Order of Operations
S A T U R D A Y , A U G U S T 2 1 ST 2 0 2 1
Add/subtract with brackets
 Perform the operations within the parenthesis (bracket) first
before the other operations.
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Find the solution.
1). (11 - 4) - 3 = 7-3 = 4
2). 2 + (12 - 1) = 2 + 11 = 13
3). 6 - 3 + 7 =
4). 17 - (6 + 6) =
5). 14 - (17 - 5) =
6). 5 + (12 - 2) =
7). 15 - (7 + 2) =
8). 5 + (4 - 1) =
9) 22 – (35 - 32) – 17 =
10) 37 – (34 + 11 – 30) =
11) 17 – 13 + (40 – 31) =
Add/subtract with brackets
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1. 20 - (12 - 7) =
2. 20 - 8 - 6 =
3. 20 - 12 - 7 =
4. 13 - (16 - 7) =
5. 5 - 20 + 16 =
6) 23 – (5 + 35 – 21) =
7) 35 – 32 + (20 – 6) =
8) 35 – 32 + 20 – 6 =
9) (9 + 36) – 23 + 37 =
10) 25 – (5 + 15 – 10) =
11) (2 + 13) – (2 + 10 + 2)
Add/Subtract/Multiply without parenthesis
 Multiplication operations are done before addition or
subtraction.
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Find the answer to each question:
1) 2 + 4 × 5 × 6 =
2) 4 × 1 + 8 – 3 =
3) 2 × 2 + 7 – 3 =
4) 6 × 1 × 6 – 10 =
5) 9 + 2 × 4 – 2 =
6) 5 × 6 × 5 – 3 =
7) 4 × 3 – 2 × 5 =
8) 5 + 10 × 1 – 9 =
9) 7 + 2 – 7 + 4 =
10) 6 × 4 + 6 × 5 =
Add/Subtract/Multiply with Parenthesis
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Clear the parenthesis (bracket) first before you multiply then add or subtract.
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Find the answer to each question:
1) 10 + 3 – (4 – 3) =
2) 10 – 3 + (10 – 3) =
3) (6 × 6 – 2) – 3 =
4) 1 × 4 + (8 × 5) =
5) 1 × (5 + 1 – 4) =
6) 2 × 5 – (8 – 4) =
7) 7 + 4 – 5 + 8 =
8) 2 + 6 × (3 – 1) =
9) 1 + (5 – 4) × 1 =
10) (8 – 4) + 9 × 1 =
11) 6 × 2 × (5 + 10) =
12) 2 + (10 × 5) + 9 =
13) (6 × 5 + 5) – 1 =
14) 4 × 4 – (8 – 8) =
ROMAN NUMERALS
Roman numerals were used by
the Ancient Romans as their
numbering system. We still use
them sometimes today.
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ROMAN NUMERALS
 Roman numerals use letters instead of numbers.
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There are seven letters you need to know:
I=1
V=5
X = 10
L = 50
C = 100
D = 500
M = 1000