Lesson 12.1: Intro to Sequence and Recursion Learning Goals: 1) What is a sequence? What notation do we use? 2) What is a recursive sequence and how can we find the ππ‘β term of it? Sequence: a list of numbers or objects in a specific order Example 1: 3, 7, 11, 15, 19, 23, … Example 2: 0, 2, 0, 2, 0, 2, … Example 3: Terms: each member of a sequence 3, 7, 11, 15, 19, 23, … 0, 2, 0, 2, 0, 2, … 1st term = 3 1st term = 0 1st term = 1 4th term = 15 4th term = 2 4th term = 7 1 Sequences A sequence is a function whose domain is a set of positive integers. If a domain is not specified, it is understood that the domain starts with 1. The values in the range are called the terms of the sequence. A finite sequence has a limited number of terms. π=1 2 3 4 An infinite sequence continues without stopping. ππ = 2 4 6 8 Finite sequence: 2, 4, 6, 8 Infinite sequence: 2, 4, 6, 8, … A sequence can be specified by an equation, or rule. For example, both sequences above can be described by the rule ππ = 2π or π(π) = 2π π3 = 2(3) = 6 or π(4) = 2(4) = 8 Example 1: Write the first six terms of ππ = 2π+1 the formula is the rule for the sequence! π=1 π=2 π=3 π=4 π=5 π=6 21+1 22+1 23+1 24+1 25+1 26+1 π2 = 8 π3 = 16 π4 = 32 π1 = 4 π5 = 64 π6 = 128 {4, 8, 16, 32, 63, 128} 2 Example 2: Write the first 4 terms of the sequence: ππ = 1+(−1)π π π=1 π=2 π=3 π=4 1+(−1)1 1+(−1)2 1+(−1)3 1+(−1)4 1 2 3 4 π1 = 0 π2 = 1 π3 = 0 π4 = 1 2 1 {0, 1, 0, } 2 Find the indicated term of the sequence: 3. ππ = (−1)π (3π − 2) 4. π (π) = π25 = (−1)25 (3(25) − 2) π(11) = π25 = (−1)(75 − 2) π(11) = π25 = −73 π(11) = 4π 2π2 −3 4(11) 2(11)2 −3 44 2(121)−3 44 239 Writing the Rule for Sequences 3 Describe the pattern, write the next term, and write a rule for the πth term of the sequence {2, π=1 4, 6, 8, … } 2 3 4 {2, π=1 ×2 ↓ ×2 ↓ ×2 ↓ ×2 ↓ ππ = 2 4 6 3, 4, 5, … } 2 3 4 +1 ↓ +1 ↓ +1 ↓ +1 ↓ 8 ππ = 2 ππ = 2π or π(π) = 2π 3 4 5 ππ = π + 1 or π(π) = π + 1 5. Describe the pattern, write the next term, and write a rule for the πth term of the sequence. a) 1, π=1 4, 9, 16, … 2 3 4 ^2 ↓ ^2 ↓ ππ = 1 ^2 ↓ ^2 ↓ 4 9 16 ππ = π2 or π(π) = π2 1 1 c) { , , 1 , 1 3 9 27 81 π=1 ππ = 2 1 3π b) 0, 7, 26, 63, … π=1 2 3 4 ↓ ↓ ↓ ↓ 7 26 63 ππ = 0 ππ = π3 − 1or π(π) = π3 − 1 ,…} 3 4 or π (π) = 1 3π 6. The diagrams below represent the first three terms of a sequence. Assuming the pattern continues, which formula determines ππ , the number of shaded squares in the πth term? (1) ππ = 4π + 12 (2) ππ = 4π + 8 (3) ππ = 4π + 4 (4) ππ = 4π + 2 4 Vocabulary: Explicit Rule: a formula that defines a sequence 2, 4, 6, 8, … (sequence) ππ = 2π or π(π) = 2π (explicit rule) Recursive Rule: a formula that requires the computation of the previous term in order to find the next term of a sequence. (1) starting term (2) rule that uses previous term The example below is a recursive sequence because you need the first term to find the second term. π1 = −4 ππ = ππ−1 + 5 π1 = −4 π2 = π2−1 + 5 = π1 + 5 = −4 + 5 = 1 π3 = π3−1 + 5 = π2 + 5 = 1 + 5 = 6 π4 = π4−1 + 5 = π3 + 5 = 6 + 5 = 11 5 Finding Terms of Recursive Sequences 7. Write the first four terms of the recursive sequence given below: π1 = 2 ππ = ππ−1 − 3 π1 = 2 π2 = π2−1 − 3 = π1 − 3 = 2 − 3 = −1 π3 = π3−1 − 3 = π2 − 3 = −1 − 3 = −4 π4 = π4−1 − 3 = π3 − 3 = −4 − 3 = −7 8. Write the first five terms of the recursive sequence given below: π(1) = 4 π(π) = 2π(π − 1) π(1) = 4 π(2) = 2π(2 − 1) = 2π(1) = 2(4) = 8 π(3) = 2π(3 − 1) = 2π(2) = 2(8) = 16 π(4) = 2π(4 − 1) = 2π(3) = 2(16) = 32 π(5) = 2π(5 − 1) = 2π(4) = 2(32) = 64 9. For the recursively defined sequence π‘π = (π‘π−1 )2 + 2 and π‘1 = 2 the value of π‘4 is (1) 18 (2) 38 (3) 456 (4) 1446 π‘1 = 2 π‘2 = (π‘2−1 )2 + 2 = (π‘1 )2 + 2 = 22 + 2 = 4 + 2 = 6 π‘3 = (π‘3−1 )2 + 2 = (π‘2 )2 + 2 = 62 + 2 = 36 + 2 = 38 π‘4 = (π‘4−1 )2 + 2 = (π‘3 )2 + 2 = 382 + 2 = 1444 + 2 = 1446 6 Homework 12.1: Intro to Sequence and Recursion 1. Given the sequence 7, 11, 15, 19, …, which of the following represents a formula that will generate it? (1) π(π) = 4π + 7 (2) π(π) = 3π + 4 (3) π(π) = 3π + 7 (4) π(π) = 4π + 3 2. Determine and label the first four terms of each of the following sequences. 2 (a) ππ = π − 5 2 π (b) π‘(π) = ( ) 3 (c) π‘π = 1 π+1 3. Which of the following formulas would represent the sequence 10, 20, 40, 80, 160, … (1) ππ = 10π (2) ππ = 10(2)π (3) ππ = 5(2)π (4) ππ = 2π + 10 4. Write an algebraic expression that represents ππ for each sequence. (a) 3, 9, 27, 81, … (b) 1 1 1 1 , , , ,… 2 3 4 5 (c) 1, √2, √3, 2, … 5. A recursive sequence is defined by ππ+1 = 2ππ − ππ−1 with π1 = 0 and π2 = 1. Which of the following represents the value of π5 ? (1) 8 (2) −7 (3) 3 (4) 4 7 6. Sequences below are defined recursively. Determine and label the next three terms of the sequence. (a) π1 = 5, ππ = ππ−1 + 1 (b) π1 = −2, ππ = −2ππ−1 (c) ππ = ππ−1 + 2π with π1 = 5 7. Sean has started an exercise program. The first day he worked out for 30 minutes. Each day for the next six days, he increased his time by 5 minutes. (a) Write a sequence for the number of minutes that Sean worked out for each of the seven days. (b) Write a recursive definition for this sequence. 8. A pattern of blocks is shown below. If the pattern of blocks continues, which formula(s) could be used to determine the number of blocks in the πth term? I ππ = π + 4 (1) I and II (2) I and III II III π1 = 2 ππ = 4π − 2 ππ = ππ−1 + 4 (3) II and III (4) III, only 8 12.2: Arithmetic and Geometric Sequences Learning Goals: 1) What is an arithmetic sequence? What is the common difference of an arithmetic sequence? 2) How can we find the πth term of an arithmetic sequence? 3) What is a geometric sequence? What is the common ratio of a geometric sequence? 4) How can we find the πth term of a geometric sequence? Arithmetic Sequence: a sequence where you are adding a fixed amount from one term to the next 1, 3, 5, 7, 9, … adding 2 4, 2, 0, −2, −4 subtracting 2 Common Difference: (π = π2 − π1 ) the fixed amount added to get to the next term. 1, 3, 5, 7, 9, … π = 2 4, 2, 0, −2, −4 π = − 2 π = 3 − 1 = 2 or d = 9 − 7 = 2 π = 2 − 4 = −2 or d = −4 − (−2) = −2 Identify Arithmetic Sequences: Example 1: Tell whether the sequence −5, −3, −1, 1, 3, … is arithmetic. Find the differences of consecutive terms. π2 − π1 = −3 − (−5) = 2 π3 − π2 = −1 − (−3) = 2 π4 − π3 = 1 − (−1) = 2 π5 − π4 = 3 − 1 = 2 Arithmetic because you add 2 to get the next term! Arithmetic sequences can be represented by a linear scatter plot. π· = −5, −3, −1, 1, 3, … π = 2, 4, 6, 8, … 9 RULE FOR AN ARITHMETIC SEQUENCE The πth term of an arithmetic sequence with the first term π1 and common difference π is given by: ππ = π1 + (π − 1)π On Reference Sheet! Example 2: Write a rule for the πth term of the sequence. Then find π19 a. 2, 9, 16, 23, … π1 = 2 Common Difference: π = π2 − π1 = 9 − 2 = 7 or π3 − π2 = 16 − 9 = 7 ππ = π1 + (π − 1)π ππ = 7π − 5 ππ = 2 + (π − 1)7 π19 = 7(19) − 5 ππ = 2 + 7π − 7 π19 = 128 ππ = 7π − 5 b. 57, 45, 33, 21, … π1 = 57 Common Difference: π = π2 − π1 = 45 − 57 = −12 or π3 − π2 = 33 − 45 = −12 ππ = π1 + (π − 1)π ππ = −12π + 69 ππ = 57 + (π − 1)(−12) π19 = −12(19) + 69 ππ = 57 − 12π + 12 π19 = −159 ππ = −12π + 69 Example 3: One term of an arithmetic sequence is π11 = 41. The common difference is π = 5. Write a rule for the πth term. π11 = 41 so π = 11 π = 5 π1 =? ππ = π1 + (π − 1)π ππ = π1 + (π − 1)π π11 = π1 + (11 − 1)5 ππ = −9 + (π − 1)5 41 = π1 + (10)5 or ππ = −9 + 5π − 5 41 = π1 + 50 or ππ = 5π − 14 π1 = −9 10 Geometric Sequence: a sequence where you are multiplying by a fixed amount from one term to the next Common Ratio: (π = π2 π1 6 54 2 18 1 3 )the fixed amount multiplied to get to the next term 18, 6, 2 … 2, 6, 18, 54, … r = 3 π = = 3 or multiplying by 18, 6, 2 … 2, 6, 18, 54, … multiplying by 3 =3 π= 6 18 = r= 1 3 or 1 3 2 6 = 1 3 Geometric because you multiply to get the next term! Geometric sequences can be represented by an exponential scatter plot. π· = 1, 2, 3, 4, … π = 1, 2, 4, 8, … Identify Geometric Sequences: Example 1: Tell whether the sequence 1, −4, 16, −64, 256, … is geometric. To decide whether a sequence is geometric, find the ratios of consecutive terms. π2 π1 = −4 1 = −4 π3 π2 = 16 −4 = −4 π4 π3 = −64 16 = −4 π5 π4 = 256 −64 = −4 Geometric because you multiply by −4 to get to the next term. RULE FOR A GEOMETRIC SEQUENCE The πth term of a geometric sequence with the first term π1 and common ratio π is given by: ππ = π1 π π−1 On Reference Sheet! 11 Example2: Write a rule for the πth term of the sequence 972, −324, 108, −36, … Then find π10 . 1 Geometric because you multiply by − . π= 3 −324 972 = −36 108 =− 1 3 ππ = π1 π π−1 1 π−1 ππ = 972 (− ) 3 1 10−1 π10 = 972 (− ) 3 1 9 4 3 81 = 972 (− ) = − Example 3*: One term of a geometric sequence is π3 = −18. The common ratio is π = 3. Write a rule for the πth term. ππ = π1 π π−1 ππ = π1 π π−1 π3 = π1 (3)3−1 ππ = (−2) (3)π−1 −18 = π1 (3)2 −18 = 9π1 π1 = −2 12 Homework 12.2: Arithmetic and Geometric Sequences 1. Does the following pair of formulas represent the same sequence? Justify your reasoning. ππ+1 2 = ππ , 3 π0 = −1, 2 π ππ = − ( ) , 3 and for π ≥ 0 2. A sequence has the following terms: π1 = 4, π2 = 10, π3 = 25, π4 = 62.5. Which formula represents the πth term in the sequence? (1) ππ = 4 + 2.5π (2) ππ = 4 + 2.5(π − 1) (3) ππ = 4(2.5)π (4) ππ = 4(2.5)π−1 3. Which arithmetic sequence has a common difference of 4? (1) {0, 4π, 8π, 12π, … } (2) {π, 4π, 16π, 64π, … } (3) {π + 1, π + 5, π + 9, π + 13, … } (4) {π + 4, π + 16, π + 64, π + 256, … . } 4. An arithmetic sequence has a first term of 10 and a sixth term of 40. What is the 20th term of this sequence? (1) 105 (2) 110 (3) 124 (4) 130 5. What is the fourth term of the sequence defined by π1 = 3π₯π¦ 5 and 2π₯ (1) 12π₯ 3 π¦ 3 ππ = ( ) ππ−1 ? π¦ (2) 24π₯ 2 π¦ 4 6. What is the common ratio of the sequence (1) − 3π 2π2 (2) − 6π π2 (3) − 3π2 π (4) − 1 64 (3) 24π₯ 4 π¦ 2 π5 π 3 , − 3 32 (4) 48π₯ 5 π¦ π3 π 4 , 9 16 ππ 5 , …? 6π2 π 7. What is the common ratio of the geometric sequence whose first term is 27 and the fourth term is 64? (1) 3 4 (2) 64 81 (3) 4 3 (4) 37 3 13 Lesson 12.3: Recursive Sequences vs. Explicit Form Learning Goal: How do we write a recursive sequence in explicit form and vice versa? Write the first four terms of the recursive sequence given below: π1 = −1 ππ = 2ππ−1 + π π2 = 2π2−1 + 2 = 2π1 + 2 = 2(−1) + 2 = −2 + 2 = 0 π3 = 2π3−1 + 3 = 2π2 + 3 = 2(0) + 3 = 0 + 3 = 3 π4 = 2π4−1 + 4 = 2π3 + 4 = 2(3) + 4 = 6 + 4 = 10 Notation: Recursive forms work with the term(s) immediately in front of the term being examined. The table shows that there are many options as to how this relationship may be expressed in notations. A recursive formula is written with two parts: a statement of the first term along with a statement of the formula relating successive terms. The statements below are all naming the same sequence: π1 = 1; π1 = 1; ππ = ππ−1 + 4 ππ−1 = ππ + 4 π(1) = 1; π(π) = π(π − 1) + 4 π(1) = 1; π(π + 1) = π(π) + 4 *For multiple choice questions, you need to know that all of these mean the same thing! 14 Rewrite the given sequence 3 other ways, using the notation in the above example. π1 = −6 π1 = 2 ππ+1 = ππ + 5 ππ = 3ππ−1 π(1) = −6 π(1) = 2 π(π + 1) = π(π) + 5 π(π + 1) = 3π(π) π(1) = −6 π(1) = 2 π(π) = π(π − 1) + 5 π(π) = 3π(π − 1) π1 = −6 π1 = 2 ππ = ππ−1 + 5 ππ+1 = 3ππ Arithmetic! Adding 5 Geometric! Multiply by 3 Converting from Recursive to Explicit Use the following explicit formulas with π1 as the first term (Use for π ≥ 1) ARITHMETIC SEQUENCE: ππ = π1 + (π − 1)π GEOMETRIC SEQUENCE: ππ = π1 π π−1 Example 1: Convert each of the following recursive formulas to explicit formulas. Identify each sequence as arithmetic, geometric, or neither. a. ππ = 4ππ−1 with π1 = 12 Geometric because you multiply by 4 to get the next term! π1 = 12 & π = 4 ππ = π1 π π−1 = 12(4)π−1 b. ππ = 4.2 + ππ−1 with π1 = 12 Arithmetic because you add 4.2 to get the next term! π1 = 12 & π = 4.2 ππ = π1 + (π − 1)π = 12 + (π − 1)(4.2) 15 c. ππ+1 = √5 ππ with π1 = 2 Geometric because you multiply by √5 to get the next term! π1 = 2 & π = √5 ππ = π1 π π−1 = 2(√5)π−1 d. ππ+1 = √5 + ππ with π1 = 2 Arithmetic because you add √5 to get the next term! π1 = 2 & π = √5 ππ = π1 + (π − 1)π = 2 + (π − 1)(√5) Convert from Explicit to Recursive Use the following recursive formulas (MEMORIZE) ARITHMETIC SEQUENCE: Subscript notation: π1 = π₯ and ππ = ππ−1 + π GEOMETRIC SEQUENCE: Subscript notation: π1 = π₯ and ππ = ππ−1 π Function notation: π(1) = π₯ and π(π) = π(π − 1)π Function notation: π(1) = π₯ and π(π) = π β π(π − 1) Example2: Write each sequence in recursive form. 1 a. ππ = (3π ) for π ≥ 0 so use π = 0 for the 1st term (π0 ) 5 1 1 5 5 1 3 5 5 1 9 5 5 π0 = (30 ) = π1 = (31 ) = π2 = (32 ) = Geometric because you multiply by 3 to get the next term! π0 = 1 5 & π=3 ππ = 3ππ−1 16 b. ππ = 16 − 2π for π ≥ 1 so use π = 1 for the 1st term (π1 ) π1 = 16 − 2(1) = 14 π2 = 16 − 2(2) = 12 π3 = 16 − 2(3) = 10 Arithmetic because you add −2 to get the next term! π1 = 14 & π = −2 ππ = ππ−1 − 2 1 π c*. ππ = 16 ( ) 2 for π ≥ 1 so use π = 1 for the 1st term (π1 ) 1 1 π1 = 16 ( ) = 8 2 1 2 π2 = 16 ( ) = 4 2 1 3 π3 = 16 ( ) = 2 2 1 π1 = 8 & π = Geometric because you multiply by to get the next term! 2 1 2 1 ππ = ππ−1 2 6 d*. ππ = 71 − π for π ≥ 0 so use π = 0 for the 1st term (π0 ) 7 6 497 7 7 π0 = 71 − (0) = 71 = 6 491 7 7 6 485 7 7 π1 = 71 − (1) = π2 = 71 − (2) = 6 Arithmetic because you add − to get the next term! 7 ππ = ππ−1 − π0 = 71 & π = − 6 7 6 7 17 Example 3: At her job, Pat earns $25,000 the first year and receives a raise of $1,000 each year. The explicit formula for the nth term of this sequence is ππ = 25,000 + (π − 1)1000. Write a rule to represent the equivalent recursive formula of this sequence. π1 = 25000 ππ = ππ−1 + 1000 Example 4: The initial value of a specialty toy is $3,000, and its value each of the following years is 20% less. Write an explicit formula and a recursive formula to model this sequence. 20% less means they have 80% left π1 =3000 π=0.80 explicit: ππ = 3000(0.80)π−1 Recursive: π1 =3000 ππ =0.80(ππ−1 ) Example 5: The last row of an auditorium has 2500 seats, and each row before it has 80 fewer seats than the row behind it. Write an explicit formula and a recursive formula to model the sequence. explicit: ππ = 2500 + (π − 1)(−80) Recursive: π1 =2500 ππ =ππ−1 −80 18 Homework 12.3: Recursive Sequences vs. Explicit Form 1. Write each recursive sequence in explicit form. Identify each sequence as arithmetic, geometric, or neither. a. π1 = 3, ππ+1 = ππ + 5 b. π1 = √2, ππ = ππ−1 √2 2. Which of the following formulas is equivalent to the geometric sequence modeled by the equation ππ = 5(2)π−1 ? (1) π1 = 5, ππ+1 = 2ππ (3) π1 = 10, ππ+1 = 2ππ (2) π1 = 2, ππ+1 = 5ππ (4) π1 = 5, ππ+1 = (ππ )2 3. If a geometric sequence has π1 = 256 and π8 = 512, find the exact value of the common ratio π. 4. Given the sequence 7, 11, 15, 19, … write an explicit formula to represent this sequence. 5. Which recursively defined function has a first term equal to 10 and a common difference of 4? (1) π(1) = 10, π(π₯) = π(π₯ − 1) + 4 (2) π(1) = 4, π(π₯) = π(π₯ − 1) + 10 (3) π(1) = 10, π(π₯) = 4π(π₯ − 1) (4) π(1) = 4, π(π₯) = 10π(π₯ − 1) 19 6. The recursive formula, π2 = 18.5, ππ = ππ−1 + 1.5 models the number of people, in millions, that own a smartphone in the U.S. π years after 2014. a. Write an equivalent explicit formula for the situation. b. Find the value of π5 using both the recursive formula and the explicit formula. Explain what π5 means in the context of the problem. 7. In an arithmetic sequence of numbers π1 = −4 and π6 = 46. Find the value of π12 . 8. Given that π1 = 5 and π2 = 15 are the first two terms of a geometric sequence, determine the values of π3 and π10 . Show the calculations that lead to your answers. 9. The formula below can be used to model which scenario? π1 = 2000 ππ+1 = ππ + 50 (1) (2) (3) (4) The last row of a concert hall has 2000 seats and each row before has 50 less seats than the one after it. The first row of a concert hall has 2000 seats and each row after has 50 more seats than the previous row. A bank account starts with a deposit of $2000 and it grows each year by 50%. A used car is worth $2000 to start and depreciates by 50% each subsequent year. 20 Lesson 12.4: Summation Notation Learning Goals: 1) What is summation notation? How can we evaluate the sum of a finite series given in summation notation? 2) How can we write a series in summation notation? Summation Notation ο· The summation of a specific number of terms of a sequence (a series) can also be represented in a compact form, called summation notation, or sigma notation. ο· The Greek capital letter sigma, ∑ , is used to indicate a sum. ο· Given a sequence π1 , π2 , π3 , π4, … we can write the sum of the first π terms of the sequence using the expression: π ∑ ππ = π1 + π2 + π3 + β― + ππ π=1 ο· It is read, “The sum of ππ from π = 1 to π = π. ο· Example: 5 ∑ 2π = 2(1) + 2(2) + 2(3) + 2(4) + 2(5) = 2 + 4 + 6 + 8 + 10 = 30 π=1 ο· To write the terms of the series, replace π by the consecutive integers from 1 to 5, as shown above. 2nd → stat → math → sum(5) & 2nd → stat → ops → seq 2π₯, π₯, 1, 5 21 Example 1: Write the sum without using summation notation. You do not need to find the sum. π π ∑π = 0+1+2+3+4+5 ∑ π π = 52 + 62 + 72 π=π π=π π ∑ π=π π 1 1 1 = + + π 2 3 4 π is not an imaginary unit in this example! π ∑ πππ−π = (1π₯ 1−1 ) + (2π₯ 2−1 ) + (3π₯ 3−1 ) + (4π₯ 4−1 ) + (5π₯ 5−1 ) + (6π₯ 6−1 ) π=π = 1 + 2π₯ + 3π₯ 2 + 4π₯ 3 + 5π₯ 4 + 6π₯ 5 Example 2: Write the sum without using summation notation, and find the sum. 4 ∑ 2π + π₯ π π=0 = (2(0) + π₯ 0 ) + (2(1) + π₯ 1 ) + (2(2) + π₯ 2 ) + (2(3) + π₯ 3 ) + (2(4) + π₯ 4 ) (2 + π₯) + (4 + π₯ 2 ) + (6 + π₯ 3 ) + (8 + π₯ 4 ) = (0 + 1) + = 21 + π₯ + π₯ 2 + π₯ 3 + π₯ 4 3 ∑(−4)π−2 = (−4)0−2 + (−4)1−2 + (−4)2−2 + (−4)3−2 π=0 = (−4)−2 + (−4)−1 + (−4)0 + (−4)1 = = 1 1 + +1−4 (−4)2 (−4) 1 1 51 + −3=− 16 −4 16 22 3 ∑ π β 3π = 102 math → 0: summation π=1 3 3 ∑ π β 3π = 3(102) = 306 just multiply the answer by 3 What if … π=1 4 ∑ log ( π=1 π ) = −.6987 π+1 4 What if … 3 + ∑ log ( π=1 π ) = 3 − .6987 = −2.3010 just add 3 to the final sum π+1 Example 3: Write each sum using summation notation. Strategies: ο· See if sequence is arithmetic or geometric→if it is you can find the explicit formula for the sequence ο· If the sequence is not arithmetic or geometric, try to look for other patterns ο· Look to see if numbers are “famous” numbers like perfect squares or cubes ο· ∑ππ=1 ππ 2 + 4 + 8 + 16 + β― + 512 π1 = 2 & π = 2 ππ = π1 π π−1 512 = 2(2)π−1 256 = 2π−1 get like “bases” ∑9π=1 2(2)π−1 28 = 2π−1 8=π−1 π=9 π Example 4: What is the value of 3 ∑6π=2 ? 2 (1) 10 (2) 13 (3) 30 (4) 60 23 Homework 12.4: Summation Notation 1. Write the sum without using summation notation, and find the sum. a. 3 ∑ π=0 105 2π + 1 b. 5 ∑(−1)π π₯ π π=0 c. 4 3 π ∑ 16 ( ) 2 π=1 2. Which of the following represents the sum of a geometric sequence? (1) ∑5π=1(2π + 2π ) (2) ∑6π=2 2(3π−1 ) (3) ∑6π=3(3π + 1) (4) ∑6π=2(2π2 ) 3. Write each sum using summation notation. a. 2 + 4 + 6 + 8 + β― + 100 b. 12 + 22 + 32 + 42 + β― + 100002 c. 1 1β2 + 1 2β3 + 1 3β4 + β―+ 1 49β50 24 Lesson 12.5: Geometric Series Learning Goal: What is a geometric series and how do we evaluate it? Do Now: Answer the following questions in order to prepare for today’s lesson. Geometric Sequence: ππ = ππ β ππ−π 1. Given the geometric sequence: −375, −75, −15, −3, … a. Write the formula for the πth term of the geometric sequence. π= −75 −375 = 1 π−1 1 ππ = −375 ( ) 5 5 b. Use the formula to find the 7th term of the sequence. π = 7 1 7−1 π7 = −375 ( ) 5 = −.024 = − 3 125 c. Find the sum of the first 7 terms of this sequence. 3 3 5 25 −375, −75, −15, −3, − , − OR ππ = π1 −π1 1−π ππ ,− 3 sum = −468.744 125 1 7 = −375−(−375)(5) 1 1−5 = −468.744 GEOMETRIC SERIES (on Reference Sheet) To find the sum of a certain number of terms of a geometric sequence: π1 − π1 π π ππ = 1−π Where ππ = the sum of π terms, π1 = the first term, and π = the common ratio 1. Find the sum of the first 8 terms of the sequence: −5, 15, −45, 135, … ο· Why is this a geometric sequence/series? Because you are multiplying by −3 ππ = π1 −π1 π π 1−π π8 = −5−(−5)(−3)8 1−(−3) = 8200 25 2. Given the geometric series: {−6 + 9 − 27 2 + β― } find the sum of the first 11 terms. ο· How do you find the common ratio? −6, 9, − ππ = π1 −π1 π π 1−π = −6−(−6)(−1.5)11 1−(−1.5) =− 27 2 ,… π= 9 −6 = −1.5 107517 512 3. Find the sum of the following summation notations by using the geometric series formula. π−1 ∑10 π=1 4(3) ππ = ππ = π1 π π−1 form so it is geometric! π1 −π1 π π 1−π = 4−4(3)10 1−3 = 118096 GEOMETRIC SERIES (need to find number of terms) ο· If you need to find the number of terms in a geometric series, use the geometric sequence formula to find "π". GEOMETRIC SEQUENCE: ππ = π1 π π−1 GEOMETRIC SERIES π1 − π1 π π ππ = 1−π 4. Calculate the sum of the geometric series: 4 + 12 + β― + 972. ππ = π1 π π−1 972 = 4(3) π−1 243 = 3π−1 ππ = ππ = π1 −π1 π π 1−π 4−4(3)6 1−3 ππ = 1456 35 = 3π−1 5=π−1 π=6 26 1 1 1 1 2 4 8 512 5. Calculate the sum of the geometric series: 1 − + − + β― − ππ = π1 π π−1 − − − ππ = 1 π−1 1 512 1 512 19 = 1 (− ) =− =− 2 ππ = 2 1π−1 ππ = 2 π1 −π1 π π 1−π 1 1−1(− )10 2 1 1−(−2) 341 512 1π−1 2 9=π−1 π = 10 6. Calculate the sum of the geometric series: 1 + √3 + 3 + 3√3 + β― + 243 π10 1 10 1 − 1 (− ) 341 2 = = 1 512 1 − (− ) 2 7*. The sum of a geometric series with four terms is 60, and the common ratio is 1 π = . Find the first term. 2 ππ = π1 −π1 π π 1−π = π1 (π−π π ) ππ = 60, π = 4, π = 1−π 1 2 14 π1 (1 − ) 2 60 = 1 1− 2 1 30 = π1 (1 − ) 16 π1 = 32 27 Homework 12.5: Geometric Series 1. Find the sum of the first 8 terms of the sequence: −12, −48, −192, −768, … π−1 2. Find the sum ∑12 by using the geometric series formula. π=1 6(−2) 3. Calculate the sum of the geometric series: 0.8 + 0.64 + 0.512 + β― + 0.32768 4. A geometric sequence has all its terms positive. The first term is 810 and the fifth term is 10. Find the common ratio. 5. The sum of a geomtric series with seven terms is −10,922, and the common ratio is π = 4, Find the first term. 6. The sixth term of an arithmetic sequence is 24. The common difference is 8. Calculate the first term of the sequence. 28 Lesson 12.6: Geometric Series Word Problems Learning Goal: How do we use the geometric series formula when working with word problems? Do Now: Answer the following question in order to prepare for today’s lesson. 1. What are the formulas for exponential growth and decay? What do the variables represent in each formula? Growth: π΄ = π(1 + π)π‘ Decay: π΄ = π(1 − π)π‘ π΄ = final amount, π = initial amount, π = rate, π‘ = time π΄ = final amount, π = initial amount, π = rate, π‘ = time 2. A computer valued at $6500 depreciates at the rate of 14.3% per year. a. Write a function that models the value of the computer after π years. Decay: π΄ = π(1 − π)π‘ Geometric! π΄ = 6500(1 − .143)π ππ = π1 π π−1 π΄ = 6500(.857)π b. Find the value of the computer after three years. π = 3 π΄ = 6500(.857)3 = $4091.25 1 3. A geometric sequence has a first term of 36 and a common ration of . 3 a. Write a geometric series formula, ππ , to represent this sum over π terms. ππ = π1 −π1 ππ 1−π 1 π = 36−36(3) 1 1−3 b. Use this formula to find the sum of the first 15 terms. 1 15 π15 = 36−36(3) 1 1−3 = 53.99999624 29 GEOMETRIC SEQUENCES WITH PERCENTAGES GEOMETRIC SEQUENCE FORMULA To find any term of a geometric sequence: ππ = π1 π π−1 Where ππ = the πth term, π1 = the first term, and π = the common ratio ο· If a question refers to a percent, this means you are dealing with a geometric sequence. ο· When given a percent, the common ratio is the percent remaining of the previous term. ο· Growth: π΄ = π(1 + π)π‘ & Decay: π΄ = π(1 − π)π‘ Example: Identify the common ratio in each situation. a. A certain water filtration system can remove 70% of the contaminants each time a sample of water is passed through it. Decay! 1 − π = 1 − .70 = .30 = π b. John’s salary earns an increase of 4% each successive year. Growth! 1 + π = 1 + .04 = 1.04 = π c. A basketball is dropped vertically. The height of each subsequent bounce is 90% of the previous bounce. Decay! Decreases by 10% 1 − π = 1 − .10 = .90 = π 1. A fan is running at 10 revolutions per second. After it is turned off, its speed decreased at a rate of 75% per second. Find an explicit formula for the sequence that represents the number of revolutions after π seconds. Geometric ππ = π1 π π−1 π1 = 10 π = 1 − .75 = .25 ππ = 10(. 25)π−1 30 2. Suppose you drop a tennis ball from a height of 15 feet. After the ball hits the floor, it rebounds to 85% of its previous height. Write an explicit formula for the sequence. Geometric Decrease by 15% ππ = π1 π π−1 π1 = 15 π = 1 − .15 = .85 ππ = 15(. 85)π−1 GOMETRIC SERIES WORD PROBLEMS ππ = the sum of π terms, π1 = the first term, and π = the common ratio GEOMETRIC SERIES ππ = π1 − π1 π 1−π π 3. George has taken a job with a starting salary of $50,000 and receives an annual raise of 2%. Write a geometric series formula, π π , for George’s total earnings over π years. ππ = ππ = π1 −π1 π π π1 = 50000 1−π π = 1 + .02 = 1.02 π =? 50000−50000(1.02)π 1−1.02 Use this formula to find George’s total earnings for his first 12 years of working, to the nearest cent. ππ = 50000−50000(1.02)12 1−1.02 = $670604.49 4. The first swing of a pendulum travels 40 centimeters. Each subsequent swing travels 95% as far as the previous swing. Write a geometric series formula, π π , for the pendulum’s total distance over π swings. It decreases by 5% ππ = ππ = π1 −π1 π π 1−π π1 = 40 π = 1 − .05 = .95 π =? 40−40(.95)π 1−.95 Use this formula to find the pendulum’s total distance after the 30th swing, to the nearest tenth of a centimeter. ππ = 40−40(.95)30 1−.95 = 628.3 31 PUTTING IT ALL TOGETHER 5. A car with an original price of $30,000 depreciates by 30% each year. a. Write an explicit formula for the price of the car after π years. Decreases by 30% ππ = π1 π π−1 = 30000(.70)π−1 b. Write a recursive formula, the price of the car after π years. π1 = 30000 ππ = 0.7ππ−1 c. Write a geometric series formula, π π , for the car’s total price over π years. ππ = 30000−30000(.70)π 1−.70 6. Kristin wants to increase her running endurance. According to experts, a gradual mileage increase of 10% per week can reduce the risk of injury. If Kristin runs 8 miles in week one, which expression can help her find the total number of miles she will have run over the course of her 6-week training program? (1) ∑6π=1 8(1.10)π−1 (2) ∑6π=1 8(1.10)π (3) 8−8(1.10)6 0.90 (4) 8−8(0.10)π 1.10 1 + .10 = 1.10 32 Homework 12.6: Geometric Series Word Problems 1. Alexa earns $33,000 in her first year of teaching and earns a 4% increase in each successive year. Write a geometric series formula, ππ , for Alexa’s total earnings over π years. Use this formula to find Alexa’s total earnings for her first 15 years of teaching, to the ππππππ π‘ ππππ‘. 2. The tuition fees for the first three years of high school are given in the table below. These tuition fees form a geometric sequence. (a) Find the common ratio, π, for this sequence. (b) If fees continue to rise at the same rate, calculate (to the nearest dollar) the total cost of tuition fees for the first six years of high school. 33 3. A basketball is dropped vertically. It reaches a height of 2 cm on the first bounce. The height of each subsequent bounce is 90% of the previous bounce. (a) What height does it reach on the 8th bounce? (b) What is the total vertical distance travelled by the ball between the first and sixth time the ball hits the ground? 4. The sum of a geometric series with seven terms is 13,116, and the common ratio is π = 3. Find the first term. 5. A theater has 35 seats in the first row. Each row has four more seats than the row before it. Which expression represents the number of seats in the πth row? (1) 35 + (π + 4) (2) 35 + (4π) (3) 35 + (π + 1)(4) (4) 35 + (π − 1)(4) 34