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CSUN Chem 101 Exam2 with Answers

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General Chemistry, CHEM 101
Exam 1, 04/13/2021 @08:00 AM
Exam duration is 45 minutes
The exam needs to be uploaded to Canvas in one single PDF file by 08:55 am
Honor code statement: I certify that the work is my own, and I did not open the textbook, notes, or
any other source during the time of this exam. Signature _______________
Problem 1. (30 points)
Part 1 (10 pnts)
What volume is occupied by 10.019 mol of helium gas at a pressure of 1 atm and a temperature of 298
K? R=0.08206 (L x atm/mol x K)
Answer:
Part 2 (20 pnts)
A wine-dispensing system uses argon canisters to pressurize and preserve wine in the bottle.
 An argon canister for the system has a volume of 50.0 mL and contains 20.0 g of argon.
Assuming ideal gas behavior, what is the pressure in the canister at 295 K?

When the argon is released from the canister, it expands to fill the wine bottle. How many
750.0-mL wine bottles can be purged with the argon in the canister at a pressure of 1.20 atm
and a temperature of 295 K?
Consider the atomic mass of Argon=40 g, and the gas constant R=0.08206 (L x atm/mol x K)
Answer:


, We need to find
0.5 mol
= 10.086 L=10086 mL
Page 1/3
Problem 2. (30 points)
Part 1 (10 pnts)
How much heat is required to warm 0.50 L of water from 50.0 °C to 100.0 °C?
The density of water is 1.0 g/mL, and the specific heat capacity of water is Cs=4.18 (J/g.°C)?
Answer
(
)
PART 2 (20 pnts). Consider the following reaction
CH4(g) + 2 O2(g)  CO2(g) + 2 H2O(g)
Write the explicit three intermediate steps, then calculate H°of the overall reaction?
Answer:
Decomposition: CH4(g) → C(s, graphite) + 2 H2(g)
Formation 2a: C(s, graphite) + O2(g) → CO2(g)
Formation 2b: 2 H2(g) + O2(g) → H2O(g)
H°f = + 70 kJ
Hf°= −400 kJ/mol CO2
2×H°f
−500 kJ
H°reaction = -500 kJ−400 kJ + 70 kJ=-830 kJ
Page 2/3
Problem 3. (40 points) Record your answers in the table below, or make a similar table
1. No two electrons can have
the same four quantum
numbers is known as the
A) Pauli exclusion principle
B) Hund's rule
C) Aufbau principle
D) Heisenberg uncertainty
principle
D)
1s22s22p63s23p64s24p5
C)
D)
E)
2. Only two electrons, with
opposing spins, are allowed
in each orbital is known as
the
A) Pauli exclusion principle
B) Hund's rule
C) Aufbau principle
D) Heisenberg uncertainty
principle
3. Choose the orbital diagram
that represents the ground
state of N.
A)
B)
C)
D)
5. Which of the following
statements is TRUE?
A) An orbital that penetrates
into the region occupied by
core electrons is less shielded
from nuclear charge than an
orbital that does not penetrate
and therefore has a lower
energy.
B) An orbital that penetrates
into the region occupied by
core electrons is more
shielded from nuclear charge
than an orbital that does not
penetrate and therefore has a
lower energy.
C) It is possible for two
electrons in the same atom to
have identical values for all
four quantum numbers.
D) Two electrons in the same
orbital can have the same
spin.
E) None of the above are
true.
7. An electron at the 3p1
which set of quantum
numbers it has
A) N=3, L=1, mL=0, ms=+1/2
B) N=2, L=1, mL=1, ms=-1/2
C) N=3, L=2, mL=1, ms=+1/2
D) N=3, L=1, mL=2, ms=-1/2
8. The shape of the S orbital
is:
A) A dot
B) A square
C) A triangle
D) A sphere
_______________________
Question #
1.
2.
3.
4.
5.
6.
7.
8.
Answer
A
C
A
A
A
C
A
D
E)
Give the complete
electronic configuration for
Mn (it has 25 electrons).
A)
1s22s22p63s23p64s24d5
B)
1s22s22p63s23p64s13d6
C)
1s22s22p63s23p64s23d5
6.
4. Choose the valence orbital
diagram that represents the
ground state of Zn.
A)
B)
Page 3/3
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