APPLIED ELECTRONICS II CHAPTER 1: FEEDBACK AMPLIFIERS 1. 2. 3. 4. OVERVIEW Types of Feedback The Feedback Concept Feedback Topologies Advantages of Negative Feedback • • • • Gain Desensitivity Noise/ Interference Reduction Reduction of Nonlinear Distortion Control of Impedance and Bandwidth Extension 5. Analysis of Feedback Amplifiers • • • • Voltage-Series (Voltage Amplifier) Feedback Current-Series (Transconductance Amplifier) Feedback Current-Shunt (Current Amplifier) Feedback Voltage-Shunt (Transresistance Amplifier) Feedback TYPES OF FEEDBACK • Feedback can either be positive or negative 1. Positive Feedback • A portion of the output signal is added to the input. Positive feedback is used in the design of oscillator and a number of other applications (will be discussed in Chapter 4 and 5). 2. Negative Feedback • A portion of the output signal is subtracted from the input signal. The basic idea of negative feedback is to trade off gain for other desirable properties, such as to desensitize the gain, Reduce nonlinear Distortion, Reduce the effect of noise, control input and output impedances and extend the bandwidth of the amplifiers. NEGATIVE FEEDBACK Example • Introducing resistor at the emitter of BJT common-emitter circuits stabilizes the Q-point against variation transistor parameters. THE FEEDBACK CONCEPT • Signal Source: This block is a voltage source Vs with a series resistor Rs (Thevenin's equivalent circuit) or a current source Is with a parallel resistor Rs (Norton’s equivalent circuit). • Feedback Network: Usually a passive two-port network with reverse transmission β. THE FEEDBACK CONCEPT • Sampling Network: Sampling Blocks shown below. • Voltage or Node Sampling: Output voltage is sampled by connecting the feedback network in shunt across the output. • Current or loop Sampling: Output current is sampled by connecting the feedback network in series with the output. THE FEEDBACK CONCEPT • Comparator or Mixer Network: mixing blocks are shown below • Series Mixing • Shunt Mixing THE FEEDBACK CONCEPT • Basic Amplifier (A): could be used to represent a Voltage Amplifier, Current Amplifier, Transconductance Amplifier or a Transresistance Amplifier. • Thevenin’s equivalent circuit of a Voltage Amplifier. It has ideally infinite input resistance (Ri), zero output resistance (RO) and a Voltage Gain (π΄π = ππ Τππ ) THE FEEDBACK CONCEPT • Norton’s equivalent circuit of a Current Amplifier. It has ideally zero input resistance (Ri), infinite output resistance (RO) and a current gain (π΄π = πΌπ ΤπΌπ ). THE FEEDBACK CONCEPT • Transconductance Amplifier which ideally has infinite input resistance (Ri), infinite output resistance (RO) and a transconductance gain (πΊπ = πΌπ Τππ ). Gm – Short circuit mutual or transfer conductance. THE FEEDBACK CONCEPT • Transresistance Amplifier which ideally has zero input resistance (Ri), zero output resistance (RO) and a transresistance gain (π π = ππ ΤπΌπ ). Rm – Open circuit mutual or transfer resistance. THE TRANSFER GAIN WITH FEEDBACK • The figure shows the basic structure of a feedback amplifier using a signal flow graph, where each of the quantities x can represent either a voltage or a current signal. THE TRANSFER GAIN WITH FEEDBACK • The open-loop gain, A represents the transfer gain of the basic amplifier without feedback. Implicit in the description is that the source, the load, and the feedback network do not load the basic amplifier. That is, the gain A does not depend on any of these three networks. In practice this will not be the case. FEEDBACK TOPOLOGIES • There are four basic feedback topologies, based on the input signal (voltage or current) and the output signal (voltage or current). They are described by the type of connection at the input and output of the circuit. A. Voltage-Series (Series-Shunt) or Voltage Amplifier B. Current-Shunt (Shunt-Series) or Current Amplifier C. Current-Series (Series-Series) or Transconductance Amplifier D. Voltage-Shunt (Shunt-Shunt) or Transeresistance Amplifier FEEDBACK TOPOLOGIES GENERAL CHARACTERISTICS OF NEGATIVE FEEDBACK • Gain Desensitivity: Variation in gain due to temperature, aging or other parameters is reduced by negative feedback. E.g. Emitter Stabilized Common Emitter Amplifier. • Assuming β is constant and taking the derivative of Af with respect to A, GAIN DESENSITIVITY • Hence the percentage change in Af (due to variations in some circuit parameter) is • smaller than the percentage change in A by a factor equal to the amount of feedback. For this reason, the amount of feedback, 1 + Aβ, is also known as the Desensitivity Factor. Example: The open-loop gain of an amplifier is A = 5 × 104V/V exhibits a gain change of 25% as the operating temperature changes. Calculate the percentage change if the closed loop gain Af = 50V/V NOISE/INTERFERENCE REDUCTION • Under certain condition feedback amplifiers can be used to reduce noise/interference. • This can be achieved if a preamplifer which is (relatively) noise/interference-free preceded the noise/interference-prone amplifier. • Under such conditions the Signal-to-Noise ratio can be improved (compared to noise/interferenceprone amplifier without feedback) by the factor of the preamplifier gain. REDUCTION OF NONLINEAR DISTORTION • Distortion in the output is due to application of large amplitude input signal applied beyond the linear region of operation. • Negative feedback can be implemented to reduce nonlinear distortion by the Desensitivity factor. • Assuming that the open-loop gain • It implies that Af is independent of the nonlinear properties of the transistors used in the basic amplifier. • Since the feedback network usually consists of passive components, which usually can be chosen to be as accurate as one wishes. BANDWIDTH EXTENSION AND REDUCTION OF FREQUENCY DISTORTION • The amplifier bandwidth is increased by the same factor by which its midband gain is decreased, maintaining the gain–bandwidth product at a constant value. CONTROL OF IMPEDANCE • Input Impedance • If the feedback signal is returned to the input in series with the applied voltage (Series mixing), it increases the input resistance. • If the feedback signal is returned to the input in shunt with the applied signal (Shunt mixing), it decreases the input resistance • Output Impedance • If the feedback samples the output voltage (Voltage sampling), it tends to decrease the output resistance • If the feedback samples the output current (Current Sampling), it tends to increase the output resistance. VOLTAGE SERIES • Input Impedance Applying KVL to the input side, and Let , where Av is the voltage gain without feedback taking the load resistor into account. Then, • Avo represents the open circuit voltage gain without feedback taking Rs into account VOLTAGE SERIES • Output Impedance: in any circuit to calculate the output impedance we must first remove the external input source (voltage or current). • Remove the load resistor and then impress a voltage across the output terminals and calculate the current in order to obtain π ππ = ππ₯ ΤπΌπ₯ Since, VOLTAGE SERIES CURRENT SERIES • Input Impedance: is calculated in a similar manner to the voltage series topology to obtain, • Where, is the short circuit transconductance, and is the transconductance without feedback taking the load into account. CURRENT SERIES • Applying KCL at the output • The input voltage is given by, • Substituting, • Rearranging for the output impedance, CURRENT SERIES • The output impedance with feedback taking the load resistor into consideration will be, • Dividing both the numerator and denominator by RO + RL we get, CURRENT SHUNT • Input Impedance: • Applying KCL at the input and current division at the output, • Taking , • Ai is the short-circuit current gain taking Rs into account, and AI is the current gain taking the load into account. • Output Impedance: is calculated in the same manner to the current series topology, VOLTAGE SHUNT • Input Impedance: is calculated in a similar manner to the current shunt topology, • Output Impedance: is calculated in a similar manner to the voltage series topology, • Rm is the open circuit transresistance gain taking Rs into account and Is the transresistance gain without feedback taking the load into account. FUNDAMENTAL ASSUMPTIONS • Some fundamental assumptions are taken in order to analyze the four feedback configurations. • The basic amplifier (A) is unilateral, transmitting signal from input to output. • The feedback network (β) is unilateral, transmitting signal from output to input. • β is independent of the source and load resistors (RS and RL) • In practical case, • • • • feedback network will not be ideal, it is resistive and will load the amplifier Source and load resistances will affect A, Ri, and Ro Source and load resistances should be lumped with basic amplifier The feedback network should be expressed as a two port network METHOD OF ANALYSIS OF FEEDBACK AMPLIFIERS • First identify the feedback component then proceed with the following steps: METHOD OF ANALYSIS OF FEEDBACK AMPLIFIERS EXAMPLE • Assume RS = 0, hfe = 50, hie = 1.1kΩ , hre = hoe = 0 and identical transistors