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1. Number
a. Calculate the exact value of
1 3
1 
7 4  1 1  3    2 1  1   22
i.
1 1  7 4   2 5  28
2 
2 5
ii. 2 
0.24
 0.4
0.15
b. Hire Purchase
i. $69  $28.50 10  $354
ii. $354  $319.95  $34.05
iii.
34.05
100%  10.6%
319.95
2. Algebra
a. Inequality
3  2x  7
i.
ii.
3  7  2x
4  2 x
2  x
x0
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b. Factorization
i.
x 2  xy  x  x  y 
ii. a 2  1   a  1 a  1
iii. 2 p  2q  p 2  pq   2  p  p  q 
c. Equation/Representation
i. 2  k  5 
ii. 2  k  5   10k  8k  20 k  10
20k  10  140
iii. 20k  130
k  $6.50
3. Sets and Geometry
a. Venn Diagram
i. Draw the Venn Diagram
ii. S    k , l , m, p , q
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iii. S I  n, r , q
b. Plane geometry
i. ABC  90 co-interior to BCD
0
ii. ABD  48 alternate to BDC
0
iii. ABD  84 sum of angles in a triangle is 1800
0
4. ..
a. Distance time
i. The length of the journey is 6 hours and 50 minutes
ii. Average speed 410  
50
 60km / h
60
b. Circle Measure
i. Area of circle 38.5cm
ii. Square area 12.25cm
iii. 12.5cm 
2
2
2
38.5
 2.625cm 2
4
5. Statistics
a. Frequency table
Number of books
0
1
2
3
4
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Frequency
2
6
17
8
3
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b. 36 boys
c. Modal is 2
d. 76 books
76
 2.1
36
e.
x
f.
P  X  3 
11
36
6. Transformation
a. Describing transformations
0
i. 180 rotation about L
2 

 1 
ii. A translation T 
b. Part B is left out Intentionally
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7. Relations and Functions
a. Copy and complete the table
b. Draw the graphs
c. …
i. Add straight line
ii.
A(0.45, 2) B(4.45, 2)
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iii.
®
x2  4x  2  0
8. Investigations
Part b
(i)
362  1296
(ii)
1

 2  n  n  1 
Part c
i.
782  6084
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2
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9. Functions relations and graphs
a. Variation
i. V 
k
p
ii. k  6400
iii. V 
40
3
b. Algebra
i. a 2   a  7    a  1
2
2
ii. a  5, a  12; use " a  12"
iii. Lengths of sides are 12, 5 and 13
10. Linear programming
a. Write the inequalities
i.
x  y  30
ii. 6 x  24 y  360
b. Draw
i. the graphs of the inequalities
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ii. Vertices of the shaded region are  0, 0  ,  0,15  ,  20,10  ,  30, 0 
c. Analysis
 0, 0  ,  0,15  ,  20,10  ,  30, 0 
i. Maximum profit in each case is P  x  3 y
$0,$45,$50,$30
ii. Maximum profit is $50
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11. Geometry and Trigonometry
a. Circle geometry
Angle WOY  100 , the angle at the center is
0
Twice the angle on the circumference
OWY  400 , Triangle OWY is isosceles
b. Bearings
i. Sketch the diagram
ii. Find AC using the cosine rule 199.3m
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iii. The bearing of C from A is 183.70, find angle CAB and add it to 180
12. …. Question 12 is deliberately omitted
13. Vectors
a. ..
i.
ii. ..
a.
b.

 

AC  2 x  3 y

3y
PQ  x 
2


iii. 2 PQ  2  x 

3y 

2
x

3
y

AC

2 
b. …
i. …
ii. …
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a.
  2 
RT   
 6 
b.
  4 
SR   
 2 
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a.
  4 
OF   
1 
b.
F  4,1
14. Matrices
2
a.
1 x 
1 
  5
 y 2 
6
y3
x4
 2 1 
R

b.
 1 3  hence R is non singular
R 70
c.
 3
1
 7
 2 1

 
 1
1 3 

 7
1
7

2

7
 3 1   1 6

0 
 2 1  7 7   7
1 0
d. 




1 6   0 1
 1 3   1 2   0

 

7 
 7 7 
 3 1
 7 7   0  1  x 
e. 
   

 1 2  7   2  y 


 7 7
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