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AP Physics C Review
Mechanics
CHSN Review Project
This is a review guide designed as preparatory information for the AP1 Physics C
Mechanics Exam on May 11, 2009. It may still, however, be useful for other purposes
as well. Use at your own risk. I hope you find this resource helpful. Enjoy!
This review guide was written by Dara Adib based on inspiration from Shelun Tsai’s
review packet.
This is a development version of the text that should be considered a work-inprogress.
This review guide and other review material are developed by the CHSN Review
Project.
Copyright © 2009 Dara Adib. This is a freely licensed work, as explained in the Definition of Free Cultural Works (freedomdefined.org). Except as noted under “Graphic
Credits” on the following page, the work is licensed under the Creative Commons
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This review guide is provided “as is” without warranty of any kind, either expressed
or implied. You should not assume that this review guide is error-free or that it will
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this product.
1
“Why do we love ideal worlds? . . . I’ve been doing this for 38 years and school is an
ideal world.” — Steven Henning
Contents
Kinematic Equations
3
Free Body Diagrams
3
Projectile Motion
4
Circular Motion
4
Friction
5
Momentum-Impulse
5
Center of Mass
5
Energy
5
Rotational Motion
7
Simple Harmonic Motion
8
Gravity
9
Graphic Credits
• Figure 1 on page 3 is based off a public domain graphic by Concordia College and vectorized
by Stannered: http://en.wikipedia.org/wiki/File:Incline.svg.
• Figure 2 on page 3 is based off a public domain graphic by Mpfiz: http://en.wikipedia.
org/wiki/File:AtwoodMachine.svg.
• Figure 5 on page 7 is a public domain graphic by Rsfontenot: http://en.wikipedia.org/
wiki/File:Reference_line.PNG.
• Figure 6 on page 7 was drawn by Enoch Lau and vectorized by Stannered: http://en.
wikipedia.org/wiki/File:Angularvelocity.svg. It is licensed under the Creative Commons Attribution-Share Alike 2.5 license: http://creativecommons.org/licenses/by-sa/
2.5/.
• Figure 7 on page 8 is based off a public domain graphic by Mazemaster: http://en.wikipedia.
org/wiki/File:Simple_Harmonic_Motion_Orbit.gif.
• Figure 8 on page 9 is a public domain graphic by Chetvorno: http://en.wikipedia.org/
wiki/File:Simple_gravity_pendulum.svg.
2
Figure 1: Normal Force
Kinematic Equations
1
∆x = at2 + v0 t
2
Figure 2: Atwood’s Machine
∆v = at
(v)2 − (v0 )2 = 2a(∆x)
Figure 3: Draw a banked curve diagram
v0 + v
∆x =
×t
2
Pulled Weights
Free Body Diagrams
a=
F−f
Σm
N Normal Force
f Frictional Force
T = ma
T Tension
mg Weight
Elevator
Normal force acts upward, weight acts downward.
F = ma
• Accelerating upward: N = |ma| + |mg|
In a particular direction:
• Constant velocity: N = |mg|
ΣF = (Σm)a
• Accelerating downward: N = |mg| − |ma|
Atwood’s Machine2
a=
2 Pulley
Banked Curve
|(m2 − m1 )|g
m1 + m2
Friction can act up the ramp (minimum velocity
when friction is maximum) or down the ramp
(maximum velocity when friction is maximum).
videal =
and string are assumed to be massless.
3
p
rg tan θ
Range
s
vmin =
rg(tan θ − µ)
µ tan θ + 1
θ represents the smaller angle from the x-axis to
the direction of the projectile’s initial motion.
Starting from a height of x = 0:
s
vmax =
rg(tan θ + µ)
1 − µ tan θ
xmax =
Projectile Motion
Circular Motion
Position
Centripetal (radial)
(v0 )2 sin 2θ
g
Centripetal acceleration and force is directed towards the center. It refers to a change in direction.
∆x = vx t
1
∆y = − gt2 + (vy )0 t
2
ac =
v2
r
Velocity
Fc = mac =
θ represents the smaller angle from the x-axis to
the direction of the projectile’s initial motion.
mv2
r
Tangential
(vx )0 = v0 cos θ
Tangential acceleration is tangent to the object’s
motion. It refers to a change in speed.
(vy )0 = v0 sin θ
at =
d|v|
dt
∆vx = 0
Combined
∆vy = −gt
atotal =
q
(ac )2 + (at )2
Height
θ represents the smaller angle from the x-axis to Vertical loop
the direction of the projectile’s initial motion.
In a vertical loop, the centripetal acceleration is
Starting from a height of x = 0:
caused by a normal force and gravity (weight).
ymax =
(v0 sin θ)2
2g
4
Top
Elastic
Kinetic energy is conserved.
F = ma
N + mg = m ×
N =
v2
r
m1 v1 + m2 v2 = m1 v10 + m2 v20
mv2
− mg
r
−(v20 − v10 ) = v2 − v1
Bottom
Inelastic
F = ma
Kinetic energy is not conserved.
v2
N − mg = m ×
r
2
mv
+ mg
N =
r
m1 v1 + m2 v2 = (m1 + m2 )v0
Center of Mass
Friction
Friction converts mechanical energy into heat.
Static friction (at rest) is generally greater than
kinematic friction (in motion).
rcm =
λ=
fmax = µN
Σm =
p = mv
Z
dm =
λdx
(Σm)vCM = Σmv = Σp
dp
dt
Fnet = (Σm)aCM
Z
I=
dm
M
=
dx
L
Z
Momentum-Impulse
F=
Z
Z
1
1
Σmr
rdm =
xλdx
=
Σm
Σm
Σm
Energy
Fdt = F∆t = ∆p = m∆v
Work
Collisions
Z
Total momentum is always conserved when there
are no external forces (F = dp
dt = 0).
5
W=
Fdx = ∆K
Power
Pavg =
Fx
W
=
t
t
Pinstant =
dW
= Fv
dt
Kinetic Energy
Linear
1
K = mv2
2
Potential Energy
dU
F=−
dx
Z xf
∆U = −
FC dx = −WC
Z
UHooke
v=
dx
dt
=
∆x
∆t
ω=
dθ
dt
=
∆θ
∆t
a=
dv
dt
=
∆v
∆t
α=
dω
dt
=
∆ω
∆t
∆x = 12 at2 + v0 t
∆θ = 12 αt2 + ω0 t
∆v = at
∆ω = αt
(v)2 − (v0 )2 = 2a(∆x)
(ω)2 − (ω0 )2 = 2α(∆ω)
∆x =
xi
Z
1
= − FHooke dx = − −kxdx = kx2
2
Ug = mgh
equilibrium point F = − du
dx = 0 (extrema)
stable equilibrium U is a minimum
v0 + v
×t
2
∆θ =
ω0 + ω
×t
2
F = ma
Rx
W = x0 Fdx
τ = Iα
Rθ
Wrot = θ0 τdθ
W = 12 mv2 − 12 m(v0 )2
Wrot = 21 mω2 − 12 m(ω0 )2
P = Fv
Prot = τω
p = mv
L = Iω
F=
unstable equilibrium U is a maximum
Angular
dp
dt
τ=
Figure 4: Rotational Motion
Total
E = K+U
Ei + WNC = Ef
WNC represents non-conservative work that converts mechanical energy into other forms of energy. For example, friction converts mechanical
energy into heat.
6
dL
dt
Torque
τ = r × F = rF sin θ
τ = Iα
Moment of Inertia
Z
2
I = Σmr =
r2 dm
Figure 5: Arc Length
I = Icm + Mh2
(h represents the distance from the center)
Values
1
2
12 ml
1
2
3 ml
rod (center)
Figure 6: Angular Velocity
rod (end)
hollow hoop/cylinder mr2
Rotational Motion
1
2
2 mr
The same equations for linear motion can be mod- hollow sphere 2 mr2
3
ified for use with rotational motion (Figure 4 on
2
solid sphere 5 mr2
the previous page).
solid disk/cylinder
Atwood’s Machine
Angular Motion
θ=
s
r
ω=
v
r
α=
at
r
at = r
p
a=
|(m2 − m1 )|g
m1 + m2 + 12 M
Angular Momentum
L = Iω
L = r × p = rp sin θ = rmv sin θ
α2 + ω4
ac = ω2 r
τ=
1
1
Krolling = Iω2 + mv2
2
2
dL
dt
Total angular momentum is always conserved
when there are no external torques (τ = dL
dt = 0).
7
ω = 2πf
r
A=
(x0 )2 +
φ = arctan
v 2
0
ω
−v0
ωx0
1
E = kA2
2
Spring
Figure 7: Simple Harmonic Motion
Fs = −kx
Simple Harmonic Motion
r
Simple harmonic motion is the projection of uniform circular notion on to a diameter. Likewise,
uniform circular motion is the combination of
simple harmonic motions along the x-axis and
y-axis that differ by a phase of 90◦ .
Ts = 2π
r
ωs =
m
k
k
m
amplitude (A) maximum magnitude of displacePendulum
ment from equilibrium
cycle one complete vibration
Simple
period (T ) time for one cycle
s
frequency (f) cycles per time
T = 2π
angular frequency (ω) radians per time
r
x = Acos(ωt + φ)
ω=
A cable with a moment of inertia swings back
and forth. d represents the distance from the
pendulum’s pivot to its center of mass.
s
I
T = 2π
mgd
a = −ω2 A cos(ωt + φ) = −ω2 x
2π
1
=
ω
f
r
f=
g
L
Compound
v = −ωA sin(ωt + φ)
T=
L
g
1
ω
=
T
2π
ω=
8
mgd
I
frictionless pivot
Energy
amplitude θ
U=
massless rod
E=
bob's
trajectory
massive bob
equilibrium
position
−Gm1 m2
R
−GMm
2r
v=
Figure 8: Simple Pendulum
2πR
T
r
vescape =
Torsional
2GM
re
For orbits around the earth, re represents the raA horizontal mass with a moment of inertia is dius of the earth.
suspended from a cable and swings back and
forth.
r
T = 2π
ω=
I
k
k
I
Gravity
F=
−Gm1 m2
R2
G ≈ 6.67 × 10−11
Nm2
kg2
Kepler’s Laws
1. All orbits are elliptical.
2. Law of Equal Areas.
2
4π
3. T 2 = GM
R3 = Ks R3 , where Ks is a uniform
constant for all satellites/planets orbiting
a specific body
9
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