Physics Classwork
Ball thrown up vertically with speed 48/ms find 1-time for maximum
height 2-total time to ground 3-maximum height
Vf=vi+at
1/-48÷9.8= 4.89s
2/ 4.89×2=9.78s
h=v.t+1⁄2at²
3/ 48(4.89) + 1⁄2 (-9.8) (5.1) ²=107.27m