LECTURE 30 TOTAL INTERNAL REFLECTION DISPERSION 1 the indices of refraction of different materials, Determine Given determine when total internal reflection occurs Objectives Relate Deduce Relate dispersion to the color separation of white light as it travels through a prism at non-normal incidence Deduce the speed of light in a medium from its dispersion curve θa θr na = 1.52 θb nb = 1.0 Is it possible that all of the light can be reflected back from the interface with none of it being transmitted? 3 Total Internal Refection (TIR) Occurs only when a ray in material π is incident on a second material π whose index of refraction is smaller than that of material π. θa θcrit θr na = 1.52 θb TIR occurs only if nb < na. nb = 1.0 4 Total Internal Refection (TIR) TIR will occur if the angle of incidence θa is larger than or equal to θcrit. When the angle of incidence reaches πππππ‘ , the angle of refraction ππ is exactly 90°. Hence, ππ sin πππππ‘ = ππ sin 90° = ππ 5 TIR in real life 6 7 8 TIR application: fiber optics 9 Example 10 Example 11 Example Light is incident along the normal on face of a glass prism of refractive index 1.52, as shown in the figure. Find the largest value the angle πΌ can have without any light refracted out of the prism at face if (a) the prism is immersed in air and (b) the prism is immersed in water. check your answer in the next slide 12 Solution No refracted ray implies TIR. ππ sinππ = ππ sinππ ππ = πππππ‘ ; ππ = 90β ππ −1 πππππ‘ = sin ππ πΌ = 90β − πππππ‘ (a) The index of refraction of air is 1.00029. LHS: 1.52 sin πππππ‘ = 1.52 sin 90° − πΌ = 1.00029 sin 90° 1.00029 90° − πΌ = sin−1 = 41.154° 1.52 πΌ = 48.846° (b) The index of refraction of water is 1.333. LHS: 1.52 sin πππππ‘ = 1.52 sin 90° − πΌ = 1.333 sin 90° 1.333 90° − πΌ = sin−1 = 61.279° 1.52 πΌ = 28.721° 13 No refracted ray implies TIR. ππ sinππ = ππ sinππ ππ = πππππ‘ ; ππ = 90β ππ −1 πππππ‘ = sin ππ πΌ = 90β − πππππ‘ Objectives • Index of refraction of primary medium is greater than than index of refraction of secondary medium ππ > π π • Angle of incidence is equal to or greater than critical angle ππ ≥ πππππ‘ Determine Given the indices of refraction of different materials, determine when total internal reflection occursReduce the speed of light in a medium from its dispersion curve White Light Ordinary white light is a superposition of waves with wavelengths extending throughout the visible spectrum. 15 Dispersion β’ dependence of wave speed and index of refraction on wavelength where: λ: wavelength of light in a material λo: wavelength of light in vacuum n: index of refraction of the material v: speed of light in the material c: speed of light in vacuum 16 The amount of dispersion depends on the difference between the refractive indexes for violet light and for red light. Dispersion is greatest for silicate flint glass, for which there is a larger difference in the value of n between red and violet. 17 Example 1. Which material has the slowest speed at violet light? Since are π0 and π are constant with higher π, we have lower π£ Silicate flint glass: largest π at 400 nm 18 Example 2. What is the speed of a 700nm-light (π0 ) traveling in silicate crown glass? π π π= →π£= π£ π From the plot, we have π ≈ 1.5. Hence, π£≈ 3×108 m/s 1.5 = 2 × 108 m/s 19 How rainbows form Dispersion Refraction Reflection 20 21 22 Exercise! 23 Exercise! 24 Relate Relate dispersion to the color separation of white light as it travels through a prism at non-normal incidence Objectives Deduce the speed of light in a medium Deduce from its dispersion curve