EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 Laboratory No. 4 Real, Reactive and Apparent Power Submitted by: Garcia, Danarie D. Garcia, Kyle Vincent L. Geron, Mark Angelo D. Harina, Mark AngeloH. Hernandez, Jean Clarence P. PetE-2101 Bachelor of Science in Petroleum Engineering 20-09878@g.batstate-u.edu.ph 20-02694@g.batstate-u.edu.ph 20-08867@g.batstate-u.edu.ph 20-01873@g.batstate-u.edu.ph 20-04458@g.batstate-u.edu.ph Engr. Jonas S. De Castro, REE Lecturer Page 1 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 Abstract – Reactive power is electrical energy that is held in the coil and then flows back to the grid. Ideal coils utilize no electrical energy while producing a substantial electric current. Real power is the power utilized because of the resistive load, whereas apparent power is the power that the grid must be able to bear. The unit of real power is watt, while the unit of perceived power is VA volt ampere. The issue of reactive power is not simply technical, but it also has significant economic implications. Indeed, a utility firm must construct an infrastructure capable of transporting visible energy, but only bills for actual electricity. It would be unsustainable if the disparity was too significant. The power factor is the ratio of real power to perceived power. The power factor should be as near to one as feasible. The goal of this experiment is to improve a student's understanding of real, reactive, and apparent power. The purpose of this experiment is to determine the relationship between the three. To determine the predicted outcomes, the experiment is carried out in Multisim which includes an AC power supply, ground, wattmeter, electrical wires, breadboard, inductors, capacitor, and virtual lamp. INTRODUCTION The product of a circuit's The apparent power is the vector sum of voltage and current without regard for real and reactive power engineers use the phase angle is known as apparent following terms to describe energy flow in a power, and it is the product of system (and assigned each of them a different unit reactive power and true power. The to differentiate between them): capital letter S represents apparent A. Real Power (P) [Unit W] power, which is measured in Volt- True power is the actual Amps (VA). amount of power used or dissipated in a circuit, and it is measured in watts (symbolized by the capital letter P, as always). Reactive loads like inductors and capacitors dissipate zero power, but the fact that they drop voltage and current impression that gives they watt (symbol: W). However, this unit is generally reserved for the real power component. B. Reactive Power (Q) [Unit VAR] draw The unit for all forms of power is the the false do. This "phantom power" is known as reactive power, and it is measured in Volt-Amps-Reactive (VAR) units Apparent power is conventionally expressed in volt-amperes (VA) since it is a simple product of RMS voltage and RMS current. The unit for reactive power is given the special name “VAR”, which stands for volt-amperes reactive (since power flow not net energy to the loads, it is sometimes called wattles power). rather than watts. The capital letter Q is the mathematical symbol for reactive power. C. Apparent Power (S) [Unit KVA] Page 2 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 a. If using offline Multisim measure it using OBJECTIVES OF THE STUDY 1. Determine the real, the wattmeter. reactive, and b. If using the online version, please apparent power by measurements. measure it using the manual computation 2. Compare the measured and calculated based on the value of the Multisim. Refer real, reactive, and apparent power for the to the formula below. given circuit. ππ = πβπ → πππ π 3. Determine the impedance of a given πππππ π’πππ = πΈπ‘ πΌπ‘ πππ π circuit to compare the measured value to calculated value of a given circuit. 6. Compute and record the magnitude and phase angle of the impedance using the MATERIALS equation Z= R + RL + jXL – JXC. Use Multisim 3uF for the value of C, 1.006H for the Is a simulation tool that can be used to speed up the analysis and design of circuits containing digital devices, transistors, diodes, op amps, and even value of L and for the resistance is computed based on the specification of the lamp. 7. Compute and record for the total power using the formula. ππππππ’π‘ππ = ππππ π motors. 8. Compute and record the reactive power and METHOD apparent power using the formula. Use the 1. Open NI Multisim 14.2, which allows users to build, design, learn, and share circuits and computed values and record it as computed. electronics online, and draw the circuit in Figure 1 on the canvas. 2. Measure the total current. Record the current ππππππ’π‘ππ = √π 2 − π2 reading. Refer to figure 2. 3. Measure the voltage e T. Record the data. 9. Compute for (measure) Refer to figure 3. 4. Using Ohm’s Law, compute the voltage and the and reactive apparent power power (measured) using the formula. current for each component. Record it as a π = ππ‘πππ measured value. Use the formula π = π/πππ πππ π ππ‘ π= πΌπ‘ π= π2 π ππππππ’π‘ππ = 10. 220 0.3145 Compute the percent difference between the measure and the computed value of the impedance. π = 687.5 πΊ 5. Measure the power factor and power of the system depending on your set up and record your data: Page 3 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 Workbench Computation % Difference ZT 687.5 πΊ 699.4436 Ω 1.74% P 49. 527 W 47.8834 W 3.32% Q 50.5277 VAr 49.9552 VAr 1.13% S 70.752 VA 69.1979 VA 2.20 % p.f (cos) 0.7 0.69 1.43% Figure 2. Getting the total current of the AC supply Table 1: Simulation and Computation Result of Power This table 1 shows the simulation and computation results for obtaining power values in the RLC circuit. The columns are Workbench, Computations and Percent Figure 3. Getting the total voltage of the Difference results. Respectively to the rows AC supply are Impedance, Real power, Reactive power, Apparent power, and p.f (cos). CIRCUIT DIAGRAM Figure 4. Getting the power factor and power of the system Figure 1. Circuit Diagram Manual Computation For the resistance of the lamp (R) RESULTS AND DISCUSSION R= This section analyses the results of the experiment including their figures during the π2 π So, V= 220 V; P= 100W experiment. R= (220 π)2 (100 π) R = 484 Ω ππ = πππ π Page 4 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 π π 699.4436 Ω < 46. 2131° 484 πΊ 699.4436 πΊ For the total current ππ = ππ = ππ = ππ = 0.69 πΌπ = For the reactance of the inductor (ππΏ ) ππ πΌπ ππ ππ So, ππΏ = 2πππΏ ππ = 220 V; ππ = 699.4436 Ω So, πΌπ = f = 60 Hz; L=1.006 H (220 π) (699.4436 πΊ) ππΏ = 2π(60 π»π§)(1.006π») πΌπ = 0.3145357253 A ππΏ = 379. 2530651 Ω πΌπ = 0.3145 A ππΏ = 379. 2531 Ω Since the circuit is in series, πΌπ = ππ = ππΏ =ππΆ For the resistance of the capacitor (ππΆ ) ππΆ = For the lamp voltage (ππ ) 106 2πππΆ R= ππ = ππ π So, So, f = 60 Hz; C = 3µF ππΆ = 106 ππ = 0.3145357253 A; R = 484Ω 2π(60 π»π§)(3µπΉ) ππ = (0.3145357253 π΄) (484Ω) ππΆ = 884.1941283 Ω ππ = 152.235291 V ππΆ = 884.1941 Ω ππ = 152.2353 V For the total impedance (ππ ) For the inductor’s voltage (ππΏ ) ππ = √π 2 + (ππΏ − ππΆ )2 ππΏ = So, R = 484Ω; ππΏ = 379. 2531 Ω; ππΆ = 884.1941 Ω ππ = ππ ππ √(484πΊ)2 = (379. 2531 πΊ − 884.1941 ππΏ ππΏ ππΏ = ππΏ ππΏ So, πΊ)2 ππΏ = 0.3145357253 A; ππΏ = 379. 2531 Ω ππ = 699.4436457 Ω ππΏ = (0.3145357253 A)(379. 2531 Ω) ππ = 699.4436 Ω ππΏ = 119. 2886489 V ππΏ = 119. 2886 V For the phase angle (π) π = π‘ππ−1 (ππΏ − ππΆ) π For the capacitor’s voltage (ππΆ ) So, ππΆ = R = 484Ω; ππΏ = 379. 2531 Ω; ππΆ = 884.1941 Ω π= (379.2531 πΊ − 884.1941 πΊ) π‘ππ−1 484πΊ π = π‘ππ−1 ππΆ ππΆ ππΆ = ππΆ ππΆ So, (− 504.941πΊ) ππΏ = 0.3145357253 A; ππΆ = 884.1941 Ω 484πΊ π = -46. 2131° ππΆ = (0.3145357253 A) (884.1941 Ω) π = 46. 2131° ππΆ = 278.1106325 V ππΆ = 278.1106 V Therefore, the value of ππ is: Page 5 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 For the apparent power (Scomputed) Scomputed = π2 π π % π·πππππππππ = So, ππ = 220 V; ππ = 699.4436 Ω Scomputed = /69.1979 ππ΄ − 70.752 ππ΄/ 70.752 ππ΄ (100) π % π·πππππππππ = 2.20% (220 π)2 (699.4436 πΊ) Scomputed = 69.19785956 VA π. π % π·πππππππππ = Scomputed = 69.1979 VA /0.69 − 0.7/ 0.7 (100) π. π % π·πππππππππ = 1.43% For the real power (Pcomputed) Questions: Pcomputed = Scosπ 1. Do the workbench and computational So, values of real, apparent and reactive S = 69.19785956 VA; π = -46. 2131° power agree? Pcomputed = (69.19785956 VA) cos (-46. Answer: Yes, the workbench and 2131°) computational values of real, apparent, Pcomputed = 47.8834 W and reactive power agree with only a little percentage variation, and the For the reactive power (Qcomputed) workbench and computational values ππππππ’π‘ππ = √π 2 − π2 produce correct findings. 2. Give So, possible reasons for any discrepancies. Any other observations or S = 69.19785956 VA; P = 47.8834 VA comments? ππππππ’π‘ππ = √69.19785956 2 − 47.8834 2 Answer: In this laboratory exercise, the ππππππ’π‘ππ = 49.9552 VAr discrepancy between benchwork and pf = 0.7 manual computation demonstrates a lack of balance between two things that PERCENT DIFFERENCE should be similar, as illustrated by the percent error solution. Rounding off the final answer and neglecting to complete π§π % π·πππππππππ = the /699.4436 − 687.5/ (100) 687.5 of the anomalies. CONCLUSION AND RECOMMENDATION /47.8834 π − 49. 527 π/ = (100) 49. 527 π π % π·πππππππππ = 3.32% component experiment could cause any errors or π§π % π·πππππππππ = 1.74% π % π·πππππππππ hardwired From this laboratory activity, we can conclude that “active power" is power that actually performs work. Reactive power is π % π·πππππππππ = /49.9552 ππ΄π − 50.5277 ππ΄π/ (100) 50.5277 ππ΄π π % π·πππππππππ = 1.13% defined as power in which the current is out of phase with the voltage, and this will help us to know that we can calculate the real power and the Page 6 of 7 EE 419 Basic Electrical Engineering | Laboratory Experiment No 4. | December 02, 2021 power factor through a wattmeter. For example, THOUGHTS: current that charges a resistor or current that Garcia, Danarie D. forms a magnetic field around a circuit. To obtain This laboratory experiment is interesting and engaging since it uses NI Circuit Multisim for hands-on simulation to demonstrate and explain the real, reactive and apparent power mesurements. It deepened our comprehension while also testing our mathematical abilities by showing that the multisim findings are same when manually calculated. the true power and power factor, plug the wattmeter in series with the IT branch and in parallel with the power supply. After modifying the above formula here on laboratory activity, we can obtain the values of apparent power and reactive power by using the power factor and actual power. Furthermore, we can acquire the simulated value of the impedance using the voltage level and total current measured in the circuit diagram, and we'll get the phase angle and the amount of the resistor for the calculated value through using RL, XC, and XL. Utilizing different functions of Multisim has been a great help for the researchers for the past experiments and in this particular experiment. Applying the learnings about Ohm's Law and utilizing it in the experiment helped the researchers to estimate voltage and current. Analyzing laws and principles from the past activities can be an advantage also in estimating the impedance of the given circuit in this experiment. Overall, applying different learnings from the previous activities with the help of teamwork and unity will help the team to achieve what needs to be achieved. REFERENCES [1] All About Circuit (n.d.). True, Reactive, and Apparent Power. Retrieved from https://www.allaboutcircuits.com/textbook/ alternating-current/chpt-11/true-reactiveand-apparent-power/ [2] Menu, JJ. (February 8, 2016). Real Power vs Apparent Power vs Reactive Power: What is the difference? Retrieved from https://www.arrow.com/en/research-andevents/articles/real-vs-reactive-power Page 7 of 7