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Rijal Falaqi Muhammad 2011102442012 Tugas 1

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Tugas 1 Dinamika Fluida
Persamaan Bernoulli Termodifikasi
Daya Hidrolik Pompa
DP = r g Q hP
Daya Turbin
DP = r g Q hT
Nm/s,
J/s,
Watt
Nm/s,
J/s,
Watt
Daya Hidrolik Pompa
DP
= r g Q hP
DP
= 20 kW = 20000 W
z3-z1
= 45 m
Q
= 0,03
m3/s
Tugas 1 Dinamika Fluida
20000 = 1000
x 10 x
hP = 20000 / 294,2
hP = 67,98 m
0,03
v1
= 30
m/s
D1
=
2
inch
L1
= 75
D2
=
L2
= 30
= 1/4 v1
v3
he +
z3 - z1
g
Q1
Q2
hf
=
m
4
3
= 85
= 9,81
inch
m
= 7,5
m/s
m
= 30
m
m/s2
m/s
= 7,5
m/s
2
r1
+ v1 - hT = z3 +
2g
g
2
2
r
r3
(z1 - z3) + 1 + v1 - v3
2g
2g
g
g
z1 +
x hP
r3
g
-
2
+ v3 +
2g
hT =
She
She + Shf
+
Shf
Tugas 1 Dinamika Fluida
2
2
(z1 - z3) + v1 - v3 - hT = She + Shf
2g
2g
900
56,25
85
+
- hT =
3
19,61
19,61
900
56,25
hT = 3 85
19,61
19,614
- hT =
3
- hT =
- hT =
hT =
3 -131
131
-
85
-
956,3
19,61
133,8
m
Daya Turbin
Q
Q
Q
=
=
=
DP
DP
DP
= r g Q hT
= 1000
x 9,81
= 77.930,5 Watt
Soal No 1
A x
0,002
0,061
V
x
30,0
x
0,061
x
131
Tugas 1 Dinamika Fluida
ΣhP =
ΣhT =
Head pompa (head yang dimasukkan ke sistem)
Head Turbin = 0, karena tidak ada turbin yang terpasang (head yang dikeluarkan ke sistem)
ΣhP = Head loss karena gesekan f = 0,01 (head yang dikeluarkan ke sistem)
z3
= 9
m
z1
= 0
m
Q
D
f
r
g
L1
L3
=
=
=
=
A
=
A
=
=
=
=
=
=
=
3
20 m /s
0,0254
m
0,01
kg/m3
999
= 9,81 m/s2
= 5 m
= 20 m
Q
V
V
V
V1
Hf
π
x D2
4
0,000506 m2
V x A
Q / A
20 / 0,000506
39490,52 m/s
V3
0,25 m
2
r1
+ v1 + hP = z3 +
2g
g
2
r
hP = z3 + 3 + v3 + She
2g
g
r3
g
She
z1
z1 +
hP = z3 +
hP =
hP =
DP
DP
DP
DP
9 + 0
9,25 m
+
+
Shf
0,25
-
-
+
0
= r g Q hP
= 999
x 9,81 x 20 x 9,25
= 1812480,705 watt
= 1,812480705 MW
2
+ v3 +
2g
Shf
-
She
z1
-
+
r1
g
Shf
2
- v1
2g
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