4.1.1 Scalars and vectors Specification Nature of scalars and vectors. Examples should include: velocity/speed, mass, force/weight, acceleration, displacement/distance. Addition of vectors by calculation or scale drawing. Calculations will be limited to two vectors at right angles. Scale drawings may involve vectors at angles other than 90°. Vectors and scalars 2 of 24 © Boardworks Ltd 2009 Displacement and velocity A runner completes one lap of an athletics track. What distance has she run? 400 m What is her final displacement? If she ends up exactly where she started, her displacement from her starting position is zero. What is her average velocity for the lap, and how does it compare to her average speed? 3 of 24 © Boardworks Ltd 2009 Displacement vectors Harry and Sally are exploring the desert. They need to reach an oasis, but choose to take different routes. Harry travels due north, then due east. N Sally simply travels in a straight line to the oasis. When Harry met Sally at the oasis, they had travelled different distances. However, because they both reached the same destination from the same starting point, their overall displacements were the same. 4 of 24 © Boardworks Ltd 2009 Scalar or vector? 5 of 24 © Boardworks Ltd 2009 4.1.1 Scalars and vectors To find the size and direction of the force you can use a scale drawing • Eg scale 10mm = 1 N • 3N • 4N • FLIP THE TRIANGLE!!!!!!! • • 5N 3N • 4N You can also find the size and direction of the resultant force by calculation • Use Pythagoras's theorem!!!! • F2 = 32 + 42 • F2 = 25 • F = 5N Size of angle • Tan θ =3/4 (SOHCAHTOA) • θ = 37o • • • 3N (opp) θ 4N (adj) Calculating a resultant When adding two perpendicular vectors, it is often necessary to calculate the exact magnitude and direction of the resultant vector. This requires the use of Pythagoras’ theorem, and trigonometry. For example, what is the resultant vector of a vertical displacement of 3 km and a horizontal displacement of 4 km? R 4 km θ magnitude: direction: R2 = 32 + 42 tan θ = 4/3 R = √ 32 + 42 = √ 25 θ = tan-1(4/3) = 53° = 5 km 3 km 8 of 24 © Boardworks Ltd 2009 Worked examples 1.1.5 1.1.5 A lorry’s load has a weight of 40 000 N and it is being pulled along by a horizontal force of 15 000 N. What is the resultant of these two forces? With this type of calculation it is often easier if you sketch a rectangle using two triangles as in the Figure. Here, the rectangle shows the two forces acting at right angles to one another, and the diagonal represents the resultant force. Using Pythagoras’s theorem gives: resultant2 = (4.0 × 104)2 + (1.5 × 104)2 = 16.0 × 108 + 2.25 × 108 = 18.25 × 108 so resultant = 4.27 × 104 N Worked examples 1.1.5 (cont.) 1.1.5 (cont.) When working out such calculations, you need to be careful if you are using powers of 10. Always check that the length of the hypotenuse is realistic. This has given you the magnitude of the resultant force, but to complete the calculation its direction is also required. Since the adjacent side is given by hypotenuse × cosθ we get: cosθ = 4.00 10 4 4.27 10 4 = 0.9368 and hence θ = 20.5° Note: Worst case scenario Much worst case scenario A raindrop falls at a constant velocity of 1.8 ms-1. If a horizontal wind of 1.4ms-1 is blowing, calculate the magnitude and direction of the resultant velocity of the raindrop by (1) a scale diagram (2) calculation Resultant velocity 1.8ms-1 x2 = 1.82 + 1.42 x = √1.82 + 1.42 x = 2.28 1.4ms-1 1.8ms-1 Tanθ = 1.4/1.8 θ Tanθ = 0.7778 SOH CAH TOA θ = 37.90 1.4ms-1 Scale: 1cm = 0.2 ms-1 1.8 ms-1 Resultant velocity Measure length of resultant velocity = 11.5 cm 1cm = 0.2 ms-1 11.5 x 0.2 = 2.3 ms-1 1.4 ms-1 Resultant vectors 13 of 24 © Boardworks Ltd 2009 On a windy day, a parachutist of mass 85 kg jumps from an aeroplane. Distinguish between speed and velocity. On a windy day, a parachutist of mass 85 kg jumps from an aeroplane. As the parachutist falls, the wind is moving him towards the right of the diagram, at a horizontal velocity of 6.3 m/s. Draw a vector diagram to determine graphically the size and direction of the resultant velocity of the parachutist. size = ....................................................... direction = ....................................................... [4] On a windy day, a parachutist of mass 85 kg jumps from an aeroplane. Calculate the kinetic energy of the parachutist. kinetic energy = ................................................. [3] Vehicle A exerts 4000N Vehicle B exerts 2000N