Formulas for Physics 292 exam #1
v = λf =
λ
T
v=
FT
µ
v=
E
ρ
B
v=
ρ
Q1Q2
1 Q1Q2
F =k 2 =
4πε 0 r 2
r

 F
E=
q
dQ
σ=
dA
dQ
λ=
dl
dQ
ρ=
dV
 
ΦE = E ⋅ A
 
Φ E = ∫ E ⋅ dA
k=
2π
λ
Q
E=k 2
r
σ
E=
ε0
  Qencl
∫ E ⋅ dA =
ε0
D( x, t ) = A sin (kx − ωt + φ )


F = qE


p = Ql