Convergence Tests for Series Test for Divergence Geometric Series ∞ ο§ ππ=1 ∞ οΏ½ ππππ ππ=0 Integral Test ο§ οΏ½ ππππ ππ−1 ∞ οΏ½ ππππ where ππ ≥ 0 and ππππ = ππ(ππ) for all ππ ππ=ππ p-series ∞ οΏ½ Comparison Test ππ=1 1 ππππ οΏ½ ππππ and οΏ½ ππππ where 0 ≤ ππππ ≤ ππππ for all ππ Limit Comparison Test οΏ½ ππππ and οΏ½ ππππ where ππππ , ππππ > 0 and lim ππππ ππ→∞ ππππ Alternating Series Test ∞ οΏ½(−1)ππ−1 ππππ where ππππ > 0 = ππ > 0 οΏ½ ππππ Ratio Test Root Test ππ→∞ If lim ππππ = 0, then inconclusive ππ→∞ ππ ο§ ο§ If |ππ| < 1, the series converges to 1−ππ If |ππ| ≥ 1, then the series diverges ο§ ο§ ππ(ππ) must be continuous, positive, and decreasing ∞ If ∫ππ ππ(π₯π₯)ππππ converges, then the series converges ∞ If ∫ππ ππ(π₯π₯)ππππ diverges, then the series diverges ο§ ο§ ο§ If p > 1, then the series converges If p ≤ 1, then the series diverges ο§ ο§ If ∑ ππππ converges, then ∑ ππππ converges If ∑ ππππ diverges, then ∑ ππππ diverges ο§ ο§ ο§ If ∑ ππππ converges, then ∑ ππππ converges If ∑ ππππ diverges, then ∑ ππππ diverges To find ππππ consider only the terms of ππππ that have the greatest effect on the magnitude ο§ Converges if 0 < bn+1 < bn for all n and lim ππππ = 0 ο§ ο§ If ∑|ππππ | converges, then ∑ ππππ converges If the series of absolute values ∑|ππππ | is convergent, then the series is absolutely ππ=1 Absolute Value Test If lim ππππ ≠ 0, then the series diverges ο§ ππ→∞ convergent If the series is convergent but not absolutely convergent, then the series is conditionally convergent |ππππ+1 | οΏ½ ππππ with lim = πΏπΏ ππ→∞ |ππππ | ππ οΏ½ ππππ with lim οΏ½ππππ = πΏπΏ ππ→∞ ο§ ο§ ο§ If L < 1, then the series converges absolutely If L > 1 or L is infinite, then the series diverges If L = 1, then the test is inconclusive ο§ ο§ ο§ If L < 1, then the series converges absolutely If L > 1 or L is infinite, then the series diverges If L = 1, then the test is inconclusive Test for Divergence Does lim ππππ = 0? ππ→∞ P-Series Flowchart for Convergence Tests for Series ∑an Diverges No Yes Does an = 1/np, n ≥ 1? Yes Is p > 1 No No Geometric Series Does an = arn-1, n ≥ 1 Yes Is |r| < 1? Does an =(-1)nbn or an = (-1)n-1bn , bn ≥ 0? ∑an Diverges ∞ οΏ½ Yes ππππ = ππ=1 No No Alternating Series Test ∑an Converges Yes ππ 1 − ππ ∑an Diverges Yes Is bn+1 ≤ bn & lim bn = 0 ππ→∞ Yes ∑an Converges No Try one of the following Tests: Comparison Test Pick {bn}. Does ∑ bn converge? Limit Comparison Test ππππππππ {ππππ }. π·π·π·π·π·π·π·π· ππππ lim = ππ > 0 ππ→∞ ππππ c finite & an , bn > 0? Integral Test Does an = f(n), f(x) is continuous, positive & decreasing on [a, ∞)? Ratio Test πΌπΌπΌπΌ lim |ππππ+1 /ππππ | ≠ 1? ππ→∞ Root Test ππ πΌπΌπΌπΌ lim οΏ½|ππππ | ≠ 1? ππ→∞ Yes No Yes Is 0 ≤ an ≤ bn Is 0 ≤ bn ≤ an ∞ π·π·π·π·π·π·π·π· οΏ½ ππππ ππππππππππππππππ? ππ=1 π·π·π·π·π·π·π·π· οΏ½ ππ(π₯π₯)ππππ ππππππππππππππππ? Yes πΌπΌπΌπΌ lim |ππππ+1 /ππππ | < 1? Yes ππ ππ→∞ ππ πΌπΌπΌπΌ lim οΏ½|ππππ | < 1? ππ→∞ ∑an Diverges Yes ∑an Converges Yes No Yes ∞ Yes ∑an Converges Yes No Yes No Yes No ∑an Diverges ∞ οΏ½ ππ=ππ ππππ ππππππππππππππππππ ∑an Diverges ∑an Abs. Conv. ∑an Diverges ∑an Abs. Conv. ∑an Diverges