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[Solved] \({\overline V _a}\) = 1∠0°, \({\overline
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Three Phase Circuits
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–
–
–
Va
Vb
Vc
= 1∠0°,
= 1∠120°,
= 1∠240° constitute a balanced set of three phase voltages.
–
V bc
The magnitude and angle of voltage
are
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1. 1/√3, -90°
2. √3, +90°
3. √3, -30°
4. 1/√3, +30°
Answer (Detailed Solution Below)
Option 2 : √3, +90°
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Finding magnitude and phase:
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[Solved] \({\overline V _a}\) = 1∠0°, \({\overline
English
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Given
Va = Vm sin ωt
Vb = Vm sin (ωt + 120°)
Vc = Vm sin (ωt + 240°)
Or Vm sin (ωt - 120°)
Vm = 1
Vbc = Vb - Vc = sin (ωt + 120°) - sin (ωt + 240°)
= √3 × sin (ωt + 90°)
Magnitude = √3
Phase = + 90°
Additional Information
An important point related to the 3 phase system:
Sr.
No.
Description
Expression
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1.
[Solved] \({\overline V _a}\) = 1∠0°, \({\overline
The phase shift between adjacent
phase voltages in a three-phase
system
English
120° or 2π/3 rad
Start Learning
VR = Vm sin ωt
2.
Mathematical representation of the
three-phase voltages
VY = Vm sin (ωt 120°)
VB = Vm sin (ωt 240°)
Or Vm sin (ωt
+ 120°)
3.
Phasor representation of three-phase
voltages
VR + VY + VB = 0
4.
Vector addition of the three-phase
voltages, at any instant, is zero
VR + VY + VB = 0
5.
Frequency of phase or line voltages
50 Hz
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More Three Phase Circuits Questions
–
–
–
–
–
–
∠ (V a, V ab) ∠ (V b, V bc) ∠ (V c, V ca)
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–
–
Va
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