MEC 461 IC Engines Chapter 2: Engine Components, operating parameters and characteristics Geometric Properties VC TC y Piston displacement: y = l + a - s B ( s = a cosθ + l 2 − a 2 sin 2 θ L BC Wrist pin Connecting rod 1/ 2 When the piston is at TC (s= l+a) the cylinder volume equals the clearance volume Vc The cylinder volume at any crank angle is: l s ) V = Vc + Ac y = Vc + πB 2 4 (l + a − s ) Maximum displacement, or swept, volume: θ a Vd = πB 2 4 L Compression ratio: For most engines B ~ L (“square engine”) rc = VBC Vc + Vd = VTC Vc 2 Geometric Properties VC TC B Average piston velocity: U p = 2 LN L BC l s stroke m rev rev stroke s Average piston speed for standard auto engine is about 15 m/s. Ultimately limited by material strength. Therefore engines with large strokes run at lower speeds “Over square engines” (B > L) with light pistons have higher rev limits ( s = a cosθ + l 2 − a 2 sin 2 θ θ a ) 1/ 2 Instantaneous piston velocity: Up = cosθ = sin θ 1 + Up 2 (l / a )2 − sin 2 θ 1/ 2 Up π ( ds dt ) 3 Piston Velocity vs Crank Angle R = l/a R=3 TC BC 4 Piston Acceleration 1/ 2 a 2 2 Piston displacement is: s = a cosθ + l 1 − sin θ l For most modern engines (a/l)2 ~ 1/9 Using series expansion approximate (1-ε)1/2 ~ 1-(ε/2) and subst θ = ωt So Substituting yields differentiating 2 a s = a cos ωt + l − sin 2 ωt 2l sin 2 ωt = (1 − cos 2ωt ) / 2 2 a s = a cos ωt + l − (1 − cos 2ωt ) 4l d 2s a 2 = a ω cos ω t + cos 2 ω t l dt 2 5 Torque and Power Torque is measured off the output shaft using a dynamometer. b Force F Stator Rotor N Load cell The torque exerted by the engine is T: T = F ⋅b units : Nm = J The power W delivered by the engine turning at a speed N and absorbed by the dynamometer is: W = ω ⋅ T = (2π ⋅ N ) ⋅ T rad rev units : ( J ) = W (1 kW = 1.341 hp ) rev s Note: ω is the shaft angular velocity in units rad/s 6 Brake Power Torque is a measure of an engine’s ability to do work and power is the rate at which work is done Note torque is independent of crank speed. The term brake power, Wb , is used to specify that the power is measured at the output shaft, this is the usable power delivered by the engine to the load. The brake power is less than the power generated by the gas in the cylinders due to mechanical friction and parasitic loads (oil pump, air conditioner compressor, supercharger, etc…). The power produced in the cylinder is termed the indicated power,Wi . 7 Indicated Work per Cycle Given the cylinder pressure data over the operating cycle of the engine one can calculate the work done by the gas on the piston. This data is typically given as P vs V The indicated work per cycle is given by Wi = ∫ PdV Compression W<0 Power W>0 Exhaust W<0 Intake W>0 8 Indicated Work per Cycle Given the cylinder pressure data over the operating cycle of the engine one can calculate the work done by the gas on the piston. This data is typically given as P vs V The indicated work per cycle is given by Wi = ∫ PdV WA > 0 A C WB < 0 Compression W<0 Power W>0 Exhaust W<0 Intake W>0 9 Work per Cycle Gross indicated work per cycle – net work delivered to the piston over the compression and expansion strokes only: Wi,g = area A + area C (>0) Pump work – net work delivered to the gas over the intake and exhaust strokes: Wp = area B + area C (<0) Net indicated work per cycle – work delivered over all strokes: Wi,n = Wi,g – Wp = (area A + area C) – (area B + area C) = area A – area B 10 Indicated Power Indicated power: WN Wi = i nR (kJ cycle)(rev s ) rev cycle where N – crankshaft speed in rev/s nR – number of crank revolutions per cycle = 2 for 4-stroke = 1 for 2-stroke Power can be increased by increasing: • the engine size, Vd • compression ratio, rc • engine speed, N 11 Indicated Work at WOT The pressure at the intake port is just below atmospheric pressure Po Pintake Pintake The pump work (area B+C) is small compared to the gross indicated work (area A+C) Wi,n = Wi,g - Wp = area A - area B 12 Indicated Work at Part Throttle The pressure at the intake port is significantly lower than atmospheric pressure Pintake The pump work (area B+C) can be significant compared to gross indicated work (area A+C) Wi,n = Wi,g - Wp = area A - area B 13 Indicated Work with Supercharging Engines with superchargers or turbochargers have intake pressures greater than the exhaust pressure, yielding a positive pump work Compressor Pintake Wi,n = area A + area B Supercharge increases the net indicated work but is a parasitic load since it is driven by the crankshaft 14 Mechanical Efficiency Some of the power generated in the cylinder is used to overcome engine friction and to pump gas into and out of the engine. The term friction power, W f , is used to describe collectively these power losses, such that: W f = Wi , g − Wb Friction power can be measured by motoring the engine. The mechanical efficiency is defined as: W f Wb Wi , g − W f = = 1− ηm = Wi , g Wi , g Wi , g 15 Mechanical Efficiency, cont’d Mechanical efficiency depends on pumping losses (throttle position) and frictional losses (engine design and engine speed). Typical values for automobile engines at WOT are: 90% @2000 RPM and 75% @ max speed. Throttling increases pumping power and thus the mechanical efficiency decreases, at idle the mechanical efficiency approaches zero. 16 Power and Torque versus Engine Speed at WOT W ∝ N ⋅ T and W ∝ N ⋅ Wcycle Rated brake power 1 kW = 1.341 hp so T ∝ Wcycle There is a maximum in the brake power versus engine speed called the rated brake power (RBP). At higher speeds brake power decreases as friction power becomes significant compared to the indicated power Wb = Wi , g − W f Max brake torque There is a maximum in the torque versus speed called maximum brake torque (MBT). Brake torque drops off: • at lower speeds due to heat losses • at higher speeds it becomes more difficult to ingest a full charge of air. 17 Indicated Mean Effective Pressure (IMEP) imep is a fictitious constant pressure that would produce the same work per cycle if it acted on the piston during the power stroke. Wi Wi ⋅ nR imep ⋅ Vd ⋅ N imep = = → Wi = Vd Vd ⋅ N nR = imep ⋅ Ap ⋅ U p 2 ⋅ nR Brake mean effective pressure (bmep) is defined as: bmep = Wb 2π ⋅ T ⋅ nR = Vd Vd → T= bmep ⋅ Vd 2π ⋅ nR imep is a better parameter than torque to compare engines for design and output because it is independent of engine size, Vd. 18 The maximum bmep of a good engine design is well established: Four stroke engines: SI engines: bmep= 850-1050 kPa* CI engines: bmep= 700 -900 kPa Turbocharged SI engines: bmep= 1250 -1700 kPa Turbocharged CI engines: bmep= 1000 - 1200 kPa Two stroke engines: Standard CI engines comparable bmep to four stroke Large slow CI engines: 1600 kPa *Values are at maximum brake torque and WOT Note, at the rated (maximum) brake power the bmep is 10 - 15% less Can use the maximum bmep in design calculations to estimate engine displacement required to provide a given torque or power at a specified engine speed. 19 Maximum BMEP bmep = Wb 2π ⋅ T ⋅ nR = Vd Vd The maximum bmep is obtained at WOT at a particular engine speed Closing the throttle decreases the bmep For a given displacement, a higher maximum bmep means more torque For a given torque, a higher maximum bmep means smaller engine Higher maximum bmep means higher stresses and temperatures in the engine hence shorter engine life, or bulkier engine. For the same bmep 2-strokes have almost twice the power of 4-stroke 20 Road-Load Power A part-load power level used for testing engines (fuel economy, emissions) is the power required to drive a vehicle on a level road at a steady speed. The road-load power, Pr , is the engine power needed to overcome rolling resistance and the aerodynamic drag of the vehicle. Pr = (C R M v g + 1 ρ a C D Av Sv2 ) ⋅ Sv 2 where CR = coefficient of rolling resistance (0.012 - 0.015) Mv = mass of vehicle g = gravitational acceleration ρa = ambient air density CD = drag coefficient (for cars: 0.3 - 0.5) Av = frontal area of the vehicle Sv = vehicle speed *Modern midsize aerodynamic cars only need 5-6 kW (7-8 HP) to cruise at 90 km/hr, hence the attraction of hybrid cars! 21 Drag Force Parameters Auto manufacturers can improve the drag force by reducing: Vehicle frontal area: 2005 Corvette is 0.57 m2 Most cars around 0.8 m2 2006 Hummer H3 is 1.56 m2 Drag coefficient CD: 2004 Toyota Prius – 0.26 2005 Porsche Boxster – 0.29 1983 Audi 100 – 0.3 2006 Dodge Challanger – 0.33 2003 Hummer – 0.57 Formula 1 car – 0.7 to 1.1 (DRS) Drag Reduction System 22 Engine power requirements α F=Mvg For a 1500 kg car moving at 50 km/hr up a 10o incline: PC = ( M v g sin α ) ⋅ S v = 35 kW = 47 hp F = Mva For a 1500 kg car accelerating (constant) from 0-100 km/hr in 8 s: Pa = M v ( S v / t ) ⋅ S v = 145 kW = 207 hp Ferrari 430 Scuderia produces 508 hp at 8500 rpm (4.3L V8 engine). It weighs 1270 kg and 0-100 km/hr in 3.6 s requires 272 kW (389 hp) 23 Automobile transmission Engine operates between 600 – 7000 rpm whereas car wheels rotate at 0 -1800 rpm Highest torque is obtained in the mid engine speed range while the greatest torque is often required at the lowest wheel speed Transmission produces high torque at low car speeds and also operates at highway speeds with the engine operating in the same speed range transmission changes the gear ratio as the car speeds up Automatic transmission – gears shift automatically based on input data from the sensors on the engine and the transmission (e.g., engine speed, vehicle speed, throttle position, brake pedal position) Manual transmission – operator shifts gears 24 Gears Gears change the speed of rotation and torque transmitted between shafts Consider a simple gear set consisting of two gears: ωo ωi Ri Ro GR = Ro Ri Vc, Fc Gear ratio (GR) is the number of turns of the input shaft required to give one revolution of the output shaft Vc = ωi Ri = ωo Ro Fc = Ti / Ri = To / Ro Ri ωi ωo = ωi = GR Ro Ro To = Ti = GR ⋅ Ti Ri 25 Automobile Transmission An automobile is more complicated because you need several gear ratios so the car can accelerate smoothly (shift for power or fuel economy?) Automatic transmission uses two sets of planetary gears to give three or four forward gear ratios and one reverse Manual transmission typically has five forward gears and a reverse Gear GR ωo/ωi To/Ti 1 3:1 1/3 3 2 2.5:1 2/5 5/2 3 1.5:1 2/3 3/2 4 1:1 1 1 0.75:1 4/3 3/4 5 (OD) 26 500 1999 Neon DOHC Engine 1st gear (GR=3.54) 2nd gear (GR=2.13) 3rd gear (GR=1.36) 4th gear (GR=1.03) 5th gear (GR=0.72) 450 400 Torque (Ft-lb) 350 ω2 nd = GR2 ω1st GR1 300 250 4210 rpm 3610 rpm 200 150 100 50 0 0 1000 2000 3000 4000 5000 6000 7000 8000 Engine speed (RPM) 27 Specific Fuel Consumption For transportation vehicles fuel economy is generally given as mpg, or L/100 km (in the future gm of CO2/km). In engine testing the fuel consumption is measured in terms of the fuel mass flow rate m f . The specific fuel consumption, sfc, is a measure of how efficiently the fuel supplied to the engine is used to produce power, m f bsfc = Wb m f isfc = Wi units : g kW ⋅ hr Clearly a low value for sfc is desirable since for a given power level the lesser the fuel consumed the better it is. 28 Brake Specific Fuel Consumption vs Engine Size Bsfc decreases with engine size due to reduced heat losses from gas to cylinder wall. Note cylinder surface to volume ratio increases with bore diameter. heat loss cylinder surface area πBL 1 = = 2 ∝ energy released cylinder volume πB L B 29 Brake Specific Fuel Consumption vs Engine Speed There is a minimum in the bsfc versus engine speed curve bsfc = m f Wb At high speeds the bsfc increases due to increased friction i.e. smaller Wb At lower speeds the bsfc increases due to increased time for heat losses from the gas to the cylinder and piston wall, and thus a smaller Wi Bsfc decreases with compression ratio due to higher thermal efficiency 30 Performance Maps Performance map is used to display the bsfc over the engines full load and speed range. Using a dynamometer to measure the torque and fuel mass flow rate for different throttle positions you can calculate: bmep = 2π ⋅ T ⋅ nR Vd m f bsfc = Wb Wb = (2π ⋅ N ) ⋅ T bmep@WOT Constant bsfc contours from a 2 litre four cylinder SI engine 31 Engine Efficiencies The time for combustion in the cylinder is very short, especially at high speeds, so not all the fuel may be consumed A small fraction of the fuel may not react and exits with the exhaust gas The combustion efficiency is defined as: Qin Q in actual heat input = = ηc = theoretical heat input m f ⋅ QHV m f ⋅ QHV where Qin = heat added by combustion per cycle mf = mass of fuel added to cylinder per cycle QHV = heating value of the fuel (chemical energy per unit mass) 32 Engine Efficiencies (2) The thermal efficiency is defined as: ηth = W W work per cycle = = heat input per cycle Qin ηc ⋅ m f ⋅ QHV or in terms of rates W W power out = = ηth = rate of heat input Q in η c ⋅ m f ⋅ QHV Thermal efficiencies can be given in terms of brake or indicated values Indicated thermal efficiencies are typically 50% to 60% and brake thermal efficiencies are usually about 30% 33 Engine Efficiencies (3) Fuel conversion efficiency is defined as: W W = ηf = m f ⋅ QHV m f ⋅ QHV Note: ηf is very similar to ηth, difference is ηth takes into account actual fuel combusted. Recall: m f sfc = W Therefore, the fuel conversion efficiency can also be obtained from: ηf = 1 ( sfc ) ⋅ QHV 34 Volumetric Efficiency Due to the short cycle time at high engine speeds and flow restrictions through the intake valve less than ideal amount of air enters the cylinder. The effectiveness of an engine to induct air into the cylinders is measured by the volumetric efficiency: ηv = ma n ⋅ m actual air inducted = = R a theoretical air ρ a ⋅ Vd ρ a ⋅ Vd ⋅ N where ρa is the density of air at atmospheric conditions Po, To and for an ideal gas ρa =Po / RaTo and Ra = 0.287 kJ/kg-K (at standard conditions ρa= 1.181 kg/m3) Typical values for WOT are in the range 75%-90%, and lower when the throttle is closed 35 Air-Fuel Ratio For combustion to take place the proper relative amounts of air and fuel must be present in the cylinder. The air-fuel ratio is defined as AF = ma m a = m f m f For gasoline fuel the ideal AF is about 15:1, with combustion possible in the range of 6 to 19. For a SI engine the AF is in the range of 12 to 18 depending on the operating conditions. For a CI engine, where the mixture is highly non-homogeneous, the AF is in the range of 18 to 70. 36 Relationships Between Performance Parameters By combining equations presented in this section the following additional working equations are obtained: W = η f ⋅ηv ⋅ N ⋅ Vd ⋅ QHV ⋅ ρ a ⋅ (1 / AF ) nR η f ⋅ηv ⋅ Vd ⋅ QHV ⋅ ρ a ⋅ (1 / AF ) T= 2π ⋅ nR mep = η f ⋅ηv ⋅ QHV ⋅ ρ a ⋅ (1 / AF ) 37 38 Scanned by CamScanner