End Of Unit-Algebraic Expression Total Marks: 30 Question 1 Express 3 2 − 2π₯ + 1 π₯ + 1 as a single algebraic fraction in its simplest form. .......................... (2 marks) Question 2 Solve the equation (2 + √5)π₯ = 6 − √5, giving π₯ in the form π + π√5 where π and π are integers. .......................... (4 marks) Question 3 The function π is defined by 2 6 2 60 π(π₯) = 2π₯+5 + 2π₯−5 + 4π₯ 2 −25 π₯>4 π΄ Show that π(π₯) = π΅π₯+πΆ where π΄, π΅ and πΆ are constants to be found. .......................... (4 marks) Question 4 The function π is defined by π(π₯) = 6 2 60 + + 2 2π₯+5 2π₯−5 4π₯ −25 π₯ > 4It can be shown that π(π₯) = 8 2π₯−5 Find π −1 (π₯). π −1 (π₯) = .......................... (3 marks) Question 5 Given π¦ = 2π₯ , express the following in terms of π¦. 3 1 42π₯−3 Write your expression in its simplest form. .......................... (2 marks) Question 6 Solve the equation 22π₯+5 − 7(2π₯ ) = 0 giving your answer to 2 decimal places. (Solutions based entirely on graphical or numerical methods are not acceptable.) .......................... (4 marks) Question 7 Solve the equation 4 10 + π₯√8 = 6π₯ √2 Give your answer in the form π√π where π and π are integers. π₯ = .......................... (4 marks) Question 8 Factorise fully 81 − 16π₯ 4 .......................... (3 marks) 5 Question 9 Figure 4 shows the plan view of the design for a swimming pool. The shape of this pool π΄π΅πΆπ·πΈπ΄ consists of a rectangular section π΄π΅π·πΈ joined to a semicircular section π΅πΆπ· as shown in Figure 4. Given that π΄πΈ = 2π₯ metres, πΈπ· = π¦ metres and the area of the pool is 250 m 2 , show that the perimeter, π metres, of the pool is given by π = 2π₯ + π ππ₯ + π₯ 2 where π is a constant to be found. .......................... (4 marks) 6 Answers Question 1 1−π₯ (2π₯+1)(π₯+1) Question 2 π = −17, π = 8 Question 3 π΄ = 8, π΅ = 2, πΆ = −5 Question 4 π −1 (π₯) = 8+5π₯ 2π₯ Question 5 64 π¦4 7 Question 6 π₯ = −2.19 Question 7 π₯ = 5√2 Question 8 (9 + 4π₯ 2 )(3 − 2π₯)(3 + 2π₯) Question 9 π = 250