Chemistry 144 Dr K de Villiers Weak Acids & Bases CONTACT SESSION Starter discussion: Important concepts: 1. Extent of ionization π»π»πΆπΆπΆπΆ(ππππ) π»π»ππππ2 (ππππ) π»π» + (ππππ) + πΆπΆπΆπΆ − (ππππ) π»π» + (ππππ) + ππππ2 − (ππππ) Chemistry 144 Weak Acids & Bases Dr K de Villiers 2. Ka and pKa π―π―π¨π¨(ππππ) + π―π―ππ πΆπΆ β π―π―ππ πΆπΆ+ (ππππ) + π¨π¨− (ππππ) [π»π» + (ππππ)][π΄π΄− (ππππ)] πΎπΎππ = [π»π»π»π»(ππππ)] Large(r) Ka? Small(er) Ka? 3. Kb and pKb π΅π΅(ππππ) + π»π»2 ππ(ππ) β π΅π΅π»π» + (ππππ) + π»π»ππ− (ππππ) [π΅π΅π»π» + (ππππ)][π»π»ππ− (ππππ)] πΎπΎππ = [π΅π΅(ππππ)] Large(r) Kb? Small(er) Kb? π¨π¨− (ππππ) + π―π―ππ πΆπΆ(ππ) β π―π―π―π―(ππππ) + π―π―π―π―− (ππππ) [π»π»π»π»(ππππ)][π»π»π»π»− (ππππ)] πΎπΎππ = [π΄π΄− (ππππ)] Chemistry 144 Dr K de Villiers Weak Acids & Bases 4. Ion product of water, Kw πΎπΎπ€π€ = [π»π» + ][πππ»π» − ] = 1.0 × 10−14 (ππππ 25 β) ππππ. ππππ = ππππ + ππππππ πΎπΎππ × πΎπΎππ = [π»π» + (ππππ)][π»π»π»π»− (ππππ)] = πΎπΎππ ππππ. ππππ = πππ²π²ππ + πππ²π²ππ Large(r) Ka? 5. Acid-base conjugate pairs Chemistry 144 Dr K de Villiers 6. Salt solutions πΊπΊπΊπΊπΊπΊπΊπΊ = πͺπͺπͺπͺπͺπͺπͺπͺπͺπͺπͺπͺ+ + π¨π¨π¨π¨π¨π¨π¨π¨π¨π¨− NO EFFECT Cation + ACIDIC (↓ pH) NO EFFECT Anion¯ BASIC (↑ pH) Weak Acids & Bases Chemistry 144 Dr K de Villiers Weak Acids & Bases IN CLASS QUESTION Determine the pH of a 0.20 M solution of NH4Cl (Kb (NH3) = 1.8 × 10-5). Before you do the calculation, do you expect the pH to be acidic, neutral or basic? Why? I C E