Heat Transfer Equation Sheet Conduction: qx = - kA ππππ ππππ Convection: q = hA(Ts - T∞) Radiation: ©2015 J. M. Hill Heat Exchangers: ΔTLM = {(THo – TCo) - (THi – TCi)}/{ln[(THo – TCo)/ (THi – TCi)]} Parallel flow q = UA ΔTLM ΔTLM = {(THo – TCi) - (THi – TCo)}/{ln[(THo – TCi)/ (THi – TCo)]} Counter flow qr = εAσT4 NTU = UA/Cmin ε = q/qmax qmax = Cmin (THi – TCi) Cr = Cmin/Cmax Diffusion equations: ππ 2 ππ πππ₯π₯ 2 1 ππ ππ 2 ππ + πππ¦π¦ 2 + ππππ ππ 2 ππ πππ§π§ 2 1 ππ ππΜ 1 ππππ + ππ = πΌπΌ ππππ ππππ (ππ ππππ ) + ππ 2 ππππ (ππππ) + ππ ππππ ππ 2 ππ πππ§π§ 2 uniform properties, α = ππΜ 1 ππππ ππ πππΆπΆππ + ππ = πΌπΌ ππππ Cylindrical coordinates ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ ππ = Ohms Law Analogy, Plane wall: π π π‘π‘,ππππππππ = Cylinder: π π π‘π‘,ππππππππ = πΏπΏ ππππ π₯π₯π₯π₯ , π π π‘π‘,ππππππππ = ππ ln( 2οΏ½ππ1 ) 2ππππππ Ts = T∞ + ππΜ L/h Generation: Plane wall, π π π‘π‘ 1 βπ΄π΄ Cylinder, T(r) = 1 , π π π‘π‘,ππππππππ = 2ππππππβ ππ− πππ π ππππ −πππ π ππΜ ππππ2 4ππ (1 − ππ ππ 2 ππππ2 To = Ts + ππΜ L2/(2k) ) + Ts T s = T∞ + = 1 – ( )2 ππ− ππππ πππ π −ππππ = (x/L)2 ππΜ ππππ 2β ππππ ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ Fins of uniform cross section: θ = T - T∞ M = (hPkAc)½θb ππ = ππππ ππ −ππππ Infinite fin: Adiabatic tip: Active tip: ππππ = ππ ππ = ππππ cosh[ππ(πΏπΏ−π₯π₯)] cosh(ππππ) ππ = ππππ (βοΏ½ππππ ) sinh[ππ(πΏπΏ−π₯π₯)]+cosh[ππ(πΏπΏ−π₯π₯)] (βοΏ½ππππ) sinh(ππππ)+cosh(ππππ) ππ = Prescribed tip: All fins: m2 = hP/kAc ππππ = ππ π‘π‘π‘π‘π‘π‘β(ππππ) ππ ( πΏπΏοΏ½ππ ) sinh(ππππ)+sinh[ππ(πΏπΏ−π₯π₯)] ππ ππππ sinh(ππππ) Effectiveness, ππππ ππππ = βπ΄π΄ ππ ππππ Efficiency, ππππ = ππππ = ππππ = ππ ππππ βπ΄π΄ππ ππππ ππ cosh(ππππ)−( πΏπΏοΏ½ππ ) ππ ππ sinh(ππππ) sinh(ππππ)+(βοΏ½ππππ)cosh(ππππ) cosh(ππππ)+(βοΏ½ππππ)sinh(ππππ) -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- Lumped Capacitance: Bi = hLc/k < 0.1 Fo = αt/(Lc)2 ππ−ππ∞ ππππ −ππ∞ = ππ −π‘π‘/πππ‘π‘ ππt = πππππΆπΆππ βπ΄π΄π π Q = πππππΆπΆππ ππππ (1 - ππ −π‘π‘/πππ‘π‘ ) ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- Semi-infinite solid: imposed temperature: ππ−πππ π = erf( π₯π₯ ) ππππ −πππ π 2√πΌπΌπΌπΌ -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- Finite difference methods: ππ+1 Explicit, 1-D unsteady: ππππ ππ ππ ππ Fo = αΔt/(Δx)2 ≤ ½ for stability = Fo(ππππ+1 +ππππ−1) + (1 – 2Fo) ππππ ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- Convection, Steady flow over a flat plate: Pr = Cpμ/k = μ/(ρα) Laminar: δ = 5x Rex-1/2 Cf,x = 0.664 Rex-1/2 Mixed laminar and turbulent for Rex,c < Rex < 108: Mixed laminar and turbulent with Rex,c = 5x105: Rex = ρu∞x/μ -1/2 οΏ½οΏ½οΏ½οΏ½οΏ½ πΆπΆ ππ,πΏπΏ = 1.328 ReL δ = 0.37x Rex-1/5 Nux = hx/kf Nux = 0.332 Rex1/2 Pr1/3 Cf,x = 0.0592 Rex-1/5 οΏ½οΏ½οΏ½οΏ½οΏ½ πΆπΆππ,πΏπΏ = 0.074 ReL-1/5 -1742/ ReL Note: If the laminar region is small, the constants 1742 and 871 in the above equations become zero. οΏ½οΏ½οΏ½οΏ½οΏ½ πππππΏπΏ = 0.664 ReL1/2 Pr1/3 Nux = 0.0296 Rex4/5 Pr1/3 οΏ½οΏ½οΏ½οΏ½ = (0.037Re L4/5 – 871)Pr1/3 ππππ