Q(1)
clear all
clc
a=11; b=9;
%could be one long expression
s=sqrt(b^2+16*a^2);
Labc = s/2 + b^2/(8*a)*log((4*a+s)/b)
Conclusion
Labc =
24.5637
Q(2)
clear,
clc
V=14; R1=120.6; R2=119.3; R3=121.2; R4=118.8;
Vab=V*(R1*R3-R2*R4)/((R1+R3)*(R3+R4))
Conclusion
Vab =
0.1071
Q(3)
clear,
clc
T0=98.6; Ts=69; T1=79.5; T2=78; hr=9; min=18;
p=log((T1-Ts)/(T0-Ts))/log((T2-Ts)/(T0-Ts));
d=p/(1-p);
t1=9+18/60;
t_d=t1-d;
PM_hd=floor(t_d)
PM_md=round(60*(t_d-PM_hd))
Conclusion
PM_hd =
2
PM_md =
35
CW1: Student ID: UPXXXXXX
Q(4)
clear, clc
rOA=[2,5,1];
rOB=[1,3,6];
rOC=[-6,8,2];
rAC=rOC-rOA;
Volume=dot(rOB,cross(rOC,rAC))
Conclusion
Volume =
248
Q(5)
clear,
clc
g=9.81;
v0=162;
alp=70;
t=1:5:31;
x=v0*cosd(alp)*t;
y=v0*sind(alp)*t - g*t.^2/2;
r = sqrt(x.^2+y.^2)
teta = atand(y./x)
Conclusion
r=
1.0e+03 *
0.1574 0.8083 1.2410 1.4759 1.5564 1.5773 1.7176
teta =
69.3893 65.7152 60.5858 53.0831 41.6187 24.0270 0.1812
Q(6)
close all
clc
R=0.08206;
T=300;
n=1;
a=1.39;
b=0.0391;
V=0.1:.02:1;
P_id=n*R*T./V;
P_v=n*R*T./(V-n*b)-n^2*a./V.^2;
e=100*(P_id-P_v)./P_v;
[m ind]=max(e);
max_e=m
at_vol=V(ind)
1
CW1: Student ID: UPXXXXXX
Conclusion
max_e =
4.2359
at_vol =
0.2400
Q(7)
clear,
clc
Re=[3 1 1 2 1; 1 2 1 3 1; 1 1 0 3 3; 2 0 3 1 2; 1 2 3 0 2];
ps=16*[128 118 112 112 104]';
res=Re\ps
Conclusion
res =
320.0000
224.0000
192.0000
256.0000
160.0000
Q(8)
clear,
clc
V1=40;
V2=30;
V3=36;
R1=16; R2=20; R3=10; R4=14; R5=8; R6=16; R7=10; R8=15; R9=6; R10=4;
A=[-(R1+R2+R3) R2 R3 0 0; R2 -(R2+R4+R5+R6) R5 R6 R4; ...
R3 R5 -(R3+R5+R7) R7 0; 0 R6 R7 -(R6+R7+R8+R9) R8; ...
0 R4 0 R8 -(R4+R8+R10)];
V=[-V1 0 -V2 V3 V1]';
I=A\V %[ I1,I2,I3,I4,I5]
2
CW1: Student ID: UPXXXXXX
Conclusion
I=
0.7406
-0.6047
0.6161
-1.5316
-2.1649
Q(9)
clear,
clc
vrun=3;
vsw=1;
L=48;
ds=30;
dw=42;
y=20:1:48;
ls = sqrt(y.^2+ds^2);
lw = sqrt((L-y).^2+dw^2);
t=ls/vrun + lw/vsw;
[tmin ind] = min(t);
min_t=t(ind)
y_at_min=y(ind)
pi = atan(y_at_min/ds);
alpha = atan((L-y_at_min)/dw);
sin_rat=sin(pi)/sin(alpha)
speed_rat=vrun/vsw
Conclusion
min_t =
59.2946
y_at_min =
37
sin_rat =
3.0658
speed_rat =
3
3
CW1: Student ID: UPXXXXXX
Discussion: The minimum time is 59.29 seconds with the lifeguard entering the water at 37 m. Snell’s
law seems only approximately satisfied, but this is due to the relatively large increment in y. The ratio
converges to Snell’s law as the increment decreases.
Q(10)
close all
clc
L0=.0254; % L0 in meter
r0=.0064; % r0 in meter
A0=pi*r0^2;
F=[0 13031 21485 31963 34727 37119 37960 39550 ...
40758 40986 41076 41255 41481 41564];
L=[25.4 25.474 25.515 25.575 25.615 25.693 25.752 25.978 ...
26.419 26.502 26.600 26.728 27.130 27.441]/1000;
sigmae=F/A0; ee=(L-L0)/L0;
sigmat=F.*L/(A0*L0); et=log(L/L0);
plot(ee,sigmae,et,sigmat,'--')
title('S-S Def')
legend('Eng','T','loc','S_E')
xlabel('Strain')
ylabel('Stress, Pa')
Conclusion
4
CW1: Student ID: UPXXXXXX
Q(11)
close all
clc
t=0:.01:4;
x=4.219*(exp(-1.58*t)-exp(-6.32*t));
v=26.67*exp(-6.32*t)-6.67*exp(-1.58*t);
subplot(2,1,1)
plot(t,x,'r')
title('Railroad Bumper Response')
ylabel('Position, m')
subplot(2,1,2)
plot(t,v,'b')
ylabel('Speed, m/s')
xlabel('Time, s')
Conclusion
5
CW1: Student ID: UPXXXXXX
Q(12)
close all
clc
for j=1:2
W=input('Please input your weight in lb:
h=input('Please input your height in in:
BMI=703*W/h^2;
if BMI<18.5
fprintf('\nYour BMI value is %.1f, which
asunderweight\n\n',BMI)
elseif BMI<25
fprintf('\nYour BMI value is %.1f, which
elseif BMI<30
fprintf('\nYour BMI value is %.1f, which
overweight\n\n',BMI)
else
fprintf('\nYour BMI value is %.1f, which
end
end
');
');
classifies you
classifies you as normal\n\n',BMI)
classifies you as
classifies you as obese\n\n',BMI)
Conclusion
Please input your weight in lb:
Please input your height in in:
Q(13)
close all
clc
disp('Part (a)')
S=[160, -40, 60]; th=20;
disp('Stress in x''-y'' coordinate system in MPa')
Stran = StressTrans(S,th)
disp('Part (b)')
S=[-18, 10, -8]; th=20;
disp('Stress in x''-y'' coordinate system in ksi')
Stran = StressTrans(S,65)
function Stran = StressTrans(S,th)
Stran(1)=0.5*(S(1)+S(2)) + 0.5*(S(1)-S(2))*cosd(2*th) + S(3)*sind(2*th);
Stran(2)=S(1)+S(2)-Stran(1);
Stran(3)=-0.5*(S(1)-S(2))*sind(2*th) + S(3)*cosd(2*th);
end
6
CW1: Student ID: UPXXXXXX
Conclusion
Part (a)
Stress in x'-y' coordinate system in MPa
Stran =
175.1717 -55.1717 -18.3161
Part (b)
Stress in x'-y' coordinate system in ksi
Stran =
-1.1293 -6.8707 15.8669
Q(14)
close all
clc
t=linspace(0,10,100);
r=8+0.6*t;
phi=5*pi*t/180;
theta=8*pi*t/180;
x=r.*cos(phi).*cos(theta);
y=r.*cos(phi).*sin(theta);
z=r.*sin(phi);
plot3(x,y,z,'k','linewidth',1)
grid on
xlabel('x (m)'); ylabel('y (m)'); zlabel('z (m)')
view(45,30)
Conclusion
7
CW1: Student ID: UPXXXXXX
Q(15)
close all
clc
p=15;
rd=3;
E=10E6; t=0.08; nu=0.3;
K=E*t^3/(12*(1-nu^2));
K1=330;%K in MPa
C=p*rd^4/(64*K);
[th,r] = meshgrid((0:5:90)*pi/180,0.02:0.01:0.14);
[X,Y] = pol2cart(th,r);
Sx=K1./sqrt(2*pi*r).*cos(th/2).*(1-sin(th/2).*sin(3*th/2));
Sy=K1./sqrt(2*pi*r).*cos(th/2).*(1+sin(th/2).*sin(3*th/2));
Sxy=K1./sqrt(2*pi*r).*cos(th/2).*sin(th/2).*cos(3*th/2);
mesh(X,Y,Sx)
xlabel('x (in.)'), ylabel('y (in.)'), zlabel('Sx (ksi)')
Conclusion
8