Chemistry 144
Dr K de Villiers
Weak Acids & Bases
CONTACT SESSION
Starter discussion:
Important concepts:
1. Extent of ionization
π»π»πΆπΆπΆπΆ(ππππ)
π»π»ππππ2 (ππππ)
π»π» + (ππππ) + πΆπΆπΆπΆ − (ππππ)
π»π» + (ππππ) + ππππ2 − (ππππ)
Chemistry 144
Weak Acids & Bases
Dr K de Villiers
2. Ka and pKa
π―π―π¨π¨(ππππ) + π―π―ππ πΆπΆ β π―π―ππ πΆπΆ+ (ππππ) + π¨π¨− (ππππ)
[π»π» + (ππππ)][π΄π΄− (ππππ)]
πΎπΎππ =
[π»π»π»π»(ππππ)]
Large(r) Ka?
Small(er) Ka?
3. Kb and pKb
π΅π΅(ππππ) + π»π»2 ππ(ππ) β π΅π΅π»π» + (ππππ) + π»π»ππ− (ππππ)
[π΅π΅π»π» + (ππππ)][π»π»ππ− (ππππ)]
πΎπΎππ =
[π΅π΅(ππππ)]
Large(r) Kb?
Small(er) Kb?
π¨π¨− (ππππ) + π―π―ππ πΆπΆ(ππ) β π―π―π―π―(ππππ) + π―π―π―π―− (ππππ)
[π»π»π»π»(ππππ)][π»π»π»π»− (ππππ)]
πΎπΎππ =
[π΄π΄− (ππππ)]
Chemistry 144
Dr K de Villiers
Weak Acids & Bases
4. Ion product of water, Kw
πΎπΎπ€π€ = [π»π» + ][πππ»π» − ] = 1.0 × 10−14 (ππππ 25 β)
ππππ. ππππ = ππππ + ππππππ
πΎπΎππ × πΎπΎππ = [π»π» + (ππππ)][π»π»π»π»− (ππππ)] = πΎπΎππ
ππππ. ππππ = πππ²π²ππ + πππ²π²ππ
Large(r) Ka?
5. Acid-base conjugate pairs
Chemistry 144
Dr K de Villiers
6. Salt solutions
πΊπΊπΊπΊπΊπΊπΊπΊ = πͺπͺπͺπͺπͺπͺπͺπͺπͺπͺπͺπͺ+ + π¨π¨π¨π¨π¨π¨π¨π¨π¨π¨−
NO EFFECT
Cation
+
ACIDIC (↓ pH)
NO EFFECT
Anion¯
BASIC (↑ pH)
Weak Acids & Bases
Chemistry 144
Dr K de Villiers
Weak Acids & Bases
IN CLASS QUESTION
Determine the pH of a 0.20 M solution of NH4Cl (Kb (NH3) = 1.8 × 10-5).
Before you do the calculation, do you expect the pH to be acidic, neutral or basic? Why?
I
C
E