Moving Straight Ahead: Linear Relationships Name: ______________________ Per: _____ Investigation 3: Solving Equations 7.EE.B.4: Use variables to represent quantities in the real world or mathematical problem, and construct simple equations and inequalities to solve problems by reasoning about the quantities. Date Learning Target/s Day 1-Wed, Feb. 1 Solve visual equations with one variable. Day 2-Thurs, Feb. 2 Write and solve symbolic equations with one variable. Solve symbolic equations with one variable. Day 3-Fri. Feb. 3 Day 4- Mon. Feb. 6 Solve symbolic equations with one variable. Day 5-Tues. Feb. 7 Solving inequality equations with one variable Create and solve word problems involving inequalities Day 6-Wed. Feb 8th Classwork Homework (Check Off Completed/ Corrected Items) (Check Off Completed/ Corrected Items) MSA 3.2 p. 2-3 Exploring Equalities: Coins & Pouches MSA 3.3 p. 5-6 Writing Equations Complete CW p. 2-3 MSA Inv 3 Day 1 p. 4 Correct with the EDpuzzle MSA Inv 3 Day 2 p. 7 Correct with the KEY MSA 3.4 Pg. 8-9: Solving Equations MSA Inv 3 Day 3 p. 10 Correct with the EDpuzzle Additional practice Pg. 11-12 Solving linear equations Exit Ticket 2 Additional practice p. 13-14 on solving 2 step-inequalities MSA 3.5: p. 16 INEQUALITY WORD PROBLEMS MSA Inv 3 Day 4 Complete and correct the classwork with the KEY MSA Inv 3 Day 5 p. 15 Correct with the KEY MSA Inv 3 Day 6 Complete the classwork and correct with the KEY Self-Assess Your Understanding of the Learning Target/s I have reviewed with a parent/guardian and I am satisfied with the work produced in this packet. Student signature: ________________________________________ Parent/Guardian Signature:__________________________________ 1 Day 1 MSA 3.2: EXPLORING EQUALITY - Mystery Pouches in the Kingdom of Montarek In the Kingdom of Montarek, money takes the form of $1 gold coins called rubas. Messengers carry money between the king’s castles in sealed pouches that always hold equal numbers of coins. One day a messenger arrived at one of the castles with a box containing two sealed pouches and five loose $1 coins. The ruler thanks the messenger for the money, which equaled $11. Does the following visual equation help in finding the number of coins in each pouch? Visual Equation Remember: Each pouch contains the same number of $1 gold coins. The total number of coins on each side of the equation is the same. Find the number of gold coins in each pouch. Write down your steps so that someone else could follow your steps to find the number of coins in a pouch. Describe how you can check your answer. That is, how do you know you have found the correct number of gold coins in each pouch? 1. 2. 3. 2 4. 5. 6. Challenge: In Visual Equation 2, Nichole thought of the left-hand side of the situation as having two groups. Each group contained one pouch and two coins. She visualized the following steps to help her find the number of coins in a pouch. Is Nichole correct? Explain. Noah looked at Nichole’s strategy and claimed that she was applying the Distributive Property. Is Noah’s claim correct? Explain. Are there other situations in which Nichole’s method might work? Explain. 3 Day 1 Homework: MSA 3.2: Complete and CORRECT with the EDpuzzle. Visual Equation Remember: Each pouch contains the same number of $1 gold coins. The total number of coins on each side of the equation is the same. Find the number of gold coins in each pouch. Write down your steps so that someone else could follow your steps to find the number of coins in a pouch. Describe how you can check your answer. That is, how do you know you have found the correct number of gold coins in each pouch? 1. 2. 3. 4. 4 Day 2 MSA 3.3: WRITING EQUATIONS Because the number of gold coins in each pouch is unknown, you can let x represent the number of coins in one pouch. You can let 1 represent the value of one gold coin. You can write the following equation to represent the situation: 2x + 4 = 12 Or, you can use Nichole’s method from Problem 3.2 to write this equation: 2(x+2) = 12 The expressions 2x + 4 and 2(x +2) are _______________________ expressions. Two or more expressions are equivalent if they have the same value, regardless of what number is substituted for the variable. These two expressions are an example of the Distributive Property for numbers. 2(x+2) = 2x +4 In this problem, you will revisit situations with pouches and coins, but you will use symbolic equations to represent your solution process. A. Visual Equation Description of Steps for Finding the Coins in Each Pouch Symbolic Equation Use x to represent the number of gold coins in each pouch Use the number 1 to represent each coin Remember the Balance Check 1. 2. 3. 5 4. B. Work backwards from the Symbolic Equation to complete the table Visual Equation Each x represents a pouch Each 1 represents a coin Description of Steps for Finding the Coins in Each Pouch Symbolic Equation Remember the Balance Check 3x = 12 2x+5=19 4x+5=2x+19 X+12=2x+6 3(x+4)=18 6 Inv 3 Day 2 Homework: Complete and CORRECT with the KEY 7 Day 3 MSA 3.4: SOLVING EQUATIONS To maintain the equality of two expressions, you can add, subtract, multiply or divide each side of the equality by the same number. These are called the properties of equality. In the last problem, you applied properties of equality and numbers to find a solution to an equation. So far in the Investigation, all of the situations have involved positive whole numbers. What strategies do you have for solving an equation like -2x + 10 = 15? 1. For each problem, record each step you take to find your solution and then check your answer. 5x + 10 = 20 5x – 10 = 20 5x + 10 = -20 5x – 10 = -20 Balance Check 10 –x = 20 Balance Check Balance Check Balance Check Balance Check 10 – 5x = -20 How do you solve a symbolic equation? Balance Check How do you check to make sure your equation is balanced? 8 2. For each problem, record each step you take to find your solution and then check your answer. 𝑥 ¼ x + 6 = 12 3/5 = -x + 15 −(2𝑥 − 15) = 3𝑥 + 15 = 12 7 Balance Check Balance Check Balance Check Balance Check 15 – 4x = 10x + 45 3(x + 1) = 21 2 + 3(x + 1) = 6x -2(2x – 3) = -2 Balance Check Balance Check Balance Check Balance Check 9 Day 3 Homework MSA 3.4: Complete and CORRECT with the EDpuzzle 1. Solve each equation. Check your answers. 2x + 6 = 6x + 2 2x – 6 = -6x + 2 2x + 6 = 6x – 2 -2x – 6 = -6x – 2 Balance Check: Balance Check: Balance Check: Balance Check: 2. Solve each equation. Check your answers. (Remember to use the Distributive Property) 3(x+2) = 12 3(x+2) = x – 18 3(x+2) = 2x Balance Check: Balance Check: Balance Check: Balance Check: 10 Day 4: ADDITIONAL PRACTICE 11 12 Day 5 MSA 3.5: SOLVING INEQUALITIES Tips to remember graphing inequalities: 1) < and > will have an ______________ dot. 2) ≤ 𝑎𝑛𝑑 ≥ will have a ________________dot. 3) When multiplying or dividing what do you do to the sign?___________________________ Solve the inequality Graph the inequality 3x+8>2 Test point: 7x-1<20 Test point: 8 − 4𝑥 ≥ −12 Test point: −5𝑥 − 9 ≥ −4 Test point: −10 + 2𝑥 ≤ −𝑥 + 11 Test point: 13 𝑥 − 13 < −23 7 Test point: −𝑥 + 2 ≤ −12 8 Test point: −3𝑥 − 7 > 2𝑥 − 23 Test point: 1 3 𝑥 + 13 < − 10 4 4 Test point: 8(2 + 𝑥) ≤ 3𝑥 − 9 Test point: 5(−3𝑥 − 1) + 7 ≤ −𝑥 − 10 Test point: 14 Day 5 Homework MSA 3.5: Complete and CORRECT with the KEY Multi-step equations and inequality practice −5 1 2 + 𝑥= 7 3 7 −𝑥 + 13 = 7 Balance check: Balance check: 6= 𝑎 +2 4 2(𝑛 + 5) = −2 Balance check: Balance check: Solve and graph: Solve and graph: 1+𝑚 >1 9 −2𝑟 − 2 ≤ 4 Test point: Test point: 15 Day 6 MSA 3.5: INEQUALITY WORD PROBLEMS At fabulous Fabian’s bakery, the expenses (E) to make n cakes per month is given by the equation E=825+3.25n. The income (I) for selling n cakes is given by the equation I=8.20n. A. What does the coefficient next to n in each equation represent? B. Fabian sells 100 cakes in January. 1. What are his expenses? Show your reasoning 2. What is his income? Show your reasoning. 3. What is his profit? Describe how you found your answer. 4. How many cakes can Fabian make if he wants his expenses to be less than $2,400 a month? Write an inequality and solve. 5. How many cakes can he make if he wants his income to be greater than $2,400 a month? Write an inequality and solve. C. For the following inequalities, find the number of cakes Fabian needs to make in a month. 1) 𝐸 < 1,475 2) 𝐼 > 1,640 16 Back in the day (around the time Mrs. Grow was your age and Ms. Pendley was still in diapers) cell phones were becoming increasingly popular. Different carriers offered different plans to their members and people had to use mathematical reasoning and inequalities to determine the best plan for their family (I wish I was kidding, but I am not). Driftless Region Telephone Company had a plan that charged a monthly rate of $10 and $.03 per text (there was no such thing as unlimited texting! The horror!). Walby Communications charged $7.50 a month plus $.04 cents a text. a. Predict: If you were paying for a plan what carrier would you choose and why? b. Write an equation that represents the scenario using the variable t for texts and d for dollars. Driftless Region Telephone: Walby Communications: c. At about what point is it less expensive to go with Walby Communications? At what point is it better to go with Driftless Region Telephone? Think about the “break even” point! Justify your reasoning. d. If you had a maximum of $15 to spend per month, what plan would you chose? Set up an inequality for both and solve, to determine the best plan. Driftless Region Telephone: Walby Communications: e. If you had a maximum of $25 to spend per month, what plan would you chose? Set up an inequality for both and solve, to determine the best plan. Driftless Region telephone: Walby Communications: 17 18