1. Given here is the joint probability mass function ππππππ (π₯π₯, π¦π¦) y 0 1 2 Total 0 0.38 0.14 0.24 0.76 x 1 0.17 0.02 0.05 0.24 Total 0.55 0.16 0.29 1 a) b) c) d) e) f) Find πΉπΉππππ (1, 2). What is the interpretation of this value? Find marginal distributions of X and Y. Are X and Y independent? Find conditional distributions of X|Y=2 and Y|X=1 Find E[X|Y=2] and Var[X|Y=2], and E[Y|X=1] and Var[Y|X=1] Find covariance and correlation coefficient of X and Y a) b) c) d) e) f) g) Find the probabilities ππππππ (3,1) and ππ[ππ < 3, ππ > 1]. Find the conditional probabilities ππ[ππ = 3 | ππ = 1] and ππ[ππ = 2 | ππ < 3]. Find the joint cdf of X anf Y, πΉπΉππππ (π₯π₯, π¦π¦). Find the marginal probability mass functions of X and Y Are X and Y independent? Explain. Compute πΈπΈ[ππ | ππ = 1] and ππππππ[ππ | ππ = 1]. Compute the πΆπΆπΆπΆπΆπΆ(ππ, ππ) and the correlation coefficient ππππππ . 2. Let the joint probability mass function of X and Y be π₯π₯π¦π¦ 2 ππππππ (π₯π₯, π¦π¦) = οΏ½ 30 π₯π₯ = 1,2,3, π¦π¦ = 1,2 0 ππ. π€π€. [Hint: you can start by presenting ππππππ (π₯π₯, π¦π¦) in form of a table] 3. Let X and Y be discrete random variables such that 3π₯π₯ + 2π¦π¦ π₯π₯ = 1 or 2, π¦π¦ = π₯π₯ + 1 or π₯π₯ + 2 ππ[ππ = π₯π₯, ππ = π¦π¦] = οΏ½ 42 0 ππ. π€π€. a) Find the marginal probability mass functions of X and Y b) Compute πΈπΈ[ππ | ππ = 3] and ππππππ[ππ | ππ = 3]. c) Compute the πΆπΆπΆπΆπΆπΆ(ππ, ππ) and the correlation coefficient ππππππ . 4. Let 2 2 )ππ −π₯π₯ , 0 ≤ π₯π₯ < ∞, − π₯π₯ ≤ π¦π¦ < π₯π₯ ππππππ (π₯π₯, π¦π¦) = οΏ½ππ(π₯π₯ − π¦π¦ 0 ππππβππππππππππππ [Hint: you may choose to use Gamma function to compute some of the integrals] a. Find c. b. Find the probability ππ[ππ > 2ππ]. c. Find πΈπΈ[ππππ]. d. Find the joint c.d.f. of X and Y, πΉπΉππππ (π₯π₯, π¦π¦). e. Find the marginal densities ππππ (π₯π₯) and ππππ (π¦π¦). f. Are X and Y independent? Explain. g. Find the conditional densities ππππ|ππ=π¦π¦ (π₯π₯) and ππππ|ππ=π₯π₯ (π¦π¦). h. Find the probability ππ[ππ > 1/2|ππ = 1]. i. Find πΈπΈ[ππ|ππ = 1]. j. Find πΆπΆπΆπΆπΆπΆ(ππ, ππ) and the correlation coefficient ππππππ . 5. The joint density function of X and Y is given by a. b. c. d. e. f. g. h. i. ππππππ (π₯π₯, π¦π¦) = οΏ½πππππ¦π¦ 0 2 π₯π₯ − 1 ≤ π¦π¦ ≤ 1 − π₯π₯, 0 ≤ π₯π₯ ≤ 1 elsewhere Find ππ. Find πΉπΉππππ (1/2, 1/2). Find πΉπΉππππ (1/2, 2). Find P(X > Y). Find marginal densities of X and Y. Find conditional densities of ππ|ππ = π¦π¦ and ππ|ππ = π₯π₯. Find πΈπΈ[ππ|ππ = π¦π¦] and πΈπΈ[ππ|ππ = π₯π₯]. Are X and Y independent? Find covariance and correlation coefficient of X and Y 6. The amount of time, T, between the occurrence and the reporting of an accident has pdf 8π‘π‘ − π‘π‘ 2 0 < π‘π‘ < 6 ππππ (π‘π‘) = οΏ½ 72 0 ππ. π€π€. Given that T=t, the amount of time between the reporting of the accident and the payment by the insurance company is uniformly distributed on [2+t, 10]. Compute the probability that the amount of time between the occurrence of the accident and the payment by the insurance company is less than 4. 7. Assume that X, Y, and Z are random variables, with E(X) = 2, E(Y) = −1, E(Z) = 4, Var(X) = 4, Var(Y) = 6, Var(Z) = 8, Cov(X, Y) = 1, Cov(X, Z) = −1, Cov(Y, Z) = 0. Find E(3X + 4Y – 6Z) and V(3X + 4Y – 6Z). 8. Let X and Y be independent random variables with ππππ = 1, ππππ = −1, ππππ2 = 0.5, and ππππ2 = 2. Compute πΈπΈ[(ππ + 1)2 (ππ − 1)2 ]. 9. Assume that X~Uniform[0, t], where t is exponentially distributed with mean π½π½. Find E[X] and Var[X]. 10. The Weibull density function is given by π¦π¦ ππ 1 ππ−1 − πΌπΌ ππ ππππ (π¦π¦) = οΏ½πΌπΌ πππ¦π¦ 0 π¦π¦ > 0 ππππππππππβππππππ where α and m are positive constants. Suppose Y has the Weibull density just given. Find the density function of ππ = ππ ππ . [Hint: notice that y>0, and use the method of transformations (justify first!!!).] 11. Let X and Y be independent standard normal random variables and U = X and V =X + Y. a. Derive the joint density of U and V. b. Are U and V independent? Why or why not? 12. X is a random variable with probability density function −2π₯π₯ ππππ (π₯π₯) = οΏ½ππ 4π₯π₯ 2ππ Let ππ = ππ 2 . Find the probability density function of T. 13. Random variables X and Y have joint density function π₯π₯ ≥ 0 π₯π₯ < 0 2 0 ≤ π₯π₯ ≤ π¦π¦ ≤ 1 ππππππ (π₯π₯, π¦π¦) = οΏ½ 0 ππ. π€π€. Let ππ = 1/ππ . Find the probability density function of Z. ππ ππ 14. Suppose that X follows a uniform distribution on the interval οΏ½− , οΏ½. Find the cdf and density of 2 2 ππ(ππ) = π‘π‘π‘π‘π‘π‘(ππ). 15. If the radius of a circle is an exponential random variable, find the density function of the area. 16. Let X and Y be jointly continuous random variables. a. Develop an expression for the joint density of X + Y and X − Y . b. Develop an expression for the joint density of XY and Y/X. c. Specialize the expressions from parts (a) and (b) to the case where X and Y are independent. 17. Let ππ1 , ππ2 , … , ππππ be independent identically distributed variables with common density function −(π₯π₯−ππ) π₯π₯ > ππ ππππ (π₯π₯) = οΏ½ππ 0 ππππβππππππππππππ for some positive constant ππ. Find a. The density function for ππ = ππ(1) = min{ππ1 , ππ2 , … , ππππ } b. πΈπΈοΏ½ππ(1) οΏ½ 18. Let X and Y be identically distributed independent random variables such that the moment generating function of X + Y is ππππ+ππ (π‘π‘) = 0.09ππ −2π‘π‘ + 0.24ππ −π‘π‘ + 0.34 + 0.24ππ π‘π‘ + 0.09ππ 2π‘π‘ Calculate P[X ≤0]. 19. X and Y are independent random variables with common moment generating function π‘π‘ 2 ππ(π‘π‘) = ππ 2 Let ππ = ππ + ππ and ππ = ππ − ππ. Determine the joint moment generating function, ππππππ (π π , π‘π‘), of W and Z. 20. Let L be the number of students who attend office hours on any given day. L follows Poisson distribution with mean 5. Using Chebyshev’s inequality, find the upper bound of ππ[|πΏπΏ − 5| ≥ 10] 21. A random variable X that assumes only nonnegative values has πΈπΈ[ππ] = 16 and ππππππ[ππ] = 36. Provide the upper bound of the probability ππ[ππ > 46]. Review all examples in Lecture Notes Review every problem on HW1 – HW6 Review every problem on Exam 1 Review every problem on Exam 1 Practice Problems