroke volume, increase systolic pressure, no change in diastolic pressure so that will increase the pulse pressure. The other factor is compliance of the arteries. So again, when the arterial wall becomes rigid, its compliance will decrease and that will again increase the systolic pressure, no change in diastolic pressure so that will widen the pulse pressure. Another condition is in hyperthyroidism. Thyroid hormones can directly stimulate the SA node and the myocardial cell so increase heart rate, increase stroke volume, increase cardiac output, increase systolic pressure. But at the same time, thyroid hormones can increase intracellular metabolism. Again, that will increase heat production, vasodilatation, decrease TPR, decrease diastolic pressure. So in hyperthyroidism, you have an increase systolic pressure, decrease diastolic pressure that will widen or increase the pulse pressure. So hyperthyroid patients are prone to what we call high cardiac output failure. Factors that Affect ABP 1. Blood volume. How come we always say that if there is hypervolemia, there is hypertension or if there is hypovolemia, there is hypotension? If blood volume increases, that will increase initially the MCSFP. When increased, MCSFP will increase venous return. The effect of an increased venous return on the heart increases the following parameters: end diastolic volume that will stretch the ventricular wall, increase force of contraction, increase stroke volume, increase cardiac output, and increase blood pressure. 2. Compliance of arteries. When the compliance of the arteries decreases, it increases mainly systolic pressure. 3. Cardiac output. Increase in cardiac output will increase mainly systolic pressure. 4. Total peripheral resistance. Vasoconstriction that will increase TPR will increase mainly diastolic pressure. Mean Arterial Pressure (MAP) MAP = DP + 1/3 (SP-DP) Where: MAP = mean arterial pressure DP = diastolic pressure SP-DP = pulse pressure The average pressure in the circulatory system in one cardiac system is the mean arterial pressure (MAP). Remember that this is not the average of systolic and diastolic pressure. This is the average pressure in the circulatory in one cardiac cycle. And it is equal to the diastolic pressure plus one third of the pulse pressure. Why diastolic pressure? Because 60% of the cardiac cycle is diastole, only 40% is systole. ABP = CO x TPR Where: ABP = arterial blood pressure CO = cardiac output TPR = total peripheral resistance The formula for arterial blood pressure (ABP) is cardiac output (CO) times total peripheral resistance. If for example TPR is normal, CO increases, which will be affected more, will it be the systolic pressure or diastolic pressure? Systolic pressure because if the stroke volume increases, increase CO, increase volume of blood in the aorta that will exert a greater force on the aortic wall. Now, if the TPR increases, which will be affected more? It is diastolic pressure but why? What causes an increase in TPR? Vasoconstriction. Remember that during diastole, supposed to be there is peripheral run off blood to decrease the volume of blood in the aorta and the aortic wall will recoil. What if there is vasoconstriction? Increase TPR, blood cannot runoff to the capillaries, to the tissues etc. so there will be pulling of blood in the arterial system so that when the arterial wall “Trust in the Lord with all your heart and lean not on your own understanding; in all your ways acknowledge him, and he will make your paths straight.” -Proverbs 3:5-6 GOD BLESS YOU ď 9 Shannen Kaye B. Apolinario, RMT| ELECTROCARDIOGRAPHY Dr. Barbon and Dra. Cundangan ď¨ Procedure to detect and obtain electrical activities coming from the heart. ď¨ Berne and Levy: enables physicians to infer the course of the cardiac impulse by recording the variations in electrical potential at various loci on the surface of the body. o Located at the junction of Superior Vena Cava with the right atrium ⪠⪠o Why is it considered as the pacemaker of the heart? ⪠Because it discharges the fastest among all other origins of electrical activities of the heart ⪠SA node normally discharges most rapidly, with depolarization spreading from it to the other regions before they discharge spontaneously. ⪠Its rate of discharge determines the rate at which the heart beats ⪠CARDIAC CONDUCTION SYSTEM SA node ď Internodal Trunk/ Internodal pathways ď AV node ď Bundle of His ď Right and Left bundle branches ď Apex ď Purkinje fibers (all parts of ventricular myocardium) ď Base ď ď ď o ď Internodal Atrial Pathways o From the SA node, the impulse will travel to the AV node via the internodal trunk. They are almost sumltaneous in activation o Anterior internodal tract of Bachmann – distribute the impulse going to the left atrium o Middle internodal tract of Wenkebach – utilized as a bridge from the SA node to the AV node; activate the middle, interatrial septum o Posterior internodal tract of Thorel – distribute impulse to the right atrium. All right are activated by the posterior tract ď Atrioventricular node o Located in the right posterior portion of the interatrial septum o Next to discharge the fastest o The only that impulses can be transmitted from atrium to ventricle is through the AV node o Atrionodal zone ď Nodal zone ď Nodal His zone ⪠Smallest fibers are at the Nodal zone o Common site of AV block o AV nodal delay ⪠Fewer gap junction ⪠Smaller fibers so the discharge is slower and there is greater resistance to impulse flow ⪠Fewer striations Atrial Muscle: 1st to depolarize is the 1st to repolarize Ventricular muscle: 1st to depolarize is the last to repolarize Sinoatrial node o Conduction in the heart originates from the SA node known as the pacemaker. P cells - actual pacemaker cells in the SA node and, to a lesser extent, in the AV node which are small round cells with few organelles and connected by gap junctions Indistinct boundaries Purpose: atrium will contract first before the ventricle; for effective ventricular filling Decremental conduction ď¨ While atrium and ventricles are in relaxed state, you have continuous ventricular filling. While it is relaxed (atrium and ventricle), you fill the ventricle up to 70% of its volume. ď¨ For it to reach the maximum filling, the atrial muscle must contract. Once it reaches the maximum filling, the impulses from the AV node will now proceed towards the ventricles. ď¨ The first to activate is the Bundle of His ď bundle branches. The part of the ventricle first to be activated—Interventricular septum (depolarizing current). ď¨ What part of the ventricle was last activated? o Purkinje fibers will go back towards the base. And the last parts of the ventricle activated on depolarize the base. When the heart contracts and the atrial muscle contracts it will contract downward because the activity will starts upward. ď¨ When the ventricle contracts, it is initiated in upward direction. The first to activate is the septum and it will contract into smaller size ď apex ď base. o Purpose: all contains blood (pulmonary artery and aorta)—located in the basal region. o Atrium will give blood to the ventricles, while the ventricles will give blood to the systemic and pulmonary circulation. o The opening is located at the base - mechanical activity. But before mechanical activities happen, electrical activities must come first. Impulse transmission and direction: ď Right atrium (where SA node is located) ď AV node o Direction: to the left o First to depolarize in the atrial wall: endocardium to epicardium ď Interventricular septum o 1st part of the ventricle that is activated o Aka: Ventricular septal activation o Left bundle branch to right bundle branch o Direction: to the right o ď ď Depolarization of the ventricular muscle starts at the left side of the interventricular septum and moves first to the right across the mid portion of the septum. The wave of depolarization then spreads down the septum to the apex of the heart. Apex o Direction: to the left Movement of depolarizing current: Endocardium to Epicardium ď In the ventricle: o Depolarization: endocardium to epicardium o Repolarization: epicardium to endocardium ď Posterobasal activity o From right ventricle ď base o The last parts of the heart to be depolarized are the: ⪠Posterobasal portion of the left ventricle ⪠Pulmonary conus o Direction: to the right Cardiac Vector – average direction of current flow or flow of impulses; allow synchronized activity of the heart o Normal Direction R ď L going down o ECG axis follow cardiac vector ECG MACHINE - - - To record electrical activity of the heart Connected by electrical cable to the patient or target body Electrodes: capable of gathering electrical impulses from the patient’s body; placed in specific body parts (RA, LA, LL) Electrical conduction will be determined and seen in the monitor or tracing in the ECG paper Use body fluids which functions as volume/fluid conductors Extracellular electrical activities: conducted by the body fluids (INTERSTITIAL FLUIDS) towards the skin and the electrodes are attached to the skin to gather electrical impulses Body fluids are good conductors (body is a volume conductor), fluctuations in potential that represent the algebraic sum of the action potentials of myocardial fibers can be recorded extracellularly. ECG machine: responsible on which lead is to be recorded. Leads will depend on what electrodes are being activated. The one activating this is the ECG. Electrodes exhibit a color coded form. It is in standard form: o RA - Red o LA - Yellow o RL – Black (ground electrode) ď§ Because heart is not the only one that makes the action potential, it can be smooth muscle, skeletal muscle. You must remove the said other action potential that are not coming from the heart, for the tracing to be clean. o LL – Green Electrodes must be placed in the correct body part for you to have a correct ECG tracing o Electrodes must also be placed at the same level on both sides of the body (mirror image) so that impulses will travel the same length towards the electrodes ďď Resting ECG o Most common procedure done; usual position o patient is lying down o cables are commonly on the chest and not in the extremities o remove all metals that will interfere with the transmission of impulses o Actual: there is electrode also in the RL (ground) ⪠Purpose: to remove other electrical activities not originating from the heart or non-cardiac ⪠Other tissues that can also generate electrical activities: Skeletal muscle (Diaphragm); Smooth muscle (GIT, ureter); Neurons ďď Stress/Exercise ECG/Treadmill test o Electrodes are directly connected to the machine. Complete electrodes o Detects the heart’s electrical activity; At least 3 chest electrodes are used o the patient is exercising in treadmill or stationary bicycle and ECG is attached to the patient o with modified attachment because it cannot be attached to the hands and feet while running ⪠No more chest electrodes because the extremity electrodes are placed on the chest o to determine any presence of abnormality that is not detected in normal ECG (example, in patients complaining with chest pain but normal in resting ECG) ⪠Some cardiac problems are only manifested if you allow the patient to have extra activity like running ⪠But there are still times when even if you conduct stress ECG, you still cannot detect the cardiac problem ďď Holter Monitoring o There is a portable ECG attached to the patient’s body for 24-48 hours continuously o aka Event recording o Indicated for patients who always complain of palpitation but are not seen in normal ECG tracing o Not necessarily that the patient will not move; The patient can still do normal daily routine and they will be provided with a diary (to write the start of ECG recording and write if ever the patient will experience palpitation, the time must be recorded in the diary) o Example, to correlate the presence of arrhythmia recorded in the ECG which is simultaneous with the palpitations or abnormalities experienced by the patient ďď Continuous Loop recording o Applied much longer; for 4 months BASIC LEADS USED IN ECG ď ď Common recording of ECG: 12 ECG leads o Bipolar limb leads: 1, 2, 3 o Unipolar limb leads: aVR, aVL, aVF o Unipolar chest leads: V1-V6 Bipolar/Extremity limb leads o “Bipolar”: there are 2 active electrodes. 1 electrode connected to the negative terminal of the machine and the other to the positive terminal of the machine In bipolar limb leads, it has negative and positive sign: o RIGHT SIDE - always negative o LEFT SIDE - always positive, except in bipolar in lead III (left arm-negative) , but in lead I (left arm-positive) o o o o ď Lead 1: RA (-) to LA (+) ⪠determines the condition of the basal region of the heart Lead 2: RA (-) to LL (+) ⪠determines the condition of the right side of the heart ⪠the highest wave because it follows the wave of cardiac vector; equals the value of Lead I and Lead III Lead 3: LA (-) to LL (+) ⪠determines the condition of the left side of the heart gives a 3-D picture of the heart Unipolar limb leads o Unipolar extremity leads or Augmented o Only 1 active electrode which is attached to the positive terminal of the machine o aVR – augmented vector to the right arm ⪠from the axis to the RA ⪠shows what is happening in the right uppermost part of the heart (right atrium) ⪠mostly the limb lead that is always presenting mostly negative deflected waves o aVL – augmented vector to the left arm ď§ shows the left uppermost part of the heart (left atrium and basal portion of left ventricle) o o o o o aVF – augmented vector to the left foot ⪠shows what is happening in the apex together with bipolar limb leads produce 6-D picture of the heart (HEXAGONAL REFERENCE SYSTEM) when 2 lead are combined, the result is neutral Limitation of Extremity Leads: it is only looking at the anterior portion of the heart (Ventral plane) o o o o ď¨ Ex. If the patient has inferior wall problem or apical problem, it can be seen in the L1, L3 and aVF Chest leads: horizontal or transverse plane; determines happening laterally and posteriorly Extremity Leads: anterior part of the heart (front only) Limitation: those happening in the frontal plane ď¨ HEXAGONAL REFERENCE SYSTEM (Frontal plane – Vertical) o o o ď¨ ď¨ ď¨ ď¨ ď¨ ď¨ ď¨ ď¨ ď¨ ď V1: 4th ICS; Right Sternal Margin ⪠right anterior side of the heart; Red V2: 4th ICS Left Sternal Margin ⪠right anterior side of the heart; Yellow V3: midway between V2 and V4 ⪠left anterior wall; Green V4: 5th ICS, Left midclavicular line (apex of the heart) ⪠left anterior wall; Brown V5: 5th ICS, Left anterior axillary line ⪠left lateral wall; Black V6: 5th ICS (same horizontal level as V5); Left Mid axillary line ⪠posterolateral wall; Violet V7: 5th ICS, posterior axillary line V8: 5th ICS (same horizontal level as V5); Left midscapular line V1 and V2 – right anterior portion of the heart V3 and V4 – left anterior portion of the heart V2 and V3 – middle portion of the heart V5 and V6 – lateral portion of the heart V7 and V8: for monitoring the posterior aspect of the heart; posterior wall of the heart To detect posterior heart problems aka Esophageal electrode Not commonly used because problems of the heart in the most posterior portion is one in a million You will allow the patient to swallow the electrode which is connected to the wire (Flag ceremony ď) Unipolar chest leads/ Pre- cordial leads ď¨ If the problem is still not detected by ECG, use other modalities like CT Scan, MRI, and specific determination of cardiac enzymes ď ď There is no Q wave in V1 and V2, and the initial portion of the QRS complex is a small upward deflection o Ventricular depolarization: mid portion of the septum from left to right toward the active electrode ď down the septum ď into the left ventricle away from the electrode ď moves back along the ventricular wall toward the electrode, producing the return to the isoelectric line. o Large S wave In left ventricular leads (V4–V6) o initial small Q wave (left to right septal depolarization) o large R wave (septal and left ventricular depolarization) o moderate S wave (late depolarization of the ventricular walls moving back toward the AV junction). ď¨ RA is always negative except for aVR o When there is activity, it will depolarize and the inside will become positive o When the heart has an electrical activity, there will be an initial change extracellular (becomes negative) in the right uppermost portion where the SA node is located ď¨ LL is always positive o Because the ECG is recording the happenings on the outside of the heart (EXTRACELLULAR) o Electrical activity of the heart: ⪠Any excitable cell that is resting is negative inside and positive outside ď¨ LA is positive in Lead 1 and aVL but it is negative in Lead 3 ď ď ď ď Hexagonal system for determining the frontal plane of the heart Using the bipolar limb lead Formula: L2 = L1 + L3 o The potential in Lead 2 is the sum of the potential of Lead 1 and Lead 3 o Margin of error: +/- 2 Lead 2 has the highest amplitude or voltage o Because Lead 2 is towards the left and most of the impulses of the heart are directed toward the left; it follows the cardiac vector RELATIONSHIP OF CHEST LEADS TO R and L Ventricles ď ď aVR o Atrial depolarization, ventricular depolarization, and ventricular repolarization move away from the active electrode o P wave, QRS complex, and T wave = all negative (downward) deflections aVL and aVF o deflections are predominantly positive or biphasic. greater works compare to the right ventricle. ď¨ Left ventricle is the one working for the whole systemic circulation while the right ventricle works on the pulmonary circulation. Review: Action potential in ventricular muscle EINTHOVEN’S TRIANGLE ď ď ď¨ Common problem of the heart: left side; because left ventricle has ď¨ Chest lead- horizontal plane of the heart ď¨ Limb and augmented limbs – vertical plane of the heart or frontal plane ď Phase 0 o rapid depolarization o The initial depolarization is due to Na+ influx through rapidly opening Na+ channels ď Phase 1 o initial rapid repolarization o The inactivation of Na+ channels ď Phase 2 o plateau o Ca2+ influx through more slowly opening Ca2+ channels ď Phase 3 o slow repolarization process o net K+ efflux through multiple types of K+ channels. ď Phase 4 o return to the resting membrane potential ď ď Why is it different from the action potential seen of ECG paper? Because the ECG machine detects electrical activities outside the tissues and uses interstitial fluid while the action potential shown above detects activities inside the cardiac tissues Normal: move from right going down to the apex (Cardiac vector) ď If the depolarizing current in the ECG (Cardiac vector) follows the ECG axis = (+) o Atrial depo: P wave o R wave: endo to epi; towards the ECG axis ď If the depolarizing current moves in the opposite direction to the ECG axis = (-) ď ď ď o Ventricular septum: Q wave In repolarizing current, if the vector of the repolarization is following the axis = (-) In repolarizing current, if the vector of the repolarization is moving opposite to the axis = (+) o T wave: in the ventricle; moving opposite to the axis Normal recording of atrial repo (though it is not normally recorded) = (-) o Atrial T wave = 2nd degree AV block ⪠Activity starts at the right side goes towards the left going down For depolarization current: ď Upward deflection (+) – flow of the electrical current is going to the positive side ď ď Downward deflection (-) : away from the positive side Isoelectric line o horizontal straight line o reference line to determine which are positive and which are negative o Anything above is positive while anything below is negative o Normally (+) waves or Depolarizing waves: P, R, and T waves o Normally (-) waves or Repolarizing waves: Q and S ď P wave o atrial depolarization QRS complex / Depolarization wave o corresponds Phase 0 o ventricular depolarization o to know if there is problem in the conducting fibers in the ventricle (Bundle of His and Purkinje fibers) o if the duration is longer than normal = Bundle branch block ECG WAVE Depolarization moving toward an active electrode in a volume conductor produces a positive deflection, whereas depolarization moving in the opposite direction produces a negative deflection. U wave - secondary to a much slower repolarization of papillary muscle o Papillary muscle – to prevent backflow from ventricle to atrium; to prevent eversion of the AV valve o If prominent, it is called SIGNIFICANT U WAVE ⪠if it is as tall or half the height of T wave ⪠indicates hypokalemia ď For repolarization current – occur in opposite direction; the first to depolarize will be the last to repolarize ď The machine will detect higher/greater electrical activity which is ventricular depo that is overshadowing atrial repo o The atrial repolarizing wave is buried in the QRS In analyzing ECG, we have to determine the normally positive waves and the normally negative waves ď ďď Standard speed of the movement of ECG paper = 25 mm/sec ď Upright/ Vertical line: amplitude / voltage (strength of electrical activity; gaano kalakas yung kuryente ng puso) ď Horizontal line: time which determine the duration of intervals (gaano katagal yung electrical activity ng puso) ď ď o ECG PAPER Downward: Atrial T wave; going to positive ď There is no wave for atrial depo because it occurs simultaneous with ventricular depo. Since atrial muscle is thinner than the ventricular muscle, ventricular depo mask the atrial repo ď ď Q wave o o o o o ď septal depolarization; seldom to be seen Normally negative Lead II When impulses reaches bundle of his and transmitted to the interventricular septum the impulses will move L to R (opposite cardiac vector so Q wave is negative) Represents depo of interventricular septum Parameters used in determining when atrial repo and ventricular depo starts includes the following: o PR segment o PR interval ď R wave o o o o apical depolarization + wave Wave representing what is happening in the apex Apex( impulses is R-L going down moving towards positive electrode—follow axis/ current flow ďď S wave o Postero - basal depolarization o Normally negative o Represent the part of the ventricle depolarized last (base) ďď T wave/ Repolarization Wave o part of ventricular repolarization; phase 3 o If repo follows ECG axis/ cardiac vector → negative deflection o It repo does not follow cardiac vector → positive deflection o Total duration of repolarization ⪠start from end of S to end of T o Duration of T wave ⪠does not give the total duration of ventricular repo o In obtaining the total duration of ventricular repo ⪠Measured from the end of S to the end of T o T interval → end of S to beginning of T HEART RATE ST segment o initial repo; corresponds Phase 1 and 2 o From the end of QRS to the beginning of T wave o At isoelectric line, while cell is repolarizing; since the machine only records electrical changes in phase II there is no electrical change(efflux of K is balance by the influx of Ca), so it is recorded at the isoelectric line but that cell is said to be repolarizing ďď PR segment o From the end of P wave to the beginning of QRS wave o Represents AV nodal delay ďď PR interval o P wave + PR segment o Atrial depo + AV nodal delay o To tell if there is AV block; conduction delay o beginning of P to beginning of Q ďď QRS interval o beginning of Q to end of S ďď QT interval o From the beginning of Q to the end of T o Action potential o To know if the patient experience tachycardia (shorter duration of action potential) or bradycardia (longer duration of action potential) ďď ST interval o end of QRS to end of T o measures the whole period of latent repolarization o to know the total duration of ventricular repo ď NORMAL INTERNAL VALUES ď J point o Reference point for ST elevation and ST depression o It is the time at which all ventricular muscle has been repolarized o To know if there is ischemia or myocardial infarction R-R interval (duration) – measure the big squares ď ď ď 60 / (5*0.2) = 60 bpm The equation is only used for regular rhythm of the heart; not for irregular rhythm because there is variable R-R interval ď Hash marks o duration is 3 sec then multiply to 20 o Count the number of R waves in a given duration to get the heart rate for irregular heart rhythm o Small vertical lines on top of the ECG paper ďď If you have hard time dealing with decimal numbers: ď o 300 / number of big squares o 1500 / number of small squares VECTORCARDIOGRAPHY ď ď ď Mean cardiac vector: average direction of the cardiac electrical activity (san papunta yung takbo ng activity sa puso) In vector analysis, aside from the direction, what other parameters should be considered? o Magnitude/strength of electrical activity (gaano kalakas yung kuryente ng puso) – measured by the length of the vector Because the standard limb leads are records of the potential differences between two points, the deflection in each lead at any instant indicates the magnitude and direction in the axis of the lead of the electromotive force generated in the heart (cardiac vector or axis). Cardiac vector calculation o R = (+) o S = (-) o Get the sum of R and S but by getting the total, you are actually subtracting the values because they have opposite signs ďď Draw horizontal line and arrow where it intersects and measure the angle = Axis of the heart o Line parallel to Lead 1 passing to the center of the triangle = 0 angle o Then draw a line going to the common intersection of the Leads o Get the angle between the two lines = Cardiac vector To get the magnitude: ďď Get the length of the arrow multiply to 0.1 mV Alternative: ď ď ď ď ď ď ď ď ď ď ď ď¨ not used for diagnostic purposes ď¨ used for annual check-up in companies; for screening purposes only Determination of the Axis of the Heart o Get the number of mm for upward (+) and downward (-) deflection o Plot in triangle (must be equilateral and equiangular = 60 degrees) o Get the center of the triangle. Midpoint of the sides are marked as 0 o Draw perpendicular line in reference to the plotted leads ďď Point of intersection = Vector = Mean QRS axis o To know if you have the correct analysis, Lead 2 must be plotted in the intersection of Lead 1 and Lead 3 Normal values of axis ď Asians: 0 to 90 degrees o Vertical position ⪠Payat na matatangkad ď; puso na parang parol o Horizontal position ⪠For obese and pregnant people o Intermediate position ⪠Anatomical position of the heart ď Americans: -30 to +110 degrees (due to bigger thoracic cage that allows their heart to move in a bigger area) ď Common cardiac vector: 59 degrees ď ď o R and S wave = ventricular vector; commonly used o T wave = atrial vector Mean cardiac vector indicates average or mean direction of flow in the heart Length will determine the thickness and activity in the muscle o If it hypertrophy, greater voltage is generated ⪠⪠⪠o peak energy; peak/prominent T wave because during repolarization, K will enter the cell. If there is increased amount of K then more K will go into the cell. At higher K+ levels, paralysis of the atria and prolongation of the QRS complexes occur. Ventricular arrhythmias may develop. The resting membrane potential of the muscle fibers decreases as the extracellular K+ concentration increases. The fibers eventually become unexcitable, and the heart stops in diastole. ⪠Hypokalemia ⪠prolonged of the PR interval, prominent U waves, and late T wave inversion in the precardial leads o 2nd degree (Incomplete) ď§ď progressive lengthening of the PR interval and absence of QRS (2:1 ratio of P wave : QRS wave) ď ⪠⪠not all atrial impulses are conducted to the ventricles Dropped beat: there will be an atrial P wave but no QRS-T wave Abnormalities Determined in ECG ď¨ Cardiac problems diagnosed using the ECG are cardiac problems wherein there is alteration in deterioration and conduction of impulses. ď Arrhythmia o Bradycardia < 60 o Tachycardia > 60 o Junctional rhythm like AV node rhythm ď Abnormal pacemakers – other potential pacemakers will discharge impulses ď Myocardial ischemia – ST depression; lack of blood flow; Ventricular strain ď Myocardial Infarction – ST elevation; T wave inversion ď Cardiac enlargement – Since it is larger and thicker, it has a tendency to produce greater contraction and voltage. o Higher R wave o Deep S wave o Longer duration of QRS > 0.10 sec o Right ventricular hypertrophy ⪠Tall R waves in V1; deep S waves in V6 o Left ventricular hypertrophy ⪠Tall R waves in V6; deep S waves in V1 ďď Electrolyte/Ionic imbalance o Hyperkalemia ď o ď Hypocalcemia ⪠prolonged ST segment and QT interval; phase 2 involves Ca conductance ⪠bradycardia AV block – block at AV node o 1st degree ⪠prolonged PR interval > 0.2 sec ⪠P-QRS interval normal ⪠P waves ď¨ there are repeated sequences of beats in which the PR interval lengthens progressively until a ventricular beat is dropped (Wenckebach phenomenon) o 3rd degree (Complete heart block) ⪠no impulse travels from the SA node ď ď AV node ď ď ventricles; complete dissociation ⪠May sariling mundo na yung ventricle caused by the activity of Purkinje fibers. Hindi na nya hinihintay si atrium. ⪠Ventricles beat at a low rate (IDIOVENTRICULAR RHYTHM) independently of the atria ď ď Bundle branch block – prolonged QRS > 0.10 sec o Longer transmission in the ventricular muscle o Left bundle branch is blocked so Right bundle branch will be activated first o Since left bundle branch is also a potential pacemaker, it will produce its own depolarization which will overlap with the previous depolarization that reached the right bundle branch. o 2 R waves (one to the right and one to the left) o Due to heart enlargement (Cardiomegaly) which requires longer time to transmit impulses in the ventricles which are bigger than normal ď Cardiac Enlargement o Very tall R waves o Very deep S waves o QRS interval > 0.10s ď Right ventricular hypertrophy o Tall R waves in V1; deep S waves in V6 Left ventricular hypertrophy o Tall R waves in V6; deep S waves in V1 ď ď Are all cardiac disorders diagnosed using the ECG? NO o Useful in cardiac disorders wherein there is disturbance in impulse generation and conduction ECG o o ď ď ď ď ECG can only detect electrical activity of the heart. It cannot identify structural abnormalities so, use other modalities like echocardiography. o 2D-echo ď ď ultrasound of the heart; problems in blood flow Cardiac problems that are not associated with the alteration, generation, or transmission of cardiac impulses are not detected in ECG. Not diagnosed by ECG: o Valvular disorders/defect o Stenosis o Septal defects - Congenital heart disease; ASD, VSD o Coronary heart disease – ECG can suggest but it cannot quantify how much is the obstruction in the coronary artery o Cardiac chamber disorders o Cardiomyopathies – weakening of heart muscle o Cardiac masses o Pericardial disorder Not only diagnose cardiac problems but also electrolyte problems → electrolyte problems affect cardiac activity Diagnose cardiac problem with alternation in electrolyte activities Echocardiography o Can diagnose cardiac problems not associated with alternation of electrical activity Cardiac masses o Abnormal growth in the cardiac tissue Pericardial disorders o Even injuries affecting pericardial sac o Initially not diagnose in ECG → they are not causing changes in the electrical activity of the heart o Problems in this conditions →BLOOD FLOW (diagnose using echocardiography Originally by (Combined): CKRP, Dela Rosa, Mauro, AJRU Updated by: CDMD, RMT ď Electrocardiography R wave Apex Depolarization Electrocardiography -­â Procedure used to record electrical activity of the human heart QRS Complex Ventricular Depolarization AJRU ST Segment Plateau S wave Posterobasal Depolarization PR Interval Atrial Depolarization + AV Nodal Delay T wave Ventricular Repolarization P wave Atrial Depolarization PR Segment AV Nodal Delay Q wave Interventricular Septum Depolarization -­â Fewer gap junctions -­â Smaller diameter fibers QT Interval Ventricular Depolarization + Ventricular Repolarization U wave Slow repolarization of the papillary muscles. If the height of the T wave is equal to the height of the U wave, it may indicate Hypokalemia in the patient. Impulse Conduction Rule #1: Depolarization following direction of impulses Rule #2: Depolarization away from direction of impulses Rule #3: Repolarization following direction of impulses Rule #4: Repolarization away from direction of impulses -­â -­â = Positive Deflection = Negative Deflection ^ v = Negative Deflection = Positive Deflection v ^ SA Node generates an impulse o Atrial Depolarization occurs §ď§ P wave §ď§ Depolarization direction • Downward Follows Rule #1 • Right to left Impulse is transmitted to the AV node o AV Nodal Delay §ď§ PR Segment §ď§ Isoelectric line (no electrical activity noted) Direction of Impulses àď Downward àď Right to Left Electrocardiography -­â Atrial Repolarization occurs (Unseen in the ECG) o Repolarization Direction §ď§ Downward Follows Rule #3 §ď§ Right to left -­â Impulse is transmitted to the Ventricular Conduction System o Ventricular Depolarization Occurs §ď§ QRS Complex • Q Wave o Interventricular Septum Depolarization §ď§ Depolarization direction • Downward Follows Rule #2 • Left to Right • R Wave o Cardiac Apex Depolarization §ď§ Depolarization Direction • Downward Follows Rule #1 • Right to Left • S Wave o Posterobasal Depolarization §ď§ Depolarization direction • Upward àď Follows Rule #2 -­â Ventricular Repolarization occurs o Q Wave §ď§ Depolarization direction • Upward àď Follows Rule #4 Automatic Cells -­â -­â -­â Sinoatrial (SA) Node o Node of Keith and Flack o Primary pacemaker of the heart o Suppresses automaticity of other automatic cells §ď§ Overdrive suppression Atrioventricular (AV) Node o Node of Kent and Tawara o AV Nodal delay o Slow velocity of impulse conduction (0.05 m/s) Purkinje system o Bundle of His o Left and Right bundle branch o Purkinje Fibers ECG Procedure -­â Types o Resting ECG §ď§ Most common procedure done §ď§ Remove all metal items §ď§ Usually uses all leads o Exercise ECG / Stress test / Treadmill test §ď§ Detects the heart’s electrical activity changes during activity §ď§ At least 3 chest electrodes are used AJRU Atrial Muscle The first part to Depolarize will be the first part to Repolarize. Ventricular Muscle The first part to Depolarize will be the last part to Repolarize. The last part to Depolarize will be the first part to Repolarize. Electrocardiography AJRU -­â Application of electrode gel -­â Leads o Method discovered by Dr. Einthoven o Ground Lead §ď§ Eliminates non-­âcardiac electrical activities §ď§ Right leg (Black) o Bipolar Limb Leads §ď§ Lead I • Records electrical activities in the base of the heart • Right Arm (Red) to Left Arm (Yellow) §ď§ Lead II • Records electrical activities from the base going to the apex on right side of the heart • Follows cardiac vector • Right Arm (Red) to Left Leg (Green) §ď§ Lead III • Records electrical activities from the base going to the apex on left side of the heart • Left Arm (Yellow) to Left Leg (Green) o Unipolar Limb Leads §ď§ aVR • Center to the right uppermost part of the heart §ď§ aVL • Center to the left uppermost part of the heart §ď§ aVF • Center to the apex of the heart o Unipolar Chest Leads §ď§ V1 4th Intercostal Space, Right Sternal Border §ď§ V2 4th Intercostal Space, Left Sternal Border §ď§ V3 In between V2 and V4 §ď§ V4 5th Intercostal Space, Left Mid Clavicular Line §ď§ V5 5th Intercostal Space, Left Anterior Axillary Line §ď§ V6 5th Intercostal Space, Left Mid Axillary Line §ď§ V7 5th Intercostal Space, Left Posterior Axillary Line Rarely used th §ď§ V8 5 Intercostal Space, Left Mid Scapular Line o Esophageal Leads §ď§ Rarely used §ď§ Most posterior portion of the heart §ď§ Patient is asked to swallow the leads -­â Body fluids transmit conduction from heart -­â Einthoven’s Equation o (Lead II) = (Lead I)+ (Lead III) §ď§ Lead II shows the tallest recording in the ECG Electrocardiography AJRU ECG Reading -­â -­â Vertical Reading o Amplitude (millivolts) Horizontal Reading o Time (seconds) 5mm = 0.5 mv 5mm = 0.2 s 1mm = 0.1 mv 1 Hash Mark Equivalent to 3 seconds (15 big boxes) 1mm = 0.04 s -­â Interpreting the Heart Rate o Only for ECG readings with a regular rhythm o Count the number of small boxes in between the RR intervals o Multiply number of small boxes by 0.04 seconds Heart Rate = 60 seconds RR Interval Example 1 5 10 12 o 12 x 0.04 = 0.48 60 seconds . = 125 bpm 0.48 seconds Shortcut! (Only for exact RR Intervals) -­â 5 small boxes (1 big box) = 300 -­â 10 small boxes (2 big boxes) = 150 -­â 15 small boxes (3 big boxes) = 100 -­â 20 small boxes (4 big boxes) = 75 -­â 25 small boxes (5 big boxes) = 60 -­â 30 small boxes (6 big boxes) = 50 -­â 35 small boxes (7 big boxes) = 43 -­â 40 small boxes (8 big boxes) = 37 ECG Intervals PR Interval QRS Interval QT Interval ST Interval Normal Duration Common Range 0.18 s 0.12 – 0.21 s 0.08 s 0.08 – 0.10 s 0.40 s 0.40 – 0.43 s 0.32 s 0.12 – 0.21 s Electrocardiography Cardiac Abnormality Detection in ECG -­â -­â -­â -­â -­â Arrhythmias o Bradycardia §ď§ RR < 60 bpm o Tachycardia §ď§ RR > 100 bpm o Pacemaker abnormalities o Heart Blocks §ď§ 1st degree • Prolonged PR Interval §ď§ 2nd degree • PQRS – P – PQRS (2:1 / 3:1) §ď§ 3rd degree • P waves found in many parts Myocardial Ischemia / Injury / Infarction o Ischemia §ď§ Depressed T wave T↓schemia o Injury Injur↑ST §ď§ ST segment elevation infarQtion o Infarction §ď§ Pathologic Q wave Hyperkalemia o T wave Hypokalemia o Prominent U wave Hypocalcemia o Narrow QRS Interval (Tischemia) (injuryST) (infarction) Vectocardiography -­â -­â -­â Determination of the electrical axis of the heart Mean cardiac vector (angle) indicates the average direction of current flow in the heart o Normal (Local) Deviation from the normal axis §ď§ 0 to 90° may indicate Cardiomegaly o Normal (Western) §ď§ -­â30 to +110° o Average / Common Vector / Common Axis §ď§ 59° 2 methods o Method 1 §ď§ Lead I and aVF o Method 2 §ď§ Lead I, Lead II and Lead III AJRU Electrocardiography (ECG) Dr. Barbon ECG - This is a procedure were we are trying to detect and obtain electrical activities coming from the heart. now in the AV node. There will be normal AV nodal delay. Its purpose is for the atrium to contract ahead of the ventricle. It cannot undergo simultaneously. Why? Because you must fill the ventricle to maximum or almost maximum. And, what will cause almost maximum filling of ventricle? You allow the muscles to contract ahead. When it contracts, AV valves are open. While atrium and ventricles are in relaxed state, you have continuous ventricular filling. While it is relaxed (atrium and ventricle), you fill the ventricle up to 70% of its volume. But, it is not yet full. For it to reach the maximum filling, the atrial muscle must contract. Once it reaches the maximum filling, the impulses from the AV node, it will now eventually proceed towards the ventricles. The first to activate is the Bundle of His, then bundle branches. So, when you are asked what part of the ventricle was first to be activated—it’s the Interventricular septum (these are depolarizing current). You need to depolarize the ventricle for it to contract. Like the atrium, first it should be depolarize, and then activates the SA node, intermodal tracts; then, there will be delay in the AV node. And if the atrium is fully depolarizing it will now contract. Next, activates the ventricles, apex, and then Purkinje fibers. If you follow the activity it starts from the right atrium, because it is the pacemaker. From the right atrium the impulses are then transmitted towards the whole atrial muscles: right and left. What will transmit impulses if the SA node is in the right atrium? We will utilize the different intermodal tracts. The anterior tract of Bachmann, middle tract of Wenckeback and posterior tract of Thorel are almost simultaneous in activation. 1 Your posterior tract will eventually activate the whole right atrium. All right are activated by the posterior tract. The anterior tract of Bachmann will activate the entire left atrial region. Then, the middle tract of Wenckeback will activate the middle, the interatrial septum. And this all happens simultaneously. They will proceed now towards the AV node. So, what will happen What part of the ventricle was last activated? The Purkinje fibers will go back towards the base. And the last parts of the ventricle activated on depolarize the base. When the heart contracts and the atrial muscle contracts it will contract downward (pababa). Why downward? Because the activity will starts upward (pataas). When the ventricle contracts, it is initiated in upward direction. The first to activate is the septum and it will contract into smaller size, then apex, lastly base. Purpose: all contains blood (pulmonary artery and aorta)—located in the basal region. Atrium will give blood to the ventricles, while the ventricles will give blood to the systemic and pulmonary circulation. The opening is located at the base -- that’s mechanical activity. But MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) before mechanical activities happen, electrical activities must come first. In ECG, direction of electrical activity is needed. The flows of current are through: Electrical changes happening in the atrial and ventricular muscles. Depolarization of atrium will proceed on this direction going through the SA node towards the AV node. In the ventricle, first is the interventricular septum. Then, the electrical activity is of the same direction and current flow. The depolarizing current will moved in the direction moving towards the right side. Next to activate is the apex, then moving to the left side. Last part to depolarize is the base. Depolarization and repolarization are used in recording ECG. Following repolarization, in the atrium, the first to depolarize is the first to repolarize. Therefore, the direction of repo and depo in the atrium is the same. In the ventricle, the first to depo is the last to repo. The direction of repo in the ventricle is moving in opposite direction. If depo is moving towards left, repo is moving towards right. towards the left (depo) and that is also the repo. The first to depolarize in the atrial wall is endocardium to epicardium. (Same in repo) Phase 2- continuous repolarization; almost no change in the electrical activity of the ventricle—Plateau phase Phase 3- rapid return to normal resting membrane potential Phase 4- returning back to the RMP In the ventricle, the first to depo is endocardium to epicardium, but in repo it will start in the epicardium towards the endocardium. Average direction of the current flow of the heart: movement is from right to left. The first to contract is atrium then ventricle. The purpose of AVR contraction: for the blood in the atrium to be emptied in the ventricle. Then, the blood from the ventricle will be released to the aorta and pulmonary artery. When the ventricle contracts, it will not totally empty the ventricular chambers. There is remaining blood—ESV. There is no total emptying of ventricular chambers. This is what the ECG needs to record. The machine must be connected to the subject using the wires. And that wire is connected to the machine and to the subject. Electrodes are the one being attached to the subject. It includes: o Right arm electrode o Left arm electrode o Chest electrode o Left leg Electrode 2 If you look at the ventricular wall and atrial wall, you follow the depolarization. In the atrium, the movement is Phase 0- depolarization period Phase 1- start of repo MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Right leg electrode- it is the ground electrode. Because the heart is not the only one that makes the action potential, it can be smooth muscle, skeletal muscle. You must remove the said other action potential that are not coming from the heart, for the tracing to be clean. ECG machine is the one responsible on which lead is to be recorded. Leads will depend on what electrodes are being activated. The one activating this is the ECG. Electrodes exhibit a color coded form. It is in standard form: ďˇ Right arm- red ďˇ Left arm- yellow ďˇ Right leg- black (ground electrode) ďˇ Left leg- green The one attached in the chest are labeled 1, 2, and 3,4,5,6. Then, th ďˇ V1 – 4 ICS, right sterna margin th ďˇ V2- 4 ICS, left sterna margin nd th ďˇ V3- middle of 2 and 4 (V2 and V4) th ďˇ V4- 5 ICS, Midclavicular line th ďˇ V5- 5 ICS, axillary line th ďˇ V6- 5 ICS, midaxillary line ECG can be done as: Resting Exercise ďˇ ďˇ In exercise: electrodes are directly connected to the machine. Complete electrodes In resting: cables are commonly on the chest and not in the extremities Common recording of ECG: 12 ECG leads ďˇ ďˇ ďˇ Bipolar limb leads: 1, 2, 3 Unipolar limb leads: aVR, aVL, aVF Unipolar chest leads: V1-V6 They are called extremities leads because we are using extremity electrodes. ďˇ ďˇ ďˇ Lead I- electrical activity of heart recorded by right arm and left arm electrodes Lead II- RA and LL (record right side of the heart) Lead III- LA and LL (record left side of the heart) Bipolar- because it uses two electrodes Unipolar- uses one active electrode ďˇ ďˇ ďˇ Develop by Einhoven’s using bipolar limb leads aVR- active is right arm (upper most right side of the heart) aVL- left electrode (left extremity leads) aVF- left leg (lower most portion of the heart—apex) Remember: In the normal tracing, aVR is mostly the limb lead that is always presenting mostly negative deflected waves. Chest leads: horizontal or transverse plane Extremity Leads: anterior part of the heart (front only) Limitation: those happening in the frontal plane V1, V2: mostly on the right side of the heart V3, V4: middle heart V5, V6: left side, lateral side V7, V8: posterior of the heart (rare) 3 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) The electrical activity recorded to Lead II is equals to the sum of the electrical activity recorded to lead I and lead III. ďź ďź ďź aVR- active is right arm aVL- active is left arm aVF- active is left leg In unipolar chest leads, there is no negative and positive, the electrodes are all positive. When you interconnect them this is the arrangement. ďź ďź ďź This is the relationship to the heart; it’s the hexagonal reference system of the procedure. If you are using the extremities lead, it’s the frontal plane (front only), and you cannot see the back portion so you need to use the unipolar chest leads. Lead I- RA (-) and LA (+) Lead II- RA (-) and LL (+) Lead III- LA (-) and LL (+) In bipolar limb leads, it has negative and positive sign: ďˇ Right side- always negative ďˇ Left side- always positive, exceptin bipolar in lead III (left arm-negative) , but in lead I (left arm- positive) When you look at the ECG, you are not looking at a three dimensional picture it is already six dimensional pictures: Lead I, II, and III, aVR, aVL and aVF; six dimensions, heart is the center Locate V1-V6: th ďˇ V1 – 4 ICS, right sternal margin th ďˇ V2- 4 ICS, left sternal margin nd th ďˇ V3- middle of 2 and 4 (V2 and V4) th ďˇ V4- 5 ICS, Midclavicular line th ďˇ V5- 5 ICS, axillary line th ďˇ V6- 5 ICS, midaxillary line nd st First palpable is the 2 ICS not the 1 ICS. ďź ďź 4 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Chest leads- horizontal plane; determines happening laterally and posteriorly Extremities lead- frontal plane ECG waves: ďź ďź ďź ďź P wave- atrial depo QRS- ventricular depo T wave- ventricular repo U wave- activity of papillary muscle, seldom seen due to slow repo happening in the papillary muscle—not strong to generate electrical activity that can be recorded at the machine P, R, S, and T wave- common waves seen Q wave- seldom to be seen To know the problem at the back of the heart: look for the most posterior portion of the heart—esophageal leads. It is seldom used. It allows the patient to swallow electrode. Esophagus is right behind the heart in determining what’s happening posteriorly. V7-V8- if you want to see the back portion. Rare problems are seen in this part because seldom problems can be seen at the posterior part of the heart. 5 Common problem of the heart: left side; because left ventricle has greater works compare to the right ventricle. Left ventricle is the one working for the whole systemic circulation while the right ventricle works on the pulmonary circulation. MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Once depolarize next will be repolarization. There is no ECG wave representing atrial repo because it happens simultaneous with the ventricular depo (QRS). Isoelectric Line - Straight line Any recording above line (+) ď upward deflected wave Any recording below line (-) ď downward deflected wave Normally: there are only 2 negative waves Q wave- seldom although it is a negative deflected wave S wave- commonly recorded downward deflection Parameters used in determining when atrial repo and ventricular depo starts includes the following: ďˇ PR segment ďˇ PR interval RS- commonly seen Q wave- start of ventricular depo - only present part of ventricular repo due to phase III only telling us the duration of phase III When cell repolarizes, it is immediately observes after end of repolarization, once depolarization ends it begins to repolarize (starT from the end of S) Total duration of repolarization start from end of S to end of T Duration of T wave does not give the total duration of ventricular repo In obtaining the total duration of ventricular repo ď¨ it is measured from the end of S to the end of T Dr. Eithoven said that the value of Lead II is equals to the value of Lead I and Lead III. Lead II has the highest wave because it follows the wave of cardiac vector. Flowing in the same direction with the cardiac vector you obtain the positive wave where the electrical activity is a depolarizing wave. Atrial T wave Activity starts at the roght side goes towards the left going down Follows the cardiac vector If the ECG axis is opposite to the cardiac vector ď downward aVR T interval ď end of S to beginning of T ST segment end of S to beginning of T represent phase II normally at the isoelectric line while cell is repolarizing; since the machine only records electrical changes in phase II there is no electrical change(efflux of K is balance by the influx of Ca), so it is recorded at the isoelectric line but that cell is said to be repolarizing Positive waves ď P, R, S, and T waves (common) NO ďˇ QRS- ventricular depo ďˇ In the lecture, Phase 0- ventricular depo ďˇ T wave- ventricular repo ďˇ Phase 1 going to phase 3- ventricular repo in the lecture 6 T wave always mentioned as to ventricular repo does not give the total duration of ventricular repo ST interval measures the whole period of latent repolarization Cardiac vector normal direction R ď L going down ECG axis follow cardiac vector R ď L going down Lead II- follows cardiac vector, moving from the RA ď LL MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) - opposite to the cardiac vector Normally negative deflected Q wave Normally negative That is Lead II When impulses reaches bundle of this and transmitted to the interventricular septumď the impulses will move L to R (opposite cardiac vector so Q wave is negative) Represents depo of interventricular septum R wave + wave Wave representing what is happening in the apex Apex( impulses is R-L going down ď moving towards positive electrode—follow axis/ current flow Apical depolarization S wave Normally negative Represent the part of the ventricle depolarized last (base) - So the flow of impulse is transmitted upwardď opposite to the cardiac vector ď negative deflection Postero-basal region of the ventricle is depolarize T wave Repolarization (recording is opposite with depolarizing current) If repo follows ECG axis/ cardiac vectorď negative deflection It repo does not follow cardiac vectorď positive deflection Atrium st 1 to depo, is also the first to repo Ventricle st 1 to depo, is the last to repo From the basal portion Movement: Endoď epi (depo) Epiď endo (repolariing current ď flow is opposite ECG axis ď upward) T wave (+) In the ventricle ď flow of repo is counter to the flow of repo but not in the atrium because the flow of depo current follow the flow of repo Hash works Equals to 3 sec duration For determination of heart rate ECG paper Calibrated Amplitude: ďˇ 1 small square= 1 mm= .1mV ďˇ 1big square= 5mm= .5mV Time: ďˇ ďˇ 1 small square= 1mm= 40 milliseconds= 0.04s 1big square= 5mm= 200 milliseconds= 0.2 s Duration/ time Represented by horizontal line Unit: seconds Electrical activity Represented by vertical line Unit: mV 7 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Heart rate Use only for regular rhythm In reporting HR it is always per minute If irregular: Count big square enclosing R-R interval x .20sec Big square = 0.20sec Ex: if 6 sec x 10 = 60 sec 1 big square= 0.20s 60/ 0.20s= 300 Limitations: Use only for regular rhythm. It can’t be used if the HR is irregular Lead II - follow the flow of heart - RA ď LL ďź ďź ďź ďź P wave- atrial depo QRS- ventricular depo T wave- ventricular repo (part only) phase III PR Interval- duration of atrial depo + AV nodal delay ďź Intermodal tracts o will activates the atrial muscles o during PR interval, it is active ďź ďź ďź ďź ďź ďź ďź PR segment- AV nodal delay; end of P beginning of QRS Q wave- septal depo R wave- apical depo S wave- depo of base ST segment- after depo of ventricle; phase II T wave- phase III ST interval- total duration of ventricular repo (phase II, T wave and phase III) QT interval o ventricular depo and repo (ventricular muscle of action potential) o will help approximate the duration of ventricular contraction ( when depo it will immediately contract, the if already finish it will repo) o also known as the electrical systole of the heart ďź Duration that depolarize before repolarizeď LATENT PERIOD (the excitable muscle is depolarizing) 8 J point end of depo, start of repo normally, this period is always at the isoelectric line once not on the isolectric line it is now called ST segment elevation (up) and ST segment depression (down) ď suffering from ischemia elevation- ď myocardial ischemia MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) When you are a doctor use: Lead I and aVF Vector Purpose: tells the direction of the electrical activity of the subject and also the magnitude (how strong is the said current) Purpose: common point of all values from the different leads. From the common point start doing horizontal line passing to the center of the triangle to lead warns. Get the center of the triangle and that is zero. From that zero point, draw an arrow going to the common point of the lines, from the values of leads I, II, and IIIď cardiac axis of the patient. This is the direction of the current flow. To get the angle, use protractor and that will be the cardiac vector. Every millimeter times 1mV. To check if the ECG technician is correct used: Lead I and aVF (easy way) Plot lead I (+5) and Lead III (+3.5) For diagnosis used: Leads I, II and III You will compute for the R wave (+6.5) and S wave (1.5), the unit is distance; next compute for the Lead III. The total should be equal to sum the of leadIII and lead I. After getting the values, make the triangle. Use the Eithovens triangle and get a protractor. Get the center (from the apex going to the opposite side). Each center of each side mark it zeros. Lead I (+ 5) and lead III (+3.5) 9 Once you record it, draw a line perpendicular to the lead study. The calibration is millimeters. There will be intersection. Then get now Lead II (+8.5). It should be exact. MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) ďź Not all abnormalities can be diagnosed by ECG. Common axis: 59 degrees Position of the heart: intermediate SA node (pacemaker) ď Sinus rhythm Not SA node, but is controlled by AV node ď AV nodal rhythm/ Junctional rhythm Easy way: 1. Get aVF and Lead I. 2. Lead I ď RA- LA 3. Get and draw the value of Lead I (+5) and aVF (+6.5) 4. Then after plotting, see the common intersection. From the intersection draw an arrow, that is the vector and you can get the cardiac axis. 10 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Prominent Q waveď previous infarction ďź Elevation: ischemia ďź Depression: infarction st 1 degree heart block P-QRS interval normal P waves PR interval are longer nd 2 degree heart block 1:1 ratio is not normal because QRS are not seen - 2:1 or 3:1 ratio rd 3 degree heart block Ventricle is independent of atrial activity Bundle Branch Block Longer and wider QRS 11 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Right ventricular hypertrophy Tall R waves in V1; deep S waves in V6 Left ventricular hypertrophy Tall R waves in V6; deep S waves in V1 ECG - Not only diagnose cardiac problems but also electrolyte problemsď electrolyte problems affect cardiac activity Diagnose cardiac problem with alternation in electrolyte activities Tall T wave (peaked T wave) Echocardiography Can diagnose cardiac problems not associated with alternation of electrical activity Action potential is longer ď phase II Prominent U wave ď HYPOKALEMIA 12 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Cardiac masses Abnormal growth in the cardiac tissue Pericardial disorders Even injuries affecting pericardial sac Initially not diagnose in ECG ď they are not causing changes in the electrical activity of the heart Problems in this conditionsď BLOOD FLOW (diagnose using echocardiography 13 MAURO, REJANE D. 1E ( ELECTROCARDIOGRAPHY- DR. BARBON) Microcirculation (Gloria Marie M. Valerio, MD) Example is a photo of an endothelium. There are individual endothelial cells. Inside is the intravascular compartment and outside is the interstitial compartment so in other words, the capillary wall or membrane separates intravascular from interstitial fluid compartment. In the vascular wall, the endothelial cells or membrane of the endothelial cells are connected by protein attachments but between the protein attachments are spaces called slits or pores or clefts. And these slits, pores or clefts can allow water molecules as well as small water soluble molecules to pass through. Although not shown in the picture, there are also vesicles present on the membrane. These vesicles will coalesce to form cave-like structures called calveolae that can allow macromolecules to pass through. Comparison of Intravascular and Interstitial Fluid PHOTO: Composite schematic drawing of the microcirculation. The circular structures on the arteriole and venule represent smooth muscle fibers, and branching solid lines represent sympathetic nerve fibers. The arrows indicate the direction of blood flow. When we say microcirculation, this will involve the activity or function of the smaller blood vessels that will include the arterioles, capillaries, and venules. In the different organs of the body, an artery will divide 6-8x giving rise to smaller branches called arterioles with an internal diameter of 10-15 µm. The arterioles themselves will divide several times giving rise to yet smaller branches with an internal diameter of 5-9µm. The terminal branch of an arteriole is a metarteriole which will then connect with the capillary. The wall of the metarteriole contains a smooth muscle layer but it is not continuous. However at the junction between a metarteriole and a capillary is a layer of smooth muscle forming what we call the pre-capillary sphincter. The precapillary sphincter is not innervated by sympathetic nerves but it can still respond to circulating vasoconstrictors. From the capillaries, blood will then be collected by the venules that will coalesce to from the bigger veins. In some areas of the body like for example in the finger tips, palm of the hand, and in the earlobes, the arteriole is directly connected to the venule bypassing the capillary forming what we call an arteriovenous anastomosis or shunt. The function of the arteriovenous anastomosis or shunt is to regulate body temperature – it transports heat away from the body. We mentioned that the capillaries are exchange vessels because of the thin and porous capillary wall or membrane, it allow exchange of fluid and some solutes between intravascular and interstitial fluid compartment. 1 Shannen Kaye B. Apolinario, RMT | Intravascular fluid is the liquid portion of blood or plasma. Plasma contains 91-92% water, solutes suspended dissolved in the plasma which include plasma proteins; electrolytes like Na+, K+, Cl- etc.; nutrients like glucose, amino acids, fatty acids; gases like oxygen and carbon dioxide; waste products of metabolism like urea; hormones; and enzymes – all are in the plasma plus the formed elements in the blood. The intravascular fluid contains formed elements and more proteins in the plasma. Present in the interstitial fluid is not only water but also two solid structures that will provide tensile strength for the tissue and these are collagen fibers and proteoglycans. In the interstitium, the fluid is not free flowing, it is a gel-like structure because of the presence of the collagen fibers and proteoglycans and there is very little amount of the free flowing fluid. Functions of the Endothelium / Endothelial Cells 1. Physical lining. It lines the blood vessel wall. 2. Permeability barrier and transport regulator. As what have mentioned earlier, it provides a permeability barrier as well as regulator of transport of water molecules and some solutes. 3. Secrete paracrine substances acting on smooth muscle. It can also secrete paracrine substances that can act on the vascular smooth muscle examples include nitric oxide that will cause vasodilatation and endothelin that will cause vasoconstriction. 4. Mediated angiogenesis. The endothelial cells can also mediate angiogenesis. Angiogenesis means formation of new blood vessels from existing blood vessels and that is made possible when the endothelial cells secrete the vascular endothelial growth factor (VEGF). 5. Produce growth factors in response to damage. The endothelial cells can also produce growth factors that will repair the damage in the vascular wall. 6. Secrete substances that regulate platelet clumping, clotting and anti-clotting, It can also secrete substances that will regulate platelet clumping, clotting, and anti-clotting. One substance that is secreted by the endothelial cells that will increase platelet adhesiveness and regulate the formation of clotting factor VIII is the von Willebrand factor. 7. Secrete cytokines in immune response. The endothelial cells also secrete cytokines in response to an immune reaction. Transcapillary Exchange How solutes and water molecules are transported across the capillary membrane? 1. Diffusion One mechanism is by simple diffusion and this is true for small water soluble substances as well as for lipid soluble substances. For small water soluble substances, they can diffuse to the clefts/pores/slits present on the capillary membrane. For lipid soluble substances, they can easily diffuse across the membrane. What are the factors that may influence diffusion rate? S = DC x SA x ΔC Where: Surface area: if the surface area available for diffusion is big, the more substances that can be diffused. The diffusion coefficient is dependent on two factors: molecular weight or size of the substance which is inversely related to diffusion and the other factor that will affect diffusion coefficient is temperature which is directly related to the diffusion rate. For small water soluble molecules, diffusion is said to be flowlimited, meaning to say, it will depend on blood flow. When the blood flow is fast, more substances can diffuse but for large water soluble or lipid insoluble substances, the limiting factor is its molecular weight or size so they are called diffusion-limited. Pinocytosis Some macromolecules can be transported by way of calveolae or vesicles. The mechanism is either through pinocytosis/endocytosis or transcytosis. 3. IN Plasma colloid osmotic pressure (Đp) Interstitial fluid pressure (Pif) To bring about filtration and absorption, there are four forces involved and we call them Starling’s forces. Forces when increased will favour movement of fluid out or filtrations are the capillary hydrostatic pressure and interstitial fluid colloid osmotic pressure. On the other hand, forces when increased will favour absorption of fluid are plasma colloid osmotic pressure and interstitial fluid pressure. Capillary hydrostatic pressure (Pc) Plasma colloidal osmotic pressure (Đp) DC = diffusion coefficient SA = surface area ΔC = concentration gradient So for diffusion of substances to take place, there has to be difference in concentration and the substances will be transported from a high concentration area to a low concentration area. 2. OUT Capillary hydrostatic pressure (Pc) Interstitial fluid colloid osmotic pressure (Đif) Filtration or Absorption Two other mechanisms will allow transport of water across the capillary membrane: one is filtration and the other one is absorption. Arterial Venous Intravascular Interstitial Filtration Absorption For example this is a capillary; there is an arterial end and a venous end, an intravascular compartment and an interstitial compartment. What does filtration mean? How is it different from diffusion? The filtering membrane is the capillary membrane. Filtration is transport of water molecules and some solutes from a high pressure area to a low pressure area and that usually happens at the arterial end of a capillary. At the venous end, water molecules will be absorbed from the interstitial to the intravascular compartment. So when we say absorption, the water goes back to the intravascular compartment. What will attract water back into the intravascular compartment? There has to be the presence of osmotically active substances specifically the plasma proteins. So you have filtration at the arterial end of a capillary and absorption at the venous end. 2 Shannen Kaye B. Apolinario, RMT | Interstitial fluid hydrostatic pressure (Pif) Interstitial fluid osmotic pressure (Đif) Capillary hydrostatic pressure is the force exerted by the volume of water on the capillary wall. So that when it is increased, this is the one that will push water out into the interstitial space. Plasma colloid osmotic pressure is determined by the number of concentration of plasma proteins. Plasma proteins are osmotically active and when increased, they can attract water molecules into the intravascular space by osmosis. Why proteins? Because of its large size and the capillary membrane is impermeable to these plasma proteins (if the capillary wall is permeable, plasma proteins will go in and out of the space and there will be water absorption. Water will go where the proteins are). When the concentration or number of plasma proteins increases, plasma colloid osmotic pressure will increase and that will attract water back into the intravascular compartment. Capillary hydrostatic pressure and plasma colloid osmotic pressure are the most important of the four forces that will regulate transcapillary exchange of fluid. The other two are less important. Interstitial fluid hydrostatic pressure is the force exerted by the volume of fluid in the interstitial space. It is less important because it does not change under normal conditions because any excess of fluid in the interstitial space will be collected by the lymphatic vessels and returned into the circulating blood. If there is an excess interstitial fluid, it means that there is edema and that will now push the fluid into the intravascular compartment. The other one is interstitial fluid osmotic pressure so that in now determined by the number or concentration of proteins in the interstitial space. Remember we mentioned that the interstitial space is not purely water, there is little amount of proteins but it is also less important because the proteins in interstitial space will not increase (under normal conditions), it will only increase when the capillary membrane is destroyed that will allow plasma proteins to pass through so when the plasma proteins go out, it will go together with water. When the interstitial fluid osmotic pressure increases, that will attract water molecules. Net Filtration Pressure (NFP) NFP = (Pc – Pif) – (Đp – Đif) (+) = favour filtration (- ) = favour absorption The net filtration pressure (NFP) is equal to capillary hydrostatic pressure minus interstitial fluid pressure minus plasma colloid osmotic pressure minus interstitial fluid osmotic pressure. If the value that you will get is positive, that will favour filtration. If the value that you will get is negative, there will be absorption. To put in another way: 15 + 3 = 18. The factors that will favour absorption are still the same. Again, you have a difference of 10 but the factors that will favour absorption is now higher so that is at the venous end. Increased Capillary Hydrostatic Pressure (CHP) Capillary Filtration Coefficient (Kf) Remember that characteristic of the capillary membrane will vary from one organ to another like for example in the brain. In the brain, the endothelial cells lining the capillaries are joined by tight junctions that is why only the smallest substances can pass through. The opposite is true in the liver wherein the clefts are wide open that even proteins can pass through so that aside from the net filtration pressure, we also have to take into consideration the number and size of pores that are present on the capillary membrane as well as the number of active capillaries in a tissue. The more actively metabolizing a tissue is, the greater the number of active capillaries. 1. Arteriolar dilatation. One factor is arteriolar dilatation that will increase blood flow to the capillaries, increasing the volume of blood in the capillaries therefore increasing the force exerted by that volume of blood on the capillary wall. 2. Venoconstriction. Remember that blood in the capillaries should flow into the venous system. If the venous system is constricted, blood cannot flow into the veins, blood will pull into the capillaries and that will again increase the CHP. 3. Increased venous pressure. The venous system normally is a low pressure are but if there is congestive heart failure, the pumping action of the heart is compromised, blood will back up in the venous system, venous pressure will increase so the blood cannot flow from the capillaries to the veins so CHP will increase. 4. Increased arterial blood pressure. An increase in arterial blood pressure that will increase blood flow to the capillaries. FR = Kf x NFP Where: FR = filtration rate Kf = capillary filtration coefficient NFP = net filtration pressure So that when we say filtration rate, it is actually the product of capillary filtration coefficient and net filtration pressure. Arterial end Pc = 35 j Pif = 0 Venous end Đp = 28 Đif = 3 Pc = 15 Pif = 0 5. Đp = 28 Đif = 3 NFP = (35-0) – (28-3) = 10 mmHg = favouring filtration NFP = (15-0) – (28-3) = -10 mmHg = favouring absorption 35 3 38 15 3 18 28 0 28 *** Two ways: increase venous pressure and increase arterial blood pressure will increase the capillary hydrostatic pressure. 28 0 28 The capillary hydrostatic averages 35 mmHg at the arterial end, remember that the arterial system is a high pressure area, the venous system is a low pressure area and the average capillary hydrostatic pressure at the venous end is only 15 mmHg. For the plasma colloid osmotic pressure, it is the same at the arterial and venous ends of a capillary average of 28 mmHg. For the interstitial fluid pressure, almost 0mmHg on both the arterial and venous end as well as the interstitial fluid osmotic pressure, both are 3 mmHg. The one that often change is the capillary hydrostatic pressure. Decreased Plasma Colloid Osmotic Pressure 1. Now we go at the venous end, so same formula: NFP = (Pc – Pif) – (Đp – Đif). The answer is still 10 mmHg but this time, it is negative so it will favour absorption. 3 Shannen Kaye B. Apolinario, RMT | Decreased plasma protein level Plasma colloid osmotic pressure is determined by the number or concentration of plasma proteins so that any condition that will cause hypoproteinemia will decrease the plasma colloid osmotic pressure and that is one cause of edema. The fluid cannot be absorbed in the intravascular compartment so it accumulates in the interstitial space. So what are the conditions that will cause hypoproteinemia? Why is there filtration on the arterial end? Let us go back to the formula of net filtration pressure (NFP): NFP = (Pc – Pif) – (Đp – Đif). You get positive 10 and if the answer is positive, it favours filtration. To put in another way, what are the forces when increased will favour filtration? It is the capillary hydrostatic pressure and interstitial fluid osmotic pressure. On the other hand, what are the forces when increased will favour absorption? It is the plasma colloid osmotic pressure and interstitial fluid pressure. You have a difference of 10 and the factor that will favour filtration is bigger so at the arterial end, you have filtration. Increased total blood volume. Another one is an increase in total blood volume which will initially affect venous return – it will increase. With increased venous return, cardiac output will increase. With increased cardiac output, arterial blood pressure will increase so will the CHP. ďˇ Poor production. Liver diseases will cause hypoproteinemia because proteins are produced in the liver ďˇ Protein losing conditions. Kidney or renal diseases that will increase excretion of proteins. ďˇ Decrease substrate. Malnutrition or starvation will cause hypoproteinemia because there are no substrates for protein synthesis. Increased Interstitial Fluid Osmotic Pressure 1. Increased capillary membrane permeability. The interstitial fluid osmotic pressure will increase with increased capillary membrane permeability. When the capillary membrane is damaged, it allow proteins to pass through that will increase the interstitial fluid osmotic pressure attracting fluid from the intravascular to interstitial fluid compartment. Causes of Increased Interstitial Fluid Volume (Edema) 1. Increased filtration pressure. The capillary hydrostatic pressure is too much so the water goes out in the interstitial space. 2. Decreased absorption. Decreased absorption because of hypoproteinemia that would decrease the plasma colloid osmotic pressure (PCOP). 3. Increased capillary permeability. Increased capillary membrane permeability that will increase the interstitial fluid osmotic pressure. 4. Inadequate lymphatic flow. More importantly, obstruction in the lymphatic circulation or inadequate lymphatic flow because remember that the primary action of the lymphatic vessels is to collect excess fluid from the interstitial space so if the lymphatic circulation is inadequate, it cannot collect the excess fluid in the interstitial space so there will be accumulation causing edema. metabolites will accumulate. When you release the occlusion, blood flow will increase rapidly and that increase in blood flow will continue until the oxygen supply is replenished and the metabolites are washed away. So in active hyperemia, the tissue is active. In reactive hyperemia, the tissues react first to the occlusion. 2. Myogenic Theory Ohm’s law (Q) = ΔP R Where: Blood Flow We go back to blood flow to the different organs of the body. Why is it in the cardiac output of 5,000 mL/min, almost 20-21% goes straight to the kidneys? Why there are organs that is increased in blood flow and why are there organs with less blood flow? Regulation of Blood Flow a. Autoregulation The first mechanism that regulates the blood flow is autoregulation. When we say autoregulation that means the tissue themselves regulate their own blood flow. It determines whether the blood flow should be increased or decreased. 1. The other mechanism is myogenic. Remember Ohm’s law – blood flow is equal to pressure gradient over resistance. So we expect that when the blood pressure increases, blood flow increases. If the blood pressure continues to increase, blood flow will also continue to increase but it is not the case because we have what call an autoregulatory range wherein an increase in blood pressure will maintain a constant blood flow. And that autoregulatory range is between 75-175 mmHg. So when blood pressure increases from 75-175 mmHg, there is very little increase in blood flow so the normal blood flow is maintained. When the blood pressure is high, the arterial wall is stretched. Stretching of the arterial wall will stimulate the receptors present on the arterial wall and that will initiate a reflex action causing vasoconstriction. So increased blood pressure, blood flow will increase initially then there will be vasoconstriction then decreased blood flow. From increased blood flow, it will decrease then it will be maintained a constant level. But outside of the autoregulatory range, let’s say the blood pressure drops below 75 mmHg, blood flow decreases. When blood pressure rises above 175 mmHg, blood flow increases. But within the autoegulatory range, the blood flow is maintained at a constant level with an increase in blood pressure. b. Metabolic Theory Decreased pO2 Increased pCO2 Increased H+, Lactic Acid (dec. pH) Increased K+, Adenosine Vasodilators At the same time, actively metabolizing cells produce carbon dioxide. Aside from carbon dioxide, actively metabolizing cells also produce hydrogen ions, as well as lactic acid. Other metabolites produced include potassium as well as adenosine. All of these are vasodilators. What happens when the cell is active, there are two factors: hypoxia and production of metabolites that are vasodilators so there will be vasodilatation, increased blood flow, increase oxygen supply to replenish the oxygen lack. Also, increased blood flow will wash away the metabolites so the oxygen will increase, the metabolites are gone, vasoconstriction. Now, that is what we call active hyperemia – increased blood flow during active metabolism. What is reactive hyperemia? This time, when you occlude a blood vessel temporarily, there will be no blood flow, no oxygen, Shannen Kaye B. Apolinario, RMT Release of vasoactive substances from the endothelium Vasodilators: - Prostacyclin - NO2 For actively metabolizing cells, they consume oxygen so that will cause a decrease in the oxygen tension in the blood. The vascular smooth muscle needs oxygen to contract so if the oxygen has been used up by the tissue, oxygen tension is decreased so there will be hypoxia or lack of oxygen and that will cause the vascular smooth muscle to relax so there will be vasodilatation, blood flow is increased, oxygen supply will also increase. When the oxygen supply is increased, vascular smooth muscle will have something (oxygen) to use, it will contract so there will be vasoconstriction. With vasoconstriction, blood flow is decreased, oxygen supply is decreased, vasodilatation. It is like a reflex action. 4 ΔP = pressure gradient R = resistance | Vasoconstrictors: - Endothelin - TXA2 Aside from autoregulation, there are local vasoactive substances secreted mainly by the endothelial cells that can act on the vascular smooth muscle and this will include vasodilators like prostacyclin and nitric oxide, vasoconstrictors like endothelin, you also include thromboxane A2. So these are local vasoactive substances produced by the endothelial cells. c. Humoral control of blood flow Vasoconstrictor agents: - Norepinephrine/epinephrine - Angiotensin II - Vasopressin - Endothelin - Serotonin Aside from local vasoactive substances, we also have circulating vasoactive substances and this will include norepinephrine and epinephrine - norepinephrine from sympathetic nerves and the adrenal medulla, epinephrine from the adrenal medulla. Another very potent vasoconstrictor is angiotensin II and we will discuss more of angiotensin II later when we go to mechanisms that regulate arterial blood pressure. The antidiuretic hormone (ADH) or vasopressin synthesized by the hypothalamus, stored and released by the posterior pituitary gland. Other vasoconstrictors are again, you have endothelin and serotonin. Vasodilator agents: - Bradykinin - Histamine Aside from autoregulation, local vasoactive substances, circulating vasoactive substances we also have the vasodilators bradykinin and histamine. Now these two, aside from causing vasodilatation, they can also increase capillary membrane permeability in response to a hypersensitivity or allergic reaction. 1. R-A-A system Neural: Low Pressure Receptor Mechanism d. Effect of ions and other chemical factors Increased Ca++ Increased K+ Increased Mg++ Increased H+ Increased CO2 Vasoconstriction Vasodilatation We have several ions that can also act on the vascular smooth muscle. Calcium for vasoconstriction then potassium, magnesium, hydrogen ion, carbon dioxide will cause vasodilatation. e. Autonomic innervation In the blood vessel of the skin and viscera, innervation is autonomic adrenergic. The neurotransmitter agent released is norepinephrine and from the adrenal medulla, norepinephrine and epinephrine. So when these two binds with alpha-1 receptors there will be vasoconstriction. When they bind with beta-2 receptors, there will be vasodilatation. In the blood vessel of the skeletal muscle, innervation is sympathetic cholinergic so you have acetylcholine binding with muscarinic receptors that will bring about vasodilatation. f. Angiogenesis Now, in growing tissues, to meet their metabolic needs, there has to be formation or proliferation of new blood vessels from existing blood vessels and this is stimulated by the vascular endothelial growth factor (VEGF) secreted by the endothelial cells. So these are the factors that regulate the blood flow. In most instances, autoregulation and metabolic will override the other mechanisms. Arterial Pressure Control Mechanisms Mechanisms that regulate arterial blood pressure: a. Acting within seconds or minutes b. These receptors are present on the atrial wall as well as on the arterial wall and they are more sensitive to an increase in blood volume rather than an increase in blood pressure. Under this, we have the Bainbridge reflex. Remember the SA node is in the right atrium. Now, when the volume of blood in the right atrium increases, that will stretch the right atrial wall and directly stimulates the SA node increasing the heart rate. With increase in heart rate, blood will be ejected from the right atrium to the right ventricle on to the pulmonary circulation so the volume of blood will be decreased on the right atrium. But at the same time, stretching the wall of the right atrium will initiate a reflex action transmitted by the vagus nerve to the medulla where you have the vasomotor center. And from the vasomotor center, back to the SA node in the right atrium again increasing the heart rate so that blood will be ejected from the right atrium, to the right ventricle and to the pulmonary circulation. So the end result of this Bainbridge reflex is to increase heart rate so that the increase volume of blood in the right atrium will be ejected immediately. When the right atrial wall is also stretched, the atrial muscles secrete a hormone that is the atrial natriuretic peptide (ANP) that will cause natriuresis. Meaning to say, this hormone will act on the renal tubules to increase excretion of sodium. When the sodium is excreted, water goes along with it so the blood volume will decrease. This reflex is stimulated by an increase in blood volume specifically on the right atrium and its result is to decrease blood volume. Inc. in atrial pressure - dec blood vol First, for immediate regulation of blood pressure, we have mostly neural mechanisms and this will include: 1. 2. 3. 4. PHOTO: Intravenous infusions of blood or electrolyte solutions tend to increase the heart rate via the Bainbridge reflex and to decrease the heart rate via baroreceptor reflex. The actual change in heart rate induced by such infusions is the result of these two opposing effects. Baroreceptor Feedback Mechanism Baroreceptor feedback mechanism CNS ischemic mechanism Chemoreceptor mechanism Low pressure receptor mechanism Acting after many minutes or hours We also have mechanisms that can act after many minutes or hours and this will include: 1. 2. 3. c. Stress-relaxation mechanism Capillary fluid shift Renal fluid shift Actin g on several hours For long term regulation of blood pressure we have the renin – angiotensin – aldosterone system. 5 Shannen Kaye B. Apolinario, RMT | PHOTO: Diagrammatic representation of the carotid sinus and carotid body and their innervation. Carotid sinus can be stimulated either by an increase or decrease in blood pressure as long as there is a change in blood pressure. The difference is if the stimulus is an increase in blood pressure, the rate of firing of action potential is also increased but if a stimulus is a decrease in blood pressure, the rate of firing of action potential will also decrease. On the other hand, the aortic sinus is stimulated only by an increase in blood pressure, it is not stimulated by a decrease in blood pressure and you need a higher increase in blood pressure to stimulate the aortic sinus. Comparing the two, the carotids sinus is more sensitive to changes in blood pressure. Functional areas of the vasomotor center The areas present in the vasomotor center (remember that this is in the medulla): PHOTO: Anterior view of the aortic arch showing the innervation of the aortic bodies and baroreceptors. 1. Vasoconstrictor region (C-1). Tonically active, it responsible for maintatining the tone of the vascular wall. is 2. Vasodilator region (A-1). The vasodilator region inhibits the vasoconstrictor region so that will bring about vasodilatation. 3. Sensory region. In the vasomotor center there is also a sensory region that will detect what are the changes in blood pressure. 4. Cardiac center. Baroreceptor Reflex Path Baroreceptors (carotid and aortic arch sinus) Glossopharyngeal nerve and vagus nerve Baroreceptor Reflex Increased MAP Vasomotor center Vasomotor center Sympathetic and parasympathetic fibers The receptors are baroreceptors or pressoreceptors stimulated when the arterial is stretched. There are two types of baroreceptors: carotid sinus and aortic sinus. In the photo, you will see the right and left common carotid arteries that will bifurcate to form the internal and external carotid arteries. The carotid sinus is located immediately above the bifurcation in the wall of the internal carotid arteries while the aortic sinus is concentrated on the wall of the aortic arch. When the arterial wall is stretched, the carotid and aortic sinus will be stimulated. When stimulated, they will generate impulses transmitted by cranial nerves IX and X. Cranial nerve IX will transmit impulses from the carotid sinus while cranial nerve X will transmit impulses from the aortic sinus. The impulses are brought to the vasomotor center which is located in the medulla and from the vasomotor center, efferent or motor impulses will be transmitted by autonomic nerves to the heart and blood vessels. So these are the components of the baroreceptor reflex. Baroreceptor Discharge Range Carotid baroreceptor Aortic baroreceptor 50 100 150 200 Baroreceptor pressure (mmHg) 250 6 | Shannen Kaye B. Apolinario, RMT Error detect Set point Barorecptor Heart and blood vessels 0 Carotid sinus CSM firing Inc. stretch sympathetic sympathetic parasympathetic Heart Dec. rate & contractility Vasc. smooth musc. Dec. TPR Inc. vol. Let us now see how the baroreceptor reflex regulates the blood pressure. Let’s say that our stimulus is an increase in blood pressure/mean arterial pressure (MAP) that will stretch the arterial wall that will stimulate both the carotid and aortic sinuses depending on what is the increase in blood pressure. When the arterial wall is stretched, it will stimulate the receptors, they will generate impulses transmitted by cranial nerves 9 and 10 to the vasomotor center where the sensory region will detect what is the stimulus – either an increase or decrease in blood pressure. The blood pressure is increased so the efferent output is decreased sympathetic outflow, increased parasympathetic outflow first to the heart. Now remember that the formula for arterial blood pressure is cardiac output x total peripheral resistance (ABP = CO x TPR). TPR increases with vasoconstriction, decreases with vasodilatation while the cardiac output will depend on the stroke volume and heart rate. Let’s look on how will it decrease the blood pressure. Decreased sympathetic outflow to the heart decreases heart rate and decreases force of myocardial contraction so the stroke volume will also decrease so when it decreases, decreased cardiac output, decreased arterial blood pressure. Increasing parasympathetic outflow to the heart will also decrease the heart rate therefore decreasing the cardiac output, decreasing the arterial blood pressure. Other effector organs are the blood vessels specifically the arterioles and veins. In sympathetic outflow to the arterioles will decrease so there will be vasodilatation and that will decrease the total peripheral resistance, decrease arterial blood pressure. In sympathetic outflow to the veins will decrease venous tone and vascular capacity will increase. With increase vascular capacity, venous return will decrease and so will the arterial blood pressure. CNS Ischemic Response Now let’s reverse. For example there is a decrease in blood pressure, how will it increase the blood pressure? For example, lying down for a prolonged period of time then suddenly gets up, due to the effect of gravity, there will be pulling of blood to the lower extremities so decrease venous return as well as blood supply to the brain resulting to dizziness and fainting. But that does not happen because when the blood pressure decreases, the baroreceptor reflex will work immediately. Within seconds, it will increase the blood pressure, in what way? A decrease in blood pressure stimulates the carotid sinus but there is less firing of impulses that will reach the vasomotor center then it will be detected by the sensory area that there are less impulses so the blood pressure will decrease. This time, sympathetic outflow will increase, parasympathetic will decrease. So with increase sympathetic outflow to the heart, heart rate will increase, the force of myocardial contraction will increase, increased stroke volume and cardiac output. With decreased parasympathetic outflow to the heart, heart rate will increase so everything will increase the cardiac output, arterial blood pressure. Then you have increased sympathetic outflow to arterioles – vasoconstriction, increasing total peripheral resistance, increased venous tone, decreasing vascular capacity, increasing venous return, cardiac output and arterial blood pressure. But take note that the baroreceptor reflex can provide only short term regulation of blood pressure. Effectivity is only up to two days after which the baroreceptor will reset. If they were exposed to blood pressure of let’s say 150, it can work until 150 only. It resets that’s why it is only a short term regulation of blood pressure. Decreased blood flow to the brain (+) VMC Ischemia Increased sympathetic Increased pCO2 Increased ABP So again, when blood pressure decreases, blood flow to the brain decreases, oxygen supply will decrease, carbon dioxide will accumulate, the vasomotor center (VMC) is stimulated to increase sympathetic outflow to heart and blood vessels increasing the arterial blood pressure (ABP). Cushing’s Reaction Increased ICP > ABP Ischemia Compress arteries CNS ischemic response Decreased blood flow Another mechanism is the Cushing’s reaction. Let’s say there is fluid accumulation in the brain or there is a tumour in the brain that will increase the intracranial pressure (ICP). If the intracranial pressure exceeds the arterial blood pressure (ABP), that will compress the arteries. So again, the blood flow will decrease, decreased oxygen supply, accumulation of carbon dioxide and it will enter again the CNS ischemic response. Chemoreceptor Reflex Decreased ABP Decreased Arterial PO2 Carotid bodies CN 9 Aortic bodies CN 10 (+) VMC Increased sympathetic Heart Increased ABP Blood Vessel 3 stimuli: ďˇ Decrease pO2 ďˇ Increase pCO2 ďˇ Increase H+ concentration (decrease pH) We have two kinds of chemoreceptors: carotid and aortic bodies which have the same location as the aortic sinus and carotid sinus. Chemoreceptors are the receptors sensitive to changes in the blood gases and this will include hypoxia, increase carbon dioxide, increase hydrogen ion concentration or a decrease in plasma pH - these are the three stimuli that will stimulate the chemoreceptors. So when the blood pressure decreases, blood flow decreases, oxygen supply decreases and that will cause the accumulation of carbon dioxide and hydrogen ions so that will now stimulate the chemoreceptors sending impulses to the vasomotor center (VMC). The vasomotor center will respond by increasing sympathetic outflow to the heart and blood vessels therefore increasing blood pressure, blood flow, oxygen supply, washing away carbon dioxide and hydrogen. 7 Shannen Kaye B. Apolinario, RMT | PHOTO: Schematic diagram illustrating neural input and output of the vasomotor region (VR). IX, glossopharyngeal nerve; X, vagus nerve. Other Mechanisms: Alteration in Glomerular Filtration Rate (GFR) Capillary Fluid Shift Dec. ABP Increased BP Increased CHP Decreased BV Dec. glomerular CHP Filtration Decreased MCSFP Decreased CO Dec. RBF Decreased filtration Decreased urine formation Na & H2O retention Preservation of BV Improve VR & CO Increased ABP Decreased VR Return ABP to normal Any condition that increases the arterial blood pressure will increase the capillary hydrostatic pressure (CHP) that will push the width out of the blood vessels therefore decreasing the blood volume. With a decrease in blood volume (BV), it will arrive in the formula for venous return. Mean circulatory static filling pressure (MCSFP) will decrease, venous return (VR) will decrease, cardiac output (CO) will decrease and that will return or decrease blood pressure to normal. It will not decrease below normal because initially, it is above normal so if it decreases, it will go back to normal. Do the reverse if the blood pressure is decreased. Capillary hydrostatic pressure is decreased, less filtration, so increased blood volume, venous return, cardiac output, increased blood pressure. Stress-Relaxation Decreased ABP Decreased distending pressure Elastic recoil Decreased vascular capacity When blood pressure decreases, renal blood flow will decrease so that blood flow to the glomerular capillaries will decrease. In the nephron, the functional unit of kidney, one set of capillaries is the glomerulus. So if the glomerular capillary hydrostatic pressure (CHP) decreases, filtration of plasma will decrease so the filtrate that will go to the renal tubules (which are supposed to be excreted in the urine) will be less also. So you have decreased urine formation, sodium and water are retained in the body that will preserve the blood volume (BV), improve venous return (VR) and cardiac output (CO), increasing the arterial blood pressure (ABP). If the blood pressure increases, renal blood flow increases, glomerular capillary hydrostatic pressure increases so there will be more that is filtered in the plasma resulting to an increased urine formation, blood volume will decrease, venous return will decrease, cardiac output and arterial blood pressure will decrease. But the kidneys are one of the organs that have strongest autoregulatory mechanism so within the autoregulatory range, it will not readily increase the blood pressure, increase blood flow and increase urine formation. Renin-Angiotensin-Aldosterone System (RAAS) Inc. MCSFP Inc. VR Inc. CO Inc. ABP Dec. ABP When the blood pressure decreases, distending pressure of the vascular wall will decrease and that will cause recoil of the vascular wall. If the vascular wall recoils, vascular capacity decreases, so the venous return will increase, cardiac output (CO) will increase, increasing blood pressure to normal. Dec. RBF (+) JG cells Renin Angiotensinogen AI A II ACE Renal Fluid Volume Shift Remember that the most important function of the kidneys is excretion. It removes excess water as well as the products of metabolism away from the body by means of urine formation. PHOTO: The nephron and its component parts. 8 Shannen Kaye B. Apolinario, RMT | Another renal mechanism that will provide long term regulation of blood pressure is the renin-angiotensin-aldosterone system. So when the blood pressure decreases, renal blood flow decreases. This will now stimulate the juxtaglomerular cells in the nephron to secrete an enzyme renin. Renin will catalyse the activation of angiotensinogen to angiotensin I (AI). But angiotensin I is less vasoactive, it has to be converted to its more active form and that is angiotensin II (A II) and the reaction is catalysed by the enzyme angiotensin converting enzyme (ACE). PHOTO: Renal concentration. Actions of Angiotensin II *** Assignment: Read on special circulation A II VC (+) adrenals Inc. TPR aldosterone Inc. Na reabsorption DCT and CD Inc. ABP ADH Hypothalamus Inc. H2O reabsorption DCT and CD Inc. TBV Inc. VR and CO Inc. MCSFP What are the actions of angiotensin II? There are three. First, it is a potent vasoconstrictor substance. So there will be vasoconstriction (VC), increased total peripheral resistance (TPR), increased arterial blood pressure. Angiotensin II can stimulate the adrenal cortex to secrete aldosterone. Aldosterone is a hormone that acts on the distal convoluted tubule (DCT) and collecting ducts (CD) of the nephron to increase sodium reabsorption. If sodium will be reabsorbed, water follows so that will increase blood volume, venous return, cardiac output and arterial blood pressure. At the same time, angiotensin II can stimulate the hypothalamus to synthesize vasopressin or antidiuretic hormone (ADH). This will also act on distal convoluted tubule and collecting duct of the nephron to increase water reabsorption further increasing blood volume, venous return, cardiac output and blood pressure. But aside from increasing water reabsorption, antidiuretic hormone (ADH) or vasopressin can also cause vasoconstriction increasing the total peripheral resistance. In summary, there are three actions of angiotensin II: vasoconstriction, stimulate the adrenal gland to secrete aldosterone and stimulate the hypothalamus to synthesize antidiuretic hormone. Aldosterone’s action is to increase sodium reabsorption in the distal convoluted tubule and collecting duct. For antidiuretic hormone, there are two actions – increase water reabsorption in the distal convoluted tubule and collecting duct and vasoconstriction. PHOTO: Algorithm of the Renin-Angiotensin-Aldosterone System (RAAS) “ “For I know the plans I have for you,” declares the Lord, “plans to prosper you and not to harm you, plans to give you hope and a future. Then you will call upon me and come and pray to me, and I will listen to you. You will seek me and find me when you seek me with all your heart. I will be found by you,” declares the Lord.” -Jeremiah 29:11-14 GOD BLESS YOU ď 9 Shannen Kaye B. Apolinario, RMT | Vascular Physiology Part 1 –Dr. Olivar Circulatory System ----------------------------------------------------------------------------Main Function of Circulation: -Service the needs of tissues -Bring nutrients to the cell -Remove waste products -* maintain appropriate environment for optimum survival and functioning of cells Rate of blood flow into tissue -regulated by the need of tissue -if need of tissue is much (highly metabolic cell) = rate of blood flow is increased (vasodilatation) -if need of tissue is small-vasoconstriction: to redirect flow of blood to area which needs more blood -higher centers: help regulate cardiac output and circulation Review: Pathway of blood flow: Veins: converge to form 2 large veins (SVC and IVC) SVC- collects blood from head and extremities at level of heart IVC-collects blood from all structures below level of heart Both SVC and IVC empty to R atrium Blood from R atrium transmitted to R ventricle via Tricuspid valve Blood exits R ventricle to pulmonary artery via pulmonic valve-divides to R and L – to pulmonary capillaries (oxygenate blood) – empty to pulmonary vein to L atriumL ventricle Characteristics of the Vascular System 1. Aorta and large arteries -very elastic structure -contain large amount of elastin Elasticity: blood vessels expand when they receive blood and recoil back Purpose of elasticity: (at aorta) first sends blood back to L ventricle but it cannot flow back because aortic valve is closed; blood will go forward into systemic circulation -Elasticity is lost usually during old age. 2. Arterioles -amount of elastin is decreased; largely replaced by smooth muscles Smooth muscle: functions as sphincters- can regulate blood flow going into capillaries -Classified as resistance vessels 3. Capillaries -exchange area arteriolar end: filtration of nutrients and gas venular end: metabolic products go back to circulation -classified as exchange vessels Heart: 2 pumps connected in series Left side of heart: composed of L atrium connected to L ventricle by Mitral valve Contraction of L ventricle: pumps blood to systemic circulation Blood exits L ventricle via aortic valve into aorta (artery – carries blood away from heart and towards periphery) Aorta: divides to smaller arteries-arterioles-capillaries (where exchange of nutrients and gases occur) Capillaries merge to become venules-merge to become veins (veins-blood vessels that carry blood from periphery back/towards right side of heart) 4. Veins -diameter is larger than artery -more distensible (ability of blood vessels to expand) -contain more blood than arteries *How does blood go back to R side of heart if they are not elastic? They contain smooth muscles-contract and blood is transmitted back to heart. -contain valves 84% of blood- in systemic circulation 64% - veins 13% - arteries 7% - arterioles and capillaties 16% of blood: heart and lungs Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 1 Differences between series and parallel connection Aorta – arteries – arterioles: series Arterioles only: parallel Blood Flow -quantity/volume of blood passing through a specific point in circulatory system per minute All blood vessels are similar in structure EXCEPT capillaries: 3 layers 1. Tunica Intima -inner layer -single layer of endothelial cells 2. Tunica Media -middle layer -circular layer of smooth muscle -arteries have thicker T.m. than vein 3. Tunica adventitia -outer layer -elastin and collagen fibers -add structural integrity to veins and arteries Capillaries -only composed of single layer of endothelial cells Total Cardiac Output= 5000ml/min (CO=Stroke Volume x HR) -amount of blood pumped by aorta per minute Factors Determining Blood flow 1. Pressure Difference -pressure gradient/force pushing blood from point 1 to point 2 2. Vascular Resistance -impediment to blood flow Cause of resistance: as blood moves around vessel, it creates friction- the resistance to blood flow Summary: Blood Flow- could be Laminar or Turbulent HEMODYNAMICS AND MICROCIRCULATION Hemodynamics -study of the physical variables related to containment and movement of blood in CVS Laminar Flow -flows in streamline when blood is allowed to flow steadily in a smooth and long vessel -each layer of blood-same distance from vessel wall -velocity of blood layer at center is greater/faster than blood layer nearer to wall -layer closer to wall is barely moving; creates friction with vessel wall -blood flow creates parabolic profile Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 2 -happens when flow is steady and vessel is long and smooth Turbulent Flow -rate of flow is too rapid; with obstruction; vessel makes a sharp turn; rougher vessel -blood is along the vessels, crosswise; creates whirls/ eddy currents-adds to resistance; adds friction to vessel wall -tendency for turbulence can be predicted by knowing the Reynolds’ Number Velocity -speed by which blood flow is displaced Smaller x-sectional area=faster velocity Higher x-sectional area= slower velocity Peak velocity of aorta = fastest because it has smallest xsectional area Capillary velocity = slowest because x-sectional area is largest -slow because exchange of substance occurs here If rate is too high=Re increased=turbulent Big diameter=Re increased=turbulent Viscosity increased=Re decreased=laminar (Amount of Blood-determines Viscosity) Polycythemia=Re decreased-=laminar Anemia=Viscosity decreased=increased velocity=turbulent Physiological conditions causing turbulence: 1. Proximal part of aorta -velocity is high -turbulent flow 2. Carotid artery -turns sharply -turbulent Pathologic conditions causing turbulence: 1. Aortic stenosis -hindrance/obstruction -murmur-turbulent flow 2. Atherosclerosis -build-up of plaque along vessel walls -smoothness is disturbed -narrowed lumen Resistance -increased when: -vessel diameter is decreased -turbulent blood flow -can’t be measured directly -unit: PRU – peripheral resistance unit Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 3 *L side of the heart usually first to fail during heart failure Blood from L side can’t be pumped to systemic circulation, blood will go to lungs-Pulmonary Congestion. If lungs can’t contain blood-blood goes to R atriumR side starts to fail. *Systemic blood circulation has greater resistance than pulmonary circulation Conductance -a measure of blood flow through a vessel for a given pressure difference -reciprocal of resistance -diameter of vessel can change its conductance Pressure from artery to vein= 100 mmHG Blood flow/ Cardiac Output= 100 ml/sec PRU=1 Vasoconstriction (through sympathetic stimulation)=pressure increases; blood flow decreases; PRU increase to 4 Vasodilatation=pressure decreases; blood flow increases; PRU decrease to 0.2 Without sympathetic effect/stimulation, PRU=1 P at L atrium=2 mmHg P at Pulmonic Vein= 16 mmHg Difference= 14mmHg PRU=0.14 *PRU at Pulmonary Circulation is lower than at Systemic circulation *therefore, HIGHER resistance at the Systemic circulation! -Change in diameter is only slight, but increase of blood flow is tremendous. -In a vessel with large diameter, blood near the wall is barely moving, blood closer to the center moves faster. At the center blood moves very rapidly. *At smaller diameter vessels, central layer of blood does not exist. Only the layer of blood that is barely moving. Blood moves slower. Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 4 -explained by… (Pwaswis? Law :D) -blood flow is directly proportional to change in pressure and radius of vessel raised to 4th power and indirectly proportional to viscosity of blood and length of vessel -resistance is directly proportional to viscosity of blood and length of blood vessel and therefore indirectly prop to change in pressure and radius of vessel *Effect of arterial pressure to blood flow: P=50 mmHg; Blood flow=1 If P is increased to 100 mmHg (50% increase) Increase of blood flow is not from 1 to 2 If pressure is increased to 100, blood flow increases to 4 Not just an effect of the pressure *If pressure is increased in a vessel, pressure also distends diameter of vessel. Increased diameter, blood flow is increased raised to the 4th power. Tremendous increase in blood flow. Inhibit sympathetic stimulation= vasodilatation; higher blood flow; lower pressure Sympathetic stimulation =vasoconstriction; low blood flow; high pressure Transmural Pressure -pressure within a vessel whenever it is filled with blood Distensibility -ability of vessel to increase its volume whenever pressure is increased times original volume Example: *Increased Hct=increased viscosity -blood flow is decreased Artery- stronger because of elastin and collagen Vein- 8x more distensible than artery Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 5 -pressure within vessel tends to rip apart the vessel if not only for the opposing pressure brought about by the walls of arteries and veins. -opposing pressure of tendency of blood vessel to rapture-tension -in capillaries, vessels don’t rapture because radius is too small. Tension is lower. -thin walled vessels can withstand high pressure because of their small radius. Compliance > Distensibility Vein -8x more distensible, therefore could contain 3x more blood volume than artery -24x more compliant than artery Clinical Correlation (Effect of aging on vascular distensibility & compliance) -When ventricle contracts, aorta distends, but because of elasticity, blood recoils back. Even when ventricle is fully relaxed, there is forward flow of blood into capillaries. -When elasticity is lost, distensibility and compliance is decreased (in aging). When ventricle contracts, blood flow into capillaries, but it does not distend on ventricular systole because of lost elasticity, there is no recoiling. No flow of blood during ventricular diastole. -in older people- no blood flow to extremities/ peripheral blood vessels; Bluish discoloration; State of hypoxia. -Blood vessels (aorta) are rigid/not elastic. No flow during ventricular diastole. Healing is not good. Wound at hands/feet may progress to gangrene = decreased compliance and distensibility. -same with cardiac output (CO); blood that is pumped by the heart must go back to the right side of the heart. -veins do not recoil -Contraction of veins via smooth muscles-brings back blood to right side of heart -mean circulatory systemic filling pressure (MCSFP): pressure within the veins = 7mmHg -pressure inside atrium= 0mmHg, so blood from veins will just flow from veins to the atrium -Increased R atrial pressure (greater than MCSFP)-blood will not be able to drain into R atrium- this is what happens when L side of heart fails (blood can’t flow to systemic circulation-goes to back to lungs-goes back to R Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 6 side of heart= blood from S/IVC can’t flow to R atrium because pressure is higher) Congestive heart failure -jugular vein pulsates because blood would like to go down to the heart but goes back up again because pressure in R atrium is higher -blood draining from IVC goes back=increased venous pressure- extends to capillaries=Edema! CVP (central venous pressure)=0 mmHg Increased MCSFP- increased venous return Increased resistance to venous return- venous return decreases *If more blood is in venous circulation, mean systemic pressure increases (MCSFP) =venous return increases Increase venous compliance (distensibility)=decrease pressure=decrease venous return Increase venous tone (contract smooth blood vessel)=venous return increases Increase venous compliance=decreased venous return Increase blood volume=MSCFP increase=increase venous return R arterial pressure= 0mmHg normally Increaser resistance=Venous return decrease Decrease resistance=Venous return increase Pressure -generated on walls of the blood vessels (BP) - (BP) fluctuates because heart contracts and relaxes Example: BP= 120/80 Pulse Pressure= 40 Elevated SP (in elderly)-rigid aorta -blood vessels are constricted -aorta cannot distend -generate very high SP -DP is the same *if high SP and same (did not differ) = pulse pressure: greater than normal Profuse bleeding -decreased blood volume -SP decrease= pulse pressure is narrow Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 7 MAP -average pressure in arterial system measured over time -close to the DP -only composed of a single layer of endothelial cells -with small slits for filtration and reabsorption of substances Arterial Blood Pressure -increased stroke volume, heart rate= increase ABP Four Forces that Determine Fluid Movement in the Capillary Aorta -highest pressure because it receives blood directly from L ventricle Terminal Arterioles -biggest drop in the BP -arterioles can constrict/contract, allowing/not allowing blood to flow Venules, Small veins, VC’s -pressure is no longer significance because of compliance of veins Pulmonary Circulation -pressure is very small because of little resistance 1. Capillary Hydrostatic Pressure -try to push fluid into the interstitial space 2. Interstitial Fluid Pressure -prevent fluid from flowing into the interstitial space If Pif is POSITIVE= prevents fluid from flowing to interstitial space If Pif is NEGATIVE=attracts fluid into interstitial space Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 8 3. Plasma colloid osmotic pressure -primarily imparted by plasma proteins -holds on to fluid to remain inside blood vessel 4. Interstitial fluid colloid osmotic pressure -proteins in interstitial fluid will attract fluid into interstitial space How do you know if fluid will be filtered/reabsorbed in the capillaries? -compute net filtration pressure Filtration-arterial end Reabsorption-venous end Excess of 0.3mmHg -if it accumulates=edema -accumulation does not occur because of the lymphatics -if lymphatics is blocked= edema Conditions that will produce EDEMA: -anything that increases Capillary Hydrostatic Pressure (CHP) and decreases plasma capillary oncotic pressure (PCOP) Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 9 Lymphatics -all excess (0.3mmHg) will go to the lymphatic system, because the pressure between capillary and interstitial fluid will always be greater than the capillary. -direction of movement will always be to the capillary -Lymphatic vessels up to the point of thoracic duct- all capillaries drain into the thoracic duct and then to the venous system via- subclavian vein -if blocked-effect is accumulation in interstitial space=edema Burn Patients -increased capillary membrane permeability -proteins go to interstitial space -Edematous *When someone is standing still, because of force of gravity, the pressure in veins, supplying the feet = 99mmHg. If the person will not move, pressure within the vein will be greater than that of the capillary (20mmHg). If pressure of capillary is lower than in the veins, blood cannot drain into the venous systems=Edema. Normal Valve -unidirectional -prevent backflow of blood Abnormal Valve -vein is too distended -blood goes back to vein even when it closes *nutrients and oxygen will not be able to go to the cell; if not resolved, tissues will become necrotic and gangrenous Causes of increased interstitial volume and Edema -anything that increase CHP, decrease PCOP -anything that increase Capillary permeability -anything that can cause inadequacy in lymphatic flow Manuel, Marie Eleonor B. 1A-Medicine ‘18ď˝ Page 10 PHYSIOLOGY A – Vascular Physiology Pt.2 Dr. Olivar Adenosine INTRODUCTION Regulations in the Vascular System -Under Basal conditions, the blood flow to the different organs is different. Organ Brain Heart Bronchi Kidneys Liver Muscle(Inactive) Bone Skin(Cool Weather) Thyroid Gland Adrenal Gland Other Tissues TOTAL %cardiac output 14 4 2 22 27 15 5 6 1 0.5 3.3 100 ml/min 700 200 100 1100 1350 1050 300 750 50 25 175 5000 ml/min/g 50 70 25 360 95 4 3 3 160 300 1.3 b. Oxygen Theory/Nutrient Lack Theory – Oxygen and nutrients are required for the smooth muscles to contract. Therefore, the absence of oxygen would cause the smooth muscle to relax and dilate the vessel. We must then recall that dilation of blood vessels will cause an increase in blood th flow to the 4 power (Poiseuille’s Law) -Take note of the large amount of blood flow to the Kidneys (360ml/min/g), Adrenal Gland (300ml/min/g), and Thyroid Gland (160ml/min/g) -Take note of the very little blood flow to the Inactive Muscle (4ml/min/g) Question: Why is blood flow not always increased in every organ, in such a way that it would always be enough to meet the needs of the tissue whether the activity of it is less or great? Answer: It is simply because the heart is unable to handle that much more blood flow than normal. Studies have also shown that if blood is regulated in such a way (as presented in the table above), almost all tissue will not suffer from oxygen deprivation or nutrient deficiency, with the heart also kept at minimal workload. LECTURE OUTLINE I. Local and Humoral Control of Blood Flow II. Nervous Regulation of the Circulation and Arterial Pressure I.LOCAL AND HUMORAL CONTROL OF BLOOD FLOW A. LOCAL 1. Acute Control (Happens in seconds to minutes) a. Vasodilator Theory - If the rate of metabolism is increase, it is accompanied by an immediate increase in blood flow. This is because when a tissue is highly metabolic, it is excreting a lot of metabolites and by-products which cause the vessels to dilate. The most commonly associated byproduct is adenosine. JOSE ALFONSO A. ROQUE, 1E-MD 2014 Examples of Situations -this theory presents in people high altitude. Due to the low supply of oxygen, vessels are dilated and blood flow is increased to the organs. (People from Baguio with fair complexion have reddish cheeks) -In Carbon Monoxide Poisoning, the hemoglobin is more attached with carbon monoxide rather than CO2 and oxygen. Patients with this poisoning have severely low oxygen in blood vessels, which trigger massive vasodilation. These patients will therefore present with reddish skin all over the body. -Cyanide Poisoning is another condition which prevents o2 utilization (ETC). The ultimate effect is that oxygen perfusion to organs will decrease, and the vessels will dilate causing the reddish discoloration. Page 1 c.1 Reactive Hyperemia is appreciable when applying tourniquet. Blocking the blood for a prolonged period of time will cause a momentary hypoxia to the tissues initiating vessel dilation. Release of the tourniquet would then cause blood to flow back to the dilated vessels at a more rapid rate because of its dilation. This is a compensation of the blood oxygenation lost during the time of blockage. c.2 Active Hyperemia is similar to vasodilator theory. It states that when a muscle is at rest, the blood vessels are constricted, and when the muscle or tissue is active, the blood vessels will dilate. This is because of the metabolites that cause vasodilation. This explains why you are flushed whenever you are exercising. The same theory applies when the blood pressure is decreased. It causes the blood flow to decrease, and there will be less oxygen reaching the cells. The blood vessel then dilates and the blood flow returns to normal. ↓BP - ↓BF - ↓O2perfusion- Smooth Muscles Relaxation – Dilate Vessel – Regulate Blood Flow Autoregulation according to the Myogenic Theory is based on the observation that sudden stretch of small blood vessels causes the smooth muscle of the vessel wall to contract for a few seconds. Therefore, it has been proposed that when high blood pressure stretches the vessel, this in turn causes the wall to react by constricting. This reduces blood flow nearly back to normal. ↑BP – Momentary ↑BF - Sudden Stretch – Smooth Muscle Contraction – Regulate Blood Flow Conversely, at low pressures, the degree of stretch of the vessel is less, so that the smooth muscle relaxes and allows increased flow. ↓BP - ↓BF – Less Degree of Stretch - Smooth Muscle Relax – Regulate Blood Flow The importance of Autoregulation is evident in cases when the blood pressure is increased. When there is increased blood pressure, the capillaries will increase Hydrostatic Pressure causing increased filtration. GFR will also increase because it is triggered by the increase in blood pressure. Therefore whenever there is a rise in blood pressure, you will urinate. d. Autoregulation Autoregulation is defined as the Capability of the blood vessels to maintain normal blood flow despite fluctuations in the blood pressure. In any tissue of the body, an acute increase in arterial pressure causes immediate rise in blood flow. But, within less than a minute, the blood flow in most tissues returns almost to the normal level, even though the arterial pressure is kept elevated. This return of flow toward normal is called autoregulation of blood flow. When the blood pressure increases, the blood vessel will dilate. Therefore, the blood flow increases as well. The oxygen delivered to the tissue will increase and this will cause the smooth muscles to contract. The blood flow ultimately returns to normal. This is termed as Autoregulatiion according to the Metabolic Theory. ↑BP - ↑BF - ↑O2perfusion – Smooth Muscle contraction – Contract Vessel – Regulate Blood Flow JOSE ALFONSO A. ROQUE, 1E-MD 2014 Between 75-175mmHg, the blood flow is regulated 2. Long Term Control(Days to Months,but more complete) a. Increased Tissue Vascularity When requirement of oxygenation is high for a prolonged period of time, the number of blood vessels in the tissue will actually increase. On the other hand, if oxygenation requirement is low, some blood vessels will disappear, or will not form any more. Page 2 When there is bacterial infection in the bone, this will require longer time for healing. This also requires prolonged metabolic process and therefore requires more oxygen perfusion. Blood vessels will therefore start to increase in the sites of the bone that are infected. This continues until the bone is healed, at which point we notice that the blood vessels will also disappear from the previous sites of infection. Recap: A. Local 1. Acute Control (Happens in seconds to minutes) a. Vasodilator Theory b. Oxygen Theory/ Nutrient Lack Theory c. Reactive and Active Hyperemia d. Autoregulation (Metabolic & Myogenic) 2. Long Term Control (Days to Months, but more complete) a. Increased Tissue Vascularity b. Formation of Collateral Circulation B. Humoral 1. Vasoconstrictors Long term control is also seen in babies born prematurely. These babies lack surfactant which is essential for proper ventilation. An immediate management is to give high dose oxygen. This can act on the retina of the babies’ eyes, preventing blood vessels from forming, or even degenerating formed blood vessels. Upon cessation of the high dose O2 (When the baby can now ventilate on its own), there will be an overcompensated perfusion of blood in the retina which can reach up to the vitreous humor of the eye (Retrolental Fibroplasia, or in this case Retinopathy of Prematurity). Ultimately, this can cause blindness. Agent Norepinephrine (more potent) and Epinephrine Angiotensin ll Where Produced -from the Sympathetic Nerve Endings or Adrenal Medulla) Vasopressin (ADH; potent vasoconstrictor) Endothelin produced by the hypothalamus, and stored in the posterior pituitary -component in the RAAS (renin angiotensin aldosterone system) -Produced in the endothelial cells of blood vessels Serotonin 2. Vasodilators Agent Bradykinin Histamine b. Formation of collateral circulation When an artery or a vein is blocked in virtually any tissue of the body, a new vascular channel usually develops around the blockage and allows at least partial resupply of blood to the affected tissue. The most important example of the development of collateral blood vessels occurs after thrombosis of one of the coronary arteries. Almost all people by the age of 60 years have had at least one of the smaller branch coronary vessels close. Yet most people do not know that this has happened because collaterals have developed rapidly enough to prevent myocardial damage. Where Produced released by mast cells, basophils Effect of Ions & Other Chemical Factors Ion Effect Calcium Vasoconstriction Potassium Vasodilatation Mmagnesium Vasodilatation H+ Vasodilatation Carbon Dioxide Vasodilatation * no need for a recap.. ď II. NERVOUS REGULATION OF THE CIRCULATION AND ARTERIAL PRESSURE -Regulation that is confined in the autonomic nervous system, specifically the sympathetic nervous system (Vasoconstriction). JOSE ALFONSO A. ROQUE, 1E-MD 2014 Page 3 Sympathetic Vasoconstriction Sympathetic vasomotor nerve fibers that leave the spinal cord immediately pass through the sympathetic chain, and the sympathetic nerves pass to supply the heart as well as the peripheral vessels. The sympathetic nerves supply all vessels except the capillaries and the metaarterioles. The effect of sympathetic stimulation on the arteries and arterioles is constriction, thus regulating blood flow to the capillaries. The effect of sympathetic stimulation on the veins and venules is increase in vasomotor tone, also constricting veins. Remember that the veins are more compliant than the arteries. They propel blood when the smooth muscles contract. Therefore when the venous tone increases, the veins will cause the blood to flow back to the right side of the heart. Vasomotor Center It is located bilaterally in the reticular substance of the medulla in the lower third of the pons. These centers send sympathetic impulses to the heart and to the blood vessels. They also send parasympathetic impulses but only to the heart, not the blood vessels. Sympathetic Heart - ↑Heart Rate (Pulse Rate) Blood Vessels – Vasoconstriction Parasympathetic Heart - ↑ Heart Rate Blood Vessels – there is no parasympathetic supply to the BV The reason why there is no parasympathetic vasodilation in the blood vessels is because the main mechanism of causing vasodilation is when the Sympathetic impulse is shut off. A blood vessel at rest is dilated, and the only reason why it is constricted is because of the effect of the sympathetic impulse. JOSE ALFONSO A. ROQUE, 1E-MD 2014 The Vasoconstrictor Area once again is responsible for sending impulses that cause vasoconstriction to the blood vessels and increase the heart rate of the heart. The Vasodilator Area inhibits the vasoconstrictor area thus causing vasodilation. A sensory area (The third center) located bilaterally in the tractus solitarius in the posterolateral portions of the medulla and lower pons. The neurons of this area receive sensory nerve signals from the circulatory system mainly through the vagus and glossopharyngeal nerves, and output signals from this sensory area then help to control activities of both the vasoconstrictor and vasodilator areas of the vasomotor center, thus providing “reflex” control of many circulatory functions. An example is the baroreceptor reflex for controlling arterial pressure. To clarify, the impulse received by the sensory area in the tractus solitarius will affect the activity of either the vasoconstrictor area or the vasomotor area. ARTERIAL PRESSURE (BP) CONTROL MECHANISMS Acting within seconds or minutes or days 1. Baroreceptor feedback mechanism 2. Chemoreceptor mechanism 3. Central nervous system ischemic mechanism 4. Low pressure receptor mechanism Acting after many minutes or hours 1. Stress- relaxation mechanism 2. Capillary fluid shift 3. Renal fluid shift Acting after several hours 1. Renin –angiotensin –aldosterone system (RAAS) ACTING WITHIN SECONDS OR MINUTES OR DAYS 1. BARORECEPTOR REFLEX To understand the BR, we must first recall the parts of the reflex arc: Receptor (Baroreceptor) – the area that receives the stimulus Sensory Neuron – sends signal from the receptor to the center Center (in the Tractus Solitaries) – analyzes the impulse and gives it off towards the motor neuron Motor Neuron – receives impulse from the Center Effector – where impulse Page 4 This can also happen the other way around… The Baroreceptors are located in the Aortic Arch or Carotid Sinuses. They are stretched receptors, meaning that they are stimulated when they are stretched. The increase in blood pressure causes this stretch. The sensory neurons can either be the Glossopharyngeal Nerve for the Carrotid Sinus or the Vagus Nerve for the Aortic Arch. The Center is the Tractus Solitarius at the Vasomotor Center, and the efferent neurons could either be the parasympathetic fibers or the sympathetic fibers. The effectors could either be the heart of the blood vessels. Baroreceptors ( Carotid sinus & Aortic Arch) ↓ Glossopharyngeal and Vagus Nerve ↓ Vasomotor Center ↓ Sympa/Parasympathetic Fibers ↓ Heart and Blood Vessels Among the two receptors, the Carotid Baroreceptors have the wider range of response. This means that the Aortic Arch only responds to high pressure, whereas the Carotid Baroreceptors can be stimulated even if the pressure is not that high. Scenario 1: Your Physiology Professor suddenly enters the room to announce that there will be an examination in a few minutes. This caused you to have a sudden increase in blood pressure. This causes the stretch of the Baroreceptor. This stretch initiates them to send impulse towards the Center. Aortic Arch sends through the Vagus and the Carotid Sinuses through the Glossopharyngeal Nerve. Your Tractus Solitarius recognizes the sudden increase in blood pressure and acts by shutting of your sympathetic nervous system. This parasympathetic impulse is sent off using the efferent neurons towards the Heart. This causes the heart rate to decrease. Without any stimulation going to the blood vessels, they will dilate. So the pressure decreases. JOSE ALFONSO A. ROQUE, 1E-MD 2014 Scenario 2: A medical student who had an examination at 7 am woke up at 7:15 am. Startled, he suddenly stood up from bed. This caused a sudden pooling of blood in the lower extremities due to gravity (Orthostatic Hypotension). The abrupt pooling of blood in the lower extremities doesn’t really stretch any baroreceptor response because they are located away from the lower extremities. This then causes the sympathetic nervous system to predominate. This then causes the heart rate to increase, and the vessels to constrict, allowing increase in blood pressure. ↑BP causes Baroreceptor reflex to shut off the SNS and to cause PSNS reflexes to go to the heart. ↓BP causes the Baroreceptor reflex to shut off, making the SNS to predominate and therefore cause ↑BP. 2. CHEMORECEPTOR MECHANISM This mechanism is similar with the Baroreceptor Reflex. The receptors are located in the Aortic Arch and Carotid Sinus as well. They also have the same nerve fibers involved. The only difference is that these receptors do not respond to pressure changes, but rather to chemical changes such as oxygen saturation. This means that when the Blood Pressure decreases, the pO2 (Oxygen Saturation of blood) also decreases. This change in saturation triggers the receptors, stimulating the vasomotor center, then causing the increase in heart rate of the heart, and thus bringing the blood pressure higher to increase Blood pressure. ↓BP - ↓pO2 – Stimulate Receptors – Afferent Neurons – Vasomotor Center –sympathetic impulse is sent to the heart - efferent neurons – ↑BP 3. CENTRAL NERVOUS SYSTEM ISCHEMIC MECHANISM This mechanism only occurs when the blood flow to the brain is very low. When your blood volume decreases (Bleeding), your blood pressure is decreased. The priority organ that needs blood supply will be the brain. So for the brain to actually have decreased blood supply, the patient would have to be severely hypovolemic (Severely low amount of blood). Korotkoff sounds cannot be heard on auscultation due to the severely low blood levels, and must be taken palpatory. When the blood oxygen is decreased, there is ischemia to the brain. This causes carbon dioxide to accumulate, causing strong stimulation of the vasomotor center. This causes an excessively strong impulse from the vasomotor center to the heart which can elevate the blood pressure to 200/120’s or higher, but only for a short time. *Palpatory blood pressure is done using the sphygmomanometer only. Instead of using a stethoscope to hear the Korotkoff sounds, you will palpate the vein and feel for the BP. Page 5 ↓↓ BF to the brain – Ischemia - ↑pCO2 – ↑↑Vasomotor Stimulation - ↑↑Sympathetic Stimulation to Heart - ↑↑BP Cushing’s Reaction Occurs when the Intracerebral pressure (ICP) is more than the arterial Blood Pressure. This occurs when there is an accumulation of cerebrospinal fluid in the Cranium. When the ICP increases, the cerebral arteries are compressed, preventing flow of oxygen into the brain. This is then followed by the same events of the CNS Ischemic Response ACTING AFTER MANY MINUTES OR HOURS 1. STRESS-RELAXATION MECHANISM To better understand this concept, we must first recall MCSFP On the other hand, if the blood pressure is decreased, the capillary hydrostatic pressure is decreased and the oncotic pressure is greater than the hydrostatic pressure. Reabsorption is favored and fluid enters the intravascular space, increasing blood volume, increasing blood pressure. ↓BP - ↑OP – Reabsorption - ↑BV - ↑BP Brief Orientation about Renal Physiology Kidneys function to filter blood, and the filtrate becomes the urine. The kidneys are bilaterally located on each side of the aorta. The renal artery is a major branch of the Aorta that supplies the kidneys. VR = MCSFP – CVP R MCSFP - Mean Circulatory or Systemic Filling Pressure *If you stop the heart from pumping, it will give off a value of 70mmHg. This is the MCSFP. CVP - Central Venous Pressure *CVP is normally 0; this is the pressure in the right atrium R - Resistance to Venous Return (Compliance) ↑Blood Flow = ↑ MCFSP ↑MCFSP = ↑Venous Return ↑ Blood Flow = ↑Venous Return ↑Compliance = ↓ MCFSP ↑Compliance = ↓Venous Return This occurs when a decrease in Arterial Blood Pressure (ABP) no longer distends the arteries. Therefore, their compliance is decreased. If the compliance is decreased, the Mean Circulatory Systemic Filling Pressure (MCSFP) increases. If the MCSFP is increased, Venous Return (VR) is also increased. So if the pressure is decreased, the vessel failed to distend and the compliance is decreased, then the MCSFP increases, causing also an increase in venous return. The increase in venous return causes an increase in End Diastolic Volume (EDV). According to Frank Starling’s Law, when EDV is increased within physiologic limits, the force of ventricular contraction will also be great. This causes the cardiac output to increase, and ultimately the blood pressure is also increased. These arteries divide into several small arterioles until they become the afferent arterioles, the smallest branch of the renal artery. These terminate into the renal glomerulus which is where filtration occurs. When filtration has undergone in the glomerulus, the filtrate is then called glomerular filtrate. The filtrate then travels to the nephron until it reaches the ureter to become the urine. ↓ABP - ↓Distending Pressure - ↓Vascular Capacity - ↑MCSFP - ↑VR - ↑ CO - ↑ABP 2. CAPILLARY FLUID SHIFT When blood pressure is increased, the hydrostatic pressure increases. This favors filtration and fluid goes to the interstitial spaces. The blood volume therefore decreases, causing the blood pressure to decrease. Also take note that the distal tubule of the nephron abuts the afferent arteriole. ↑BP - ↑HP – Filtration - ↓BV - ↓BP JOSE ALFONSO A. ROQUE, 1E-MD 2014 Page 6 3. RENAL FLUID SHIFT When the arterial blood pressure is decreased, the blood flow to renal artery will also be decreased. This means that there will be decreased blood flowing to the afferent arteriole causing a decreased in glomerular filtrates, or urine. This means that you are preserving your blood volume which increases venous return, thus also increasing cardiac output and overall blood pressure. This is evident in patients with decreased blood volume (Bleeders). An initial symptom in them is decreased or absent urine. This is because the afferent arterioles are closed. This serves the function to maintain blood volume so that blood can reach the more important organs. When the volume has already been corrected and the pressure has risen back to normal, the first sign to assess for will be urination. This will signify the start of improvement in the circulation of the patient. The afferent arterioles have already dilated, and blood is being filtered. -Can stimulate the hypothalamus to release Vasopressin (ADH). It is a potent vasoconstrictor and can also promote water reabsorption in the distal tubule of the kidney. The overall effect is to increase blood volume, therefore increasing venous return. This also means increase in cardiac output and finally leading to an increase in blood pressure. AII – Hypothalamus – ADH - ↑H2O reabsorption in DCT & CD - ↑BV - ↑MCSFP - ↑VR & CO - ↑BP In some adults with Chronic Hypertension, there is an increase in angiotensin II. We manage this by giving Ace Inhibitors which prevent conversion of angiotensin I to angiotensin II. Finally, a summary of RAAS… ↓BP - ↓Renal Blood Flow – Glomerular Capillary HP ↓Filtration - ↓Urine Formation – Preserved Blood Volume – Improve VR and CO - ↑BP This also explains why the more you drink fluids, the more you urinate. Increased fluid intake causes increased blood volume, thus increasing blood pressure. This causing increased renal blood flow, causing increased filtration. Therefore, urine production is increased. ACTING AFTER SEVERAL HOURS 1. RENIN–ANGIOTENSIN–ALDOSTERONE SYSTEM (RAAS) This is the most important control of long term regulation of blood pressure. Remember that the distal tubule of the nephron abuts the afferent arteriole. This is important because a special structure called Macula Densa found in the distal tubule. This structure can detect the Sodium content of the filtrate. If the amount of filtrate is low (↓BP), the amount of sodium delivered in the Macula Densa is also low and this causes the JG cells found at the afferent arterioles to secrete Renin. Renin functions by converting the protein Angiotensinogen to Angiotensin I. Angiotensin I is converted to Angiotensin II (potent vasoconstrictor) in the lungs by the enzyme Angiotensin Converting Enyzme (ACE). ↓BP - ↓NA in Renal Blood Flow - Alert JG Cells Release Renin - Converts Angiotensinogen to Angiotensin I - ACE - Converted to Angiotensin II Functions of Angiotensin II -Increases total peripheral resistance, bringing the BP up back to normal AII - ↑TPR - ↑BP -Can stimulate the Adrenal Cortex to release Aldosterone, a steroid hormone that promotes sodium absorption in the tubules of the kidney. Where sodium goes, water goes. Therefore the blood pressure goes back to normal. AII-↑Aldosterone - ↑Sodium Reabsortion in DCT & CD -↑BP JOSE ALFONSO A. ROQUE, 1E-MD 2014 God Bless Us All ď Page 7 PHYSIOLOGY A – Vascular Physiology Pt.2 Dr. Olivar Adenosine INTRODUCTION Regulations in the Vascular System -Under Basal conditions, the blood flow to the different organs is different. Organ Brain Heart Bronchi Kidneys Liver Muscle(Inactive) Bone Skin(Cool Weather) Thyroid Gland Adrenal Gland Other Tissues TOTAL %cardiac output 14 4 2 22 27 15 5 6 1 0.5 3.3 100 ml/min 700 200 100 1100 1350 1050 300 750 50 25 175 5000 ml/min/g 50 70 25 360 95 4 3 3 160 300 1.3 b. Oxygen Theory/Nutrient Lack Theory – Oxygen and nutrients are required for the smooth muscles to contract. Therefore, the absence of oxygen would cause the smooth muscle to relax and dilate the vessel. We must then recall that dilation of blood vessels will cause an increase in blood th flow to the 4 power (Poiseuille’s Law) -Take note of the large amount of blood flow to the Kidneys (360ml/min/g), Adrenal Gland (300ml/min/g), and Thyroid Gland (160ml/min/g) -Take note of the very little blood flow to the Inactive Muscle (4ml/min/g) Question: Why is blood flow not always increased in every organ, in such a way that it would always be enough to meet the needs of the tissue whether the activity of it is less or great? Answer: It is simply because the heart is unable to handle that much more blood flow than normal. Studies have also shown that if blood is regulated in such a way (as presented in the table above), almost all tissue will not suffer from oxygen deprivation or nutrient deficiency, with the heart also kept at minimal workload. LECTURE OUTLINE I. Local and Humoral Control of Blood Flow II. Nervous Regulation of the Circulation and Arterial Pressure I.LOCAL AND HUMORAL CONTROL OF BLOOD FLOW A. LOCAL 1. Acute Control (Happens in seconds to minutes) a. Vasodilator Theory - If the rate of metabolism is increase, it is accompanied by an immediate increase in blood flow. This is because when a tissue is highly metabolic, it is excreting a lot of metabolites and by-products which cause the vessels to dilate. The most commonly associated byproduct is adenosine. JOSE ALFONSO A. ROQUE, 1E-MD 2014 Examples of Situations -this theory presents in people high altitude. Due to the low supply of oxygen, vessels are dilated and blood flow is increased to the organs. (People from Baguio with fair complexion have reddish cheeks) -In Carbon Monoxide Poisoning, the hemoglobin is more attached with carbon monoxide rather than CO2 and oxygen. Patients with this poisoning have severely low oxygen in blood vessels, which trigger massive vasodilation. These patients will therefore present with reddish skin all over the body. -Cyanide Poisoning is another condition which prevents o2 utilization (ETC). The ultimate effect is that oxygen perfusion to organs will decrease, and the vessels will dilate causing the reddish discoloration. Page 1 c.1 Reactive Hyperemia is appreciable when applying tourniquet. Blocking the blood for a prolonged period of time will cause a momentary hypoxia to the tissues initiating vessel dilation. Release of the tourniquet would then cause blood to flow back to the dilated vessels at a more rapid rate because of its dilation. This is a compensation of the blood oxygenation lost during the time of blockage. c.2 Active Hyperemia is similar to vasodilator theory. It states that when a muscle is at rest, the blood vessels are constricted, and when the muscle or tissue is active, the blood vessels will dilate. This is because of the metabolites that cause vasodilation. This explains why you are flushed whenever you are exercising. The same theory applies when the blood pressure is decreased. It causes the blood flow to decrease, and there will be less oxygen reaching the cells. The blood vessel then dilates and the blood flow returns to normal. ↓BP - ↓BF - ↓O2perfusion- Smooth Muscles Relaxation – Dilate Vessel – Regulate Blood Flow Autoregulation according to the Myogenic Theory is based on the observation that sudden stretch of small blood vessels causes the smooth muscle of the vessel wall to contract for a few seconds. Therefore, it has been proposed that when high blood pressure stretches the vessel, this in turn causes the wall to react by constricting. This reduces blood flow nearly back to normal. ↑BP – Momentary ↑BF - Sudden Stretch – Smooth Muscle Contraction – Regulate Blood Flow Conversely, at low pressures, the degree of stretch of the vessel is less, so that the smooth muscle relaxes and allows increased flow. ↓BP - ↓BF – Less Degree of Stretch - Smooth Muscle Relax – Regulate Blood Flow The importance of Autoregulation is evident in cases when the blood pressure is increased. When there is increased blood pressure, the capillaries will increase Hydrostatic Pressure causing increased filtration. GFR will also increase because it is triggered by the increase in blood pressure. Therefore whenever there is a rise in blood pressure, you will urinate. d. Autoregulation Autoregulation is defined as the Capability of the blood vessels to maintain normal blood flow despite fluctuations in the blood pressure. In any tissue of the body, an acute increase in arterial pressure causes immediate rise in blood flow. But, within less than a minute, the blood flow in most tissues returns almost to the normal level, even though the arterial pressure is kept elevated. This return of flow toward normal is called autoregulation of blood flow. When the blood pressure increases, the blood vessel will dilate. Therefore, the blood flow increases as well. The oxygen delivered to the tissue will increase and this will cause the smooth muscles to contract. The blood flow ultimately returns to normal. This is termed as Autoregulatiion according to the Metabolic Theory. ↑BP - ↑BF - ↑O2perfusion – Smooth Muscle contraction – Contract Vessel – Regulate Blood Flow JOSE ALFONSO A. ROQUE, 1E-MD 2014 Between 75-175mmHg, the blood flow is regulated 2. Long Term Control(Days to Months,but more complete) a. Increased Tissue Vascularity When requirement of oxygenation is high for a prolonged period of time, the number of blood vessels in the tissue will actually increase. On the other hand, if oxygenation requirement is low, some blood vessels will disappear, or will not form any more. Page 2 When there is bacterial infection in the bone, this will require longer time for healing. This also requires prolonged metabolic process and therefore requires more oxygen perfusion. Blood vessels will therefore start to increase in the sites of the bone that are infected. This continues until the bone is healed, at which point we notice that the blood vessels will also disappear from the previous sites of infection. Recap: A. Local 1. Acute Control (Happens in seconds to minutes) a. Vasodilator Theory b. Oxygen Theory/ Nutrient Lack Theory c. Reactive and Active Hyperemia d. Autoregulation (Metabolic & Myogenic) 2. Long Term Control (Days to Months, but more complete) a. Increased Tissue Vascularity b. Formation of Collateral Circulation B. Humoral 1. Vasoconstrictors Long term control is also seen in babies born prematurely. These babies lack surfactant which is essential for proper ventilation. An immediate management is to give high dose oxygen. This can act on the retina of the babies’ eyes, preventing blood vessels from forming, or even degenerating formed blood vessels. Upon cessation of the high dose O2 (When the baby can now ventilate on its own), there will be an overcompensated perfusion of blood in the retina which can reach up to the vitreous humor of the eye (Retrolental Fibroplasia, or in this case Retinopathy of Prematurity). Ultimately, this can cause blindness. Agent Norepinephrine (more potent) and Epinephrine Angiotensin ll Where Produced -from the Sympathetic Nerve Endings or Adrenal Medulla) Vasopressin (ADH; potent vasoconstrictor) Endothelin produced by the hypothalamus, and stored in the posterior pituitary -component in the RAAS (renin angiotensin aldosterone system) -Produced in the endothelial cells of blood vessels Serotonin 2. Vasodilators Agent Bradykinin Histamine b. Formation of collateral circulation When an artery or a vein is blocked in virtually any tissue of the body, a new vascular channel usually develops around the blockage and allows at least partial resupply of blood to the affected tissue. The most important example of the development of collateral blood vessels occurs after thrombosis of one of the coronary arteries. Almost all people by the age of 60 years have had at least one of the smaller branch coronary vessels close. Yet most people do not know that this has happened because collaterals have developed rapidly enough to prevent myocardial damage. Where Produced released by mast cells, basophils Effect of Ions & Other Chemical Factors Ion Effect Calcium Vasoconstriction Potassium Vasodilatation Mmagnesium Vasodilatation H+ Vasodilatation Carbon Dioxide Vasodilatation * no need for a recap.. ď II. NERVOUS REGULATION OF THE CIRCULATION AND ARTERIAL PRESSURE -Regulation that is confined in the autonomic nervous system, specifically the sympathetic nervous system (Vasoconstriction). JOSE ALFONSO A. ROQUE, 1E-MD 2014 Page 3 Sympathetic Vasoconstriction Sympathetic vasomotor nerve fibers that leave the spinal cord immediately pass through the sympathetic chain, and the sympathetic nerves pass to supply the heart as well as the peripheral vessels. The sympathetic nerves supply all vessels except the capillaries and the metaarterioles. The effect of sympathetic stimulation on the arteries and arterioles is constriction, thus regulating blood flow to the capillaries. The effect of sympathetic stimulation on the veins and venules is increase in vasomotor tone, also constricting veins. Remember that the veins are more compliant than the arteries. They propel blood when the smooth muscles contract. Therefore when the venous tone increases, the veins will cause the blood to flow back to the right side of the heart. Vasomotor Center It is located bilaterally in the reticular substance of the medulla in the lower third of the pons. These centers send sympathetic impulses to the heart and to the blood vessels. They also send parasympathetic impulses but only to the heart, not the blood vessels. Sympathetic Heart - ↑Heart Rate (Pulse Rate) Blood Vessels – Vasoconstriction Parasympathetic Heart - ↑ Heart Rate Blood Vessels – there is no parasympathetic supply to the BV The reason why there is no parasympathetic vasodilation in the blood vessels is because the main mechanism of causing vasodilation is when the Sympathetic impulse is shut off. A blood vessel at rest is dilated, and the only reason why it is constricted is because of the effect of the sympathetic impulse. JOSE ALFONSO A. ROQUE, 1E-MD 2014 The Vasoconstrictor Area once again is responsible for sending impulses that cause vasoconstriction to the blood vessels and increase the heart rate of the heart. The Vasodilator Area inhibits the vasoconstrictor area thus causing vasodilation. A sensory area (The third center) located bilaterally in the tractus solitarius in the posterolateral portions of the medulla and lower pons. The neurons of this area receive sensory nerve signals from the circulatory system mainly through the vagus and glossopharyngeal nerves, and output signals from this sensory area then help to control activities of both the vasoconstrictor and vasodilator areas of the vasomotor center, thus providing “reflex” control of many circulatory functions. An example is the baroreceptor reflex for controlling arterial pressure. To clarify, the impulse received by the sensory area in the tractus solitarius will affect the activity of either the vasoconstrictor area or the vasomotor area. ARTERIAL PRESSURE (BP) CONTROL MECHANISMS Acting within seconds or minutes or days 1. Baroreceptor feedback mechanism 2. Chemoreceptor mechanism 3. Central nervous system ischemic mechanism 4. Low pressure receptor mechanism Acting after many minutes or hours 1. Stress- relaxation mechanism 2. Capillary fluid shift 3. Renal fluid shift Acting after several hours 1. Renin –angiotensin –aldosterone system (RAAS) ACTING WITHIN SECONDS OR MINUTES OR DAYS 1. BARORECEPTOR REFLEX To understand the BR, we must first recall the parts of the reflex arc: Receptor (Baroreceptor) – the area that receives the stimulus Sensory Neuron – sends signal from the receptor to the center Center (in the Tractus Solitaries) – analyzes the impulse and gives it off towards the motor neuron Motor Neuron – receives impulse from the Center Effector – where impulse Page 4 This can also happen the other way around… The Baroreceptors are located in the Aortic Arch or Carotid Sinuses. They are stretched receptors, meaning that they are stimulated when they are stretched. The increase in blood pressure causes this stretch. The sensory neurons can either be the Glossopharyngeal Nerve for the Carrotid Sinus or the Vagus Nerve for the Aortic Arch. The Center is the Tractus Solitarius at the Vasomotor Center, and the efferent neurons could either be the parasympathetic fibers or the sympathetic fibers. The effectors could either be the heart of the blood vessels. Baroreceptors ( Carotid sinus & Aortic Arch) ↓ Glossopharyngeal and Vagus Nerve ↓ Vasomotor Center ↓ Sympa/Parasympathetic Fibers ↓ Heart and Blood Vessels Among the two receptors, the Carotid Baroreceptors have the wider range of response. This means that the Aortic Arch only responds to high pressure, whereas the Carotid Baroreceptors can be stimulated even if the pressure is not that high. Scenario 1: Your Physiology Professor suddenly enters the room to announce that there will be an examination in a few minutes. This caused you to have a sudden increase in blood pressure. This causes the stretch of the Baroreceptor. This stretch initiates them to send impulse towards the Center. Aortic Arch sends through the Vagus and the Carotid Sinuses through the Glossopharyngeal Nerve. Your Tractus Solitarius recognizes the sudden increase in blood pressure and acts by shutting of your sympathetic nervous system. This parasympathetic impulse is sent off using the efferent neurons towards the Heart. This causes the heart rate to decrease. Without any stimulation going to the blood vessels, they will dilate. So the pressure decreases. JOSE ALFONSO A. ROQUE, 1E-MD 2014 Scenario 2: A medical student who had an examination at 7 am woke up at 7:15 am. Startled, he suddenly stood up from bed. This caused a sudden pooling of blood in the lower extremities due to gravity (Orthostatic Hypotension). The abrupt pooling of blood in the lower extremities doesn’t really stretch any baroreceptor response because they are located away from the lower extremities. This then causes the sympathetic nervous system to predominate. This then causes the heart rate to increase, and the vessels to constrict, allowing increase in blood pressure. ↑BP causes Baroreceptor reflex to shut off the SNS and to cause PSNS reflexes to go to the heart. ↓BP causes the Baroreceptor reflex to shut off, making the SNS to predominate and therefore cause ↑BP. 2. CHEMORECEPTOR MECHANISM This mechanism is similar with the Baroreceptor Reflex. The receptors are located in the Aortic Arch and Carotid Sinus as well. They also have the same nerve fibers involved. The only difference is that these receptors do not respond to pressure changes, but rather to chemical changes such as oxygen saturation. This means that when the Blood Pressure decreases, the pO2 (Oxygen Saturation of blood) also decreases. This change in saturation triggers the receptors, stimulating the vasomotor center, then causing the increase in heart rate of the heart, and thus bringing the blood pressure higher to increase Blood pressure. ↓BP - ↓pO2 – Stimulate Receptors – Afferent Neurons – Vasomotor Center –sympathetic impulse is sent to the heart - efferent neurons – ↑BP 3. CENTRAL NERVOUS SYSTEM ISCHEMIC MECHANISM This mechanism only occurs when the blood flow to the brain is very low. When your blood volume decreases (Bleeding), your blood pressure is decreased. The priority organ that needs blood supply will be the brain. So for the brain to actually have decreased blood supply, the patient would have to be severely hypovolemic (Severely low amount of blood). Korotkoff sounds cannot be heard on auscultation due to the severely low blood levels, and must be taken palpatory. When the blood oxygen is decreased, there is ischemia to the brain. This causes carbon dioxide to accumulate, causing strong stimulation of the vasomotor center. This causes an excessively strong impulse from the vasomotor center to the heart which can elevate the blood pressure to 200/120’s or higher, but only for a short time. *Palpatory blood pressure is done using the sphygmomanometer only. Instead of using a stethoscope to hear the Korotkoff sounds, you will palpate the vein and feel for the BP. Page 5 ↓↓ BF to the brain – Ischemia - ↑pCO2 – ↑↑Vasomotor Stimulation - ↑↑Sympathetic Stimulation to Heart - ↑↑BP Cushing’s Reaction Occurs when the Intracerebral pressure (ICP) is more than the arterial Blood Pressure. This occurs when there is an accumulation of cerebrospinal fluid in the Cranium. When the ICP increases, the cerebral arteries are compressed, preventing flow of oxygen into the brain. This is then followed by the same events of the CNS Ischemic Response ACTING AFTER MANY MINUTES OR HOURS 1. STRESS-RELAXATION MECHANISM To better understand this concept, we must first recall MCSFP On the other hand, if the blood pressure is decreased, the capillary hydrostatic pressure is decreased and the oncotic pressure is greater than the hydrostatic pressure. Reabsorption is favored and fluid enters the intravascular space, increasing blood volume, increasing blood pressure. ↓BP - ↑OP – Reabsorption - ↑BV - ↑BP Brief Orientation about Renal Physiology Kidneys function to filter blood, and the filtrate becomes the urine. The kidneys are bilaterally located on each side of the aorta. The renal artery is a major branch of the Aorta that supplies the kidneys. VR = MCSFP – CVP R MCSFP - Mean Circulatory or Systemic Filling Pressure *If you stop the heart from pumping, it will give off a value of 70mmHg. This is the MCSFP. CVP - Central Venous Pressure *CVP is normally 0; this is the pressure in the right atrium R - Resistance to Venous Return (Compliance) ↑Blood Flow = ↑ MCFSP ↑MCFSP = ↑Venous Return ↑ Blood Flow = ↑Venous Return ↑Compliance = ↓ MCFSP ↑Compliance = ↓Venous Return This occurs when a decrease in Arterial Blood Pressure (ABP) no longer distends the arteries. Therefore, their compliance is decreased. If the compliance is decreased, the Mean Circulatory Systemic Filling Pressure (MCSFP) increases. If the MCSFP is increased, Venous Return (VR) is also increased. So if the pressure is decreased, the vessel failed to distend and the compliance is decreased, then the MCSFP increases, causing also an increase in venous return. The increase in venous return causes an increase in End Diastolic Volume (EDV). According to Frank Starling’s Law, when EDV is increased within physiologic limits, the force of ventricular contraction will also be great. This causes the cardiac output to increase, and ultimately the blood pressure is also increased. These arteries divide into several small arterioles until they become the afferent arterioles, the smallest branch of the renal artery. These terminate into the renal glomerulus which is where filtration occurs. When filtration has undergone in the glomerulus, the filtrate is then called glomerular filtrate. The filtrate then travels to the nephron until it reaches the ureter to become the urine. ↓ABP - ↓Distending Pressure - ↓Vascular Capacity - ↑MCSFP - ↑VR - ↑ CO - ↑ABP 2. CAPILLARY FLUID SHIFT When blood pressure is increased, the hydrostatic pressure increases. This favors filtration and fluid goes to the interstitial spaces. The blood volume therefore decreases, causing the blood pressure to decrease. Also take note that the distal tubule of the nephron abuts the afferent arteriole. ↑BP - ↑HP – Filtration - ↓BV - ↓BP JOSE ALFONSO A. ROQUE, 1E-MD 2014 Page 6 3. RENAL FLUID SHIFT When the arterial blood pressure is decreased, the blood flow to renal artery will also be decreased. This means that there will be decreased blood flowing to the afferent arteriole causing a decreased in glomerular filtrates, or urine. This means that you are preserving your blood volume which increases venous return, thus also increasing cardiac output and overall blood pressure. This is evident in patients with decreased blood volume (Bleeders). An initial symptom in them is decreased or absent urine. This is because the afferent arterioles are closed. This serves the function to maintain blood volume so that blood can reach the more important organs. When the volume has already been corrected and the pressure has risen back to normal, the first sign to assess for will be urination. This will signify the start of improvement in the circulation of the patient. The afferent arterioles have already dilated, and blood is being filtered. -Can stimulate the hypothalamus to release Vasopressin (ADH). It is a potent vasoconstrictor and can also promote water reabsorption in the distal tubule of the kidney. The overall effect is to increase blood volume, therefore increasing venous return. This also means increase in cardiac output and finally leading to an increase in blood pressure. AII – Hypothalamus – ADH - ↑H2O reabsorption in DCT & CD - ↑BV - ↑MCSFP - ↑VR & CO - ↑BP In some adults with Chronic Hypertension, there is an increase in angiotensin II. We manage this by giving Ace Inhibitors which prevent conversion of angiotensin I to angiotensin II. Finally, a summary of RAAS… ↓BP - ↓Renal Blood Flow – Glomerular Capillary HP ↓Filtration - ↓Urine Formation – Preserved Blood Volume – Improve VR and CO - ↑BP This also explains why the more you drink fluids, the more you urinate. Increased fluid intake causes increased blood volume, thus increasing blood pressure. This causing increased renal blood flow, causing increased filtration. Therefore, urine production is increased. ACTING AFTER SEVERAL HOURS 1. RENIN–ANGIOTENSIN–ALDOSTERONE SYSTEM (RAAS) This is the most important control of long term regulation of blood pressure. Remember that the distal tubule of the nephron abuts the afferent arteriole. This is important because a special structure called Macula Densa found in the distal tubule. This structure can detect the Sodium content of the filtrate. If the amount of filtrate is low (↓BP), the amount of sodium delivered in the Macula Densa is also low and this causes the JG cells found at the afferent arterioles to secrete Renin. Renin functions by converting the protein Angiotensinogen to Angiotensin I. Angiotensin I is converted to Angiotensin II (potent vasoconstrictor) in the lungs by the enzyme Angiotensin Converting Enyzme (ACE). ↓BP - ↓NA in Renal Blood Flow - Alert JG Cells Release Renin - Converts Angiotensinogen to Angiotensin I - ACE - Converted to Angiotensin II Functions of Angiotensin II -Increases total peripheral resistance, bringing the BP up back to normal AII - ↑TPR - ↑BP -Can stimulate the Adrenal Cortex to release Aldosterone, a steroid hormone that promotes sodium absorption in the tubules of the kidney. Where sodium goes, water goes. Therefore the blood pressure goes back to normal. AII-↑Aldosterone - ↑Sodium Reabsortion in DCT & CD -↑BP JOSE ALFONSO A. ROQUE, 1E-MD 2014 God Bless Us All ď Page 7 RESPIRATORY PHYSIOLOGY I LUNGS Functions: 1. Gas exchange - Transport of gas from the atmosphere towards the lungs, to the blood, to the different tissues. - Elimination of CO2 2. Host defense - It secretes several inflammatory mediators, immunoglobulins. 3. Metabolic organ - It secretes several hormones - Ex. Dopamine, Serotonin, Angiotensin Volume: 4 Liters Surface Area: 85 m2 Demonstrates “functional unity” Weight (Adults): approximately 1 kg - VISCERAL PLEURA: tightly adherent to the lung itself - PARIETAL PLEURA: attached inside the chest wall/ thoracic cavity NOSE - Very important because it is where air enters - Although we can breathe through our mouth, it is better if we breathe through our nose because: - it humidifies the air - entraps of clear particles more than 10μm in size (protective function: it acts as protective barrier) - sense of smell (olfactory sense) - 50% of the total resistance of the airway - Host defense - Secretes several inflammatory mediators, immunoglobulins. PARANASAL SINUSES - Frontal, Sphenoid, Ethmoid, Maxillary - It lightens the skull - For voice resonance - In SINUSITIS, changes in voice may be evident. LARYNX RIGHT LUNG - Divided into 3 LOBES (upper, middle, lower) - 2 interlobular fissures: HORIZONTAL FISSURE and OBLIQUE FISSURE - Opening from the oropharynx towards the trachea - Formed by: - Epiglottis - Arytenoids - Vocal cords - Also acts as a gate/door towards the airway - During swallowing, epiglottis closes (covers the larynx) so that the food will not enter the airway; LEFT LUNG - Divided into 2 LOBES (upper, lower) - Divided by OBLIQUE FISSURE - It has the LINGULA (part of the lungs where the heart lies) 1 The lungs are covered by a thin membrane called PLEURA. JOHN LERY T. MENIANO I-C LOWER AIRWAY - As it goes further down, it becomes the BRONCHIOLES. LOWER AIRWAY - Undergoes dichotomous branching (divides into two’s) - This tubular structure is composed of cartilage and muscle - Bronchi and bronchioles differ in: - Size - Cartilage - Epithelium - Blood supply - Any structures found BELOW the LARYNX is considered LOWER RESIPIRATORY TRACT; ABOVE the LARYXNX is UPPER RESIPIRATORY TRACT. - The demarcation is the LARYNX. TRACHEA - Further down the line, once the bronchioles attach to the alveoli or the alveolar ducts, it now forms the respiratory unit. RESPIRATORY UNIT (“Gas Exchange Unit”) - It is where gas exchange occurs. Composed of: - Respiratory bronchioles - Alveolar ducts - Alveoli - Those that are not attached to the alveoli or the alveolar ducts, is called the conducting unit. - Ex. trachea, main stem bronchus CONDUCTING UNIT (“Anatomic Dead Space”) - Only conducts air from the upper airways towards the alveoli. - Dead space because there is no gas exchanges that occurs. - 150 ml in adults - Divides into several bronchi. - RIGHT and LEFT MAINSTEM bronchus → divides into SECONDARY bronchus → TERTIARY bronchus TRACHEA→ divides 16x After the 16th division, it becomes the RESPIRATORY UNIT. It is now attached to the Respiratory Bronchioles and Alveolar Ducts JOHN LERY T. MENIANO I-C 2 the trachea down to the respiratory bronchus are known as the CONDUCTING airways. ALVEOLI - It is where gas exchange occurs. - Polygonal in shape. - Type 1 and Type 2 cells. - TYPE1 CELLS - 96-98% of the surface area - Thin cytoplasm - Basement membrane fused with the capillary endothelium TYPE2 CELLS Small and cuboidal Although they are more numerous that Type1 cells, they only cover around 2-4% of surface area because they are small and cuboidal. FUNCTIONS: Synthesize pulmonary surfactant Repair of alveolar structures Gas exchange occurs in the alveoli through a dense meshlike network of capillaries and alveoli called ALVEOLAR-CAPILLARY NETWORK The barrier between gas in the alveoli and the red blood cell is only 1-2 μm in thickness. - It is like a white polygon provided with several RBC’s;Íž basement membrane, septum is not visible because it is very thin. - LUNG INTERSTITIUM - Composed of connective tissues, primarily fibroblast. - FIBROBLAST - COLLAGEN- limits lung distensibility - ELASTIN- for elastic recoil of the lung - Cartilage - Neuroendocrine cells - KULTSCHITZKY CELLS: secretes DOPAMINE and SEROTONIN - Responsible for the metabolic function of the lungs, because it secretes dopamine and serotonin. BLOOD SUPPLY 1. PULMONARY CIRCULATION - Pulmonary Artery: the ONLY artery that carries UNOXYGENATED blood. - Pulmonary Vein: carries OXYGENATED blood; the blood vessel that comes from the lungs. - Largest vascular bed in the body (70-80 m2) - Dense capillary network - At REST: each capillary has a volume is 70 ml - During EXERCISE: it can span and open up, and the volume can increase up to 200 ml. 2. BRONCHIAL CIRCULATION - 2 Bronchial Arteries - Supplies the bronchi, bronchioles, blood vessels, nerves, lymph nodes and visceral pleura. - 1/3 of the blood returns to the atrium - Rest of the blood to the left atrium via the pulmonary veins. INNERVATION - When we breathe, our breathing is AUTOMATIC and UNDER CNS CONTROL - Autonomic Nervous system Parasympathetic stimulation: BRONCHOCONSTRICTION Sympathetic BRONCHORELAXATION/DILATION stimulation: Non-Adrenergic, Non-cholinergic BRONCHODILATION Inhibitory: Non- Adrenergic, Non-cholinergic Stimulatory: BRONCHOCONSTRICTION CENTRAL CONTROL OF RESPIRATION - Automatic, rhythmic, and centrally regulated - VOLUNTARY control - But when you hold your breath, you can just hold it for a period of time. - BRAINSTEM: main control center MUSCLES OF RESPIRATION 1. At INSPIRATION - Principal Muscles: A. DIAPHRAGM JOHN LERY T. MENIANO I-C 3 B. EXTERNAL INTERCOSTALS - Accessory Muscles: A. STERNOCLEIDOMASTOID B. SCALENE MUSCLES 2. At EXPIRATION - In ordinary quiet respiration, EXPIRATION is purely PASSIVE. It is accomplished when the muscles of inspiration relax. - In forced expiration: a. Rectus abdominis, oblique and transverse muscles b. Internal intercostals MUCOCILIARY CLEARANCE SYSTEM 1. PERICILIARY FLUID Secreted by the pseudostratified columnar epithelium 2. MUCUS GLANDS - Secreted by mucus and serous cells Functions: - To remove particles and particulate in the lungs (protective function) PULMONARY SURFACTANT Secreted by Type2 pneumocytes 80% phospholipids: Dipalmitoyl Choline (DPPC); ex.Lecithin 8% proteins 8% Neutral Lipids (cholesterol) Phosphatidyl 4 Surfactant Proteins: SP-A, B, C, D Function: reduces surface tension inside the lungs SP-A ďˇ ďˇ ďˇ SP-B ďˇ ďˇ ďˇ Figure 37–1 shows the mechanism by which the external and internal intercostals act to cause inspiration and expiration. To the left, the ribs duringexpiration are angled downward, and the externalintercostals are elongated forward and downward. As they contract, they pull the upper ribs forward in relationto the lower ribs, and this causes leverage on theribs to raise them upward, thereby causing inspiration. The internal intercostals function exactly in the opposite manner, functioning as expiratory muscles becausethey angle between the ribs in the opposite directionand cause opposite leverage. (Guyton and Hall , 2011) SP-C ďˇ ďˇ ďˇ SP-D ďˇ ďˇ ďˇ ďˇ ďˇ ďˇ hydrophilic collectin, Type II epithelial cells and clara cells Required in the formation of tubular myelin Hydrophobic protein Protein clipped from Type II cell Optimize rapid absorption and spreading of phospholipids Hydrophobic Develops Airway during early gestation Spreading of Pho