45-45-90
45: k
90: k√2
30-60-90
30: k
60: k√3
90: 2k
45: 1
90: √2
a ​^ ​x​ = ​n​ → log ​a​ ​n​ = ​x
A = Pe^rt
*continuously
A = P (1 + r/n)^nt
*annual
(always years, not months bc its annual)
30: 1
60: √3
90: 2
positive, odd: ​falls to the left, rise to the right
positive, even:​ ​rise to the right and left
negative, odd: ​rise to the left, fall to the right
negative, even:​ falls to the left and the right
# of powers = # of roots you should have at the end
V​ertical ​A​symptotes = set denominator to ​zero
H​orizontal ​A​symptotes = degree of the numerator ​must​ be bigger than the denominator → if not it is ​0
* if it is deg. num. > deg. denom. then it is ​none
* if it is deg num. = deg. denom. then you ​divide the coefficients
S​lant ​A​symptotes = numerator degree is ​one​ more than that of the denominator degree (if then, perform synthetic division
and only take the quotient, disregard the remainder.
before you hand in check:
* CHECK BRACKETS - ​hard brackets on domain/range quantities with # instead of infinite signs
* ​CHECK SIGNS - ​remember to switch the sign when dividing by negative numbers
* ​ABSOLUTE VALUE PROBLEMS - ​absolute value problems cannot equal negative numbers - don’t start them if they
equal ​“-x”
DEGREES
SIN
COS
TAN
0
0
1
0
30
1/2
√3 / 2
1 / √3
45
√2 / 2
√2 / 2
1
60
√3 / 2
1/2
√3 / 2
90
1
0
UD
180
0
-1
0
270
-1
0
UD
360
0
1
0
-90
-1
0
UD